Answer:
Bro you have not given options but answer is 4 × 10 raise to power -8
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
Solve. x/4 + ½ = 1/8
x = ____ (Simplify your answer.)
Answer:
\( \frac{x}{4} + \frac{1}{2} = \frac{1}{8} \)
\( \frac{x}{4} = - \frac{3}{8} \)
\(x = - \frac{3}{2} = - 1 \frac{1}{2} \)
The solution to the equation x/4 + 1/2 = 1/8 is x = -3/2.
Consider the equation, we have only one x term, so taking all the terms without x to the other side and terms with x on one side.
x/4 + 1/2 = 1/8
Take the 1/2 term on the other side,
x/4=1/8 - 1/2
Taking the LCM on the Right side,
x/4 = (1-4) / 8
x/4 = -3/8
Now, we have x/4 so what we can do is, shift the 4 to the other side too, we get,
x = ( -3/8) * 4
x = -3/2
The solution to the equation x/4 + 1/2 = 1/8 is x = -3/2.
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Please help me with edge question .
\(~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill\\\\ (4)^{\frac{-4}{2}} \implies (4)^{-2}\implies 4^{-2}\implies \cfrac{1}{4^2}\implies \cfrac{1}{16}\)
on average, 3 traffic accidents per month occur at a certain intersection. what is the probability that in any given month at this intersection (a) exactly 5 accidents will occur? (b) fewer than 3 accidents will occur? (c) at least 2 accidents will occur?
a)The probability of exactly 5 accidents will occur is 0.1008.
b) The probability of fewer than 3 accidents will occur is 0.42318.
Define probability.It is predicated on the likelihood that something will occur. The justification for probability serves as the basic foundation for theoretical probability. For instance, the theoretical chance of receiving a head while tossing a coin is 12. Mathematics' study of random events is known as probability, and there are four primary types of probability: axiomatic, classical, empirical, and subjective. Since probability is the same as possibility, you could say that it is the likelihood that a specific event will occur.
Given,
Mean = 3
a) By using Poission probability formula,
P( X = 5) = e⁺³ (3)⁵/5!
P(X = 5) = 0.1008
The probability of exactly 5 accidents will occur is 0.1008.
b) fewer than 3 accidents will occur:
P( X <3) = e⁻³ (3)⁰ + e⁻³ (3)¹ + e⁻³(3)²
P( X< 3) = 0.4978 + 0.14936 + 0.22404
P( X < 3) = 0.42318
The probability of fewer than 3 accidents will occur is 0.42318.
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Use the graph to answer the question.
The line graph shows tuition amounts for a university for the years 1996 through 1999. Which of the
following is a valid claim based on the graph?
A Tuition rates have increased faster than inflation.
O
B. The tuition has increased steadily over this time span.
O
C. Tuition increased twice as much from 1997 to 1998 as it did from 1996 to 1997.
D. The rate of tuition inflation will decrease in the next 5 years.
Answer:
B.
Step-by-step explanation:
hope it helps :)
which one is smallest 0.28,1/4,15%,0.65,32%,1/3
Answer:
15%
Step-by-step explanation:
please help and answer......
Answer:
C not like terms
Step-by-step explanation:
Answer:
the answer is LIKE TERMS because 10 doesnt have a variable of y
Step-by-step explanation: Brainliest please.
Can someone please help me I don’t understand and it’s a really important homework
Answer:
The large box weighs 18.75 and the small box weights 15.75
Step-by-step explanation:
We are looking to find 2 variables so we will need two equations.
Let l = the large box weight
Let s = the small box weight
7l + 9s + 273 5l +3s = 141
I want to add these two equations together and have one of the variables be eliminated. The way both equations are written now, neither variable will drop out. I see that 9 is a multiple of 3. If I multiply the second equation all the way through by - 3, the s variable will be eliminated.
-3(5l +3s) -3(141) Multiple everything by -3
-15l -9s = -423 Now I will add this to the original equation 7l + 9s = 273
7l + 9s = 273
-8l = -150 Divide both sides by -8
l = 18.75 This is the weight of the large box.
Plug in 18.75 to either of the ordinal equations to find the weight of the small box.
5l + 3s = 141
5(18.75) + 3s = 141 Distribute the 5
93.75 + 3s = 141 Subtract 93.75 from both sides
3s = 47.25 Divide both sides by 3
s = 15.75
Check:
Plug in 15.75 for s and 18.75 for l into both of the original equation to see if they equal.
7l + 9s = 273
7(18.75) + 9(15.75) =273
131.25 + 141.75 = 273 Checks
5l + 3s = 141
5(18.75) + 3(15.75) = 141
93.75 + 47.25 = 141
141 = 141 Checks
The volume, Vm³, of liquid in a container is given by V = (3h² + 4) ³ - 8, where h m is the depth of the liquid. Which of the following is/are true? Liquid is leaking from the container. It is observed that, when the depth of the liquid is 1 m, the depth is decreasing at a rate of 0.5 m per hour. The rate at which the volume of liquid in the container is decreasing at the instant when the depth is 1 m is 4.5√7. dV 6h√3h² +4. dh The value of at h = 1 m is 9√/7. Non of the above is true. d²V 9h√3h² +4. dh² 000 = 4
Previous question
The correct statement among the given options is "The rate at which the volume of liquid in the container is decreasing at the instant when the depth is 1 m is 4.5√7. dV/dh = 6h√(3h² + 4)."
In the given problem, the volume of liquid in the container is given by V = (3h² + 4)³ - 8, where h is the depth of the liquid in meters.
To find the rate at which the volume is decreasing with respect to the depth, we need to take the derivative of V with respect to h, dV/dh.
Differentiating V with respect to h, we get dV/dh = 3(3h² + 4)²(6h) = 18h(3h² + 4)².
At the instant when the depth is 1 m, we can substitute h = 1 into the equation to find the rate of volume decrease.
Evaluating dV/dh at h = 1, we get dV/dh = 18(1)(3(1)² + 4)² = 18(7) = 126.
Therefore, the rate at which the volume of liquid in the container is decreasing at the instant when the depth is 1 m is 126 m³/hr.
Hence, the correct statement is "The rate at which the volume of liquid in the container is decreasing at the instant when the depth is 1 m is 4.5√7. dV/dh = 6h√(3h² + 4)."
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true or false we can represent the pdf of a discrete random variable x with a histogram. group of answer choices
The given statement "We can represent the pdf of a discrete random variable x with a histogram." is True, because histograms are often used to graphically represent the distribution of a discrete random variable.
In a histogram, the x-axis represents the different possible values of the discrete random variable, and the y-axis represents the probability or frequency of observing each value. The bars in the histogram represent the probabilities or frequencies of the different values, and the height of each bar corresponds to the probability or frequency.
Note that for a discrete random variable, the PDF is actually a probability mass function (PMF), which gives the probability of each possible value of X. However, the histogram can be used to represent the PMF by scaling the heights of the bars appropriately so that they represent probabilities rather than frequencies.
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How many times would you expect to land on heads if you flipped a standard coin 250 times?
Answer:
125
Step-by-step explanation:
250/2=125 this is how many time you would expect to get heads
4. (20pts) a. find a power series representation of the function f(x) = (x ^ 3)/((x - 5) ^ 2)
The series representation is as follows: f(x) = x^3 * (1 / (x - 5)^2) = x^3 * (1 / (25 - 10x + x^2)) = x^3 * (1 / 25) * (1 / (1 - (10/25)x + (1/25)x^2)). The power series representation of the function f(x) = (x^3)/((x - 5)^2) can be found by using the geometric series expansion and the binomial theorem.
1. Now, we can recognize the form of a geometric series (1 / (1 - r)), where r = (10/25)x - (1/25)x^2. By applying the geometric series expansion, we have: f(x) = (x^3 / 25) * (1 + (10/25)x - (1/25)x^2 + (10/25)^2 * x^2 - (10/25)^3 * x^3 + ...)
2. This power series representation of f(x) shows that it can be expressed as a sum of terms multiplied by powers of x. The coefficients of the terms are obtained from the binomial expansion of (1 / (1 - r)). The terms involving higher powers of x correspond to higher-order derivatives of f(x) evaluated at x = 0.
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The manager of an art supply store decides to hold a Buy 2, Get 1 Free sale on tubes of watercolor paints. The sale is held for one week and a total of 280 tubes of paint were sold (not including the ones given away for free). If each tube of watercolor paint cost the store $7.25, how much money did the store lose by giving away the free tubes of paint?
Answer:
$1015
Step-by-step explanation:
280 divided by 2 140 times $7.25 is $1015
The amount of money that the store lose by giving away the free tubes of paint is $1015.
Since the manager held Buy 2, Get 1 Free sale on tubes of watercolor paints, then when 280 tubes of paints are sold, 1/2 × 280 = 140 tubes of paints will be given out for free.
Therefore, the amount lost will be calculated by multiplying the number of paints given out by the price. This will be:
= 140 × $7.25
= $1015
Therefore, the amount of money that the store lose by giving away the free tubes of paint is $1015.
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I need help, answering this!
Answer:
The length is 15.71 feet.
Step-by-step explanation:
Find the solution of the following differential equation by Laplace transforms with initial conditions for each equation: a) y" – y = t y(0) = 1, y'(0) = 1 b) y" + y' = t² + 2t y(0) = 4, y'(0) = -2 c) d²y/dt⁴ + d³y/dt³ = cost y(0) = y'(0) = y"' (0) = 0, y" (0) = 1
Laplace transforms are an essential mathematical tool used to solve differential equations. These transforms transform differential equations to algebraic equations that can be solved easily.
To solve the differential equations given in the question, we will use Laplace transforms. So let's start:Solution:a) y" – y = t y(0) = 1, y'(0) = 1First, we take the Laplace transform of the given differential equation.L{y" - y} = L{ty}
Taking the Laplace transform of both sides gives:L{y"} - L{y} = L{ty}Using the formula, L{y"} = s²Y(s) - s*y(0) - y'(0), and L{y} = Y(s) then we get:s²Y(s) - s - 1 = (1/s²) + (1/s³)Rearranging the above equation, we get:Y(s) = [1/(s²*(s² + 1))] + [1/(s³*(s² + 1))]Now, we apply the inverse Laplace transform to find the solution.y(t) = (t/2)sin(t) + (cos(t)/2)
The solution of the differential equation y" – y = t, with initial conditions y(0) = 1, y'(0) = 1 is y(t) = (t/2)sin(t) + (cos(t)/2).
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Write the equation of a line perpendicular to 3x + 4y = 6 going through the point (2,-5).
write the given equation in a standard form
3x + 4y = 6
4y = 6 - 3x
4y = - 3x + 6
divided by 4 in both sides
y = - 4/3x + 3/2
standard form of a linear equation is
y = mx +c
therefore m for gradient is -4/3
the product of the gradient of the lines that are perpendicular to each other is -1
- 4/3 × mx = -1
mx = 3/4
y = mx + c
-5 = 3/4(2) + c
-5 = 3/2 + c
c = -13/2
therefore your equation is
y = 3/4x - 13/2
Write an equation in slope-intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation.
(-5,8); y=1/5x-3
Answer:
y = –5x – 17
Step-by-step explanation:
First, we shall determine the slope of the equation y = 1/5x – 3.
The slope of the equation y = 1/5x – 3 can be obtained by comparing the equation with y = mx + c.
This is illustrated below:
y = 1/5x – 3
y = mx + c
Thus, the slope (m) of equation
y = 1/5x – 3 is 1/5
Next, we shall determine the slope of the line perpendicular to the equation as follow:
For perpendicular lines, their slope (m1 and m2) are related as follow:
m1 × m2 = –1
m1 = 1/5
1/5 × m2 = –1
m2/5 = –1
Cross multiply
m2 = 5 × –1
m2 = –5
Therefore, the slope of the line is –5.
Finally, we shall determine the equation of the line as follow:
Coordinate = (–5, 8)
x1 coordinate = –5
y1 coordinate = 8
Slope (m) = –5
y – y1 = m(x –x1)
y – 8 = –5(x – (–5))
y – 8 = –5(x + 5)
y – 8 = –5x – 25
Rearrange
y = –5x – 25 + 8
y = –5x – 17
Therefore, the equation is y = –5x – 17.
Please Help 50 POINTS!!
Answer:
D. \(\frac{(x-7)^2}{8^2} -\frac{(y-2)^2}{7^2}\)
Step-by-step explanation:
hope this helps
Answer: D has the largest perimeter
Step-by-step explanation:
The top numbers of fractions describe the vertex and the bottom number square rooted tells you how long each or wide each part of the asymptote rectangle is.
A.
P = 2(11) + 2(3)
P = 22+6
P=28
B.
P = 2(4) + 2(9)
p = 8 +18
P = 26
C.
P = 2(5) + 2(9)
P = 10 +18
P = 28
D.
P = 2(8) + 2(7)
P = 16 +14
P = 30
For what values of c does the quadratic equatrion x^2-2x+c=0 have two roots of the same sign
The roots have positive or same signs when c>0.
Note that only real numbers can be positive or negative. This concept does not apply to complex non real numbers. So first we have to make sure that the roots are real which occurs when discriminant is greater or equal to 0.
\(b^{2} -2ac > 0\\2^{2} -2(-1) (c) > 0\\4-2c > 0\\c > -2\)
Roots of quadrant equation have Samsame sign if product of roots >0.
\(\frac{a}{c} > 0\\\frac{c}{-1} > 0\\c < 0\)
Roots of quadratic equation have positive sign if product of roots<0.
c>0.
Combining results, we get:-
roots have positive signs when:-
c>0.
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A triangle has side lengths of 10,11, and 15. What type of triangle is it ?
Answer:
Obtuse
Step-by-step explanation:
square the 2 smaller side lengths. 10^2+11^2= 221. If you square the longer side length, you get 225. 15^=225.
An acute triangle is when the 2 smaller side lengths are greater
A right triangle is when the 2 smaller side lengths are equal
An obtuse triangle is when the 2 smaller side lengths are less.
221 is less than 225, making it obtuse.
Answer:
SCALENE TRIANGLE
Step-by-step explanation:
42 POINTS!!!
Better Cable Company must provide service to a customer whose house is located 2 miles from the main highway. The nearest connection box for the cable is located 5 miles down the highway from the customer's driveway. The installation cost is $14/mile for any cable that is laid from the house to the highway. (The cable must be laid along the driveway to the house or across the field). The cost is $10/mile when the cable is laid along the highway. Determine where the cable should be laid so that the installation cost is as low as possible.
Please show work!
The required point is 0.25 miles away from the nearest point on the shore.
What is differentiation?The differentiation of a function is defined as rate of change of its value at a point. It can be written as f'(x) = lim h--> 0 (f(x + h) - f(x)) /(x + h - x).
here, we have,
It can be applied to minimize or maximize a function.
The given problem can be shown in the form of a diagram as follows
Suppose the underwater cable meet the shore at a distance x from the nearest point.
Then, the distance of cable in water is x² + 3.5² = x² + 12.25
And, the distance of cable in the ground is 10 - x.
As per the question, the cost of the laying cable can be represented as follows,
C(x) = 1200(10 - x) + 2400(x² + 12.25)
In order to minimize the cost the above function can be differentiated and equated to zero as,
C'(x) = -1200 + 4800x = 0
=> x = 1200/4800
= 1/4
= 0.25
Hence, in order to minimize the cost of the entire project the underwater cable should meet the shore at 0.25 miles away from the nearest point.
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1 poi (6) Jason's part-time job pays him $105 a week. If he has already saved $325, what is the minimum number of weeks he needs to work in order to have enough money to buy a dirt bike for $900?
We are told that Jason has $325 and that he earns $105 per week. That means that if "w" is the number of weeks then the amount of money he has in total is what he has saved by the product of $105 by the number of weeks. That is, if A is the amount he has, then:
\(A=325+105w\)Now, we are asked how many weeks it takes to get to $900. This means that we set A = 900 and solve for "w".
\(900=325+105w\)To solve for "w" we first subtract 325 on both sides:
\(\begin{gathered} 900-325=325-325+105w \\ 575=105w \end{gathered}\)Now we divide both sides by 105
\(\frac{575}{105}=\frac{105w}{105}\)Solving the operations:
\(5.5=w\)Therefore, it takes Jason 5.5 weeks to get to $900
ms.garcia’s seventh grade class is collecting aluminum cans yo buy new board games. They receive $0.35 for each pound of cans they collect.What is the minimum number of pounds of aluminum cans they need to collect in order to purchase a broad game that cost $27.20
Answer:
The minimum number of pounds they need to collect is 78
Step-by-step explanation:
27/0.35 = 77.7
but in this specific problem you can't have less than part of a pound, so the final answer would be 78 pounds
Find an equation of the line parallel to y=2x-6 that passes through the point (3,-8) if possible write the equation in slope intercept form
Given the equation:
\(\text{ y = 2x -6}\)The equation is at Slope-Intercept Form: y = mx + b and the m in the equation represents the slope of the line. Therefore, the slope of the line that represents the equation y = 2x - 6 is 2.
It's been given that the equation of the line that we are looking for is parallel to y = 2x - 6 and passes through the point (3, -8). Thus, we will adapt the slope of the equation and determine the y-intercept by substituting the coordinates in the slope-intercept formula y = mx + b.
We get,
\(\text{ y = mx + b}\)At slope, m = 2 and x,y = 3, -8:
\(-8\text{ = (2)(3) + b}\)\(-8\text{ = 6 + b}\)\(\text{ b = -8 - 6 = -14}\)Let's substitute m = 2 and b = -14 to y = mx + b to complete the formula:
\(\text{ y = mx + b}\)\(\text{ y = (2)x + (-14)}\)\(\text{ y = 2x - 14}\)Therefore, the equation of the line parallel to y = 2x - 6 and passes through (3, -8) is
y = 2x - 14.
The optimal amount of x1, x2, P1, P2 and income are given by the
following:
x1= 21/ 7p1 x2= 51 / 7p2
The original prices are: P1=10 P2=5 The original income is: I
=4189 The new price of P1 is the foll
The total change in the consumed quantity of x₁ as per given price and income is equal to 213.
x₁ = (21/7)P₁
x₂ = (51/7)P₂
P₁ = 10
P₂ = 5
P₁' = 81
To calculate the total change in the quantity consumed of x₁ when the price of P₁ changes from P₁ to P₁',
The difference between the quantities consumed at the original price and the new price.
Let's calculate the quantity consumed at the original price,
x₁ orig
= (21/7)P₁
= (21/7) × 10
= 30
x₂ orig
= (51/7)P₂
= (51/7) × 5
= 36.4286 (approximated to 4 decimal places)
Now, let's calculate the quantity consumed at the new price,
x₁ new
= (21/7)P1'
= (21/7) × 81
= 243
x₂ new
= (51/7)P2
= (51/7) × 5
= 36.4286
The total change in the quantity consumed of x₁ can be calculated as the difference between the new quantity and the original quantity,
Change in x₁
= x₁ new - x₁ original
= 243 - 30
= 213
Therefore, the total change in the quantity consumed of x₁ is 213.
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The above question is incomplete, the complete question is:
The optimal amount of x1, x2, P1, P2 and income are given by the following:
x1= 21/ 7p1 x2= 51 / 7p2
The original prices are: P1=10 P2=5 The original income is: I =4189 The new price of P1 is the following: P1'=81 Assume that the price of x1 has changed from P1 to P1'. What is the total change in the quantity consumed of x1?
Please answer step by step
What is the mean height of Bella's corn stalks?
A 69cm
B 75cm
C 78cm
D 80cm
E 81cm
Answer:
C. 78
Step-by-step explanation:
Add all of them together, then divide by 5 because there are 5 different plants.
Fransisco and kazuko guess the number of marbles in a jar. Fransisco guesses 50 marbles and kazuko guesses 60. The actual number of marbles is 55. Kazuko says there is less error in her guess because 50/50=10% and 5/60= 8.3%. Explain why kazuko is incorrect
Answer:
The difference in both the guessed values is 5 unit
Step-by-step explanation:
The less error computation is done by dividing the difference between the guessed value and the actual value.
Here in this case
Error in case of Fransisco = 55-50 = 5
Error in case of Kazuko = 60 -55 = 5
Hence, both have guessed incorrect value and their incorrect values is either 5 units less or 5 units higher than the actual value.
Suppose we are given the following information about a signal x[n]: 1. x[n] is a real and even signal. 2. x[n] has period N = 10 and Fourier coefficients ar. 3. Q11 = 5. 4. To Ślx[n]? = 50. n=0 A cos(Bn+C), and specify numerical values for the constants Show that x[n] = A cos(Bn+C), and specify numer B, and C.
The signal x[n] is: x[n] = 19 cos((pi/5)n - pi/2).
The numerical values for A, B, and C are:
A = \(sqrt(2 * a0^2 - a5^2)\)
B = \(2 * pi / N\)
C = \(arctan((a5 / sqrt(2 * a0^2 - a5^2)) / tan(5 * pi / N))\)
How can we show that x[n] =A cos(Bn+C), and specify numbers B, and C?The given information about the signal x[n] can be used to find the constants A, B, and C in the representation of x[n] as:
x[n] = A cos(Bn + C)
where A, B, and C are constants. We have:
x[n] is a real and even signal with period N=10
The Fourier coefficient a0 is 11
The Fourier coefficient a5 is 5
The energy of x[n] is 50
The numerical values for A, B, and C can be found as follows:
A = \(sqrt(2 * a0^2 - a5^2) = sqrt(2 * 11^2 - 5^2)\) = 19
B = \(2 * pi / N\) = pi / 5
C = \(-arctan(a5 / sqrt(2 * a0^2 - a5^2)) = -arctan(5 / sqrt(2 * 11^2 - 5^2)) = -pi/2\)
Therefore, the signal x[n] can be represented as:
x[n] = 19 cos((pi/5)n - pi/2)
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Answer:
x=30
Step-by-step explanation:
We have a line crossing two other lines which are parallel, so the angles on the same side add up to 180º. Then
-3x + 100 + 6x - 10 = 180
3x + 90 = 180
3x = 180 - 90
3x = 90
x = 90/3
x = 30
YOUR TURN
3. Fifteen bicycles are produced each hour at the
Speedy Bike Works. Show that the relationship
between the number of bikes produced and the
number of hours is a proportional relationship.
Then write an equation for the relationship.
Answer:
The equation is: y = 15·x
Step-by-step explanation:
It is provided that at the Speedy Bike Works, 15 bicycles are produced each hour.
Consider the table below.
Number of Hours: 1 3 6 10
Number of Bicycles Produced: 15 45 90 150
Compute the ratio of number of bicycles produced and number of hours for every data above as follows:
\(\text{1 hour}=\frac{15}{1}=15:1\\\\\text{3 hour}=\frac{45}{3}=\frac{15}{1}=15:1\\\\\text{6 hour}=\frac{90}{6}=\frac{15}{1}=15:1\\\\\text{10 hour}=\frac{150}{10}=\frac{15}{1}=15:1\)
The ratio of the number of bicycles produced and number of hours is same for every data value.
Thus, the relationship between the number of bicycles produced and number of hours is proportional.
The equation for the relationship is:
y = 15·x
y = number of bicycles produced
x = number of hours
One kitten weighs 2 pounds, 4 ounces, and a second kitten weighs 2 pounds, 2 ounces. What is their combined weight in ounces? *
I WILL GIVE BRAINLEST BECAUSE I WANT TO BE NICE