The number of the molecules present in 16.8 L gas 'X' at S.T.P is given by the term of 4.52×10²³ molecules.
To acquire the needed number of molecules, first calculate the substance's molecular weight in units of one mole. Next, divide the molar mass value by the molecular mass, and multiply the resulting number by the Avogadro constant.
The link between the number of moles and Avogadro's number, which is given by; may be used to calculate the number of molecules.
Avogadro's constant (1 mole) (NA)
Once the number of moles has been established, the number of molecules will equal the sum of the number of moles and Avogadro's number.
The number of molecules in 22.4 L of gas (X) = 6.02 x 10²³
Thus, the number of molecules in 16.8 L of gas (X) = 6.02 x 10²³ x 16.8/22.4
= 4.52×10²³ molecules.
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Complete question:
Calculate the number of molecules present in 16.8 L gas 'X' at S.T.P.
There are approximately 3.92 x 10^23 molecules of xenon gas in 16.8 L at STP.
To answer this question, we need to use the Ideal Gas Law equation: PV=nRT. At STP (Standard Temperature and Pressure), the temperature is 273 K and the pressure is 1 atm. The molar volume of a gas at STP is 22.4 L/mol.
First, we need to find the number of moles of xenon gas in 16.8 L:
V = 16.8 L
n = PV/RT = (1 atm)(16.8 L)/(0.0821 L•atm/mol•K)(273 K) = 0.652 mol
Now, we can use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules:
Number of molecules = (0.652 mol)(6.022 x 10^23 molecules/mol) = 3.92 x 10^23 molecules
To find the number of molecules in 16.8 L of xenon gas at STP, you'll need to use the Ideal Gas Law and Avogadro's number.
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 L. First, determine the number of moles of xenon:
moles of xenon = (16.8 L) / (22.4 L/mol) = 0.75 mol
Next, use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules:
molecules of xenon = (0.75 mol) x (6.022 x 10^23 molecules/mol) ≈ 4.52 x 10^23 molecules
So, there are approximately 4.52 x 10^23 molecules in 16.8 L of xenon gas at STP.
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ID compound from lineup using % composition and gravimetric analysis. To identify unknown sample of salt made from an Alkali cation and chloride anion, you decide to use gravimetric analysis. You dissolve 0.825 g of the salt in water, then add excess lead(II) nitrate. Lead(II) chloride precipitates out. After collecting and drying the solid, you find its mass to be 0.949 g. Which Alkali metal was the cation of the original salt? Hint: this differs from the worked example problem in that after finding percent composition of chlorine of the unknown salt, you must compare it to the percent compositions of all the salts made by pairing an Alkali metal cation with chloride anion.
No answer text provided.
Li, lithium
Na, sodium
K, potassium
Rb, rubidium
Cs, cesium
Fr, francium
The alkali metal cation in the original salt is lithium (Li), based on the percent composition of chlorine
To identify which alkali metal cation was present in the original salt, we can compare the percent composition of chlorine in the unknown salt with the percent compositions of salts formed by pairing alkali metal cations with chloride anions.
First, we need to calculate the percent composition of chlorine in the unknown salt:
Mass of chlorine = Mass of lead(II) chloride - Mass of lead(II) nitrate
= 0.949 g - 0.825 g
= 0.124 g
Percent composition of chlorine = (Mass of chlorine / Mass of unknown salt) x 100
= (0.124 g / 0.825 g) x 100
= 15.03%
Next, we compare this percent composition of chlorine to the percent compositions of alkali metal chlorides:
LiCl: 100% chlorine
NaCl: 60.66% chlorine
KCl: 47.28% chlorine
RbCl: 43.71% chlorine
CsCl: 40.42% chlorine
FrCl: 37.72% chlorine
Based on the percent composition of chlorine in the unknown salt (15.03%), we can see that it is closest to the percent composition of lithium chloride (100% chlorine). Therefore, the alkali metal cation in the original salt is Li, lithium.
The alkali metal cation in the original salt is lithium (Li), based on the percent composition of chlorine in the unknown salt obtained through gravimetric analysis
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The primary food source for many sea animals is:
crayfish
squid
sea grass
plankton
Answer:
plankton
Explanation:
like in spongebob lol but for real I'm a marine biologist I know this is the answer lol
what happens if the same zero error occurs in every reading
Zero error occur in every reading means that the measuring instrument needs to recalibrated and adjusted.
What is Zero error?This error occurs when a measuring instrument reflects a digit which isn't zero despite the real value being zero.
When this occurs, only the zero screw on the device should be adjusted so as to correct this technical error. This is why recalibration should be the most appropriate solution.
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Please help me answer these true or false chemistry questions!! 33 points!!
1) Galium's (Ga) electron configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1 = TRUE OR FALSE
2) Galium has two valence electrons = TRUE OR FALSE
3) Iridium electron configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d7 = TRUE OR FALSE
4) Iridium (Ir) has two valence electrons = TRUE OR FALSE
5) Oxygen's orbital notation is 1sX 2sX 2pX// = TRUE OR FALSE
6) Scandium's (Sc) orbital notation is 1s2 2s2 = TRUE OR FALSE
7) Carbon (C) noble gas abbreviation is [Rn] 7s2 = TRUE OR FALSE
8) Neon's (Ne) noble gas abbreviation is [Xe] 6s2 4f6 = TRUE OR FALSE
9) Lithium's noble gas abbreviation is [He] 2s1 = TRUE OR FALSE
10) The long form electron configuration of Iodine ion with a -1 charge (I^-1) is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 = TRUE OR FALSE
11) Iodine ion with -1 charge is isoelectronic with Neon = TRUE OR FALSE
12) Calcium ion with +2 charge's (Ca^+2) electron configuration is 1s2 2s2 2p6 3s2 3p6 = TRUE OR FALSE
13) Calcium ion with +2 charge is isoelectronic with Argon (Ar) = TRUE OR FALSE
14) Helium's Electron configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 = TRUE OR FALSE
15) Helium is isoelectronic with Xenon (Xe) = TRUE OR FALSE
16) The neutral 1s2 2s2 2p6 3s2 3p5 atom is Cl = TRUE OR FALSE
17) The atom with the -1 charge and the electron configuration 1s2 2s2 2p6 3s2 3p6 is Cl-1 = TRUE OR FALSE
18) The atom with the -3 charge and the electron configuration of 1s2 2s2 2p6 3s2 3p6 is P^-3 = TRUE OR FALSE
19) The quantum number for Chlorine ion with -1 charge is (3, 1, +1, -1/2) = TRUE OR FALSE
Thanks to anyone that answers!!
Answer: 1) True
2) False 4)False 5)True
Explanation: I took a test that had similar questions
2. Calculate the mass of K in 90g of KOH
KOH = 90g
KOH = 57 g/mol
K = 40g/mol
57g/mol contains 90 g
40g/mol will contain?
= 63.15 g
The mass of K is 63.15g
What orbital does the quantum numbers n=4 l=2 ml=2 describe
Answer:
Orbital designation
for Principle Quantum number n=4, this is the shell number & corresponds to N shell, (shells are designated K,L,M,N)
for Angular Momentum number l=2, this is the orbital level corresponding to d, given that l can be any integer 0-(n-1), for( 0,1,2,3 )corresponds to (s, p, d, f)
The orbital designation is 4d
for Magnetic Quantum number ml, the suborbitals correspond to -l through l, (-2,-1,0, 1,2)
for ml=-1 the suborbital -1 in the 4d sub shell with electron spin state ms=-1/2
A camel eats 18.3 kg of Bermudagrass hay that is 14.7 %
CP on a dry matter basis. If the DM percentage of the hay is 83.4
%, how much protein did the camel consume?
The camel consumed approximately 2.24 kg of protein from the Bermudagrass hay.
To calculate the amount of protein the camel consumed, we need to consider the dry matter basis of the hay. Here's how you can calculate it:
Calculate the dry matter weight of the hay:
Dry Matter Weight = Total Weight of Hay × Dry Matter Percentage
Dry Matter Weight = 18.3 kg × (83.4/100)
Dry Matter Weight = 18.3 kg × 0.834
Dry Matter Weight = 15.2442 kg
Calculate the protein content in the dry matter;
Protein Content = Dry Matter Weight × Protein Percentage
Protein Content = 15.2442 kg × (14.7/100)
Protein Content = 15.2442 kg × 0.147
Protein Content = 2.2414194 kg
Therefore, the camel consumed approximately 2.24 kg of protein from the Bermudagrass hay.
