One car travels 56 meters due east in 2.0 seconds, and a second car travels 84 meters due west in 3.0 seconds. During their periods of travel, the cars definitely had the same

They have narrowed down to two answer choices. Using your knowledge, help them decide which answer choice is correct. Explain your reasoning.

average speed
average velocity

When reading the simile "Bolt runs as fast as lightning," the most appropriate visual interpretation would be that "Bolt runs very fast."

This simile compares Bolt's speed to that of lightning, which is known for its incredible swiftness. The intention is to emphasize Bolt's exceptional speed by equating it to the rapid movement of lightning.

While the simile highlights Bolt's remarkable speed, it does not specify the manner in which he runs or the impact of each step. Therefore, the options suggesting Bolt runs in a straight line, in a wavy manner, or that each step produces thunder are not directly implied by the simile itself. These additional details go beyond the comparison of speed and introduce elements that are not explicitly mentioned.

Hence, the most accurate interpretation based solely on the simile is that Bolt runs very fast, comparable to the speed of lightning.

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The mass will be moving at 14.3 m/s when it reaches the equilibrium position.

To determine the speed of the mass when it reaches the equilibrium position, we need to consider the conservation of mechanical energy, which includes both the spring potential energy and the gravitational potential energy.

The total mechanical energy (E) of the system is the sum of the potential energy and the kinetic energy:

E = PE (potential energy) + KE (kinetic energy)

At the equilibrium position, all the potential energy is converted into kinetic energy, so the total mechanical energy is entirely in the form of kinetic energy.

The potential energy stored in the spring (PE_spring) is given by Hooke's Law:

PE_spring = (1/2) * k * \(x^{2}\)

Where k is the spring constant (250 N/m) and x is the displacement from the equilibrium position (0.32 m).

PE_spring = (1/2) * 250 N/m *\((0.32 m)^2\)

PE_spring = 12.8 J

The change in gravitational potential energy (ΔPE_gravity) is given by:

ΔPE_gravity = m * g * h

Where m is the mass (0.125 kg), g is the acceleration due to gravity (9.8 m/\(s^2\)), and h is the change in height (which is zero in this case since the height doesn't change).

ΔPE_gravity = 0 J

Therefore, the total mechanical energy (E) is equal to the potential energy stored in the spring:

E = PE_spring

E = 12.8 J

Since the total mechanical energy is entirely in the form of kinetic energy at the equilibrium position, we can calculate the speed (v) using the equation:

E = (1/2) * m * \(v^2\)

Rearranging the equation, we get:

\(v^2\) = (2 * E) / m

\(v^2\) = (2 * 12.8 J) / 0.125 kg

\(v^2\) = 204.8 \(m^2\)/\(s^2\)

Taking the square root of both sides:

v = √ 204.8 \(m^2\)/\(s^2\)

v ≈ 14.3 m/s

Therefore, the mass will be moving at approximately 14.3 m/s when it reaches the equilibrium position.

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ANSWER:

a) -11.4 in/s

b) -29.3 in/s^2

STEP-BY-STEP EXPLANATION:

We have the following function corresponding to the position at a given time:

If we differentiate this function with respect to time, we obtain the velocity function, like this:

We calculate the velocity by replacing t = 5, just like this:

If we differentiate the function again, we obtain the acceleration function, as follows:

We calculate the acceleration by replacing t = 5, just like this:

The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

The formula for acceleration due to gravity is:

g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet

In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.

Therefore, g is proportional to 1/r².

So, using the ratio of radii given (1.8), we can write:

r = 1.8 x r Earth, where r Earth is the radius of Earth.

Substituting this value of r in the formula for acceleration due to gravity, we get:

g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²

We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².

Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:

gh = (1/3.24) x g Earth = 3.02 m/s²

Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

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The length of the wire is 1.12m

What is Resistance ?

Resistance is opposition to the current flowing in the circuit.

