number of parameters 0/1 point (graded) for the following set of questions, let us consider generating documents that are english letter sequences (assume no spaces or punctuation), i.e. the vocabulary is made up of all the letters in the english alphabet. we would like to generate documents using this vocabulary using a multinomial model . as described in the lecture, what is the minimal number of parameters that the model should have? enter your answer below.

7 is what percent of 90

Let us put it as an equation

7 = x% * 90

Is means = and of means times

You must change x% to normal value by divide x by 100

Now we will solve the equation

Multiply both sides by 100 to cancel the denominator in the right side

To find x divide both sides by 90

x = 7.8

7 is 7.8% of 90

Answer:

Yes, d = 7, 32, 39, 46

Step-by-step explanation:

You can see each time it goes up by 7, meaning it is arithmetic.

The sequence would be: 4, 11, 18, 25, 32, 39, 46

Step-by-step explanation:

Ima just answer this to getpoints

Answer:.

Answer:1.we have dividend =divisor*quotient+remainder=

(x²+2x-1)(x²-2x+1)+(-4x+1)

=x²(x²-2x+1)+2x(x²-2x+1)-1(x²-2x+1)-4x+1

=x⁴-2x³+x²+2x³-4x²+2x-x²+2x-1-4x+1

=x⁴-4x²

Dividend is x⁴-4x².

2.

Multiplier is a-a²+1.

Answer:

\(i \: hope \: the \: above \: picture \\ helps\)

\(have \: a \: nice \: day \: \)

\(#Liliflim\)

Answer:

19/40 OR 0.475 OR 47.5%

Step-by-step explanation:

The probability of an event is calculated by dividing the total number of 'favorable outcomes' by the number of total outcomes. Here, the number of 'favorable outcomes' is the number of students who play tennis, so 19. The total number of outcomes is 40 as there are 40 students. Therefore the probability a student plays tennis is 19/40, or 0.475 or 47.5%.

Hope this helped!

The term that describes an event that increases the likelihood of a response being repeated is known as reinforcement.

Reinforcement can be defined as any consequence that strengthens or increases the probability of a behavior occurring again in the future. This can include positive reinforcement, which involves adding a desirable consequence after a behavior, or negative reinforcement, which involves removing an aversive consequence after a behavior. Both types of reinforcement have been shown to be effective in increasing the likelihood of a behavior being repeated.

Overall, understanding the concept of reinforcement is essential in the field of psychology, particularly in the areas of behaviorism and behavior modification. By providing positive consequences after desired behaviors, individuals can be motivated to continue engaging in those behaviors, which can lead to long-term positive changes. Reinforcement can also be used to shape new behaviors or replace unwanted behaviors with more desirable ones.

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Anaswer Let the height of the tree be  

y

ft. By condition;  

tan

38

=

y

43

or

y

=

43

tan

38

or

y

=

33.6

ft [Ans]

Step-by-step explanation:

Answer:

Step-by-step explanation:

The CORRECT answer is

C. 32.8 feet Got it correct

By solving the quadratic equations,

It will take the ball 1 second to reach 18 feet

It will take the ball 1.71 seconds to be at 10 feet

It will take the ball 2.06 seconds to hit the ground

From the question, we are to determine how long it would take the ball to reach 18 feet

To determine how long it would take the ball to reach 18 feet, we will set h = 18 in the equation

The given equation is

h = -16t² + 32t + 2

Put h = 18

18 = -16t² + 32t + 2

Rearrange

16t² - 32t - 2 + 18 = 0

16t² - 32t + 16 = 0

16t² - 16t - 16t + 16 = 0

16t(t - 1) -16(t - 1) = 0

(16t - 16)(t - 1) = 0

16t - 16 = 0 OR t - 1 = 0

16t = 16 OR t = 1

t = 16/16 OR t = 1

t = 1 OR t = 1

Hence,

t = 1 second

Hence, it will take the ball 1 second to reach 18 feet

To determine how long it will take the ball to reach 10 feet, we will set h = 10

h = -16t² + 32t + 2

Put h = 10

10 = -16t² + 32t + 2

Rearrange

16t² - 32t - 2 + 10 = 0

16t² - 32t + 8 = 0

Using the quadratic formula,

t = 0.29 second OR t = 1.71 seconds

The ball will hit the ground when h = 0

Set h = 0 in the equation

h = -16t² + 32t + 2

0 = -16t² + 32t + 2

16t² - 32t - 2 = 0

Using the quadratic formula,

t = -0.06 OR t = 2.06

Since t cannot be negative,

t = 2.06 seconds

Hence, it will take 2.06 seconds for the ball to hit the ground

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It is not possible to determine which data set has a higher standard deviation without computing it.

Without computing the standard deviation, it is impossible to determine which data set has a higher standard deviation. The rationale behind this is that the standard deviation is a measure of the dispersion or spread of data points around the mean. It takes into account the individual values and their distances from the mean. Therefore, to compare the standard deviations of two data sets, we need to consider the actual values in each set and how they vary from the mean. This information is not provided in the question, so we cannot make a definitive comparison without computing the standard deviations.

To verify which data set has a higher standard deviation, we would need to calculate the standard deviations of both sets by hand or using a statistical software. This involves finding the mean of each data set, then calculating the differences between each value and the mean, squaring those differences, averaging them, and taking the square root. By performing these calculations, we can determine the precise standard deviation for each set and compare them to identify the one with the higher value.

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Answer: 141.3cm^3

Step-by-step explanation:

Pi((3)^2)(-5)

Pi(9)(5)

Pi(45)

3.14×45

141.3

The given statement "context switching is required by all preemptive algorithms " is False.

Context switching is not required by all preemptive algorithms. Preemptive algorithms allow the operating system to interrupt the currently executing process and switch to another process.

Context switching involves saving the state of the currently running process and restoring the state of the next process to be executed. While context switching is a common mechanism in preemptive scheduling algorithms, there are non-preemptive algorithms that do not require context switching as they allow processes to run until they voluntarily release the CPU.

So, the statement that context switching is required by all preemptive algorithms is false.

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The length of the shorter leg is 16 units which was found using the given data.

A quadratic equation is a second-degree algebraic equation in x. In its usual form, the quadratic equation is ax² + bx + c = 0.

Given: The larger leg of a right triangle is twice more than three times the shorter leg, and the triangle's area is 400.

We know that,

Area of triangle = 1/2(larger leg)(shorter leg)

                  400=1/2(larger leg)(shorter leg)   Equation(1)

larger leg = 2 + 3(shorter leg)

We need to substitute this in Equation(1)

400 = 1/2[2+3(shorter leg)](shorter leg)

800 = 2(shorter leg) + 3(shorter leg)²

3(shorter leg)² + 2(shorter leg) - 800 = 0

Solving this quadratic equation,

we get, shorter leg = - 16 or +16

Thus, we found that the length of the shorter leg is 16 units as -16 cannot be the length because it is negative.

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Answer:

16

Step-by-step explanation:

\((-64)^2/3\)

64 = \(2^{6}\)

\(2^{6} ^{\frac{1}{3} } ^{2}\)

\(2^{ 2^{2} }\)

\(2^{4}\)

16

The equation of the graphed function is given as follows:

f(x) = x³ + 2x² - 5x - 6.

The equation of the function is obtained considering the Factor Theorem, as a product of the linear factors of the function.

From the graph, the zeros of the function are:

Hence the function is:

f(x) = a(x + 3)(x + 1)(x - 2).

In which a is the leading coefficient.

Expanding the product, we have that:

f(x) = a(x² + 4x + 3)(x - 2)

f(x) = a(x³ + 2x² - 5x - 6).

When x = 0, y = -6, hence the leading coefficient a is obtained as follows:

-6a = -6

a = 1.

Hence the function is:

f(x) = x³ + 2x² - 5x - 6.

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Answer:

x + 3y = 9

Step-by-step explanation:

The bacteria culture has an initial size of 79.7409

Given,

The count in a bacteria culture;

After 10 minutes is 400

After 30 minutes is 2000

Assume that the count grows exponentially;

We have to find the initial size of the culture;

Here,

The growth of population can be calculated using;

P = P₀ (1 + r)^t

Here,

Count of bacteria, P = 400 and 2000

Time period, t = 15 and 30

Initial size =  P₀

So,

400 = P₀ × (1 + r)¹⁰

2000 = P₀ × (1 + r)³⁰

Take P₀ common.

Then,

400/(1 + r)¹⁰ = 2000/(1 + r)³⁰

(1 + r)³⁰/ (1 + r)¹⁰ = 2000/400

(1 + r)¹⁰ = 5

1 + r = 1.175

r = 0.175

Now,

The value of P₀ should be determined from the above equation;

That is,

400 = P₀ × (1 + 0.175)¹⁰

P₀ = 400/ (1 + 0.175)¹⁰

P₀ = 79.7409

Therefore,

The initial size of the bacterial culture is 79.7409

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Answer:

30

Step-by-step explanation:

Answer:

x=5

y=-5.8

Step-by-step explanation:

4x-3x=1x

1x=5

x=5

8(5)-5y=11

40-5y=11

40-11=29

-5y=29

29/-5=-5.8

y=-5.8

The resulting dimensions of the acetal disk under a 30-kN load cannot be calculated without additional information about the material properties and deformation behavior.

To calculate the resulting dimensions of the acetal disk, we need to know its properties such as its modulus of elasticity, Poisson's ratio, and yield strength. Without this information, it is not possible to accurately calculate the resulting dimensions.

However, assuming that the acetal disk behaves as a linearly elastic material and that it does not yield under the applied load, we can use the following formula to calculate the resulting dimensions:

δ = PL/(Et^3π/16)

where δ is the deflection of the disk, P is the applied load, L is the diameter of the disk, t is the thickness of the disk, E is the modulus of elasticity, and ν is Poisson's ratio.

Assuming that the acetal disk has a modulus of elasticity of 2.8 GPa and a Poisson's ratio of 0.35, we can calculate the deflection of the disk as follows:

δ = (30 kN)(25 mm)/[(2.8 GPa)(5 mm)^3π/16] ≈ 0.021 mm

Therefore, the resulting dimensions of the acetal disk would be:

Diameter: 25 mm + 2δ ≈ 25.042 mm

Thickness: 5 mm - δ ≈ 4.979 mm

Note that these calculations are based on several assumptions and simplifications, and the actual resulting dimensions of the acetal disk may differ from these estimates. It is always important to consider the specific properties and behavior of the material being used in any mechanical loading device.

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Answer:

Step-by-step explanation:

Part (a)

\(C=\pi d \implies d=\frac{C}{\pi}\)

Part (b)

\(d=\frac{8}{\pi}\)

Step-by-step explanation:

Force = Mass × Acceleration

Hope it helps :)

★ As per newton's second law of motion, force is measured as the product of mass and acceleration\(.\)

F denotes force

m denotes mass

a denotes acceleration

➤ Force is a polar vector quantity as it has point of application.

It has both magnitude as well as direction.

Answer:

The formula for the volume of a hemisphere is V = (2/3)πr³. Solving for r, we get r = (3V/4π)^(1/3). Substituting V = 2507 in³, we get r ≈ 7.5 in. The diameter of a hemisphere is twice its radius, so the diameter of this hemisphere is approximately 15 inches to the nearest tenth of an inch.

Step-by-step explanation:

The conditional distribution of X given that the first two tosses both land Heads is:

P(X = 0 | HH) = 1

P(X = 1 | HH) = 2

P(X = 2 | HH) = 0

Given that the first two tosses both land Heads, the sample space is reduced to {HH, HT}. Therefore, X can take values 0, 1, or 2, with respective probabilities P(X = 0 | HH) = P(X = 0, HH) / P(HH), P(X = 1 | HH) = P(X = 1, HH) / P(HH), and P(X = 2 | HH) = P(X = 2, HH) / P(HH).

We have:

Probability of getting two heads in a row = P(HH) = 1/2 × 1/2 = 1/4

Probability of getting one head and one tail = P(HT) = 1/2 × 1/2 = 1/4

Now, if the first two tosses are both Heads, then we can only get the following: HH. Thus, the distribution of X is:

X = 0:

- Only one way, P(X = 0, HH) = 1/4

- Hence P(X = 0 | HH) = (1/4) / (1/4) = 1

X = 1:

- Only one way, P(X = 1, HH) = 2/4 = 1/2

- Hence P(X = 1 | HH) = (1/2) / (1/4) = 2

X = 2:

- No way, P(X = 2, HH) = 0

- Hence P(X = 2 | HH) = 0

Thus, the conditional distribution of X given that the first two tosses both land Heads is:

P(X = 0 | HH) = 1

P(X = 1 | HH) = 2

P(X = 2 | HH) = 0

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Answer: 50 houses

Step-by-step explanation: If there was 100 houses the 60 percent would be 60 houses but all they did was cut the number of houses in half to try and trick you.

Answer: (My view) 6.

Step-by-step explanation: Letting "n" be the number of pictures taken. The probability of no one look at the camera for n photos is of (3/4)^n.

Hence, the probability of at least one photo be the picture craven is of:

(1 - (3/4)^n), and since the likelihood of that being equal to 4/5, it's feasible to assume that (1 - (3/4)^n) = 4/5, solving for that would give:

(3/4)^n = 1/5. Notice that the proposal can also be interpreted as "The number of pictures needed such that the probability of a picture NOT including one with everyone looking at the camera is at most 1/5",

Therefore, (3/4)^n < 1/5;

To solve for that:

n = 1:

3/4 > 1/5,

n = 2:

9/16 > 1/5

n = 3

27/64 > 1/5

n = 4

81/256 > 1/5

n = 5

243/1024 > 1/5

But finally:

n = 6

729/4096 < 1/5

For at least 6 pictures she must take to have at least a 4/5 chance of having a picture in which everyone is looking at the camera.

Let p define the probability of success in a Bernoulli trial, and P define the probability Sara wants to reach "at least" and n be defined as the number of trials. Then,

= 1 - (1 - p)ⁿ ≥ P

= (1 - p)ⁿ ≤ 1 - P

= n ≥ ln(1-P)/ln(1-p)

= n ≥ ln (0.2) / ln (0.75)

=5.6

Hence for at least n=6 photos, there is at least a chance of 4/5 that everyone is looking at the camera.

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\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

Here's the solution ~

\(\qquad \sf  \dashrightarrow \: \sqrt{5} \times \sqrt{12} \times \sqrt{50} \)

\(\qquad \sf  \dashrightarrow \: \sqrt{5} \times \sqrt{2 {}^{2} \times 3 } \times \sqrt{2 \times {5}^{2} } \)

\(\qquad \sf  \dashrightarrow \: \sqrt{5} \times 2 \sqrt{3} \times 5 \sqrt{2} \)

\(\qquad \sf  \dashrightarrow \: 2 \times 5 \sqrt{5 \times 3 \times 2} \)

\(\qquad \sf  \dashrightarrow \: 10 \sqrt{30} \)

\(\huge\underline\mathtt\colorbox{cyan}{ATTACHMENT}\)

Answer:

see explanation

Step-by-step explanation:

(1)

a + 3b = 5 ( subtract 3b from both sides )

a = 5 - 3b → (1)

3a + 2b = 8 → (2)

Substitute a = 5 - 3b into (2)

3(5 - 3b) + 2b = 8 ← distribute and simplify left side

15 - 9b + 2b = 8

15 - 7b = 8 ( subtract 15 from both sides )

- 7b = - 7 ( divide both sides by - 7 )

b = 1

Substitute b = 1 into (1)

a = 5 - 3(1) = 5 - 3 = 2

Then a = 2 and b = 1

(2)

3m - 4n = - 14 → (1)

2m + 2n = 14 → (2)

Multiplying (2) by 2 and adding to (1) will eliminate the n- term

4m + 4n = 28 → (3)

Add (1) and (3) term by term to eliminate n

7m + 0 = 14

7m = 14 ( divide both sides by 7 )

m = 2

Substitute m = 2 into either of the 2 equations and solve for n

Substituting into (2)

2(2) + 2n = 14

4 + 2n = 14 ( subtract 4 from both sides )

2n = 10 ( divide both sides by 2 )

n = 5

Then m = 2 and n = 5

56/120

Step-by-step explanation:

The body masses of the two children in terms of their father's body mass, x, are:

First child's body mass = 5x/6 kg

Second child's body mass = 4x/5 kg

To express the body mass of the man's two children in terms of their father's body mass, we can use the given ratios.

Let the body mass of the man be x kg.

The first child's body mass is five-sixths of their father's body mass:

Body mass of the first child = (5/6) * x

= 5x/6 kg.

The second child's body mass is four-fifths of their father's body mass:

Body mass of the second child = (4/5) * x

= 4x/5 kg.

Therefore, the body masses of the two children in terms of their father's body mass, x, are:

First child's body mass = 5x/6 kg

Second child's body mass = 4x/5 kg

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