Answer:
He needs 0.275 cups of orange juice to reach his estimates
Step-by-step explanation:
Patel estimates he needs 2 cups of orange juice for his family . He squeezed fresh juice from 5 different oranges and got the following quantities measured in cups.
4/17 cups, 3/10 cups , 9/20 cups, 3/11 cups and 7/15 cups.
Adding them together we will know the amount he got. Therefore,
4/17 + 3/10 + 9/20 + 3/11 + 7/15
(40 + 51)/170 + 9/20 + 3/11 + 7/15
91/170 + 9/20 + (45 + 77)/165
(1820 + 1530)/3400 + 122/165
3350/3400 + 122/165
0.98529411764 + 0.73939393939
1.72468805703
Patel got approximately 1.725 cups of orange juice . He will require 2 - 1.725 = 0.275 cups of orange juice to reach his estimates.
1/2 cup of orange juice
2 2.1 Mathematical intro show that there is another form for spherical harmonics: 1 3 3 Y₁ x iy 1/√√2 (²-1) 2πT 2π 1 3 3 z YO 2 2π π r 1 3 x iy Y₁¹ 3 2π - - 12 √ √ 2² (²+²) 2 2π
Spherical harmonics are an integral part of quantum mechanics. They describe the shape of the orbitals, which electrons occupy in atoms. Moreover, the spherical harmonics provide the angular distribution of a wave in spherical coordinates. In 3D, the spherical harmonics can be written as:
Ylm(θ, φ) = √(2l + 1)/(4π) * √[(l - m)!/(l + m)!] * Plm(cosθ) * e^(imφ)
Here, l and m are known as the angular quantum numbers. They define the shape and orientation of the orbital. Plm(cosθ) represents the associated Legendre polynomial, and e^(imφ) is the exponential function. The spherical harmonics have various forms, including:
Y1,1 = -Y1,-1 = 1/2 √(3/2π) sinθe^(iφ)
Y1,0 = 1/2 √(3/π)cosθ
Y2,2 = 1/4 √(15/2π)sin²θe^(2iφ)
Y2,1 = -Y2,-1 = 1/2 √(15/2π)sinθcosφ
Y2,0 = 1/4 √(5/π)(3cos²θ-1)
Y0,0 = 1/√(4π)
The spherical harmonics have various applications in physics, including quantum mechanics, electrodynamics, and acoustics. They play a crucial role in understanding the symmetry of various systems. Hence, the spherical harmonics are an essential mathematical tool in modern physics. Thus, this is how one can show another form for spherical harmonics.
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what is the value of x that makes 2/3 to 9 and x to 36.
Answer:
Hope this helps :)
Step-by-step explanation:
2/3 to 9
x to 36
36/9 = 4
\(\frac{2}{3}*4\) = x
x = \(\frac{8}{3}\)
Select whether the equation has a solution or not.
roots
no roots
The system of equations composed by the equality in this problem does not have a solution, as the two equations do not intersect.
How to solve the system of equations?The equations that compose the system in this problem are given as follows:
\(t = \sqrt{y} - \sqrt{7}\)\(t = \sqrt{y + 7}\)We solve the system graphically, hence the solution is given by the point of intersection of the graphs of the two functions.
From the image presented at the end of the answer, the two graphs do not intersect, hence the equation does not have a solution.
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Megan, Sally and Tom share £180 in the ratio 1:3:2 how much more does Sally recieve than Megan?
Answer: Sally recieves £60 more than Megan
Step-by-step explanation:
Add the ratio together 1+3+2=6
£180 divided by 6 = 30
Megan gets 30
Sally gets 30x3=90
Tom gets 30x2=60 30:90:69
Hi can someone help me with this?Writing the algebraic equation for the phrase below.. 1. The sum of X and 96 equals half of X .
Given:
1. The sum of X and 96 equals half of X.
To determine the algebraic equation, we note that the sum of x and 96 would be:
x+96
Next, half of x must be like this:
x/2
Then, the phrase equals means we set x+96 equals to x/2.
Therefore, the answer is:
\(x+96=\frac{x}{2}\)Is $9 : 4 visitors - $18 : 8 visitors proportional
Yes, $9 for 4 visitors and $18 for 8 site visitors are proportional.
To determine whether or not $9 for 4 visitors and $18 for 8 visitors are proportional, we need to test if the ratio of the value to the number of visitors is the equal for both cases.
The ratio of cost to the quantity of visitors for $9 and four visitors is:
$9/4 visitors = $2.25/ visitors
The ratio of value to the quantity of visitors for $18 and eight visitors is:
$18/8 visitors = $2.25/ visitors
We are able to see that both ratios are equal to $2.25 per visitor.
Therefore, $9 for 4 visitors and $18 for 8 site visitors are proportional.
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A right triangle has an opposite side of 8th and an adjacent side of 6ft. What is the length of the missing side?
The length of the missing side (the hypotenuse) is 10 ft.
We have,
We can use the Pythagorean theorem to find the length of the missing side of the right triangle.
So,
a² + b² = c²
where a and b are the lengths of the legs, and c is the length of the hypotenuse.
In this case,
The opposite side (which is the leg) has a length of 8 ft, and the adjacent side (which is the other leg) has a length of 6 ft.
Let x be the length of the missing side. Then we have:
a = 8 ft
b = 6 ft
c = x
Plugging these values into the Pythagorean theorem, we get:
8² + 6² = x²
64 + 36 = x²
100 = x²
Taking the square root of both sides, we get:
x = √100 = 10 ft
Therefore,
The length of the missing side (the hypotenuse) is 10 ft.
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plz help ASP i need hyelp
Answer:
equilateral acute
Step-by-step explanation:
Answer:
Equilateral Acute Triangle
Step-by-step explanation:
I NEED HELP!! Solve the quadratic by factoring. Show your work. x² + 8 = -6x
The height of a parallelogram is 5 feet, and the area of the rectangle is 117.5 square feet. What is the length of the base of the parallelogram in feet?
The length of the base of the parallelogram is given as follows:
23.5 feet.
How to obtain the area of a parallelogram?The area of a parallelogram is obtained by the multiplication of it's base by it's height, as follows:
A = b x h.
The parameters for this problem are given as follows:
Height of h = 5.Area of A = 117.5.Hence the base length is obtained as follows:
5b = 117.5
b = 117.5/5
b = 23.5 feet.
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is their any identities like this:( a - b - c)²
PLEASE ANSWER THIS QUESTION I WILL MAKE U AS BRAINLIST JUST SAY YES OR NO
1 point If the distance from A(1, 6) to B(x, -2) is 10, then what is a possible value for x? (A) 11 (B) -5 (C) -7 (D) 8 (E) 6
Answer:
B
Step-by-step explanation:
calculate the distance between A and B using the distance formula
d = \(\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }\)
with (x₁, y₁ ) = A (1, 6 ) and (x₂, y₂ ) = B (x, - 2 )
d = \(\sqrt{(x-1)^2+(-2-6)^2}\)
= \(\sqrt{(x-1)^2+(-8)^2}\)
= \(\sqrt{(x-1)^2+64}\)
given AB = 10, then equating gives
\(\sqrt{(x-1)^2+64}\) = 10 ( square both sides to clear the radical )
(x - 1)² + 64 = 10² = 100 ( subtract 64 from both sides )
(x - 1)² = 36 ← take square root of both sides
x - 1 = ± \(\sqrt{36}\) = ± 6 ( add 1 to both sides )
x = 1 ± 6
then
x = 1 - 6 = - 5
x = 1 + 6 = 7
from the list then x = - 5 is a possible value
HELP FAST SECOND TIME POSTING❗️❗️❗️❗️The points (-1, r) and (5, -5) lie on a line with slope - 3. Find the missing coordinate r.
pls help ...................
=======================================================
Explanation:
Start by graphing the system of equations
\(\begin{cases}x-y = 6\\2x+5y = -4\\ x = -1\end{cases}\)
This is represented as the boundary lines. The first two equations produce solid boundary lines. The last equation makes a dashed boundary line. We use solid boundary lines whenever "or equal to" is involved with the inequality sign.
Note how 7 separate regions result from the intersecting lines. Check out the diagram below to see the different regions.
--------------------------
To graph \(x-y \le 6\) which is the same as \(y \ge x-6\), we will shade in regions 1, 2, 4 and 5. All of these regions are above the boundary line y = x-6
Ignore any other region (3,6, and 7) since they don't make the first inequality true.
Of regions 1, 4, 5 and 6, only regions 4 and 5 are below the boundary line 2x+5y = -4. So we cross off regions 1 and 6.
We're now down to just two regions: 4 and 5
We cross off region 5 because it is not to the right of the vertical line x = -1
All that's left is region 4. Any point in region 4 makes all of the three original inequalities true.
So the solution will only have region 4 shaded like choice D shows.
Complete the table for the given rule.
Rule: y=x/2
(X over 2)
X y
X 1
X 2.5
X 3.5
Answer y = X/2
How to complete the table using y=x/2 (X over 2) rule ?
The given function is a linear function passing through Origin.
We have to Complete the table using the given rule.
y=x/2
1.→ 1= x/2
x=2
2.→ 2.5=x/2
x=5
3.→2=3.5=x/2
x=7
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Convert this rational number
to its decimal form and round
to the nearest thousandth.
Answer:
.857
Step-by-step explanation:
6/7 = about .8571
rounded to thousandth is .857
Find the equation of the line through point (-7,2) and parallel to y=2/5x-1/2
Answer:
y = 2/5x + 24/5
*View graph to see the lines*
Step-by-step explanation:
y = 2/5x - 1/2
Parrel lines have the same slope
y = mx + b
y = 2/5x + b
2 = 2/5(-7) + b
2 = -14/5 +b
5(2 = -14/5 +b)
10 = -14 + 5b
+14 +14
24 = 5b
/5 /5
24/5 = b
y = 2/5x + 24/5
Hope this helps!
Answer:
y = 2/5x + 24/5
Step-by-step explanation:
What is the slope of the line represented by the equation y=4/5x - 3?
A).-3
B).-4/5
C).4/5
D).3
The equation y = (4/5)x - 3 is in slope-intercept form, y = mx + b, where m is the slope of the line. Therefore, the slope of the line represented by the equation is:
m = 4/5
So the answer is C) 4/5.
very fast
Show, by induction, that \( T(n)=10 n^{2}-3 n \quad \) if \( n=1 \)
Given that \(\(T(n)\) = \(10n^2-3n\)\) if (\(\(n=1\)\)), you have to prove it by induction. So, we have proved it by induction that \($$\(T(n)=10n^2-3n\)$$\) if ( n= 1). The given statement is true for all positive integers n
Let's do it below: The base case (n=1) is given as follows: \(T(1)\) =\(10\cdot 1^2-3\cdot 1\\&\)=\(7\end{aligned}$$\). This implies that \(\(T(1)\)\) holds true for the base case.
Now, let's assume that \(\(T(k)=10k^2-3k\)\) holds true for some arbitrary \(\(k\geq 1\).\)
Thus, for n=k+1, T(k+1) = \(10(k+1)^2-3(k+1)\\&\) = \(10(k^2+2k+1)-3k-3\\&\)=\(10k^2+20k+7k+7\\&\) = \(10k^2-3k+20k+7k+7\\&\) = \(T(k)+23k+7\\&\) = \((10k^2-3k)+23k+7\\&\) = \(10(k+1)^2-3(k+1)\).
Therefore, we have proved that the statement holds true for n=k+1 as well. Hence, we have proved it by induction that \($$\(T(n)=10n^2-3n\)$$\) if (n=1). Therefore, the given statement is true for all positive integers n.
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the radius of a sphere increases at a rate of 1 m/sec. find the rate at which the volume increases when the radius is 20 m.
We need to know about rate of change to solve the problem. The rate of change of volume of the sphere is 5026.55 sq/m.
Rate of change of a quantity is the rate at which it increases or decreases. It is given that the radius of the sphere increases at a rate of 1m/second. We need to find out the rate of change of volume of the sphere given the radius is 20m. We can calculate the rate of change of volume by calculating the derivative of volume with respect to time.
V=4/3\(\pi r^{3}\)
dV/dt=4\(\pi r^{2}\) dr/dt =4 x \(\pi\)x20x20x1=5026.55 sq m/ second
Therefore the volume of the sphere increases at a rate of 5026.55 sq/m.
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Five integers have an average of 6969. The middle integer (the median) is 8383. The most frequently occurring integer (the mode) is 8585. The range of the five integers is 7070. What is the second smallest of the five integers
The second smallest integer is given as follows:
x2 = 77.
How to obtain the second number?The numbers are given as follows:
x1, x2, x3, x4, x5.
The median is of 83, hence x3 = 83 and the integers are:
x1, x2, 83, x4, x5.
The mode is of 85, hence x4 = x5 = 85, thus:
x1, x2, 83, 85, 85.
The range is of 70, hence:
x5 - x1 = 70
85 - x1 = 70
x1 = 15.
Hence:
15, x2, 83, 85, 85.
The mean is of 69, hence:
(15 + x2 + 83 + 85 + 85)/5 = 69
268 + x2 = 345
x2 = 345 - 268
x2 = 77.
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Solve each system.
[x-3 y =-1 -6 x+19 y =6 ]
The system of equations [x - 3y = -1 and -6x + 19y = 6] can be solved, resulting in x = -1 and y = 0.
To solve the system of equations [x - 3y = -1 and -6x + 19y = 6], we can use the method of substitution or elimination.
Let's solve it using the method of elimination.
First, we can multiply the first equation by 6 and the second equation by -1 to eliminate the x terms.
This gives us [6x - 18y = -6 and 6x - 19y = -6].
Now, subtracting the first equation from the second eliminates the x terms, leaving us with -y = 0. Solving for y, we find y = 0.
Substituting this value back into the first equation, we get x - 3(0) = -1, which simplifies to x = -1.
Therefore, the solution to the system of equations is x = -1 and y = 0.
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Bob is interested in examining the relationship between the number of bedrooms in a home and its selling price. After downloading a valid data set from the internet, he calculates the correlation. The correlation value he calculates is only 0.05What does Bob conclude? A)Bob gives up on his research becauser=.05 means there is no relationship of any kind between bedrooms and selling price. B) Bob continues his research because even though there is no linear relationship here, there could be a different relationship.
Bob continues his research because even though there is no linear equation relationship between the number of bedrooms and selling price, there could be another type of relationship.
Bob continues his research because even though the correlation value he calculated between the number of bedrooms and the selling price was only 0.05, this does not necessarily mean that there is no relationship of any kind between these two variables. It simply means that there is no linear relationship between the two. There could still be other types of relationships between the two variables, such as an exponential or quadratic relationship. It is possible that further analysis and exploration of the data set would reveal such a relationship and allow Bob to uncover the relationship between the two variables. Additionally, even if the correlation value is low, it does not necessarily mean that there is no relationship between the two variables. It simply means that the relationship is weak. Therefore, Bob should continue his research in order to uncover any potential relationships between the number of bedrooms and selling price.
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The five values for a data set are: minimum = 0 lower quartile = 2 median = 3. 5 upper quartile = 5 maximum = 10 Bruno created the box plot using the five values. What error did he make? The right whisker should go from 3. 5 to 10. The left whisker should go from 0 to 2. The box should go from 2 to 3. 5. The box should go from 3. 5 to 5
The five values for a data set are: minimum = 0 lower quartile = 2 median = 3. 5 upper quartile = 5 maximum = 10 Bruno created the box plot using the five values. Bruno made error. The left whisker should go from 0 to 2.
About quartileQuartiles is a type of quartile that divides data into four parts with approximately the same number. The first quartile or lower quartile (Q1) is the middle value between the smallest value and the median of the data group. The first quartile is a marker that the data in that quartile is 25% below the data group.
The second quartile (Q2) is the median data which marks 50% of the data (dividing the data in half). The third or upper quartile (Q3) is the middle value between the median and the highest value of the data set. The third quartile is a marker that the data in that quartile is 75% below the data group. Quartiles are a form of an ordered statistic because to determine quartiles, data needs to be sorted from smallest to largest value first.
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1
What is the range of the following numbers?
12, 20, 18, 25,6
Find the area of the shaded region.
Answer:
1 ) 264m^2
2) 2888cm^2
Step-by-step explanation:
22×16=352
8×11=88
352-88=264m^2
76×76=5776
5776÷2=2888cm^2
What is the greatest common factor of 3x^43x 4 3, x, start superscript, 4, end superscript, 15x^315x 3 15, x, cubed, and 21x^221x 2 21, x, squared?
Answer:
3x²Step-by-step explanation:
Given three functions 3x⁴, 15x³and 21x², the greatest common factor is the greatest value that can divide through the three functions at the same time.
To get this GCF, let us divide each functions into simplest form
3x⁴ = (3 *x * x) * x * x
15x³ = 5 * (3 * x * x) * x
21x² = 7 * (3 * x * x)
It can be seen that the product in parenthesis is common to the three functions given on expanding them, hence the greatest common factor of the three functions is 3 * x * x = 3x²
in a bacteria growing experiment, a biologist observes that the number of bacteria in a certain culture triples every 4 hourse. after 12 hours, it is estimated that there are 1 million bacteria in the culture. what is the doubling time for the population?
The bacteria's population increases exponentially, and its equation is
P(t) = P\(_{0}\)e\(^{kt}\)
Where,
P\(_{o}\) is the initial population t is the number of hours.
k is the growth rate.
It is given that the population of the bacteria after one hour triples itself. i.e
P(1)=3P\(_{o}\)
3P\(_{o}\)=Pe\(k^{(l)}\)
3=e\(^{k}\)
In 3 = In e\(^{k}\)
In 3=k ln e
In 3 = k(1)
k = ln (3)
Thus, the rate of growth is k= ln (3)
Substitute k = ln (3) in the equation P(t) = P\(_{o}\)e\(^{kt}\).
P(t) = P\(_{o}\)e\(tln^{(3)}\)
It is given that there are 1 million bacteria after 5 hours. i.e. P(5)=10,00,000
P(5) = P\(_{o}\)e\(^{(5)} ln^{(3)}\)
10,00,000 Pe\(^{(5)}ln^{(3)}\)
10,00,000 = P\(_{o}\)e\(ln^{(3)^{5} }\)
10,00,000 = P\(_{o}\)\((3)^{5}\)
P\(_{o}\) = 10,00,000 / \(3^{5}\)
P\(_{o}\) = 10,00,000 / 243
Thus, the formula for any t is P(t) = (10,00,000 / 243) e\(ln^{(3)^{t} }\)
Find the doubling time for the bacteria population.
Let X= 10,00,000 / 243 then the equation for the doubling time for the bacteria is
2X = Xe\(ln^{(3)t\)
2 = e\(ln^{(3)t}\)
t= ln (2) / ln (3) ≈ 0.63094 hours
Or t=37.8564 minutes.
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After solving a series of mathematical problems using a complicated formula, Mark uses the same formula to solve another problem he could have solved using a much simpler formula. Mark's continued reliance on the complicated formula BEST illustrates:
Answer:
C. mental set
Step-by-step explanation:
A mental set generally refers to the brain's tendency to stick with the most familiar solution to a problem and stubbornly ignore alternatives. This tendency is likely driven by previous knowledge (the long-term mental set) or is a temporary by-product of procedural learning (the short-term mental set).
Computing equipment is bought from a supplier. The cost of 5 Computers and 4 Printers is £6,600, the cost of 4 Computers and 5 Printers is £6,000. Form two simultaneous equations and solve them to find the costs of a Computer and a Printer. A used Car salesperson can be paid using two methods of commission. METHOD X uses straight commission 3.5% of the selling price of all vehicles sold. METHOD Y uses a fixed amount of £250 per week plus commission of 1.5% of the selling price of all vehicles sold. If the total selling price of the Cars sold in each week is on average £20,000, calculate which of the two methods of commission the salesperson would prefer.
The cost of one computer is £600 and the cost of one printer is £800.
Computing equipment is bought from a supplier. The cost of 5 Computers and 4 Printers is £6,600, and the cost of 4 Computers and 5 Printers is £6,000. Form two simultaneous equations and solve them to find the costs of a Computer and a Printer.
Let the cost of a computer be x and the cost of a printer be y.
Then, the two simultaneous equations are:5x + 4y = 6600 ---------------------- (1)
4x + 5y = 6000 ---------------------- (2)
Solving equations (1) and (2) simultaneously:x = 600y = 800
Therefore, the cost of a computer is £600 and the cost of a printer is £800..
:Therefore, the cost of one computer is £600 and the cost of one printer is £800.
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