no links, please!

Simplify
7⋅3−68−5

Answer:

Answer b)

Step-by-step explanation:

In the sequence 0, 5, 10, 15,...

5 is added to each term in order to get the next one. Therefore the next three terms would be; 20, 25, 30.

This agrees with answer b) in the list of possible answers.

Answer:

He should be able to make 13, 3 ounces servings of fruit salad

Step-by-step explanation:

Hope this helps!!

Answer:

A = 22.62°

B = 67.38°

c = 26

Step-by-step explanation:

\(a^2+b^2=c^2\\10^2+24^2=c^2\\100+576=c^2\\676=c^2\\26=c\)

\(\sin A=\frac{\text{Opposite}}{\text{Hypotenuse}}=\frac{10}{26}\\\\A=\sin^{-1}(\frac{10}{26})\\\\A\approx22.62^\circ\)<-- You can also use other trig ratios

\(B=180^\circ-(90^\circ+22.62^\circ)=180^\circ-112.62^\circ=67.38^\circ\)

There's no specific order in how to solve for A and B, so there may be more than one way to approach these solutions.

5 "Always." Consecutive angles of a rectangle are always congruent.

6 "Never." A parallelogram is not always a square.

7 "Sometimes." In a rhombus, the diagonals are always perpendicular bisectors of each other, but they are not always congruent.

8 "Always." A rectangle has congruent sides, but not necessarily all four sides.

9 Given: ABCD is a parallelogram

To prove: AABC = ACDA

Proof:

AB || DC (definition of parallelogram)

AD || BC (definition of parallelogram)

∠ABC = ∠CDA (alternate interior angles)

AC = AC (reflexive property)

∠BCA = ∠DAC (alternate interior angles)

Therefore, AABC = ACDA (ASA congruence theorem)

10 Given: TRAP is an isosceles trapezoid

To prove: AAPR ARTA

TR = AP (definition of isosceles trapezoid)

∠APT = ∠ATR (alternate interior angles)

∠PAR = ∠RTA (alternate interior angles)

∠PAR = ∠APT (angles at a point)

Therefore, AAPR ARTA (AA congruence theorem)

Consecutive angles of a rectangle are always congruent. This is a property of rectangles that is true for every rectangle.

A square is a specific type of parallelogram that has all four sides congruent and all four angles right angles.

A rectangle has two pairs of opposite sides that are congruent, but the adjacent sides may have different lengths. This is a defining characteristic of rectangles, and it is always true for every rectangle.

The ASA congruence theorem states that two triangles are congruent if two angles and the included side of one triangle are congruent to the two angles and the included side of the other triangle. In this case, ∠ABC and ∠CDA are congruent by (3), AC is congruent by (4), and ∠BCA and ∠DAC are congruent by (5). Therefore, AABC = ACDA by the ASA congruence theorem.

The AA congruence theorem states that two triangles are congruent if two angles of one triangle are congruent to two angles of the other triangle, and the side between those angles is congruent in both triangles

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Answer:

x = -2 ± 3√2

Step-by-step explanation:

x^2 + 4x + 4 = 18:

or, (x + 2)^2 = 18

Taking the square root of both sides, we get:

or, x + 2 = ±√18

or, x + 2 = ±3√2

or,x = -2 ± 3√2

therefore, x = -2 + 3√2 or x = -2 - 3√2

or,

using Shridharacharya's formula

x = (-b ± √(b^2 - 4ac)) / (2a)

now,

x^2 + 4x + 4 = 18.

or, x^2 + 4x + 4 - 18 = 0

or, x^2 + 4x - 14 = 0

or, x = (-4 ± √(4^2 - 4(1)(-14))) / (2(1))

or, x = (-4 ± √(16 + 56)) / 2

or, x = (-4 ± √72) / 2

(√72 = √(36 x 2) =6√2)

or, x = (-4 ±6√2 ) / 2

or, x = -2 ± 3√2

Therefore,x = -2 + 3√2 and x = -2 - 3√2.

Answer:

Step-by-step explanation:

Given that,

To find the standard form of the equation of the parabola with a focus at (0, 9) and a directrix y = -9.

What is a parabola?

