name the major differences in schemes and assimilation for a preoperational thinker (preschool years) as compared to a sensorimotor thinker (infancy)
Answers
In developmental psychology, there are many major differences in schemes and assimilation between a preoperational thinker (preschool years) and a sensorimotor thinker (infancy).
Developmental psychology is a subfield of psychology that focuses on the examination of how people evolve and develop throughout their lives. Physical, cognitive, and socioemotional development are just a few of the components of human development that are examined in this field of research.
The main differences in schemes and assimilation between a preoperational thinker (preschool years) and a sensorimotor thinker (infancy) can be summarized as follows:
Schemes: During the sensorimotor stage, newborns create schemes by using their perceptions and motor skills to explore the environment. Reflexes and physical interactions with the environment are the main foundations of these designs. In contrast, during the preoperational stage, kids create increasingly complex mental images of the environment, including concepts based on language and symbolic cognition.Assimilation: Assimilation in the sensorimotor stage is mostly focused on bodily movements and sensory encounters. Infants absorb new knowledge by integrating it into their preexisting schemas or by adapting their behavior to suit new experiences. As toddlers start to utilize mental representations to comprehend the environment in the preoperational stage, assimilation becomes more complicated. Egocentrism: During the preoperational stage, children are often egocentric, meaning they have difficulty seeing things from another person's perspective. This is a major difference from the sensorimotor stage, where infants are not yet capable of understanding other people's thoughts or intentions.Symbolic thought: One of the most significant changes in the preoperational stage is the development of symbolic thought. Children in this stage can use symbols, such as words and images, to represent objects, events, and ideas. In contrast, infants in the sensorimotor stage have limited symbolic abilities and rely primarily on their senses and physical interactions with the environment.To learn more about developmental psychology, refer to:
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The major differences are, Schemes,Assimilation,Object Permanence and Egocentrism
The major differences in schemes and assimilation for a preoperational thinker (preschool years) as compared to a sensorimotor thinker (infancy) are:
1. Schemes: In the sensorimotor stage, the child's schemes are based on sensorimotor actions and perceptions, such as grasping and mouthing objects. In the preoperational stage, the child's schemes become more mental and symbolic, such as using words and images to represent objects.
2. Assimilation: In the sensorimotor stage, the child's assimilation is based on the physical actions and objects in their environment. In the preoperational stage, the child's assimilation is more based on their own mental representations of objects and concepts.
3. Object Permanence: In the sensorimotor stage, the child develops the concept of object permanence, meaning they understand that objects exist even when they are out of sight. In the preoperational stage, the child's understanding of object permanence becomes more advanced and they can imagine objects in different locations or situations.
4. Egocentrism: In the preoperational stage, the child is more egocentric and has difficulty understanding other people's perspectives or beliefs. In the sensorimotor stage, the child is not yet capable of being egocentric as they do not yet have the mental capacity for such cognitive processes.
Overall, the preoperational stage marks a significant shift in a child's cognitive development, as they begin to develop more complex and abstract mental processes.
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Related Questions
A vertical spring has a spring constant k=32 N/m with a 2 kg mass connected to it. The spring is initially at rest and hanging at its equilibrium position. At t=0, a force is applied to the spring given by: F=128sin(4t). Neglecting air resistance or other damping forces, find the position of the mass as a function of time.
Answers
The position of the mass as a function of time is x(t) = 5 * sin(4t).
To find the position of the mass as a function of time, we can use Newton's second law of motion, which states that the sum of the forces acting on an object is equal to the mass of the object multiplied by its acceleration.
The equation of motion for a mass-spring system is given by:
m * d^2x/dt^2 + k * x = F(t)
Where:
m is the mass connected to the spring,
x is the position of the mass,
t is time,
k is the spring constant,
F(t) is the applied force as a function of time.
In this case, the mass m is 2 kg, the spring constant k is 32 N/m, and the applied force is given by F(t) = 128sin(4t).
Plugging these values into the equation of motion, we get:
2 * d^2x/dt^2 + 32 * x = 128sin(4t)
Rearranging the equation, we have:
d^2x/dt^2 + 16 * x = 64sin(4t)
This is a second-order linear ordinary differential equation with constant coefficients. To solve this equation, we can assume a solution of the form x(t) = A * sin(ωt + φ), where A is the amplitude, ω is the angular frequency, and φ is the phase angle.
Differentiating x(t) twice with respect to time, we have:
dx/dt = A * ω * cos(ωt + φ)
d^2x/dt^2 = -A * ω^2 * sin(ωt + φ)
Substituting these derivatives into the equation of motion, we get:
-A * ω^2 * sin(ωt + φ) + 16 * A * sin(ωt + φ) = 64sin(4t)
Equating the terms with sin(ωt + φ) on both sides, we have:
-A * ω^2 + 16 * A = 64
Simplifying the equation, we get:
16A - Aω^2 = 64
We know that the angular frequency ω is related to the spring constant k and the mass m as ω = √(k/m). Substituting the given values, we have:
ω = √(32 N/m / 2 kg) = √(16) = 4
Plugging ω = 4 into the equation, we get:
16A - 16 = 64
Solving for A, we have:
16A = 80
A = 5
Therefore, the amplitude A is 5.
