Peter and Jane have some money in the ratio 1:3
Jane has £12 more than Peter how much money does Peter have?

Answer:

20 i'm sure

Step-by-step explanation:

Answer:

20! brandonlugo2026 is correct.

Step-by-step explanation:

The correct answer is 82% of 50 (41) / 170% of 30 (51) /65% of 80 (52)

Explanation:

The first step to know whether a value is greater than another is to find the value each percentage represents depending on the total. This process is shown below.

1. 65% of 80- This implies 80 is 100% and 85% needs to be found. Use the following formula:

80 / 100 = 0.8 x 65 = 52 or the total number divided by 100 and multiplied by the percentage you want to know

2. 82% of 50 - Repeat the same process

50 / 100 = 0.5 x 82 = 41

3. 170% of 30

30 / 100 = 0.3 x 170 = 51

4. Finally organize the values

82% of 50 (41)

170% of 30 (51)

65% of 80 (52)

Based on the information given about the percentages ,the ordering will be 82% of 50, 170% of 30, and 65% of 80.

It should be noted that 82% of 50 will be:

= 82% × 50

= 41

170% of 30 will be:

= 1.7 × 30

= 51

65% of 80 will be:

= 65% × 80

= 0.65 × 80

= 52

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The statement that is true about rhombus is d. some rhombuses have four right angles.

A rhombus is a parallelogram with equal-length sides, though the angles at the opposing ends need not be equal, nor must the sides be parallel. If a rhombus is also a cube, it can have four right angles. It can be viewed as an equal-sided trapezoid as well.

A parallelogram has two sets of parallel sides, whereas a trapezoid only has one pair of parallel sides. Therefore, it is untrue that a trapezoid has two sets of parallel edges. Not all rectangles are squares, but they are all quadrilaterals with four right angles. A unique variety of parallelogram called a square has equal-length edges. Therefore, it is untrue to say that all circles are squares.

Complete Question:

which statement about a quadrilateral is true?

a. a rhombus has exactly one pair of parallel sides.

b. a trapezoid has two pairs of parallel sides.

c. all rectangles are squares.

d. some rhombuses have four right angles.

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the mean of each sample in row 1 is 9, in row 2 is 4.5, in row 3 is 4.75, and in row 4 is also 4.75.

To find the mean of each sample, we'll calculate the average value for each row in the table.

Row 1: The mean of the samples in row 1 is obtained by summing the values 11, 6, 14, and 5, and dividing by 4 (the number of values in the row):

Mean of row 1 = (11 + 6 + 14 + 5) / 4 = 36 / 4 = 9

Row 2: The mean of the samples in row 2 is calculated similarly:

Mean of row 2 = (8 + 6 + 0 + 4) / 4 = 18 / 4 = 4.5

Row 3: The mean of the samples in row 3:

Mean of row 3 = (9 + 2 + 3 + 5) / 4 = 19 / 4 = 4.75

Row 4: The mean of the samples in row 4:

Mean of row 4 = (4 + 6 + 7 + 2) / 4 = 19 / 4 = 4.75

Hence, the mean of each sample in row 1 is 9, in row 2 is 4.5, in row 3 is 4.75, and in row 4 is also 4.75.

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Answer:

1668 feet.

Step-by-step explanation:

We know the opposite side of the right triangle and we need the adjacent side, so we use the tangent function.

If the distance required is x  (adj side) we have:

tan 41 = opp/adj

tan 41 = 1450/x

x = 1450 / tan 41

= 1668.03

The finite difference approximation for a Neumann boundary condition, \(\left(\frac{df}{dx}\right)\), at node \(n\) (right boundary) to \(O(h^2)\) is given by

\(\left(\frac{df}{dx}\right)_n \approx \frac{f_{n-2} - 4f_{n-1} + 3f_n}{2h}\),

where \(f_{n-2}\), \(f_{n-1}\), and \(f_n\) represent the function values at nodes \(n-2\), \(n-1\), and \(n\) respectively, and \(h\) represents the spacing between the nodes.

To derive this approximation, we start with the Taylor series expansion of \(f_{n-1}\) and \(f_n\) around \(x_n\):

\(f_{n-1} = f_n - hf'_n + \frac{h^2}{2}f''_n - \frac{h^3}{6}f'''_n + \mathcal{O}(h^4)\),

\(f_{n-2} = f_n - 2hf'_n + 2h^2f''_n - \frac{4h^3}{3}f'''_n + \mathcal{O}(h^4)\).

By subtracting \(4f_{n-1}\) and adding \(3f_n\) from the second equation, we eliminate the first-order derivative term and retain the second-order derivative term. Dividing the result by \(2h\) gives us the desired finite difference approximation to \(O(h^2)\).

In conclusion, the finite difference approximation for a Neumann boundary condition, \(\left(\frac{df}{dx}\right)\), at node \(n\) (right boundary) to \(O(h^2)\) is \(\left(\frac{df}{dx}\right)_n \approx \frac{f_{n-2} - 4f_{n-1} + 3f_n}{2h}\). This approximation is obtained by manipulating the Taylor series expansion of \(f_{n-1}\) and \(f_n\) to eliminate the first-order derivative term and retain the second-order derivative term, resulting in a second-order accurate approximation.

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Answer:

5,154

Step-by-step explanation:

Answer:

4/3

Step-by-step explanation:

slope=X1-Y1/X2-Y2

= -8-4/-4-5

= -12/-9

= 4/3

Under the given transformation, the image of the set S = {(u, v) | 0 ≤ u ≤ 3, 0 ≤ v ≤ 2} is the set {(x, y) | 0 ≤ x ≤ 12, -2 ≤ y ≤ 3}.

To find the image of the set S under the given transformation, we substitute the bounds of S into the equations for x and y and determine the resulting range of values.

The set S is defined as {(u, v) | 0 ≤ u ≤ 3, 0 ≤ v ≤ 2}. We will find the image of each boundary point and then determine the range of values for the transformed set.

For u = 0 and v = 0:

x = 2(0) + 3(0) = 0

y = 0 - 0 = 0

The point (0, 0) is transformed to (0, 0).

For u = 3 and v = 0:

x = 2(3) + 3(0) = 6

y = 3 - 0 = 3

The point (3, 0) is transformed to (6, 3).

For u = 0 and v = 2:

x = 2(0) + 3(2) = 6

y = 0 - 2 = -2

The point (0, 2) is transformed to (6, -2).

For u = 3 and v = 2:

x = 2(3) + 3(2) = 12

y = 3 - 2 = 1

The point (3, 2) is transformed to (12, 1).

Now, let's consider the range of transformed points for the x and y coordinates.

For the x-coordinate, we observe that the minimum value is 0 (from point 1) and the maximum value is 12 (from point 4). Therefore, the range of x is [0, 12].

For the y-coordinate, we observe that the minimum value is -2 (from point 3) and the maximum value is 3 (from point 2). Therefore, the range of y is [-2, 3].

Combining the ranges of x and y, we have the image of set S as:

{(x, y) | 0 ≤ x ≤ 12, -2 ≤ y ≤ 3}

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On solving the provided question, we can say that 1 degree = 3600 arc seconds and 1 degree = 60 arc minutes.

A 160 degree angle is measured in arc minutes, often known as arcmin, arcmin, arcmin, or arc minutes (represented by the sign '). One minute is equal to 121600 revolutions, or one degree, hence one degree equals 1360 revolutions (or one complete revolution). A degree, also known as a complete angle of arc, angle of arc, or angle of arc, is a unit of measurement for plane angles in which a full rotation equals 360 degrees. A degree is sometimes referred to as an arc degree if it has an arc of 60 minutes. Since there are 360 degrees in a circle, an arc's angles make up 1/360 of its circumference.

1 degree = 3600 arc seconds

1 degree = 60 arc minutes

A. 2 degree 18'36 = 2 + 18/60 + 36 / 2600 = 231 / 100 degree

B. 36 ′ 18 ′′ = 36/60 + 18/2600 = 121 / 200 degree

C. 7 degrees 59′ 59′′ = 7 + 59 / 60 + 59 / 3600 = 28799 / 3600 degree

D. 1' = 1/60 degree

F. 1" = 1/3600 degree

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Answer:

Option (1)

Step-by-step explanation:

Coordinates of the vertices are A(-2, 1), B(2, 7), C(8, 3) and D(4, -3)

Since ABCD is a square,

Perimeter of a square = 4 × (length of a side)

                                    = 4 × (AB)

Formula to calculate the distance between two points \((x_1,y_1)\) and \((x_2,y_2)\) is,

d = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Therefore, distance between two points A(-2, 1) and B(2, 7) will be,

AB = \(\sqrt{(2+2)^2+(7-1)^2}\)

AB = \(\sqrt{4^2+6^2}\)

AB = \(\sqrt{52}\)

AB = \(2\sqrt{13}\)

Now area of  square ABCD = 4 × \(2\sqrt{13}\)

                                              = \(8\sqrt{13}\) unit

Therefore, option (1) will be the answer.

Answer:

They trees on school property have no correlation with the students score on standardized tests

Step-by-step explanation:

this problem made no sense but hopefully this helps

Answer:

\( 3\bigg( \dfrac{a}{b^2}+\dfrac{6c}{b^2}\bigg) \)

Step-by-step explanation:

Here we have ,

\(\sf\longrightarrow \dfrac{3a+18c}{b^2} \)

This can be written as ,

\(\sf\longrightarrow \dfrac{3a}{b^2}+\dfrac{18c}{b^2} \)

You can take out 3 as common,

\(\sf\longrightarrow 3\bigg( \dfrac{a}{b^2}+\dfrac{6c}{b^2}\bigg) \)

We can't simplify this any further. Hope this helps!

Answer:

\(33\frac{1}{3}\)

Step-by-step explanation:

square is just multiplying things twice

(-3 1/3)(-3 1/3)

(-10/3)(-10/3)

100/3

33 1/3

Hopes this helps

Answer: 1

Step-by-step explanation:

(-3 1/3)= (-1/3)+(-1/3)+(-1/3) = -1

(-3 1/3)^2 = (-1)^2 = (-1)(-1) = 1

Answer:

62.5%

Step-by-step explanation:

There are a total of 8 options.

We are trying to get 5 of the 8.

5/8 = 0.625 = 62.5%

Answer:

perimeter of quadrant circle=1/4×pi×radius

""""" =1/4×3.14×10

perimeter of quadrant circle= 7.85cm

e

Answer:

\(5\pi\)

Step-by-step explanation:

Circle perimeter: 2\(\pi\)r

You get \(\frac{1}{4}\) of circle perimeter

So: Circle perimeter = 2*\(\pi\)*10=20\(\pi\)

and:  \(\frac{20\pi }{4}=5\pi\)

Answer:

x=-14

Step-by-step explanation:

think the number is x

According to the question

x/7+12=10

=>x+84=70 (multiply both side by 7)

=>x=70-84

x=-14

The probability that exactly 28 of the employees work over forty hours per week using the binomial distribution is given below. Information required to find the probability of employees working over forty hours per week are as follows:

n = 54

x = 28

p = 0.35

Formula used in the binomial distribution is given below:

P(X=x) = nCx * p^x * q^(n-x)

Where:

P(X=x) is the probability of exactly x successes in n trialsn

Cx = n! / x!(n-x)!p = probability of success q = 1 - p = probability of failure.

The probability that exactly 28 of the employees work over forty hours per week can be found as:P(X=28) = 54C28 * 0.35^28 * 0.65^26= 0.1646Therefore, the probability that exactly 28 of the employees work over forty hours per week using the binomial distribution is 0.1646.

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The table of values that represents exponential decay is (c)

From the question, we have the following parameters that can be used in our computation:

The table of values

An exponential function is represented as

y = abˣ

Where

Rate = b

When the rate is less than 1, then the table represents a decay

i.e when y reduces as x increases

The table that has the above features is the table (c)

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Answer:

a) P(t) = 5/6t + 20

b) 34.2 beetles

c) After 78 weeks.

Step-by-step explanation:

a) A general linear growth model can be expressed as P(t) = at + b, where P is the number of beetles in time t and t is the time in weeks.

It is known that:

P(0) = 20

P(6) = 25

These values can be substituted in the general equation to find a and b:

P(t) = at + b

P(0) = 20:

20 = a*0 + b

20 = 0 + b

20 = b

So,

P(t) = at + 20

Using P(6) = 25:

25 = a*6 + 20

25 - 20 = a*6

5 = a*6

5/6 = a

So, the linear growth model can the represented as:

P(t) = 5/6t + 20

b)

The number of beetles after 17 weeks is P(17):

P(17) = 5/6*17 + 20

P(17) = 14.1 + 20

P(17) = 34.2

34.2 beetles.

c)

P(t) = 85

85 = 5/6t + 20

85 - 20 = 5/6t

65 = 5/6t

t = 65*6/5

t = 78

After 78 weeks.

\({ \purple{ \sf{11 {x}^{2} - 5x + 18}}}\)

Step-by-step explanation:

Re-arrange the problem in the form of ax²+bx+c = 0. i.e. quadratic equation.

\({ \red{ \sf{p(x) = - 5 {x}^{2} + 3x + 2}}}\)

\({ \red{ \sf{q(x) = 16 {x}^{2} - 8x + 15}}}\)

\({ \red{ \sf{p(x) + q(x) = \: ? }}}\)

\({ \green{ \sf{p(x) + q(x) }}}\)

\( { \red{ \sf{ = ({ - 5x}^{2} + 3x + 2) + (16 {x}^{2} - 8x + 15)}}}\)

\({ \red{ \sf{ - 5 {x}^{2} + 3x + 2 + 16 {x}^{2} - 8x + 15}}}\)

\({ \blue{ \sf{11 {x}^{2} - 5x + 18}}}\)

If we have 3/5 bran muffins and Andrea has 10 muffins, she purchased 6.

Purchased in the past tense and past participle. In a sale, the transaction is finished when the buyer pays the seller. In a transaction, the buyer has two options: they either pay the seller in full or they can arrange financing with a third party, like a bank or leasing firm. The amount an investor pays for an investment is referred to as the purchase price, and when the investment is sold, that figure becomes the investor's cost basis for calculating gain or loss. Shoes Unlimited places an order with a foreign supplier for 10,000 pairs of sneakers. This entails the issuance of a purchase order, which is a formal declaration by the business that it will buy the specified kind and number of shoes.

Based on the given condition,

Formulate:

10*3/5

Calculate.

10*3/5

Simplify.

2*3

Calculate.

6

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The equation that represents the amount of discount offered (d) on an item whose usual price is p d = 0.15p.

The discount on 80 pounds will be 12 pounds.

From the information given, Dominic is shopping at a store that is offering a discount of 15 percent off the usual price of any item.

Let the price of the item be illustrated as p.

Since there's a 15% off, this will be:

= p - (15% × p)

= p - 0.15p

= 0.85p

The discount is 0.15p

The discount on 80 pounds will be:

= 0.15 × 80

= 12

The discount is 12 pounds.

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Answer: 4000

Step-by-step explanation: 2000 there and 2000 back. 2000+2000=4000

Hope this helps!

The perimeter of the Christian's sandbox is 24 feet.

The given two quadrialterals are similar

Let us find the remaining lengths of Christian's sandbox

By proportional equation

36/8=18/x=27/y=18/z

4.5=18/x=27/y=18/z

x=18/4.5 = 4

y=27/4.5 = 6

z=4

The perimeter is sum of all the sides

So perimeter of Christian's sandbox is 8+6+4+4

24 feet

Hence, the perimeter of the Christian's sandbox is 24 feet.

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Answer:

Its definitley square to be precise so that's my answer, but its also a rhombus

Step-by-step explanation:

assuming a is 1, regardless, graph would always be square, which is a rhombus. hope  square is correct :)

The most basic distinction between types of data is that some data are quantitative while other data are qualitative. Quantitative data consists of numerical information that can be measured or counted, allowing for statistical analysis and objective comparisons. This type of data can be further classified into two subcategories: continuous data and discrete data.

Continuous data represent measurements that can take on any value within a specified range, such as height, weight, temperature, or time. These measurements can be represented using fractions or decimals and are typically collected using precise instruments like rulers or thermometers.

Discrete data, on the other hand, consist of distinct, separate values that can be counted or categorized. Examples of discrete data include the number of students in a class, the number of cars in a parking lot, or the number of books sold in a month. Discrete data is often collected through surveys or counting processes.

In contrast, qualitative data are non-numerical and describe attributes, characteristics, or experiences. This type of data is typically obtained through observation, interviews, or open-ended survey questions. Examples of qualitative data include feelings, opinions, beliefs, or descriptions of events.

In summary, the primary distinction between types of data lies in their nature: quantitative data is numerical and allows for objective measurement, while qualitative data is descriptive and explores subjective aspects. Understanding the difference between these two types of data is essential for conducting accurate and meaningful research.

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