Given ,

D= 0.6m

R= 0.6/2m

R= 28Ω

rho = 1Ωm

R= rho ×l/A

where R is resistance , l is length ,A is area and rho is resistivity

By applying value and Solving we get,

l= 1.12m

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Answer:

Largest; options A & B

2nd largest; Option F

3rd Largest; Option D

Smallest; Options E & C

Explanation:

Looking at the charges, basically, the net force of the charge q1 is the sum of charges q2 and q3.

When 2 charges are opposite, the force will be attractive but if they are same, then the force will be repulsive.

Thus, the order of the forces is;

I) Largest: q1= +1nC, q2= -1nc, q3= -1nc and (q1= -1nC, q2= +1nc, q3= +1nc)

II) Second largest is: q1= +1nC, q2= -1nc, q3= +1nc

III) Third largest: q1= +1nC, q2= +1nc, q3= -1nc

IV) Smallest: (q1= -1nC, q2= -1nc, q3= -1nc) and (q1= +1nC, q2= +1nc, q3= +1nc)

Answer:

hjbyvtf ghbj

Explanation:

uhgbnm,likjh

The most likely reason parents and their children have similar physical traits is that (b) they have similar genetic structures.

Physical traits are largely determined by genes, which are segments of DNA passed down from parents to their offspring. Genetic information contains instructions for the development of various physical characteristics, such as eye color, height, and facial features. Therefore, children inherit genetic variations from their parents that contribute to the similarities in their physical traits.

Genes are responsible for the transmission of hereditary traits, and variations in these genes can result in different physical appearances. Children receive half of their genetic material from their biological mother and the other half from their biological father, leading to a combination of genetic traits from both parents. This genetic inheritance process explains why children often share physical characteristics with their parents, such as hair color or body structure.

While living in the same home and being born in similar environments can influence certain aspects of physical traits, such as lifestyle choices or exposure to certain factors, these factors do not have as direct and significant an impact as genetic inheritance. They may contribute to some environmental influences, but genetic factors are the primary drivers of physical trait similarities between parents and their children.

The similarity in blood types between parents and children is a result of genetic inheritance as well. Blood type is determined by specific genes, and children inherit their blood type alleles from their parents. However, blood type alone does not account for the full range of physical traits shared between parents and children, as it is just one characteristic among many that are determined by genetics.

In summary, while living in the same home and being born in similar environments can have some influence, the primary reason parents and their children have similar physical traits is due to their shared genetic structures. Genetic inheritance is the key factor that determines the passing down of physical characteristics from one generation to the next.

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The magnitude of the displacement is 1,097.7 mi, and the angle is 89.9°

To find the displacement from Dallas to Chicago, we can break down the vectors representing the distances and directions into their x and y components. Since the Earth is modeled as flat, we can use basic trigonometry to calculate the components.

Let's start by considering the vector from Dallas to Atlanta. The magnitude of this vector is given as 730 miles, and the direction is 5.00° north of east. To calculate the x and y components, we can use the following equations:

Substituting the values:

x = 730 * cos(5.00°)

y = 730 * sin(5.00°)

Similarly, for the vector from Atlanta to Chicago, with a magnitude of 560 miles and a direction 21.0° west of north:

x = magnitude_AC * sin(angle_AC)

y = magnitude_AC * cos(angle_AC)

Substituting the values:

x = 560 * sin(21.0°)

y = 560 * cos(21.0°)

To find the displacement from Dallas to Chicago, we can sum the x and y components:

Now, we can calculate the magnitude and direction of the displacement using these x and y components:

magnitude_displacement = √(x_displacement² + y_displacement²)

angle_displacement = atan(y_displacement / x_displacement)

Finally, we can substitute the calculated values and solve for the magnitude and direction:

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Answer:

Look at work

Explanation:

Elastic Collision: Ki=Kf

M1=4.65kg

M2: 0.060kg

v1=5m/s

v2=0m/s

4.65*5+0.060*0=4.65*v1'+0.060*v2'

23.25+0=4.65v1'+0.060v2'

