on a horizontal axis. a 2-kg mass is suspended from the wheel by a rope wound around the rim. find the

Răspuns:

B.) 25m C.) = 10m / s

Explicaţie:

Dat fiind :

Poziția inițială (u) = odihnă = 0

Poziția inițială = 2m de la origine

Accelerarea = 2 m / s²

Legea mișcării: prima lege a mișcării care afirmă că un corp va continua în starea sa de repaus sau viteză uniformă în linie dreaptă, cu excepția cazului în care este acționat de o altă forță pentru a-l face să acționeze altfel.

B.) poziție după 5 secunde:

Folosind relația:

S = 1/2 * la ^ 2

S = distanță; a = accelerare; t = timp

S = 0,5 (2) (5 ^ 2)

S = 0,5 * 2 * 25

S = 25 m

C.) viteza după 5 secunde:

v = u + la

Unde a = accelerație; t = timp; v viteza finală

v = 0 + 2 (5)

v = 10 m / s

Answer:

63.8454kgm/s

Explanation:

According to Newton's second law;

Force = mass ×acceleration

Fore = m(v-u)/t

Force = mv-mu/t

MV is the final momentum

mu is the initial momentum = 38kgm/s

Force = 88.3N

Time = 0.338s

Substitute and get mv

88.3 = mv-38/0.338

88.3×0.338 = mv-38

29.8454 = mv-38

MV = 29.8454+34

mv = 63.8454kgm/s

Hence the final momentum is 63.8454kgm/s

Answer:

67.8

Explanation:

im an acellus student, and this is the answer that i got when doing the problem.

The poison was most likely found was B)arsenic

What is poisioning?

Poisoning is defined as harm or death brought on by ingesting, inhaling, touching, injecting, or ingesting different medications, chemicals, venoms, or gases. Many chemicals, including pharmaceuticals and carbon monoxide, become dangerous only when they are consumed in large quantities. While some cleaners only cause harm when consumed, others also release hazardous vapors or fumes.

When large doses of arsenic are ingested or inhaled, arsenic poisoning, also known as arsenicosis, occurs. Gray, silver, or white in hue, arsenic is a form of carcinogen. For humans, arsenic is exceedingly dangerous. Because it has no taste or odor, arsenic is particularly hazardous because you can be exposed to it covertly. After death, the toxin leaves residues on the body.

Hence the poison was most likely found was B)arsenic

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The component of horizontal velocity of bullet is 8m/s for 4 radians per second.

Given - Rotation rate = 4 rad per sec.

This means 4 radians for one seconds . i.e. one seconds is equivalent to 60min.

To resolve the velocity following equation can be employed-

\(\beta =vt+\frac{\alpha t^2}{2}\\ \\\beta = rotation\\\\v= velocity\\\\t= time\\\\\alpha =acceleration\)

Now substituting all values in this equation

4= 0+α/2

α=4 x 2 ⇒8m/s²

since the rotation is for one seconds so velocity = acceleration.

\(acceleration=\frac{dv}{dt}\)

dt =1

so α=v=8m/s

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The current needed to create a maximum torque of 5.00 N·m in the loop is approximately 0.103 A.

The torque (τ) experienced by a current-carrying loop in a magnetic field is given by the equation:

τ = NIABsinθ,

where N is the number of turns, I is current, A is the area of the loop, B is the magnetic field strength, and θ is the angle between the magnetic field and the normal to the loop.

In this case, the torque (τ) is given as 5.00 N·m, the number of turns (N) is 52, the area of the loop (A) is \((13.0 cm)^2\), which is equal to \(0.169 m^2\), and the magnetic field strength (B) is 0.700 T.

Rearranging the formula, solve for the current (I):

I = τ / (NABsinθ)

Since the angle θ is not given, assume it to be 90 degrees (sinθ = 1).

Plugging in the given values:

\(I = 5.00 N.m / (52 * 0.169 m^2 * 0.700 T * 1)\)

I ≈ 0.103 A

Therefore, the current needed to create a maximum torque of 5.00 N·m in the loop is approximately 0.103 A.

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The second derivative of the given function ∫(x) = x² - (4/3)x - 6 is: ∫''(x) = 2

The second derivative of a function represents the rate of change of the first derivative. It is obtained by differentiating the function twice with respect to the independent variable.

To find the second derivative of the given function, we need to differentiate it twice with respect to x.

Given:

∫(x) = x² - (4/3)x - 6

To find the first derivative, let's differentiate the function:

∫'(x) = d/dx (x² - (4/3)x - 6)

∫'(x) = 2x - 4/3

Now, to find the second derivative, let's differentiate the first derivative:

∫''(x) = d/dx (2x - 4/3)

∫''(x) = 2

Therefore, the second derivative of the given function is 2.

The correct question should be:

Which of the following is the second derivative of

∫(x) = \(\frac{x^{2}-4 }{3x-6}\)

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Answer:

Which surface applied the greatest force of friction on the object?

Rougher surfaces have more friction between them. Heavier objects also have more friction because they press together with greater force.

I hope you helped>_<

The flow of electricity in a certain path is the circuit.

Space is a vacuum, and since it contains no matter, it has no intrinsic temperature which varies from extremely hot to extremely cold.

Space is a vacuum, and since it contains no matter, it has no intrinsic temperature. However, temperature can be defined as a measure of the average kinetic energy of the particles in a system, and space does contain various types of energy that can affect the temperature of objects within it.

The temperature of space varies depending on the location and the conditions. For example, objects in the vicinity of the sun or other stars can experience extreme temperatures due to the intense radiation and thermal energy. In contrast, regions of space that are far away from stars or other sources of radiation can be extremely cold, approaching absolute zero (-273.15 degrees Celsius or -459.67 degrees Fahrenheit).

Additionally, objects in space can experience changes in temperature due to their proximity to other objects or the presence of an atmosphere or other insulating material. For example, the International Space Station experiences a range of temperatures, from extremely hot when it is in direct sunlight to extremely cold when it is in the Earth's shadow.

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According to Newton's law of cooling the temperature of a body that is colling down is related to time by the following formula:

Where:

In this case, the initial and ambient temperatures are the same. Therefore, the rate at which the temperature changes depends on the value of "k". The greater the value of "k" the faster the mass will cool down.

Answer:

D

Explanation:

im not sure just sounds right

Transformer-Rectifier units for CAC-A (Constant Current Arc Welding) should have a minimum of 60% duty cycle, with at least three-phase units.

Constant Current Arc Welding is also known as "stick welding." The acronym CAC stands for "constant current," which means the power source must be able to produce a constant output current, regardless of the resistance of the welding arc.

To create the appropriate current for the welding, a transformer-rectifier is used. A transformer-rectifier unit comprises of a transformer and a rectifier. The transformer converts high voltage, low current AC electricity from the power source to low voltage, high current AC electricity, which is then supplied to the rectifier. The rectifier transforms the AC input into a direct current (DC) output that the welding equipment requires.

The duty cycle is defined as the amount of time during which the machine can operate without overheating. The transformer-rectifier should have a 60% duty cycle or higher because welding generates a lot of heat and needs a lot of power. If the duty cycle is too low, the unit will shut down too often and be unable to perform effectively.

A 60% duty cycle ensures that the welding machine can run continuously for six minutes out of every ten minutes. It is recommended that you choose a transformer-rectifier with a duty cycle that meets your requirements, as a higher duty cycle would allow you to weld for longer periods of time before requiring a cool down period.

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The thinnest soap film that appears black when illuminated with light with a wavelength of 520 nm is about 195 nm.

A natural phenomenon known as "thin-film interference" occurs when light waves reflected by a thin film's upper and lower limits collide with one another, either enhancing or weakening the light that is reflected.

First, draw the diagram. From the diagram 1 is the first reflected ray and 2 is the second reflected ray. The red circle indicates the phase change. The first ray experience phase change but the second ray doesn't experience phase change.

Therefore, the thickness of the soap bubble is given by the thin-film interference formula,

\(\begin{aligned}2t& = m\lambda_{soap}\\t&=\frac{m\lambda_{soap}}{2}\\\lambda_{soap}&=\frac{2t}{m}\end{aligned}\)

From Snell's law, we know that n₁λ₁=n₂λ₂, where λ is the wavelength and n is the index of refraction.

Then, for the soap film, \(n_{air}\lambda_{air}=n_{soap}\lambda_{soap}\).

We know that n (air) is 1. From this,

\(\begin{aligned}\lambda_{soap}&=\frac{\lambda_{air}}{n_{soap}}\\\frac{2t}{m}&=\frac{\lambda_{air}}{n_{soap}}\\t&=\frac{m\lambda_{air}}{2n_{soap}}\end{aligned}\)

Excluding the case of zero thickness, substitute m=1 for the first destructive interference.

Then, the smallest thickness is,

\(\begin{aligned}t&=\frac{\lambda_{air}}{2n_{soap}}\\&=\frac{520}{2\times1.33}\\&=\mathrm{195\;nm}\end{aligned}\)

The answer is 195 nm.

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If a thin thread is placed between a screen and a bright source of light, a pattern of of parallel light and dark strips appears on the screen. This phenomenon is called the diffraction of light.

When a thin thread comes in the path of light waves, it obstructs the upfront of the light wave causing the change in the phase difference of the wave. Overlapping of these different waves of different phase differences cause the dark and light pattern appearance on the wall.  On the other hand, thin thread also cast a thin shadow due to the obstruction in the path of light. Pattern on the wall depends on the phase difference in the wave-upfront.

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1/second Equals 1.99 x 10-7 radians. Earth rotates at a rate of 1.99 x 10-7 per second.

If the angles were not approximately 1 one of, then the radius times the angle's measurement in radians, or the width of a arc s = r, would be the ratio of the distance by the point located on the circle. The result of substituting into the linear speed formula is v = r t or v = r t.

A pseudovector used in physics to express how quickly the angular location or orientation of an item changes over time is called an angular velocity or rotational velocity.

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Answer:

C

Explanation:

they involve breaking and making chemical bonds

Answer: C

Explanation:

The motorcycle is likely to appear farther away than it actually is because it is smaller in size than your car. This phenomenon is known as the size-distance illusion, where our brains tend to perceive smaller objects as farther away, even if they are not. This is because our brain assumes that larger objects are closer and smaller objects are farther away.

Moreover, the visual angle of the motorcycle, which is the angle that the motorcycle subtends on your eye, is smaller than that of your car due to its smaller size. Hence, our brain interprets this smaller visual angle as an indication that the motorcycle is farther away than it actually is.

As a driver, it is crucial to be aware of this illusion and take necessary precautions while turning or changing lanes to avoid accidents with smaller vehicles such as motorcycles. One should always check their surroundings thoroughly and double-check before making a move.

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For a uniform electric field  E, the equipotential surface is normal to its field lines.

A area in space where all points have the same potential is known as an equipotential or isopotential.

Potential is inversely proportional to radial distance for a solitary, isolated point charge.

As a result, the point charge is located in the center of the equipotential surface for a solitary point charge, which is spherical.

The area where all things have the same potential is referred to as the equipotential surface.

A charge can be shifted effortlessly from one location to another on the equipotential surface. A surface that has the same electric potential at every location is said to be equipotential. The diagram for the equipotential surface is attached below.

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The value of the work that was done on the car is 24.6 J.

Work is an energy that move from or to one object into another object that might make the object have the displacement, or we can say work is equal to force multiply with displacement in meters. In formula form, it will be written as W = F x s. As per data given F = 36.8 N and s = 668 m. The work will be:

W = F x s

W = 36.8 x 668

W =  24,582J  

Let round the work value. So, the work value will be 24.6 J

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The government can address the environmental damage caused by thrown-away plastic water bottles through solutions such as implementing a deposit and return system or imposing taxes, which incentivize responsible behavior, reduce plastic waste, and mitigate negative externalities.

a. The economic concept that explains the damage created by thrown-away empty plastic water bottles is "negative externality."

b. Negative externality occurs when the production or consumption of a good or service imposes costs on third parties who are not involved in the transaction. In this case, the irresponsible disposal of plastic water bottles creates environmental damage, such as pollution in landfills and oceans, affecting society as a whole. It is a market failure because the private cost of producing and consuming bottled water does not include the full social cost of the resulting environmental damage.

The market situation in this context involves a divergence between private and social costs. Consumers of bottled water do not bear the full cost of the environmental damage caused by the improper disposal of plastic bottles. Consequently, the market equilibrium for bottled water fails to account for the negative externalities imposed on society.

c. Two solutions available to the government to correct this environmental issue are:

Implementing a plastic bottle deposit and return system: The government can establish a system where consumers pay an additional deposit fee when purchasing plastic water bottles, which is refunded when they return the empty bottles to designated collection points. This incentivizes consumers to return the bottles for recycling or proper disposal, reducing environmental damage.

Imposing taxes or levies on plastic water bottles: The government can impose taxes or levies on the production or consumption of plastic water bottles. This increases the cost of bottled water, reflecting the social cost of environmental damage. The additional revenue generated from these taxes can be used to fund environmental conservation and recycling programs.

d. These solutions will correct the given situation by internalizing the external costs associated with plastic water bottle consumption. By implementing a deposit and return system or imposing taxes, consumers are incentivized to act responsibly by returning the bottles or opting for alternative packaging options. This reduces the amount of plastic waste in landfills and oceans, mitigating environmental damage.

The deposit and return system encourages recycling and reuse of plastic bottles, reducing the need for new bottle production and decreasing overall plastic waste. The taxes or levies increase the price of bottled water, making alternatives like reusable bottles or tap water more economically attractive. The revenue generated from these taxes can be utilized for environmental initiatives such as recycling infrastructure, public awareness campaigns, and research and development of sustainable packaging materials.

Therefore, by internalizing the negative externalities associated with plastic water bottle consumption, these solutions promote responsible behavior, reduce plastic waste, and mitigate the environmental damage caused by improper disposal.

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Answer:

After 2 seconds the velocity of the object is 0 m/s.

Explanation:

The velocity at 2 seconds later can be calculated as follows:

\( V_{f} = V_{0} - gt \)

Where:

\(V_{f}\): is the velocity at 2 seconds

\(V_{0}\): is the initial velocity = 20 m/s

g: is the gravity = 10 m/s²

t: is the time = 2 s

Hence, the final velocity is:

\( V_{f} = V_{0} - gt = 20 m/s - 10 m/s^{2}*2 s = 0 m/s \)

This value (0 m/s) means that the object has reached the maximum height.

Therefore, after 2 seconds the velocity of the object is 0 m/s.

I hope it helps you!

The anthracite coal price per MMBtu is $3.00/MMBtu. Therefore, the correct option is A.

The heat content of anthracite coal is 15,000 BTU/pound. The question requires the conversion of an anthracite coal price of $90/ton to $/MMBtu. Let us use the given data to solve the problem. 1 ton equals 2000 pounds (lb). Hence,

2000 lb of anthracite coal has a heat content of 2000 lb x 15,000 BTU/lb = 30,000,000 BTU

Thus, the price per MMBtu can be calculated by the given formula;

Price per MMBtu = Price per ton / (BTUs per ton / MMBTUs per ton)

Price per MMBtu = $90 / (30,000,000 / 1,000,000)

Price per MMBtu = $90 / 30

Price per MMBtu = $3.00/MMBtu

Thus, the price per MMBtu of anthracite coal is $3.00/MMBtu. Therefore, the correct answer is option A: $3.00/MMBtu.

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Answer:

The unique physical properties, including a high heat of vaporization, strong surface tension, high specific heat, and nearly universal solvent properties of water are also due to hydrogen bonding.

a) V= 13m/s at 24 degrees

X component of velocity Vx= V*cos24 =11.876 m/s

distance =4.2 meter

time =distance/speed =4.2/11.876 =0.3537 s

b) Vertical component of speed = Vy=vsin24=

5.29 m/s

s=ut+0.5at^2 =5.29880.3537-0.5*9.8*0.3537^2

=1.257 m above ground

Hope I helped! ヾ(^▽^*)))

If the frequency of wave 'a' is one-third of that of wave 'b', then the time period of wave a will be three times as compared to the time period of wave 'b'

The frequency of a wave is inversely proportional to its time period, and it is defined as the number of oscillations per second.

which means F ∝ 1/T

If we remove the proportionality we will need to add a constant.

which makes the relation F = k/T

Time period is defined as the total time taken by a wave to complete one oscillation.

Now as per the data we have,

let the frequency of wave b be 'F', and the time period of b be 'T'

\(F_{a}\) = F/3 and \(T_{a}\) = T/3

Arranging the data into the formula we get

\(\frac{F_{a}}{F_{b}} = \frac{T_{b}}{T_{a}}\)

Which gives us \(T_{b}\) = 3\(T_{a}\)

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The youngest is Calliope.

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Answer:

Explanation:

let's find the acceleration

\(v = u + at \\ 8 = 0 \times a \times 2.5 \\ \alpha = 3.2m {s}^{ - 2} \)

then distance

\( {v}^{2} = {u}^{2} + 2as \\ {8}^{2} = 2 \times 3.2 \times s \\ \\ s = 10m \)

The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.

d (distance) from A to B is = √2gh

In this case given are, g = 9.8 m/s² and h = 100m,

so here d = √(2⋅9.8⋅100) = 44.3m.

Final velocity ,v = √2gh

Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,

g = 9.8 m/s² ,h = 100m,

v = √(2⋅9.8⋅100)

= 44.3 m/s (final velocity)

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The speed of the 1.2 kg block after the spring is released is 3 m/s to the left.

According to the question, a 1.2 kg block and a 1.8 kg block are initially at rest on a frictionless, horizontal surface. When a compressed spring between the blocks is released, the 1.8 kg block moves to the right at 2.0 m/s as shown. We need to determine the speed of the 1.2 kg block after the spring is released.The system's initial momentum is zero since the blocks are at rest. The system's final momentum is made up of the 1.2 kg and 1.8 kg blocks' respective momenta. As a result, the conservation of momentum equation becomes:m1i * v1i + m2i * v2i = m1f * v1f + m2f * v2fWhere m1i * v1i is the 1.2 kg block's initial momentum, m2i * v2i is the 1.8 kg block's initial momentum, m1f * v1f is the 1.2 kg block's final momentum, and m2f * v2f is the 1.8 kg block's final momentum.

As the 1.8 kg block moves to the right at 2.0 m/s after the spring is released, its momentum is:m2i * v2i = 1.8 kg * 0 m/s = 0 kg * m/sm2f * v2f = 1.8 kg * 2 m/s = 3.6 kg * m/sTo calculate the final momentum of the 1.2 kg block, we must first determine its final velocity. We can rearrange the conservation of momentum equation above to solve for v1f:m1f * v1f = m1i * v1i + m2i * v2i - m2f * v2fv1f = (m1i * v1i + m2i * v2i - m2f * v2f) / m1fPlugging in the values:v1f = (1.2 kg * 0 m/s + 1.8 kg * 0 m/s - 1.8 kg * 2 m/s) / 1.2 kgv1f = -3 m/s. Therefore, the speed of the 1.2 kg block after the spring is released is 3 m/s to the left.

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