p2. an automobile tire has a volume of 1.64 x 10-2 m3 and contains air at a gauge pressure (pressure above atmospheric pressure) of 165 kpa when the temperature is 0.00 degrees celsius. what is the gauge pressure of the air in the tires when its temperature rises to 27.0 degrees celsius and its volume increases to 1.67 x 10-2 m3 ? assume atmospheric pressure is 1.01 x 105 pa.

According to the statement, the vapor pressure of the NaCl solution is 22.63 torr.

To calculate the vapor pressure of the NaCl solution, we need to first calculate the mole fraction of water in the solution:

moles of water = mass of water / molar mass of water

moles of water = 150.0 g / 18.015 g/mol = 8.32 mol

moles of NaCl = mass of NaCl / molar mass of NaCl

moles of NaCl = 20.0 g / 58.44 g/mol = 0.342 mol

total moles = moles of water + moles of NaCl = 8.32 mol + 0.342 mol = 8.662 mol

X(water) = moles of water / total moles = 8.32 mol / 8.662 mol = 0.9603

Next, we can use Raoult's law to calculate the vapor pressure of the solution:

P = X(water) * P°(water)

Where P°(water) is the vapor pressure of pure water, which is given as 23.56 torr.

P = 0.9603 * 23.56 torr = 22.63 torr

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The induced EMF increases to four times its initial value if the rate of change of the magnetic field quadruples.

Faraday's law of electromagnetic induction specifies that an emf (electromotive force) is induced in a closed conductor or coil whenever there is a change in magnetic flux associated with it.

  EMF = − d(ΦB) /dt

  ΦB = BAcosθ

This equation suggests that emf is proportional to the rate at which magnetic flux ΦB is changing with respect to time. As a result, if the rate of change of the magnetic field quadruples, the induced EMF increases to four times its initial value.

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Explanation:

Solution,

We know that,

The sun is Yellow, red, orange, and blue. Therefore option B is correct.

The star is moving toward an observer. Therefore option B is correct.

39. The type of radioactive decay represented by the equation provided Gamma. Therefore option A is correct.

40. The statement is completed correctly by the information which states that the coal in Alberta has a lower carbon content than coal in other parts of Canada, resulting in reduced greenhouse gas emissions.

29. graph B depicts the relationship between gravitational field strength and the mass of the International Space Station orbiting Earth.

30. The correct sequence of colors representing the changing temperature from the surface to the atmosphere of the sun is Yellow, red, orange, and blue. Therefore option B is correct.

1. When a star undergoes a blue shift, it indicates that the star is moving toward an observer. Therefore option B is correct.

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Answer:

67.2 m

Explanation: source - trust me bro

The new force of attraction between the two objects would be 4 units. This is because the gravitational force between two objects is inversely proportional to the square of the distance between them.

Units refer to standardized measurements used to quantify the amount, size, or intensity of something. They are essential in all areas of science and engineering, allowing for comparison and communication between different people, places, and times. Units are typically based on an international standard, so that measurements are consistent worldwide. For example, a meter is the same all over the world, and a kilogram is the same everywhere. This allows for accurate measurements to be taken and communicated, no matter the location. Units are also important for engineering and construction, since they allow for precise calculations and measurements to be taken. Without them, it would be impossible to accurately build complex structures.

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Answer:

36km/h = 10m/s

Explanation:

That's the formula to convert

Her jumper would appear dark and drab, practically a dark shade of gray, if Ray shone a green filter on it.

This is so because the wavelengths of light that an object reflects define its color. In the case of red clothing, it reflects red light with wavelengths between 620 and 750 nm. The green filter, however, blocks all other wavelengths, including red ones, and only allows green light wavelengths (between 495 and 570 nm) to get through when it is positioned in front of the red jumper.

We wouldn't see the colour red because red wavelengths are blocked and red clothing can't reflect them back to our eyes. Instead, we would observe the dark and dreary greyish-green color that is produced when residual green wavelengths combine with the color of the red garment.

