Answers
Answer:
False.
Step-by-step explanation:
The difference between the proton and neutron is that the neutron's second down quark is heavier than the proton's second-up quark. Therefore, the neutron has a greater mass than the proton.
Related Questions
Giving Brainliest!
Temperature is a vector quantity because it can go down as well as up. True or false?
Answers
Answer:
Explanation:
temperature is a scalar quantity
Using the Left Hand Rule, if motion is toward you and the field is up, which way is the current?
A. Left
B. Right
C. Toward you
D. Away from you
Answers
C
Explanation:
Just trust
A major point of understanding natural selection is that not all organisms in a population get to reproduce. How does this apply to these frogs?
Answers
Answer:
The term fitness refers to the measure of reproductive success that an organism displayed; It has to do with the number of offspring that an organisms leave in the next generation compared to other organisms in the group. Populations usually evolve by natural selection. In natural selection, organisms with Inheritable traits, which help them to survive and reproduce tend to leave more children than the other organisms. Overtime, the feature that help the organisms to survive will become more common in the population and make the animals more suited to their habitats.
Calculate the electric potential at the center of the square described as follows: Four charges are placed at the corners of a 20 cm square. The particles are as follows: 10 microC at x =0, y = 0, -5 microC at x = 20, y = 0, -15 microC at x = 20, y = 20, and 20 microC at x=0 and y = 20 .
Answers
, the answer is 2020 kV
Explanation
Electric potential of a point charge is
\(\begin{gathered} V=\frac{KQ}{d} \\ where\text{ kis a constant k=9*10}^9\text{ N*}\frac{m^2}{C^2} \\ Q\text{ is charge , d is the distance} \end{gathered}\)so
Step 1
Diagram:
Step 2
distances:fromthe center to each charge:
:
\(\begin{gathered} d=\sqrt{0.10^2+0.10^2}=\sqrt{0.02}\text{ m=0.1414m} \\ d=0.1414\text{ m} \end{gathered}\)
Step 3
electric potential due to each charge.
a) Q1
\(\begin{gathered} V=\frac{KQ}{d} \\ V=\text{9*10}^9\text{ N*}\frac{m^2}{C^2}*\frac{10*10^{-6}C}{0.1414\text{ m}} \\ V=636.49\text{ kV} \\ \end{gathered}\)b)Q2
\(\begin{gathered} V=\frac{KQ}{d} \\ V=\text{9*10}^9\text{ N*}\frac{m^2}{C^2}*\frac{-5*10^{-6}C}{0.1414\text{ m}} \\ V=-318.24\text{ KV} \\ \end{gathered}\)c)Q3
\(\begin{gathered} V=\frac{KQ}{d} \\ V=\text{9*10}^9\text{ N*}\frac{m^2}{C^2}*\frac{-15*10^{-6}C}{0.1414\text{ m}} \\ V=-954.73\text{kV} \\ \end{gathered}\)d)Q4
\(\begin{gathered} V=\frac{KQ}{d} \\ V=\text{9*10}^9\text{ N*}\frac{m^2}{C^2}*\frac{20*10^{-6}C}{0.1414\text{ m}} \\ V=-954.73\text{kV} \\ V=1272.98\text{ kV} \end{gathered}\)so, the resultant electric potential are:
:
So
\(\begin{gathered} v=\sqrt{1309.2^2+1591.22^2} \\ v=2060\text{ Kv} \end{gathered}\)therefore, the answer is 2020 kV
I hope this helps you
Which is missing square?
Need reason, how comes to get the answer. Thank you
Answers
The missing square in the given sequence is a large dot without circle.
option C.
What is a sequence?A sequence refers to an ordered collection of objects, typically numbers or other mathematical entities, arranged in a specific order according to a well-defined rule. Each object in the sequence is called a term or an element of the sequence.
In the given sequence, we can notice that it alternates between two circles and a circle.
From the first sequence, it has 2 circles and large dot, the second has one circle and a dot.
The third sequence has a small circle and a larger dot, so the next sequence will have no circle and a large dot.
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A puffin accidentally drops a 0.3 kg fish from a height of 9 meters. What is the fish's GPE (in J) from this height?
Answers
Answer:
Therefore, the GPE of the fish from the given height is 26.19 J.
Explanation:
The gravitational potential energy (GPE) of an object at a height h is given by the formula:
GPE = mgh
where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.