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Which statement describes a chemical property of
aluminum?
(1) Aluminum has a density of 2.698 g/em at STP.
(2) Aluminum reacts with sulfuric acid.
(3) Aluminum conducts an electric current.
(4) Aluminum is malleable.
Answer:
2 aluminum reacts with sulfuric acid
Identify the group number and generic outer electron configuration for a neutral main‑group element with the following two Lewis dot symbols.
X with 1 dot on the top, bottom and right
X with 1 dot on all sides
Answer: Answer to #1 is 3A and ns2np1
Answer to #2 is 4A and ns2np2
Explanation:Group number is the number of valance electrons and generic outer electron configuration has to add up to equal the number of valance electrons
The element in the first diagram is in group 13 while the element in the second diagram is in group 14.
The Lewis structure of an atom of an element is a representation of the number of valence electrons on the outermost shell of the atom of that element. Every group of elements have a generic electron configuration which represents the number of valence electrons contained by atoms of elements in that group.
In the first diagram, the element X belongs to group 3A(13) and has a generic outer electron configuration, ns2np1. In the second diagram, the element X is in group 4A(14) and has outer electron configuration ns2np2.
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Using the rules for significant figures, what do you get when you multiply 67.6 by 1.2?
Answer:
The answer should have as many significant figures as the lowest number used in the multiplication, which is 1.2 .
Gas and dust are the primary components of the interstellar medium. They differ in structural form, elemental composition, and the density with which each is distributed across the interstellar medium. Complete the table by placing the physical descriptions of gas and dust in the appropriate column.
Gas: Structural Forms are Atoms and small molecules whereas Density is quite Low density
Dust: Structural Forms are Clumps of atoms and large molecules wherease Density is Extremely low density
Most of the gas between stars in our galaxy and other galaxies is hydrogen and helium, which is dispersed at different densities between the stars. The gas ratios are comparable to those of the Sun
A buildup of gas and dust falls under the influence of gravity to generate stars. From the moment the first gas cloud begins to compress to the time the star is formed and begins to shine like the Sun, the process of star creation takes roughly one million years.
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Which of the following statements correctly describe the change in entropy when a solution is formed? Select all that apply.
-Entropy usually increases when a solution forms because there are more interactions between particles in a solution.
-The particles in a solution generally have a greater freedom of movement than the particles in a pure solute.
Entropy usually increases when a solution forms because there are more interactions between particles in a solution.
The particles in a solution generally have greater freedom of movement than the particles in a pure solute.
When a solution is formed, the interactions between particles increase, leading to an increase in entropy. In a solution, solute particles interact with solvent particles, resulting in more degrees of freedom for the particles. This increased freedom of movement contributes to higher entropy compared to the particles in a pure solute.
The first statement is correct because the increased number of interactions between particles in a solution leads to more possible arrangements, resulting in higher entropy.
The second statement is also correct because, in a solution, solute particles are dispersed and surrounded by solvent molecules, allowing them greater freedom of movement compared to being in a pure solute state.
Overall, both statements correctly describe the change in entropy when a solution is formed: entropy usually increases due to increased interactions between particles and greater freedom of movement for the particles in the solution.
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during a firework show the white incandescent light is produced by the following reaction. P+O2->P4O10. if a chemical uses 8.00 grams of oxygen in an excess of phosphorus how many grams of P4O10 will the chemist make
14.2g of \(P_4O_{10}\) will be made by the chemist when a chemical uses 8.00 grams of oxygen in an excess of phosphorus.
Given the white incandescent light is produced during a firework show
The reaction is as follows:\(P + O_2 - > P_4O_{10\)
After balancing the equation we get:\(4P + 5O_2 -- > P_4O_{10\)
The mass of oxygen used = 8g
From the reaction we can see that 5 moles of Oxygen (\(O_2\)) react with phosphorous to form 1 mole of \(P_4O_{10\).
Mass of oxygen used initially = moles x molar mass of \(O_2\) = 5 * 32 = 160g
mass of \(P_4O_{10\) used = 1 mole x 284g/mole = 284g
for 160g of oxygen 284g of \(P_4O_{10\) is produced.
Then for 8g of oxygen = 8 * 284/160 = 14.2g of \(P_4O_{10\) is obtained.
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100 milligrams of Uranium-238 are stored in a container. If Uranium-238 has a half-life of about 4.47 billion years, after how many years will only 10 milligrams be present
The time (in years) taken for only 10 mg to remain is 14.84 billion years
Data obtained from the questionOriginal amount (N₀) = 100 mgHalf-life (t½) = 4.47 billion yearsAmount remaining (N) = 10 mgTime (t) =? Determination of the number of half-lives that has elapsed Original amount (N₀) = 100 mgAmount remaining (N) = 10 mgNumber of half-lives (n) =?
N × 2ⁿ = N₀
10 × 2ⁿ = 100
Divide both side by 10
2ⁿ = 100 / 10
2ⁿ = 10
Take the log of both side
Log 2ⁿ = Log 10
nLog 2 = Log 10
Divide both side by Log 2
n = Log 10 / Log 2
n = 3.32
How to determine the time (in years)
Half-life (t½) = 4.47 billion yearsNumber of half-lives (n) = 3.32Time (t) =?t = n × t½
t = 3.32 × 4.47
t = 14.84 billion years
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Calculate the Standard Free Energy Change at 25 degrees celsius given the Equilibrium constant of 1.3 x 10^4.
The standard free energy change at 25 degrees Celsius is approximately -78.48 J/mol.
To calculate the standard free energy change (ΔG°) at 25 degrees Celsius using the equilibrium constant (K), we can use the following equation:
ΔG° = -RT ln(K)
Where:
ΔG° is the standard free energy change.
R is the gas constant (8.314 J/(mol·K)).
T is the temperature in Kelvin (25 degrees Celsius = 298.15 K).
ln is the natural logarithm.
Plugging in the values, we get:
ΔG° = - (8.314 J/(mol·K)) * ln(1.3 x 10^4)
Now, we can calculate it:
ΔG° = - (8.314 J/(mol·K)) * ln(1.3 x 10^4)
ΔG° ≈ - (8.314 J/(mol·K)) * 9.472
ΔG° ≈ -78.48 J/mol
Therefore, the standard free energy change at 25 degrees Celsius is approximately -78.48 J/mol.
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Explain what is meant by spheres of power. Choose a particular
corporation and describe the power it wields in different
spheres.
Spheres of power refer to the different areas in which corporations hold influence and power, including economic, political, cultural, and social spheres.
Corporations hold significant power in modern societies, often extending beyond traditional political boundaries. Corporate power is often characterized by the ability to influence public policy, shape public opinion, and control economic markets. Different corporations wield power in different spheres, depending on their size, sector, and geographic location.
Let us consider the example of Apple Inc. to describe the power it wields in different spheres.
Economic Sphere: Apple is one of the world's largest corporations, with a market capitalization of over $2 trillion. It holds significant economic power, controlling a sizable portion of the global smartphone and computer markets. It has been able to leverage its economic power to negotiate favorable trade deals, acquire smaller companies, and invest in research and development.
Political Sphere: Apple has been able to influence public policy through lobbying efforts. For example, it has lobbied for tax breaks and incentives to promote innovation and job creation. Apple has also been involved in high-profile legal battles over privacy concerns and intellectual property rights, with the outcome of these cases having implications for other technology companies.
Cultural Sphere: Apple has a strong brand identity and is often associated with innovation, creativity, and high quality. Its products have become a symbol of status and aspiration for many people, contributing to its cultural power. Apple has also invested in the entertainment industry through its Apple Music and Apple TV+ services, further extending its cultural influence.
Social Sphere: Apple has been able to shape social norms and behaviors through its products and marketing. For example, the iPhone has revolutionized the way people communicate and interact with technology, contributing to the rise of social media and the decline of traditional forms of communication. Apple's marketing campaigns have also had a significant impact on popular culture, influencing fashion trends and consumer behavior.
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: How might the water cycle and Earth be affected if the average temperature of the Earth decreases five degrees every year for ten years?
A decrease in the Earth's average temperature could potentially have significant impacts on the water cycle and the planet as a whole.
What is the patterns of evaporation ?As the temperature drops, more water in the form of ice and snow may accumulate on land and in polar regions. This could cause changes in the global distribution of precipitation, leading to altered patterns of evaporation and runoff.
Additionally, the cooler temperatures may cause a reduction in the amount of water vapor in the atmosphere, which could lead to changes in cloud formation and the amount of precipitation that falls in different regions.
Furthermore, the colder temperatures could affect the growth and reproduction of plants and animals, which could have cascading effects throughout ecosystems.
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How does modern periodic table explain the cause of periodicity.
Answer:
The cause of periodicity in properties is the repetition of similar outer electronic configuration after certain regular intervals. For example, all the elements of group 1 i.e. alkali metals have a similar outer electronic configuration, ns1.
How does nuclear fusion produce energy in a star?
Nuclear fusion in stars, such as our Sun, produces energy through the fusion of light atomic nuclei, mainly hydrogen, into heavier nuclei like helium. This fusion process releases a tremendous amount of energy.
Within the core of a star, where temperatures and pressures are extremely high, nuclear fusion takes place. The collisions between hydrogen atoms at such high temperatures provide the necessary energy to overcome electrostatic repulsion, enabling the fusion process.
In the proton-proton chain, the most common fusion process in stars, hydrogen nuclei combine to form helium nuclei through several reactions. The conversion of a small fraction of mass into energy, as described by Einstein's mass-energy equivalence, results in the release of energy in the form of gamma rays.
These high-energy photons interact with matter, gradually transforming into light and heat. This energy release sustains the star's stability by countering gravitational collapse and powers its luminosity for billions of years.
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Earth materials that are soluble in water or react to a weak acid commonly have what type of appearance?.
Which equation is derived from the combined gas law?
StartFraction V subscript 1 over T subscript 1 EndFraction equals StartFraction V subscript 2 over T subscript 2 EndFraction.
StartFraction V subscript 1 over T subscript 2 EndFraction equals StartFraction V subscript 2 over T subscript 1 EndFraction.
V subscript 1 T subscript 1 equals P subscript 2 T subscript 2.
P subscript 1 V subscript 1 T subscript 1 equals P subscript 2 V subscript 2 T subscript 2.
The equation derived from the combined gas law is option D: P₁V₁T₁ = P₂V₂T₂. Option D
The combined gas law combines Boyle's law, Charles's law, and Gay-Lussac's law into a single equation that relates the pressure, volume, and temperature of a gas sample. It allows us to analyze changes in these variables while keeping the amount of gas constant.
Boyle's law states that at a constant temperature, the pressure and volume of a gas are inversely proportional. In other words, if the volume of a gas decreases, its pressure increases, and vice versa. This is expressed as P₁V₁ = P₂V₂.
Charles's law states that at a constant pressure, the volume and temperature of a gas are directly proportional. If the temperature of a gas increases, its volume increases, and vice versa. This is expressed as V₁/T₁ = V₂/T₂.
Gay-Lussac's law states that at a constant volume, the pressure and temperature of a gas are directly proportional. If the temperature of a gas increases, its pressure increases, and vice versa. This is expressed as P₁/T₁ = P₂/T₂.
By combining these three laws, we obtain the combined gas law equation: (P₁V₁)/T₁ = (P₂V₂)/T₂. To eliminate the division, we can cross-multiply to get P₁V₁T₂ = P₂V₂T₁, which can be rearranged as P₁V₁T₁ = P₂V₂T₂.
This equation allows us to calculate the final values of pressure, volume, or temperature when any two of these variables change while the amount of gas remains constant. It is particularly useful in analyzing the behavior of gases under different conditions or when studying gas systems.
Option D
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Answer:
it was A for me.. don't know if this will help
Explanation:
Which of the following is an advantage of using an energy-efficient household
appliance instead of a traditional household appliance?
A. It works only during the daytime.
B. It uses no electricity
c. It conserves electricity.
D. It does not work as effectively
3g of clean mg ribbon and 8g of clean copper metal was burnt separately in equal volume of air and both mass reacted completely with air state and explain where they was greater change in mass??
Answer:
gshshs
Explanation:
bshsjskskehhshs
The copper metal is heated in the air. The magnesium ribbon emits a brilliant light and magnesium oxide, which is white. When oxygen is passed over copper (in the presence of heat), an oxidation reaction occurs, resulting in the formation of black copper oxide. The greater change in mass observed when they start to burned.
What is copper metal ?Copper is a mineral and an element that is essential to our daily lives. It is a significant industrial metal due to its high ductility, malleability, thermal and electrical conductivity, and corrosion resistance. It is a necessary nutrient in our diet.
Metals are a class of materials that have high electrical and thermal conductivity, as well as malleability, ductility, and high light reflection. Copper (Cu), aluminium (Al), and other metals are examples.
The combustion of magnesium ribbon is a combined reaction. This is due to the fact that magnesium reacts with oxygen to form the single product magnesium oxide. When magnesium ribbon is burned in air, it reacts with the oxygen in the air to form magnesium oxide.
Thus, 3g of clean mg ribbon and 8g of clean copper metal were burnt separately in equal volume of air and both mass reacted completely with air the greater change in mass observed when they start to burned.
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PLEASE HELP WILL MARK AS BRAINIEST
Answer:
for 1st question the answer is maybe 4th or 1st ( I think 4th ).
and for the 2nd question 4th ( consumers ) option is the answer
and the answer of third question is omnivores.
Answer:
1) The transfer or flow of energy.
2)Consumers
3)Omnivores
May it help you
calculate the rf value for a spot in a chromatography experiment if the solvent moved 14.2 cm and the spot moved 9.9 cm from the origin.
Rf will be 0.697
Retention factor can be defined as;
The ratio of distance travelled by substance to the distance travelled by solvent. Substances start at the origin. The starting point of the compound is called the origin. This is where we measure the distance moved by the substance.
According to the question;
The given data is:
spot distance = 9.9 cm
solvent distance = 14.2 cm
We will have to find the retention factor value:
Rf = ?
The formula to find Rf is as follows;
Rf = spot distance / solvent distance
Rf = 9.9 cm / 14.2 cm
The answer after the solution is :
Rf = 0.697
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Match the following aqueous solutions with the appropriate letter from the column on the right. 1.0.147 m
2.0.205 m
3.8.75×10 −2
mCr 3
(CH 3
COO) 3
4.0.380 m
Ni(NO 3
) 2
CuSO 4
C. Third highest boiling point Ethylene glycol (nonelectrolyte)
A. Highest boiling point B. Second highest boiling point D. Lowest boiling point
Matching the solutions with the appropriate letters, we have:
0.147 m CuSO4 - C
0.205 m Ni(NO₃)₂ - B
8.75 × 10⁻² m Cr(CH₃COO)₃ - D
0.380 m ethylene glycol - A
Based on the information provided, we need to match the given aqueous solutions with the appropriate letter from the column on the right. The options are:
A. Highest boiling point
B. Second highest boiling point
C. Third highest boiling point
D. Lowest boiling point
Let's analyze each solution and determine their boiling points:
0.147 m CuSO₄ (copper sulfate) - This is an ionic compound and will dissociate into Cu²⁺ and SO₄²⁻ ions in water. As an electrolyte, it will exhibit colligative properties, including an increase in boiling point. Therefore, this solution would have the third highest boiling point. So the match is C.
0.205 m Ni(NO₃)₂ (nickel nitrate) - Similar to the previous solution, this is also an ionic compound and will dissociate into Ni²⁺ and NO³⁻ ions in water. It will exhibit colligative properties, resulting in a higher boiling point. This solution would have the second highest boiling point. So the match is B.
8.75 × 10⁻² m Cr(CH₃COO)₃ (chromium(III) acetate) - This is also an ionic compound and will dissociate into Cr³⁺ and CH₃COO⁻ ions in water. Like the previous solutions, it will exhibit colligative properties, leading to an increase in boiling point. This solution would have the lowest boiling point. So the match is D.
0.380 m ethylene glycol - Ethylene glycol is a nonelectrolyte, and it does not dissociate into ions in water. Therefore, it does not exhibit colligative properties to the same extent as ionic compounds. However, it still has a significant effect on the boiling point due to its high boiling point itself. Ethylene glycol has the highest boiling point among the given options. So the match is A.
Matching the solutions with the appropriate letters, we have:
0.147 m CuSO₄ - C
0.205 m Ni(NO₃)₂ - B
8.75 × 10⁻² m Cr(CH₃COO)₃ - D
0.380 m ethylene glycol - A
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what would happen to a piece of iron if it were placed close to this device
Answer: c) it moves toward a piece of iron
Explanation:
Carbon cycle – What are the main reservoirs
of the carbon cycle? Where do the inorganic and organic carbon
cycles interact? What are the major differences and similarities
between the inorganic and organic carbon?
The main reservoirs of the carbon cycle are the atmosphere, oceans, land (including vegetation and soils), and fossil fuels. In these reservoirs, carbon exists in both inorganic and organic forms.
The inorganic carbon cycle involves the exchange of carbon dioxide (CO2) between the atmosphere and oceans through processes like photosynthesis and respiration.
Organic carbon, on the other hand, is found in living organisms, dead organic matter, and soil organic matter. It is cycled through processes such as decomposition and consumption by organisms. The interactions between the inorganic and organic carbon cycles occur primarily in the biosphere, where photosynthesis converts inorganic carbon into organic carbon compounds. While inorganic carbon is primarily in the form of CO2, organic carbon is present in complex organic molecules. Both forms of carbon play crucial roles in energy transfer, nutrient cycling, and climate regulation.
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For a hydrogen atom, calculate the wavelength of the four visible transitions in the Balmer series. Recall that for the Balmer series ny = 2 and n, ≤7. Calculate to 4 sig figs.
The wavelength of the transition for n=7 in the Balmer series is 397.0 nm.
The Balmer series is a pattern of spectral emission lines observed in the visible region of the hydrogen emission spectrum, which corresponds to transitions from higher levels down to the energy level with
n=2.
The Rydberg formula can be used to calculate the wavelengths of spectral lines for hydrogen. It is given by;
`1/λ=R(1/ni^2 - 1/nf^2)`
where R is the Rydberg constant with a value of 1.0973731568539 x 10^7 m^(-1).
For the Balmer series, ni ≥ 3 and nf = 2.
Therefore, `1/λ=R(1/4-1/n^2)`
Where n is an integer,
n=3,4,5,6,7 for the Balmer series.
We can now substitute the values of n into the equation and solve for λ. Thus, for n=3:`1/λ=R(1/4-1/9)`From this equation, we can solve for
λ:`λ= 656.3 nm`
Thus, the wavelength of the transition for
n=3 is 656.3 nm.
For n=4:`1/λ=R(1/4-1/16)`
From this equation, we can solve for
λ:`λ= 486.1 nm`
Thus, the wavelength of the transition for n=4 is 486.1 nm.
For n=5:`1/λ=R(1/4-1/25)`
From this equation, we can solve for
λ:`λ= 434.0 nm`
Thus, the wavelength of the transition for n=5 is 434.0 nm.
For n=6:`1/λ=R(1/4-1/36)`
From this equation, we can solve for λ:`λ= 410.2 nm`
Thus, the wavelength of the transition for n=6 is 410.2 nm.
For n=7:`1/λ=R(1/4-1/49)`From this equation, we can solve for λ:
`λ= 397.0 nm`
Thus, the wavelength of the transition for n=7 is 397.0 nm.
Therefore, the wavelength of the four visible transitions in the Balmer series are;
λ(n=3) = 656.3 nmλ(n=4)
= 486.1 nmλ(n=5)
= 434.0 nmλ(n=6)
= 410.2 nm.
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Which of the following is a synthesis reaction?
AgNO3 + NaCl → AgCl + NaNO3
CH4 + O2 → CO2 + H2O
SO3 + H2O → H2SO4
Cu + AgNO3 → Ag + CuNO3
Synthesis reaction
It is a reaction in which 2 or more reactants combine with each other to form one product .
Check option C
Sulphate and water are combining to form sulfuric acid .
Hence option C is correct
Answer:
SO3 + H2O => H2SO4
Explanation:
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