On a number line, point A is located at -3 and point B is located at 19. Find coordinate of a point between A and B such that the distance from A to point B is 3/11 of distance A to B

Answer:

y-int: (0, 275)

X-int: (125, 0)

Step-by-step explanation:

Answer:

The y intercept is (0, 275)

The x intercept is (125, 0)

Step-by-step explanation:

The y intercept is 0, 275

The x intercept is 125, 0

Answer:

AC = 36

Step-by-step explanation:

We could totally prove that AB ~= BC

But they didn't really ask for the proof, so we'll just use that idea.

-x + 25 = 3(2x - 8)

Use distributive property.

-x + 25 = 6x - 24

Add x to both sides.

25 = 7x - 24

Add 24 to both sides.

49 = 7x

Divide by 7

7 = x

Now we can calculate either AB or BC and double it(or calculate both AB and BC and add them together)

-x + 25

= -7 + 25

= 18

Both AB and BC are 18 so AC = 36

Calculating BC separately is also a good check.

3(2x - 8)

= 3(2•7 - 8)

= 3(14 - 8)

= 3(6)

= 18

So we get 2(18) or 18+18 to find that AC = 36

Answer: F

Step-by-step explanation:

We know the angle is in the first quadrant, so its argument is in between 0 and 90 degrees.

Also, its modulus is the distance from the origin, which in this case is \(\sqrt{3^2 + 1^2}=\sqrt{10} \approx 3.16\)

The answer that best matches this is F

The formulated Linear Program aims to minimize the objective function, which is the sum of production and inventory costs minus the revenue from selling the end-of-period inventory at month 4.

In this problem, we need to determine the optimal production and inventory levels over the four-month period to minimize costs and maximize revenue. We can formulate this as a linear programming problem with the following decision variables:

Let x1, x2, x3, x4 represent the production quantities for months 1, 2, 3, and 4, respectively.

Let y1, y2, y3, y4 represent the end-of-month inventory levels for months 1, 2, 3, and 4, respectively.

The objective function we want to minimize is:

Minimize: (5x1 + 8x2 + 4x3 + 7x4) + (2y1 + 2y2 + 2y3) - (15y4)

Subject to the following constraints:

1. Initial inventory: y1 = 15 (given)

2. Production capacity constraints:

  x1 <= 90 (month 1 capacity)

  x2 <= 75 (month 2 capacity)

  x3 <= 80 (month 3 capacity)

  x4 <= 50 (month 4 capacity)

3. Inventory balance equations:

  y1 + x1 - 50 = y2 (month 1)

  y2 + x2 - 65 = y3 (month 2)

  y3 + x3 - 100 = y4 (month 3)

  y4 + x4 - 70 = 0 (month 4, no carryover inventory)

4. Non-negativity constraints:

  x1, x2, x3, x4, y1, y2, y3, y4 ≥ 0

Learn more about Linear Program

brainly.com/question/32090294

#SPJ11

The value of side a and b for the given triangle is 46.68 units and 17.92 units.

A triangle's angles and side lengths are related by the law of sines, a trigonometric identity. It asserts that the ratio of the sine of one angle to the length of the side opposite that angle is constant for all three angles for any triangle with sides a, b, and c and opposing angles a, b, and c:

If a/sin(A) = b/sin(B) = c/sin(C), then

As long as at least one angle and its matching side length are known, this can be used to solve for unknown angles or side lengths in a triangle.

For the given triangle we have:

cos B = a / c

Thus, substituting the values we have:

cos 21 = a / 50

a = 46.68 units.

Now, sin B = b/50

Sin 21 = b / 50

b = 17.92 units.

Hence, the value of side a and b for the given triangles is 46.68 units and 17.92 units.

Learn more about law of sines here:

https://brainly.com/question/17289163

#SPJ1

The complete question is:

The factor that does NOT control the stability of a slope is the angle of repose for intact bedrock. The angle of repose refers to the steepest angle at which a pile of loose material remains stable without sliding. It is mainly applicable to loose materials like soil and granular substances, not intact bedrock.

Bedrock stability depends on factors such as its strength, fracturing, and geological properties, rather than the angle of repose. Factors that control the stability of a slope include whether the slope is rock or soil. Rock slopes tend to be more stable than soil slopes due to the cohesive nature of intact rock.

The amount of water in the soil also affects slope stability, as excessive water can increase pore pressure and reduce the shear strength of the soil, leading to slope failure. Additionally, the orientation of fractures, cleavage, and bedding in the rock can influence slope stability by creating planes of weakness or strength.

To summarize, while the angle of repose is a significant factor in slope stability, it is not applicable to intact bedrock. The stability of a slope is influenced by the type of material (rock or soil), the presence of water, and the orientation of fractures and bedding.

know more about Bedrock.

https://brainly.com/question/2948854

#SPJ11

m = 54.8 inches

std = 4.9 inches

We can standarize the variable as:

(X - m)/std

So, the probability of a height randomly choosen is between 51.05 and 54.75 inches is:

P[ 51.05 < X < 54.75]

Standarizing those values:

(51.05 - m)/std = (51.05 - 54.8)/4.9 = -75/98...

(54.75 - m)/std = (51.05 - 54.8)/4.9 = -1/98...

So, the new probability is:

P[ -75/98 < Z < -1/98] = Phi(-1/98) - Phi(-75/98)

Where Z is the new standarized variable.

We can find these Phi values from tables of the standarized normal distributions:

Phi(-1/98) = 0.77796

Phi(-75/98) = 0.49593

So the probability is:

P[ -75/98 < Z < -1/98] = Phi(-1/98) - Phi(-75/98) = 0.77796 - 0.49593

P[ 51.05 < X < 54.75] = 0.28203 = 0.282

And that is the answer

Answer:

HCF = 2

LCM = 60

Step-by-step explanation:

?

The value of angle G for both kites are respectively:

∠G = 110°

∠G = 80°

In a kite, the angles between the two non- congruent sides usually have the same angle size. Thus:

∠E ≅ ∠G

In a quadrilateral, the sum of the inner angles is 360 degrees. Thus:

100 + 40 + ∠E + ∠G = 360

140 + 2(∠G) = 360

2(∠G) = 360 - 140

(∠G) = 220/2

∠G = 110°

Similarly, for the second kite:

∠G = 360 - (110 + 60 + 110)

∠G = 80°

Read more about missing kite angle at: https://brainly.com/question/63210

#SPJ1

Answer:

\(y=-\frac{2}{5} x+3\)

Step-by-step explanation:

Slope, line, form.

y=mx+b

Points: 0,3 and -5,5

Find slope: 5-3/-5-0 or -2/5

y=-2/5x+b

5=-2/5(-5)+b

5=2+b

b=3

y=-2/5x+3

Hope this helps ;D

An acute angle theta that satisfies the equation sin θ =cos (2 theta + 27 degrees) is 45 degrees.

To find an acute angle theta that satisfies the equation sin theta =cos (2 theta + 27 degrees), we can use the identity cos (90 - theta) = sin theta.

Substituting 90 - theta for 2 theta + 27 degrees, we get:
sin theta = cos (90 - theta)

Using the identity cos (90 - theta) = sin theta, we can simplify the equation to:
sin theta = sin (90 - theta)
Since sin θ = sin (90 - theta), we can conclude that theta = 90 - theta.
Solving for theta, we get:
2 theta = 90
theta = 45 degrees
Learn more about acute angle θ,:https://brainly.com/question/30199609

#SPJ11

The equation of the horizontal asymptote of the function g(x) is y = 0.

Equation of the asymptote: y = 0

To find the horizontal asymptotes of g(x) = (5 - e^2x) / (4e^x - 3), we need to take the limit as x approaches positive or negative infinity.

As x approaches infinity, both the numerator and denominator of the fraction become very large. To determine which term dominates, we can divide numerator and denominator by the term with the highest degree in the denominator, which is e^x. This gives:

g(x) = [(5/e^(2x)) - 1] / [4 - (3/e^x)]

As x approaches infinity, the term e^(2x) in the numerator becomes much larger than any other term, so we can ignore all other terms in the numerator and denominator. Taking the limit as x approaches infinity, we get:

lim g(x) = lim [(5/e^(2x))] / [4 - (3/e^x)]

= 0 / 4

= 0

Therefore, the horizontal asymptote of g(x) as x approaches infinity is y = 0.

Similarly, as x approaches negative infinity, we can ignore all terms except e^(2x) in the numerator and e^x in the denominator. Dividing by e^x gives:

g(x) = [(-5/e^(2x)) + 1/e^(2x)] / [4/e^x - 3/e^x]

Taking the limit as x approaches negative infinity, we get:

lim g(x) = lim [(-5/e^(2x)) + 1/e^(2x)] / [4/e^x - 3/e^x]

= 0 / 4

= 0

Therefore, the horizontal asymptote of g(x) as x approaches negative infinity is also y = 0.

In conclusion, the equation of the horizontal asymptote of the function g(x) is y = 0.

Equation of the asymptote: y = 0

Learn more about Equation here:

https://brainly.com/question/10724260

#SPJ11

Answer:

(-3,-1)

Step-by-step explanation:

So we need to find a number, x=a, such that when we average that number and x=3, we get x=0.

Since we want x=0 to be middle and x=3 is 3 units right of 0, then we are looking for number 3 units left of 0 which is x= -3.

Since we want y=2 to be the middle and y=5 is 3 units above 2, then we are looking for a number 3 units below 2 which is y=-1.

The other endpoint is (-3,-1).

Let's average (-3,-1) and (3,5).

(-3+3)/2=0/2=0

(-1+5)/2=4/2=2.

Check mark.

Answer:

i beleive that B is the best option

Answer:

x=1/2 or x=0.5

Step-by-step explanation:

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

Answer:

FG = 16

Step-by-step explanation:

Given:

If M is the midpoint of FG then:

⇒ FM = MG

⇒ 5y + 13 = 5 - 3y

⇒ 5y + 13 + 3y = 5 - 3y + 3y

⇒ 8y + 13 = 5

⇒ 8y + 13 - 13 = 5 - 13

⇒ 8y = -8

⇒ y = -1

As M is the midpoint of FG then:

⇒ FG = FM + MG

⇒ FG = (5y + 13) + (5 - 3y)

⇒ FG = 5y + 13 + 5 - 3y

⇒ FG = 2y + 18

Substitute the found value of y into the found equation for FG:

⇒ FG = 2(-1) + 18

⇒ FG = -2 + 18

⇒ FG = 16

Answer:

4.089, 4.87 4.881 , 4.89

Step-by-step explanation: this is true because for 4.89 you would just add a 0 to make it 4.890

Answer:

Step-by-step explanation:

You want to know which diagram shows a function.

A function is a relation in which each value in the domain maps to exactly one value in the range. When a domain value corresponds to more than one range value, the relation is not a function.

(a) and (b) are functions.

(c) is not a function, as there are two arrows emanating from domain value 5.

The width of the enlargement would be 34.2857 cm.

The distance separating an object's ends is its length. The longest dimension is this one. The width of an object is the separation between its two sides. The shortest dimension is this one.

Initial dimension of shorter side = 10 cm

Initial dimension of longer side = 7 cm

Final dimension of shorter side = 24

Final dimension of longer side = x cm

The enlargement always ensure the aspect ratio = longer side / shorter side

10/7 = x/24

Solving for x, we get

\($\frac{x}{24}=\frac{10}{7}$$\)

simplifying the above equation, we get

\($\frac{24 x}{24}=\frac{10 \cdot 24}{7}$$\)

\($x=\frac{240}{7} cm$$\)

Therefore, the  value of x be 34.2857 cm.

To learn more about width refer to:

https://brainly.com/question/25292087

#SPJ1

E) is a partially ordered set. a) E is a reflexive relation: A relation is reflexive if for every element X in P(A), XEX holds true. Since every set is a subset of itself (X ⊆ X), the relation E is reflexive.

b) E is not a symmetric relation:
A relation is symmetric if for every pair of elements X, Y in P(A), whenever XEY, it's also true that YEX. To disprove symmetry, consider two distinct sets X and Y where X is a proper subset of Y (X ⊆ Y and X ≠ Y). In this case, XEY, but YEX does not hold, so E is not symmetric.

c) E is an antisymmetric relation:
A relation is antisymmetric if for every pair of elements X, Y in P(A), if XEY and YEX, then X = Y. Since X ⊆ Y and Y ⊆ X implies X = Y, the relation E is antisymmetric.

d) E is a transitive relation:
A relation is transitive if for every three elements X, Y, Z in P(A), if XEY and YEZ, then XEZ. If X ⊆ Y and Y ⊆ Z, then X ⊆ Z, which means XEZ holds true. Therefore, E is a transitive relation.

e) E is not an equivalence relation:
An equivalence relation must be reflexive, symmetric, and transitive. While E is reflexive and transitive, it is not symmetric, so E is not an equivalence relation.

1) (P(A), E) is a partially ordered set:
A partially ordered set is a set with a binary relation that is reflexive, antisymmetric, and transitive. Since E has these properties, (P(A), E) is a partially ordered set.

Learn more about subset here:

brainly.com/question/31739353

#SPJ11

the probability of obtaining a sample mean within 500 of the population mean is approximately 0.6827.

To solve this problem, we need to use the central limit theorem which states that the distribution of the sample means will be approximately normal with mean equal to the population mean and standard deviation equal to the population standard deviation divided by the square root of the sample size.

Given that the population mean is 51800 and the population standard deviation is 4000, we can calculate the standard error of the mean as follows:

Standard error of the mean = 4000 / sqrt(64) = 500

We want to find the probability of obtaining a sample mean within 500 of the population mean. This can be written as:

P(51800 - 500 < X < 51800 + 500)

where X is the sample mean.

We can standardize this interval using the standard error of the mean:

P(-1 < Z < 1)

where Z is a standard normal variable.

Using a standard normal table, we find that the probability of Z being between -1 and 1 is approximately 0.6827.

Therefore, the probability of obtaining a sample mean within 500 of the population mean is approximately 0.6827.

To  learn  more about probability click here:brainly.com/question/31120123

#SPJ11

Approximately 1,200 students would be expected to vote for alternative as their favorite type of music.

To determine the number of students expected to vote for alternative music out of 6,000 students, we need to know the proportion or percentage of students who prefer alternative music in the survey. Let's assume this proportion is p.

Convert the proportion to a percentage: p = p × 100%

Calculate the expected number of students who prefer alternative music:

Expected number = p × Total number of students

Expected number = p × 6,000

For example, if 20% of the students prefer alternative music, we would have:

Expected number = 0.20 × 6,000 = 1,200

So, the expected number of students who would vote for alternative as their favorite type of music among 6,000 students would be approximately 1,200.

For more questions like Survey click the link below:

https://brainly.com/question/30504929

#SPJ11

For n = 3, x = 9, and x = 2i, we can say that one of the factors is (x - 9) as well as (x - 2i).

(x - 2i) is derived from x² = -4 which is equal to (x² + 4). Therefore, the two factors are (x - 9) and (x² + 4). To get the polynomial function, let's multiply the two factors using FOIL Method.

The polynomial function of the first bullet is f(x) = x³ - 9x² + 4x - 36.

For n = 3, x = -1, and x = 4 + i, we can say that the factors are:

(x + 1) , (x - (4 + i)), and (x - (4 - i))

Note: Always remember those complex zeros like x = 4 + i come in conjugate pairs.

To solve the polynomial function, let's multiply the three factors.

The polynomial function of the second bullet is f(x) = x³ - 7x² + 9x + 17.

Answer:

71

Step-by-step explanation:

(2x² = 2 × 5² = 2 × 25) + ([4x = 4 × 5 = 20] + 1)

(50) + (21) = 71

Answer: its 12 and 8 10 12 14 16 either of those

Step-by-step explanation:

The first quartile is always equal to one of the values in the sample when the sample size is a multiple of 4.

This is because the first quartile is the median of the lower half of the data set, and when the sample size is a multiple of 4, there is anThe first quartile is always equal to one of the  valuesin the sample when the sample size is a multiple of 4. This is because the first quartile is the median of the lower half of the data set, and when the sample size is a multiple of 4, there is an even number of values in the lower half of the data set. Therefore, the first quartile will be one of the values in the sample. For example, if the sample size is 8, the first quartile will be the median of the first 4 values, which will be one of the values in the sample.

In summary, the first quartile is always equal to one of the values in the sample when the sample size is a multiple of 4. of values in the lower half of the data set. Therefore, the first quartile will be one of the values in the sample. For example, if the sample size is 8, the first quartile will be the median of the first 4 values, which will be one of the values in the sample.
In summary, the first quartile is always equal to one of the values in the sample when the sample size is a multiple of 4.

Read more about quartile here:https://brainly.com/question/28277179

#SPJ11

We can conclude that the value of det(A²B⁽ᵀ⁾) is 4.

Given the matrices A and B are nxn matrices, and det(A) = -1 and det(B) = 4.

To find the determinant of A²B⁽ᵀ⁾ we can use the properties of determinants.

A² has determinant det(A)² = (-1)² = 1B⁽ᵀ⁾ has determinant det(B⁽ᵀ⁾) = det(B)

Thus, the determinant of A²B⁽ᵀ⁾ = det(A²)det(B⁽ᵀ⁾)

= det(A)² det(B⁽ᵀ⁾)

= (-1)² * 4 = 4.

The value of det(A²B⁽ᵀ⁾) = 4.

As per the given information, A and B both are nxn matrices, and det(A) = -1 and det(B) = 4.

We need to find the determinant of A²B⁽ᵀ⁾

.Using the property of determinants, A² has determinant det(A)² = (-1)² = 1 and B⁽ᵀ⁾ has determinant det(B⁽ᵀ⁾) = det(B).Therefore, the determinant of

A²B⁽ᵀ⁾ = det(A²)det(B⁽ᵀ⁾)

= det(A)² det(B⁽ᵀ⁾)

= (-1)² * 4 = 4.

Thus the value of det(A²B⁽ᵀ⁾) = 4.

Hence, we can conclude that the value of det(A²B⁽ᵀ⁾) is 4.

To know more about matrices visit:

brainly.com/question/30646566

#SPJ11

Answer:

\( x = \frac{7 \sqrt{2} }{2} \)

Step-by-step explanation:

\( \cos \: 45 \degree = \frac{x}{7} \\ \\ \frac{1}{ \sqrt{2} } = \frac{x}{7} \\ \\ x = \frac{7}{ \sqrt{2} } \\ \\ x = \frac{7 \sqrt{2} }{2} \)