In this case, the mass of the fish is 0.3 kg, the height from which it was dropped is 9 meters, and the acceleration due to gravity on Earth is approximately 9.81 m/s². Thus, the GPE of the fish can be calculated as:
GPE = (0.3 kg) × (9.81 m/s²) × (9 m) = 26.19 J
Therefore, the GPE of the fish from the given height is 26.19 J.
I like puffins
The show waterbell Nowing into a pool of water
Which statement des describes the energy of the objects in the drawing?
The pool of water has more kinetic energy and the falling water has more potential energy.
The falling water has potential energy and the rock over which it flows has kinetic energy
The water has potential energy at the top of the waterfall and increasing kinetic energy as it falls.
The water at the top of the fall has kinetic energy that becomes potential energy as it falls into the pool.
Answers
Answer:
The water has potential energy at the top of the waterfall and increasing kinetic energy as it falls.
Explanation:
Why must humans limit their exposure to X-rays and gamma rays?
A. The rays can change molecules and atoms in the body into ions.
B. Exposure can cause the human body to give off heat.
O C. Even a small amount of radiation can burn the skin.
D. These rays act similarly to microwaves on the human body.
Answers
Answer:
A. The rays can change molecules and atoms in the body into ions.
Two vectors are being added, one at an angle of 20.0 , and the other at 80.0. The only thing you know about the magnitudes is they are both positive. Will the equilibrant vector be in the:
a. first quadrant
b. second quadrant
c. third quadrant
d. fourth quadrant
e. you cannot tell which quadrant from the available information
Answers
Answer:a
Explanation: they are all positive
The equivalent vectors of both the vectors lie in the first quadrant. So, the right choice is a. first quadrant.
How the resultant of the vectors can be calculated?The resultant of the vectors can be calculated using the Parallelogram theorem of vector addition. In this theorem, a parallelogram is formed using the vectors, having the vectors as the adjacent side and the diagonal of this parallelogram is the resultant of both the vectors.
How the theorem is implemented to find out the resultant?The vectors A and B are drawn at the given angle, angles of 20° and 80° respectively. Using the vectors, A and B, the dotted parallelogram is drawn, and the vector C is the resultant.
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A grandfather clock works by swinging a pendulum back and forth with a
period of 2 seconds. What is the frequency?
Answers
Answer:
For example, a wave with a time period of 2 seconds has a frequency of
1 ÷ 2 = 0.5 Hz.
Explanation:
How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food
A. The amount of oxygen in the atmosphere increased
B. Mass extinctions occurred
C. The oceans became larger
D. Rainfall increased
Answers
A toy is undergoing SHM on the end of a horizontal spring with force constant 310 N/m . When the toy is 0.120 m from its equilibrium position, it is observed to have a speed of 3 m/s and a total energy of 3.6 J .
1.) Find the mass of the toy.
2.) Find the amplitude of the motion.
3.) Find the maximum speed obtained by the object during its motion.
Answers
Answer:
1) the mass of the toy is 0.304 kg
2) the amplitude of the motion is 0.1524 m
3) the maximum speed obtained by the object during its motion is 4.87 m/s
Explanation:
Given the data in the question;
force constant of spring k = 310 N/m
position of toy x = 0.120 m
speed v = 3 m/s
Total energy E = 3.6 J
let m represent mass of toy.
1.) Find the mass of the toy.
we know that; The total energy of the system equals the sum of kinetic energy of the toy and the potential energy of the spring;
E = \(\frac{1}{2}\)kx² + \(\frac{1}{2}\)mv²
we substitute
3.6 = ( \(\frac{1}{2}\) × 310 × (0.120)² ) + ( \(\frac{1}{2}\) × m × (3)² )
3.6 = 2.232 + 4.5m
3.6 - 2.232 = 4.5m
1.368 = 4.5m
m = 1.368 / 4.5
m = 0.304 kg
Therefore, the mass of the toy is 0.304 kg
2) Find the amplitude of the motion.
we know that;
E = \(\frac{1}{2}\)kA²
where A is the amplitude of the motion,
we substitute
3.6 = \(\frac{1}{2}\) × 310 × A²
3.6 = 155 × A²
A² = 3.6 / 155
A² = 0.0232258
A = √0.0232258
A = 0.1524 m
Therefore, the amplitude of the motion is 0.1524 m
3) Find the maximum speed obtained by the object during its motion;
we know that;
E = \(\frac{1}{2}\)m\(v_{max\)²
where \(v_{max\) is the maximum speed
so we substitute
3.6 = \(\frac{1}{2}\) × 0.304 × \(v_{max\)²
3.6 = 0.152 × \(v_{max\)²
\(v_{max\)² = 3.6 / 0.152
\(v_{max\)² = 23.6842
\(v_{max\)² = √23.6842
\(v_{max\)² = 4.8664 ≈ 4.87 m/s
Therefore, the maximum speed obtained by the object during its motion is 4.87 m/s
Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?
