On a map of the Thunderbird Country Club golf course, 1.5 inches equals 45 yards. How long is the 17th hole if the map shows 8.5 inches?

Converting moles to grams is a relatively straightforward process.

To begin, you'll need to know the molecular weight of the substance you're dealing with. This is the sum of the atomic masses of all the atoms in the molecule.

Once you have the molecular weight, you can then use the following equation to convert moles to grams: moles x molecular weight = grams. For example, if you wanted to convert 1 mole of water to grams, you would use the molecular weight of water (18.015 g/mol) to get the answer: 1 mole x 18.015 g/mol = 18.015 g.

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Answer:

75

Step-by-step explanation:

did it 5 mins ago

The percentage of youths surveyed that prefer reading electronic books is 54%

The percentage of a number represents a portion or fraction of that number expressed as a percentage. It is often used to describe a proportion or relative value.

To calculate the percentage of a number, you can use the following formula:

Percentage = (Part / Whole) * 100

To determine the percentage of youths that prefer electronic books is;

youths (electronic books) = number of electronic books(youth) / total number of youths.

youths (electronic books) = 40/(40 + 34) * 100

youths (electronic books) = 40/74 * 100

youths (electronic books) = 0.54 * 100

youths (electronic books) = 54%

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Answer:

84

Step-by-step explanation:

\(A\)trapezoid= \(\frac{h(b_{1} + b_{2})}{2}\)

Substitute the values into the equation: \(A=\frac{12(9 + 5)}{2}\)

\(A=\frac{12(9 + 5)}{2}\) (add 9 and 5)

↓

\(A=\frac{12(14)}{2}\) (multiply 14 by 12)

↓

\(A=\frac{168}{2}\)(divide 168 by 2)

↓

\(A=84\) (your answer)

Hope this helps! Have a good day! :)

The electron domain charge cloud geometry of \(BrF_5\) is trigonal bipyramidal.

To determine the electron domain charge cloud geometry of \(BrF_5\), we need to examine the number of electron domains around the central atom (Br).

\(BrF_5\) consists of one central bromine atom (Br) surrounded by five fluorine atoms (F). Each bond and lone pair of electrons represents an electron domain.

In \(BrF_5\), there are five bonding pairs (Br-F) and no lone pairs around the central bromine atom. Therefore, the total number of electron domains is five.

Based on this information, the electron domain charge cloud geometry of \(BrF_5\) is trigonal bipyramidal.

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Answer:

1684.8 cubic units

Step-by-step explanation:

In oblique cylinder the height (altitude) is measured from the opposite base to the base of the cylinder, but it lies outside. We can find the height using Pythagoras theorem.

       h + 7² = 13²

              h²= 169 - 49

              h² = 120

               h = √120

                h = 10.95 units

radius = r = 7 units

\(\boxed{\text{\bf Volume of oblique cylinder = $\bf\pi r^2h$} }\)

                                                    = 3.14 * 7 * 7 * 10.95

                                                    = 1684.8 cubic units

Answer:

d = 55.5  

x = 1

c = 11

m = \(\frac{1}{122}\)

k = \(\frac{a}{(c + 5)}\)

Step-by-step explanation:

Sorry, the formatting is slightly hard to understand, but I think this is what you meant.

Q1.

\(\frac{1}{6}\)d - 8 = \(\frac{5}{8}\) x 2

Step 1. Simplify.

\(\frac{5}{8}\) x 2 = \(\frac{5}{8}\) x \(\frac{2}{1}\) = \(\frac{10}{8}\)

Step 2. Cancel out the negative 8.

\(\frac{1}{6}\)d - 8 = \(\frac{10}{8}\)

+ 8 to both sides (do the opposite: \(\frac{1}{6}\)d is subtracting 8 right now, but to cancel that out, we will do the opposite of subtraction, i.e. addition)

\(\frac{1}{6}\)d = \(\frac{10}{8}\) + 8

Step 3. Simplify.

\(\frac{10}{8}\) + 8 = \(\frac{10}{8}\) + \(\frac{8}{1}\) = \(\frac{10}{8}\) + \(\frac{64}{8}\) = \(\frac{74}{8}\) = \(\frac{37}{4}\)

Step 4. Cancel out the \(\frac{1}{6}\).

\(\frac{1}{6}\)d = \(\frac{37}{4}\)

÷ \(\frac{1}{6}\) from both sides (do the opposite: d is multiplied by \(\frac{1}{6}\) right now, but to cancel that out, we will do the opposite of multiplication, i.e. division)

÷ \(\frac{1}{6}\) = x 6

So....

x 6 to both sides

d = \(\frac{37}{4}\) x  6 = \(\frac{37}{4}\) x \(\frac{6}{1}\) = \(\frac{222}{4}\) = \(\frac{111}{2}\) = 55.5

Step 5. Write down your answer.

d = 55.5

Q2.

3x - 4 + 5x = 10 - 2x × 3

Step 1. Simplify

3x - 4 + 5x = 3x + 5x - 4 = 8x - 4

10 - 2x × 3 = 10 - (2x × 3) = 10 - 6x

Step 2. Cancel out the negative 6x

8x - 4 = 10 - 6x

+ 6x to both sides (do the opposite - you're probably tired of reading this now - right now it's 10 subtract 6x, but the opposite of subtraction is addition)

14x - 4 = 10

Step 3. Cancel out the negative 4

14x - 4 = 10

+ 4 to both sides (right now it's 14x subtract 4, but the opposite of subtraction is addition)

14x = 14

Step 4. Divide by 14

14x = 14

÷ 14 from both sides (out of the [14 × x] we only want the [x], so we cancel out the [× 14])

x = 1

Step 5. Write down your answer.

x = 1

Q3.

7(c - 3) = 14 × 4

Step 1. Expand the brackets

7(c - 3) = (7 x c) - (7 x 3) = 7c - 21

Step 2. Simplify

14 x 4 = 56

Step 3. Cancel out the negative 21

7c - 21 = 56

+ 21

7c = 56 + 21

7c = 77

Step 4. Cancel out the ×7

7c = 77

÷ 7

c = 77 ÷ 7

c = 11

Step 5. Write down your answer.

c = 11

Q4.

11(\(\frac{m}{22}\) + \(\frac{3}{44}\)) = 87m + m × 5

Step 1. Expand the brackets

11(\(\frac{m}{22}\) + \(\frac{3}{44}\)) = (11 x \(\frac{m}{22}\)) + (11 x \(\frac{3}{44}\)) = (\(\frac{11}{1}\) x \(\frac{m}{22}\)) + (\(\frac{11}{1}\) x \(\frac{3}{44}\)) = \(\frac{11m}{22}\) + \(\frac{33}{44}\) = \(\frac{m}{2}\) + \(\frac{3}{4}\)

Step 2. Simplify.

87m + m x 5 = 87m + 5m = 92m

Step 3. Cancel out the add \(\frac{3}{4}\)

\(\frac{m}{2}\) + \(\frac{3}{4}\) = 92m

- \(\frac{3}{4}\)

\(\frac{m}{2}\) = 92m - \(\frac{3}{4}\)

\(\frac{m}{2}\) = \(\frac{92m}{1}\) - \(\frac{3}{4}\)

\(\frac{m}{2}\) = \(\frac{368m}{4}\) - \(\frac{3}{4}\)

\(\frac{m}{2}\) = \(\frac{368m - 3}{4}\)

Step 4. Cancel out the ÷ 4

\(\frac{m}{2}\) = \(\frac{368m - 3}{4}\)

x 4

2m = 368m - 3

Step 5. Cancel out the 368m

2m = 368m - 3

- 368m

-366m = - 3

Step 6. Cancel out the × -366

-366m = -3

÷ -366

m = \(\frac{-3}{-366}\)

m = \(\frac{1}{122}\)

Step 7. Write down your answer.

m = \(\frac{1}{122}\)

Q5.

ck + 5k = a

Step 1. Factorise

ck + 5k = (c × k) + (5 × k) = (c + 5) x k = k(c + 5)

Step 2. Cancel out the × (c + 5)

k(c + 5) = a

÷ (c + 5)

k = a ÷ (c + 5)

k = \(\frac{a}{(c + 5)}\)

The value of cos2x when sine of x equals negative 15 over 17 and cos x > 0 is -161/289.

The ratio of the neighboring side's length to the longest side, or hypotenuse, in a right triangle is known as the cosine. Let's say that the hypotenuse of a triangle ABC is written as AB, and the angle between the hypotenuse and base is written as.

It's interesting to see that cos's value varies depending on the quadrant. As observed in the above table, cos 0°, 30°, etc. have positive values while cos 120°, 150°, and 180° have negative values. Cos will have a good value in the first and fourth quadrants.

Given that, sin x equals negative 15 over 17.

Using the Pythagoras theorem we have:

(17)² = (- 15)² + y²

y = 8

The value of cos x = 8/17

Then the value of cos2(x) is calculated using the formula:

cos2x = cos²x - sin²x

cos2x = (8/17)² - (15/17)²

cos2x = -161/289

Hence, the value of cos2x when sine of x equals negative 15 over 17 and cos x > 0 is -161/289.

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Answer:

  3.75 miles

Step-by-step explanation:

You want to know the number of miles represented by 6 km, when the relationship is 1.6 km = 1 mile.

Anytime measures are related by a constant conversion factor, the values of the measures in one unit are proportional to the values expressed in a different unit. That is, the ratio of km to miles is a constant.

We can let d represent the distance between the school and the park.

  miles / km = (1 mi)/(1.6 km) = d/(6 km) . . . . miles and km are proportional

Multiplying by 6 km, we get ...

  d = (6 km)(1 mi)/(1.6 km) = (6/1.6) mi ≈ 3.75 mi

The school and the park are 3.75 miles apart.

Answer:

Density (ρ) = 0.1875 gram/cubic centimeter

Step-by-step explanation:

Steps:

p=m/v, 3/16

To write the coordinates of a point in a x - y plane you:

1. Find the distance in x-axis:

The given point A is 7 units distance in x-axis

2. Find the distance in y- axis

The given point A is -5 units distance in y-axis

You write the coordinates in form (x,y)

As x=7 and y=-5

Answer: -5,7

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

So the concept is that co-interior angles add up to 180 in parallel line. This means:

3x + 9 + 9x + 15 = 180

So we solve for x.

12x + 24 = 180 ( What I did was simplifying the equation).

12x + 24 - 24 = 180 - 24

12x / 12= 156 / 12

x = 13

HOPE THIS HELPED

The solutions to the given equation on the interval 0≤x<2π. −8sin(5x)=−4√ 3 The solutions to the equation -8sin(5x) = -4√3 on the interval 0 ≤ x < 2π are:

x = π/3 and x = 2π/3.

To find the solutions to the equation -8sin(5x) = -4√3 on the interval 0 ≤ x < 2π, we can start by isolating the sine term.

Dividing both sides of the equation by -8, we have:

sin(5x) = √3/2

Now, we can find the angles whose sine is √3/2. These angles correspond to the angles in the unit circle where the y-coordinate is √3/2.

Using the special angles of the unit circle, we find that the solutions are:

x = π/3 + 2πn

x = 2π/3 + 2πn

where n is an integer.

Since we are given the interval 0 ≤ x < 2π, we need to check which of these solutions fall within that interval.

For n = 0:

x = π/3

For n = 1:

x = 2π/3

Both solutions, π/3 and 2π/3, fall within the interval 0 ≤ x < 2π.

Therefore, the solutions to the equation -8sin(5x) = -4√3 on the interval 0 ≤ x < 2π are:

x = π/3 and x = 2π/3.

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We are given –

\(\qquad\) \(\twoheadrightarrow\bf x² = 4x -4\)

\(\qquad\) \(\twoheadrightarrow\bf x² -4x +4 = 0\)

Let's find it's discriminant.

We know –

\(\qquad\) \(\purple{\twoheadrightarrow\bf Discriminant = b² - 4ac}\)

\(\qquad\) \(\twoheadrightarrow\sf Discriminant = (-4)² - 4 \times 1 \times 4\)

\(\qquad\) \(\twoheadrightarrow\sf Discriminant = 16-16\)

\(\qquad\) \(\purple{\twoheadrightarrow\sf Discriminant =0 }\)

As we got –

Answer:

D / 10

Step-by-step explanation:

X - 1 over 3 = 3

10-1 = 9/3 = 3

Answer:

\(value \: of \: k \: = 3 \\ \\ \frac{x - 1}{3} = k \\ put \: value \: of \: k \: which \: is \: 3 \\ \frac{x - 1}{3} = (3) \\ as \: 3 \: is \: dividing \: here \: it \: will \\ be \: multiplied \: on \: anthor \: side \: \\ x - 1 = 3 \times 3 \\ x - 1 = 9 \\ x = 9 + 1 \\ x = 10 \: \: \: answer \\ \\ so \: answer \: is \: option \: d) \: 10\)

(a) Simplifying this expression gives:

x = cos(theta) + cos(3theta)

Now we have eliminated the parameter and have a Cartesian equation for the curve.

(b) To indicate the direction in which the curve is traced, we can draw an arrow pointing counterclockwise along the curve.

We can first eliminate sec2(theta) by using the identity sec2(theta) = 1/cos2(theta). Substituting this into the equation for y gives:

y = 1/cos2(theta)

Next, we can use the double angle formula for cosine to write cos2(theta) = (1 + cos(2theta))/2. Substituting this into the equation for x gives:

x = 2 cos(theta) = 2 cos(theta) (1 + cos(2theta))/2

Simplifying this expression gives:

x = cos(theta) + cos(3theta)

Now we have eliminated the parameter and have a Cartesian equation for the curve.

To sketch the curve, we can use the fact that cos(theta) has a period of 2π and oscillates between -1 and 1, while cos(3theta) has a period of 2π/3 and oscillates between -1 and 1 as well. The sum of these two functions will create a new curve that repeats every 2π/3 radians.

Starting at theta = 0, the value of cos(theta) is 1 and the value of cos(3theta) is 1, so the initial point on the curve is (3, 1). As theta increases, the curve moves counterclockwise and oscillates between a maximum value of 3 + 1 = 4 and a minimum value of 3 - 1 = 2.

To indicate the direction in which the curve is traced, we can draw an arrow pointing counterclockwise along the curve.

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Answer:I think its 2

Step-by-step explanation:Im not really sure but i think thats the answer

Answer:

2

Step-by-step explanation:

The basic unit of mass of the ball in the metric system is the gram.

The base units of length (distance), capacity (volume), and weight (mass) in the metric system are the meter, liter, and gram, respectively. We utilize units that are derived from metric units to measure smaller or greater quantities.

Mass is a physical body's total amount of matter. Inertia, or the body's resistance to acceleration when a net force is applied, is also measured by this term. The strength of an object's gravitational pull to other bodies is also influenced by its mass.

Therefore, the basic unit of mass of the ball in the metric system is the gram.

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Answer:

5cm

Step-by-step explanation:

I don’t see a picture so I’m assuming it’s a right triangle, otherwise it’s impossible to solve.

The vertical component of the vector with initial point (1,4) and terminal point (5, -3) is -7. The correct option is b).

We need to find the vertical component of the vector v with initial point (1, 4) and terminal point (5, -3).

Step 1: Determine the coordinates of the vector v.
The coordinates of v can be found by subtracting the initial point coordinates from the terminal point coordinates.

v = (5 - 1, -3 - 4)
v = (4, -7)

Step 2: Identify the vertical component.
The vertical component is the second coordinate of the vector, which represents the change in the vertical (y) direction.

In this case, the vertical component of vector v is -7. So, the correct answer is b).

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Answer:

The table on the far left is a linear function.

Step-by-step explanation:

The table on the far left is the function

\(y = \frac{1}{2} x\)

Answer:

no solution

Step-by-step explanation:

3(x – 5) = 1/2 (6х- 12)

3х-15= 6/2х-12/2

3х-6/2х=15-12/2

3х-3х=15-6

0х=9 no solution

Answer:

no solution

Step-by-step explanation:

3(x – 5) = 1/2 (6х- 12)

3х-15= 6/2х-12/2

3х-6/2х=15-12/2

3х-3х=15-6

0х=9 no solution

To solve the system of equations:

4x^2 + 9y^2 = 72

x^2 - y^2 = 5

We can use the method of substitution. Let's solve the second equation for x^2:

x^2 = y^2 + 5

Now substitute x^2 in the first equation:

4(y^2 + 5) + 9y^2 = 72

4y^2 + 20 + 9y^2 = 72

13y^2 + 20 = 72

13y^2 = 52

y^2 = 4

y = ±2

Substituting y = 2 into x^2 = y^2 + 5, we get:

x^2 = 2^2 + 5

x^2 = 9

x = ±3

Therefore, the solutions to the system of equations are:

(x, y) = (-3, 2), (-3, -2), (3, 2), (3, -2)

Listing the solutions with the smallest x-values and then the smallest y-value first, we have:

(-3, -2), (-3, 2), (3, -2), (3, 2)

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Answer:

ranalllldooo

Step-by-step explanation:

suiiiiiii

Answer:

slope of  line segment XY is -2.

Step-by-step explanation:

plz gve me points thank you

From the given graph, we have

coordinate of the point X is (-1,3)

coordinate of the point y is (1,-1)

The slope of a line through the point  is given by

Here, we have

On substituting these value in the above formula of slope, we get

Therefore, the slope of  line segment XY is -2.

Answer:

p = 0.70z

Step-by-step explanation:

p is the food the penguins eat

z is the food the zebras eat

We are told that:  p < z

Then we are told that:  p = 70% of z

This can be written as p = 0.70z

An alternative way this can be written is:  p/z = 0.70  [The ratio of p to z is 0.7]

The period for the following graph is 90 degrees. So correct option is C.

In mathematics, a period is a specific type of repetition in a function or a sequence. A period is the smallest positive value of a constant T for which a function or a sequence f(x + T) = f(x) for all x.

Periods are used to describe the behavior of functions and sequences that exhibit a repeating pattern. The length of the period determines the frequency of the pattern, and it is often used to describe the periodicity of functions in various applications, such as signal processing, harmonic analysis, and Fourier series.

For example, the sine function sin(x) is periodic with a period of 2π. This means that sin(x + 2π) = sin(x) for all x. Similarly, the cosine function cos(x) is also periodic with a period of 2π. Other common examples of periodic functions include the tangent function, cotangent function, and exponential function.

In addition to their applications in mathematics, periods also have practical applications in fields such as physics, engineering, and computer science, where they are used to model periodic phenomena such as waves and oscillations.

Overall, periods are an important concept in mathematics and are used to describe the repeating patterns that are found in many mathematical functions and sequences.

The period for the following graph is 90 degrees.

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The solution for x is 621.5424 M \(s^{-1}\), with units of molar per second (M \(s^{-1}\)).

To solve for x in the equation x = (6.4×10^3 M^(-2) s^(-1))(0.46M)^3, we can simplify the expression and calculate the result. Let's break it down step by step: x = (6.4×10^3 M^(-2) s^(-1))(0.46M)^3

First, let's simplify (0.46M)^3: (0.46M)^3 = (0.46^3)(M^3) = 0.097336M^3

Now, substitute this back into the equation:

x = (6.4×10^3 M^(-2) s^(-1))(0.097336M^3)

Next, multiply the terms: x = 6.4×10^3 × 0.097336 M^(-2) s^(-1) M^3

When multiplying the terms with the same base, we add the exponents:

x = 6.4×10^3 × 0.097336 M^(-2 + 3) s^(-1)

Simplifying the exponent: x = 6.4×10^3 × 0.097336 M^(1) s^(-1)

Now, multiply the numerical values: x = 621.5424 M s^(-1)

Therefore, the solution for x is 621.5424 M s^(-1), with units of molar per second (M s^(-1)).

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