One British horsepower (550 ft⋅lb/s) is equal to 746 W. The horsepower rating of a 150-W lightbulb would be 0.20 British horsepower.
Determining the horsepower rating of a lightbulb:
Step 1: Identify the given value and the conversion factor:
Given value: 150 W
Conversion factor: 1 British horsepower = 746 W
Step 2: Set up the conversion equation: (150 W) × (1 British horsepower / 746 W)
Step 3: Cancel out the W (watts) unit: (150 / 746) British horsepower
Step 4: Calculate the result and round it to two significant figures:
0.201 British horsepower (unrounded)
0.20 British horsepower (rounded to two significant figures)
So, the horsepower rating of a 150-W lightbulb is approximately 0.20 British horsepower.
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Jaune moves North 15 meters, South 5 meters, then North 8 meters. How far is Jaune DISPLACED?
Answer:
Displacement = 7 meters
Explanation:
Given that,
Jaune moves North 15 meters, South 5 meters, then North 8 meters. We need to find the displacement of Jaune.
The attached figure shows the motion of Jaune.
We know that, Displacement = final position - initial position
Initially, Jaune traveled 15 meters due North and finally, he travel 8 meters North.
Displcement = 15 m - 8 m
Displacement = 7 m
So, the displacement of Jaune is 7 meters.
Under normal conditions the human heart converts about 12.5J of chemical energy per second into 1.25 W of mechanical power as it pumps blood throughout the body. (a) Determine the number of Calories required to power the heart for one day, given that 1 Calorie equals 4186 J. ________ Cal (b) Metabolizing 1 kg of fat can release about 9000 Calories of energy. What mass of metabolized fat (in kg) would power the heart for one day? _____ kg
(a) The number of Calories required to power the heart for one day is 258 Cal.
(b) The mass of metabolized fat that would power the heart for one day is 0.0287 kg.
What is the number of Calories required to power the heart?
The number of Joules of energy required to power the heart for one day is calculated as follows;
Power = 12.5 J / s
Energy = power x time
time = 1 day = 86400 seconds
Energy pumped by heart in one day = 12.5 J/s x 86400 s = 1,080,000 J
The number of calories contained in 1,080,000 J of chemical energy is calculated as;
1 Calorie = 4186 J
= 1,080,000 J / 4186 J
= 258 Cal
The mass of metabolized fat that would power the heart for one day is calculated as;
9000 Cal = 1 kg
258 Cal = ?
= 258 / 9000
= 0.0287 kg
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A 1.2kg mass is oscillating without friction on a spring whose spring constant is 3400N/m. When the mass's displacement is 7.2cm. What is its acceleration?
The acceleration of the mass is -181.8 m/s² (or 181.8 m/s² downwards).
The formula for acceleration of a simple harmonic oscillator can be used to find the acceleration of the given mass. The given values are: a mass of 1.2 kg; a displacement of 7.2 cm; and; a spring constant of 3400 N/m. The displacement is in centimeters, but it is required in meters for the formula. We can obtain the displacement in meters by dividing it by 100. Therefore, the displacement is 0.072 m. Using the formula for acceleration in a simple harmonic oscillator, we can get the acceleration as: a = - {k}{m} x a = -{(3400 N/m)}{(1.2 kg)}(0.072 \space m) a = - 181.8 \space m/s²
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Determine the maximum constant speed at which the pilot can travel around the vertical curve having a radius of curvature p = 800 m, so that he experiences a maximum acceleration an = 8g = 78.5 m/s2. If he has a mass of 70 kg, determine the normal force he exerts on the seat of the airplane when the plane is traveling at this speed and is at its lowest point.
The maximum constant speed at which the pilot can travel around the vertical curve with a radius of curvature of
p = 800 m so that he experiences a maximum acceleration of
an = 8g = 78.5 m/s2 is 89.4 m/s.
Given data:
Radius of curvature p = 800 m
Maximum acceleration an = 8g = 78.5 m/s²
Mass of the pilot m = 70 kg
Maximum speed v for the plane is given as follows:
an = (v²) / pm
g = (v²) / p78.5 m/s²
= (v²) / (800 m)
where v is the velocity and an is the maximum acceleration Let's solve the above equation for v to determine the maximum constant speed:
v² = 78.5 m/s² × 800
mv² = 62800
v = √62800
v = 250.96 m/s
The pilot can travel at a maximum speed of 250.96 m/s
to experience a maximum acceleration of 8g if we consider the theory of relativistic mass increasing with speed.