Now, we can write the position function as:
x(t) = 5 * sin(4t + φ)
To find the phase angle φ, we can use the initial conditions. At t = 0, the spring is initially at rest and hanging at its equilibrium position, which means x(0) = 0.
Plugging this into the position function, we have:
0 = 5 * sin(0 + φ)
Since sin(0) = 0, we get:
0 = 0 + φ
φ = 0
Therefore, the phase angle φ is 0.
Finally, the position of the mass as a function of time is:
x(t) = 5 * sin(4t)
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If you have a piece of brass and a piece of aluminurn that have the same volume, which will have a larger mass?
Answers
Answer:
the aluminum would have the most mass
A student performed an investigation into the refraction of light in a transparent material.
The results are shown below:
The angle of refraction of the refracted ray through the material shown is 32o .
Use this information to calculate the critical angle of the transparent material
Answers
The critical angle of the transparent material is 35.3 degrees.
What is the critical angle?The critical angle is the angle of incidence at which the angle of refraction is 90 degrees. In this case, the angle of refraction is 32 degrees. Therefore, the critical angle is calculated as follows:
sin(critical angle) = sin(90 degrees) / sin(angle of refraction)
sin(critical angle) = 1 / sin(32 degrees)
sin(critical angle) = 0.574
critical angle = arcsin(0.574)
critical angle = 35.3 degrees
Therefore, the critical angle of the transparent material is 35.3 degrees.
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the uncompressed density of a planet in our solar system
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The uncompressed density of a planet in our solar system varies.
The uncompressed density of a planet in our solar system can vary depending on its composition and structure. Different planets have different compositions, including a mix of rock, metal, gas, and ice. This composition affects their overall density.
For example, terrestrial planets like Earth, Mercury, Venus, and Mars have relatively high uncompressed densities due to their rocky compositions. These planets have solid surfaces and a dense core made of metal and rock.
Gas giants like Jupiter and Saturn have lower uncompressed densities because they are composed mainly of hydrogen and helium gases. These planets have a thick atmosphere surrounding a core, but the overall density is much lower than that of terrestrial planets.
Ice giants like Uranus and Neptune have a combination of gases and icy materials, resulting in a slightly higher uncompressed density compared to gas giants.
It's important to note that the uncompressed density of a planet can vary within its interior, with different layers having different densities. This variation is due to differences in pressure, temperature, and composition as we move deeper into the planet.
Therefore, the uncompressed density of a planet in our solar system cannot be generalized, and it varies depending on the specific planet and its composition.
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A train is moving along a horizontal track. A pendulum suspended from the roof makes an angle of 4° with the vertical. If g=10m/s2, what is the acceleration of the train?
Answers
Answer:
Train accaleration = 0.70 m/s^2
Explanation:
We have a pendulum (presumably simple in nature) in an accelerating train. As the train accelerates, the pendulum is going move in the opposite direction due to inertia. The force which causes this movement has the same accaleration as that of the train. This is the basis for the problem.
Start by setting up a free body diagram of all the forces in play: The gravitational force on the pendulum (mg), the force caused by the pendulum's inertial resistance to the train(F_i), and the resulting force of tension caused by the other two forces (F_r).
Next, set up your sum of forces equations/relationships. Note that the sum of vertical forces (y-direction) balance out and equal 0. While the horizontal forces add up to the total mass of the pendulum times it's accaleration; which, again, equals the train's accaleration.
After doing this, I would isolate the resulting force in the sum of vertical forces, substitute it into the horizontal force equation, and solve for the acceleration. The problem should reduce to show that the acceleration is proportional to the gravity times the tangent of the angle it makes.
I've attached my work, comment with any questions.
Side note: If you take this end result and solve for the angle, you'll see that no matter how fast the train accelerates, the pendulum will never reach a full 90°!
A 8. 43-newton force was applied for an unknown displacement; however, it is known that 376 joules of work was done. What is the value of the mystery displacement?(1 point).
Answers
Answer:
8.74 m
Explanation:
W = FΔx
376 = 43(Δx)
8.74 = Δx
Hey there everyone!
_____________________________________________________
Answer:
So, if you have the following to choose from:
O 368 m
O 44.6 m
O 384 m
O 3170 m
44.6 m (aka. Option B) is correct.
