On a scale drawing, a school is 1.6 feet tall. the scale factor is 1/22. Find the height of the school

Answer:

2.14 rounded ............

Answer:

Step-by-step explanation:

A) To find the area covered by two-way radio A, we need to calculate the area of a circle with a radius of 8 miles:

Area = πr² = 3.14 x 8² = 200.96 square miles

Rounding to the nearest whole number, two-way radio A covers 201 square miles.

B) To find the area covered by two-way radio B, we need to convert the radius from kilometers to miles and then calculate the area of a circle with that radius:

Radius in miles = 11.27 / 1.61 = 6.9988 miles (rounded to 4 decimal places)

Area = πr² = 3.14 x (6.9988)² = 153.94 square miles

Rounding to the nearest whole number, two-way radio B covers 154 square miles.

C) Two-way radio A covers a larger area than two-way radio B (201 square miles vs 154 square miles).

D) The scale factor relationship between the radio coverages can be found by dividing the radius of radio A by the radius of radio B:

Scale factor = radius of A / radius of B = 8 miles / (11.27 km / 1.61 km/mile) = 4.97

This means that the coverage of two-way radio A is almost 5 times larger than that of two-way radio B.

Answer:

1.12

Step-by-step explanation:

Based on the information provided, The ratio of 750 m to 3km is 1:4

To find the ratio of each value Start by converting both numbers to the same value. convert kilometer to meter or convert meter to kilometer.

1000m = 1km

750 m = 3000 m

750/750 = 3000/750

Ratio = 1:4

OR

750 meters to kilometers. 750 meters = 750/1000 = 0.75 kilometers.

0.75 kilometers to 3 kilometers

0.75/0.75 : 3/0.75 = 1 : 4

The above answer is based on the full question below;

Find the ratio of 750 m to 3km. Here, 3 km = 3x1000 m. 3000m.​
Ratio of 750m and 3km is ____

a. 3 : 7

b. 3 : 5

c. 2 : 7

d. 1 : 4

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Answer:

a. 0.691

b. 0.382

c. 0.933

d. $88.490

e. $58.168

f. 5th percentile: $42.103

95th percentile: $107.897

Step-by-step explanation:

We have, for the purchase amounts by customers, a normal distribution with mean $75 and standard deviation of $20.

a. This can be calculated using the z-score:

\(z=\dfrac{X-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\P(X<85)=P(z<0.5)=0.691\)

The probability that a randomly selected customer spends less than $85 at this store is 0.691.

b. We have to calculate the z-scores for both values:

\(z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{65-75}{20}=\dfrac{-10}{20}=-0.5\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\\\P(65<X<85)=P(-0.5<z<0.5)=P(z<0.5)-P(z<-0.5)\\\\P(65<x<85)=0.691-0.309=0.382\)

The probability that a randomly selected customer spends between $65 and $85 at this store is 0.382.

c. We recalculate the z-score for X=45.

\(z=\dfrac{X-\mu}{\sigma}=\dfrac{45-75}{20}=\dfrac{-30}{20}=-1.5\\\\\\P(X>45)=P(z>-1.5)=0.933\)

The probability that a randomly selected customer spends more than $45 at this store is 0.933.

d. In this case, first we have to calculate the z-score that satisfies P(z<z*)=0.75, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

\(P(z<0.67449)=0.75\)

Then, we can calculate X as:

\(X^*=\mu+z^*\cdot\sigma=75+0.67449\cdot 20=75+13.4898=88.490\)

75% of the customers will not spend more than $88.49.

e. In this case, first we have to calculate the z-score that satisfies P(z>z*)=0.8, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

\(P(z>-0.84162)=0.80\)

Then, we can calculate X as:

\(X^*=\mu+z^*\cdot\sigma=75+(-0.84162)\cdot 20=75-16.8324=58.168\)

80% of the customers will spend more than $58.17.

f. We have to calculate the two points that are equidistant from the mean such that 90% of all customer purchases are between these values.

In terms of the z-score, we can express this as:

\(P(|z|<z*)=0.9\)

The value for z* is ±1.64485.

We can now calculate the values for X as:

\(X_1=\mu+z_1\cdot\sigma=75+(-1.64485)\cdot 20=75-32.897=42.103\\\\\\X_2=\mu+z_2\cdot\sigma=75+1.64485\cdot 20=75+32.897=107.897\)

5th percentile: $42.103

95th percentile: $107.897

Answer:

Step-by-step explanation:

ans = 2

Answer:

2

Step-by-step explanation:

exponential 1/4 = sq root twice

so √16 =4, √4=2

Answer:

Center: (3, - 4)

Step-by-step explanation:

We can start to solve this problem by converting this equation into standard form. In other words, by completing the square --- (1)

Subtract " 10 " from either side of the equation x² + y² - 6x + 8y + 10 = 0

x² + y² - 6x + 8y = - 10

Step 1: Complete the square for the expression " x² - 6x "

Using the quadratic equation ax² + bx + c we know that a = 1, b = - 6, c = 0. Assume that d = b / 2a. We have...

d = - 6 / 2(1) = - 6 / 2 = - 3

Now let's assume that e = c - (b²) / 4a...

e = 0 - (-6)² / 4(1) = 0 - 36 / 4 = 0 - 9 = 9 (Substitute values d and e)

(x - 3)² - 9

Step 2: Respectively we can complete the square for the remaining expression " y² + 8y "

Here a = 1, b = 8, c = 0

d = 8 / 2(1) = 8 / 2 = 4

e = 0 - (8)² / 4(1) = 0 - 64 / 4 = 0 - 16 = - 16 (Substitute values)

(y + 4)² - 16

This leaves us with the expression " (x - 3)² - 9 + (y + 4)² - 16 = - 10. " If we simplify this a bit further it leaves us with the following circle equation. Using this we can identify the center of the circle as well --- (2)

\(\mathrm{Standard}\:\mathrm{Circle}\:\mathrm{Equation} : (x - 3)^2 + (y +4)^2 = 15,\\\mathrm{General}\:\mathrm{Form} : (x - h)^2 + (y +k)^2 = r^2,\\\mathrm{Properties} : \mathrm{Center} = (3, - 4), \mathrm{Radius} = \sqrt{15}\)

As you can see our center here is (3, - 4)

The values of the variables are;

x = 7

y = -9

From the information given, we have that;

5x−y=44

−3x−y=−12

Using the elimination method of solving simultaneous equations

Subtract equation (2) from equation (1), we get;

5x - y - (-3x - y) = 44 - (-12)

Now, expand the bracket

5x - y+ 3x + y = 56

collect the like terms

5x + 3x = 56

add the terms

8x = 56

Make 'x' the subject of formula

x= 7

Now, substitute the value of x in equation (2)

-3x - y = -12

-3(7) - y = -12

expand the bracket

-21 - y= - 12

collect like terms

-y = 9

y = -9

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Answer:

slope = – 1

Step-by-step explanation:

\(m = \frac{y2 - y1}{x2 - x1} = \frac{6 - 8}{8 - 6} = \frac{ - 2}{2} = - 1\)

Answer:

wwwwwwwwwwwwwwwwwww

Answer:

d= +3

Step-by-step explanation:

1st term = -19

2nd term = -16

d = 2nd - 1st

d= -16-(-19)

d = +3

Answer:

1/2=10

Step-by-step explanation:

it depends upon the area of the triwngle

Answer:

$37,600

Step-by-step explanation:

2:4 ratio which means there is 6 parts

56,400/6 = 9,400

Mandy is the 4 as she came second in the question which said respectfully(in that order)

9,400 x 4 = $37,600

Though in all honesty I may be wrong, I haven't worked on any ratios in a longggg time

Answer: B)310

Step-by-step explanation:

Add up all the students from the different types of transportation to get to school.

Bus=150

Car=40

Bicycle=70

Walk=50

=310

Answer:

half of 60 is 30

13 more than that is

13+30=43

so the answer is 43

Step-by-step explanation:

hope it helps you

The completed statement that specifies the rule of congruency between triangle ΔSAT and triangle ΔSAO, is as follows;

ΔSAT ≅ ΔSAO by SAA rule.

Two triangles, ΔA and ΔB are congruent if the three lengths of the sides of triangle ΔA are congruent to the three side lengths of triangle ΔB.

The possible dimensions of the triangles, obtained from the triangle diagrams in a similar question on the site are;

Side ST in triangle ΔSAT is congruent to side SO in triangle ΔSAO

Angle ∠AST in triangle ΔSAT is congruent to angle ∠ASO in triangle ΔSAO

Side SA is congruent to side SA by reflexive property of congruency

Therefore, a side, (ST) an included angle (∠AST) and another side (SA), in triangle ΔSAT are congruent to a side (SO), an included angle (∠ASO), and another side SA in triangle ΔSAO

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The probability of a defect is 5.7330 x \(10^{-5}\) and the number of defects is 5.73.

To calculate the probability of a defect, we need to find the area under the standard normal curve that lies outside of the process control limits of 9.75 ounces and 10.25 ounces. We can use the standard normal distribution table to find this area.

First, we need to standardize the weight limits as follows -

\(Z_{lower}\) = (9.75 - 10) / 0.25 = -4

\(Z_{upper}\) = (10.25 - 10) / 0.25 = 4

Next, we will find the area under the standard normal curve that lies outside of these limits as follows -

P(Defect) = P(Z < -4) + P(Z > 4)

Using a standard normal distribution table, we can find that P(Z < -4) = 2.8665 x   \(10^{-5}\)  and P(Z > 4) = 2.8665 x  \(10^{-5}\) .

So, the total probability of a defect is -

P(Defect) = 2.8665 x  \(10^{-5}\)  + 2.8665 x  \(10^{-5}\)  = 5.7330 x  \(10^{-5}\)

Finally, we will find the number of defects for a 1,000-unit production run as follows -

The number of defects = 1000 * 5.7330 x  \(10^{-5}\)  = 5.73 (rounded to the nearest whole number).

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Answer:

Step-by-step explanation:

Comment

Without doing a lot of math, the answer is

-x + 0 + x

It can be anything that gives 0. They are the same number but one of them is minus

-5 + 0 + 5  = 0

-1000 + 0 + 1000 =0

or the simplest one

-1 +0 + 1 =0

Answer:

3,952 ft

Step-by-step explanation:

Use the sine function since you need to find the hypotenuse but know the opposite side of the angle, since sine is equal to opposite/hypotenuse.

sin8°=\(\frac{550}{c}\)

csin8°=550

c=550/sin8°

c= 3,952

1/2=1/2=1/2.is the value for the given equivalent fraction, by putting the value 3.4 in the numerators respectively

The fractions with distinct numerators and denominators but the same value are said to be equivalent fractions.

For instance, since 2/4 and 3/6 both equal the 1/2, they are identical fractions. An element of a whole is a fraction. The same amount of the whole is represented by equivalent fractions.

1/2 =    /6 =   /8.

a. Multiply numerator and denominator by 3 for equivalenting the equation    /6

Therefore,

3*3/6*3

=9/18

=1/2

therefore:1/2=1/2.

b. Multiply numerator by 4

Therefore,

4/8

=1/2.

Therefore:

1/2=1/2.

1/2=1/2=1/2.

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The x-intercepts of the quadratic function y = x² + 2x - 15 are:

a. (-5, 0) and (3, 0).

The graph is sketched at the end of the answer;

A quadratic function is given according to the following rule:

y = ax² + bx + c

The solutions are:

In which:

\(\Delta = b^2 - 4ac\)

In this problem, the function is:

y = x² + 2x - 15.

The coefficients are:

a = 1, b = 2, c = -15.

Hence:

Hence the x-intercepts are:

a. (-5, 0) and (3, 0).

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Answer:

Step-by-step explanation:

Answer: 6x^2

Step-by-step explanation:

The area of a triangle is 1/2bh

Thus, simply multiply 2x*3x = 6x^2

Hope it helps <3

Answer:

Solution,

Base(b)= 3x

Height(h) = 2x

Now,

Finding the area of triangle:

\( \frac{1}{2} \times b \times h\)

\( \frac{1}{2} \times 3x \times 2x\)

\( \frac{1}{2} \times 6 {x}^{2} \)

\(3 {x}^{2} \)

Hope this helps....

Good luck on your assignment....

Answer:

A = 530.929158457

Answer:

Area = 706.8583471

Explanation:

The used law to measure the surface area of the sphere is

\(area \: = 4\pi \: {r}^{2} \)

Where (r) is the radius. The radius is half the diameter, so it will be half 13 which is equal to 7.5. By using this law:

\(4\pi \: {7.5}^{2} = 706.8583471\)

Answer:

Area of Parallelogram Using Diagonals ; Using Base and Height, A = b × h ; Using Trigonometry, A = ab sin (x) ; Using Diagonals, A = ½ × d1 × d2 .....

Using Diagonals: A = ½ × d1 × d2 sin (y)

Using Base and Height: A = b × h

Using Trigonometry: A = ab sin (x)

Answer:

7 ft

Step-by-step explanation:

hypotenuse (h) = 25

perpendicular (p) = 24

base (b) = ?

We know by using Pythagoras theorem

b = √h² - p²

= √ 25² - 24²

= √ 49

= 7 ft

Answer:

missing side= 7 ft

Step-by-step explanation:

using pythogoras theoram

25^2-24^2=x^2

625-576=x^2

49=x^2

x=7

Answer:

x = 100°

Explanation:

The polygon has 6 sides, meaning it's a hexagon. In the picture you can see the following steps under #1:

(6-2) x 180° = 4 x 180 = 720°

720 is the total amount that all the angles should add up to, including the missing number x.

To solve for x add all of the angles up:

120 + 156 + 145 + (x + 9) + x + 90 = 720

520 + 2x = 720 (subtract 520 from both sides)

                 -520

          2x = 200 (divide 200 by 2 to have x on its own)

             x = 100°

To make sure it's correct, plug in the value (100°) for x in the original equation to check the answer:

120 + 156 + 145 + 100 + 9 + 100 + 90 = 720

720 = 720 Correct