Also since it is an elastic collision we can use

v1+v1'=v2+v2'

4.65+v1'=v2'

4.65+v1'=v2'

Substitute into the earlier equation

23.25=4.65v1'+0.060(4.65+v1')

Expand

23.25=4.65v1'+0.279+0.06v1'

Solve for v1'

22.971=4.71v1'

v1'=4.88m/s

v2'=4.65+4.88=9.53m/s

Answer:

Speed, Vfx = 7.619 m/s

Explanation:

Vertical distance, Dx = 5.4m

Horizontal distance, Dy = 8m

Acceleration due to gravity, g = 9.8m/s²

Initial speed, Vix = 0m/s²

To find the speed, we would use the second equation of motion to find the time, t;

Dx = Vixt + ½gt²

Substituting into the equation, we have;

5.4 = 0(t) + ½(9.8)*t²

5.4 =  0 + 4.9t²

Rearranging the equation, we have;

4.9t² = 5.4

t² = 5.4/4.9

t² = 1.1020

Taking the square root of both sides;

t = 1.050 secs.

For the speed;

Dy = Vfxt

Vfx = Dy/t

Vfx = 8/1.050

Vfx = 7.619 m/s

Therefore, the speed of the pelican is 7.619 m/s

The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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Answer:

bowling ball

Explanation:

A bowling ball has more mass than the others, thus having more inertia.

An item at rest will remain at rest, and an object in motion will continue to move in a straight path at a constant speed, according to the first law of motion, commonly known as the law of inertia.

Newton's laws of motion govern how a baseball moves as a result of being thrown or struck. According to Newton's first law, a moving ball will continue to move in a straight line until other forces are acting on it.

The ball is severely distorted by the enormous force the bat applies to it ball being struck. The average force acting during the bat-ball collision is therefore about two tons, with a peak force of nearly four tons, during the 0.7 millisecond contact time. There's a lot of force there!

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Answer:

they are quantities with magnitude without direction e.g weight,

Answer:

option c is correct

Explanation:

we know that

2as=vf^2-vi^2

vf=24 m/s

vi= 0 m/s

a=g= 9.8 m/s^2

s=vf^2-vi^2/2a

s=(24)²-(0)²/2*9.8

s=576/19.6

s=29.4 m

therefore option c is correct

Answer:

Explanation:

Using the equation of motion to get the distance

average Speed =distance/ time

Distance = average speed * time

Distance = (v-u)t

Distance = (16-8)* 10

Distance =8*10

Distance = 80m

Hence the distance covered by the object is 80m

Usability of the New E-mail System 1. Substitute a more descriptive scale, such as "Strongly Agree," "Agree," "Somewhat Agree," "Somewhat Disagree," "Disagree," and "Strongly Disagree" for the numerical scale.

Simply remove the numerical scale and insert the more descriptive scale in its place to do this. The first sentence, for instance, may be altered to read "I can work more quickly and efficiently in my work group since we use the new e-mail system. Use the following scale to indicate your level of agreement with this statement: Strongly Agree, Agree, Somewhat Agree, Somewhat Disagree, Disagree, Strongly Disagree."

2. Ensure that the questions are precise and short.

You must make sure the questions are simple to grasp, not too long or difficult to answer, and plain and succinct. For instance, you could reword the survey's second statement to read, "Does using the new e-mail system boost my work performance?"

3. Check if the survey's questions are pertinent to the subject at hand.

The survey topic should be addressed by the questions. The survey in this instance concerns how usable people believe the new email system to be. Therefore, this subject should be the subject of all queries. The third statement in the survey has to be changed or removed because it has nothing to do with the subject matter.

4. Only posit inquiries that can be fully answered.

The questions ought to be created in a way that allows for truthful responses. The inquiries must to be clear and devoid of any possibility for interpretation. The fourth line, for instance, may be changed to read, "Using the new e-mail system makes it easier for me to prepare for meetings and finish my work on time?"