Answers
The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:
Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)
ω ≈ 115.28 rad/s
The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².
Use the formula for rotational kinetic energy:
Rotational Kinetic Energy (KE_rot) = (1/2) I ω²
Substituting the given values:
KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²
Calculate the value inside the parentheses:
KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)
KE_rot ≈ 1.331 × 10^-3 J
Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.
KE_rot ≈ 4.8 × 10^-4 J
Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
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2. For electric circuit shown in Figure find currents in each resistor.
Answers
The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.
What is the current flowing in each resistor?The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;
The total voltage in loop 1 is calculated as;
2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
The current flowing in loop 2 is calculated as;
I = V/R
I₂ = ( 6 V - 4 V ) / (3 + 4)
I₂ = 0.286 A
The value of the current flowing in loop 1 is calculated as;
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0
6 - 3I₁ - 3₁ + 0.858 = 0
-6I₁ = -6.858
I₁ = 6.858 / 6
I₁ = 1.14 A
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the mass of the velociraptor and cage together is 175 kg. What is the gravitational potential energy added when when the velociraptor and cage is lifted from the ground to a height of 9 m?
Answers
The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.
What is Potential Energy?
Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.
The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:
GPE = mgh
Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.
Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:
GPE = mgh
GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)
GPE = 15,998.95 J (joules)
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What is molecular magnet?
Answers
Answer:
A molecular magnet is a type of compound that displays magnetic behavior at the molecular level. These compounds contain metal ions with unpaired electrons that can align their magnetic moments in response to an external magnetic field. The properties of molecular magnets are determined by the geometry and electronic structure of the molecule, as well as the interactions between individual molecules. Molecular magnets have potential applications in data storage, quantum computing, and magnetic resonance imaging (MRI).
Answer:
A molecule having a nonvanishing magnetic dipole moment, whether it is permanent or produced by an external field.
_____________________________
An object that is fired horizontally hits the ground in 0.500 seconds. If it had been fired with twice the speed, but still horizontally, it would have hit the ground in
Answer choices:
A) Less than 0.500s
B) More than 0.500s
C) 0.500s
D) Not enough Information
Answers
The answer is (C), 0.500s.
This is because in both instances the bullet is fired with all horizontal speed, meaning the initial vertical component of velocity (\(\vec v_{y}\)) will equal 0. We also know that vertical acceleration (\(\vec a_{y}\)) is the acceleration of gravity, which is 9.8 m/s^2. In both cases when the bullet is fired, the acceleration of gravity will pull them down in the same way. Thus, the time the bullet takes to hit the ground will be the same.
In short, because the velocity and acceleration is constant in the vertical direction, the bullets will fall in the same amount of time.
An unknown radioactive sample is observed to decrease in activity by a factor of two in a one hour period. What is its half-life?
Answers
Answer:
The half-life is \( t_{1/2} = 1.005 h\)
Explanation:
Using the decay equation we have:
\(A=A_{0}e^{-\lambda t}\)
Where:
λ is the decay constantA(0) the initial activityA is the activity at time tWe know the activity decrease by a factor of two in a one hour period (t = 1 h), it means that \(A = \frac{A_{0}}{2}\)
\(\frac{A_{0}}{2}=A_{0}e^{-\lambda*1 h}\)
\(0.5=e^{-\lambda*1 h}\)
Taking the natural logarithm on each side we have:
\(ln(0.5)=-\lambda\)
\(\lambda=0.69 h^{-1}\)
Now, the relationship between the decay constant λ and the half-life t(1/2) is:
\(\lambda = \frac{ln(2)}{t_{1/2}}\)
\( t_{1/2} = \frac{ln(2)}{\lambda}\)
\( t_{1/2} = \frac{ln(2)}{0.69}\)
\( t_{1/2} = 1.005 h\)
I hope it helps you!
Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1100-kg car was moving at 10.9 m/s and stopped in 0.159 seconds.
Answers
The change in momentum of Kara's car is -1.43 × 10⁴ kg.m/s, the magnitude of force is -1.021 × 10⁵ N.
What is Force?Force is the external agent which causes the motion of an object or it is the resistant which makes the object come at rest from motion. It is a vector quantity, because it has both the magnitude and direction.
Mass of Kara's car = 1300 Kg
moving with speed = 11 m/s
time taken to stop = 0.14 s
final velocity = 0 m/s
distance between Lisa ford and Kara's car = 30 m
a) change in momentum of Kara's car
Δ P = m Δ v
Δ P = m(vf - vi)
Δ P = 1300 (0 - 11)
Δ P = -1.43 × 10⁴ kg.m/s
The impulse is equal to the change in momentum of the car
I = -1.43 × 10⁴ kg.m/s
Magnitude of the force experienced by Kara
I = F × t
where, I is impulse acting on the car
t is time
- 1.43 × 10⁴ = F × 0.14
F = -1.021 × 10⁵ N
Negative sign represents the direction of the force.
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Your question is incomplete, most probably the complete question is:
Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1300-kg car was moving at 11 m/s and stopped in 0.14 seconds.
a. Determine the momentum change of Kara's car.
b. Determine the impulse experienced by Kara's car.
c. Determine the magnitude of the force experienced by Kara's car.
Suppose your actual height is 5 feet and 5.2 inches. A tape measure which can be read tothe nearest 1/8 of an inch gives your height as 65 3/8 inches. The laser device at the clinic that givesreadings to the nearest hundredth of an inch says you are 65.31 inches.
Required:
a. Which measuring device is more accurate?
b. Which measuring device is more precise?
Answers
Answer:
a) The laser device
b) The tape
Explanation:
First, there is a need to understand what accuracy and precision mean.
Accuracy is the closeness of a measurement to its true (pre-determined) value.
Precision is the closeness of repeated measurements to each other.
Since 1 feet = 12 inches, then, 5 feet and 5.2 inches would be equivalent to 65.2 inches. This value represents the true value of my height.
The tape measured the height as 65 3/8, which is equivalent to 65.375 inches.
The laser device measured the height as 65.31.
Error = true value - measured value
Absolute error from the tape = 65.2 - 65.375
= -0.175 inches
Absolute error from laser device = 65.2 - 65.31
= -0.11
a) The magnitude of error from the tape is more than that of the laser device. Hence, the laser device is said to be more accurate.
b) Even though there were just single readings from both instruments, the tape can be read to the nearest 1/8 of an inch and as such, can give more precisive measurements than the laser device.
help me get the answer in Physical Science.
Answers
Answer:
lithium
Explanation:
I took physical science 2 years ago and passed with an A
Which of the following is NOT a human blood type?
a.
O
c.
B
b.
AB
d.
R
Answers
Answer:
d. R
Explanation:
There are 4 main types of blood – A, B, AB and O.
Blood is the most important component of our life. It is a fluid connective tissue which consists of plasma, blood cells and platelets. It circulates throughout the body and delivers oxygen. Among the given options R is not a blood type. The correct option is D.
What are blood types?It was Karl Landsteiner who discovered the ABO blood group system. There are 4 main blood groups, they are A, B, AB and O. Your blood group is determined by the genes you inherit from your parents. Each blood group may be either RhD positive or RhD negative.
Blood group A has antigens on the red blood cells with anti-B antibodies in the plasma. Blood group B has B antigens with anti-A antibodies in the plasma. The blood group O has no antigens but both antibodies are present whereas AB has no antibodies.
Group O is the universal donor and AB is universal recepient.
Thus the correct option is D.
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On a warm summer day, a large mass of air (atmospheric pressure 1.01×105Pa) is heated by the ground to a temperature of 25.0 ∘C and then begins to rise through the cooler surrounding air. Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×104 Pa. Assume that air is an ideal gas, with γ=1.40. (This rate of cooling for dry, rising air, corresponding to roughly 1 ∘C per 100 m of altitude, is called the dry adiabatic lapse rate.)
Answers
The temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.
Using the ideal gas law, we can write: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the mass of air is not changing, we can write: PV = constant.
Applying this to the situation where the air mass rises to a level where the pressure is 8.70×10⁴ Pa, we get:
(1.01×10⁵ Pa)×V = (nR/T1)×T1(8.70×10⁴ Pa)×V = (nR/T2)×T2Dividing the second equation by the first and using the fact that γ=Cp/Cv=1.40 for air, we get:
(T2/T1) = [(P2/P1)^(γ-1)/γ] = [(8.70×10⁴ Pa)/(1.01×10⁵ Pa)]^(1.4/1.4) = 0.813Solving for T2, we get:
T2 = T1×(P2/P1)^(γ-1)/γ = (25+273) K×0.813 ≈ 287.3 K ≈ 14.3°CThus, the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.
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1-The amount of heat required to raise the temperature
of 1 g of a substance by degree celsius is
one
Answers
Answer:
• specific heat
1 Answer. The specific heat is the amount of heat required to raise the temperature of 1 g of substance by one degree Celsius or one Kelvin
A submarine has a 'crush depth" (that is, the depth at which water pressure will crush the submarine) of 100 m. What is the approximate pressure (water plus atmospheric) at this depth? (Recall that the density of seawater is 1025 kg/m³, g = 9.81 m/s², and 1 kg/(m•s²) = 1 Pa = 9.8692 x 10-⁶ atm.)
A) 10.9 atm
B) 9.9atm
C)37.9atm
D)25.9atm
Answers
Answer:
25.9atm
Explanation:
Answer: my grandfather was a marine so he kept me in check
25.8 atm
Explanation:
Total pressure is:
P = Patm + ρgh
where Patm is the atmosphere pressure,
ρ is the fluid density,
g is acceleration due to gravity,
and h is the depth of the fluid.
P = (1 atm) + (1025 kg/m³) (9.81 m/s²) (250 m) (9.8692×10⁻⁶ atm/Pa)
P = 1 atm + 24.8 atm
P = 25.8 atm
vector of magnitude 15 is added to a vector of magnitude 25. The magnitude of this sum
might be:
A. Zero
B.5
C.9
0 15
E.4
and how ?
Answers
Explanation:
Given that,
Magnitude of vector A, |A| = 15
Magnitude of vector B, |B| = 25
We need to find the magnitude of this sum.
The maximum sum of the resultant vector,
\(R_{max}=|A_1|+|A_2|\\\\=15+25\\\\=45\)
The minimum sum of the resultant vector,
\(R_{min}=|A_1|-|A_2|\\\\=15-25\\\\=-10\)
So, the magnitude of this sum either 45 or -10.
An 8.00-cm-diameter, 360 g solid sphere is released from rest at the top of a 2.00-m-long, 16.0 incline. It rolls, without slipping, to the bottom.
What is the sphere's angular velocity at the bottom of the incline?
What fraction of its kinetic energy is rotational?
Answers
Rotational kinetic energy makes for 0.94 of total kinetic energy.
How do you calculate a ball's rate of descent down a slope?To determine how the ramp's height affects the ball's speed, we may change the potential energy equation to be equal to the kinetic energy equation: mgh=12mv2 m g h = 1 2 m v 2 where m is the ball's mass, g is the ramp's height, and v is the ball's speed.
mgh = (1/2)mv² + (1/2)Iω²
A solid sphere possesses a (2/5)mr2 moment of inertia.
Substituting in the given values and solving for v, we get:(1/2)(0.36 kg)(9.81 m/s²)(2 m) = (1/2)(0.36 kg)v² + (1/2)(2/5)(0.36 kg)(0.04 m)²ω²
Simplifying and solving for v, we get:
v = 3.43 m/s
To find the angular velocity, we use the relationship between linear velocity and angular velocity:
v = rω
ω = v/r = (3.43 m/s)/(0.04 m) = 85.8 rad/s
The sphere at the bottom has the following kinetic energy:
(1/2)mv² = (1/2)(0.36 kg)(3.43 m/s)² = 0.89 J
The rotational kinetic energy is:
(1/2)Iω² = (1/2)(2/5)(0.36 kg)(0.04 m)²(85.8 rad/s)² = 0.84 J
The proportion of rotating kinetic energy is thus:
0.84 J / 0.89 J = 0.94
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pls hurry worth 28 points <3
At what point is the object moving the fastest and how do you know?
Question 13 options:
Point B because it has the steepest slope.
Point D because it has a slope of 0.
Point A because it is curved upward.
Point E because it curves down.
Answers
Answer:
Explanation:
I will GUESS that we're supposed to be looking at a plot of a position in time.
IF that is the case.
THEN the answer would be Point B because it has the steepest slope.
I HAVE A PHYSICS TEST, ITS 25 QUESTIONS AND I HAVE ABOUT AN HOUR TO SOLVE IT PLEASE IF YOU'RE GOOD AT PHYSICS CONTACT ME ASAP
Answers
Answer:
yes sir
Explanation:
Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next
Answers
Answer: Hope this helps ;) don't forget to rate this answer !
Explanation:
There are two correct answers:
A) A corporation leader makes direct payment to the candidate.
D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.
Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.
Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.
I hope this helps! Let me know if you have any other questions.