So we need to lower the speed to achieve 8g.
For a safe speed, let's take 80% of the maximum speed; 80% of 250.96 m/s = 200.768 m/s
Therefore, the maximum constant speed that the pilot can travel around the vertical curve having a radius of curvature p = 800 m,
so that he experiences a maximum acceleration an = 8g = 78.5 m/s2, is 200.768 m/s.
When the plane is traveling at this speed and is at its lowest point, the normal force he exerts on the seat of the airplane is;
N = m(g + an)
Here, m = 70 kg, g = 9.81 m/s²,
and an = 78.5 m/s²
N = (70 kg)(9.81 m/s² + 78.5 m/s²)
N = 5662.7 N (approx)
Therefore, the normal force the pilot exerts on the seat of the airplane when the plane is traveling at the maximum constant speed and is at its lowest point is 5662.7 N.
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Copy and complete the sentences below, choosing the correct words, to describe the image formed in
a plane mirror.
The image in a plane mirror is real / virtual.
It is bigger than / smaller than / the same size as the object.
c It is as far behind the mirror as the object / image is in front.
It is left-right inverted / upside down.
A. The image in a plane mirror is virtual
B. It is the same size as the object
C. It is as far behind the mirror as the object is in front
D. It is left-right inverted
What are the characteristics of image by plane mirror?A plane mirror is described as a flat reflective surface which gives image having the following characteristics:
The image is virtual as it is formed behind the mirror.Same size as the objectDistance of image is the same a distance of there object from the mirrorLaterally (i.e left-right) invertedWith the above information, we can give the correct answers to the question as follow:
The image formed in a plane mirror is:VirtualSame size as the objectIt is as far behind the mirror as the object is in frontIt is left-right invertedLearn more about image by plane mirror:
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how would the air pressure change if ""fair"" weather were approaching?
As fair weather approaches, the air pressure generally increases. Fair weather is associated with high-pressure systems, where air descends and becomes more compressed, resulting in higher atmospheric pressure. This increase in air pressure indicates stable weather conditions with clear skies and relatively calm winds.
There is typically a rise in air pressure. Fair weather is associated with high-pressure systems, where air descends and spreads outwards, leading to compression and an increase in atmospheric pressure. This rise in air pressure indicates stable weather conditions with clear skies, minimal cloud cover, and generally calm winds. The higher air pressure inhibits the formation of clouds and precipitation, creating a favorable environment for pleasant and sunny weather. Meteorologists often monitor changes in air pressure as an indicator of approaching fair weather systems.
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1. What is the pressure caused on the ground by an elephant of weight 20000N
if each foot has an area of 0.2m??
Answer:
2000 pascal
Hope it helps
12) A road has a round hump 12.0 m in radius. What is the minimum speed at which a car can leave the road at the top
of the hump?
The minimum speed at which a car can leave the road at the top is 10.84 m/s.
The minimum speed
The minimum speed at which the car can leave the road is calculated as follows;
\(F_c = F_n\\\\\frac{mv^2}{r} = mg\\\\\frac{v^2}{r} = g\\\\v^2 = rg\\\\v = \sqrt{rg} \\\\\)
where;
r is the radius of the curved road = 12 mg is acceleration due to gravity = 9.8 m/s².\(v = \sqrt{12 \times 9.8} \\\\v = 10.84 \ m/s\)
Thus, the minimum speed at which a car can leave the road at the top is 10.84 m/s.
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Which of these sources are used to generate electrical energy in power plants? Check all that apply.
coal
natural gas
biodiesel
nuclear reactions
wind
batteries
water
Answer:
all but biodeisel and batteries
Explanation:
well batteries are used to STORE energy not generate it
What is the ratio between the force of gravity of the Earth on the Moon and the Earth on a hypothetical object orbiting Earth at 1/5 the distance between the Earth and Moon but this object has 1/100th the mass of the Moon?
The ratio between the force of gravity of the Earth on the Moon and the Earth on a hypothetical object orbiting Earth at 1/5 the distance between the Earth and Moon, but with 1/100th the mass of the Moon, is 100:1.
The force of gravity between two objects depends on their masses and the distance between them. In this scenario, we have the Earth and the Moon, as well as a hypothetical object orbiting Earth at 1/5 the distance between the Earth and Moon, with 1/100th the mass of the Moon.
Let's denote the mass of the Earth as E, the mass of the Moon as M, and the mass of the hypothetical object as O. The force of gravity between the Earth and the Moon is given by the equation FEM = G * (E * M) /\(R^2,\) where G is the gravitational constant and R is the distance between the Earth and the Moon.
Now, for the hypothetical object orbiting Earth, the force of gravity between the Earth and the object is given by FEO = G * (E * O) /\((1/5 R)^2\), where (1/5 R) is the reduced distance between the Earth and the object.
To find the ratio between the two forces, we can divide FEM by FEO. Substituting the respective values and simplifying the equation, we get the ratio as (E * M) / (E * O) *\((1/5 R)^2\) /\(R^2\) = M/O * (1/25) = 1/100 * (1/25) = 1/2500.
Thus, the ratio between the force of gravity of the Earth on the Moon and the Earth on the hypothetical object is 1:2500, or approximately 100:1.
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5. Based on your experiences with damping in the simulation, how do you think you could damp a sound wave?
Sound waves between layers of mass are dampened or diminished using MLV (Mass Loaded Vinyl).
By converting sound waves into heat through the use of a viscoelastic damping compound or MLV, the waves are weakened before they reach the next layer of mass.
Sound can only be stopped by mass. A mass can be made of plywood, drywall, or concrete.
The typical model for wave damping includes a velocity dependent term.
The damping increases when you try to distort the medium more quickly. The amount of damping is significantly influenced by the fluid's viscosity, through which the sound wave is propagating.
Only the bass portion of music is audible when heard from a distance because higher frequency sound dampens in air more quickly.
How does wave damping work?The wave's amplitude decreases with increasing displacement due to the decrease in energy per unit volume. However, when the wave's energy is dispersed over a huge region, causing it to decay rapidly, a different sort of damping (decrease in energy per unit volume) can be seen.
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2. A block of mass 1.2 kg lies on a frictionless surface. A man slides the block
against a spring, compressing it .15m. When the man lets go of the spring, the
block moves at 5 m/s. What is the spring constant of the spring?
mm
.
Answer:
The spring constant will be "1333.33 N/m".
Explanation:
The given values are:
Mass,
m = 1.2 kg
Displacement compression,
x = 0.15 m
Block's velocity,
\(v_i=5 \ m/s\)
As we know,
⇒ \(E_i=E_f\)
or,
⇒ \(K_i+v_i=K_f+v_f\)
⇒ \(\frac{1}{2}mv_i^2+0=0+ \frac{1}{2}Kx^2\)
So,
⇒ \(K=\frac{mv_i^2}{x_2}\)
On substituting the values, we get
⇒ \(=\frac{1.2\times 5\times 5}{0.15\times 0.15}\)
⇒ \(=\frac{30}{0.0225}\)
⇒ \(=1333.33 \ N/m\)
horizontal angulation is a. determined by the stabe bite-block. b. correct when the central ray is parallel to the curvature of the arch. c. the side-to-side angulation. d. different when using the paralleling and bisecting techniques.
The location of the tubehead and the central ray's direction in a horizontal, or side-to-side, plane are referred to as horizontal angulation. Whether you use the paralleling or bisecting technique, the horizontal angulation stays the same.
How does vertical angulation work?The recorded image's length is determined by vertical angulation. When employing the paralleling technique and receptor holders, the holding device determines the vertical angulation, which causes the x-ray beam to be directed perpendicular to both the receptor and teeth.
What distinguishes vertical from horizontal angulation?Angles in the vertical: The long axis of the tooth and the film should both be perpendicular to the central ray of the x-ray beam. Horizontal angulation: Pass the x-ray beam's central ray via the contact points where the teeth are located.
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When is it safer to drive a heavier car over a lighter car?
a. When you crash into a wall
b. When you crash into a tree
c. When you crash into another car
d. It is never safe in a hevaier car
Answer:
I think it would be c, crashing into another car
how does an elevator model Newton’s First Law of Motion?
