Part 3 - Discussion/Explanation Question
In what ways can vertical, horizontal, and
oblique asymptotes be identified? Use a
mathematical example to
explain the ways.

100 points
Thank you so much

Answer:

Adult-. $4

Student-. $2.50

Step-by-step explanation:

equation

1a + 3s = $11.50

3a + 2s = $17.00

$4+$2.50(3)=$11.50

$12+$2.50(2)=$17.00

or

1($4)+3($2.50)=$11.50

3($4)+2($2.50)=$17.00

sorry if this is a little confusing, this is a simpler equation-

$4.00+($2.50x3)=$11.50

($4.00x3)+($2.50x2)=$17.00

Answer:

c

Step-by-step explanation:

Answer:

A 4/5

Step-by-step explanation:

Cosine of an angle is the adjacent side over the hypotenuse. Sin A = 36/45 = 4/5.

Hope this Helps :)

Carrying value on June 30, 2024  is $176 million, total  Interest revenue  is $12.44 million

To calculate the interest revenue for the first six months, we need to find the carrying value of the bonds on June 30, 2024.

The carrying value is the purchase price plus the accrued interest, which is calculated as follows:

Accrued interest = Face value x Coupon rate x Time

where Time = 6/12 = 0.5 (since interest is paid semiannually)

Accrued interest = $200 million x 6% x 0.5 = $6 million

Carrying value on June 30, 2024 = Purchase price + Accrued interest

= $170 million + $6 million

= $176 million

The interest revenue for the first six months is calculated as follows:

Interest revenue = Carrying value x Market rate x Time

= $176 million x 8% x 0.5

= $7.04 million

For the second six months, the carrying value is the fair value of $180 million, since the bonds were revalued at December 31, 2024.

The interest revenue for the second six months is calculated as follows:

Interest revenue = Carrying value x Coupon rate x Time

= $180 million x 6% x 0.5

= $5.4 million

Total interest revenue = Interest revenue for first six months + Interest revenue for second six months

= $7.04 million + $5.4 million

= $12.44 million

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The probability that the random sample of 100 male students has a mean gpa greater than 3. 42 is 0.9452.

A statistic known as the standard deviation is used to describe how volatile or dispersed a group of numerical values is. While a big standard deviation denotes that the values are scattered across a wider range, a low standard deviation indicates that the values tend to be close to the set mean.

From the given information, a scores random sample of 100 male students is selected and the GPA for each student is calculated which follows approximately normal with a mean of 3.5 and standard deviation of 0.5. That is,

µ = 3. 5 and σ = 0. 5

and the random sample of 100 male students has a mean GPA 3.42 is considered.

The z-score value is,

Z=( 3.42-3.5)/ (0.5/√100)

Z= -0.08/0.05

Z=-1.6

The value of z-score is obtained by taking the difference of x and µ. Then the resulting value is divided with the standard deviation by sample size.

The probability that the random sample of 100 male students has a mean GPA greater than 3.42 is obtained below:

The required probability is,

P(X>3.42)=P(z>-1.6)

= 1- P(Z≤-1.6)

From the “standard normal table”, the area to the left of Z=-1.6 is 0.0548.

P(X>3.42)= 1- P(Z≤-1.6)

=1-0.0548

=0.9452

The probability that the random sample of 100 male students has a mean GPA greater than 3.42 is 0.9452.

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Answer:

sweefe

Step-by-step explanation:

EFEFEEa

Answer:

Step-by-step explanation:

.40m + 80 = .80m + 20

-.40m + 80 = 20

-.40m = -60

m = 150 miles in a day

Answer:

https://www.chegg.com/homework-help/questions-and-answers/questions-23-29-use-following-information-answer-question-recent-book-noted-20-investment--q13619465

Step-by-step explanation:

this might help you

Answer:

x=2

y=3

Step-by-step explanation:

y=−2x+7

y=5x−7

Set the two equations equal since they are both equal to y

−2x+7 =5x−7

Add 2x to each side

-2x+7+2x = 5x-7+2x

7 = 7x-7

Add 7 to each side

7+7 = 7x-7+7

14 =7x

Divide by 7

14/7 = 7x/7

2 =x

Now find 7

y = 5x-7

y = 5(2) -7

y = 10-7

y = 3

Given that y=y=y,

→ -2x+7 = 5x-7

Let's find the value,

→ -2x+7 = 5x-7

→ 7 = 5x+2x-7

→ 7 = 7x-7

→ 7+7=7x

→ 14 = 7x

→ x = 14/7

→ [x = 2]

Then we can find 7,

→ y = 5x-7

→ y = 5(2) -7 y = 10-7

→ [y = 3]

This is required answer.

The independent variable in this data is the speed of the car. This is because the congressman is trying to determine whether or not the gas mileage improves at lower speeds.

The dependent variable is the gas mileage, because it is the variable that is being measured and that is affected by the independent variable.

The other variables in this data are the weight of the car, the type of engine, and the year of the car. However, these variables are not being changed in this experiment, so they are not considered to be independent variables.

The data shows that the gas mileage of the Toyota Camry improves as the speed of the car decreases. This supports the claim of the supporters of the bill to reduce the speed limit.

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Answer:

0.731353701619170483287543608275622403378...

Step-by-step explanation:

cos((43 π)/180)

UwU

It's verified you can trust

Is what you needed

Answer:

99.9453% of matter in the ore is neither diamond or copper

Step-by-step explanation:

First add  0.0297 and 0.025

0.0297+0.025=0.0547

Now subtract 0.0547 from 100

100-0.0547=99.9453

99.9453% of matter in the ore is neither diamond or copper

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Answer:

1. 90

2. 61

3. 29

4. 61

Step-by-step explanation:

1 is a 90 degree angle. Triangles = 180 degrees

Answer:

21 cases

Step-by-step explanation:

red cases=2x.    white cases=x

2x+x=81

3x=81

x=21 cases

Answer:

1 - 100 primes numbers

Step-by-step explanation:

2,3,5,7,11,13,17,19,23,29,31,37,41,47,57,59,61,67,71,79,83,8797

At \($5 \mathrm{pm}$\) the distance between the ships is changing at the speed of \($\mathbf{3 0 . 2 1}$\) knots

Firstly we need to an equation to represent both ships and the distance between each. A is moving \($25 \mathrm{knots}$\) west and \($B$\) is moving \($17 \mathrm{knot}$\) north. \($D$\)will be the distance between the two. Drawing it, you'll notice that it creates a right triangle.

So we use the Pythagorean Theorem:

\($$D^{\wedge} 2=A^{\wedge} 2+B^{\wedge} 2$$\)

Differentiate in relation to time:

\($$2 \mathrm{D}(\mathrm{dD} / \mathrm{dt})=2 \mathrm{~A}(\mathrm{dA} / \mathrm{dt})+2 \mathrm{~B}(\mathrm{~dB} / \mathrm{dt})$$\)

Now we must find all of our variables.

\(& A=\text { time(speed })+\text { original distance }=5(25)+10=135 \\\)

\(& B=5(17)+0=85 \\\)

\(& D=V\left(A^{\wedge} 2+B^{\wedge} 2\right)=159.53 \\\)

\(& d A / d t=25 \\\)

\(& d B / d t=17\)

Plug in all your variables and solve for

\($(\mathrm{dD} / \mathrm{dt})$ :\)

\(& 2 \mathrm{D}(\mathrm{dD} / \mathrm{dt})=2 \mathrm{~A}(\mathrm{dA} / \mathrm{dt})+2 \mathrm{~B}(\mathrm{~dB} / \mathrm{dt}) \\\)

\(& 2(159.53)(\mathrm{dD} / \mathrm{dt})=2(135)(25)+2(85)(17) \\\)

\(& 319.061(\mathrm{dD} / \mathrm{dt})=9640 \\\)

\(& \mathrm{dD} / \mathrm{dt}=9640 / 319.061 \\\)

\(& \mathrm{dD} / \mathrm{dt}=30.21 \text { knots }\end{aligned}\)

At \($5 \mathrm{pm}$\) the distance between the ships is changing at the speed of \($\mathbf{3 0 . 2 1}$\) knots

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Answer:

Step-by-step explanation: Option A is correct.

Answer:

\(25m^{2} -40m+16\)

Step-by-step explanation:

Rewrite (5m−4)^2 as (5m−4)(5m−4).

Expand (5m−4)(5m−4) using the FOIL Method.

\(25m^{2} -40m+16\)

Answer: The product of 6,370*30 is 191,100

To set up the amortization table, we can use the mortgage and interest formulas as follows:

Mortgage formula:

M = P [ i(1 + i)^n / (1 + i)^n - 1]

where M is the monthly payment, P is the principal (the amount borrowed), i is the monthly interest rate (APR divided by 12), and n is the total number of payments (20 years multiplied by 12 months per year).

Interest formula:

I = P * i

where I is the monthly interest payment, P is the remaining principal balance, and i is the monthly interest rate.

Using these formulas, we can set up the following amortization table for the first two months:

Month Payment Principal Interest Balance

1    $400,000

2    

To fill in the table, we need to calculate the monthly payment (M) and the monthly interest payment (I) for the first month, and then use these values to calculate the principal payment for the first month. We can then subtract the principal payment from the initial balance to get the balance for the second month, and repeat the process to fill in the remaining columns.

To calculate the monthly payment (M), we can use the mortgage formula:

M = P [ i(1 + i)^n / (1 + i)^n - 1]

where P is the principal amount, i is the monthly interest rate, and n is the total number of payments.

Plugging in the given values, we get:

M = 400,000 [ 0.00279 (1 + 0.00279)^240 / (1 + 0.00279)^240 - 1]

M = $2,304.14

Therefore, the monthly payment is $2,304.14.

To calculate the interest payment for the first month, we can use the interest formula:

I = P * i

where P is the remaining principal balance and i is the monthly interest rate.

Plugging in the values for the first month, we get:

I = 400,000 * 0.00279

I = $1,116.00

Therefore, the interest payment for the first month is $1,116.00.

To calculate the principal payment for the first month, we can subtract the interest payment from the monthly payment:

Principal payment = Monthly payment - Interest payment

Principal payment = $2,304.14 - $1,116.00

Principal payment = $1,188.14

Therefore, the principal payment for the first month is $1,188.14.

To calculate the balance for the second month, we can subtract the principal payment from the initial balance:

Balance = Initial balance - Principal payment

Balance = $400,000 -$1,188.14

Balance = $398,811.86

Therefore, the balance for the second month is $398,811.86.

Using these values, we can complete the first two rows of the amortization table as follows:

Month Payment Principal Interest Balance

1 $2,304.14 $1,188.14 $1,116.00 $398,811.86

2    

To fill in the remaining columns for the second month, we can repeat the process using the new balance of $398,811.86 as the principal amount for the second month. We can calculate the interest payment using the same method as before, and then subtract the interest payment from the monthly payment to get the principal payment. We can then subtract the principal payment from the balance to get the new balance for the third month, and repeat the process for the remaining months of the amortization period.

Answer:

1

Step-by-step explanation:

There are 8 marbles.

All marbles are red.

p(red) = 8/8 = 1

Answer: 1

Answer:

1/8

Step-by-step explanation:

out of the 8 only 1 is chosen

The number of eraser Stefanie bought is 10.

Stefanie bought a package of pencils for $1.75 and some erasers that cost $0.25 each. She paid a total of $4.25 for these items, before tax.

Therefore, the number of eraser Stefanie bought can be calculated as follows;

let

x = number of eraser bought

Therefore,

4.25 = 1.75 + 0.25x

subtract 1,75 from both sides of the equation

4.25 - 1.75 = 1.75 - 1.75 + 0.25x

2.5 = 0.25x

divide both sides by 0.25

x = 2.5 / 0.25

x = 10

Therefore,

number of eraser = 10

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Answer:

10, 41, 42

Step-by-step explanation:

n+4n+1+5n-8=93

10n-7=93

10n=100

n=10

Side 1: 10

Side 2: 41

4(10)+1

40+1

41

Side 3: 42

5(10)-8

50-8

42

The domain of the function f(x) = -3x + 2 is (-∞, +∞), representing all real numbers, and the range is (-∞, 2], representing all real numbers less than or equal to 2.

The function f(x) = -3x + 2 is a linear function defined by a straight line. To determine the domain of this function, we need to identify the range of values for which the function is defined.

The domain of a linear function is typically all real numbers unless there are any restrictions. In this case, there is no explicit restriction mentioned, so we can assume that the function is defined for all real numbers.

Therefore, the domain of the function f(x) = -3x + 2 is (-∞, +∞), which represents all real numbers.

Now, let's analyze the range of the function. The range of a linear function can be determined by observing the slope of the line. In this case, the slope of the line is -3, which means that as x increases, the function values will decrease.

Since the slope is negative, the range of the function f(x) = -3x + 2 will be all real numbers less than or equal to the y-intercept, which is 2.

Therefore, the range of the function is (-∞, 2] since the function values cannot exceed 2.

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a) The mean of the sample of size 5 is equals to 103.

b) The mean of the sample of size 12 is equals to 103.3.

c) Median of sample of size 5 is 104.

d) Median sample of size 30 is 105.5.

Mean: Sum of observations is divided by number of observations in the sample is named as mean, which is denoted by X- bar. Moreover, the sample mean signifies the measure of centre of the data.

X-bar = (x₁ + x₂ + --- + xₙ)/n

Median: Median divides the observations into two equal parts. It represents the middle value for a set of observations when they are arranged in order of magnitude. There are two cases arises.

Case (1): Sample size (n) is odd: First, arrange the data in ascending order. Then, the median is the middle value and lies at the position.

Case (2): Sample size (n) is even: First, arrange the data in ascending order. Then, the median is the mean of the two data values that lie on either side of the position. Median = ( n/2)ᵗʰ term , n is odd

=[(( n/2)ᵗʰ term + (n/2 + 1)ᵗʰ term]/2, n is even

Now, a) Mean of first sample with sample size, n = 5.

Sum of values = 105 + 111 + 97 + 94 + 108 = 515

So, mean = 515/5 = 103

b) Sample 2, sample size , n = 12

Sum of values = 105 + 111 + 97 + 94 + 108 + 101 + 112 + 114 + 103+ 102+ 91 + 101

= 515 + 724 = 1239

Mean = 1239/12 = 103.25

c) Now, we have to determine median for sample size 5. Here, sample values are odd in number, i.e., 5. So, middle term is median after arranging in order. Ascending order is 94,97, 104, 108, 111 and middle term is 104, so median is 104.

d) Now, we have a sample of size 30, which is an even number. First arrange the numbers in ascending order as 91,92,92,94,95,97,100,101,101,101,101,102,103,105,105,105,106,107,107,108,110,111, 111, 112,113,114,115,115,116,116. So,

Median is [((n/2)th + (n/2 + 1)th ]/2 i.e, [ 30/2)th + 30/2 + 1)th ]/2

=( 15th + 16th)/2 ( observations)

= (105 + 106 )/2 = 211/2 = 105.5

Hence, the median of sample size 30 is 105.5.

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Complete question:

See the above figure, each of the following three data sets represents the iq scores of a random sample of adults. iq scores are known to have a mean and median of 100.

a) What is the mean of the sample of size 5? Full data set Sample of Size 108 114 (Type an integer or decimal rounded to one decimal place as needed._ Sample of Size 12

b) What is the mean of the sample of size 12? 114 105 115 (Type an integer or decimal rounded to one decimal place as needed:)

c) What is the median of the sample of size 5? (Type an integer or decimal rounded to one decimal place as needed:)

d) What is the median of the sample of size 30? (Type an integer or decimal rounded to one decimal place as needed:)

Answer: 15cm and 5cm

Step-by-step explanation:

A rectangle's area is the product of the length and width

Given length x and width y, 2x+2y = 40 and x*y = 75.

Verifying my answer:

2(15)+2(5) = 40

30+10 = 40

40 = 40

15*5 = 75

75= 75

This is a week late so I hope this helped.

The length and the width of the rectangle​ are 15cm and 5cm respectively

The given parameters are:

Area (A) = 75

Perimeter (P) = 40

The area of a rectangle is LW, while the perimeter is 2(L + W)

So, we have:

LW = 75

2(L + W) = 40

Divide by 2

L + W = 20

Make L the subject

L = 20 - W

Substitute L = 20 - W in LW = 75

(20 - W)W = 75

Expand

20W - W^2 = 75

Rewrite as:

W^2 - 20W + 75 = 0

Expand

W^2 - 15W - 5W + 75 = 0

Factorize

(W - 15)(W -5) = 0

Split

W - 15 = 0 or W - 5 = 0

Solve for W

W = 15 or W = 5

Recall that:

L= 20 - W

So, we have

L = 20 - 15 or L = 20 - 5

This gives

L = 5 or L = 15

Hence, the length and the width of the rectangle​ are 15cm and 5cm respectively

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