5. If necessary, give the questions context.

It could occasionally be required to provide the questions background. How simple is it for you to use the new e-mail system to get ready for meetings and finish your work on time, for instance, is how the fifth sentence may be phrased.

6. Lower the overall number of inquiries.

It's crucial to limit the overall number of inquiries to minimum.

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When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Some energy in a body is unavailable to do useful work. According to second law of thermodynamic, unavailable energy is quantified as the . the increase in entropy.

According to second law of thermodynamics, the heat is flowing from a hot body to colder body. This heat transfer from hot to cold, for instance, is related to nature's tendency for disorganized systems and a lack of energy available for labor.

It has been demonstrated that a system's entropy is a measurement of its disorder and the lack of energy for work.Entropy is a measurement of the amount of energy that cannot be used for labor.

Even if all kinds of energy are interconvertible and all of them can be utilized to do work, it is not always feasible to employ all of the available energy for labor, even in theory.

The study of thermodynamics is interested in this unusable energy because efforts to turn heat into work gave rise to the discipline.

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Raju's statement is not correct fully as it states that uniform motion is seen only in objects traveling in a straight line while ,Tejas is correct in pointing out that uniform motion can also be observed in objects traveling in circular motion. 

Uniform motion refers to the movement of an object at a constant speed in a particular direction. In this type of motion, the object covers equal distances in equal intervals of time. Suppose for example (straight line movement), a car moving on a straight road at a constant speed of 60 km/h. If the car maintains this speed without any change in direction, it exhibits uniform motion. Other example is regarding the object moving in circular path where  a race car driving around a circular track with a radius of 100 meters. If the car maintains a constant speed of 40 meters per second and completes each lap in the same amount of time, it exhibits uniform motion. Therefore, Tejas' justification is valid, as he states that uniform motion can indeed be observed in objects traveling in circular paths, in addition to objects moving in straight lines.

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The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

Thus, Waveforms with periodic variations are those that recur consistently at set intervals.

The phrase is typically used in electronics to describe periodically changing voltages, currents, or electromagnetic fields. It is typically used in acoustics to describe constant periodic sounds caused by changes in air pressure or other media.

In these situations, the signal's frequency, amplitude, or phase shift have no bearing on the waveform, which is a characteristic. Additionally, non-periodic signals like chirps and pulses can be referred to by this name.

Thus, The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

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Answer:

D)parallel circuit

Explanation:

the components are placed parallel from eachother

V = 331 + 0.59 Tc

v= d/t = 272 / 0.8 = 340 m/s

340 = 331 + 0.59 Tc

340 - 331 = 0.59 TC

9 = 0.59 Tc

9/0.59 = Tc

Tc = 15.25°C

Answer:

If there is a system of magnets being held in place, there is potential energy. When you let go the potential energy makes to kinetic energy and the magnets move.

Magnets cause objects to have kinetic energy as a result of the magnetic

force present in it.

Magnets is a material which has a strong metallic field which attracts

ferromagnetic substances such as steel, iron etc.

When  the magnets are put near these substances , the magnets attract them and causes them to move towards its direction . The magnets causes the conversion of the potential energy into kinetic energy through the strong metallic field.

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Answer:

a.) 12\(\frac{rad}{s^2}\)

b.) 48\(\frac{rad}{s}\)

c.) 23.87 rev

Explanation:

First, convert linear velocity to angular velocity.  The angular velocity can be calculated using the relationship v=rω, where v is the linear velocity, r is the radius, and ω is the angular velocity.  Rearrange the equation to solve for ω:

\(\omega=\frac{v}{r}\)

For this problem, let v=30\(\frac{m}{s}\) and r=0.5m.  So,

\(\omega=\frac{30\frac{m}{s}}{0.5m}\\\omega=60\frac{rad}{s}\)

Next, to solve for angular acceleration use rotational motion equation #1, \(\omega_f=\omega_i+\alpha t\).  For this problem, let

\(\omega_i=0.0\frac{rad}{s}\\\omega_f=60\frac{rad}{s}\\t=5s\)

So,

\(60\frac{rad}{s}=0.0\frac{rad}{s}+\alpha(5s)\\(\frac{1}{5s})60\frac{rad}{s}=\alpha(5s)(\frac{1}{5s})\\12\frac{rad}{s^2}=\alpha\)

Next, use the angular acceleration and the time given in part b in rotational motion equation #1 to solve for the angular velocity at t=4s:

\(\omega_f=\omega_i+\alpha t\\\omega_f=0.0\frac{rad}{s}+(12\frac{rad}{s^2})(4s)\\\omega_f=48\frac{rad}{s}\)

To find the number of revolutions, use rotational motion equation #3, \(\theta=v_it+\frac{1}{2}\alpha t^2\), to find the angular displacement at t=5s.  So,

\(\theta=0.0\frac{m}{s}(5s)+\frac{1}{2}(12.0\frac{rad}{s^2})(5s)^2\\\theta=0.0m+150\ rad\\\theta=150\ rad\)

To convert the angular displacement in radians to revolutions, recall that one revolution equals 2π radians.  So,

\(150\ rad(\frac{1\ rev}{2\pi\ rad})=\frac{75}{\pi}\ rev\approx23.87\ rev\)

Answer:  

Explanation:

Step one:

given data

period T= 3 milliseconds= 0.003

velocity v= 175m/s

wave lenght λ=?

Step two:

we know that f=1/T

the expression relating period and wave lenght is

v=λ/T

λ=v*T

λ=175*0.002

λ=0.525m

to cm= 0.525*100

=52.5cm

The wavelength of the wave is E) 52.5 cm

In magnetic elements, each atom’s magnetic domains are aligned which creates magnetic force. In nonmagnetic elements, each atom’s domains are pointing in the different directions so, resulting element has nonmagnetic force.

Attraction or repulsion that arises between electrically charged particles because of their motion is called magnetic force and it is the basic force responsible for such effects as action of electric motors and also attraction of magnets for iron.

Magnetism is caused by motion of electric charges. Every substance is made up of tiny units called atoms and each atom has electrons, particles that carry electric charges. Spinning like tops, electrons circles the nucleus, or core, of an atom.

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The examples of light behaving like an electromagnetic wave are Compton scattering, interference through two slits, diffraction through one slit, and refraction.

Light is a type of electromagnetic radiation that is composed of electromagnetic waves. Light behaves like an electromagnetic wave in several ways. Electromagnetic waves are transverse waves that travel through a vacuum. They don't need a medium to propagate. Light can behave like an electromagnetic wave in several ways. Let's discuss each option in the question.
Compton scattering: Compton scattering is a phenomenon in which an incident X-ray or gamma-ray photon collides with an electron resulting in a scattered photon and a recoiling electron. It can only be explained by assuming that light behaves as both waves and particles. Therefore, Compton scattering is an example of light behaving like an electromagnetic wave.
Interference through two slits: When light passes through two narrow slits separated by a distance that is small compared to the wavelength of the light, it will diffract and interfere. The interference pattern will be characterized by bright and dark fringes. This phenomenon is an example of light behaving like an electromagnetic wave.
Diffraction through one slit: When light passes through a single narrow slit, it diffracts and creates an interference pattern similar to that produced by two slits. This phenomenon is an example of light behaving like an electromagnetic wave.
Photoelectric effect: The photoelectric effect is a phenomenon in which electrons are ejected from a metal surface when light shines on it. The photoelectric effect can be explained by assuming that light behaves as a stream of particles or photons. Therefore, the photoelectric effect is not an example of light behaving like an electromagnetic wave.
Refraction: Refraction is the bending of light as it passes from one medium to another, such as from air to water. It can be explained by assuming that light behaves like an electromagnetic wave. Therefore, refraction is an example of light behaving like an electromagnetic wave.

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Answer:

Volume flow rate is the same in both sections of the pipe

Explanation: