Omar observes that many buildings in his city were built using limestone. He has read that acid rain can damage limestone. He also knows that limestone reacts with acids and that chemical reactions are affected by temperature. With this in mind, he conducts an investigation to see how the amount of damage to the limestone is affected by the amount of acid on the stone.
Which statement describes the correct plan for his procedure?Rhonda watched a video taken by a camera that was lifted into the upper atmosphere by a weather balloon. She saw the balloon pop when it reached a certain height. Afterward, Rhonda wondered what effect the air pressure at high altitudes has on the volume of gas in balloons.
What scientific practice is Rhonda performing
Answers
Answer:he conducts the investigation to see the effect acidic water has on limestone
Explanation:
Related Questions
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?
Answers
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.
To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).
The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:
E_initial = KE_initial + PE_initial
The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:
E_final = KE_final + PE_final
The nonconservative work done on the boy is equal to the change in mechanical energy:
Work_nonconservative = E_final - E_initial
Let's calculate each term:
KE_initial = (1/2) * m * v_initial^2
= (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = m * g * h_initial
= 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * m * v_final^2
= (1/2) * 66.1 kg * (8.51 m/s)^2
PE_final = m * g * h_final
= 66.1 kg * 9.8 m/s^2 * 0
Since the boy ends at ground level, the final potential energy is zero.
Substituting the values into the equation for nonconservative work:
Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)
Simplifying:
Work_nonconservative = KE_final - KE_initial - PE_initial
Calculating the values:
KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2
Substituting the values:
Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]
Calculating the result:
Work_nonconservative ≈ -42.7 kJ
Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.
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Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next
Answers
Answer: Hope this helps ;) don't forget to rate this answer !
Explanation:
There are two correct answers:
A) A corporation leader makes direct payment to the candidate.
D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.
Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.
Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.
I hope this helps! Let me know if you have any other questions.
What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m
Answers
The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.
In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.
When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.
For example, if the answer is 12.345, we would round it to 12.3.
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I want to know about the inventions caused due to rain. Like the Benjamin Franklin's Lightning Conductor. I have to make a chart.
Answers
He had his materials at the ready: a simple kite made with a large silk handkerchief, a hemp string, and a silk string. He also had a house key, a Leyden jar (a device that could store an electrical charge for later use), and a sharp length of wire. His son William assisted him.
Franklin had originally planned to conduct the experiment atop a Philadelphia church spire, according to his contemporary, British scientist Joseph Priestley (who, incidentally, is credited with discovering oxygen), but he changed his plans when he realized he could achieve the same goal by using a kite.
The speed of sound is measured to be 340 m/s on a certain day.
What is this in Kilometers per hour?? s/km/h=
Please help and explain how to do these types of problems in very confused!!!
Answers
Explanation:
To do this, we pick the first unit and convert
Picking m first and converting to km:
Since we're converting from a non-prefix to a prefix, we divide the value by the prefix were taking it to. In this case, kilo = 10³ which means we're going to divide our value by 1000 to convert it from m to km
340 m/s ÷ 1000 = 0.34 km/s
Now, let's convert our seconds to hour:
We'll need to calculate how many hours is equivalent to one second first;
1 hr = 60×60 seconds
X hr = 1 second
*Cross multiply*
1 × 1 = X × 60 × 60
1 = 3,600 X
X = 1 / 3,600
X = 2.778×10⁻⁴ hour
So, in the place of "1 Second", we're going to be inserting 2.778×10⁻⁴ hour instead
0.34 km / s = 0.34 km / 2.778×10⁻⁴ hour
(0.34 / 2.778×10⁻⁴) km/hour
1,224 km/h.
340 m/s = 1,224 km/h
Who pioneered the use of galvanoplastic compounds for preserving footprints and ballistics?
A.
Mathieu Orfila
B.
Calvin Goddard
C.
Edmon Locard
D.
Alphonse Bertillon
E.
Dr. Joseph Bell
Answers
Answer:
Option D (Alphonse Bertillon) is the correct response.
Explanation:
He seems to have been a policeman turned biometrics expert from France. Forensic techniques such as forensic record analysis were developed by Bertillon. To retain proof, he always pioneered or developed the use of such galvanoplastic compounds as molds for footsteps as well as ballistics. To research physical changes with age, Bertillon has developed a method focused on images of almost the same person’s performance.All those other choices weren’t connected to the instance offered. So, the best one is the one described.
jose has a mass of 70 kg, what is his weight
Answers
The input and output forces for four machines are shown in the table. Machine Forces Machine Input Force (N) Output Force (N) 1 5 50 2 10 50 3 25 50 4 50 50 Which machine would have the greatest mechanical advantage? Responses 1 1 2 2 3 3 4
Answers
Machine 1 has the greatest mechanical advantage among the given machines. To determine the machine with the greatest mechanical advantage, we need to calculate the mechanical advantage for each machine.
Machine 1: Mechanical Advantage = Output Force / Input Force = 50 N / 5 N = 10
Machine 2: Mechanical Advantage = Output Force / Input Force = 50 N / 10 N = 5
Machine 3: Mechanical Advantage = Output Force / Input Force = 50 N / 25 N = 2
Machine 4: Mechanical Advantage = Output Force / Input Force = 50 N / 50 N = 1
Comparing the mechanical advantages, we can see that Machine 1 has the highest mechanical advantage of 10. This means that Machine 1 can multiply the input force by 10 to produce the output force. It provides the greatest amplification of force among the four machines.
Machine 2 has a mechanical advantage of 5, Machine 3 has a mechanical advantage of 2, and Machine 4 has a mechanical advantage of 1. Therefore, Machine 1 has the greatest mechanical advantage among the given machines.
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A machine part consists of three heavy disks linked by struts of negligible weights as shown in the figure. Calculate the moment of inertia of the body about an axis through the centre of disk A and the kinetic energy, if the body rotates about an axis through A perpendicular to the plane of the diagram, with angular speed ω = 6.0 rads-1..
Answers
if the values of mass (m) and radius (R) are provided, the moment of inertia of the body about an axis through the center of disk A can be calculated as (3/2) * m * R^2, and the kinetic energy of the rotating body would be 162 * m * R^2 Joules.
To calculate the moment of inertia of the body about an axis through the center of disk A, we need to consider the moment of inertia contributions from each individual disk and add them up.
Let's denote the moment of inertia of each disk as I_A, I_B, and I_C, respectively. The moment of inertia of a disk rotating about its center can be calculated using the formula:
I = (1/2) * m * r^2
Where m is the mass of the disk and r is its radius.
Since the struts have negligible weight, we can assume that each disk has the same mass.
Let's assume the mass of each disk is m and the radius of each disk is R.
The moment of inertia of disk A (I_A) is given by:
I_A = (1/2) * m * R^2
The moment of inertia of disk B (I_B) and disk C (I_C) will be the same since they have the same mass and radius:
I_B = I_C = (1/2) * m * R^2
The total moment of inertia of the body about the axis through the center of disk A (I_total) is the sum of the individual moment of inertias:
I_total = I_A + I_B + I_C
= (1/2) * m * R^2 + (1/2) * m * R^2 + (1/2) * m * R^2
= (3/2) * m * R^2
To calculate the kinetic energy of the rotating body, we can use the formula:
Kinetic Energy = (1/2) * I_total * ω^2
Substituting the given values:
Kinetic Energy = (1/2) * ((3/2) * m * R^2) * (6.0 rad/s)^2
Simplifying further, if the values of m and R are given, we can calculate the moment of inertia and kinetic energy.
Assuming that the values of mass (m) and radius (R) are given, we can calculate the moment of inertia (I_total) and kinetic energy.
For the given values of ω = 6.0 rad/s and the previously calculated I_total:
I_total = (3/2) * m * R^2
Kinetic Energy = (1/2) * I_total * ω^2
= (1/2) * [(3/2) * m * R^2] * (6.0 rad/s)^2
= (9/2) * m * R^2 * (36.0 rad^2/s^2)
= 162 * m * R^2 Joules
Therefore, if the values of mass (m) and radius (R) are provided, the moment of inertia of the body about an axis through the center of disk A can be calculated as (3/2) * m * R^2, and the kinetic energy of the rotating body would be 162 * m * R^2 Joules.
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is the average speed is 60 kilometers per hour and the trip lasts 6 hours what is the total distance covered?
Answers
Answer:
\(d = 60(km. {hr}^{ - 1} ) \times 6(hr) = 360km = 36 \times {10}^{4} m\)
An astronaut standing on a platform on a foreign planet drops a hammer. If the hammer falls 9.0 meters vertically in 2.5 seconds, what is the acceleration due to gravity on that planet?
Answers
Answer: 1.646 m/s²
Explanation:
The distance that is traveled by the astronaut given that the motion is free-fall can be calculated through the equation,
d = Vot + 0.5at²
where d is the distance, Vo is the initial velocity, t is the time, and a is the acceleration. Substituting the known,
6 = (0 m/s)(2.7 s) + 0.5(a)(2.7 s)²
Determining the value of a,
a = 1.646 m/s²
4. A 50.0-kg homogeneous beam supports a mass of 15.0 kilograms,as shown. The center of gravity of the beam is at the midpoint ofthe beam. Find the magnitude of the tension, T, in the rope.D. 0.01 10
Answers
First let's find the tension generated by the mass of 15 kg.
We can use the following formula to find this tension component:
\(\begin{gathered} T_{y1}=m\cdot g\cdot\sin (\theta) \\ T_{y1}=15\cdot9.81\cdot\sin (37\degree) \\ T_{y1}=15\cdot9.81\cdot0.602 \\ T_{y1}=88.58\text{ N} \end{gathered}\)Now, to find the tension generated by the beam, first let's find the angle from the connection point of the rope with the wall and the center of gravity of the beam:
\(\begin{gathered} \tan (37\degree)=\frac{x}{5} \\ 0.754=\frac{x}{5} \\ x=3.77 \\ \\ \tan (\theta)=\frac{x}{2.5} \\ \tan (\theta)=\frac{3.77}{2.5} \\ \text{tan(}\theta)=1.508 \\ \theta=56.45\degree \end{gathered}\)Now, let's use the same formula we used in the beggining:
\(\begin{gathered} T_{y2}=m\cdot g\cdot\sin (\theta) \\ T_{y2}=50\cdot9.81\cdot\sin (56.45\degree) \\ T_{y2}=50\cdot9.81\cdot0.833 \\ T_{y2}=408.59 \end{gathered}\)Adding both tensions, we have:
\(\begin{gathered} T=T_{y1}+T_{y2} \\ T=88.58+408.59 \\ T=497.17 \end{gathered}\)
SI unit differ from one country to another . true or false
Answers
Answer:
false ..........false
Answer:
FALSE
Explanation:
An 80 kg running back used 2560 Joules to run to the end zone. what was his velocity
Answers
The velocity of the running back is 8 m/s.
To calculate the velocity of the running back, we can use the work-energy principle. The work-energy principle states that the work done on an object will be equal to the change in its kinetic energy.
Given; Mass of the running back (m); 80 kg
Work done (W); 2560 Joules
We can use the formula for kinetic energy;
KE = 0.5 × m × v²
where KE is the kinetic energy, m is the mass, and v is the velocity of the running back.
According to the work-energy principle, the work done is equal to the change in kinetic energy;
W = KE - KE0
where KE0 is the initial kinetic energy.
Rearranging the formula for kinetic energy, we get;
KE = 0.5 × m × v²
Substituting the given values, we get;
2560 = 0.5 × 80 × v²
Solving for v;
v² = (2 × 2560) / 80
v² = 64
v = √(64)
v = 8 m/s
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T or F A red-hot object is hotter than one that is while-hot?
Answers
Answer:
True. The two laws of thermal radiation state; 1) "Each square meter of a hotter object
Explanation:
Earth rotate once every 24 hours. In a reference frame fixed to Earth, how far does
a point on the equator move in 1 hour? RE = 6.34×106 m
Answers
In a reference frame fixed to Earth, a point on the equator moves zero distance in 1 hour.
What is the frame of reference?A frame of reference in physics is made up of an abstract coordinate system and the collection of physical reference points that fix the coordinate system specifically and regulate measurements inside it.
When we take a reference frame fixed to Earth, the displacement due to earth's rotation can not be measured. So, any point on earth remains in rest through out the day with respect to the reference frame fixed to Earth. Hence, a point on the equator moves no distance in 1 hour in a reference frame fixed to Earth.
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5. A car is traveling at 20 0 m/s when the driver sees a child standing in the road. The
driver takes8 s to react, then steps on the brakes and slows at 5.0 ms. Once the
brakes are pressed, the car stops in an additional 4 seconds. How far does the car
travel before it stops from when the driver sees the child?
Help please !!
Answers
We know that
• The initial velocity is 20 m/s.
,• The acceleration is -5 m/s^2.
,• The final velocity is zero because it stops.
,• The time spent to stop is 4 seconds.
Let's use the following formula.
\(v^2_f=v^2_0+2ad\)Using the given magnitudes, we have
\(0=20^2+2(-5)d\)Let's solve for d.
\(\begin{gathered} 0=400-10d \\ -400=-10d \\ d=\frac{-400}{-10} \\ d=40m \end{gathered}\)Therefore, the car stops 40 meters away after stepping on the brakes.Thermal expansion of a gas causes a change in the ____ of the gas.
A. Radioactiveness
B. Density
C. Mass
D. Altitude
Answers
Answer:
B. Density
Explanation:
Thermal expansion of a gas will cause a definite change in the density of the gas.
It is product of an increase in the average kinetic energy of the system in which molecules are found.
Gaseous thermal expansion will increase the volume in which gases occupy. Mass of the gas will still remain the same. Since density is the mass per unit volume, as the gases expand, their density reduces more and more.Therefore, thermal expansion of gas will cause a change in the density of the gas.
a. If the frequency of light is increased above the threshold frequency, the
energy of the electrons emitted will _________________.
b. If the frequency of light is decreased to below the threshold frequency, the
rate at which electrons are emitted will _______________.
c. If the intensity of light is decreased, the energy of the electrons emitted will ____________________.
d. If the intensity of light is decreased, the rate at which electrons are emitted will ________________.
Answers
b. If the frequency of light is decreased to below the threshold frequency, the rate at which electrons are emitted will decrease.
c. If the intensity of light is decreased, the energy of the electrons emitted will remain the same.
d. If the intensity of light is decreased, the rate at which electrons are emitted will decrease.
Answer:
a. If the frequency of light is increased above the threshold frequency, the energy of the electrons emitted will increase.
b. If the frequency of light is decreased to below the threshold frequency, the rate at which electrons are emitted will decrease.
c. If the intensity of light is decreased, the energy of the electrons emitted will remain the same, but fewer electrons will be emitted.
d. If the intensity of light is decreased, the rate at which electrons are emitted will decrease.
The girl in the diagram is accelerating down the hill. What is the girl's acceleration?
m = 50kg
f net = 150 N right
(Hint: Use the formula a=\frac{F}{m}a= m F.)
A. a = 3 m/s2 A. is correct.
B. a = 5 m/s2
C. a = 150 m/s2
D. a = 6 m/s2
Answers
Answer:
150÷50=3 and the answer is letter Awhen a58g tennis ball is served.it accelerate from rest to aspeed of 45m/s.the impact with the racket gives the ball acontant acceleration over adistance of44cm.what is the magnitude of the net force acting on the ball?
Answers
Answer: We first calculate the acceleration on the ball using:
2as = v² - u²; u = 0 because ball is initially at rest
a = (36)²/(2 x 0.35)
a = 1850 m/s²
F = ma
F = 0.058 x 1850
= 107.3 Newtons
Explanation:
The type of spectrum is produced when electromagnetic radiation is emitted or absorbed as electrons change energy levels is an atom is ..
Answers
76. Two electric charges -6μC and
+6μC are placed respectively in two
points A and B distant of 1m apart. The
electric field is null at the point C:
A.Located in the middle of the
segment AB
B.Located outside segment AB at
1m from A.
C.Located outside segment AB at
1m from B
D.Outside the line AB
E.No answer is right.
Answers
A. The electric field is null at the point C; located in the middle of the
segment AB.
What is electric field?Electric field is the region of space where the influence of electric force is felt.
Electric field at the middle of ABE = kq/r²
where;
r is the middle of AB = 0.5 mE(+6μC) = (9 x 10⁹ x 6 x 10⁻⁶) / (0.5²)
E(+6μC) = +216,000
E(-6μC) = (9 x 10⁹ x 6 x 10⁻⁶) / (0.5²)
E(-6μC) = -216,000
Sum of the electric field at the middle of ABE(net) = E(+6μC) + E(-6μC)
E(net) = 216,000 - 216,000 = 0
Thus, the electric field is null at the point C; located in the middle of the
segment AB.
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Use the graph to answer the following questions.
Answers
Answer:
8a = 20. 8b=4
Explanation:
Distance is total amount the object moved. It went from 10, to -2 which is 12 meters away, then to 6 which is 8, adding 8 and 12 is 20 so that is the distance. Displacement is how far it is relative to the starting position, so 10 and 6 are 4 meters away, therefore displacement is 4.
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Question 4 of 10
Which of the following describes the reactants of a chemical reaction?
OA. The chemicals on the right side of a chemical equation
B. The substances that are formed
OC. The substances that are made
O D. The chemicals on the left side of a chemical equation
Answers
The substances that are altered and the chemicals on the right side of a chemical equation are the results of a chemical reaction. B and D are the appropriate choices.
Reactants are the substance(s) in a chemical equation to the left of the arrow. A component that is present at the outset of a chemical reaction is known as a reactant. Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product. The creation of products from the reaction of two reactants is known as a chemical reaction. The compounds that result from a reaction are called products. The substances that are original materials are the reactants.
On the left side of the reaction are the reactants, and on the right are the products. B and D are the proper choices as a result.
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A roller-coaster car has a mass of 1240 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 22 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car from the track if the car's speed is v = 8.7 m/s? (b) What is FN if v = 20 m/s? Use g=9.81 m/s2.
Answers
Answer:
a) N = 7.90 10³ N, b) N = -1.04 10⁴ N
Explanation:
a) For this exercise we can use Newton's second law
N -W = m (-a)
The relationship is centripetal, the negative sign of the acceleration is because it points towards the center of the circle
a = v² / r
we substitute
N = mg -m v² /r
N = m (g - v² /r)
let's calculate
v = 8.7 m / s
N = 1240 (9.81 - 8.7²/22)
N = 7.90 10³ N
b) v = 20 m / s
N = 1240 (9.81 - 20²/22)
N = -1.04 10⁴ N
Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 8.01 nC, and the other has a charge of 4.22 nC.
Answers
a. The magnitude of the electric force that one particle exerts on the other is 1.72 millinewtons (mN). and b. the force is repulsive
To calculate the magnitude of the electric force between two charged particles, we can use Coulomb's Law, which states that the magnitude of the electric force (F) between two charged objects is given by:
F = k * (|q1| * |q2|) / r^2
where k is the electrostatic constant (k = 8.99 x 10^9 N·m^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.
Given:
q1 = 8.01 nC (nanocoulombs)
q2 = 4.22 nC (nanocoulombs)
r = 1.72 m
Converting the charges to coulombs:
q1 = 8.01 x 10^-9 C
q2 = 4.22 x 10^-9 C
Plugging the values into Coulomb's Law:
F = (8.99 x 10^9 N·m^2/C^2) * ((8.01 x 10^-9 C) * (4.22 x 10^-9 C)) / (1.72 m)^2
Calculating the magnitude of the force:
F ≈ 1.72 x 10^-3 N
Therefore, the magnitude of the electric force that one particle exerts on the other is approximately 1.72 millinewtons (mN).
To determine if the force is attractive or repulsive, we need to consider the signs of the charges. If the charges have opposite signs (one positive and one negative), the force is attractive. If the charges have the same sign (both positive or both negative), the force is repulsive.
In this case, both charges are positive, so the force between them is repulsive. The particles will experience a repelling force due to their like charges, causing them to push away from each other.
The question was incomplete. find the full content below:
Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 8.01 nC, and the other has a charge of 4.22 nC.
(a) What is the magnitude (in N) of the electric force that one particle exerts on the other?
(b) Is the force attractive or repulsive?
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How have astronomers used models to explain galactic evolution through mergers and collisions? Use this model to explain how astronomers might test their understanding of the physical processes of the universe.
Answers
Answer:
Astronomers use computer models to simulate the process of galactic evolution through mergers and collisions. These models are based on our current understanding of the physical laws that govern the behavior of matter and energy in the universe. By running simulations of galactic mergers and collisions, astronomers can test their understanding of how these physical processes work in practice and how they contribute to the formation and evolution of galaxies.
One way that astronomers might test their understanding of the physical processes of the universe is by comparing the predictions of their models to observations of real galaxies. For example, if a model predicts that a particular type of galaxy should have a certain shape, size, or distribution of stars, astronomers can compare these predictions to observations of actual galaxies to see if they match up. If there is a discrepancy between the model's predictions and the observations, this can indicate that there are some physical processes that are not well understood or included in the model.
Another way that astronomers might test their understanding is by looking for patterns or trends in the properties of galaxies that are consistent with the predictions of their models. For example, if a model predicts that galaxies that have undergone a recent merger should have a particular distribution of gas and dust, astronomers can look for evidence of this pattern in observations of real galaxies. If they find that the predicted pattern is consistently observed in a large sample of galaxies, this can provide support for the model's predictions and the physical processes that it includes.
Overall, computer models of galactic evolution through mergers and collisions provide a powerful tool for astronomers to test their understanding of the physical processes of the universe. By comparing the predictions of their models to observations of real galaxies and looking for consistent patterns and trends, astronomers can refine their understanding of how galaxies form and evolve over time.
A student sits on a rotating stool holding two
3 kg objects. When his arms are extended
horizontally, the objects are 1 m from the
axis of rotation, and he rotates with angular
speed of 0.64 rad/sec. The moment of inertia
of the student plus the stool is 8 kg m2
and
is assumed to be constant. The student then
pulls the objects horizontally to a radius 0.3 m
from the rotation axis.
Answers
part A. The final angular speed of the student is 1.28 rad/s.
part B. The change in kinetic energy of the system is 7.04 J.
How do we calculate?We have that the moment of inertia of the system is assumed to be constant, we then write:
Iω = I'ω'
The moment of inertia of the objects is written in the form of :
I_objects = 2MR^2
Therefore, the initial moment of inertia is gotten as:
I = M_student R_stool^2 + 2MR^2
The final moment of inertia is gotten as:
I' = M_student R_stool^2 + 2M(0.3)^2
The angular momentum is conserved, we ten have:
Iω = I'ω'
Solving for ω', we get:
ω' = (Iω)/(I') = ω (I/I')
ω' = 0.64 rad/s (M_student R_stool^2 + 2MR^2) / (M_student R_stool^2 + 2M(0.3)^2)
ω' = 1.28 rad/s
part b.
The initial kinetic energy is
K = 1/2 I ω^2
K = 1/2 (8 kg m^2) (0.64 rad/s)^2 = 1.6384 J
The final kinetic energy is given by:
K' = 1/2 I' ω'^2
K' = 1/2 (8 kg m^2 + 2(3 kg)(0.3 m)^2) (1.28 rad/s)^2 = 8.6784 J
The change in kinetic energy is therefore calculated as:
ΔK = K' - K = 8.6784 J - 1.6384 J = 7.04 J
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prepare a report on why a vehicle needs to be maintained/serviced after a certain period of time. How is servicing different in a petrol/diesel and electric vehicle?
Answers
Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.
Why should cars be maintained and / or serviced ?First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.
The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.
This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.
Find out more on servicing cars at https://brainly.com/question/30700999
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