p30. the center of gravity of an object may be located outside the surface of an object. give two examples for which that is the case.

The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.

Answer:

Net Force. when all combinations of force acting on an object. Force. A push or pull

So it's the third answer

( the combination of all forces acting on it )

Answer:

The answer is: Plants and animals exchange carbon dioxide and oxygen with the atmosphere.

Explanation:

Got the answer right.

Answer:

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects.

Explanation:

9.8 N is the magnitude of the force that maintains circular motion acting on the puck.

32.53 m/sec is the linear speed of the puck.

The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. An item does not have a force inside of it or within it. Another item applies a force to another. The concept of a force is not restricted to living or non-living entities. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

As we know, from free body diagram, when the system is in equillibrium, the force acting on the puck on the table is as follows:

When the air puck of mass is revolving round the circle, then the tension (T) in the top string and the bottom of the string is same.

F = T

F = 9.8 N

Now, calculate the velocity of the puck:

From the given data, the air puck moves in a circular path. Hence, the tension in the top string is equal to the centripetal force acting on the puck.

Thus, the expression for the tension in the top string is as follows:

T = mv² / R

The velocity of the puck is as follows:

Mg = mv² / R

v² = MgR / m

v² = (2.7 × 9.8 × 1.2 ) / 0.030

v² = 1058.4

v = \(\sqrt{1058.4}\)

v = 32.53 m/sec

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By wearing the helmet, the time isextended during which the change in momentum of the body takes place during the crash.

This increase in time for the force acting on the body will decrease the impact of force on the body.

In the given graph, the value of force on the head is less and time taken is more in the first graph.

Thus, the first graph (1) represent the wearing helmet case.

The force on the head is more and time is less in the second case.

Thus, the second graph (2) represents the without helmet case.

Answer:

1. Information Gathering

2. Analysis and Planning.

3. Implementation of a solution.

4. Assessment of the effectiveness of the solution.

5. Documentation of the incident.

Answer:

  48.54 m/s

Explanation:

If the rock takes 9 seconds to reach your position after being thrown, it reaches its maximum height in 4.5 seconds.

The height the rock reaches above your position is ...

  h = (1/2)gt^2 = (4.9 m/s^2)(4.5 s)^2 = 99.225 m

This height is an additional 21 m above the water, so the maximum height above the water is ...

  99.225 m +21.0 m = 120.225 m

The velocity (v) achieved when falling from this distance is found from ...

  v^2 = 2gh

  v = √(2(9.8)(120.225)) = √2356.41 ≈ 48.543 . . . . m/s

The speed of the rock when it hits the water is about 48.54 m/s.

Answer: The amount of potential energy stored in 300g object is 1,75m.

The amount of potential energy stored in the object is 13.755 J.

To determine the potential energy stored in the object, we need to know about the gravitational potential energy and how is it calculated.

      where, m=mass

                  g= gravitational field or acceleration due to gravity

                  h= height

Potential energy = 0.3×26.2×1.75=13.755J.

Thus, we can conclude that the amount of potential energy stored in a 300g object 1.75 m above Jupiter's surface would be 13.755J.

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Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.

Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.

Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.

Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.

To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.

For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.

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Answer: a or b can u pls give me brainlest

Explanation:A straight line is a curve with constant slope. Since slope is acceleration on a velocity-time graph, each of the objects represented on this graph is moving with a constant acceleration.

1 Therefore, the kinetic frictional force experienced by the block on the incline is 6.784 N.

2 The magnitude of the velocity of the block at point B is approximately 5.11 m/s.

1. The formula for the kinetic frictional force is given by f = μN, where μ is the coefficient of kinetic friction and N is the normal force. Since the block is on an incline, the normal force can be calculated as N = mg * cos(θ), where θ is the angle of inclination.

N = 4 kg * 9.8 m/s² * cos(30°) = 33.92 N

f = 0.2 * 33.92 N

= 6.784 N

2. Potential energy at point A = mgh, where h is the vertical height of the incline.

Potential energy at point A = 4 kg * 9.8 m/s² * 3 m * sin(30°)

= 58.8 J

The work done by friction is given by W = f * d, where d is the distance traveled along the incline (3 m).

Work done by friction = 6.784 N * 3 m = 20.352 J

Since the work done by friction is negative (opposite to the direction of motion), the total work done on the block is:

Total work = Potential energy at A - Work done by friction

Total work = 58.8 J - 20.352 J = 38.448 J

According to the work-energy theorem, this work done on the block is equal to the change in its kinetic energy. Therefore, we have:

38.448 J = 0.5 * 4 kg * B²

Solving for B, we find:

B = √(38.448 J / (0.5 * 4 kg)) ≈ 5.11 m/s

Therefore, the magnitude of the velocity of the block at point B is approximately 5.11 m/s.

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Answer:

The maximum potential difference across capacitor is 20 V

Explanation:

Given;

maximum emf of the ac circuit, \(V_{max}\) = 25 V

maximum potential difference across resistor, \(V_R\)  = 15 V

maximum potential difference across capacitor, \(V_C\) = ?

Determine the maximum potential difference across capacitor using the equation below;

\(V_{max} = \sqrt{V_R^2 + V_C^2} \\\\25^2 = V_R^2 + V_C^2\\\\V_C^2 = 25^2 - V_R^2\\\\V_C^2 = 25^2 - 15^2\\\\V_C^2 = 400\\\\V_C = \sqrt{400} \\\\V_C = 20 \ V\)

Therefore, the maximum potential difference across capacitor is 20 V

The approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s is 3.94 KN

ac = v² / r

v = 2 π r / T

ac = Centripetal acceleration

v = Linear / Tangential velocity

T = Time period

r = Radius

r = 5 m

T = 2 s

v = 2 * 3.14 * 5 / 2

v = 15.7 m / s

ac = 15.7 * 15.7 / 5

ac = 49.298 m / s²

Fc = m ac

m = Mass

m = 80 kg

Fc = 80 * 49.298

Fc = 3943.8 N

Fc = 3.94 KN

Therefore, the approximate centripetal force on the astronaut is 3.94 KN

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Explanation:

Wapp=w+ma

Wapp=mg+ma

Wapp=6*10+6*10

Wapp=60+60

Wapp=120N

The pressure applied by the standing book on the table is 1,800 N/m².

option B is the correct answer.

The pressure applied by the standing book on the table is determined from the ratio of weight of the book and the area of the standing book.

Mathematically, the formula for the pressure of a material is given as;

P = F / A

where;

The weight of the book , F = mg

where;

F = 1.5 kg  x  9.8 m/s²

F = 14.7 N

The dimension of the book include;

The height of the book is not in contact with the surface of the table, so the area of the book in contact with the table becomes;

A = w x b

W = 0.21 m  x  0.04 m

W = 8.4 X 10⁻³ m²

P = F / A

P = ( 14.7 N ) / ( 8.4 X 10⁻³ m² )

P = 1,750 N/m² ≈ 1,800 N/m²

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Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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(a) the shell's horizontal range = 285839 m.

(b) the amount of time the shell is in motion is: 273.11 sec.

The length of the horizontal axis is a projectile's horizontal range. In addition, it would move before returning to the original vertical position.

Horizontal range is equal to Initial Speed in the horizontal direction, multiplied by the time the shell is in motion.  Therefore, both questions can be solved at the same time.

Step 1.  Find Velocity in the Horizontal direction by:  

Vx = (1.70 x 10³) × cos(52°)

Vx = 1046.6 m/sec

Step 2.  Find Velocity in the Vertical direction by:

Vy = (1.70 x 10³) × sin (52°)

Vy = 1339.6 m/sec

Step 3. Find the amount of time the shell is in motion by:  

t= (2 × Vy)/gravity

t = (2 × 1339.6) / 9.81       [ Gravity = 9.81m/s²]

t = 273.11 sec

Step 4. Find the shell's horizontal range:  

Distance = Vx × t

or, distance = (1046.6 × 273.11)

or, distance = 285839 m

Thus, (a) the shell's horizontal range = 285839 m.

(b) the amount of time the shell is in motion is: 273.11 sec.

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Explanation:

Given:

Diameter = 200 m

Radius, r = 200/2 = 100 m

Time taken, t = 30 seconds

Formula to be used:

Distance traveled, = circumference of circle = 2πr

Answer:

Putting all the values, we get

Distance traveled = 2πr

So, the distance traveled by Raju is 628.57 m.

Now, magnitude of the displacement,

At the end of 30 seconds, Raju will come to starting position or initial position, so displacement is zero.

The property that is oscillating would be the electric and magnetic fields.

For light, the property that is oscillating or vibrating at a particular frequency is the electric and magnetic fields.

Light is an electromagnetic wave, which means that it consists of oscillating electric and magnetic fields that are perpendicular to each other and to the direction of wave propagation.

The frequency of the wave corresponds to the number of complete oscillations of the electric and magnetic fields that occur per second, and is measured in hertz (Hz).

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The magnitude of the weight force on the block is 5.88 Newton.

Given the following data:

Scientific data:

To calculate the magnitude of the weight force on the block:

Mathematically, the weight force on the block is given by this formula:

\(W = mg\)

Where:

Substituting the given parameters into the formula, we have;

\(Weight = 0.6 \times 9.8\)

Weight = 5.88 Newton.

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The power at which the crane operates, if it can lift a mass of 500 kg is 1225 Watts.

Power is the rate at which work is done.

To calculate the power the crane operates with, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the right option is B. 1225 Watts.

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The magnitude of the puck's acceleration is 210.83 m/s².

The magnitude of the puck's acceleration in the horizontal direction is calculated as follows;

s = ut + ¹/₂aₓt²

where;

1.66 = 27.7 x 0.0503   +  (0.5)(0.0503)²aₓ

1.66 = 1.3933 + 1.265 x 10⁻³ aₓ

1.66  -  1.3933  = 1.265 x 10⁻³ aₓ

0.2667 = 1.265 x 10⁻³ aₓ

aₓ = 0.2667 / ( 1.265 x 10⁻³)

aₓ = 210.83 m/s²

Thus, the magnitude of the puck's acceleration is 210.83 m/s².

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To solve this problem, we can use the principle of conservation of energy. According to this principle, the total mechanical energy of an object remains constant as long as there are no external forces doing work on the object.

The initial mechanical energy of the girl and sledge is the potential energy they have due to their height above the ground. This potential energy is given by the formula:

PE = m * g * h

where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height above some reference point.

The final mechanical energy of the girl and sledge is the sum of their kinetic energy and potential energy at the end of their motion.

We can set up the following equation to represent the conservation of energy:

Initial PE + Initial KE = Final KE + Final PE

Since the girl and sledge start from rest, their initial kinetic energy is zero. Therefore, the equation simplifies to:

Initial PE = Final KE + Final PE

We can determine the distance the girl and sledge travel down the slope by calculating the final kinetic energy and potential energy and solving for the distance.

The final kinetic energy is given by the formula:

KE = 1/2 * m * v^2

where KE is the kinetic energy, m is the mass, and v is the velocity.

The final potential energy is given by the formula:

PE = m * g * h

where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height above some reference point.

To calculate the final kinetic energy, we need to determine the velocity of the girl and sledge at the end of their motion. We can use the principle of conservation of energy to solve for the velocity.

Substituting the given values into the equation for conservation of energy, we get:

Initial PE = Final KE + Final PE

= 1/2 * 40 kg * v^2 + 40 kg * 9.8 m/s^2 * h

We can solve for the velocity by rearranging the terms and substituting the values for the mass, initial potential energy, and final potential energy:

v = sqrt((2 * (Final PE - Initial PE)) / m)

= sqrt((2 * (40 kg * 9.8 m/s^2 * h - 40 kg * 9.8 m/s^2 * h)) / 40 kg)

= 0

Since the velocity is zero, the final kinetic energy is also zero. This means that the final mechanical energy is equal to the final potential energy, which is equal to the initial potential energy.

We can therefore set up the following equation to solve for the distance the girl and sledge travel down the slope:

Initial PE = Final KE + Final PE

= 0 + Final PE

= Initial PE

This equation tells us that the initial potential energy is equal to the final potential energy. Since the girl and sledge start from rest at the top of the slope and end at rest at the bottom of the slope, the final potential energy is equal to the initial potential energy.

Therefore, the distance the girl and sledge travel down the slope is equal to the distance they travel up the slope, which is 25m.

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The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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Answer:

40.2 N

Explanation:

I'm an Acellus student who got it correct.

The magnitude of  y-component of the total force on the skier is 40.18 N.

Force is an influence which tends to set a stationary body in motion or stop a moving body, or which tends to change the speed and direction of a moving body, or which tends to change the shape and size of body.

Given parameters:

Mass of the water: M = 73.8 kg.

Magnitude of force acting at 22.5° angle is: F₁ = 105 N.

Magnitude of force acting at directly backwards is: F₂ = 74.8 N.

We have to find: the y-component of the total force on the skier = ?

As F₂ acting directly backwards, this force has no y-component.

Hence, resultant y-component of the total force on the skier

= F₁ sin22.5°

= 105 ×sin22.5° N.

= 40.18 N.

Hence, magnitude of  y-component of the total force on the skier is 40.18 N.

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