When the elevator is going up, though, you are accelerating, which adds more force to the scale and increases your apparent weight. When the elevator is going down, the same is true, but the acceleration is negative, subtracting force from the scale and decreasing your apparent weight.
How are endothermic and exothermic processes identified and how does the energy of the system change with each?
Answer:
Exothermic processes release energy upon completion
Explanation:
Endothermic processes require an input of energy to proceed and are signified by a positive change in enthalpy.
what is the volume occupied by a mole of an ideal gas, if the pressure is 626 mmhg and the temperature is 25.0°c?
The volume occupied by a mole of an ideal gas, if the pressure is 626 mmHg is 30.16 L.
At standard Temperature and stress (STP) the molar volume (Vm) is the volume occupied via one mole of a chemical element or a chemical compound. it may be calculated by dividing the molar mass (M) by using mass density (ρ).
An ideal gas is a theoretical gas composed of many randomly shifting point particles that are not a problem to interparticle interactions. the ideal fuel concept is useful as it obeys the best fuel regulation, a simplified equation of country, and is amenable to evaluation under statistical mechanics.
An ideal gas is defined as one for which the extent of molecules and forces between the molecules are so small that they have got no impact on the conduct of the gas.
PV = nRT
V = nRT/P
= 1× 0.083 × 298 / 626
= 1× 0.083 × 298 / 0.824
= 30.16 L
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Could someone please help me
Answer:
For the first one I Would just draw a triangle type shape going out towards the screen like light is being shined upon it. And the next question I would say the answer is yes.Explanation:
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In Young's double slit experiment using monochromatic light the fringe pattern shifts by a certain distance on the screen when a mica sheet of refractive index 1.6 and thickness 1.964 micron (1 micron = 10^-m) is introduced in the path of one of the interfering waves. The mica sheet is then removed and the distance between the screen and the slits is doubled. It is found that the distance between the successive maxima now is the same as the observed fringe-shift upon the introducing of the mica sheet. Calculate the wevelength of the monochromatic light used in the experiment
The fringe shift Δs due to the introduction of any sheet of thickness t and refractive index n in the path of any of the interfering waves is given by, Δs=(n−1)t D/2d which is 5892 Ä.
Due to the change in the distance of separation between the plane of the slits and the screen, the fringe width is given by λ×2D/2d
According to the statement of the problem,
λ×2D/2d =(n−1) t D/2d
λ=(n−1) t/2
(1.6−1) 1.964×10⁻⁶/2 =5892 Ä
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Stretch a copper wire so that it is thinner and the resistance between its ends Stretch a copper wire so that it is thinner and the resistance between its ends decreases. increases. remains unchanged.
Stretch a copper wire so that it is thinner and the resistance between its ends remains unchanged.
Resistance is proportional to resistivity and length, and inversely proportional to cross sectional area. Resistivity can be defined as the resistance of a conducting material per unit length with unit area of cross section.
Resistance = rho * (L/A)
rho = resistivity
L = length of wire
A = Cross section 'area of wore
if copper wire get stretched , length of wire will increase but due to thinning area of cross section get decreased
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show answer no attempt 50% part (a) what type of wave is created through a battering ram when it hits a wall?
When a battering ram strikes a wall, it creates a type of mechanical wave known as a pressure wave or a shock wave.
Pressure waves are created by the transfer of energy through a medium, such as a wall or the air, as a result of a sudden change in pressure. The energy from the battering ram creates a compression wave that moves out from the point of impact and spreads throughout the medium. This type of wave is different from transverse waves, such as light or radio waves, which move perpendicular to the direction of the wave's motion, or longitudinal waves, such as sound waves, which move parallel to the direction of the wave's motion. The pressure wave created by the battering ram is an example of a longitudinal wave that moves through the medium, transmitting the energy from the ram to the wall.
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What must happen to light in order for an image to form
Just like Coke is a type of soda, __________ is a type of ___________.
A.concentration,.equilibrium
B..equilibrium, concentration
C.diffusion, osmosis
D.osmosis. diffusion
Answer:
osmosis diffusionExplanation:
ok it's correct
You are waiting in line to use the diving board at your local pool. While watching people dive
into the pool from the board, you realize that using a diving board to spring into the air before a
dive is a good example of Newton’s third law of motion. Explain how a diving board illustrates
Newton’s third law of motion.
Answer:
because the diving board is helping the diver jump and helping increase the force of the diver's jump, they work together to help the jumper have a jump.
What is the speed of a jet plane that travels 3000 meters in 10 seconds?
Answer:
300 m/s
Explanation:
gravitational attraction is the driving force for which processes?
Answer:
stellar fusion
Explanation:
formation of moons expansion of the universe formation of stars, formation of planets, formation of nebulae
Which law do astronomers use to determine the masses of the stars in a spectroscopic binary system?.
Kapler's 3rd law use to determine the masses of the stars in a spectroscopic binary system by astronomers.
A star's mass (the amount of matter it contains) is one of its most important properties. As we'll see, knowing a star's mass allows us to estimate how long it will last and what its ultimate fate will be. However, it is very difficult to directly measure the mass of stars. The mass of the binary system can be estimated using Newton's formulation of Kepler's third law (described in Newton's Law of Universal Gravitation). Kepler discovered that the time it takes a planet to orbit the Sun is related to its distance from the Sun by a specific formula. When two bodies rotate relative to each other in a binary situation, the period (P) in which they orbit each other is related to the semimajor axis (D) of one of its orbits. Formula is D³ = ( M₁ + M₂ ) P²
where D is in astronomical units, P is in years, and ( M₁ + M₂) is the sum of the masses of the two stars in solar mass units. This is a very useful formula for astronomers. If we can observe the size of the orbits of the stars and the period of their mutual rotation in a binary system, we can calculate the sum of their masses.
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What is the cause of the aurora borealis (the northern lights)?
a. As the Earth moves through the solar magnetic field, a voltage is built up between the south and north magnetic poles. b. This voltage accelerates charged particles to collide with both poles, thus causing the atmosphere to glow.
c. The northern lights are reflections of fluorescent lights from large cities off clouds in the arctic. Electrons in the Van Allen radiation belts flip over their spin direction and emit light.
d. The Earth's magnetic field guides trapped charged particles to follow field lines toward the poles, where they collide with the atmosphere, causing a glow.
The cause of the aurora borealis (the northern lights) is the Earth's magnetic field guides trapped charged particles to follow field lines toward the poles, where they collide with the atmosphere, causing a glow. Option d.
The other options: As the Earth moves through the solar magnetic field, a voltage is built up between the south and north magnetic poles; This voltage accelerates charged particles to collide with both poles, thus causing the atmosphere to glow; The northern lights are reflections of fluorescent lights from large cities off clouds in the arctic. Electrons in the Van Allen radiation belts flip over their spin direction and emit light are all incorrect. Therefore the correct answer is option d.
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Correct statement is b. This voltage accelerates charged particles to collide with both poles, thus causing the atmosphere to glow.
How does aurora borealis occur?The cause of the aurora borealis, or the northern lights, is primarily described by option b. When the Earth moves through the solar magnetic field, it creates a voltage between the south and north magnetic poles.
This voltage accelerates charged particles, mainly electrons, in the Earth's magnetosphere. These accelerated particles then collide with atoms and molecules in the Earth's upper atmosphere, resulting in the emission of light. The glowing phenomenon of the northern lights is a direct consequence of these collisions.
The colors observed in the aurora are determined by the type of gas particles present in the atmosphere and the altitude at which the collisions occur. Hence correct statement is b. This voltage accelerates charged particles to collide with both poles, thus causing the atmosphere to glow.
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In reality, the kinetic energy at the bottom of the ramp will always be less than the gravitational potential energy at the top of the ramp. Does this disprove the law of conservation of energy? Where did the "lost" energy go?
Answer:
Conservation of energy still holds - so somewhere in traversing some of the potential energy was converted into something other than kinetic energy.
The loss of energy can be attributed to several things - friction on the ramp, air resistance, friction within the item descending the ramp; in general one would say that some of the initial PE was lost during the descent of the ramp. and did not show up as KE.
If you decrease the mass of an object to half of the original, how does the pressure change?
Answer:
The acceleration is equal to the net force divided by the mass. If the net force acting on an object doubles, its acceleration is doubled. If the mass is doubled, then acceleration will be halved. If both the net force and the mass are doubled, the acceleration will be unchanged.
Explanation:
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