A parabola is a cross-section cut out of the cone and represented by an equation

Focus of the prabola = (h , k + F ) =  (0, 9)

Since the directrix, y =  -9

F = -9

k + F = 9

k = 0

Vertex of the parabola = (h,  k  )

                                    =  (0, 0)

Standard equation of the parabola

( y - k ) = 4a (x - h)²

( y - 0 ) = 4a (x - 0)²

y = 4 * 9 x²

y = 36 x²

Thus, the required expression for the parabola with focus at (0, -9) and a directrix y = 9 is y = 36x².

Reflex angle

Step-by-step explanation:

Reflex angle is more then 180 and less then 360

Answer:

yes buddy ans is reflex angle

The maximum and minimum value of the function subject to the given constraint is f(0,0) = 0.

What are Lagrange multipliers?

Lagrange's multiplier is a mathematical technique used to find the maximum or minimum value of a function subject to certain constraints. It is named after Joseph-Louis Lagrange, who first introduced the method in the 18th century.

To use Lagrange multipliers to find the maximum and minimum values of the function f(x, y) = y^2 - x^2 subject to the constraint 1/4x^2 + y^2 = 64, we need to first set up the Lagrange function:

L(x, y, λ) = y^2 - x^2 + λ(1/4x^2 + y^2 - 64)

We then find the partial derivatives of L with respect to x, y and λ:

∂L/∂x = -2x + λ(1/2x) = 0

∂L/∂y = 2y + λ(y) = 0

∂L/∂λ = 1/4x^2 + y^2 - 64 = 0

Solving these equations, we find the following solutions:

x = 0, y = 0, λ = -8

x = 8√2, y = 8√2, λ = 4

x = -8√2, y = -8√2, λ = 4

Now, we need to check these solutions to see if they satisfy the constraint 1/4x^2 + y^2 = 64. Only the first solution x = 0, y = 0 satisfies the constraint.

Hence, the maximum and minimum value of the function subject to the given constraint is f(0,0) = 0.

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Answer:

\(s=17\)

Step-by-step explanation:

Pythagorean Theorem: \(a^{2} +b^{2} =c^{2}\)

\(8^2+15^2=c^2\)

\(64+225=c^2\)

\(c^2=289\)

\(c=17\)

Answer:

Unit 4- Expressions and Equations: In this unit, students build on their knowledge from unit 2, where they extended the laws of exponents to rational exponents. Students apply this new understanding of number and strengthen their ability to see structure in and create quadratic and exponential expressions.

Answer:

  x = 1

Step-by-step explanation:

You want to know the value of x in the trapezoid with adjacent angles (43x+2)° and 135°.

The two marked angles can be considered "consecutive interior angles" where a transversal crosses parallel lines. As such, they are supplementary.

  (43x +2)° +135° = 180°

  43x = 43 . . . . . . . . . . . . . . divide by °, subtract 137

  x = 1 . . . . . . . . . . . . . . . divide by 43

The value of x is 1.

__

Additional comment

Given that the figure is a trapezoid, we have to assume that the top and bottom horizontal lines are the parallel bases.

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Given that 16 families went on a trip and the cost of the trip was Rs. 2,16,352.The amount paid by each family is to be determined by unitary method Hence each family paid Rs.13522

Now, let's solve this by using the method of unitary method. To find the cost of 1 family trip, we will divide the total cost of the trip by the number of families.2,16,352 / 16 = 13,522 So, the cost of the trip per family is Rs. 13,522.Hence, each family paid Rs. 13,522 for the trip.

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Answer:

Step-by-step explanation

1. The total cost of the trip for all 16 families is Rs 2,16,352.
2. To find out how much each family paid, we need to divide the total cost by the number of families: Rs 2,16,352 ÷ 16.
3. When we do the division, we get the result: Rs 13,522.

Now let's check if this result is correct:

1. If each family paid Rs 13,522 for the trip, then the total cost for all 16 families would be: 16 × Rs 13,522 = Rs 2,16,352.
2. This is exactly the same as the total cost given in the problem statement.

So we have shown that each family paid **Rs 13,522** for the trip

7.3692 8.7 8.72 8.702

Answer:

1.15

Step-by-step explanation:

Answer:

1.15

Step-by-step explanation:

2.3 x 0.5 = 1.15

The total materials handling cost allocated to the modular homes is $246,372.84.

The total materials handling cost allocated to the Prefab Barns is closest to $108,000.

To allocate materials handling cost based on material moves, we must determine proportion of material moves for each product and then apply that proportion to the total materials handling cost.

Proportion of material moves for Modular Homes:

= (Total expected material moves for Modular Homes) / (Total expected material moves for both products)

= 590 / (590 + 190)

= 0.756

Total materials handling cost allocated to Modular Homes:

= Proportion of material moves for Modular Homes * Total materials handling cost

= 0.756 * $325,890

= 246 372.84

= $246,372.84.

To allocate the materials handling cost based on direct labor-hours, we need to determine proportion of direct labor-hours for each product.

For Modular Homes:

Total direct labor-hours for Modular Homes:

= 6,000 units * 800 hours/unit

= 4,800,000 hours

For Prefab Barns:

Total direct labor-hours for Prefab Barns:

= 9,000 units * 300 hours/unit

= 2,700,000 hours

Total direct labor-hours for both products:

= 4,800,000 hours + 2,700,000 hours

= 7,500,000 hours

Proportion of direct labor-hours for Prefab Barns:

= 2,700,000 hours / 7,500,000 hours

= 0.36

Allocated materials handling cost for Prefab Barns:

= Proportion of direct labor-hours for Prefab Barns * Total materials handling cost

= 0.36 * $300,000

= $108,000.

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Answer:

See Below

Step-by-step explanation:

Trend for line one: (+3)       9,12,15,18,21,24

Trend for line two: (+2)       4,6,8,10,12,14

Trend for line three: (+1 alternating each number) 1,8,2,9,3,10

Trend for line four: (+7 for alternating numbers) 2,11,9,18,16,23

2+7=9

11+7=18

9+7=16

18+7=23

Number: 912-810-310-1623

Let me know if this works, I can revise it if there are any issues. Thanks

To prove: The number of left cosets of a subgroup is equal to the number of its right cosets.

Proof: Let H be a subgroup of a group G. Let g be an element of G. Consider the map f: H→ gH defined by f(h) = gh for all h in H. We claim that f is a bijection from H to gH.

First, we show that f is injective. Suppose f(h1) = f(h2) for some h1, h2 in H. Then gh1 = gh2, which implies that h1 = h2, by left cancellation law. Therefore, f is injective.

Next, we show that f is surjective. Let gh be an element of gH. Then h is an element of G, since gH is a subset of G. Since H is a subgroup of G, it follows that gh is an element of gH. Therefore, f(h) = gh, which shows that f is surjective.

Hence, f is a bijection from H to gH. Therefore, the number of left cosets of H is equal to the number of right cosets of H.

Answer:

\(\huge\boxed{\$ 88.98}\)

Step-by-step explanation:

In order to find the total price, we know that the total price will be all the items added up minus the coupon.

You get 10$ off any new video game. This means that when the customer purchases a video game for $59.99, he earns $10 off, so it ends up costing \(59.99-10=\$49.99\).

Now we can add 39.99 to this since we do nothing to it. \(49.99+39.99=88.98\)

Hope this helped!

The general solution of the partial differential equation is:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

The partial differential equation (PDE) is given as:

Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)

Assume that the solution can be written as a product of two functions:

U(x, t) = X(x)T(t)

Substituting this into the PDE, we have:

X''(x)T(t) = (1/2)X(x)T'(t)

Dividing both sides by X(x)T(t), we get:

(X''(x))/X(x) = (1/2)(T'(t))/T(t)

Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:

(X''(x))/X(x) = -λ²

(1/2)(T'(t))/T(t) = -λ²

Simplifying the second equation, we have:

T'(t)/T(t) = -2λ²

Solving the second equation, we find:

T(t) = Ce^(-2λ²t)

Applying the boundary condition U(0, t) = 0, we have:

U(0, t) = X(0)T(t) = 0

Since T(t) ≠ 0, we must have X(0) = 0.

Applying the boundary condition U(3, t) = 0, we have:

U(3, t) = X(3)T(t) = 0

Again, since T(t) ≠ 0, we must have X(3) = 0.

Therefore, we can conclude that X(x) must satisfy the following boundary value problem:

X''(x)/X(x) = -λ²

X(0) = 0

X(3) = 0

The general solution to this ordinary differential equation is given by:

X(x) = Asin(λx) + Bcos(λx)

Applying the initial condition U(x, 0) = 5*sin(4πx), we have:

U(x, 0) = X(x)T(0) = X(x)C

Comparing this with the given initial condition, we can conclude that T(0) = C = 5.

Therefore, the complete solution for U(x, t) is given by:

U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)

where:

Σ represents the summation over all values of n

λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).

To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):

X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0

X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0

From the first equation, we have Bₙ = 0.

From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.

This implies that 3λₙ = nπ, where n is an integer.

Therefore, λₙ = (nπ)/3.

Substituting the eigenvalues into the general solution, we have:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

where Aₙ are the coefficients that can be determined from the initial condition.

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Answer:

To find the rules for (fg)(x) and (gf)(x), we need to evaluate the composite functions.

(fg)(x) = f(g(x)) = f(sqrt(x - 5)) = (sqrt(x - 5))^2 + 5 = x - 5 + 5 = x

(gf)(x) = g(f(x)) = g(x^2 + 5) = sqrt(x^2 + 5 - 5) = sqrt(x^2) = |x|

Therefore, the rules for (fg)(x) and (gf)(x) are:

(fg)(x) = x

(gf)(x) = |x|

Step-by-step explanation:

Solution :

Given information :

A sample of n = 10 adults

The mean failure was 24 and the standard deviation was 3.2

a). The formula to calculate the 95% confidence interval is given by :

\($\overline x \pm t_{\alpha/2,-1} \times \frac{s}{\sqrt n}$\)

Here, \($t_{\alpha/2,n-1} = t_{0.05/2,10-1}$\)

                       = 2.145

Substitute the values

\($24 \pm 2.145 \times \frac{3.2}{\sqrt {10}}$\)

(26.17, 21.83)

When the \(\text{sampling of the same size}\) is repeated from the \(\text{population}\) \(n\) infinite number of \(\text{times}\), and the \(\text{confidence intervals}\) are constructed, then \(95\%\) of them contains the \(\text{true value of the population mean}\), μ in between \((26.17, 21.83)\)

b). The formula to calculate 95% prediction interval is given by :

    \($\overline x \pm t_{\alpha/2,-1} \times s \sqrt{1+\frac{1}{n}}$\)

   \($24 \pm 2.145 \times 3.2 \sqrt{1+\frac{1}{10}}$\)

   (31.13, 16.87)

Answer:

6 Km / hour

Step-by-step explanation:

Convert distance to Km ( 1 Km = 1000 m )

150 m = 150 ÷ 1000 = 0.15 Km

Convert 1.5 mins to hours ( 1 hour = 60 minutes )

1.5 = 1.5 ÷ 60 = 0.025 hours

average speed = \(\frac{distance}{time}\) = \(\frac{0.15}{0.025}\) = 6 Km / hour

The average speed in km per hour is 6 kilometers per hour

The given parameters are:

Convert meters to kilometers

Distance = 150/1000 km

Distance = 0.15 km

Convert minutes to hours

Time = 1.5/60 hour

Time = 0.025 hour

The average speed is then calculated as:

Speed = Distance/Time

This gives

Speed = 0.15 km/0.025 hour

Evaluate

Speed = 6 kilometers per hour

Hence, the average speed in km per hour is 6 kilometers per hour

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Based on the fact that the cross-country course is shaped like a parallelogram, the total length of the cross-country course is 10 miles.

The total length of the cross-country course will be the perimeter of the shape that the course is shaped like.

As this course is shaped like a parallelogram, the total length would therefore be:

= Base + Base + Length + Length

Solving gives:
= 3 + 3 + 2 + 2

= 6 miles

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The order for the extra materials that are ordered by the man will be between 17.31 ft² and 23.08 ft².

From the information, the man is ordering new tile for her kitchen floor the area of the floor is 115.4 ft.² and wants to order between 15% and 20% extra of the material.

It should be noted that 15% of the material will be:

= 15% × 115.4

= 17.31 ft²

It should be noted that 20% of the material will be:

= 20% × 115.4

= 23.08 ft²

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Soooooo sorry but I only understood part a and c.

sorry

Answer:

im taking the 50 points

Step-by-step explanation:

Answer:

48 prime factors are: 2 x 2 x 2 x 2 x 3

Answer:

i belive its 5 percent

Step-by-step explanation:

5 perent

Answer:

2x^2 +4x +1

Step-by-step explanation:

x (2x+1) +3 (x-2)+7

= 2x^2 + x + 3x - 6 +7

= 2x^2 +4x +1