The interaction between green filter's color wavelengths and red jumper's color wavelengths causes red jumper to appear as a dark and dreary greyish-green color when green filter is shone upon it.

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The motor could  lift 15 g in a time of 8 seconds 10884 meter.

The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.

Given that motor operates at 200 W.

At time interval of 8 second, it do a work = 200×8 joule = 1600 joule.

Hence,  it lift 15 g in a time of 8 seconds = 1600/(0.015×9.8) meter

= 10884 meter.

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Exactly, 1 Joule of energy per second is what is used to define a Watt. Joules and seconds, respectively, are the SI units for time and work. A power of 1 Joule per second was used to define a Watt.

A one newton (N) force applied over a one meter distance does one joule's worth of work (or energy) (m).. To put it simply, it requires approximately 1 joule of energy to raise a 3/4 pound weight 1 foot off the ground or to drag something 1 foot using a parallel pulling force of 3/4 pound. According to this definition from physics, 1 volt is the same as 1 joule of electric potential energy divided by 1 coulomb of charge. The power unit is the watt. According to this, 1 joule of labor is completed in 1 second. It is, in essence, the ability of an appliance to use energy at a rate of 1 joule per second.

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Option 1 is correct. The gravity on a planet with a mass of 3 times that of Earth and a radius 3 times that of Earth would be 1/9th of Earth's gravity.

The force of gravity on a planet is determined by its mass and radius. According to Newton's law of universal gravitation, the force of gravity (F) between two objects is given by the equation \(F = (G * m1 * m_2) / r^2\), where G is the gravitational constant, \(m_1\) and \(m_2\) are the masses of the two objects, and r is the distance between their centres.

In this case, we are comparing the gravity of a planet with a mass (\(m_2\)) of 3 times that of Earth (\(M_\oplus\)) and a radius (r) of 3 times that of Earth. Since the radius is directly proportional to the distance between the centres of the two objects, the value of \(r^2\) would be \(3^2 = 9\) times larger than Earth's radius.

As a result, the force of gravity on this planet would be \(1/9th (1/3^2)\) of Earth's gravity, which is the first option given. Therefore, the correct answer is 1/9 × Earth's gravity.

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Answer:

3V

Explanation:

From the question given above, we can see clearly that the resistors are arranged in parallel connection. Hence, the same voltage will pass through the resistors i.e

Total voltage = voltage of 3 Ω = voltage of 6 Ω

From the question given above,

The total voltage = 3 V

Therefore,

Voltage of 3 Ω = total voltage

Voltage of 3 Ω = 3V

Thus, option 3 gives the correct answer to the question.

Answer:

B.

Explanation:

w=mg

g=10m/s

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sin(ø)=Us*cos(ø) is an expression for the maximum angle, θm, that the board can make with respect to the horizontal before the block starts moving.

What is friction?

The force that prevents one solid item from moving over another is known as friction. Static friction, sliding friction, rolling friction, and fluid friction are the four major categories of friction. Two surfaces that come into contact and slide against one another produce frictional energy. Surface roughness and the quantity of force pressing them together have the biggest an impact on these forces.

The angle of friction is the product of normal reaction and limiting friction with the normal reaction. The tangent of the friction angle is equivalent to the coefficient of static friction.

0= Usmgcos(ø) - mg*sin(ø)

mgsin(ø) = Usmg*cos(ø)

=> sin(ø)=Us*cos(ø)

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Answer:

The answer to this question is given below in this explanation section.

Explanation:

If you place a row of several steel balls on a track and let ball strike it and one end of the row,then the last ball at the other end will fly off,corresponding to the income impulse.All the other balls will remain at rest.This experiment is well known from the newton cradle toy,However you world be you surprise if the last ball in the row shot away like a bullet,even through the first ball.only seemed to have a very moderate velocity.This would not seem consistent with the law of the conservation of energy.

The effect is so surprising that one guesses it might be a trick and you would be right: one or more of the similar looking balls are in fact magnetic.

The first strike approaching from the left hand is from a non magnetic steel ball which will be strongly accelerated through the magnetic balls and thrust with a relatively high velocity on the row of resting balls.

Vector quantities include displacement, force, torque, momentum, acceleration, and velocity. A physical quantity that has both directions and magnitude is referred to as a vector quantity.

Summary. Any quantity with magnitude and direction, such displacement or velocity, is referred to as a vector quantity. Mathematical entities referred to as vectors are used to express vector quantities. Geometrically, a vector is represented by an arrow with an arrowhead at the end.

displacement, such as 50 kilometers east. velocity, for instance, 11 m/s and above. acceleration, for instance 9.8 m/s2 of downward motion momentum, such as 250 kg m/s (kg meters per second) in the south west.

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a. The overall displacement Δx of the particle is 75 m to the east.

b. The average velocity vav of the particle over the time interval Δt=50.0s is 1.5 m/s to the east.

c. To find the instantaneous velocity v of the particle at t=10.0s, we can calculate the derivative of the position function x(t) with respect to time t at t=10.0s.

From the given position function x(t) = 0.25t³ - 1.5t² + 3t, we can find the velocity function v(t) by taking the derivative: v(t) = dx/dt = 0.75t² - 3t + 3. At t=10.0s, the instantaneous velocity v of the particle is v(10.0) = 57.0 m/s to the east.

The displacement of the particle can be found by subtracting its initial position from its final position, which gives Δx = x(60.0s) - x(10.0s) = 3000 m - 2925 m = 75 m to the east. The average velocity of the particle over the time interval is given by the formula vav = Δx/Δt = 75 m/50.0 s = 1.5 m/s to the east.

Finally, the instantaneous velocity of the particle at t=10.0s can be found by taking the derivative of the position function x(t) with respect to time t and evaluating it at t=10.0s, giving the value of the velocity at that instant.

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Calculations of displacement, average velocity, and instantaneous velocity require specific information about the motion of the particle. Each of these calculations can be performed using calculus when the motion of the particle is defined as a function of time.

The questions are about the interpretation of the motion and the velocity of a particle. However, the actual values, for displacement Δx, average velocity vav, and instantaneous velocity v, could not be directly calculated without additional specific information about the motion of the particle. But here's a general method:

a. The overall displacement, Δx, of the particle can be calculated by integrating the velocity function, v(t), over the time interval.

b. The average velocity, vav, of a particle over a time interval, Δt, can be found by dividing the total displacement, Δx, by the total time, Δt.

c. The instantaneous velocity, v, of a particle at a specific time, t, can be calculated by taking the derivative of the position function, x(t), at that time.

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The magnitudes of Emax and  Bmax for the electromagnetic waves at the top of the Neptune's atmosphere are 33.95 N / C and 11.31 * 10⁻⁸ T respectively.

I = ( Emax )² / ( 2 μo c )

I = Intensity

Emax = Maximum Electric field

μo = Absolute permeability of free space

c = Speed of light

μo = 4π * 10⁻⁷ H / m

c = 3 * 10⁸ m / s

I = 1.529 W / m²

Emax² = I * 2 μo c

Emax² = 1.529 * 2 * 4π * 10⁻⁷ * 3 * 10⁸

Emax² = 1152.25

Emax = 33.95 N / C

I = c Bmax² / ( 2 μo )

Bmax² = 2 μo I / c

Bmax² = ( 2 * 4π * 10⁻⁷ * 1.529 ) / ( 3 * 10⁸ )

Bmax² = 128 * 10⁻¹⁶

Bmax = 11.31 * 10⁻⁸ T

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Answer:

This values shows a right angle triangle

Explanation:

Given;

a vector 4.0 km due East

a 3.0 km due north

the resultant vector is 5.0 km

The resultant vector can be obtained by Pythagoras theorem if the vectors form a right angle triangle.

R² = 4² + 3²

R² = 16 + 9

R² = 25

R = √25

R = 5 km    (right angle triangle proved)

Therefore, this values shows a right angle triangle

Answer:

1loaf = 435litres of water

3loaf = 3045 litres of water

1305

The statement, "The earth is much cooler than the sun, so the earth does not transfer energy to its surroundings" is false.

The answer to the question is yes. There are three main ways in which the earth interacts with the surroundings and exchanges energy with it. These include radiation, conduction, and convection.

In addition, the earth moves around the sun and when it is closer to the sun, it receives more warmth. It is not logical to say that the Earth does not transfer energy to its surroundings.

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Answer:

Explanation:

The collision between the 93kg fullback and the 127kg defensive tackle is an example of an inelastic collision. In an inelastic collision, the total kinetic energy of the system is not conserved as some of the energy is transformed into other forms such as heat or sound. The resulting final speed of both players would be 0m/s, indicating that they have come to a stop after the collision.

Answer:

h = 35857 km

Explanation:

A geosynchronous orbit can be defined as circular orbit which lies on the Earth's equatorial plane and follows the direction of the Earth's rotation in a period that's equal to the Earth's rotational period and thereby appearing motionless, at a fixed position in the sky relative to the ground observers.

We are given;

Radius of earth(R) = 6.37 x 10^(6) m

Mass of earth (Me) = 5.97 x 10^(24) kg

Gravitational constant = 6.67 × 10^(-11) m³/kg.s²

The earth has a rotational period of 24 hours per day. This gives in seconds

T = 24 × 60 × 60

T = 86400 s

Let's make the height of the orbit from Earth's surface to be h

Also, let ω be the uniform angular velocity in rad/s with which the satellite rotates in the geosynchronous orbit

Now, equating the centripetal force with the gravitational force gives us;

mω²(R + h) = G•Me•m/(R + h)²

m will cancel out. Also ω can be written as 2π/T

Thus,we now have;

(R + h) = ∛(G•Me•T²/(4π²))

Plugging in the relevant values, we have;

(R + h) = ∛(6.67 × 10^(-11) × 5.97 x 10^(24) × 86400²/(4π²))

(R + h) = 42227 Km

Since R = 6.37 x 10^(6)m = 6370 km

Thus;. h = 42227 - 6370 = 35857 km

Explanation:

If the moon doubled in mass, that means that the Earth will not experience a total solar eclipse like today. Also, if it doubled in mass, tide waves would increase in size, as the moon would be bigger and would have a bigger gravitational pull. Also, gravity would be different on earth because the moon is bigger (gravity law by mass). Also, the sky would be ‘smaller’ than our actual sky

Answer:

If the moon's mass doubles, the Earth will not witness a total solar eclipse as today. Also, if its mass doubled, tide waves would double in size since the moon would be bigger and have a stronger gravitational attraction. Also, because the moon is larger, gravity on Earth would be different (gravity law by mass). Also, the sky would be "smaller" than it is now.

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The mass of the measuring stick if it is balanced by a support force at the 0.25 m mark is 0.75 kg.The mass of the measuring stick can be found using the principles of torque.

Given that a 1.0 kg rock is suspended by a massless string from one end of a 1 m measuring stick, and is balanced by a support force at the 0.25 m mark. Thus, taking clockwise as the negative direction of torque and counterclockwise as the positive direction, the torques at the 0.25 m mark are:T clockwise = weight of the rock x distance from support forceT clockwise = (1.0 kg)(9.8 m/s²)(0.75 m) = 7.35 NmT counterclockwise = weight of the measuring stick x distance from support forceT counterclockwise = (mass of measuring stick)(9.8 m/s²)(0.25 m) = 2.45 NmFor balance, T clockwise = T counterclockwise. Substituting values,7.35 Nm = 2.45 Nm(mass of measuring stick) = (7.35 Nm)/(2.45 Nm) = 3 kg.

Therefore, the mass of the measuring stick is 3 kg.Subtracting the weight of the rock, the mass of the measuring stick is:mass of measuring stick = 3 kg - 1 kg = 2 kgSo, the mass of the measuring stick if it is balanced by a support force at the 0.25 m mark is 0.75 kg.

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Answer:x rays are electromagnetic waves.

x rays are transverse waves

x rays travel at the speed of light

Explanation: