Organ pipe A, with both ends open, has a fundamental frequency of 475 Hz. The third harmonic of organ pipe B, with one end open, has the same frequency as the second harmonic of pipe A. Use 343 m/s for the speed of sound in air. How long are (a) pipe A and (b) pipe B?

Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.

1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.

2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:

Element   | Electron Configuration | Group | Period |

--------------------------------------------

Hydrogen  | 1s^1                              | 1     | 1      |

Lithium       | [He] 2s^1                     | 1     | 2      |

Carbon       | [He] 2s^2 2p^2          | 14    | 2      |

Oxygen      | [He] 2s^2 2p^4          | 16    | 2      |

Neon          | [He] 2s^2 2p^6          | 18    | 2      |

--------------------------------------------

3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.

- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.

- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.

By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.

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The diagram below that shows a free-body diagram is the third option m

A free-body diagram shows all the forces acting on a single object. In this case, the object is m3. The forces acting on m3 are:

The force F1 exerted by m1. This force is directed to the left. The force F2 exerted by m2. This force is directed to the right.

The force F3 exerted by m3. This force is directed to the left.

The net force on m3 is zero, since the forces F1 and F2 are equal and opposite. This means that m3 is in equilibrium.

Diagram (a) shows the forces F1 and F2, but it does not show the force F3. This is incorrect, since F3 is also acting on m3. In conclusion,the correct option is C.

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Answer:

The atomic and molecular interactions unveil the bulk properties of matter in our environment by ways of the fact that everything in the whole universe is made of either atoms, molecules or even ions

How matter is made up of atoms and molecules?

It has been proven practically everything in the whole universe is matter and everything which interact with matter is also matter. This explains to us the reasons why matter could be atoms, molecules or ions.

That being said, some substances (matter) is made up of atoms of elements, some made up of molecules or atoms and molecules and others ions or both. However, matter is anything which has mass and occupies space.

In conclusion, we can now conclude from the explanation above that the properties of matter are as a result of the interaction which exists between matter at the atomic and molecular level.

Answer:

s=50m

Explanation:

you can use the formula

s=ut+1/2at²

s=0t+1/2(1)10²

=1/2(100)

=50

I hope this helps

120V is the line-to-neutral voltage .

It is defined as the voltage of a power transmission circuit or distribution circuit up to the point of transformation or utilization.

The secondary line voltage is \(V_{L} = 280 V\)

The notation AC indicates that the current is an alternating current.

The given formula is \(V_{ph} = \frac{V_{L} }{\sqrt{3} }\)

Substitute  208 V into the formula

\(V_{ph} = \frac{V_{L} }{\sqrt{3} } \\\\V_{ph} = \frac{208V}{\sqrt{3} } \\\\= 120 (Approx)\)

So, the line-to-neutral voltage is 120 V.

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\(\Huge\boxed{\boxed{\dfrac{4}{5}\ \text{meters}}}\)

Let's start by finding the time it takes for the dog to reach a velocity of \(4\) m/s.

We can use the following equation, where \(v_i\) is initial velocity, \(v_f\) is final velocity, \(t\) is time, and \(a\) is acceleration.

\(v_f-v_i=at\)

We're trying to solve for \(t\) first, so divide both sides by \(a\).

\(\dfrac{v_f-v_i}{a}=t\)

Substitute in the known values.

\(\dfrac{4-0}{10}=t\)

\(\dfrac{4}{10}=t\)

\(\dfrac{2}{5}=t\)

Now, we can use the following formula to find the distance.

\(s=v_it+\dfrac{1}{2}at^2\)

Substitute in the known values.

\(s=0*\dfrac{2}{5}+\dfrac{1}{2}*10*(\frac{2}{5})^2\)

Anything multiplied by \(0\) is

\(s=\dfrac{1}{2}*10*(\frac{2}{5})^2\)

Just simplify from there.

\(s=\dfrac{1}{2}*10*\dfrac{4}{25}\)

\(s=5*\dfrac{4}{25}\)

\(s=\dfrac{20}{25}\)

\(s=\boxed{\dfrac{4}{5}}\)

Hey there!

The hind legs of the dog create it to accelerate.

We know the mass of the dog is 36km (m).

We know that the acceleration of the dog it 10m/s² (a).

Find the average force with the formula [ f = ma ] where m = mass and a = acceleration.

f = 36*10

f = 360 newtons

We don't know the traveled distance but we do know that the starting speed of the dog was 0m/s and the ending speed was 4m/s.

We can use the formula [ vf² = vo² + 2ad ] where vf = final speed, vo = starting speed, a = acceleration, and d = distance.

We know all the variables except the distance, so we are going to solve for d.

(4)² = (0)² + 2(10)(d)

16 = 0 + 20d

16 = 20d

16/20 = 20d/20

0.8 = d

Therefore, the dog runs 0.8 meters until it reaches 4m/s.

Best of Luck!

Answer:

\(\displaystyle \sqrt{\frac{(5/2)\, (g - a)\, m\, R^{2}}{M^{2}\, a}}\), assuming that the tension in the rope is the only tangential force on the sphere (\(g\) denote the gravitational acceleration.)

Explanation:

The forces on the bucket are:

Since the weight of the bucket and the tension from the rope are in opposite directions, the magnitude of the net force would be:

\(\begin{aligned} \|\text{Net Force}\| =\; & \|\text{Weight}\| - \|\text{Tension}\| \end{aligned}\).

The upward tension in the rope prevents the bucket from accelerating at \(g\) (free fall.) Rather, the bucket is accelerating at an acceleration of only \(a\). The net force on the bucket would be thus \(m\, a\).

Rearrange the equation for the net force on the bucket to find the magnitude of the tension in the rope would be:

\(\begin{aligned} & \|\text{Tension}\| \\ =\; & \|\text{Weight}\| - \|\text{Net Force}\| \\ =\; & m\, g - m\, a \\ =\; & (g - a)\, m\end{aligned}\).

At a distance of \(R\) from the center of the sphere, the tension in the rope \((g - a)\, m\) would exert a torque of \((g - a)\, m\, R\) on the sphere. If this tension is the only tangential force on this sphere, the net torque on the sphere would be \((g - a)\, m\, R\!\).

Let \(M\) denote the mass of this sphere. The moment of inertia of this filled sphere would be \(I = (2/5)\, M^{2}\).

Therefore, the magnitude of the angular acceleration of this sphere would be:

\(\begin{aligned}& \|\text{Angular Acceleration}\| \\ =\; & \frac{\|\text{Net Torque}\|}{(\text{Moment of Inertia})} \\ =\; & \frac{(g - a)\, m\, R}{(2/5)\, M^{2}} \end{aligned}\).

The bucket is accelerating at a magnutide of \(a\) downwards. The rope around the sphere need to unroll at an acceleration of the same magnitude, \(a\!\). The tangential acceleration of the sphere at the surface would also need to be \(\! a\).

Since the surface of the sphere is at a distance of \(R\) from the center, the angular acceleration of this sphere would be \((a / R)\).

Hence the equation:

\(\begin{aligned}& \frac{(g - a)\, m\, R^{2}}{(2/5)\, M^{2}} = \|\text{Angular Acceleration}\| = \frac{a}{R} \end{aligned}\).

Solve this equation for \(M\), the mass of this sphere:

\(\begin{aligned}& \frac{(g - a)\, m\, R^{2}}{(2/5)\, M^{2}} = \frac{a}{R} \end{aligned}\).

\(\begin{aligned}M^{2} &= \frac{(g - a)\, m\, R^{2}}{(2/5)\, a} \\ &= \frac{(5/2)\, (g - a)\, m\, R^{2}}{a}\end{aligned}\).

\(\begin{aligned}M&= \sqrt{\frac{(5/2)\, (g - a)\, m\, R^{2}}{a}}\end{aligned}\).

The part of the mind that  interprets what your seeing, hearing, or thinking about in the moment is visual cortex of the brain.

The primary visual cortex is the primary cortical region of the brain that receives, integrates, and processes visual information relayed from the retinas.

This primary visual cortex is located in the occipital lobes at the back of the head, that the brain uses to process image to our conscious awareness.

Thus, the part of the mind that  interprets what your seeing, hearing, or thinking about in the moment is visual cortex of the brain.

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Answer:conscious mind

Explanation:

C. 1.1 m/s east

Step 1

Diagram

Step 2

Velocity is defined as a vector measurement of the rate and direction of motion.

we can find the manginutde of the velocity using the formula:

so

a)let

b) now, replace in the formula

so, the magnitude is 1.1

c) finally, The direction of a vector can be described as beingeast or west or north or south,therefore, as the person goes from west to east the answer is

C. 1.1 m/s east

I hope this helps you

The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

The formula for acceleration due to gravity is:

g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet

In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.

Therefore, g is proportional to 1/r².

So, using the ratio of radii given (1.8), we can write:

r = 1.8 x r Earth, where r Earth is the radius of Earth.

Substituting this value of r in the formula for acceleration due to gravity, we get:

g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²

We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².

Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:

gh = (1/3.24) x g Earth = 3.02 m/s²

Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

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To balance the lever, the 20kg mass will be positioned at 1.5m

When all the forces that act upon an object are balanced, the object is said to be in a state of equilibrium. The forces are considered to be balanced if the rightward forces are balanced by the leftward forces and the upward forces are balanced by the downward forces. This however does not necessarily mean that all the forces are equal to each other.

The product of mass and distance of right hand side should be equal to the product of mass and distance of the left hand side.

m1 x d1 = m2 x d2

where m1 = 15kg

d1 = 2m

m2 = 20kg

m1 x d1 = m2 x d2

Therefore;

d2 = (m1 x d1 )/m2

d2 = (15 x 2)/20

d2 = 30/20

d2 = 1.5m

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The image would be 53 cm from the lens of your eye.

What is Lens?
A lens is a transmissive optical tool that uses refraction to focus or disperse a light beam. A compound lens is made up of multiple simple lenses (elements), typically arranged along a common axis, as opposed to a simple lens, which is one solid piece of transparent material. Glass or plastic are used to make lenses, which are then polished or moulded into the desired shape. In contrast to a prism, which simply refracts light without focusing it, a lens can focus light to create an image. Lenses are also devices that focus or disperse waves as well as radiation other than visible light, such as explosive lenses, microwave lenses, particle lenses, and acoustic lenses.

Lenses are a common component of telescopes, binoculars, and cameras, among other imaging devices.

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Answer:

Explanation:

1. First draw a free body diagram of the scenerio (a block sliding down a a slant surface).
2. Then we analyze the forces and write equations that satisfy Fnet = ma. This will give us the acceleration as the block slides down the surface.

3. Last, we can use the kinematic equation (vf^2 = vi^2 + 2as) and to solve the final speed of the block.

Students monitor the progress of a marble by measuring its speed and distance travelled. They calculate the speed using the formula Speed = Distance / Time.

How do you find the velocity of a marble?

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Acceleration of an object down a slope increases as the angle of the slope is increased

(a) The ball that arrives at the end first is ball A

(b) Racing cyclist select areas having a steeper slope on a hill that gives them a velocity boost

Reason:

A drawing to clarify the explanation and to represent the possible drawing of figure 3 in the question is attached

The acceleration of the balls on the inclined plane is given by the following formula;

Force, F = m·g·sin(θ)

Therefore, the acceleration, a, of ball A and ball B at the part having the same slope are equal

The acceleration of ball A at the part of its track that is almost vertical is approximately, g, (acceleration due to gravity). The velocity at the end of the drop is u' = v + g·Δt, therefore;

(b) The principle is applied by racing cyclist by selecting a steeper path that gives them a velocity boost much larger than what is being normally applied, by the force applied by pedaling

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The acceleration of the box that has a mass of 4 kg and a coefficient of kinetic friction of 0.2, when moved by an exerted force of 58 N, is 10.06 m/s².    

The acceleration of the box can be calculated with the sum of the forces acting on the x-direction:

\( \Sigma F_{x} = ma \)

We will not take into account the forces acting on the y-direction since we need to find the acceleration of the box when it is moving (x-direction).

\( T_{x} - F_{\mu} = ma \)    (1)

Where:

From equation (1) we have:

\( Tcos(34) - \mu N = ma \)  

\( Tcos(34) - \mu mg = ma \)  

Hence, the acceleration is:

\( 58N*cos(34) - 0.2*4 kg*9.81 m/s^{2} = 4 kg*a \)  

\( a = \frac{58N*cos(34) - 0.2*4 kg*9.81 m/s^{2}}{4 kg} = 10.06 m/s^{2} \)

Therefore, the acceleration of the box when the box is moving is 10.06 m/s².

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Answer:

C.

Explanation:

Ultraviolet light shining on the minerals will cause them to give off visible light.

The escape velocity (Ve) which is required by the particle to escape the gravitational field of the Earth is 110.87  × 10³ km/sec.

Escape velocity is the minimum velocity that a moving body such as a rocket must possess to escape from the gravitational field of a celestial body like the Earth and move outward into space.

Particle is above the surface of Earth (r) = 1600 km = 16 × 10⁵m

Radius of Earth (Re) = 6400 km = 64 × 10⁵m

Acceleration due to gravity (g) = 9.8m/s²

To find the value of escape velocity (Ve),

We know,

Ve = √2 gR

Ve = √2 g (Re + r)

Ve = √2 g (64 + 16) × 10⁵

Ve = √2 × 9.8 × 80 × 10⁵

Ve = 1108.743 × 10⁵

Ve =  110.8743 × 10⁶

Ve = 110.87 × 10³ km/sec.

Therefore, the escape velocity (Ve) is 110.87 × 10³ km/sec.

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The force experienced by an object is 144.76 N.

O\ption B is correct.

A force is described as an influence that can change the motion of an object or that can cause an object with mass to change its velocity

The force can be calculated using the equation of force = change in momentum / time.

So, force = 1.52 kg·m/s / 0.0105 s = 145 N

Therefore, the answer is 144.76 N.

Some types of force available includes the following:

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The gravitational field strength at Pluto's surface is 5.827 x 10⁹ N/kg.

The force of gravity between the object and Pluto's surface is 5.827 x 10¹³ N.

The gravitational field strength at Pluto's surface is calculated as follows;

G_E = GM/r²

where;

G_E = (6.67 x 10⁻¹¹ x 1.2 x 10²²) / (1.172 x10)²

G_E = 5.827 x 10⁹ N/kg

The force of gravity between the object and Pluto's surface is calculated as follows;

F = GMm/r²

F = (6.67 x 10⁻¹¹ x 1.2 x 10²² x 100) /(1.172 x 10)²

F = 5.827 x 10¹³ N

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Answer:

(1.8 × 10^9) meters in one minute

Explanation:

To determine how far light can travel in one minute, we need to multiply its speed by the number of seconds in a minute.

The speed of light is 3 × 10^8 meters per second.

There are 60 seconds in a minute.

Therefore, the distance light can travel in one minute is:

Distance = Speed × Time

Distance = (3 × 10^8 meters per second) × (60 seconds)

Calculating this, we get:

Distance = 3 × 10^8 meters/second × 60 seconds

Distance = 18 × 10^8 meters

Distance = 1.8 × 10^9 meters

So, light can travel approximately 1.8 billion (1.8 × 10^9) meters in one minute.

