number 9?? please help.

Answer:

No

Step-by-step explanation:

Without any side lengths, the most three angles can determine is similarity, not congruency. This means you can determine the ratio of the lengths of the sides, but not any of the sides individually.

Answer:

  8.5 years

Step-by-step explanation:

You want to know the number of years until 18500 depreciates to 9100 at the rate of 8% per year.

The depreciation rate given as a percentage of current value tells you the depreciation is exponential. The formula will be ...

  value = (initial value) × (1 - (depreciation rate))^t

where the rate is "per year" and t is in years.

  value = 18500·(1 -0.08)^t

  9100 = 18500·0.92^t . . . . fill in the value of interest

  9100/18500 = 0.92^t . . . . divide by 18500

  log(91/185) = t·log(0.92) . . . . take logarithms

  t = log(91/185)/log(0.92) ≈ -0.3081/-0.03621 ≈ 8.509

It will be about 8.5 years until the value is $9100.

__

Additional comment

The graph shows the solution to ...

  18500·0.92^t -9100 = 0

We find it fairly easy to locate an x-intercept, so we wrote the equation in the forms that makes the x-intercept the solution.

The store should have 445 picks remaining, not 450 as estimated by the manager. To determine if the store manager's estimate is reasonable, let's analyze the situation.

The store initially has 500 guitar picks. They order 15 boxes, and each box contains 9 picks. So the total number of picks they receive from the order is:

15 boxes * 9 picks/box = 135 picks

Next, the store sells 19 boxes, with each box containing 10 picks. Therefore, the total number of picks sold is:

19 boxes * 10 picks/box = 190 picks

To find the remaining number of picks, we can subtract the sold picks from the received picks:

Total remaining picks = Initial picks + Received picks - Sold picks

Total remaining picks = 500 + 135 - 190 = 445 picks

According to the calculations, the store should have 445 picks remaining, not 450 as estimated by the manager.

However, it's important to note that we are working with whole numbers, so there might be some rounding involved in the manager's estimate. It's possible that the manager rounded up to 450 for simplicity or other reasons.

Given the small discrepancy of 5 picks between the calculated value and the manager's estimate, it is reasonable to conclude that the manager's estimate is close enough to the actual number of picks. The discrepancy could be due to rounding or a small counting error. It's unlikely to have a significant impact on the store's operations or inventory management.

In summary, while the manager's estimate of 450 guitar picks may not be exactly accurate, it is reasonably close to the actual remaining number of picks based on the given information.

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Answer: y=-3x-5

Step-by-step explanation:

(0,-5)   (-1,-2)

\(\displaystyle\\\frac{x-x_1}{x_2-x_1} =\frac{y-y_1}{y_2-y_1}\)

x₁=0     x₂=-1     y₁=-5    y₂=-2

\(\displaystyle\\\frac{x-0}{-1-0}=\frac{y-(-5)}{-2-(-5)} \\\\\frac{x}{-1} =\frac{y+5}{-2+5} \\\\-x=\frac{y+5}{3}\)

Multiply both parts of the equation by 3:

\(-3x=y+5\\\\-3x-5=y+5-5\\\\-3x-5=y\)

\(Thus,\ y=-3x-5\)

1. to find angle x:

angles on a straight line add to 180º : 180-92º = 88º

to find angle y:

exterior angle equals opposite interior angles: 88+22=110º

2. to find angle x:

angles on a straight line add to 180º : 180-118 = 62º

to find angle y:

exterior angle equals opposite interior angles: 62+52 = 114º

sorry if i got any of the angles wrong, the picture was a bit blurry and I couldn't tell that well, let me know if i got it wrong and i'll fix it

Answer:

6000 metres is equal to 6 kilograms

Route 1 has the possibility of a very short amount of time to drive to work.

Route 1 results in the most consistent times.

Route 2 is more likely to take a very long time on occasion.

According to me, Joe should choose route 1.

Joe should re-evaluate his decision if his job location changes if there is road construction on the route he has chosen or if the number of vehicles on the routes changes.

Mean is the average of a set of n data x1.

Standard deviation is the most commonly used measure of the spread or dispersion of data around the mean. The standard deviation is defined as the square root of the variance (V).

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Answer:

D. y= 0.3x2

Step-by-step explanation:

In quadratic functions, the value of a affects the wideness of the graph. The smaller the absolute value of a, the wider the graph. In these choices, 1/3 and 0.3 are the smallest. To understand which is smaller convert both to decimals; 1/3 is 0.3333 repeating. Therefore, 0.3 is slightly smaller and wider.

Answer:

c

Step-by-step explanation:

The red line represents the critical value, and the shaded region on the right-hand side of the red line represents the rejection region. If the calculated test statistic is greater than the critical value of z, which is 1.88 in this case, we will reject the null hypothesis.

The critical value(s) and rejection region(s) for the type of z-test with a level of significance a = 0.03 and a right-tailed test are as follows :Step 1: Determine the critical value of  zThe critical value is calculated by using the normal distribution table and the level of significance. A right-tailed test will have a critical value of zα. For a level of significance of 0.03, we will look for the z-value that corresponds to 0.03 in the normal distribution table.Critical value for a = 0.03 is z = 1.88 (approx).Step 2: Determine the Rejection Region The rejection region for a right-tailed test is defined as any z-value that is greater than the critical value. That is, if the test statistic is greater than 1.88, we reject the null hypothesis at the 0.03 level of significance, and if it is less than or equal to 1.88, we fail to reject the null hypothesis.Therefore, the rejection region for a right-tailed test with a level of significance of 0.03 is as follows:Rejection Region: Z > 1.88  OR  Z ≤ -1.88Graph: The graph for the given values will be as follows:The red line represents the critical value, and the shaded region on the right-hand side of the red line represents the rejection region. If the calculated test statistic is greater than the critical value of z, which is 1.88 in this case, we will reject the null hypothesis.

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Answer: If there is 50 in each box, yes.

Step-by-step explanation:

The cost of the brand less than 6 bags is less than 11.94

If the cost y of a brand can be represented by the equation y=1.99x

where

For a brand that costs less than 6 bags, we will substitute x = 6 into the function

y = 1.99(6)

y = 11.94

Hence the cost of the brand less than 6 bags is less than 11.94

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Answer:

my guess would have to be a= -9   (negative nine)

Step-by-step explanation:

sorry, i tried solving the problem otherwise and couldn't get an answer, good luck

Answer:

-5

12

36

60

Step-by-step explanation:

not really sure,. are you going to solve for the x only? or should you include the y?

Check the picture below.

Answer:

54

Step-by-step explanation:

Multiply each number by 3

The standardized residuals are -0.11, 0.75, -0.38, 2.08, and 2.16, respectively.

(a) The estimated regression equation can be found by first calculating the sample means and sample standard deviations for both x and y, as well as the sample correlation coefficient, and then using these values to calculate the slope and intercept of the regression line:

x = (6 + 11 + 15 + 18 + 20)/5 = 14

y = (7 + 7 + 13 + 21 + 30)/5 = 15.6

sx = sqrt(((6-14)^2 + (11-14)^2 + (15-14)^2 + (18-14)^2 + (20-14)^2)/4) = 4.49

sy = sqrt(((7-15.6)^2 + (7-15.6)^2 + (13-15.6)^2 + (21-15.6)^2 + (30-15.6)^2)/4) = 8.25

r = ((6-14)(7-15.6) + (11-14)(7-15.6) + (15-14)(13-15.6) + (18-14)(21-15.6) + (20-14)(30-15.6))/4sxsy

= 0.962

b = r(sy/sx) = 1.71

a = y - b(x) = -9.23

Therefore, the estimated regression equation is y = -9.23 + 1.71x.

(b) The residuals can be found by subtracting the predicted values of y (based on the regression line) from the actual values of y:

xi

yi

y

Residuals

6

7

0.09

-0.09

11

7

6.38

0.62

15

13

13.31

-0.31

18

21

19.29

1.71

20

30

23.57

6.43

(c) The standardized residuals can be found by dividing each residual by its estimated standard deviation:

xi

yi

ŷ

Residuals

Standardized Residuals

6

7

0.09

-0.09

-0.11

11

7

6.38

0.62

0.75

15

13

13.31

-0.31

-0.38

18

21

19.29

1.71

2.08

20

30

23.57

6.43

2.16

The estimated standard deviation of the residuals can be found by calculating the root mean squared error (RMSE):

RMSE = sqrt(((-0.09)^2 + (0.62)^2 + (-0.31)^2 + (1.71)^2 + (6.43)^2)/4) = 3.04

Therefore, the standardized residuals are -0.11, 0.75, -0.38, 2.08, and 2.16, respectively.

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Answer:

x = -3 ; y = -6

Step-by-step explanation:

x = y + 3

-2x + 4y = -18

-2(y+3) + 4y = -18

-2y -6 + 4y = -18

2y = -12

y = -6

x = -6+3

x = -3

Answer:

x = -3    y = -6

Step-by-step explanation:

x = y + 3

x - 3 = y

-2x + 4(x - 3) = -18

-2x + 4x - 12 = -18

2x = -6

x = -3

x = y + 3

-3 = y + 3

-6 = y

The cost of each printer is $568.

To find the cost of each printer, we need to use a system of equations.

Let's call the cost of each printer "p" and the cost of each camera "c".

The first equation we can create is: 6p + 3c = 4773

The second equation we can create is: 4p + 6c = 5002

Now we can use the elimination method to solve for one of the variables.

Let's eliminate the "c" variable by multiplying the first equation by -2: -12p - 6c = -9546

And then add the two equations together: -8p = -4544

Now we can solve for "p" by dividing both sides by -8: p = 568

So the cost of each printer is $568.

To find the cost of each camera, we can plug the value of "p" back into one of the original equations and solve for "c":

6(568) + 3c = 4773

3408 + 3c = 4773

3c = 1365

c = 455

So the cost of each camera is $455.

Therefore, the cost of each printer is $568 and the cost of each camera is $455.

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The main advantage of an independent measures design is that it reduces the risk of order or practice effects and minimizes the influence of individual differences between participant

An independent measures design, also known as a between-subjects design, is a type of research study in which different groups of participants are used for each condition being tested.

In other words, each participant is only exposed to one condition, and the data from each group is analyzed and compared to determine if there are any significant differences between the groups.

The main characteristics of an independent measures design are:

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Answer:

Hey there!

Let x be the number.

Thus, we have \((x-9)^3\)

Hope this helps :)

Answer:

Step-by-step explanation:

32

Answer:

32

Step-by-step explanation:

The critical values for the test statistic T₀ are as follows:(a) For α = 0.01 and n = 20, T₀ ≥ 2.861 (b) For α = 0.05 and n = 12, T₀ ≥ 1.796 (c) For α = 0.10 and n = 15, T₀ ≥ 1.345

We want to determine the appropriate value from the t-conveyance in light of the importance level () and opportunity levels (df) associated with the example size (n) in order to determine the fundamental incentive for the test measurement T0.

df = n - 1 is the probability of testing a population mean with unclear variation.

(a) α = 0.01 and n = 20:

For α = 0.01 and n = 20, the degrees of chance (df) would be 20 - 1 = 19. We need to find the fundamental worth from the t-dissemination for a one-followed test with a significance level of 0.01 and 19 degrees of chance. Let's refer to this fundamental worth as t1.

Using a t-table or factual programming, we discover that, for df = 19 and t1 = 0.01, the approximate value is 2.861.

(b) α = 0.05 and n = 12:

The levels of opportunity (df) would be 12 - 1 = 11 for n = 12 and  = 0.05. For a one-followed test with 11 levels of opportunity and an importance level of 0.05, we want to determine the basic worth from the t-conveyance. Could we mean this essential worth as t₁₋α.

Using a t-table or factual programming, we discover that, for df = 11 and t1 = 0.05, the approximate value is 1.796.

(c) α = 0.10 and n = 15:

For α = 0.10 and n = 15, the degrees of chance (df) would be 15 - 1 = 14. We need to find the essential worth from the t-dispersal for a one-followed test with a significance level of 0.10 and 14 degrees of chance. We ought to refer to this fundamental worth as t1.

Using a t-table or real programming, we find that t₁₋α for α = 0.10 and df = 14 is generally 1.345.

As a result, the fundamental characteristics of the test measurement T0 are as follows:

(a) For α = 0.01 and n = 20, T₀ ≥ 2.861

(b) For α = 0.05 and n = 12, T₀ ≥ 1.796

(c) For α = 0.10 and n = 15, T₀ ≥ 1.345

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Answer:

if x>0 and y=0 the point is located on the x-axis

Answer:

x-axis on the right side

Step-by-step explanation:

the point (x,y) located on the x-axis

example x=1, y=0

The algebraic expression for the scenario is 15 + x = 60

From the question, we have the following parameters that can be used in our computation:

Amount saved up = $15

Cost of item = $60

Amount gifted by your grandma = x

The above parameters means that the mathematical statement is an equation statement

So, we have the following representation

Amount saved up + Amount gifted by your grandma = Cost of item

Substitute the known values in the above equation, so, we have the following representation

15 + x = 60

Hence, the algebraic expression is 15 + x = 60

The question does not require that the equation be solved

However, when it is solved, we have:

15 + x = 60

Subtract 15 from both sides

x = 45

So, the amount is 45

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The cylindrical shell is subjected to an internal pressure of 70MPa. The shell's inner radius is 10 cm, and the outer radius is 16 cm. The maximum and minimum hoop stresses in the cylindrical shell are determined below.

For an element of thickness dr at a distance r from the center, the hoop stress is given by equation i:

σθ = pdθ...[i]Where, p is the internal pressure.

The thickness of the shell is drThe circumference of the shell is 2πr.

Therefore, the force acting on the element is given by:F = σθ(2πrdr)....[ii]

Let σmax be the maximum stress in the shell. The stress at radius r = a, which is at the maximum stress, is given by:σmax = pa/b....[iii]

Here a = radius of the shell, and b = thickness of the shell.

According to equation [i], the hoop stress at radius r = a is given by:σmax = pa/b....[iii].

Substitute the given values:σmax = 70 × 10^6 × (16 - 10)/(2 × 10) = 56 × 10^6 Pa.

The minimum hoop stress in the shell occurs at the inner surface of the shell. Let σmin be the minimum stress in the shell.σmin = pi/b....[iv].

According to equation [i], the hoop stress at radius r = b is given by:σmin = pi/b....[iv]Substitute the given values:

σmin = 70 × 10^6 × 10/(2 × 10) = 35 × 10^6 Pa.

Therefore, the maximum hoop stress in the shell is 56 × 10^6 Pa and the minimum hoop stress is 35 × 10^6 Pa.

A thick cylindrical shell with an inner radius of 10 cm and an outer radius of 16 cm is subjected to an internal pressure of 70MPa. Maximum and minimum hoop stresses in the cylindrical shell can be determined using equations and the given data. σθ = pdθ is the formula for hoop stress in the cylindrical shell.

This formula calculates the hoop stress for an element of thickness dr at a distance r from the center.

For the cylindrical shell in question, the force acting on the element is F = σθ(2πrdr).

Let σmax be the maximum stress in the shell. According to equation [iii], the stress at the radius r = a, which is the maximum stress, is σmax = pa/b.σmax is calculated by substituting the given values.

The maximum hoop stress in the shell is 56 × 10^6 Pa according to this equation.

Similarly, σmin = pi/b is the formula for minimum hoop stress in the shell, which occurs at the inner surface of the shell.

The minimum hoop stress is obtained by substituting the given values into equation [iv].

The minimum hoop stress in the shell is 35 × 10^6 Pa.As a result, the maximum and minimum hoop stresses in the cylindrical shell are 56 × 10^6 Pa and 35 × 10^6 Pa, respectively.

Thus, the maximum hoop stress in the shell is 56 × 10^6 Pa and the minimum hoop stress is 35 × 10^6 Pa. These results are obtained using equations and given data.

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Answer:

97,988.216

Step-by-step explanation:

So, we can find this by using the following formula:

First value(change)^time

We know that the orginal, or first value, is 120,000.

We know that the time interval for this is 8 years, which is our time value.

We know that the decrease in this price is 2.5%. However, this is not our change.

Our change is the 97.5% price that is left.

This makes sense, because you would get a super small price when you use 2.5% as change.

So to sum up what we have done so far:

First value - 120,000

Change - 100%-2.5% = 97.5%. In decimal form: 0.975

Time - 8

So lets plug these into:

\(First_.value(change)^t^i^m^e\)

=

\(120,000(0.975)^8\)

And remember your order of operations here.

We dont have any equations or expressions inside the parethese, so we can move on to what comes next - exponents.

We have the exponent 8, which is attached to the 0.975.

So in your calculator, take 0.975, and put it to the 8th power.

You should get 0.816651803662261962890625

Lets leave it like this, becuase 120,000 is a very large value, and rounding what you multiply could change what you get in the end.

Now  our equation looks like:

120,000(0.816651803662261962890625)

We have done parethese, exponents - now we have multiplication and division.

We do indeed have this, since 120,000(0.816651803662261962890625) could also be written as:

\(120,000*0.816651803662261962890625\)

Now multiplying this you should get:

97,998.216439471435546875

This is where you can round your answer.

I do not know what exactly they want you to round to, so its safe to just round your answer to the hundreths place:

97,998.22

So this is the new price of the car!

Hope this helps!

oh I did a mistake earlier , pardon ^^"

Let price after 8 years be P.

Using the compound interest formula of shrinking principal :-

P = Pₒ( 1 - R/ 100) ᵀ

P = 120, 000 ( 1 - 2.5/ 100)ᵀ

P = 120, 000 { (100 - 2.5)/ 100}ᵀ

P = 120, 000{ 97. 5/ 100 }ᵀ

P = 120, 000 {0. 975 } ⁸

P = 120, 000 { 0. 8166}

P = 97,998.216 $

Since, P is is price after 8 years

The price of the car after 8 years will be 97, 998. 216 $