Once a rock has become either igneous, sedimentary, or metamorphic it stays that way forever.

Responses

True



False

Answer:

5 sq. root 3

Explanation:

theta= 60°

=> u sin theta = 10 × sin 60

= 10× sq. root 3/2

= 5 sq. root 3

we have that from the Question"A projectile is launched at an angle of 60 degrees to the horizontal at an initial speed of 10 meters per second" it can be said that  

the magnitude of the vertical component of its initial velocity is

From the Question we are told

A projectile is launched at an angle of 60 degrees to the horizontal at an initial speed of 10 meters per second. What is the magnitude of the vertical component of its initial velocity?

Generally the equation for  vertical component is mathematically given as

The  vertical component will be the resolution of the vertical axis

Therefore

Fy=10sin60

Fy=8.660N

Therefore

the magnitude of the vertical component of its initial velocity is

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Answer:

First tell what are the directions and what we've to do?? add subtract or multiply??

a. The Aya's weight on Earth is 441 Newtons.

b. The Aya's mass on the moon would still be 45 kg.

c. Aya's weight on the moon is 72 Newtons.

a. Ayas weight on Earth can be calculated using the formula:

Weight = mass * gravitational acceleration

The gravitational acceleration on Earth is 9.8 m/\(s^2\).

Plugging in the given mass:

Weight = 45 kg * 9.8 m/\(s^2\) = 441 N

Therefore, Ayas' weight on Earth is 441 Newtons.

b. Aya's mass remains the same on the moon as it does on Earth. Therefore, Aya's mass on the moon would still be 45 kg.

c. To calculate Aya's weight on the moon, we need to consider the gravitational acceleration on the moon. The gravitational acceleration on the moon is approximately 1.6 m/\(s^{2}\). Using the same formula:

Weight = mass * gravitational acceleration

Weight = 45 kg * 1.6 m/\(s^{2}\) = 72 N

Therefore, Aya's weight on the moon is 72 Newtons.

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The magnitude of the change in momentum is therefore 6.12 kg*m/s, and the direction is downward and the floor exerts an average net force of 51 N upward on the ball during the collision.

(a) To find the magnitude and direction of the ball's change in momentum, we need to first find the initial and final momenta of the ball. The initial momentum is given by:

\(p_i = m*v_i\)

where m is the mass of the ball, and \(v_i\) is the initial velocity of the ball before it hits the floor. Substituting the given values, we get:

\(p_i\) = (0.60 kg)(6.0 m/s) = 3.6 kg*m/s

The final momentum is given by:

\(p_f = m*v_f\)

where \(v_f\) is the velocity of the ball after it rebounds from the floor. Substituting the given values, we get:

\(p_f\)= (0.60 kg)(-4.2 m/s) = -2.52 kg*m/s

Note that the negative sign indicates that the direction of the final momentum is opposite to that of the initial momentum.

The change in momentum is given by:

Δp = \(p_f - p_i\)

Substituting the calculated values, we get:

Δp = -2.52 kgm/s - 3.6 kgm/s = -6.12 kg*m/s

The magnitude of the change in momentum is therefore 6.12 kg*m/s, and the direction is downward.

(b) To find the average net force that the floor exerts on the ball, we can use the impulse-momentum theorem:

Δp = \(F_avg\) * Δt

where Δt is the time duration of the collision. Substituting the calculated value of Δp and the given value of Δt, we get:

-6.12 kg*m/s = \(F_avg\) * 0.12 s

Solving for \(F_avg\), we get:

\(F_avg\) = -6.12 kg*m/s / 0.12 s = -51 N

Note that the negative sign indicates that the direction of the average net force is opposite to that of the change in momentum, i.e., upward. Therefore, the floor exerts an average net force of 51 N upward on the ball during the collision.

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Answer:

(C) new continental crust

Explanation:

Answer:

GIDDTAEWJRGAB SEIawuYECIauwGE awyE UIa wyYUGSZEFUG SeRGYSEUSR SDJFS UEF SDJK VVSUGEFIUseR suoe RY:osE RseuiR

Explanation:

I EUISTsjie hYRUyeRE HueRU seUILQALUIE SLieQLALle gLIU EGeL EIeusR eSRUOhr

(a) The tension in the nearer cable is 941 N, and (b) the tension in the farther cable is 1373 N.

We need to find the tension in both the nearer and farther cables supporting the scaffold with a window washer on it.

a) To find the tension in the nearer cable, we must first calculate the total torque acting on the system, keeping in mind that the torque must be zero for the system to be in equilibrium. The torque contributions are:

1. The torque due to the window washer's weight (80 kg * 9.81 m/s²) acting at a distance of 1.5 m from the nearer cable.

2. The torque due to the scaffold's weight (60 kg * 9.81 m/s²) acting at the midpoint of the scaffold, which is 2.5 m from each cable.

Now, we can set up the torque equation:

T_near * 5.0 m = (80 kg * 9.81 m/s² * 1.5 m) + (60 kg * 9.81 m/s² * 2.5 m)

Solve for T_near:

T_near = ((80 kg * 9.81 m/s² * 1.5 m) + (60 kg * 9.81 m/s² * 2.5 m)) / 5.0 m
T_near ≈ 941 N

b) To find the tension in the farther cable, we can use the fact that the sum of the tensions in both cables must equal the total weight of the system (scaffold + window washer):

T_far + T_near = (80 kg + 60 kg) * 9.81 m/s²

Solve for T_far:

T_far = (140 kg * 9.81 m/s²) - T_near
T_far ≈ 1373 N

Therefore,  the tension in the nearer cable (a) is approximately 941 N, and the tension in the farther cable (b) is approximately 1373 N.

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The diagrams of two vectors is shown below in pictorial representation.

Since the two balloons are charged with the same amount and are hanging from strings near each other, they will experience electrostatic repulsion due to their like charges.

Therefore, the force diagrams for each of the balloons will include a repulsive electrostatic force pointing away from the other balloon.

In addition to the electrostatic force, each balloon will experience a gravitational force due to its mass and the force of tension from the string that is holding it up.

Since the two balloons have different masses, the force diagram for each balloon will be slightly different.

For the lighter balloon, the force diagram would look something like this:

  /        \

 /          \

|            |

|            |

|  Electro-  |

|  static    |

|   force    |

|            |

|            |

|            |

 \          /

      |

      |

  Tension

  force

      |

      |

   Gravitational

   force

      |

      |

     Mass

For the heavier balloon, the force diagram would look similar, but with a larger gravitational force vector and a smaller tension force vector due to the increased weight of the balloon:

  /        \

 /          \

|            |

|            |

|  Electro-  |

|  static    |

|   force    |

|            |

|            |

|            |

 \          /

      |

      |

  Tension

  force

      |

      |

     Gravitational

     force

      |

      |

     Mass

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Answer:

An electron added to a noble gas must go in the next higher energy level. The periodic trend for electron affinity values is not as consistent as for other trends.

Answer:

b. Thermal energy will flow from your hand to the snowball.

Explanation:

Answer:

B

Explanation:

The region that best matches a typical IR spectrum is 4000 to 400 cm-1.

The IR spectrum is a plot of transmitted (or absorbed) frequencies versus transmission intensity (or absorption).

The region that best matches a typical IR spectrum is typically considered to be 4000 to 400 cm-1 , also known as the "fingerprint region" as it contains the majority of the vibrational absorption bands for most organic compounds.

However, it's worth noting that different types of compounds or samples may exhibit different spectral features and may require different regions to be examined in order to obtain meaningful information.

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Answer:

please help

Explanation:

Answer:

6.8×10^6 m

Explanation:

f = velocity of light/ wavelength

440= 3×10^8 / wavelength

so

wavelength = 3×10^7/ 44

= 6.8×10^6 m

The oxygen-to-sulfur mass ratio of sulfur dioxide is 2:1.

Sulfur dioxide (SO2) is a chemical compound made up of one sulfur atom and two oxygen atoms. It is a colorless, strong-smelling gas that is often produced when sulfur-containing fuels are burned.The molecular mass of sulfur dioxide is 64 g/mol, with the mass of each sulfur and oxygen atom being 32 g/mol and 16 g/mol, respectively. As a result, the oxygen-to-sulfur mass ratio in sulfur dioxide can be computed as follows:mass of oxygen/mass of sulfur=2*16 g/mol/32 g/mol=2:1Therefore, the oxygen-to-sulfur mass ratio of sulfur dioxide is 2:1. This means that for every 32 grams of sulfur in sulfur dioxide, there are 2 times 16 grams, or 32 grams, of oxygen. This ratio can be used to calculate the mass of either oxygen or sulfur in a given quantity of sulfur dioxide, as long as the quantity of one of the elements is known.

In conclusion, the oxygen-to-sulfur mass ratio of sulfur dioxide is 2:1, which means that for every 32 grams of sulfur, there are 32 grams of oxygen. This ratio can be used to calculate the mass of either element in a given quantity of sulfur dioxide, given that the quantity of one of the elements is known.

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Answer:

(i)

Force of gravity acting on the boy = mg

= 40 * 10

= 400 N

(ii)

Work done by him = mgh

= 40 * 10 * 0.08

= 32 J

(iii)

Power = Work / Time

= 32 / 5

= 6.4 Watt

Explanation:

hope this helps

Answer:

Option A (1.51 m) is the appropriate option.

Explanation:

The given values are:

Speed of wave,

= 362 m/s

Period,

= 4.17

Now,

⇒  \(v=\frac{\lambda}{T}\)

then,

⇒  \(\lambda=vT\)

⇒     \(= 362\times 4.17\times 10^{-3}\)

⇒     \(=1.51 \ m\)

The amount of M112 required to breach a 6-foot thick first-class masonry wall will depend on various factors such as the dimensions and characteristics of the wall, the placement and configuration of the charge, and the specific properties and performance of the explosive material.

Therefore, it is difficult to give a definitive answer without additional information. However, it is important to note that the use of explosives is a highly regulated activity that requires specialized training and permits. It should only be performed by authorized and trained personnel following established safety protocols and regulations.

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potassium ions into the cell and

outside

⇒ sodium ions out of the cell.

\(\rm \text{Work} = -1620 \, \text{Joules} \]\)

The negative sign indicates that Sam does negative work, which means he exerts a force in the opposite direction of the displacement, decelerating the boat to a stop.

To calculate the work done by Sam to stop the boat, we need to use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.

Given:

Mass of the boat and its riders \(\rm (\(m\))\) = 1000 kg

Initial velocity of the boat \(\rm (\(v_{\text{initial}}\))\) = 1.8 m/s

Final velocity of the boat \(\rm (\(v_{\text{final}}\))\) = 0 m/s (as it comes to a stop)

The kinetic energy of the boat initially is given by:

\(\rm \[ KE_{\text{initial}} = \frac{1}{2} m v_{\text{initial}}^2 \]\)

The kinetic energy of the boat finally is given by:

\(\rm \[ KE_{\text{final}} = \frac{1}{2} m v_{\text{final}}^2 \]\)

As the boat comes to a stop, the final kinetic energy \(\rm (\(KE_{\text{final}}\))\) is zero. Therefore, the work done by Sam to stop the boat is:

\(\rm \[ \text{Work} = KE_{\text{final}} - KE_{\text{initial}} = 0 - \frac{1}{2} m v_{\text{initial}}^2 \]\)

Substitute the given values:

\(\[ \text{Work} = 0 - \frac{1}{2} \times 1000 \times (1.8)^2 \]\\\\\ \text{Work} = -\frac{1}{2} \times 1000 \times 3.24 \]\\\\\ \text{Work} = -1620 \, \text{Joules} \]\)

The negative sign indicates that Sam does negative work, which means he exerts a force in the opposite direction of the displacement, decelerating the boat to a stop.

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The rate at which the radius increases when the radius is 6 cm is approximately 0.056 cm/s.

To determine how fast the radius increases, we can use the given information about the volume of a cylinder and its rate of change. The volume of a cylinder is given by the formula v = πR²H, where R represents the radius and H represents the height.

Given that the radius is three times the height, we can express the height as H = R/3. Substituting this value into the volume equation, we have v = πR²(R/3). Simplifying further, the volume equation becomes v = (π/3)R³.

Now, we are given that the volume increases at a rate of 10 cm/s. By taking the derivative of the volume equation with respect to time, we can determine how the radius changes over time. The derivative, dv/dt, is equal to (π/3)(3R²)(dR/dt), where dR/dt represents the rate of change of the radius.

Simplifying the equation, we have dv/dt = πR²(dR/dt). Substituting the given values, we have 10 cm/s = π(6²)(dR/dt).

Solving for dR/dt, we find that the rate at which the radius increases when the radius is 6 cm is approximately 0.056 cm/s.

Calculus and related concepts to explore the relationships between variables and their rates of change. Understanding these mathematical principles is essential for analyzing dynamic systems and their behaviors.

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The magnitude of your displacement after driving 650 ft to the east and 400 ft to the north is approximately 763.14 ft.

The magnitude of your displacement after driving 650 ft to the east and 400 ft to the north can be found by,

Understand that displacement is the change in position and is a vector quantity, meaning it has both magnitude and direction.

Draw a right triangle with the eastward distance (650 ft) as the base and the northward distance (400 ft) as the height.

Use the Pythagorean theorem to find the magnitude of the displacement. The theorem states that the square of the length of the hypotenuse (displacement) is equal to the sum of the squares of the lengths of the other two sides (eastward and northward distances).

In this case, the equation will look like this:

Displacement^2 = (650 ft)^2 + (400 ft)^2

Calculate the square of each distance:

Displacement^2 = 422,500 ft^2 + 160,000 ft^2

Add the squared distances:

Displacement^2 = 582,500 ft^2

Take the square root of the sum to find the magnitude of the displacement:

Displacement = √582,500 ft^2 ≈ 763.14 ft

So, the magnitude of your displacement after driving 650 ft to the east and 400 ft to the north is approximately 763.14 ft.

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Answer:

Label A: red

Label B: yellow

Label C: green

Label D: blue

Label E: violet/purple

I think this should be correct. I'm sorry if I'm incorrect

Based on the degree of refraction from least to most refracted, the colors are as follows: Red, Orange, Yellow, Green, Blue, Indigo, Violet.

Refraction of light is the bending of light rays as they cross the boundary between two media of different densities.

White light consists of seven colors of light; Red, Orange, Yellow, Green, Blue, Indigo, Violet.

The red color has the shortest wavelength and is the least refracted while violet color has the longest wavelength and is most refracted.

Therefore, based on the degree of refraction from least to most refracted, the colors are as follows: Red, Orange, Yellow, Green, Blue, Indigo, Violet.

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According to Hubble's law, with v = 70 km/s, the recessional velocity of a galaxy at a distance of 180 Mpc is 12.86 km/s. The correct option is c) 12.86 km/s.

What is Hubble's law?

The Hubble's law states that the universe is continuously expanding; that is, the farther the galaxies are, the faster they are moving away from us. It can be defined as the relationship between the recessional velocity of a galaxy and its distance from the Earth expressed in km/s/Mpc.

Mathematically, Hubble's law can be represented as:

v = H*d

where:

v is the recessional velocity of the galaxy,

H is the Hubble's constant (70 km/s/Mpc),

d is the distance of the galaxy from the Earth (180 Mpc)

We can substitute the given values into the formula:

v = 70 km/s/Mpc * 180 Mpc

v = 12600 km/s / 1000

v = 12.6 km/s

Therefore, the answer is 12.86 km/s, which is close to option c.

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When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, the magnetic induction (B) is increased.

Therefore, the correct answer is:

(a) There is a large increase in the magnetic induction (B)

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Answer:

30MPH

Explanation:

30/5 = 6 x 5 = 30 mph

On a seismogram, which is the record of ground motion produced by an earthquake, the S-P interval can be measured by finding the time difference between the arrival of the S-wave and P-wave signals.

The S-P interval, also known as the S-P time interval, is an important measurement in seismology used to determine the distance between an earthquake and a seismic station. It represents the time difference between the arrival of the S-wave and P-wave at the seismograph station.

On a seismogram, which is the record of ground motion produced by an earthquake, the S-P interval can be measured by finding the time difference between the arrival of the S-wave and P-wave signals. Typically, the seismogram will have distinct arrivals for both the P-wave and S-wave, which appear as distinct lines or traces on the seismogram.

To measure the S-P interval, you would locate the arrival times of the P-wave and S-wave on the seismogram and calculate the time difference between them. This time difference can then be used, along with known travel time curves or equations, to estimate the distance from the seismic station to the earthquake epicenter.

It's important to note that the actual seismogram recording and interpretation should be conducted by trained seismologists or experts in the field, as they have the knowledge and experience to accurately analyze seismic data.

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If your new motorcycle weighs 2540 N, the mass of your new motorcycle is 259.18 kg.

To calculate the mass of the motorcycle, we can use the formula:

Weight = mass × acceleration due to gravity

In this case:

Rearranging the formula to solve for mass:

mass = Weight / acceleration due to gravity

Substituting the given values into the formula:

mass = 2540 N / 9.8 m/s²

Calculating the value:

mass ≈ 259.18 kg

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The resistance per unit length of a 22-gauge nichrome wire with a radius of 0.33 cm is 9.259 x \(10^{-6\) Ω/cm.

R = (ρ * L) / A

A = π * r² = π * (0.33 cm)² = 0.108 cm²

R/L = (ρ/A) = (1.0 x \(10^{-6\) Ω-m) / (0.108 cm²) = 9.259 x \(10^{-6\) Ω/cm

Resistance can refer to a few different things, but in general, it describes opposition or refusal to comply with something. In the context of physics, resistance refers to the hindrance or opposition to the flow of electric current through a material. Electrical resistance is measured in ohms, and materials with high resistance impede the flow of electricity more than materials with low resistance.

In other contexts, resistance can describe opposition to social or political change, such as a resistance movement or resistance to an authoritarian government. Resistance can also refer to a force opposing motion or change, such as friction or air resistance. In the field of psychology, resistance can describe a patient's reluctance or opposition to engage with or confront certain emotions or issues in therapy.

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