Paul is building a bridge for a school project and wants to make a right triangle out of three popsicle sticks that measure 8 cm, 10 cm and 18 cm. Can he make a right triangle out of these lengths?

Answer:

i cant see question one very much

Step-by-step explanation:

\(\underset{in~degrees}{\textit{sum of all interior angles}}\\\\ S = 180(n-2) ~~ \begin{cases} n=\stackrel{number~of}{sides}\\[-0.5em] \hrulefill\\ n = 4 \end{cases}\implies S=180(4-2)\implies S=360\)

Check the picture below.

Answer:

0.6

Step-by-step explanation:

Answer: 0.6

Step-by-step explanation:

Answer:

First, an asymptote means that the function "tends to go" to a value, bt actually never reaches it.

The functions here are:

A.f(x) = 2 + 1

B.f(x) = x^2 + 1

c.f(x) = x^2 - 1

D.f(x) == +1

The functions are really poorly written, but i will try to answer this.

first:

"a root at x = -1"

Means that f(-1) = 0,

The only function that is zero when x = -1, is the option c.

f(-1) = (-1)^2 - 1 = 1 - 1 = 0.

Now, if we want to have a vertical asymptote at x = 2, then we should have a function like:

\(f(x) = \frac{something}{x - 2}\)

So we want to have a quotient, where the denominator is equal to zero when x = 2, this will lead to a vertical asymptote.

I can not see this in the options provided, so i guess that the functions are just not well written.

For a horizontal asymptote, we have something like:

\(f(x) = \frac{something}{x} + 1\)

So as x starts to grow, the first term in the function will start to decrease, until it becomes really close to zero (but is never equal to zero) so in that case we have an horizontal asymptote to f(x) = 1.

Stacks exhibit the property of Last-In-First-Out (LIFO), and they have constant-time insertion and removal. However, the statement "linear time" is not applicable to stacks.

Stacks exhibit the property of Last-In-First-Out (LIFO), which means that the last item inserted into the stack is the first one to be removed. This property allows for efficient insertion and removal of elements. However, the statement "linear time" is not applicable to stacks as it does not specify a specific operation or time complexity. Instead, the time complexity of stack operations depends on the implementation and the specific operation being performed.

Stacks have several key characteristics:

LIFO Order: Stacks follow the Last-In-First-Out order, where the most recently added item is the first one to be removed.

Constant-Time Insertion and Removal: Both pushing (inserting) and popping (removing) an element from a stack have a constant time complexity of O(1). This efficiency is achieved because elements are added or removed from the top of the stack.

Limited Access: Stacks typically allow access only to the topmost element. In other words, you can only push, pop, or peek (view) the top element without direct access to other elements in the stack.

Dynamic Size: Stacks can dynamically grow or shrink as elements are added or removed.

In summary, the statement "linear time" is not applicable to stacks as it does not describe a specific characteristic or operation of stacks.

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Answer:

Not!

Volume = m/d

Step-by-step explanation:

It is just Volume = m/d

where

m is the mass of the ice cube and

d is the density of water.

In the second state, where the ice has melted, it turns into water of volume....

Volume = m/d! exactly the same volume as it displaced before.

Answer:

26% of 200 is 52.

Step-by-step explanation:

Answer:

It would be C or 56.70

Answer:

assuming youre using slope intercept form im pretty sure the equation would be

y=4x+3

because if you only have to rent shoes one time and every game costs $4 you pay $4 every game you played.

Another equation you could use using the variables provided:

3n + 4g = x

Step-by-step explanation:

hope this helps

Answer:

4b+4

Step-by-step explanation:

7b-3b = 4b and then you cant do anything with the four so your answer should be 4b+4!

The points (2, 2), (4, - 2), (- 6, - 2), (- 2, 4) are examples of ordered pairs on the coordinate plane.

Coordinate planes are generated by the intersection of two orthogonal axes, a "horizontal" (x-axis) and a "vertical" (y-axis), at a point known as origin. These axes creates four regions known as quadrants, which are introduced in the image attached below.

All the ordered pairs are points of the form (x, y), where x and y represent the orthogonal positions of the point with respect to the origin. Now we proceed to present four examples of ordered pairs, each located in each quadrant: (2, 2), (4, - 2), (- 6, - 2), (- 2, 4).

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A preventive maintenance program that follows the philosophy of optimum parts replacement will have minimal parts replacement costs.

Preventive maintenance is conducted on equipment and machines to prevent unexpected breakdowns and failures.

A preventive maintenance program follows the philosophy of optimum parts replacement; it seeks to minimize the number of parts that need to be replaced to ensure optimal performance, minimal downtime, and minimal costs.

The answer to this question is that a preventive maintenance program that follows the philosophy of optimum parts replacement will have minimal parts replacement costs.

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Answer:

  (c)  y = −1/3x −2

Step-by-step explanation:

We notice two things in the table.

__

The slope of the line is ...

  m = (change in y)/(change in x) = +1/-3 = -1/3

Then the slope-intercept equation is ...

  y = mx +b . . . . . . slope m, y-intercept b

  y = -1/3x -2

Answer is C

Step-by-step explanation:

math

Answer:

and then I said I was going to sleep in the morning and then I said I was going to sleep in the morning and when I get

Answer:

idfk

Step-by-step explanation:

you add

Since probabilities cannot be negative, we can conclude that the given probabilities are inconsistent or there might be an error in the information provided. Please verify the values and provide correct probabilities so that we can accurately calculate P(B|A), the probability of the flight being delayed when it is raining.

Let's denote the events as follows:

A: It will rain

B: The flight will be delayed

We are given the following probabilities:

P(A) = 0.11 (probability of rain)

P(B) = 0.14 (probability of flight delay)

P(A'∩B') = 0.76 (probability of no rain and on-time departure)

We can use the probability formula to calculate the probability of the flight being delayed when it is raining, P(B|A), which is the probability of B given A.

We know that:

P(B|A) = P(A∩B) / P(A)

To find P(A∩B), we can use the formula:

P(A∩B) = P(A) - P(A'∩B')

Substituting the given values:

P(A∩B) = P(A) - P(A'∩B')

P(A∩B) = 0.11 - 0.76

P(A∩B) = -0.65

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Answer:

704 people out of 800

Step-by-step explanation:

88% of 800= 704

Answer:

\(The \: problem \: probably \\ \: assumes \: direct \: variation \: \\ \\

y \: = \: k \: x \\ \\

IF \: so, \: then \: plug \: in \: the \: \\ values \: and solve \: for \: k \\ \\

27 \: = \: k(8) \\ \\

k \: = \: \frac{27}{8}

\\ \\

y \: = \: ( \frac{27}{8} )x. \\ \\ Now \: let \: x \: = \: 11 \\ \\

y \: = \: ( \frac{27}{8} )11 = \\ \\ \frac{27(11)}{8} \\ \\ = 37.125 = \\ \\ \frac{371}{8y} \\ \\

y \: = \frac{371}{8}

\)

Answer:

-8 is the final answer

Step-by-step explanation:

-(2⁵)^3/5

-2³

-8

Answer:

3x + 2y = 16

x = 2 , y = 5

Step-by-step explanation:

Given that George bought x quarts at $3.00 per quart & y quarts at $2.00 per quart and he bought 7 quarts for $16.00

Considering the total cost

3x + 2y = 16

For the cost of each

x + y = 7

solving the 2 equations simultaneously be substitution

x = 7 - y

3(7 - y) + 2y = 16

21 - 3y + 2y = 16

-3y + 2y = 16 - 21

-y = - 5

Divide both sides by -1

y = 5

x = 7 -y

x = 7 - 5

= 2

Answer:

the answer to your question is simply

Step-by-step explanation:

4

The answer is 4

Hope this helps:)

Answer:

No solution

Step-by-step explanation:

The given equation simplifies to:

5x - 15 = -15 + 10(x + 3) - 5x, or

5x        =  10x + 30 - 5x, or

10x        =  10x + 30   NO SOLUTION!

Answer:

the Compound interest is £1,543.90

Step-by-step explanation:

The computation of the compound interest is shown below:

As we know that

Compound interest is

Amount = Principal × (1 + rate of interest)^number of years

= £1,200 × (1 + 0.032)^8

= £1,200 × 1.286582318

=  £1,543.90

hence, the Compound interest is £1,543.90

We simply applied the above formula so that the correct value could come

And, the same is to be considered

The comparision between decimal number are 1.9 = 1.90, 0.05 < 0.2, 3.88 < 6.38

Suppose that the number is abcd.efg and belongs to the decimal numerical system.

Therefore, one thing that the place on the left of decimal point is called ones. Move one-one places to right, and divide by 10 and 10 more and more.

Move one-one places to left, and multiply (un-divide) by 10 and 10 more and more.

Here we can see that

1.9 = 1.90

0.05 < 0.2

3.88 < 6.38

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Answer:

She found 19 pennies and 21 dimes

Step-by-step explanation:

Let the number of dimes present be d and the number of pennies present be p

From the question, the total of both is 40

Mathematically;

p + d = 40 •••••••(i)

While a penny worths 1 cent, a dime is worth 10 cents

Total penny amount would be 1 * p = p cents

While total dime amount would be 10 * d = 10d cents

Before we add both to give the total amount, let’s convert this total amount to cents and that would be 2.29 * 100 = 229 cents

So mathematically;

p + 10d = 229 •••••••(ii)

So let’s solve both equations simultaneously

From i) p = 40 - d

let’s put this into equation ii

40 - d + 10d = 229

40 + 9d = 229

9d = 229-40

9d = 189

d = 189/9

d = 21

Recall;

P = 40-d

P = 40-21

P = 19

Answer:

53

Step-by-step explanation:

If the diagonals of a quadrilateral divide each other proportionally, it is a trapezium.

Let's consider a quadrilateral ABCD, where the diagonals AC and BD intersect at point E. If the diagonals divide each other proportionally, it means that AE/CE = BE/DE.

To prove that the quadrilateral is a trapezium, we need to show that one pair of opposite sides is parallel.

Using the proportionality condition, we can rewrite it as (AE/CE) = (BE/DE) = 1.

By the Converse of the Basic Proportionality Theorem, we know that if two lines are cut by a transversal such that corresponding angles are equal, then the lines are parallel. In this case, AE is parallel to CD, and BE is parallel to AD.

Therefore, we have shown that AB || CD, which is the definition of a trapezium.

If the diagonals of a quadrilateral divide each other proportionally, it can be concluded that the quadrilateral is a trapezium.

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Answer: False. here is standard form; 5x − 4y = 7

Step-by-step explanation: