The energy of the incident electron is approximately 4.396 keV.
What is the energy (in keV) of the incident electron in an elastic collision with a second electron, given their trajectories' radii of 0.00 cm and 2.60 cm, respectively, in a perpendicular uniform magnetic field of magnitude 0.0350 T?To determine the energy of the incident electron, we can utilize the principles of conservation of momentum and conservation of kinetic energy in an elastic collision.
Initial radius of the incident electron's trajectory (r₁) = 0.00 cm
Final radius of the incident electron's trajectory (r₂) = 2.60 cm
Magnitude of the uniform magnetic field (B) = 0.0350 T
The magnetic field causes the charged particles (electrons) to move in circular paths due to the Lorentz force acting on them. We can use the following equation to relate the radius of the trajectory to the momentum and the magnetic field:
mv = qBr
m is the mass of the electron,
v is the velocity of the electron,
q is the charge of the electron, and
r is the radius of the trajectory.
Since both electrons have the same charge and mass, their velocities can be related as:
m₁v₁ = m₂v₂
To calculate the energy of the incident electron (E₁), we can use the formula:
E = (1/2)mv²
Let's proceed with the solution:
Since the collision is elastic, momentum is conserved:
m₁v₁ + m₂v₂ = 0
Also, since the radii of their trajectories are perpendicular to the magnetic field, their velocities can be related to the radii as:
v₁ = ωr₁
v₂ = ωr₂
where ω is the angular velocity.
Substituting these relationships into the momentum conservation equation, we get:
m₁ωr₁ + m₂ωr₂ = 0
Since m₁ = m₂ = m (same mass for both electrons) and ω is common, we can simplify the equation to:
mω(r₁ + r₂) = 0
From this equation, we find that (r₁ + r₂) = 0.
Now, let's calculate the energy of the incident electron using the formula:
E₁ = (1/2)m₁v₁²
Since v₁ = ωr₁, we can substitute the value of ωr₁ from the equation (r₁ + r₂) = 0:
E₁ = (1/2)m(ωr₁)²
E₁ = (1/2)m(ω²r₁²)
E₁ = (1/2)m(v₁/r₁)²
E₁ = (1/2)(mv₁²/r₁²)
Since v₁²/r₁² = B² (from the equation mv = qBr), we can substitute the value of B²:
E₁ = (1/2)B²m
Finally, let's substitute the given values to calculate the energy of the incident electron in keV (electron volt, a unit of energy):
E₁ = (1/2)(0.0350 T)²(9.11 × 10^-31 kg) * (1.6 × 10^-19 C) / (1.6 × 10^-16 J)
E₁ ≈ 4.396 keV
Therefore, the energy of the incident electron is approximately 4.396 keV.
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Choose the correct answer: A simple pendulum makes 40 oscillations in 200 seconds.
A) 10 seconds
B) 20 seconds
C) 50 seconds
D) 5 seconds
HELP!!!A car accelerate from a stand still to 60KM/H. and 10 seconds what is acceleration
Answer: i think 1.666...
Explain why electromagnetic forces are essential to forming compounds.
Explanation:
formation of compounds because the electric forces compel the atoms to attract each other and formed bonds which leads to the formation of chemical compounds. The attractive or repulsive interaction between any two charged bodies is known as an electric force so the attraction between two opposite charged atoms causes the formation of compounds so we can conclude that electric forces are important for the formation of compounds.
In the compound MgCl2, how many atoms of Mg are there?
Which statement about a HORIZONTAL projectile is false?
The horizontal velocity is constant.
The horizontal acceleration is constant.
The vertical velocity is constant.
The vertical acceleration is constant.
Answer:
the vertical velocity is constant.
Explanation:
The horizontal velocity of a projectile is constant (a never changing in value), There is a vertical acceleration caused by gravity; thus, the vertical velocity of a projectile changes. and the horizontal motion of a projectile is independent of its vertical motion.
A 0.675 kg mass is attached to a
spring of spring constant 72.4 N/m,
pulled, and released. What is the
period of the resulting oscillation?
(Unit = s)
Answer:
T= 0.6 secExplanation:
This problem bothers on the simple harmonic motion of a loaded spring
Given data
mass attached, m= 0-.675 kg
spring constant, k= 72.4 N/m
the period of oscillation can be solved for using the formula bellow
\(T= 2\pi \sqrt{\frac{m}{k} }\)
Substituting the given data into the expression above we have
\(T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6\)
T= 0.6 sec
Answer:
0.607
Explanation:
Trust me
Study the arrow that is circled in the image.
The sun is in the sky. Clouds with blue arrows pointing down toward water. A circled arrow is pointing from the water inland. Red arrows are pointing up from the land to the sky.
What happens at this point?
A. Warm air is rising.
B. Cool air is sinking.
C. There is a difference in air pressure.
D. Cool air is less dense than warm air.
Answer:
C. There is a difference in air pressure.
Explanation:
Why does mining considered the most important industry?
Answer:
it makes most recourses and gives us most of a materials
Explanation:
What is the gravitational force between the Earth and the Sun? The mass of the Earth is 5.972 x 1024 kg, the mass of the Sun is 1.99 x 1030 kg, and the
distance between the Earth and the Sun is 1.496 x 101 m.
5.295 x 1033N
9881N
O 3.54 x 1022N
5.11 x 1014 N
Which of the following is most useful in allowing us to learn about clouds of intergalactic gas?
A) Quasar spectra
B) Solar wind
C) Lunar rock samples
D) Earth's atmosphere
Quasar spectra are most useful in allowing us to learn about clouds of intergalactic gas.
So correct answer is A) Quasar spectra
Quasars are extremely bright and distant objects that emit large amounts of energy, including light. When light from a quasar passes through intergalactic gas clouds, it is absorbed by atoms in the gas. By analyzing the spectrum of light emitted by a quasar and comparing it to the spectrum of light that reaches us on Earth, scientists can identify the specific wavelengths of light that were absorbed by intergalactic gas. This allows them to determine the chemical composition, density, and temperature of the gas clouds, and to learn more about the processes that govern the behavior of matter in the universe. Quasar spectra have been used to study a variety of intergalactic gas clouds, including those associated with galaxies, clusters of galaxies, and the large-scale structure of the universe.
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For brainliest !!!!!!! Do it
Answer and Explanation:
Using a = F/m, we get:
Acceleration for Road A = 480/62 = ~7.74 m/s^2
Acceleration for Road B = 240/62 = ~3.87 m/s^2
Acceleration for Road C = 600/62 = ~9.68 m/s^2
If the net force becomes higher than 600N and the mass stays constant, the acceleration will increase proportionally to how much the force increases and the acceleration will be greater than the acceleration when the force is 600N.
I hope this helps! :)
I am really confused can someone please help and explain.
B
They store the radioactive waste in pools of water until it is no longer dangerous. It is then transferred to a dry cask. :))
A 50kg skater is moving due east at a speed of 3m/s before colliding into another skater of mass 60kg moving in the opposite direction at a speed of 7m/s. After the collision, the two skaters hold on to each other. In which direction will they move? What is the speed of the two skaters?
Please help me quickly
Describe what sandpaper does to wood to make it smoother, and explain why.
Answer it scapes away loose anf rough pieces of wood
Explanation:
Answer:
To achieve a nice smooth finish, it's essential to sand to help prepare the area for painting application, by sanding you are removing imperfections (also known as pimples), creating a nice smooth finish while at the same time adding adhesion by developing small, rough ridges for the paint to stick to.
Using the right sandpaper can make all the difference in a woodworking, painting, or finishing project; but choosing between the many different types of sandpaper that are available can be a challenge. Here are some tips on how to choose the best sandpaper for your next project.
Explanation:
Sry if this is wrong :(
Which statement correctly describes the relationship between a blackbody radiator, its temperature, and the electromagnetic radiation it gives off? A. As the blackbody radiator becomes warmer, it emits light of shorter wavelengths.
B. As the blackbody radiator becomes warmer, it reflects different wavelengths of light.
C. As the blackbody radiator becomes warmer, it emits random wavelengths of light.
D. As the blackbody radiator becomes cooler, it emits light of shorter wavelengths.
It's A
Answer:
A. As the blackbody radiator becomes warmer, it emits light of shorter wavelengths.
The temperature, and electromagnetic radiation has a relationship where blackbody radiator becomes warmer, it emits light of shorter wavelengths.
What is radiation?radiation can be regarded as the process of heat dissipation without contact with a body.
Therefore , temperature, and electromagnetic radiation of a black body works in the sense that
blackbody radiator becomes warmer during emissions.
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A compact car, mass 664 kg, is moving at 19 km/h toward the east. What is the car's momentum in kg x m/s?
Answer:
3504.4 kgm/s
Explanation:
First, convert km/hr to m/s:
19 km/hr x 1000m/1km x 1/60min x 1/60s = 5.28 m/s
p = mv
p = (664 kg)(5.28 m/s) = 3504.4 kgm/s
An object that does not vibrate cannot produces what?
A.sound
B.light
C.heat
D.electricity
Answer:
An object that does not vibrate cannot produce sound
A meteor moving 468 km per minute traveling south-to-north direction passed near Earth in 2013. Because the meteor was only 45 m wide and 27,700km above Earth’s surface, it was not visible without a telescope.
Which variables from the passage would identify the velocity of the meteor?
A)468 km per minute and south-to-north direction
B)468 km per minute and 45 m
C)27,700 km and south-to-north direction
D)27,000 km and 45 m
A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s,
how high is the cliff, if it took 12 s for the ball to reach the ground?
What is the correct sketch of the electric field lines in the region between the plates that includes the effect of the conducting sphere.
electric lines of pressure are the important thing idea that turned into employed to conquer the issue.
Use the truth that an electric field always extends outward from a fine price as a start line. The fact that the electrical traces of force continually factor toward the bad charge will later be useful. eventually, create the drawing based on the instances.
wonderful charge to bad charge is the route in which the electric strains of pressure are always oriented. because the electric discipline constantly factors from negative charge to superb charge, draw the photograph thus.
parent 1 is visible below:
The truth that the electric discipline traces always factor from wonderful to terrible charge is used to create the lines with out accounting for engaging in spheres. knowing that there is a accomplishing sphere between the plates allow you to draw the diagram.
determine 2 is seen below:
The drawing makes use of the conducting sphere this is sandwiched among the parallel plates.
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what type of wave travels through matter only??
A mechanical wave can only travel through matter.
When you eat food, not all of the food can be broken down into the basic building blocks and why?
Answer:
cause you crazy..
Explanation:
A marble rolls off the edge of a table 0.75 m high with a horizontal velocity of 1 5 m/s With what velocity does it strike the floor?
It will strike the floor horizontally with the same horizontal velocity it had when it rolled off the table, which is 1.5 m/s.
To determine the velocity with which the marble strikes the floor, we can use the principles of projectile motion. Since the marble rolls off the edge of the table horizontally, its vertical motion can be treated independently.
The vertical motion of the marble can be analyzed using the equation:
v_\(f^{2}\) = v_\(i^{2}\) + 2aΔd,
where:
v_f = final velocity
v_i = initial vertical velocity
a = acceleration due to gravity
Δd = vertical displacement (0.75 m).
Since the initial vertical velocity, we get:
v_\(f^{2}\) = 2aΔd.
Substituting the known values:
v_\(f^{2}\) = 2(-9.8 m/\(s^{2}\))(0.75 m).
Simplifying the equation:
v_\(f^{2}\) = -14.7 \(m^{2}\)/\(s^{2}\).
Taking the square root of both sides:
v_f = √(-14.7 \(m^{2}\)/\(s^{2}\)).
This means that the marble will not strike the floor vertically with a positive or negative velocity. Instead, it will strike the floor horizontally with the same horizontal velocity it had when it rolled off the table, which is 1.5 m/s.
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For the vectors A and B in Fig. E1.22, use a scale drawing to find the magnitude and direction of (a) the vector sum A + B and (b) the vector difference A − B. Use your answers to find the magnitude and direction of (c) − A − B and (d) B − A. (See also Exercise1.29
To find the vector B - A, draw the vector A with its tail at the origin and draw the vector -A with its tail at the head of vector B. The vector B - A is then the vector drawn from the origin to the head of vector -A.
What is Vector?
In physics, vectors are often used to represent physical quantities such as velocity, force, and acceleration. They are typically represented graphically as arrows, with the length of the arrow representing the magnitude of the vector and the direction of the arrow representing the direction of the vector. Vectors can be added and subtracted to find the resulting vector, and they can also be multiplied by scalars (real numbers) to change their magnitude.
Without the provided figure, it is difficult to provide a specific answer. However, in general, to find the vector sum A + B, draw the vector A with its tail at the origin of the coordinate system and draw the vector. The vector sum A + B is then the vector drawn from the origin to the head of vector B.
To find the vector difference A - B, draw the vector A with its tail at the origin and draw the vector -B with its tail at the head of vector A. The vector difference A - B is then the vector drawn from the origin to the head of vector -B.
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A box is being pushed to the right with a force of 300 Newton’s, and to the left with a force of 400 Newton’s. What is the magnitude of the net force on the box?
100 Newtons (to the left)
A student looks at the image of a ball rolling down a ramp. The image shows four different positions for the ball Use this image to answer Questions 4–5 are attached.
The law of conservation of energy states that energy is always conserved, and cannot be destroyed.
At the top of the hill, the ball is at the maximum height. Because the equation for gravitational potential energy is (\(U_{g}\) = mgH), we can safely conclude that the GPE at A, the top of the hill, is the greatest in all 4 options.
Now, what about Kinetic Energy? Recall the law of conservation of energy. At the point where Gravitational Potential Energy is the lowest, Kinetic Energy will be the highest. Total energy is always conserved, and so it is logical that KE will increase to compensate for GPE decreasing. Therefore, we know that at point C, the ball will have the greatest Kinetic Energy. Because this point is the lowest point in the hill, the ball will have the lowest possible GPE and therefore the largest possible KE out of the 4 options.
4. A
5. C
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What is the difference between a low tide and a high tide
Answer:
High water level during a tide is called High tide.
Low water level during a tide is called Low tide.
Which list places the three types of radiation in order from least penetrating to most penetrating?
a. gamma, alpha, beta
b. gamma, beta, alpha
c. alpha, beta, gamma
d. alpha, gamma, bet
alpha < beta < gamma.
What are the properties of Alpha , Beta , Gamma Rays?
Gamma rays are parts of electromagnetic spectrum.
1. Gamma rays travel with the speed of light with maximum velocity.
2. Gamma rays do not have mass have maximum penetrating power.
Beta rays are negatively charged and have negligible mass.
1. Neutron is divided into proton and electron on emission of beta particles.
2 .Beta particles have less mass and very high velocity, so their penetrating power is more than alpha particles.
Alpha rays are positively charged it contain high energy Helium nucleus with 2 proton and 2 neutron.
1. Mass of Alpha rays are 4u
2. Alpha rays are heavier and maximum charged than beta and gamma particles.
3.Alpha particles have least penetration power it can't travel more than 10-18 cm.
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3. Using the electrostatic image discuss the electrostatic potential and the electrostatic field due to a point charge place near the surface of a grounded conducting plane.
The presence of a point charge near the surface of a grounded conducting plane creates an electrostatic potential and an electrostatic field. The electrostatic potential decreases with distance from the point charge, and the electrostatic field is stronger closer to the charge and weaker farther away.
When a point charge is placed near the surface of a grounded conducting plane, it induces a redistribution of charges on the conducting plane. This redistribution results in an equal but opposite charge accumulation on the surface facing the point charge, creating an electrostatic potential.
The electrostatic potential decreases with distance from the point charge according to the inverse square law. It is highest closest to the point charge and decreases as you move away from it. The potential is zero at infinity, representing the reference point where there is no interaction with the charge.
The electrostatic field is related to the gradient of the electrostatic potential. It points away from the point charge and is stronger closer to the charge and weaker farther away. The field lines are perpendicular to the equipotential surfaces, indicating the direction of the force experienced by a positive test charge. The field lines converge toward the grounded conducting plane, indicating that the induced charges on the plane create an attractive force on positive charges.
In summary, when a point charge is placed near the surface of a grounded conducting plane, it creates an electrostatic potential that decreases with distance and an electrostatic field that is stronger closer to the charge. The induced charges on the conducting plane contribute to the overall electrostatic potential and field, resulting in an attractive force on positive charges.
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