The y component

where mg is the weight of the car i.e. 1150kg

and

Substituting the known values in the equation we get,

That is y component of W is 173.95 N

Answer: 4.97 years

Explanation: I got the answers right

By the use of the Kepler's laws, the period of the orbit is 5.22 years. Option D

We know that when we are dealing with the orbits that our mind would have to be turned to the Kepler's law. In the Keplers law, we see the relationship that cold be used in the attempt to connect the period of the orbit to the radius of the semi major axis of an orbiting body.

By the application of the Keplers third law;

T^2 = r^3

The statement of the law is that the square of the period of the objects orbit is equal to the cube of the length of the semi major axis.

We then know that;

T = period

r = distance

Hence;

T = r^3/2

T = (3.01 )^3/2

T = 5.22 years

The period of the object is seen to be 5.22 years from the calculation above.

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The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people

We'll begin by converting 175 cm to m. This can be obtained as illustrated below:

100 cm = 1 m

Therefore,

175 cm = (175 cm × 1 m) / 100 cm

175 cm = 1.75 m

Thus, 175 cm is equivalent to 1.75 m

The number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:

Number of people needed = Height of tower / height of a person

Number of people needed = 553 / 1.75

Number of people needed = 316 people

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The volume flow rate of the water through the hose is 4.58×10⁻⁴m³/sec.

Flow-restrictive lesions in the carotid, vertebral, and intracranial vessels have been assessed for severity and hemodynamic significance using MR volume flow rate measurements. The volume flow rate distal to the stenosis may significantly decrease as a result of a severe stenosis.

The volume flow rate () is the amount of fluid that moves through a cross-sectional area in a given amount of time. Volume flow rate and mass flow rate are related by the conservation of mass rule.

Given,

Radius = 0.0137 m

Area =  πr²

Area = 3.14×(0.0137)²

Area = 0.000589m².

Volume filled in 90sec = 25L

Rate = 25/90 = 0.27L/sec

Volume flow rate =  0.27× 1000/0.000589

Volume flow rate = 4.58×10⁻⁴m³/sec.

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To find:

The direction of the magnetic force.

Explanation:

The direction of the magnetic field or a magnetic force on a charged particle is given by the right-hand rule. It states that when the thumb, middle finger, and index finger are held in such a way that they are perpendicular to each other if the thumb is pointing in the direction of the positive charge and the middle finger is pointing in the direction of the magnetic force then the index finger will point in the direction of the magnetic field.

Thus applying this rule we find that the index finger will be pointing to the east.

Final answer:

Thus the direction of the magnetic field is east.

The current in the series circuit  across a 9.0 V potential difference is determined as 0.333 A.

The current in the series circuit is determined by applying ohms law as shown below;

V = IR

where;

R = 12 Ω  + 15 Ω  = 27 Ω

I = V/R

I = 9/27

I = 0.333 A

Thus, the current in the series circuit  across a 9.0 V potential difference is determined as 0.333 A.

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More energy to escape gravitational pull of the Earth than to escape the pull of Moon is calculated as : D) 5

Escape velocity is the minimum speed needed for free, non-propelled object to escape from gravitational influence of primary body.

Energy required to escape the gravitational pull of a planet or a moon is:

\(\mathrm{E = (1/2)mv^2}\)

E is the energy required, m is mass of the object being launched, and v is escape velocity.

E(Earth) = (1/2)(1 kg)\(\mathrm{(11,000 m/s)^2}\) = \(\mathrm{6.05 \times 10^7 J}\)

E(Moon) = (1/2)(1 kg)\(\mathrm{(2,400 m/s)^2}\) = \(\mathrm{2.88 \times 10^6 \ J}\)

E(Earth) - E(Moon) = \(\mathrm{6.05 \times 10^7 J}\) - (\(\mathrm{2.88 \times 10^6 \ J}\)) = \(\mathrm{5.76 \times 10^7 \ J}\)

Answer D) is correct.

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