newton's first law is often called the law of inertia and is based on the work of carson kepler galileo hawkinT/F

If a ball is given a push so that it has an initial velocity of 2 m/s down a certain inclined plane, then the distance it has rolled after t seconds is s = 2t + t². Then it takes 11 seconds for the velocity to reach 24 m/s. The correct option is D.

To find the time it takes for the velocity of the ball to reach 24 m/s, we need to solve for the time when the velocity function equals 24 m/s.

The velocity function is the derivative of the distance function, so we'll first find the derivative of the distance function s = 2t + t² with respect to time t:

ds/dt = d/dt(2t + t²)

ds/dt = 2 + 2t

Now we can set the velocity function equal to 24 m/s and solve for t:

2 + 2t = 24

Subtracting 2 from both sides:

2t = 22

Dividing both sides by 2:

t = 11

Therefore, it takes 11 seconds for the velocity to reach 24 m/s.

The correct answer is (d) 11 seconds.

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Answer:

The force of gravitational attraction is 8.454 x 10⁻⁸ N.

Explanation:

Given;

mass of the boy, m₁ = 78 kg

mass of the girl, m₂ = 65 kg

distance between the boy and the girl, r = 2 meters

The force of gravitational attraction is given as;

\(F = \frac{Gm_1m_2}{r^2}\)

where;

G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

r is the distance between two masses, m₁ and m₂

\(F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67 \times 10^{-11})(78 \times 65)}{2^2}\\\\F = 8.454 \times 10^{-8} \ N\)

Therefore, the force of gravitational attraction is 8.454 x 10⁻⁸ N.

Therefore, approximately 45.89 kg of coal can be brought to the surface per minute.

The amount of coal that can be brought to the surface per minute can be determined using the power supplied by the engine and the vertical distance the coal is lifted.

To calculate the amount of coal, we need to use the formula:

Power = Work / Time

Given that the power supplied by the engine is 475 W and the vertical distance is 63 m, we can rearrange the formula to solve for the work done:

Work = Power x Time

Since we are interested in the amount of coal per minute, we can convert the power from watts to joules per minute:

475 W x (60 seconds/minute) = 28500 J/min

Now, we can plug in the values for work and power into the formula to solve for time:

Work = Power x Time
28500 J/min = Work

Since we are interested in the amount of coal, we can use the equation:

Work = Force x Distance

Given that the force of gravity is acting on the coal, we can use the formula:

Force = mass x gravity

Since we are solving for the mass of the coal, we can rearrange the formula to:

mass = Work / (gravity x Distance)

Plugging in the values for work (28500 J/min), gravity (9.8 m/s^2), and distance (63 m), we can calculate the mass of the coal per minute:

mass = 28500 J/min / (9.8 m/s^2 x 63 m)

mass = 45.89 kg/min

Therefore, approximately 45.89 kg of coal can be brought to the surface per minute.

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Answer:

Compared to the station, are the passengers moving or stationary? Why?

The two is not moving ..

because the newton or the movement

of the passenger and the stationary are equal

they are not move they stay in there places

Answer:

-3.5 m/s²

Explanation:

We know that :-

\(\longrightarrow \) Stopping distance = u²/2(-a)

\(\longrightarrow \) 63m = (21m/s)² / -2a

\(\longrightarrow \) a = - 21 * 21 / 63 * 2 m/s²

\(\longrightarrow \) a = - 3.5 m/s²

**Edits are welcomed**

Given:

The mass of the car is m = 1725 kg

The initial velocity of the car is

The final velocity of the car is

The time is t = 4.4 s

To find the applied force.

Explanation:

The force can be calculated by the formula

Here, a is the acceleration.

The acceleration can be calculated as

On substituting the values, the force applied will be

Thus, the applied force is 3527.625 N

The number of photons in the pulse is 1.21 × 1022.

The energy of a photon can be calculated using the equation:

E = hf, where

E is the energy of a photon,

h is the Planck's constant, and

f is the frequency of the light.

Then, using the equation c = λf, where

c is the speed of light,

λ is the wavelength of the light and

f is the frequency of the light, the frequency of the light can be determined.

Planck's constant (h) is a fundamental constant in quantum mechanics that relates the energy of a photon to its frequency.

Its value is 6.626 × 10-34 joule seconds (J·s).

The frequency of the light is:

f = c / λ

= 3.00 × 108 / 480 × 10-9

= 6.25 × 1014 Hz

The energy of the photon can be calculated:

E = hf

= 6.626 × 10-34 × 6.25 × 1014

= 4.14 × 10-19 J

The number of photons can be determined by dividing the energy of the pulse by the energy of a photon:

n = E / E_photon

= 5.0 × 103 / 4.14 × 10-19

= 1.21 × 1022 photons

Therefore, the number of photons in the pulse is 1.21 × 1022.

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A 1Msun star in a closed binary system with a 2Msun star.

Systems in which the two stars are close to each other are called close binary star system.

The most massive stars have the shortest lifespans. The reason is that they have most fuel, they burn it so enormously that their lifetimes are very short. As a 1Msun star in a closed binary system with a 2Msun star becomes the massive star so it has the shortest life expectancy.

a. No, an isolated 1Msun star has not the shortest life expectancy.

b. No, a 1Msun star in a closed binary system with a 0.8Msun star has not the shortest life expectancy.

c. Yes, A 1Msun star in a closed binary system with a 2Msun star has the shortest life expectancy.

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Density is a measure of how much mass is contained within a given volume.  An object with a density of 1000 kg/m³ is denser than an object with a density of 1 g/cm³.

Density is a measure of how much mass is contained within a given volume. The formula for density is mass divided by volume (ρ = m/V). In the metric system, density is commonly expressed in kilograms per cubic meter (kg/m³) or grams per cubic centimeter (g/cm³).

Comparing the given densities, we can see that 1 g/cm³ is equivalent to 1000 kg/m³ since there are 1000 grams in a kilogram and 1 cubic meter is equal to 1,000,000 cubic centimeters. Therefore, the object with a density of 1000 kg/m³ has a higher mass per unit volume compared to the object with a density of 1 g/cm³.

This means that for the same volume, the object with a density of 1000 kg/m³ contains more mass, making it denser than the object with a density of 1 g/cm³. In simpler terms, if you were to compare objects of the same size, the object with the higher density would feel heavier because it has more mass packed into the same amount of space.

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The reading which shows the precision of a Vernier calipers reading to one tenth of a millimeter is 3.31cm. Thus, the correct option is B.

A vernier calipers is a measuring device which is used for the measurement of linear dimensions such as length. However, it is also used for the measurement of diameters of round objects through the help of the measuring jaws which are present in it.

Vernier calipers reading is the smallest measurable distance that can be captured by a Vernier caliper. It is termed as the resolution of the Vernier caliper. The resolution of metric Vernier calipers varies from 0.02mm to 0.05mm that is it reads to one tenth of a millimeter unit. Thus, 3.31cm is a precise reading.

Therefore, the correct option is B.

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To calculate the cost of delivering 10 kW of power to a home 100 miles away, we can start by drawing a schematic of the power transmission process.

The power is generated at a generating station with a voltage of less than 35,000 V. It is then stepped up using a transformer to a higher voltage of typically 345,000 V for transmission through power lines. Next, it is stepped down to 13,800 V for local transmission and finally, another step down transformer is used to bring the voltage down to 120 V for residential customers.

Now, let's calculate the cost per unit time to deliver 10 kW to the house.

First, we need to convert 10 kW to kilowatt-hours (kWh). Since power is measured in watts and time is measured in hours, we can divide 10 kW by the power factor (PF) to get the energy consumed in one hour.

The power factor is the ratio of real power (watts) to apparent power (volt-amperes). In this case, we assume an ideal power factor of 1, so the real power and apparent power are the same.

Since power is given in kilowatts (kW), we can convert it to watts by multiplying by 1000. So, 10 kW is equal to 10,000 watts.

Now, we need to find the energy consumed in one hour (kWh). We can use the formula:

Energy (kWh) = Power (watts) * Time (hours) / 1000

Plugging in the values, we get:

Energy (kWh) = 10,000 watts * 1 hour / 1000 = 10 kWh

Next, we need to calculate the cost of 10 kWh at a rate of 10 cents per kWh.

Cost = Energy (kWh) * Rate ($/kWh) = 10 kWh * $0.10/kWh = $1

So, it would cost $1 per unit time to deliver 10 kW to a house located 100 miles away when transmitting electricity at 120 V and 60 Hz.

Now, let's move on to the power factor in the problem above. Since we assumed an ideal power factor of 1, the power factor is 1.

If a large capacitor of 1F is used in parallel with the line coming into the house to filter out noise, we need to calculate the power lost in delivery. Assuming the same 10 kW load in parallel with the capacitor, we need to consider the power factor again.

In this case, the power factor will be affected by the reactive power of the capacitor. Reactive power is caused by the reactive components in the circuit, such as capacitors and inductors. To calculate the power factor, we need to know the reactive power and the apparent power.

The apparent power can be calculated using the formula:

Apparent Power (VA) = Voltage (V) * Current (A)

Since the load is parallel with the capacitor, the current will be the same for both the load and the capacitor. Therefore, the apparent power will be the same as the power consumed by the load.

Now, let's consider how to reduce the power factor and make it unity. The power factor can be improved by adding a power factor correction device, such as a capacitor or an inductor, to the circuit. These devices help to offset the reactive power and bring the power factor closer to unity (1).

In terms of resonance in a LCR circuit model, the inductor plays a role in storing and releasing energy in the form of a magnetic field. When the circuit is at resonance, the inductor and capacitor exchange energy back and forth, resulting in a high level of voltage and current oscillation. This can lead to increased losses and lower power factor if not properly managed.

The inductor current is determined by the inductance value and the rate of change of current flowing through it. It opposes changes in current, and in a resonant circuit, it helps to maintain a stable current flow.

The capacitor current is determined by the voltage across the capacitor and the capacitance value. It leads the voltage and helps to maintain a stable voltage across the capacitor.

to calculate the cost of delivering 10 kW to a home 100 miles away, we need to consider the power factor, energy consumption, and rate. Adding a large capacitor in parallel with the load can affect the power factor and result in power losses. Power factor can be improved by adding power factor correction devices. The inductor and capacitor in a resonance circuit play roles in storing and releasing energy.

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Answer:

104 IMA

Explanation:

Answer:

i think its  Russia, USA, Germany.

Answer:

Neptune or Uranus.

Explanation:

The blue skies and rapid tilt

Answer:

I don't know to be honest

The time required for the first-order reaction with a rate constant of 7.5 × 10–3 s–1 to be complete is determined by the initial concentration of the reactant.

The time required for a first-order reaction with a rate constant of 7.5 × 10–3 s–1 to be complete can be calculated using the formula:

Time = (1/rate constant) x ln(1/[A]0)

Where [A]0 is the initial concentration of the reactant.

In this case, the time required for the reaction to be complete is:

Time = (1/7.5 x 10–3 s–1) x ln(1/[A]0)

Therefore, the time required for the first-order reaction with a rate constant of 7.5 × 10–3 s–1 to be complete is determined by the initial concentration of the reactant.

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import numpy as np:

random_vector = np.random.rand(15)

modified_vector = np.where(random_vector == np.max(random_vector), -1, random_vector)

print("Original Array:", random_vector)

print("Modified Array:", modified_vector)

A NumPy program that creates a random vector of size 15, replaces the maximum value with -1, and prints both the original array and the modified array:

```python

import numpy as np

# Create a random vector of size 15

random_vector = np.random.rand(15)

# Find the maximum value in the vector

max_value = np.max(random_vector)

# Replace the maximum value with -1

modified_vector = np.where(random_vector == max_value, -1, random_vector)

# Print the original and modified arrays

print("Original Array:")

print(random_vector)

print("\nModified Array:")

print(modified_vector)

```

When you run this program, it will generate a random vector of size 15 and display the original array. Then, it will replace the maximum value in the array with -1 and display the modified array.

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Answer:

65

Explanation:

50+3*5

Answer:

A) but be sure and read the answer.

Explanation:

If the object does not move at all, (that's an important restriction) the net force = 0. That being so, the acceleration must be 0 as well. But there is no law saying that there cannot be a constant motion and that's why the restriction is important.

The final velocities of the truck and car after the collision are both 13.0 m/s and 0 m/s, respectively.

To solve this problem, we can use the conservation of momentum and kinetic energy:

Conservation of momentum:

m1v1 + m2v2 = m1v1' + m2v2'

where

m1 = 1690 kg (mass of the truck)

v1 = 13.0 m/s (initial velocity of the truck)

m2 = 615 kg (mass of the car)

v2 = 0 m/s (initial velocity of the car)

v1' = final velocity of the truck

v2' = final velocity of the car

Solving for v1' and v2':

m1v1 + m2v2 = m1v1' + m2v2'

1690 kg * 13.0 m/s + 615 kg * 0 m/s = 1690 kg * v1' + 615 kg * v2'

21970 kg m/s = 1690 kg * v1' + 0 kg m/s

v1' = 21970 kg m/s / 1690 kg = 13.0 m/s

So the truck maintains its initial speed of 13.0 m/s after the collision.

Now let's solve for the final velocity of the car:

m1v1 + m2v2 = m1v1' + m2v2'

1690 kg * 13.0 m/s + 615 kg * 0 m/s = 1690 kg * 13.0 m/s + 615 kg * v2'

0 kg m/s = 0 kg m/s + 615 kg * v2'

v2' = 0 m/s

So the car comes to a complete stop after the collision.

Therefore, the final velocities of the truck and car after the collision are both 13.0 m/s and 0 m/s, respectively.

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Answer:

its Solid

Explanation:

Molecules in the solid phase has the least amount of energy, while the gas particles has the greatest amount of energy.

Answer:

Solid

Explanation:

Molecules in the solid phase have the least amount of energy, while gas particles have the greatest amount of energy. The temperature of a substance is a measure of the average kinetic energy of the particles.

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The discharge of the stream is 400 cubic feet per second.

An area of flowing water on Earth's surface is called a stream. Stream and river are frequently used interchangeably, while rivers typically refer to bigger streams.

Humans gain various advantages from streams. In addition to supplying drinking water and agriculture irrigation, streams also wash away trash and have the potential to generate electricity through hydropower. Streams are frequently used recreationally by people for activities like swimming, fishing, and boating. Additionally, streams are crucial habitat for species.

Speed of water = 10 feet per second

The cross sectional area of the pipe = 40 square feet

The volume moving out per second = ?

The volume of water moving    = 10 feet per second x 40 square feet

out per second

=> volume moving out per second = 400 cubic feet square

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Answer:

8.6348020882604e-23

Explanation:

answer

64 is C (c) 1-Bromo-3-methylbutane

63 is D

i is secondary ii is primary

The energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.

To calculate the energy per photon, we can use the equation: E = hf, where E represents the energy, h is the Planck's constant (6.62607015 × 10^-34 J·s), and f is the frequency of the photon. Given that the frequency is 1260 kHz, we need to convert it to hertz (Hz) by multiplying it by 10^3:

Frequency = 1260 kHz × 10^3 = 1.26 × 10^6 Hz

Now, we can substitute the values into the equation:

E = (6.62607015 × 10^-34 J·s) × (1.26 × 10^6 Hz)

E = 8.33929859 × 10^-28 J

The answer is given in scientific notation as 8.34 × 10^-28 J. However, the question specifically asks for the answer in the format of 0.00×10^0. To achieve this, we can multiply the result by 10^3 and adjust the exponent accordingly:

E = (8.33929859 × 10^-28 J) × (10^3)

E = 8.33929859 × 10^-25 J

Thus, the energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.

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Question: A 2.0 kg sphere with a velocity of 6.0 m/s collides head-on and elastically with a stationary 10 kg sphere, What is thier velocities after collision.

Answer:

v = 6 m/s, v' = 0 m/s

Explanation:

From the question,

For Elastic collision,

mu+m'u' = mv+m'v'......................... Equation 1

Where m = mass of the first sphere, m' = mass of the second sphere, u = initial velocity of the first sphere, u' = initial velocity of the second sphere, v = final veolocity of the first sphere, v' = final velocity of the second sphere.

Also,

The relative velocity before collision = relative velocity after collision

u-u' = v-v'............................ Equation 2

Given:  m = 2 kg, m' = 10 kg, u = 6 m/s, u' = 0 m/s

Substitute into equation 1 and 2

2(6)+10(0) = 2v+10v'

2v+10v' = 12.............. Equation 3

6-0 = v-v'

v-v' = 6 ................... Equation 4

Solve equation 3 and 4 simultaneously.

v = 6+v'............. Equation 5

Substitute equation 5 into equation 3

2(6+v')+10v' = 12

12+2v'+10v' = 12

12v' = 12-12

v' = 0/12

v' = 0 m/s.

Also substitute the value of v' into equation 5

v = 6+0

v = 6 m/s

The energy released when tritium decays by β-emission is approximately 18.01 MeV.

The decay of tritium (H-3 or T) by β-emission results in the formation of helium-3 (He-3) and an electron (β-particle).

The energy released during this decay process can be calculated using the mass-energy equivalence principle, E = mc^2, where E is the energy, m is the mass, and c is the speed of light.

The mass difference between tritium and the decay products (He-3 and the electron) corresponds to the energy released.

The atomic mass of tritium (T) is approximately 3.01604927 atomic mass units (u), while the combined atomic masses of helium-3 (He-3) and the electron (β-particle) are approximately 3.01493244 u.

The mass difference is:

Δm = (mass of tritium) - (mass of helium-3 + mass of electron)

   = 3.01604927 u - (3.01493244 u)

   = 0.00111683 u

Using the conversion factor of 1 u = 931.494095 MeV/c^2, we can convert the mass difference to energy:

ΔE = Δm * (931.494095 MeV/c^2)

   = 0.00111683 u * (931.494095 MeV/c^2)

   ≈ 1.039 MeV

Rounding to four significant figures, the energy released when tritium decays by β-emission is approximately 18.01 MeV.

The energy released when tritium decays by β-emission is approximately 18.01 MeV.

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Answer: They have different rigidities.

Explanation:

The given function is f(t)=t3(1−2t2)The velocity of a particle is represented by the derivative of the position of the particle with respect to time. Thus, we need to find the derivative of the given function f(t) to find the velocity of the particle.

Let us differentiate f(t) by using the product and chain rule of differentiation:f(t)=t3(1−2t2)⇒ f′(t)=3t2(1−2t2)+t3(−4t)⇒ f′(t)=3t2−6t4−4t4The velocity of the particle at any given time is the absolute value of the derivative of the position function at that time. Thus, to find the velocity of the particle at t = 1, we will substitute t = 1 in the derivative function:f′(1)=3(1)2−6(1)4−4(1)4=3−6−4=−7.

Therefore, the speed of the particle at t = 1 is 7, which is option C).The definition of speed and velocity:Speed is the magnitude of velocity. It can be calculated as follows:|v|=|dx/dt|Where v is velocity, and x is the position of the object. The absolute value of the velocity of the particle is the speed of the particle.

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