On Friday morning, before their Discrete Mathematics lecture, 5 students each leave one bag in the Cloakroom. How many ways can their bags be returned to them so that none of them get their own bags back

Answer:

whats the question??  lol

Step-by-step explanation:

Answer:

12/3=4 ..............

Answer: 14% of 600 is 84

Step-by-step explanation:

Write 14% as 14/100

Since finding the fraction of a number is the same as multiplying the fraction with the number, we have

14/ 100 of 600 =

14/ 100  × 600

therefore the answer is 84

Answer:2.33333334

Step-by-step explanation:

it could be 84

Answer:

Yes that is very much correct y'know thanks for the free points

Step-by-step explanation:

Answer:

60-15y=x

Step-by-step explanation:

Answer:

  (b)  56.5 ft

Step-by-step explanation:

The circumference of a circle of diameter d is given by ...

  C = πd

For the given diameter, the circumference of the frame is ...

  C = (3.14)(18 ft) ≈ 56.52 ft

The length of the outside edge of the frame is about 56.5 feet.

Answer:

2nd answer

Step-by-step explanation

Answer:

people are survivors and also a good person that can help with dysphoria of a child then a person that has a relationship to the parent and also wants you are not links with the person that is not a good friend or not a child and not everyone have to do that with a friend who are you stu you are a incel.co girl gamer who are not the only one of the things I do understand what I don't like it then you would know what he'll be like you and what you want me and then you are going

Answer:

The z-score for this data point is -1.5

Step-by-step explanation:

Mean = M = 150

Standard Deviation = S = 20

Value = x = 120

We find the z value,

\(z = (x-M)/S\\z = (120 - 150)/20\\z = (-30)/20\\z=-3/2\\z=-1.5\)

Hence the z value is z = -1.5

The simplest way to perform a division is long division and synthetic division.

What is division?

Division in mathematics is the process of dividing an amount into equal parts. For instance, we may split a group of 20 people into four groups of 5, five groups of 4, and so on.

There are two methods to perform division:

Long division: The mathematical procedure for splitting big numbers into more manageable groups or sections is known as long division. A difficulty can be solved by breaking it down into manageable parts. Dividends, divisors, quotients, and remainders all exist in long divisions.

Synthetic division: In algebra, synthetic division is a technique for manually dividing polynomials according to Euclid, requiring less writing and calculation than long division. Although the approach can be applied to division by any polynomial, it is often taught for division by linear monic polynomials.

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Mean of rt = 0.02,

Variance of rt = 0.02,

Lag-1 Autocorrelation (ρ1) = -0.01,

Lag-2 Autocorrelation (ρ2) = Unknown,

1-step ahead forecast = -0.005,

2-step ahead forecast = 0.02,

The standard deviation of forecast errors = √0.02.

We have,

To find the mean and variance of the return series, we can substitute the given model into the equation and calculate:

Mean of rt:

E(rt) = E(0.02 + 0.5rt-2 + et)

= 0.02 + 0.5E(rt-2) + E(et)

= 0.02 + 0.5 * 0 + 0

= 0.02

The variance of rt:

Var(rt) = Var(0.02 + 0.5rt-2 + et)

= Var(et) (since the term 0.5rt-2 does not contribute to the variance)

= 0.02

The mean of the return series rt is 0.02, and the variance is 0.02.

To compute the lag-1 and lag-2 autocorrelations of rt, we need to determine the correlation between rt and rt-1, and between rt and rt-2:

Lag-1 Autocorrelation:

ρ(1) = Cov(rt, rt-1) / (σ(rt) * σ(rt-1))

Lag-2 Autocorrelation:

ρ(2) = Cov(rt, rt-2) / (σ(rt) * σ(rt-2))

Since we are given r100 = -0.01 and r99 = 0.02, we can substitute these values into the equations:

Lag-1 Autocorrelation:

ρ(1) = Cov(rt, rt-1) / (σ(rt) * σ(rt-1))

= Cov(r100, r99) / (σ(r100) * σ(r99))

= Cov(-0.01, 0.02) / (σ(r100) * σ(r99))

Lag-2 Autocorrelation:

ρ(2) = Cov(rt, rt-2) / (σ(rt) * σ(rt-2))

= Cov(r100, r98) / (σ(r100) * σ(r98))

To compute the 1- and 2-step-ahead forecasts of the return series at

t = 100, we use the given model:

1-step ahead forecast:

E(rt+1 | r100, r99) = E(0.02 + 0.5rt-1 + et+1 | r100, r99)

= 0.02 + 0.5r100

2-step ahead forecast:

E(rt+2 | r100, r99) = E(0.02 + 0.5rt | r100, r99)

= 0.02 + 0.5E(rt | r100, r99)

= 0.02 + 0.5(0.02 + 0.5r100)

The associated standard deviation of the forecast errors can be calculated as the square root of the variance of the return series, which is given as 0.02.

Thus,

Mean of rt = 0.02,

Variance of rt = 0.02,

Lag-1 Autocorrelation (ρ1) = -0.01,

Lag-2 Autocorrelation (ρ2) = Unknown,

1-step ahead forecast = -0.005,

2-step ahead forecast = 0.02,

The standard deviation of forecast errors = √0.02.

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Answer:

Minimum amount she needs = $44,444 (Approx)

Step-by-step explanation:

Given:

Down payment of house = $42,000

Real estate commission = 5.5%

Find:

Minimum amount she needs

Computation:

Minimum amount she needs = Down payment of house / (100% - Real estate commission)

Minimum amount she needs = [$42,000 / 94.5]100

Minimum amount she needs = $44,444 (Approx)

Answer:

d

Step-by-step explanation:

The estimated salary for an employee with 18 years of experience is $65,856.46.

To find the estimated salary for an employee with 18 years of experience using the given regression equation, follow these steps:

1. Identify the regression equation: Estimated Salary = 21,640.90 + 2456.42 (Years of Experience)

2. Substitute the given years of experience (18 years) into the equation:

Estimated Salary = 21,640.90 + 2456.42(18)

3. Multiply 2456.42 by 18: 2456.42(18) = 44,215.56

4. Add 21,640.90 to the result from step 3: 21,640.90 + 44,215.56 = 65,856.46

The estimated salary for an employee with 18 years of experience is $65,856.46.

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37.4% of the students would have scores between 60 and 75.

To find the percentage of students who would have a score between 60 and 75, we need to calculate the area under the normal distribution curve between these two values.

Let's plug in the given values into the formula you provided and calculate the probability.

P(60 ≤ X ≤ 75) = ∫[60, 75] (1/(15 * √(2π))) * e^(-((x - 70)^2)/(2*15^2)) dx

To solve this integral, we can use numerical methods or standard statistical tables. However, in this case, it is more convenient to use z-scores.

First, we need to convert the scores 60 and 75 into z-scores by using the formula:

z = (x - μ) / σ

where x is the score, μ is the mean, and σ is the standard deviation.

For 60:

z₁ = (60 - 70) / 15 = -2/3

For 75:

z₂ = (75 - 70) / 15 = 1/3

Now we can look up the probabilities corresponding to these z-scores in the standard normal distribution table (also known as the z-table) or use a statistical calculator.

From the z-table, we can find the following probabilities:

P(-2/3 ≤ Z ≤ 1/3) ≈ 0.628 - 0.254 = 0.374

Among the given answer choices, the closest option is C. 0.378.

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Answer:

you can add 3x and 2x

Step-by-step explanation:

you can add them because they are both like terms

Answer:

yes

Step-by-step explanation:

you can combine them because they have the same base, and you can combine like terms

The quarts of water needed for 9 quarts of grape juice is 18 quarts of water .

The amount of grape juice needed for 15 / 4 quarts of water is 1 7/8.

The amount of water needed for 100 quarts is  66 2/3 quarts.

The amount of grape juice needed for 100 quarts is 33 1/3 quarts.

The first step is to determine the ratio between the ingredients needed for sparking grape juice.

Ratio of sparking water to grape juice - 1 1/2 : 2/4

When expressed in its simplest form, the ratio becomes - 1 1/2 : 1.2

This means that there are twice the amount of water is needed for 1 quart of grape juice.

Quarts of sparking water needed for 9 quarts of grape juice = 9 x 2 = 18 quarts of sparking water

Grape juice needed for 15/4 quarts of sparking water = 15 / 4 ÷ 2

15 / 4 x 1/2 = 15 / 8 = 1 7/8

Let a represent the quarts of grape juice that would be used to make 100 quarts of punch.

Let a represent the quarts of sparking water that would be used to make 100 quarts of punch.

a + 2a = 100

3a = 100

a = 100 / 3

a = 33 1/3

Quarts of sparking water needed = 100 - 331/3 = 66 2/3 quarts

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Resolviendo una simple ecuación con porcentajes, veremos que el número total de estudiantes es 17,727,273

Sabemos que en un dado año, 22% del numero total de estudiantes universitarios estaban matriculados a tiempo parcial, y hay un total de 3,900,000 estudiantes matriculados a tiempo parcial.

Sí definimos N como el numero total de estudiantes, entonces el 22% de N es igual a 3,900,000, entonces podemos escribir la ecuación:

(22%/100%)*N = 3,900,000

0.22*N = 3,900,000

N = 3,900,000/0.22 = 17,727,273

Ese es el numero total de estudiantes.

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We can say that the probability of observing a sample mean of 123.5 wpm or higher by chance alone, assuming the population means is 119 wpm and the standard deviation is 15 wpm, is 4.18%.

To solve this problem, we need to use the central limit theorem, which states that the distribution of sample means will be approximately normal, regardless of the underlying distribution, as long as the sample size is sufficiently large.

In this case, we have a population mean of 119 wpm and a standard deviation of 15 wpm. We want to know the probability that the sample mean would be greater than 123.5 wpm if 33-speed typists are randomly selected.

We can start by calculating the standard error of the mean, which is the standard deviation of the sample mean distribution. We can use the formula:

\($SE = \frac{\sigma}{\sqrt{n}}$\)

where SE is the standard error of the mean, σ is the population standard deviation, and n is the sample size.

Plugging in the values we have:

\($SE = \frac{15}{\sqrt{33}} \approx 2.60$\)

Next, we can calculate the z-score for a sample mean of 123.5 wpm using the formula:

\($z = \frac{\bar{x} - \mu}{SE}$\)

Plugging in the values we have:

z = (123.5 - 119) / 2.60 ≈ 1.73

Using a standard normal distribution table, we can find the probability that the z-score is greater than 1.73. This probability is approximately 0.0418.

Therefore, the probability that the sample mean would be greater than 123.5 wpm if 33-speed typists are randomly selected is approximately 0.0418 or 4.18% (rounded to four decimal places).

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One-half of the dogs in each shelter are between the weights represented by the first and third quartiles, which are approximately 20-55 pounds for the first shelter and 25-65 pounds for the second shelter, respectively.

A box plot is a visual representation of a set of data that shows the median, quartiles, and outliers of the data. The box represents the middle 50% of the data, with the bottom and top edges of the box representing the first and third quartiles, respectively. The line inside the box represents the median, or the middle value of the data set. The "whiskers" extend from the edges of the box to the minimum and maximum values of the data set, but outliers beyond the whiskers are represented as individual points.

Now, let's look at the two box plots showing the weights of dogs in two different animal shelters. One-half of the dogs in each shelter are between the first and third quartiles, which are represented by the edges of the box in each plot.

If we take the first box plot, we can see that the first quartile is approximately 20 pounds and the third quartile is approximately 55 pounds. Therefore, one-half of the dogs in this shelter weigh between 20 and 55 pounds.

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The height of the triangle whose base is 4 cm and area is 20 cm² is 10 cm .

It is given that base is 4 cm and area is 20 cm² .

Putting above values in area formula , we get

         Area = 1 / 2 × base × height

            20  = 1 / 2 × 4 × height

             20 = 2 × height

              10 cm = height

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The complete question is given below :

Find the height of the triangle whose base is 4cm and area is 20 cm².

A

Let's start by finding the gear ratio which is given by the ratio of the number of teeth on the larger gear to the number of teeth on the smaller gear. Since the problem doesn't specify the number of teeth on each gear, we can assume that the gear ratio is expressed as a fraction p/q. Since the smaller gear completes 3 2/3 revolutions every time the larger gear completes 1/3 of a rotation, the gear ratio must be p/q = (11/3)/(1/3) = 11. This means that the larger gear must have 11 times as many teeth as the smaller gear.

If the larger gear completes one rotation, the smaller gear will complete 1/11 of a rotation, or 0.090909... rotations. Therefore, the smaller gear completes approximately 0.0909 rotations (or 3/33 rotations) when the larger gear completes 1 rotation.

Answer:  C   11

Step-by-step explanation:

Small Gear  3 2/3 rotations for  large 1/3 rotation

Ratio:

3 2/3  :  1/3          >mulitply both by 3 to make the large side =1

\((3\frac{2}{3} )(3) : \frac{1}{3} (3)\)        >change 3 2/3 to improper and  simplify right side

\(\frac{11}{3} (3) : 1\)                 >simplify

11 : 1                      

Interpretation:  

The left side was the small gear and right side was large gear.  Now we have the ratio that says the small gear will rotate 11 times for every 1 time the large gear rotates.  

This makes sense because a small gear will rotate more times vs. a big one.

The measure of the angle z of triangle ∆ABD in the same segment with angle C of triangle ∆ABC is equal to 51°

When two angles are in the same segment, they have the same measure. This means that if you know the measure of one angle in a particular segment, you can determine the measure of any other angle in that segment.

angle z = angle C

angle C = 180° - (55 + 34 + 40)° {sum of interior angles of triangle ABC

angle C = 180° - 129°

angle C = 51°

also;

angle z = 51°

Therefore, the measure of the angle z of triangle ∆ABD in the same segment with angle C of triangle ∆ABC is equal to 51°

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Answer:

\(\triangle {UVW} \sim \triangle {UVA} \sim \triangle {UAW}\)

Step-by-step explanation:

The triangles UVW, UVA and UAW, since all three are right angles and have the same combination of angles, meaning the existence of proportionality between corresponding lengths. That is:

\(UA \propto AV \propto UV\), \(AW \propto UA \propto UW\), \(UW \propto UV \propto WV\)

Hence, the complete similarity statement is:

\(\triangle {UVW} \sim \triangle {UVA} \sim \triangle {UAW}\)

The volume of the solid that results when the region enclosed by the curves is revolved about the axis x = -1 is approximately 26.704 units cubed.

To find the volume of the solid that results when the region enclosed by the curves is revolved about the given axis, we use the method of cylindrical shells. The formula for the volume of a cylindrical shell is:

V = 2πrhΔx

where r is the distance from the axis of rotation to the shell, h is the height of the shell, and Δx is the thickness of the shell.

In this case, the axis of rotation is x = -1. We need to find the limits of integration for x and y in order to set up the integral for each problem.

The curves are \(y = x^2 - 1, y = -x,\) and x = -1. Solving for x in terms of y for each curve, we get:

\(x =± \sqrt{(y+1} )\) for y in [-1, 1]

x = -y for y in [-1, 0]

The limits of integration for y are -1 to 0 for the segment of the curve y = -x, and -1 to 1 for the segment of the curve \(y = x^2 - 1\). The limits of integration for x are -1 to √(y+1) for the upper half of the parabola, and -√(y+1) to -1 for the lower half.

The integral for the volume is:

V = 2π ∫[-1,0] ∫[-1,0] (-x - (-1))y dx dy + 2π ∫[-1,1] ∫[-√(y+1),√(y+1)] (√(y+1) - (-√(y+1)))y dx dy

Simplifying and evaluating this integral, we get V = 26.704.

Therefore, the volume of the solid that results when the region enclosed by the curves is revolved about the axis x = -1 is approximately 26.704 units cubed.

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Answer:

75

Step-by-step explanation:

hope this helps

Answer:

\(y=-\frac{1}{7}x+9\)

Step-by-step explanation:

The slope-intercept formula is:

\(y=mx+b\)

y= keep as variable

m= slope of the line

x= keep as variable

b= y-intercept of the line.

Hope this helped!

Brainliest please!

Answer:

1.75 inches deep into the post

Step-by-step explanation:

First, you do 2.5 - 0.75 which is 1.75 in

The answer is 1.75 in

Hope this helps!

From the straight line AB and CD with point M as midpoint of both lines, AM = BM = 3.2 cm and CM = DM = 2 cm

An equation is an expression that shows the relationship between two or more variables and numbers.

m as the midpoint of both ab and cd, hence:

AM = BM = AB/2 = 6.4/2 = 3.2 cm

CM = DM = CD/2 = 4/2 = 2 cm

From the straight line AB and CD with point M as midpoint of both lines, AM = BM = 3.2 cm and CM = DM = 2 cm

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Answer:

B. As the value of x increases, the value of f(x) moves toward positive infinity.