The following molecules are substrates or products in the glycolytic pathway are glucose and pyruvate
The glycolytic pathway is a series of enzymatic reactions that converts glucose into two molecules of pyruvate, ATP, and NADH. The glycolytic pathway is a metabolic pathway that breaks down glucose to produce ATP. The glycolytic pathway is a metabolic pathway that breaks down glucose to produce ATP. The glycolytic pathway is a series of enzymatic reactions that converts glucose into two molecules of pyruvate, ATP, and NADH.
Glucose is a substrate in the glycolytic pathway that is converted into pyruvate and pyruvate is the end product of the glycolytic pathway that is used in other metabolic pathways to produce energy. Glycolysis occurs in the cytoplasm of cells and requires the presence of enzymes that catalyze the reactions. The glycolytic pathway is an important pathway that produces energy for cells in the body. The glycolytic pathway is important in the production of ATP and NADH, which are important molecules in cellular metabolism. The following molecules are substrates or products in the glycolytic pathway are glucose and pyruvate
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What is Dowex 50WX4 ion-exchange resin used for?
Dowex 50WX4 ion-exchange resin is a type of resin that is commonly used in various industrial processes for purification and separation purposes. This resin has a high selectivity for certain ions and can be used to remove impurities or separate specific ions from a solution.
Another common use of Dowex 50WX4 ion-exchange resin is in the pharmaceutical industry. This resin can be used to separate and purify various drugs and active ingredients, helping to ensure their quality and efficacy.
Overall, Dowex 50WX4 ion-exchange resin is a versatile and effective tool for a wide range of purification and separation applications. Its unique properties make it an ideal choice for industries ranging from water treatment to pharmaceuticals, and it continues to be a popular choice among researchers and manufacturers alike.
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gold, au, is found in which block of the periodic table?
Gold (Au) is located in group 11 and the d-block of the periodic table.
Gold (Au) is found in the d-block, specifically in group 11, of the periodic table. The d-block elements are also known as the transition metals. These elements are characterized by the filling of the d orbitals in their electron configuration.
Gold is located in period 6 of the periodic table, meaning it has six electron shells. Its atomic number is 79, indicating that it has 79 protons in its nucleus and 79 electrons orbiting the nucleus. The electron configuration of gold is [Xe] 4f^14 5d^10 6s^1.
The d-block elements are known for their characteristic properties such as high melting and boiling points, good electrical and thermal conductivity, and the ability to form colored compounds. Gold, in particular, is well-known for its attractive yellow color, high malleability, and resistance to corrosion. These properties make gold highly valued and widely used in jewelry, investment, and various industries.
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the most common type of regenerated fiber, which is derived from cellulose and is mostly plant in origin, is rayon.
It is true that the most common type of regenerated fiber, which is derived from cellulose and is mostly plant in origin, is rayon.
The most widely used type of regenerated fibre is rayon, which is mostly derived from plants and is manufactured from cellulose. Synthetic polymer fibres with a cellulose base are all derived from petroleum.
Dietary fibres are produced from indigestible plant parts and frequently consist of long, repeated chains of carbohydrates. The majority of fibers come from cereal and grain husks, which contain the insoluble fibers cellulose and lignin. The bulk of plant fibers are made of cellulose, sometimes in combination with other materials like lignin.
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1. What was the mass of a sample of water if the addition of 4280 joules raised the temperature of the sample from 22.00C to 34.50C?
2. What is the specific heat of a sample of an alloy if 3750 joules of heat are released when a 315 gram sample of alloy cools from 78.00C to 28.40C?
3. The specific heat of iron is 0.448 J/g0C. What will be the final temperature if 35000 joules of heat are added to a 454 gram sample of iron at 24.00C?
4. What will be the final temperature when 8750 joules are added to 75.0 grams of water at 23.00C?
5. When 38800 joules were added to a sample of iron, specific heat 0.448 J/g0C, the temperature rose from 24.5 deg C to 178 deg C. What was the mass of the iron sample?
Explanation:
Number 1
Q = 4280J
mass = x
∆∅ = 34.5 - 22
∆∅ = 12.5°C
Specific heat capacity of water = 4200J
Q = mc∆∅
4280 = x(4200)(12.5)
4280 = 52500x
x = 4280/52500
x = 0.0815kg
Number 2
c = x
Q = 3750
m = 315g
∆∅ = 78 - 28.4
∆∅ = 49.6°C
Q = mc∆∅
3750 = 315×x×49.6
3750 = 15624x
x = 3750/15624
x = 0.2400J(g°C)-¹
Number 3
c = 0.448
Q = 35000
m = 454g
∆∅ = x
Q = mc∆∅
35000 = 454(0.448)(x)
35000 = 203.392x
x = 35000/203.392
x = 172.0815
∅2 - ∅1 = ∆∅
∅2 = ∆∅ + ∅1
∅2 = 172.0815 + 24
∅2 = 196.0815
∅2 = 196°C
Number 4
Q = 8750J
m = 75g = 0.075
c = 4200J/kg/°C
∆∅ = x
Q = mc∆∅
8750 = 0.075(4200)∆∅
8750 = 315×x
x = 8750/315
x = 27.7778
∅2 - ∅1 = 27.7778
∅2 = 27.7778 + ∅1
∅2 = 27.7778 + 23
∅2 = 50.7778
∅2 = 50.8°C
Number 5
Q = 38800J
c = 0.448J/(g°C)
∆∅ = 178 - 24.5
∆∅ = 153.5°C
m = x
Q = mc∆∅
38800 = x × 0.448 × 153.5
38800 = 68.768x
x = 38800/68.768
x = 564.2159
x = 564g
1. what type of polymer would you obtain if sorbital (a sugar alcohol found in sugar free gum) was used as a plasticizer addictive?
2a. Starch-borate and starch-glycerol polymers have been used for encapsulation of pharmaceutical drugs or pesticides. Explain what effect ths might have and why it would be beneficial.
2b. Are these polymers considered to be biodegradable? why or why not?
1. The type of polymer that would you obtain if sorbitol is a polyol.
2a. The use of starch-borate and starch-glycerol polymers for the encapsulation of pharmaceutical drugs or pesticides would have a number of beneficial effects.
2b. Yes, these polymers are considered to be biodegradable.
1. The type of polymer that would you obtain if sorbitol (a sugar alcohol found in sugar-free gum) was used as a plasticizer additive is a polyol. This is because sorbitol is a polyol, which is a substance used to modify the properties of polymers. The process of polymer modification involves adding polyols to the polymer matrix, which helps to reduce the glass transition temperature of the polymer. Sorbitol can be used as a plasticizer addictive because it is a natural and non-toxic compound that is biodegradable.
2a. The use of starch-borate and starch-glycerol polymers for the encapsulation of pharmaceutical drugs or pesticides would have a number of beneficial effects. These polymers are natural and non-toxic, and they are biodegradable, which means that they do not pose a risk to the environment. Additionally, they can be used to modify the properties of the drugs or pesticides, making them more effective and reducing their toxicity.
2b. Yes, these polymers are considered to be biodegradable. This is because they are made from natural materials that can be broken down by biological processes. Starch-borate and starch-glycerol polymers are particularly attractive for use in biodegradable materials because they are non-toxic and biocompatible. They can be used in a variety of applications, including packaging materials, agricultural films, and medical devices, where their biodegradability is an important factor.
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n the diagram shown, when an object ‘X’ is brought near the ring shaped magnet, the magnet moves away from it. Four friends are discussing what they can say about X. Nikhil: X can be a piece of any metal. Shailaja: X can only be a piece of iron. Akash: X is definitely a magnet. Vinay: X can neither be a magnet or an iron piece. Who is correct?
Answer:
Akash
Explanation:
it could be a magnet with the same poles facing eachoher
what happens to the volume of an ideal gas if its pressure is halved and its kelvin temperature is doubled, assuming the moles of gas does not change? what happens to the volume of an ideal gas if its pressure is halved and its kelvin temperature is doubled, assuming the moles of gas does not change? the volume remains constant the volume decreases by a factor of 4 the volume quadruples the volume doubles
The volume of an ideal gas if its pressure is halved and its kelvin temperature is doubled than the volume quadruples.
The ideal gas equation is given as :
P V = n RT
from the question , is given that :
P2 = P1 / 2
T2 = 2 T1
then from the ideal gas equation we get :
P1 V1 / T1 = P2 V2 / T2
P1 V1 / T1 = ( P1 / 2 × V2 ) 2 T1
V2 = 4V1
Thus, The volume of an ideal gas if its pressure is halved and its kelvin temperature is doubled than the volume quadruples.
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amino acids and carbohdrates are absorbed in teh small intestine.T/F
The given statement "amino acids and carbohdrates are absorbed in teh small intestine" is True. Amino acids and carbohydrates are indeed absorbed in the small intestine.
After food is broken down into smaller molecules through digestion, the absorption process takes place in the small intestine, where nutrients are absorbed into the bloodstream to be transported to various cells and tissues of the body.
The small intestine has specialized structures called villi and microvilli, which increase the surface area available for absorption.
Amino acids, the building blocks of proteins, are absorbed through active transport mechanisms, while carbohydrates are primarily absorbed as monosaccharides, such as glucose, through facilitated diffusion or active transport.
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PLEASE HELPP!
True or False: Hydrogen is an alkali metal.
Answer: falso
Explanation:
What is the mass of 0.05 moles of hydrogen
Answer:
The mass of 0.05 moles of Hydrogen is 0.05 grams
Explanation:
We know,
Atomic mass of Hydrogen= 1 g
Now,
1 mole of Hydrogen = 1 g
∴ 0.05 moles of Hydrogen= (1 X 0.05) g
= 0.05 g
So, the mass of 0.05 moles of Hydrogen is 0.05 grams
What mass of K reacted when
6.41 g S reacted completely to
form 10.32 g K2S?
PLEAS HELP
Answer:
3.91 on Acellus
Explanation:
1.88 g potassium would be have been used to produce 10.32 g K2S, meaning that 6.41 g S would be left over.
What is potassium ?The chemical element with the atomic number 19 and the letter K is potassium. Potassium is a silvery-white metal that may be easily and gently sliced with a knife. Within seconds of exposure, potassium metal quickly combines with air oxygen to produce flaky, white potassium peroxide.
Potassium can be obtained as a dietary supplement and naturally in many foods. Its primary function in the body is to support the maintenance of regular fluid levels inside our cells. It's opposite, sodium, keeps fluid levels within cells normal. Additionally, potassium supports proper blood pressure and aids in the contraction of muscles.
2K + S → K₂S
two moles K react with one mol S
6.41 g S react with K to formed 10.32g of K₂S
stoichiometric ratio of K:S is 2.44
reaction conditions your supplied ratio of K:S is 1.28
Therefore, sulfur is in excess and potassium is the limiting reagent.
The reaction of 6.41 g S would produce 10.32g K2S
The reaction of 6.41 g S would produce 6.41 (10.32/78.2) = 6.47 g K2S
Thus, 1.88 g K would be have been used to produce 10.32 g K2S, meaning that 6.41 g S would be left over.
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In Philip’s French class, the students are learning how to pronounce closed vowels and open vowels. The students are most likely studying French __________. A. syntax B. phonemes C. semantics D. morphemes
Answer:
It sounds like they are studying French phonemes
Explanations:
I just learned this.
The students were most likely studying French phonemes.
Words are distinguished from each other by respective sounds of the vowels in the word. There are open vowels and there are closed vowels. These exist in every language.
The part of language learning that has to do with the differentiation of pronunciation of sounds is called phonemes. This means that the students were most likely studying French phonemes.
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Hypoxic areas such as in the Gulf of Mexico develop when
A. oxygen levels fall below 5ppm.
B. large amounts of nitrate are added into the water.
C. die-off from a large phytoplankton bloom uses up the oxygen in water.
D. methyl-mercury is added to water.
Hypoxic areas, such as those found in the Gulf of Mexico, develop primarily due to option C: die-off from a large phytoplankton bloom uses up the oxygen in water. The correct option is C.
Phytoplankton blooms occur when there is an excessive growth of microscopic algae in the water, often caused by high nutrient levels, such as nitrogen and phosphorus.
These blooms can create dense layers of algae on the water surface. As the algae die and decompose, bacteria consume the organic matter and consume oxygen in the process, leading to a decrease in oxygen levels in the water.
This process is known as eutrophication, and it can deplete oxygen concentrations to a critical level, resulting in hypoxic conditions.
Oxygen levels below 5ppm (option A) can contribute to hypoxia, but the primary cause is the consumption of oxygen by the decomposition of organic matter from the phytoplankton bloom (option C).
Nitrate additions (option B) and the presence of methyl-mercury (option D) can have additional negative impacts on aquatic ecosystems, but they are not the main drivers of hypoxia in this context. The correct option is C.
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Which electron in an atom (Z=17) is the most shielded from
nuclear charge?
A. an electron in the 2s
B. an electron in the 3p
C. an electron in the 3d
D. an electron in the 1s
Answer:
option no. C is correct
an electron in the 3d
True or false? First nations people along the west coast of british columbia used smelting technology to create copper plaques
First nations people along the west coast of British Columbia used smelting technology to create copper plaques is false.
Smelting process is the form of extractive metallurgy to produce a metal from its ore. it is the process of melting and separation of charges . it is extensive energy process. Plaques are made by pouring molten metal in to a mold. and when it gets cools , it solidified into a copper solid plaque. first nation people use copper as hunting weapons, spear tools etc. copper is metal.
Thus, First nations people along the west coast of British Columbia used smelting technology to create copper plaques is false.
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PLEASE HELP
Referring to the energy diagram below which arrow segment represents the activation
energy of this reaction?
O Arrow B
O Arrow D
O Arrow A
O Arrow C
Answer:
Arrow B
Explanation:
What is the pH of a mixture of 1.0 M HC3H5O2 and 1.0 MNaC3H5O2 ? Ka = 1.3 x 10-5
Use the Henderson-Hasselbalch equation.
The pH of the mixture is 4.74.
What is the Henderson-Hasselbalch equation and how is it used in calculating pH?The Henderson-Hasselbalch equation is pH = pKa + log([A-]/[HA]), where pKa is the dissociation constant, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the acid. It is used to calculate the pH of a buffer solution.
What is a buffer solution and how does it work?A buffer solution is a solution that resists changes in pH when small amounts of acid or base are added. It works by containing a weak acid and its conjugate base, or a weak base and its conjugate acid. When an acid is added to the solution, the weak base in the buffer neutralizes it, and when a base is added, the weak acid in the buffer neutralizes it. This helps to maintain the pH of the solution.
pH = pKa + log([A-]/[HA]), where pKa = -log(Ka)
pKa = -log(1.3 x 10^-5) = 4.89
[A-]/[HA] = [NaC3H5O2]/[HC3H5O2] = 1/1 = 1
pH = 4.89 + log(1) = 4.89
Therefore, the pH of the mixture is 4.89.
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What percentage of the Earth's surface is covered by oceans?
What percentage of the Earth's surface is covered by oceans?
Answer:71 percentage
#CARRYONLEARNING #STUDYWELLWhat percentage of the Earth's surface is covered by oceans?
Answer:71 percent/%
#READINGHELPSWITHLEARNING #CARRYONLEARNING #STUDYWELLWhat is the temperature of lukewarm water? Select the better estimate.
80°C
80°F
Answer:
80°F
Explanation:
Lukewarm means moderately warm. 80°C (176°F) water is extremely hot and could burn someone. 80°F (26 2/3°C) is moderately warm.
Which of the following is an example of a combustion reaction?
A) Mixing of an acid and base
B) Photosynthesis in plants
C) Lighting of a Matchstick
D) Reacting sodium and chlorine
Answer:
C) Lighting a matchstick
Explanation:
Mixing an acid and base will cause a neutralization reaction, a type of double displacement.
Photosynthesis is just a series of chemical reactions, but don't deal with the use of O2, but rather it's creation.
Reacting sodium and chlorine would make NaCl in a synthesis reaction.
Answer:
C) Lighting a matchstick
Explanation:
janice g. smith, organic chemistry, sixth edition, mcgraw hill, new york, 2019. (isbn 978-1-260-11910-7) (solution guide is provided with this package!!!).
The book "Organic Chemistry, Sixth Edition" by Janice G. Smith, published by McGraw Hill in New York in 2019, includes an ISBN of 978-1-260-11910-7. It also comes with a solution guide.
The book "Organic Chemistry, Sixth Edition" is authored by Janice G. Smith and published by McGraw Hill in New York in 2019. It is a comprehensive resource for studying organic chemistry. The book covers various topics in organic chemistry, including the structure, properties, and reactions of organic compounds. It provides a thorough understanding of the principles and theories that govern organic chemistry.
The ISBN (International Standard Book Number) 978-1-260-11910-7 uniquely identifies this edition of the book. The ISBN is a standardized numerical code used to identify books and facilitate their distribution and cataloging.
It is mentioned that the solution guide is provided with this package, which indicates that the book includes a separate guide containing solutions to the problems and exercises presented in the book. The solution guide can be a valuable resource for students studying organic chemistry as it helps in understanding and practicing problem-solving techniques.
Overall, "Organic Chemistry, Sixth Edition" by Janice G. Smith is a reputable textbook in the field of organic chemistry, offering comprehensive content and a solution guide to aid students in their learning process.
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Which one of the equations below is an exothermic reaction?
A) CO2 (g) - C(s) + O2 (g) AH = 394 kJ/mol
B) CaO (s) + H2O (D = Ca(OH)2 (aq) AH = -64
kJ/mol
C) C (s) + 2 F2 (g) - CF. (9) AH = 141.3
kJ/mol
2 NO (9) AH° = 180.6
D) N2 (g) + O2 (9)
kJ/mol
Answer:
B) CaO(s) + H2O(l) --> Ca(OH)2(aq)
Explanation:
This is the only reaction with a negative enthalpy value. Exothermic reactions have a negative enthalpy.
Which of the following is the correct equilibrium constant expression for this reaction? Hin(aq) + H2O(l) <=> In"(aq) + H30+(aq) K = [Hin](H20] / [In"][H30+1 OK- K = [In ] [H30*] / [Hin] O K = [In"][H30*]/[Hin][H20] O K= [Hin] / [In ][H30+1 How do we determine the equilibrium constant for bromophenol blue in this experiment?
The equilibrium expression for this reaction is K = [In"][H30ˣ]/[Hin][H20].
In order to determine the equilibrium constant for bromophenol blue in this experiment, we must first calculate the concentrations of the reactants and products at equilibrium.
We can then use the equilibrium expression for this reaction to calculate the equilibrium constant. The equilibrium expression for this reaction is K = [In"][H30ˣ]/[Hin][H20]. The concentrations of the reactants and products in the reaction are determined by measuring the absorbance of the solution at various wavelengths and comparing it to a standard calibration curve.
Once these concentrations are known, we can substitute them into the equilibrium expression to calculate the equilibrium constant. This value can then be used to determine the equilibrium concentrations of the reactants and products in the reaction.
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No matter how much of a substance you have, the density always remains the same.
True or false
Answer:
True
Explanation:
Density is an intensive property. This means that regardless of the object's shape, size, or quantity, the density of that substance will always be the same. Even if you cut the object into a million pieces, they would still each have the same density
What has occurred?
an endothermic reaction
an energy formation
a chemical reaction
a precipitate formation
The Statue of Liberty is made out of copper and was once shiny and copper-colored. Over the years, the copper has gone through a process called oxidation, where it has changed into a new material.
Answer:
a chemical reaction
Explanation:
What has happened to the statue of liberty is that a chemical reaction has occurred to the materials making up this edifice.
The statue is made up of copper. On reacting with oxygen, it undergoes an oxidation.
This makes the copper to rust and decolorize.
It implies that copper has reacted with oxygen in air and possibly from water.
This gives a new product.
We know this because for most chemical changes, they give new products and are not easily reversible.
Consider some parameters that we could use to describe the gas: the mass of the molecules (m), the average speed of the molecules (v), and the number density of molecules (N/v), the number of molecules packed into a volume V). Does it seem like the pressure should depend on any of these parameters? And if so, how? For each of those parameters, determine whether you think pressure should be proportional to them or inversely proportional to them (i.e. if you increase the average speed of molecules in a gas, would you expect the pressure the gas exerts on objects to increase or decrease?). Based on that, write a proportionality equation for what you expect pressure to depend on. For example, if you expect pressure to be proportional to their speed and inversely proportional to their mass, and not depend on N or V, you would write p∝ m
v
(hint - that is not correct). The proportional symbol (∝) is there because for allwe know there may be some constant in front.
The pressure of a gas is determined by factors such as the average speed of the molecules (v) and the number density of molecules (N/v). However, the mass of the molecules (m) does not directly influence the pressure.
Pressure is a result of the collisions between gas molecules and the walls of the container.
The more collisions that occur per unit area, the higher the pressure.
Therefore, the pressure should be directly proportional to the number density of molecules (N/v) and inversely proportional to the average speed of the molecules (1/v).
However, when considering the mass of the molecules, an increase in mass leads to a decrease in the average speed, which lowers the number of collisions and subsequently reduces the pressure.
Therefore, the pressure is inversely proportional to the product of the mass and volume, or p∝(mN)/V.
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8.3 kg, 1.7 Kg/cm3
-> ? cm3
Answer:
4.9 cm³
Explanation:
Given data:
Mass value = 8.3 kg
Density = 1.7 kg/cm³
Volume = ?
Solution;
In given question from the units we got to know that the mass and density value is given and we have to calculate the volume.
Thus, we will apply density formula.
Density = mass/ volume
d = m/v
1.7 kg/cm³ = 8.3 kg/ v
v = 8.3 kg/ 1.7 kg/cm³
v = 4.9 cm³
Thus, the volume is 4.9 cm³.
What are some examples of supersaturated solutions? Give 10.
Examples include carbonated water (i.e. soda water); honey; sugar syrup (used in confectionery); supersaturated drug delivery systems. "SDDS"; and sodium acetate solutions prepared from 160 g NaOAc and 30 mL water.
which purpose is most used for tlc method?
a. Identification
b. Makes the eluent more polar
c. neutral or acid
d. slightly sour
Makes the eluent more polar is the correct option.this is the purpose which is most used for TLC method.TLC means thin-layer chromatography.
Non-volatile mixtures can be separated using the chromatography technique known as thin-layer chromatography (TLC). A sheet of an inert substrate, such as glass, plastic, or aluminum foil, is used for thin-layer chromatography. This substrate is covered with a thin layer of an adsorbent material, often silica gel, aluminum oxide (alumina), or cellulose. To elute more strongly retained solutes, an increase in eluent strength is necessary. RP-HPLC (raise organic, create more non-polar) (increase organic, make more non-polar). NP-HPLC (increase solvent to make more polar) (increase solvent to make more polar) For many separations, eluent strength gradients (gradual changes) are utilized. When polar compounds are induced to be more attracted to the mobile phase by a moderately polar eluent, the equilibrium shifts and the compound spends more time in the mobile phase, increasing the R f.
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Calculate the Empirical Formula for the following compound:
0.300 mol of S and 0.900 mole of O.
Answer:
\(\boxed {\boxed {\sf SO_3}}\)
Explanation:
An empirical formula shows the smallest whole-number ratio of the atoms in a compound.
So, we must calculate this ratio. Since we are given the amounts of the elements in moles, we can do this in just 2 steps.
1. DivideThe first step is division. We divide the amount of moles for both elements by the smallest amount of moles.
There are 0.300 moles of sulfur and 0.900 moles of oxygen. 0.300 is smaller, so we divide both amounts by 0.300
Sulfur: 0.300/0.300= 1 Oxygen: 0.900/0.300= 3 2. Write Empirical FormulaThe next step is writing the formula. We use the numbers we just found as the subscripts. These numbers go after the element's symbol in the formula. Remember sulfur is S and there is 1 mole and oxygen is O and there are 3 moles.
S₁O₃This formula is technically correct, but we typically remove subscripts of 1 because no subscript implies 1 representative unit.
SO₃\(\bold {The \ empirical \ formula \ for \ the \ compound \ is \ SO_3}}\)