Part (b)A cassette recorder uses a plug-in transformer to convert 120 V to 12.0 V, with a maximum current output of 355 mA. (b) What is the power input (in W)?

The traffic cop needs 23.3 seconds to pass the automobile.

When your velocity (not speed) changes, you are accelerating. A automobile moving at a steady 100 km/h in a straight line has no acceleration. Average acceleration is equal to (change in velocity) / (duration). The car's acceleration is zero because its change in velocity is also zero.

\(d1 = v1*t1 = 35.0 m/s * 1 s = 35.0 m\)

\(d = d1 = 35.0 m\)

\(d2 = v2*t + (1/2)at^2\)

\(d2 = (1/2)at^2\)

\(v2*t + (1/2)at^2 = (1/2)at^2\)

\(v2*t = (1/2)at^2\)

Solving for t, we get:

\(t = (2v2/a) = (235.0 m/s)/3.0 m/s^2 = 23.3 s\) (rounded to 2 decimal places)

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The mass of the Ball B is 1.35 x 10⁻⁶ kg.

Gravitational Force is described by Newton's law of universal gravitation, which states that the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

The law of universal gravitation is important in many fields, including astronomy, physics, and engineering.

The gravitational force F between two objects of masses m1 and m2 separated by a distance r is given by:

F = G(m₁m₂)/r²

where G is the gravitational constant.

We can rearrange the equation to solve for the mass of Ball B:

m₂ = Fr²/Gm₁

Substituting the given values, we get:

m₂ = (8.7 x 10⁻¹⁰ N)(3.0 m)²/(6.6743 x 10¹¹ N(m^2/kg²))(30 N)

m₂ = 1.35 x 10⁻⁶ kg

Therefore, the mass of Ball B is approximately 1.35 x 10⁻⁶kg.

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Answer:yeah it A

Explanation:

Answer:

Pretty sure it’s A

Explanation:

Would ike brainliest

Knowing the exits are exactly 7 km apart, the cars pass each other at 9:29 and 15 seconds a.m.

The relative velocity of the cars is 30 m/s - 26 m/s = 4 m/s.

The distance between the cars is 7 km = 7000 m.

The time it takes for the cars to pass each other is 7000 m / 4 m/s = 1750 seconds.

1750 seconds is 29 minutes and 15 seconds.

To calculate the time in minutes;

Let:

v_p = the speed of car P (m/s)

v_q = the speed of car Q (m/s)

d = the distance between the cars (m)

t = the time it takes for the cars to pass each other (s)

Given that:

v_p = 30 m/s

v_q = 26 m/s

d = 7000 m

Use the equation for relative velocity to find the velocity of the cars relative to each other:

v_r = v_p - v_q

v_r = 30 m/s - 26 m/s = 4 m/s

Use the equation for distance to find the time it takes for the cars to pass each other:

d = v_r × t

7000 m = 4 m/s × t

t = 7000 m / 4 m/s = 1750 s

Convert 1750 seconds to minutes and seconds:

1750 s = 29 minutes and 15 seconds

Therefore, the cars pass each other at 9:29 and 15 seconds a.m.

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Answer:

B. They do not provide explanations for why they are true.

C. They are considered to be proven facts.

Explanation:

edge 2021

The statements describe scientific laws but not theories or hypotheses are they do not provide explanations for why they are true and they are considered to be proven facts.

The law given by the experimenters or scientists after years of observations and experiments based on the scientific reasons are called scientific laws.

The laws are not the proven facts. They even don't explain why the scientific laws are true.

Thus, the correct option is B and C.

