Newton’s first law of motion states that an object's motion remains the same unless a force acts upon it. What would be an example of this law in action?

Frequency is measured in hertz (Hz) (frequency = cycles/seconds). Simply divide 1 by the frequency that is equal to the time interval.

Time interval=1/ frequency

What is frequency?

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Mugabe gained power by using political strategies, forming alliances, and exploiting his status as a liberation hero within ZANU-PF.

Robert Mugabe, the former president of Zimbabwe, was able to build power through a combination of political strategies and alliances. One key factor was his involvement in the liberation struggle against white minority rule in Rhodesia (now Zimbabwe).

Mugabe emerged as a prominent figure within the Zimbabwe African National Union (ZANU) party, which later merged with the Zimbabwe African People's Union (ZAPU) to form the Zimbabwe African National Union - Patriotic Front (ZANU-PF). Mugabe's role as a liberation hero and his ability to mobilize support among the majority black population of Zimbabwe gave him a strong power base.

Within ZANU-PF, Mugabe strategically positioned himself and gained influence by forming alliances and outmaneuvering rivals. He rose to become the party's leader and played a key role in negotiating the Lancaster House Agreement in 1979, which paved the way for Zimbabwe's independence in 1980. Mugabe became the country's first prime minister and later transformed the position into an executive presidency, consolidating his authority.

Mugabe maintained power through various means, including controlling key institutions such as the military, intelligence agencies, and the ruling party. He also utilized patronage networks, distributing resources and positions to loyal supporters within the party and government. Mugabe's policies, such as the controversial land reform program, further solidified his power base by appealing to nationalist sentiments and redistributing land from white farmers to black Zimbabweans.

However, Mugabe's consolidation of power was also marked by authoritarianism, human rights abuses, and a declining economy. His grip on power faced challenges over the years, including opposition movements, internal party factions, and economic crises. Ultimately, his rule came to an end in 2017 when he was ousted from power following a military intervention.

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Answer: sonar and radar

Explanation:

Picture

Since the car is moving horizontally, we can use the conservation of energy principle:

Initial kinetic energy + Initial potential energy = Final kinetic energy + Final potential energy

We know that the initial kinetic energy is 1/2 mv^2 and the initial potential energy is mgh, where m is the mass of the car, v is its velocity, h is the height of the hump and g is the acceleration due to gravity.

At the top of the hump, the car's potential energy is converted entirely into kinetic energy, so we have:

1/2 mv^2 = mgh

Solving for v, we get:

v = √(2gh)

Substituting the values, we get:

v = √(2 x 9.8 m/s^2 x 12.2 m) = 11.9 m/s

Therefore, the car will be going at 11.9 m/s (rounded to one decimal place) when it reaches the top of the 12.2 m tall hill.

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Answer :

We can use the conservation of energy principle, since the car is moving horizontal

According to the Principle:

Initial kinetic energy + Initial potential energy = Final kinetic energy + Final potential energy

We know that the initial kinetic energy is 1/2 mv^2 and the initial potential energy is mgh, where m is the mass of the car, v is its velocity, h is the height of the hump and g is the acceleration due to gravity.

At the top of the hump, the car's potential energy is converted entirely into kinetic energy, so we have:

1/2 mv^2 = mgh

Solving for v, we get:

v = √(2gh)

Substituting the values, we get:

v = √(2 x 9.8 m/s^2 x 12.2 m) = 11.9 m/s

Therefore, the car will be going at 11.9 m/s (rounded to one decimal place) when it reaches the top of the 12.2 m tall hill.

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Answer:

Your answer would be D.

The frequency of oscillation of a simple pendulum depends on its length and the gravitational acceleration. Increasing the mass (1) or decreasing the initial angular displacement (2) will not affect the frequency.

The frequency of oscillation of a simple pendulum can be affected by changes in the length of the pendulum and the gravitational acceleration.

Therefore, increasing the length of the pendulum would decrease its frequency of oscillation, while decreasing the gravitational acceleration would also decrease the frequency of oscillation.

However, hanging the pendulum in an elevator accelerating downward would also change the gravitational acceleration, resulting in a change in the frequency of oscillation. Increasing the mass or decreasing the initial angular displacement would not have an effect on the frequency of oscillation.

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Answer:

100 m/s

Explanation:

Speed increases at a rate of 10 m/s (actually 9.8 m/s) every second. Thus after 10 seconds, the speed is 10 x 10 = 100 m/s.

Answer:

hurricanes are the most awesome Violet storms on the earth people call the storms by other names such as typhoon or cyclone depending on where the car whatever they are called topical cologne all from the same way

Explanation:

so technically hurricanes are the most Violet storms

The circuit expression for i1 and i2 in terms of r1, r2, and ve is \(i1 = (i2 * r2) / r1\)

we need to consider the loop involving branches i1 and r1, and the loop involving branches i2 and r2.

We can use Ohm's law to write the equation:

\(i1 * r1 - ve = 0\)

Next, let's write the loop equation involving i2 and r2:

\(i2 * r2 - ve = 0\)

Now, we have two equations:
\(i1 * r1 - ve = 0    (Equation 1)\\\\i2 * r2 - ve = 0    (Equation 2)\)

To solve these equations, we can substitute ve from Equation 1 into Equation 2:

\(i2 * r2 - (i1 * r1) = 0\)

We can rearrange this equation to solve for i2:

\(i2 = (i1 * r1) / r2\)

Similarly, we can solve for i1 by substituting ve from Equation 2 into Equation 1:

\(i1 * r1 - (i2 * r2) = 0\)

Rearranging this equation gives us:

\(i1 = (i2 * r2) / r1\)

Now, we have expressions for i1 and i2 in terms of r1, r2, and ve. By substituting the given values of r1, r2, and ve, we can calculate the values of i1 and i2.

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Answer: W = 331.1 J

Explanation:

W = pdv

= (4.3 x 10^5 Pa) (9.5 × 10−4 m3 - 1.8 × 10−4 m3)

W = 331.1 J or 3.3 x 10^2 J

The work done on the surrounding air by the helium-filled balloon during this expansion is 331.1 J.

Pressure-volume work is defined as the work that a fluid does when it is compressed or expanded by an external force factor.

Here,

Pressure of the helium gas, P = 4.3 x 10⁵Pa

Initial volume of the helium gas, V₁ = 1.8 x 10⁻⁴m³

Final volume of the helium gas, V₂ = 9.5 x 10⁻⁴m³

The expression for the pressure-volume work is given by,

Work done, W = PΔV

where ΔV is the change in volume of the helium gas.

Therefore,

W = P(V₂ - V₁)

W = 4.3 x 10⁵(9.5 x 10⁻⁴- 1.8 x 10⁻⁴)

W = 4.3 x 10⁵x 7.7 x 10⁻⁴

W = 331.1 J

Hence,

The work done on the surrounding air by the helium-filled balloon during this expansion is 331.1 J.

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As an acorn falls from a tree toward the ground, gravitational potential energy is converted into kinetic energy.

To find the correct option among all the options, we need to know about the conversation of energy.

Thus, we can conclude that option (d) is correct.

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Answer:

I think it's how far out the water goes from the beach before the tsunami because before tsunami usually the water goes back way behind the tide before tsunami and that tells them everything they need I think

Given the mass of the car and the change in velocity, the impulse exerted on the car by the brakes is 45000kgm/s.

Impulse is simply the product of force and time.

Using the formula of impulse.

Ft  = m( v - u )

Given the data in the question;

We substitute our values into the expression above.

Ft  = m( v - u )

Ft  = 1800kg( 25m/s - 0m/s )

Ft  = 1800kg × 25m/s

Ft = 45000kgm/s

Therefore, Given the mass of the car and the change in velocity, the impulse exerted on the car by the brakes is 45000kgm/s.

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The causes the electric field to become weaker, as the presence of the dielectric material reduces the overall capacitance of the capacitor.

The dielectric material like paper is inserted between the plates of a capacitor holding a charge, the electric field becomes weaker. This happens because the dielectric material reduces the effective electric field between the capacitor plates by aligning its internal dipoles with the field. As a result, the capacitance of the capacitor increases, allowing it to store more charge at the same voltage.Adding a dielectric allows the capacitor to store more charge for a given potential difference. When a dielectric is inserted into a charged capacitor, the dielectric is polarized by the field. The electric field from the dielectric will partially cancel the electric field from the charge on the capacitor plates.

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Answer:

the estimated ambient supersaturation is approximately 18.7%.

Explanation:

ln(R2/R1) = (4/3) * S * L * t

Where:

R1 is the initial radius of the droplet (2 um)

R2 is the final radius of the droplet (20 um)

S is the ambient supersaturation (what we need to find)

L is the Kelvin factor, which is dependent on temperature and pressure

t is the time duration (10 min)

Since we are neglecting the solution and curvature terms, we can assume the Kelvin factor (L) to be 1.

Now let's calculate the ambient supersaturation (S) using the given data:

ln(20/2) = (4/3) * S * 1 * 10

ln(10) = (4/3) * 10S

ln(10) = 40S/3

S = (3 * ln(10)) / 40

S ≈ 0.187

To convert the supersaturation to a percentage, we multiply it by 100:

S ≈ 0.187 * 100

S ≈ 18.7%

Complete Question:

The length, breadth and height of an object are 20 cm, 15 cm and 25 cm respectively. Its mass is 7 kg. Find its volume and density

Answer:

a. Volume of cuboid = 7500 cm³

b. Density = 0.000933 Kg/cm³

Explanation:

Given the following data;

a. To find the volume of the object.

An object that has a length, breadth and height is a cuboid.

Mathematically, the volume of a cuboid is given by the formula;

Volume of cuboid = length * breadth * height

Substituting into the formula, we have;

Volume of cuboid = 20 * 15 * 25

Volume of cuboid = 7500 cm³

b. To find the density of the object;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

\( Density = \frac {mass}{volume} \)

Substituting into the formula, we have;

\( Density = \frac {7}{7500} \)

Density = 0.000933 Kg/cm³

Answer -:

rate of charge of angular displacement of a circular motion is called angular velocity it is denoted by omega ( ω ) . if particle trave△θ angluar displacement time then

\( \bold {average \: velocity \: } \: \bold{ \frac{angular \: displacement \: }{time} }\)

or

\( \omega \frac{ \triangle \theta}{ \triangle \: t} \)

if t is very small then instantaneous

\( \omega = \lim \: \frac{ \triangle \theta}{ \triangle \: t \: } \)

Hi friend! I have an iPhone. why do you ask????

Answer:

b

Explanation:

because its b duuuuuuuu

The final velocity of the rock before hitting the ground is 34.42m/s

Velocity of an object can be said as, the rate of change of displacement with respect to time of an object . Its unit is m/s and it is a vector quantity.

V = Δx/Δt

In here , V is velocity ,  Δx is change in displacement and Δt is change in time of an object.

We are given that,

The rock thrown downward with initial velocity = (-u) = -20m/s

The height of the building before and after hitting the ground = -Δy = -40 m

Therefore , to get the value of the final velocity (v) of the rock before hitting the ground , then the equation of motion cab be written as,

v² = u² + 2a(Δy )

Here , (a) is the acceleration due to gravity and taken negative (-9.81m/s²) due downward direction of the building then putting all the values in above equation of motion ,

v² = (-20m/s)² + 2(-9.81m/s²) (-40m)

v² = 1184.42m/s

v = 34.42m/s

Hence, the final velocity of the rock before hitting the ground would be 34.42m/s .

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The gravitational potential energy of the coaster train and its riders relative to the ground is 1,150,000 J.

What is the gravitational potential energy of the coaster train and its riders?

To calculate the gravitational potential energy, we use the formula U = mgh, where U is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height. Given that the height is 115 m and the combined mass of the coaster train and riders is 4,500 kg, we can plug these values into the formula along with the acceleration due to gravity (g = 10 m/s²) to find that the gravitational potential energy is 1,150,000 J.

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Maps can include B. Compass rose and C. Legends. Maps are visual representations of the earth's surface or a portion of it. Hence, options B and C) are correct.

They can be constructed to provide a general overview of an area, such as a world map, or they can be constructed in greater detail, such as a map of a specific city or region. In general, a map will include a variety of components to help the reader understand what they are looking at and to provide additional context and information.

A compass rose is a graphic element that shows the orientation of the map and the directions of north, south, east, and west. This helps readers orient themselves and understand which way the map is oriented. Legends, also known as keys, are a way to provide additional information about the map's symbols and what they represent.

Graphs, on the other hand, are not typically included on maps. While maps can certainly show patterns and trends, they generally do not include the kind of quantitative data that is typically represented in a graph.

So, in short, maps can include a variety of components to help the reader understand what they are looking at. In this case, the correct options are B. Compass rose and C. Legends.

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That's a pretty good intuitive definition of a theory .

Answer:

Explanation:

Weight loss for a fat body does not make a sense of healthy habits. The scale should just be one method of monitoring her overall health.

Healthy habits include good food habits, regular exercising, personal hygiene and positive mind. These all factors affecting our health and it not just our weight.

Body weight can be controlled up to a limit by healthy habits and and controlled food. However, the some people might have a nature of fatty body or skelt irrespective of their habits. In such cases people no need to worry on their health by just looking on their weight.

Weight scale should just be one method of monitoring  the overall health. By losing weight or gaining weight we cant said to be in good health. Therefore, option A be the best response to Shondra.

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Answer: 500 ft

Explanation:

High beam headlights help one to see better at night as the range of vision is greatly expanded. They can however, blind drivers coming on the opposite lane.

It is therefore prudent to ensure that when using high beam headlights, you dim them when a car is coming towards you. The appropriate distance to do so is a minimum of 500 ft from the car.

In conclusion, the acceleration of the hollow spherical shell as it rolls down the slope is equal to the net force acting on it divided by its mass. The exact value of the acceleration depends on the radius of the shell, which is not provided in the problem.

To solve this problem, we can apply the principles of rotational motion and the concept of torque.

Given:

Mass of the hollow spherical shell (m) = 1.50 kg

Angle of the slope (θ) = 31.0°

We need to determine the acceleration of the shell as it rolls down the slope.

First, let's calculate the gravitational force acting on the shell. The gravitational force can be determined using the formula:

F_gravity = m * g

where g is the acceleration due to gravity, which is approximately 9.8 m/s^2.

F_gravity = 1.50 kg * \(9.8 m/s^2\) = 14.7 N

Next, let's analyze the forces acting on the shell as it rolls down the slope. There are two main forces involved: the gravitational force (F_gravity) acting vertically downward and the normal force (N) acting perpendicular to the surface of the slope.

The component of the gravitational force parallel to the slope can be calculated as:

F_parallel = F_gravity * sin(θ)

F_parallel = 14.7 N * sin(31.0°) = 7.73 N

Since the shell rolls without slipping, the friction force (f) can be calculated as:

f = μ * N

where μ is the coefficient of static friction. However, since the shell is rolling without slipping, the friction force is zero, as there is no relative motion between the surface and the shell.

Since there is no friction force, the net force acting on the shell is the parallel component of the gravitational force:

Net force (F_net) = F_parallel = 7.73 N

Finally, we can use Newton's second law for rotational motion to determine the angular acceleration (α) of the shell:

F_net = I * α

where I is the moment of inertia of the hollow spherical shell.

The moment of inertia of a hollow spherical shell can be calculated as:

I = (2/3) * m * R^2

where R is the radius of the shell.

Since the radius is not given in the problem, we cannot calculate the exact value of the angular acceleration. However, we can analyze the rotational motion of the shell.

As the shell rolls down the slope, it experiences a torque due to the net force acting on it. The torque can be calculated as:

τ = F_net * R

where R is the radius of the shell.

Since the shell rolls without slipping, the linear acceleration (a) can be related to the angular acceleration (α) as:

a = R * α

Combining these equations, we have:

τ = m * a * R

F_net * R = m * a * R

F_net = m * a

Therefore, the net force is equal to the mass of the shell times its linear acceleration.

In conclusion, the acceleration of the hollow spherical shell as it rolls down the slope is equal to the net force acting on it divided by its mass. The exact value of the acceleration depends on the radius of the shell, which is not provided in the problem.

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