On a drive from your home to town, you
wish to average 60 mph. The distance from
your home to town is 78 miles. However,
at 39 miles (half way), you find you have
averaged only 45 mph.
What average speed must you maintain in
the remaining distance in order to have an
overall average speed of 60 mph?
Answer in units of mph.

Answers

Answer 1

On a drive from your home to town, you wish

to average 33.6 mph. The distance from your

home to town is 90 miles. However, at 45 miles

(half way), you find you have averaged only

25.2 mph.

What average speed must you maintain in

the remaining distance in order to have an

overall average speed of 33.6 mph?

Answer in units of mph

let the speed be x

total average = 33.6


Related Questions

a 27 kg is accelerated at a rate of 1.7m/s/s . what force does the object experience

Answers

The answer should be (C)46n

Determine the values of m
and n
when the following average distance from the Sun to the Earth is written in scientific notation: 150,000,000,000 m
.
Enter m
and n
, separated by commas.

Answers

Answer:

To write 150,000,000,000 meters in scientific notation, we need to move the decimal point 11 places to the left to get a number between 1 and 10. This gives us:

1.5 × 10^11 meters

Therefore, m is 1.5 and n is 11.

The answer is: 1.5,11

a. At a constant temperature, the volume of the vessel is compressed to half. How will the rms speed of gas in it change? [2] Air at temper 9727​

Answers

According to the information, the rms speed of the gas will remain unchanged.

How will the rms speed of gas in it change?

The rms (root-mean-square) speed of a gas is directly proportional to the square root of its temperature. In this scenario, the temperature is constant, which means that the rms speed of the gas will also remain constant.

The change in volume does not have a direct effect on the rms speed of the gas, as long as the temperature remains unchanged. Therefore, the rms speed of the gas in the vessel will not change.

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Below are 3 pieces of cobalt metal . In each, four different magnetic domains are drawn. Each domain is labeled with an arrow indicating the direction of the magnetic field in that domain. Which of these bars of cobalt metal has a magnetic field?

O Bar A
O Bar B
O Bar C

Below are 3 pieces of cobalt metal . In each, four different magnetic domains are drawn. Each domain

Answers

Answer: B

Those two are the only ones with the lines in opposite directions. The lines are also going towards one another so there is a magnetic pull

Calculate Time
d
12. A vehicle drives a distance of 26000 m at a speed of 65m/s, calculate the time taken for
this journey.
13. A train travels at a speed of 16 m/s and travel a distance of 3200 m, calculate the time it
takes the train to complete this journey.
urs 14. Calculate the time it takes to travel a distance of 672 km at a speed of 96 km/h.
15. A beetle travels at a speed of 0.09 m/s, it travels a distance of 1.08 m before it is caught
in a jar. Calculate the time taken for the beetle to run.
16. Carlisle is a distance of 35 miles away from Lockerbie. If I travelled at a constant speed
5147
deudate the time takon for this journey

Answers

12. The time taken for the journey is 400 s

13. The time taken for the train is 200 s

14. The time taken is 7 h

15. The time taken for the beetle is 12 s

16. The time taken for the journey is 0.0068 h

How do i determine the time taken?

The time taken in each case as given by the question can be obtain as follow:

12. The time taken for the journey

Distance traveled = 26000 mSpeed = 65 m/s Time taken =?

Time taken = Distance / Speed

Time taken = 26000 / 65

Time taken = 400 s

13. The time taken for the train

Distance traveled = 3200 mSpeed = 16 m/s Time taken =?

Time taken = Distance / Speed

Time taken = 3200 / 16

Time taken = 200 s

14. The time taken to travel

Distance traveled = 672 kmSpeed = 96 Km/h Time taken =?

Time taken = Distance / Speed

Time taken = 672 / 96

Time taken = 7 h

15. The time taken for the beetle

Distance traveled = 1.08 mSpeed = 0.09 m/s Time taken =?

Time taken = Distance / Speed

Time taken = 1.08 / 0.09

Time taken = 12 s

16. The time taken for the journey

Distance traveled = 35 milesSpeed = 5147 mile per hourTime taken =?

Time taken = Distance / Speed

Time taken = 35 / 5147

Time taken = 0.0068 h

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How have astronomers used models to explain galactic evolution through mergers and collisions? Use this model to explain how astronomers might test their understanding of the physical processes of the universe.

Answers

Answer:

Astronomers use computer models to simulate the process of galactic evolution through mergers and collisions. These models are based on our current understanding of the physical laws that govern the behavior of matter and energy in the universe. By running simulations of galactic mergers and collisions, astronomers can test their understanding of how these physical processes work in practice and how they contribute to the formation and evolution of galaxies.

One way that astronomers might test their understanding of the physical processes of the universe is by comparing the predictions of their models to observations of real galaxies. For example, if a model predicts that a particular type of galaxy should have a certain shape, size, or distribution of stars, astronomers can compare these predictions to observations of actual galaxies to see if they match up. If there is a discrepancy between the model's predictions and the observations, this can indicate that there are some physical processes that are not well understood or included in the model.

Another way that astronomers might test their understanding is by looking for patterns or trends in the properties of galaxies that are consistent with the predictions of their models. For example, if a model predicts that galaxies that have undergone a recent merger should have a particular distribution of gas and dust, astronomers can look for evidence of this pattern in observations of real galaxies. If they find that the predicted pattern is consistently observed in a large sample of galaxies, this can provide support for the model's predictions and the physical processes that it includes.

Overall, computer models of galactic evolution through mergers and collisions provide a powerful tool for astronomers to test their understanding of the physical processes of the universe. By comparing the predictions of their models to observations of real galaxies and looking for consistent patterns and trends, astronomers can refine their understanding of how galaxies form and evolve over time.

23.15. Can an object carry a charge of 2.0 10-19 C?​

Answers

Answer:

Ok, the minimal quantity of charge that we can find is on the electron or in the proton (the magnitude is the same, but the sign is different)

Where the charge of a single proton is:

C = 1.6x10^-19 C

Now, you need to remember that when we are working with charges, we are working with discrete math:

What means that?

If the minimum positive is the charge of one proton, then the consecutive charge will be the charge of two protons (there is no somethin in between)

So the consecutive charge will be:

C = 2*1.6x10^-19 C = 3.2x10^-19 C.

So, because we are working in discrete math, we can not have any object that has charge between  1.6x10^-19 C and 3.2x10^-19 C.

Particularly, 2.0x10^-19 C is in that range, so we can conclude that:

No, an object can not carry a charge of 2.0x10^-19 C.

If the change in kinetic energy of a tennis ball hit by the racket
is 29), and the average force that the racket exerts on the ball
is 80. N, what is the distance that the force is exerted over?

Answers

Answer: .36 m

Explanation:

The distance that the force is exerted over is equal to 0.3625 meter.

Given the following data:

Change in kinetic energy = 29 Joules.Average force = 80 Newton

To calculate the distance that the force is exerted over, we would apply the law of conservation of energy.

The law of conservation of energy.

According to the law of conservation of energy, the work done by an external force equals the change in kinetic energy for the motion of the tennis ball hit by the racket.

Mathematically, this is given by this expression:

\(Work\;done = \Delta K.E = Fd\)

Where:

F is the force.d is the distance.

Substituting the given parameters into the formula, we have;

\(29 = 80 \times d\\\\d=\frac{29}{80}\)

Distance, d = 0.3625 meter.

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Explain why it takes much more effort to stop a freight train compared with a car?

Answers

Answer:

Train wheels and rails are both made of steel, and the steel-steel friction coefficient is around 0.25. As a result, the stopping time and distance will be three to four times that of a car.

A music store marks up the instruments it sells by 30%. If the store bought a guitar for $45, what will be its store price?

Answers

Answer:

45/10=4.5•3=13.5+45=58.5

Explanation:

Answer:

$58.50

Explanation:

it would be 58.5 but if it with money it is $58.50

A 15 kg box is pushed with a force of 35 N in the +x direction, and the box accelerates to the right. It does not accelerate up or down

Answers

The box accelerates to the right due to the applied force of 35 N in the +x direction.

Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:

acceleration = net force / mass

acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)

Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.

Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.

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messier 74 (m74), nicknamed the phantom galaxy, is a grand design spiral galaxy located in the constellation pisces. it can be found 1.5 degrees east-northeast of , the brightest star in pisces. g

Answers

It's called the Phantom because the galaxy's surface brightness is low.

Because of the galaxy's low surface brightness, it is known as the Phantom. Of all the Messier objects that amateur astronomers view using tiny telescopes, it is the most challenging to locate. The galaxy almost faces Earth, which accounts for the low surface brightness.

M74 is a star in the constellation Pisces that is around 32 million light-years from Earth. Through modest telescopes, the galaxy appears as a dim patch of light with an apparent magnitude of only 10. The ideal time to view it is around November. A spiral galaxy with a majestic pattern, M74 is the ideal illustration.

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A meterstick of negligible mass is placed on a fulcrum at the 0.4 m mark, with a 1 kg mass hung at the zero mark and a 0.5 kg mass hung at the 1.0 m mark. The meterstick is held horizontal and released. Immediately after release, the magnitude of the net torque on the meterstick about the fulcrum is most nearly:________

a. 1 Nm
b. 2 Nm.
c. 2.5 Nm.
d. 7 Nm
e. 7.5 Nm

Answers

Answer:

The net torque is 0.98 Nm.

Explanation:

The torque is given by

Torque = force x perpendicular distance

The clock wise torque is taken as negative while the counter clock wise torque is taken as positive.

Take the torques about the fulcrum.

Torque =  1 x 9.8 x 0.4 - 0.5 x 9.8 x 0.6

Torque = 3.92 - 2.94 = 0.98 Nm

A meterstick of negligible mass is placed on a fulcrum at the 0.4 m mark, with a 1 kg mass hung at the

A uniform solid cylindrical log begins rolling without slipping down a ramp that rises 28.0° above the horizontal. After it has rolled 4.20 m along the ramp, what is the magnitude of the linear acceleration of its center of mass?

Answers

Answer:

3.07 m/s

Explanation:

The magnitude of the linear acceleration will be "3.07 m/s²".

Given:

Angle, \(\Theta = 28^{\circ}\)Length = 2.40 m

The acceleration of its center of mass will be:

= \(\frac{2}{3}g Sin \Theta\)

By putting the above given values, we get

= \(\frac{2}{3}\times 9.8 Sin 28^{\circ}\)

= \(\frac{2}{3}\times 9.8\times 0.46\)

= \(\frac{9.0167}{3}\)

= \(3.07 \ m/s^2\)

Thus the solution above is appropriate.

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Victor covers 210 km by car at a speed of 70 km/hr. find the time taken to cover this distance.

Answers

Answer:

3 hrs

Explanation:

the distance covered by victor= 210 km

speed= 70 km/hrs

so, 70×3= 210

so the answer is 3 hrs

BTW im a small kid so don't just right away say the explanation sucks and the subject physics is not yet started in my grade.

edit: don't give me brainless answer plz.

A teenager of mass m1 = 64 kg pushes backward against the ground with his foot as he rides his skateboard. This exerts a horizontal force of magnitude Ffoot = 13 N. The skateboard has m2 = 2.9 kg.

a. Write an expression for the magnitude of the horizontal component of force that the ground exerts on the teenager's foot, Fground.
b. Write an expression in terms of given quantities for the magnitude of the skateboard's acceleration, a, while the teenager is pushing backwards on the ground.
c. What is the numerical value for the magnitude of the acceleration, a, in m/s2?

Answers

We multiply the magnitude of the vector even by the cosine angle referenced towards the horizontal. The horizontal force defines as the force exerted inside a direction parallel to the horizon. Acceleration is merely the rate during which velocity changes. As a result, the magnitude indicates how rapidly velocity varies, and the further calculation can be defined as follows:

For option a:

\(\to F_{foot}= 13 \ N\\\\\to m_1= 64 \ kg\\\\\to m_2=2.9 \ kg\\\\\)

Please find the graph for the direction:

\(\to |F_{ground}|= |F_{foot}| \\\\ \to F_{ground}= -F_{foot}= - 13 \ N\\\\\)

For option b:  

\(F_{ground}=(m_1+m_2)a\\\\a=\frac{F_{ground}}{m_1+m_2}\\\\\)

For option c:  

\(\bold{a=\frac{13}{64+2.9}}\\\\\)

  \(\bold{=\frac{13}{66.9}}\\\\\bold{=0.194 \ \frac{m}{s^2}}\\\\\)

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A teenager of mass m1 = 64 kg pushes backward against the ground with his foot as he rides his skateboard.

A coke can that has been shaken and then opened

Answers

Answer:

will explod

Explanation:

Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)

Answers

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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Explain why synovial joints have greater flexibility than fixed and cartilaginous joint.

Answers

Unlike fixed joints or cartilaginous joints, where the bones are connected by either connective tissue or cartilage, the bones in synovial joints are not directly joined by anything, which allows for a much greater range of motion.

Answer:Unlike fixed joints or cartilaginous joints, where the bones are connected by either connective tissue or cartilage, the bones in synovial joints are not directly joined by anything, which allows for a much greater range of motion.

Explanation: I got a 100% on my test

A textbook of mass 1.93 kg
rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.190 m
, to a hanging book with mass 2.96 kg
. The system is released from rest, and the books are observed to move a distance 1.24 m
over a time interval of 0.770 s
.

Answers

The tensiοn οf the chοrd attached tο the hanging bοοk is 5.624 N

What happens when a bοdy mοves acrοss a frictiοnless hοrizοntal surface?

As an item travels οver a rοugh surface, frictiοnal fοrce is generated in the οppοsing directiοn οf mοtiοn. Because οf this antagοnism, the item cοmes tο a halt after a given distance. As a result, when an item mοves οver a frictiοnless surface, there is nο οppοsitiοn and nο unbalanced fοrce acting οn it, and it gοes equally.

The victim will thereafter be unable tο stand οr walk, making leaping difficult. As a result, yοu'll have tο fοrce sοmething οut οf yοur bοdy, and tοssing a chunk οf stοne is a better alternative.

The tensiοn οf the chοrd attached tο the hanging bοοk is calculated as fοllοws;

T = mg - ma

T = 3.1(9.8 - 2.96)

T = 21.2 N

T = ma

T = 1.9 x 2.96

T = 5.624 N

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Complete question:

A textbook of mass 1.90 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.190 m, to a hanging book with mass 2.96 kg. The system is released from rest, and the books are observed to move 1.24 m in 0.770 s. Part A What is the tension in the part of the cord attached to the textbook?

Express your answer with the appropriate units

Time (min)
3. A car accelerates at 2 m/s². Assuming the car starts from rest, how much time
does it need to accelerate to a speed of 16 m/s?[ t = (vi-vi//a ]

Answers

The initial velocity of the car is u = 0 m/s because the car starts from rest.

The acceleration of the car is a = \(2m/s^{2}\).

The instantaneous velocity is v = 16 m/s.

By applying the formula that connects the details that we have with the duration

a = v − u t

      t

we get the duration as follows

Make t the subject of the formula

    t = v − u

            a

=  16m/s− 0 m/s

      \(2M^{2}\)

= 8s.

The duration for that speed change is 8s.

Calculating acceleration involves dividing velocity by using time or in phrases of SI units, dividing the meter according to the second m/s by the second one. Dividing distance by time twice is the same as dividing distance via the rectangular of time. hence the SI unit of acceleration is the meter according to 2nd squared. If the acceleration is consistent, it's far viable to discover acceleration without time if we have the preliminary and final pace of the item as well as the amount of displacement. The system v2=u2+2as where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement is used.

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What does the slope represent? v^2/h = what variable?

Answers

Answer:

Slope measures the rate of change in the dependent variable as the independent variable changes.

Explanation:

27. The number of coils of wire through which a bar magnet is moved is increased. The
amount the needle on the meter is deflected

A. increases
B. decreases
C. shows no change
D. does not move at all

Answers

The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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An electrical circuit has a courent of 13A and 26 Ohm of resistance. What is voltage using the Ohm's law​

Answers

The voltage in the circuit is 338 Volts.

Ohm's law states that the voltage (V) in a circuit is equal to the current (I) multiplied by the resistance (R): V = I x R.

1. Identify the given values: In this problem, we are given the current (I) and resistance (R) in the circuit.

2. Recall Ohm's law:  V = I x R.

3. Substitute the given values: We can substitute the given values of current (I = 13A) and resistance (R = 26 Ohm) into Ohm's law to find the voltage (V).

4. Calculate the voltage: Using the equation V = I x R and substituting the values of current and resistance, we can calculate the voltage as V = 13A x 26 Ohm = 338 Volts.

Therefore,  The voltage in the circuit is 338 Volts.

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A gas expands from I to F in the figure. The energy added to the gas by heat is 465 J when the gas goes from I to F along the diagonal path. What is the change in internal energy of the gas?

Answers

The gas's internal energy that expands from I to F changes by 1015 J.

How to determine internal energy?

Since the gas is expanding and energy is added to it by heat, the change in internal energy of the gas can be calculated using the first law of thermodynamics, which states that:

ΔU = Q - W

where ΔU = change in internal energy,

Q = heat added to the system, 465 J and

W = work done by the system.

Assuming that the process is quasi-static use approximation known as the "staircase approximation."

By adding up the work done in each step, find that the total work done by the gas is approximately -550 J. The negative sign indicates that work is done on the gas.

Therefore, using the first law of thermodynamics, we can calculate the change in internal energy of the gas as:

ΔU = Q - W

ΔU = 465 J - (-550 J)

ΔU = 1015 J

Therefore, the change in internal energy of the gas is 1015 J.

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pls helpp
Heidi sees a bowl of apples sitting on a table. She knows that if no force acts on that bowl, it will stay right where it is. Which part of Newton's laws of
motion explains why the bowl will stay at rest?
A Objects at rest tend to stay at rest.
OB. Objects in motion tend to stay in motion.
OC. Every action has an equal and opposite reaction.
OD. Larger objects require greater amounts of force to move.

Answers

Objects at rest tend to stay at rest as per the Newton's laws of motion. The correct option is A.

What is Newton's laws of motion?

The basic three fundamental laws of classical mechanics referred to as Newton's laws of motion describe the ways in which an object's motion and the forces acting on it interact.

The first statement of Newton's laws of motion, which states that "Objects at rest tend to stay at rest, and objects in motion tend to stay in motion, with not only the same speed but also in the same direction.

It takes place unless acted upon by an external force," will lead the bowl of apples to remain at rest.

This rule, often known as the law of inertia, holds that unless an outside force acts upon an object, it will continue to move uniformly in a straight line or be at rest. Since no force is operating on the bowl of apples, it will continue to be at rest.

Thus, the right response is A.

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Charge q1 is distance r from a positive point charge Q. Charge q2=q1/3 is distance 2r from Q. What is the ratio U1/U2 of their potential energies due to their interactions with Q?

Charge q1 is distance s from the negative plate of a parallel-plate capacitor. Charge q2=q1/3 is distance 2s from the negative plate. What is the ratio U1/U2 of their potential energies?

Charge q1 is distance r from a positive point charge Q. Charge q2=q1/3 is distance 2r from Q. What is
Charge q1 is distance r from a positive point charge Q. Charge q2=q1/3 is distance 2r from Q. What is

Answers

We have that The ratio U1/U2 of their potential energies due to their interactions with Q is

\(U1/U2=6\)\(U1/U2=6\)

From the question we are told that

Question 1

Charge q1 is distance r from a positive point charge Q.

Question 2

Charge q2=q1/3 is distance 2r from Q.

Charge q1 is distance s from the negative plate of a parallel-plate capacitor.

Charge q2=q1/3 is distance 2s from the negative plate.

Generally the equation for the potential energy  is mathematically given as

\(U=\frac{-k*qQ}{r}\)

Therefore

The Equations of U1 and U2 is

For U1

\(U1=\frac{-k*q_1Q}{r}\)

For U2

\(U2=\frac{-k*q_1Q}{3*2r}\)

Since

U is a function of q and  q2=q1/3

Therefore

\(U1/U2=6\)

For Question 2

For U1

\(U1=\frac{-k*q_1Q}{s}\\\\For U2\\\\U2=\frac{-k*q_1Q}{3*2r}\)

Therefore

\(U1/U2=6\)

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How does the force of gravity change as the mass of one object doubles?

Answers

If the mass of one of the objects is doubled, then the force of gravity between them is doubled. ... Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.

The force of gravity changes as the mass of one object doubles. As the mass of one object is doubled then the force between the objects also gets doubled.

What is Force?

Force is an influence which can change the motion of an object through the application of an external force. A force can cause an object with the mass to change its velocity, that is the object undergo acceleration.

Force is directly proportional to the mass of the object and the acceleration of the object. If we double the mass of one of the objects, then we double the strength of the force. If we double the masses of both the objects, then we quadruple the strength of force.

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A zebra is running at 80 kmh in front of a lion that is moving with 100 km h. If the zebra is 15 km ahead of lion, how long (in minutes) it
takes for the lion to catch the zebra if their velocities remain unchanged?

Answers

Answer: 45 minutes

Explanation:

hope this helps!

An airbys A380 airliner lands at 30 m/s. Partially loaded, its mass is 480000 kg. The engines apply reverse thrust for 12s to slow the plane to 25 m/s.How much thrust did the engines apply?

Answers

To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.

First, we calculate the change in velocity (∆v):

\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)

Next, we calculate the acceleration (∆a) using the formula:

\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)

where ∆t is the change in time, which is 12 seconds in this case.

\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)

Now, we can determine the force (thrust) applied by the engines using Newton's second law:

\(\displaystyle\sf F=m\cdot a\)

where m is the mass of the airplane, which is 480000 kg.

\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)

Calculating the result:

\(\displaystyle\sf F=-200000\,N\)

Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.

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