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Explanation:

Let's set the x-axis to be parallel to the and positive up the plane. Likewise, the y-axis will be positive upwards and perpendicular to the plane. As the problem stated, we are going to assume that m1 will move downwards so its acceleration is negative while m2 moves up so its acceleration is positive. There are two weight components pointing down the plane, \(m_1g \sin \theta\) and \(m_2g \sin \theta\) and two others pointing up the plane, the two tensions T along the strings. There is a normal force N pointing up from the plane and two pointing down, \(m_1g \sin \theta\) and \(m_2g \sin \theta\). Now let's apply Newton's 2nd law to this problem:

x-axis:

\(m1:\:\:\:\displaystyle \sum_i F_i = T - m_1g \sin \theta = - m_1a\:\:\:\:(1)\)

\(m2:\:\:\:\displaystyle \sum_i F_i = T - m_2g \sin \theta = m_2a\:\:\:\:(2)\)

y-axis:

\(\:\:\:\displaystyle \sum_i F_i = N - m_1g \cos \theta - m_2g \cos \theta = 0\)

Use Eqn 1 to solve for T,

\(T = m_1(g \sin \theta - a)\)

Substitute this expression for T into Eqn 2,

\(m_1g \sin \theta - m_1a - m_2g \sin \theta = m_2a\)

Collecting all similar terms, we get

\((m_1 + m_2)a = (m_1 - m_2)g \sin \theta\)

or

\(a = \left(\dfrac{m_1 - m_2}{m_1 + m_2} \right)g \sin \theta\)

We will have the following:

Then, we from the work-kinetic force theorem we will have that the total kinetic energy gained by the rocket was 200 Joules.

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

    \(v_y =  5.14 \  m/s\)

b

\(\Delta t = 0.5248 \ s \)

Explanation:

From the question we are told that

The maximum height is H = 2.70

The Range is R = 12.9 m

Generally from projectile motion we have that

\(Range = \frac{ u^2 sin2(\theta)}{g}\)

\(12.9 = \frac{ u^2 sin2(\theta)}{g}\)

Generally from trigonometric identity

\(sin 2(\theta) = 2sin (\theta) cos(\theta)\)

So

\(12.9 = \frac{ u^2 2sin(\theta) cos(\theta)}{g}\)

=> \(u^2 * 2sin(\theta) cos(\theta) = 12.9 * g\)

\(u^2 * 2sin(\theta) cos(\theta) = 12.9 * 9.8\)

\(u^2 *2sin(\theta) cos(\theta) = 126.42 \ \cdots (1)\)

Also the maximum height is

\(H = \frac{u^2 sin^2 (\theta)}{2g}\)

=> \(2.70 = \frac{u^2 sin^2 (\theta)}{2g}\)

=> \(u^2 sin^2 (\theta) = 2.70 * 2 * g\)

=> \(u^2 sin^2 (\theta) = 2.70 * 2 * 9.8\)

=> \(u^2 sin^2 (\theta) = 52.92\cdots (2)\)

Dividing equation 2 by (1)

\(\frac{u^2 sin^2 (\theta)}{u^2 *2sin(\theta) cos(\theta)} =\frac{52.92}{126.42 }\)

=> \(tan(\theta ) = \frac{52.92}{126.42 }\)

=> \(\theta = tan^{-1} [0.4186]\)

=> \(\theta =22.71^o \)

So

From equation 1

\(u^2 *2sin(22.71) cos(22.71) = 126.42 \ \cdots (1)\)

=> \(u = 13.322 \ m/s\)

Generally the vertical component of the initial velocity is mathematically evaluated as

\(v_y = usin (\theta)\)

=> \(v_y = 13.322 * sin (22.71)\)

=> \(v_y = 5.14 \ m/s\)

Generally the time taken is mathematically represented as

\(\Delta t = \frac{u sin (\theta )}{g}\)

=>      \(\Delta t =  \frac{13.322 sin (22.71 )}{9.8}\)

=> \(\Delta t = 0.5248 \ s \)

The total charge in the circuit is 240 microcoulombs.

To calculate the total charge in a series circuit with capacitors, we need to use the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage.

In this case, we have three capacitors connected in series with capacitances of 4 μF, 3 μF, and 2 μF, respectively. The voltage across the circuit is 260 V.

To find the total capacitance (C_total) in a series circuit, we use the reciprocal rule: 1/C_total = 1/C1 + 1/C2 + 1/C3. Plugging in the values, we get 1/C_total = 1/4 + 1/3 + 1/2.

Simplifying this equation gives us 1/C_total = (3 + 4 + 6)/12 = 13/12. Taking the reciprocal, we find C_total = 12/13 μF.

Now, we can calculate the total charge (Q_total) using Q = C_total × V. Substituting the values, we get Q_total = (12/13) μF × 260 V.

Calculating the numerical value, Q_total = (12/13) × 260 = 240 μC (microcoulombs).
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Answer:

The atomic nucleus is the small, dense region consisting of protons and [[]]s at the center of an atom

Explanation:

The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.

The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.

To calculate the time interval, we can use the following formula:

time = distance / speed

where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.

distance = 2 x 300m = 600m

speed = 343 m/s

time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)

Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

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Answer:

b. throw it against a net i think

Answer:

There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.

Reaction Total Number of Molecules

 Reactant Side (left) Product Side (right)

Make Ammonia  4  2

Separate Water  2  3

Combust Methane  3  3

No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.

Reaction Total Number of Atoms

 Reactant Side (left) Product Side (right)

Make Ammonia  1C, 4H, 4O  1 C, 4H, 4O

Separate Water  2H, 4O  2H, 4O

Combust Methane  2N, 6H  2N, 6H

Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.

Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.

No, you could not use a non-integer number.

Explanation:

PF

Answer: There are three different ways that the equation is represented visually when it is balanced. First, the scale is at equilibrium when it is balanced. The balance turns yellow and a smiley face appears. Second, the graph shows equal amounts on both the reactant and product side of the equation. Third, within the individual molecule box, there should be the same number of each element on both the product and a reactant side of the equation.

Reaction Total Number of Molecules

 Reactant Side (left) Product Side (right)

Make Ammonia  4  2

Separate Water  2  3

Combust Methane  3  3

No, the number of total molecules on the left side of a balanced equation is not equal to the number of total molecules on the right side of the equation. A molecule is the smallest number of atoms bonded together for a chemical reaction. The total number of atoms must be the same, but not molecules. The reactants and products will bond together in different ways leading to different numbers of reactants and products.

Reaction Total Number of Atoms

 Reactant Side (left) Product Side (right)

Make Ammonia  1C, 4H, 4O  1 C, 4H, 4O

Separate Water  2H, 4O  2H, 4O

Combust Methane  2N, 6H  2N, 6H

Yes, in order for the equation to be correct, the total number of atoms on the left side of the balanced equation must always equal the total number of atoms on the right side of the balanced equation.

Answers to this question vary. A good answer could say start with the chemical with the smallest amount on each side of the equation and balance that. Alternatively, you could start with the largest and balance that first. You also could say that you examined the visual representation in the reactant and product box to see if there was an equal number of atoms. Sometimes, it does require trial and error to get an equal number of atoms on each side of the equation. You could also use math concepts such as greatest common factors to use the smallest number possible of each molecule.

No, you could not use a non-integer number.

At the critical temperatures of the substance, the substance can't lose any more thermal energy. Hence, option B is correct.

At the critical temperature, the properties of the liquid and gas phases become difficult to differentiate, and the substance exhibits particular type of behavior such as infinite compressibility and a lack of surface tension.

Additionally, at the critical temperature, the substance reaches its maximum vapor pressure, and any further increase in temperature and pressure will not cause it to change its state but only its density and hence, it cannot lose any more thermal energy from itself.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

The concentration of mole evil at oxygen on that day is 0.00858 mol/L

Explanation:

Here, we want to calculate the concentration of molecular oxygen

The pressure on that day is 1.0 atm

Since oxygen is at a concentration of 21%, the pressure of oxygen will be 21/100 * 1 = 0.21 atm

Now let’s calculate the concentration;

From Ideal gas law;

PV = nRT

This can be written as;

P/RT = n/V

The term n/V refers to concentration;

Let’s make substitutions now;

P = pressure = 0.21 atm

R = molar gas constant = 0.0821 L•atm/mol•k

T = temperature = 25 = 25 + 273.15 = 298.15 K

Substituting these values, we have;

n/V = C = 0.21/(0.0821 * 298.15) = 0.00858 mol/L

The frequency of a note two octaves lower than note A (the one right above the center of the piano keyboard) is 110 Hz (the so-called A-440).

The frequency of a repeated event is the number of occurrences per unit of time. It is separate from angular frequency and is sometimes referred to as temporal frequency. The unit of frequency is hertz, which equals one occurrence every second. The number of waves that travel through a particular point in a given length of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second. The frequency is 100 per hour if it takes 1/100 of an hour. Frequency is a measurement of how frequently a recurrent event, such as a wave, happens in a certain period of time. A cycle is one completion of the repeating pattern.

Here,

The frequency of a note two octaves lower than note A (the one just above the middle of the piano keyboard) has a frequency of 440 Hz (the so-called A-440) is 110 Hz.

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The density (ρ) of the chunk of metal is, approximately, 7,213.74 kg/m³.

First of all, let's define the word density in physics.

Density is a value that represents how much mass of a given substance can be contained in a determined volume. This value changes for each element or mix of elements from the periodic table and can be used to identify some of them.

The formula for density is the following;

\(D=\frac{m}{V}\); where "m" is the given mass of the substance, and "V" is the volume that the given mass occupies in space.

Side note. Density is typically represented by the greek letter ρ (rho). The most common used units for density are:

• Kilograms/cubic meters (kg/m³);
• Grams/cubic centimeters (g/cm³);
• Pounds/cubic feet (lb/ft³).

So we already know that density only requires 2 values to be calculated, mass and volume, and the problem already provides that information, therefore:

\(m=945(kg)\\ \\V=0.131(m^{3} )\)

\(D=\frac{m}{V} =\frac{945(kg)}{0.131(m^{3} )} =7213.7405(\frac{kg}{m^{3} } )\)

The density (ρ) of the chunk of metal is, approximately, 7,213.74 kg/m³.

This means that 1 cubic meter of this substance has a mass of 7,213.74 kg.

This is an exercise in density, a physical property of matter that is defined as mass per unit volume. It is an important property to identify and characterize different materials, since it varies depending on the type of substance and the conditions in which it is found.

Density is expressed mathematically as mass divided by volume, which gives us a measure of the amount of matter present in a given space. This property is very useful for identifying and classifying different types of substances, from solids to liquids and gases.

In general, solids have a higher density than liquids and gases, due to the way the particles are arranged and the force with which they interact with each other. For example, iron has a greater density than water, which means that an equal amount of iron will have a greater mass than the same amount of water.

Density is important in everyday life, as it is used to measure the concentration of substances in solutions or mixtures. For example, the density of pure water is 1 gram per cubic centimeter (1 g/cm³), while the density of ethyl alcohol is 0.789 g/cm³. If we mix a quantity of water with a quantity of alcohol, the density of the resulting mixture will be a combination of both densities, which will allow us to determine the concentration of alcohol in the mixture.

Density is an important property in geology, where it is used to identify and classify different types of rocks and minerals. For example, sedimentary rocks often have a lower density than igneous or metamorphic rocks, due to the way they formed and the materials they are made of.

In engineering, density is important for the design of structures and materials that must support loads and efforts. For example, the materials used in the construction of bridges or buildings must have an adequate density to support the weight of the structure and the forces to which it will be subjected.

Density is also important in physics and chemistry, where it is used to calculate the mass and volume of substances, as well as to determine the concentration of solutions and mixtures. In physics, density is an important property for understanding fluid behavior, acoustics, and thermodynamics.

It tells us that the metal has a volume of 0.131 m³ and has a mass of 945 kg, and we are asked to calculate its density.

D = m/v

Where

Mass is measured in kilograms (kg).

The volume in cubic meters (m^3).

Density is measured in kg/m^3.

D = m/v

D = (945 kg)/(0.131 m³)

D ≈ 7213.74 kg/m³

Therefore, the density of the piece of metal is approximately 7213.74 kg/m³.

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Answer:

5

Explanation:

when you move 3 unit to the right your object is at 3.then when you move 4 units to the left your object is at -1 because

a number line also has negative numbers.Then if you move 6 units your object is at 5

Because they used cutting-edge tools and technology to strengthen the signal and increase the range, the Swedish Space Agency was able to transmit a wifi signal over such a long area.

With a 2.4GHz frequency, Wi-Fi transmissions typically have a range of over 45 metres, or roughly 150 feet. You will have a reach of approximately 15 metres or 50 feet when using a 5Ghz frequency.

802.11g - Indoor effective ranges of 100–150 feet at 54 Mbps wireless throughput using a 2.4GHz transmission frequency. 802.11g and 802.11b can communicate at 11 Mbps.

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Given data:

* The final velocity of the ball is 0m/s.

* The acceleration of the ball is,

* The time taken by the ball is 8 s.

Solution:

By the kinematics equation, the initial velocity of the ball in terms of the final velocity, acceleration, and the time taken is,

where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken,

Substituting the known values,

Thus, the initial velocity of the ball is 3.2 m/s.

Hence, option D is the correct answer.

To design an approximate voltage source from a current source, we can use Ohm's law. The short-circuit current IN = infinity and parallel resistance RN = R.

The open-circuit voltage should be 5.0 volts, so we can calculate the resistance needed to maintain that voltage as: R = V / I, where V is the open-circuit voltage, I is the current, and R is the resistance. The resistance should be no lower than 4.9 volts when a 100 load is attached, so the current through the resistance should be: I = V / R = 4.9 / R. To determine the short-circuit current IN, we can set the resistance to zero, resulting in IN = 5.0 / 0 = infinity. The parallel resistance RN can be calculated as: RN = R || (1 / (1 / 100) + 1 / R) = R.

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Answer:

B porque tiene energía n..

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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First, we need to know how much time it takes to hit the bull's eye :

h = 1/2 • g • t²

(0.09 m) = ½ (9.81 m/s²) t²

t = 0.135 s

Then, we will know the distance between the rifle and the bull's eye :

X = v • t

X = (700 m/s)(0.135 s)

X = 94.5 m

Hi there!

We can begin by solving for the time taken for the bullet to travel a VERTICAL distance of 0.09 m due to the effects of gravity.

We can use the kinematic equation for uniform acceleration:

\(d_y = v_{0y}t + \frac{1}{2}at^2\)

Since there is no initial vertical velocity:

\(d_y = \frac{1}{2}at^2\)

Rearrange to solve for time. (a = g = 9.8 m/s²)

\(t = \sqrt{\frac{2d}{g}}\)

\(t = \sqrt{\frac{2(0.09)}{9.8}} = 0.136 s\)

Now, we can use the distance, speed, and time equation in the horizontal direction:

\(d_x = v_xt\)

Plug in the values:

\(d_x = 700(0.136) = \boxed{94.89 m}\)

7.1 The reading on V₁ is 0 V.

7.2 The total resistance of the circuit is 6 Ω.

The reading on V₁ is zero because the two cells are connected in parallel. When cells are connected in parallel, the voltage across each cell is the same. In this case, the voltage across each cell is 3 V. Therefore, the reading on V₁ is 0 V.

The total resistance of the circuit is given by the following equation:

R_T = R₁ + R₂

where:

R_T is the total resistance of the circuit in ohms

R₁ is the resistance of the first resistor in ohms

R₂ is the resistance of the second resistor in ohms

In this case:

R_T = ?

R₁ = 2 Ω

R₂ = 4 Ω

Substituting these values into the equation:

R_T = 2 Ω + 4 Ω

R_T = 6 Ω

Therefore, the total resistance of the circuit is 6 Ω.

Find out more on total resistance here: https://brainly.com/question/1851624

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