_______________________________________________________
Step By Step Explanation:
1. F = 8.43 N
2. W = 376 J
3. W = F x d
4. 376 J = 8.43 N × d
5. d = 44.6 m ← Our Final Solution
_______________________________________________________
Hope this helps! If you still need help on this, feel free to check out the flash cards I made below.
h t t p s : / / q u i z l e t . c o m / 7 6 4 3 6 7 9 6 0 / p h y s i c a l - s c i e n c e - 2 2 - f o r c e - a n d - w o r k - r e l a t i o n s h i p s - f l a s h - c a r d s / ? n e w
28,800 C of charge flow through a lamp every hour. Calculate the current used by this lamp
Answers
This lamp's estimated current consumption is 8 amperes.
What is electric current ?Electric current is the rate of charge (electron) passing in a conductor. The SI unit for electric current is the ampere. As current does not obey vector addition, it is a scalar quantity.
Given information:
amount of charge flowing through the lamp, Q = 28800 C;
The charge flow time was t = 1 hour = 3600 seconds.
Hence, the current passing through the bulb as a result.
I = Q/t
= 28800/3600 ampere,
= 8 ampere
Therefore, this lamp consumes 8 amperes of current.
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How and where is old oceanic crust destroyed?
Answers
Answer:
It is destroyed in subduction zones. A Geologic process in which a tectonic plate made of dense lithospheric material melts or falls below a plate made of less-dense lithosphere at a convergent plate boundary
Explanation:
Hope this helps (:
if we measure the speed of rotation of a system (held together by gravity) at different distances d from the center, and we find that it does not fall as but that it stays more or less flat as far as we can measure it, it means that
Answers
As the distance from the centre grows, a system bound together by gravity has "constant rotational speed" or "constant angular velocity." Galaxies and whirling objects exhibit this phenomena.
Dark matter is commonly found in flat rotation curves with constant rotational speed. It implies that dark matter is needed to explain the observed rotating behaviour in astrophysics.
In such instances, the system is in rotational equilibrium because the centripetal forces induced by rotation balance the gravitational forces. This equilibrium maintains a constant rotational speed regardless of distance from the centre.
The conservation of angular momentum explains this behaviour. Unless torques act on a system, its total angular momentum remains constant. To balance gravitational and centripetal forces and preserve total angular momentum, the rotational speed may need to decrease as the distance from the centre rises.
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Mr. Wang works in a recycling center. Recyclable materials arrive at the
center mixed together. Workers use magnets to separate steel cans
from other items. Which two statements are true about the force
between a steel can and a magnet?
A. Gravity pushes the can toward the magnet.
B. The force between the can and the magnet is a noncontact force.
C. The attraction between the can and the magnet is a pull.
D. The attraction between the can and the magnet is a push.
Answers
PLEASE HELP. i will mark brainliest. and do more!
Answers
I would suggest an easier route. So for example, I would research light energy, where it comes from, and what causes it. I won't be able to do the work for you though.
An object is in equilibrium at 400 K. Calculate its change in Helmholtz free energy when heat is transferred from the object to lower its temperature to 282 K while the environment remains at 400 K. Assume that the heat capacity of the object is C=0.5 kJ K−1C=0.5 kJ K−1. Express your answer in kilojoules and round to 2 decimal places.
Answers
The change in Helmholtz free energy is when heat is transferred from the object to lower its temperature to 282 K while the environment remains at 400 K would be -67.83 kJ.
Determining free energy:
The change in Helmholtz free energy can be calculated using the equation:
ΔF = ΔU - TΔS
where ΔU is the change in internal energy, T is the temperature, and ΔS is the change in entropy.
First, we need to calculate the change in internal energy. Since the object is transferring heat to the environment, the change in internal energy is given by:
ΔU = -Q
where Q is the heat transferred. Using the equation for heat transfer:
Q = CΔT
where C is the heat capacity and ΔT is the change in temperature. In this case, ΔT = 400 K - 282 K = 118 K. Therefore:
Q = 0.5 kJ K^-1 * 118 K = 59 kJ
So, ΔU = -59 kJ.
Next, we need to calculate the change in entropy. Since the process is reversible (the object is in equilibrium), we can use:
ΔS = Q / T
where Q is the heat transferred and T is the temperature. In this case:
ΔS = 59 kJ / 400 K = 0.1475 kJ K^-1
Finally, we can calculate the change in Helmholtz free energy:
ΔF = ΔU - TΔS
ΔF = (-59 kJ) - (282 K)(0.1475 kJ K^-1)
ΔF = -67.83 kJ
Therefore, the change in Helmholtz's free energy is -67.83 kJ (rounded to 2 decimal places).
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The student hung the plastic strip over a wooden rod
Answers
Answer:
The main force in play here is weight W, or m*g (where m is Mass and g is Gravity) that make up the main force acting downwards. This could also be referred to as the normal force.
Explanation:
From what we can see the plastic strip is at a certain angle. To which other forces, such as: friction, pull and the ones mentioned above come into play in this question.
the bose? (The weightidensty of water is 62.4 pounds per outec foct.) 7f−lb [0/1 Points] LARCALCET7 7. 5,027Mi
Answers
The weight density of water is 62.4 pounds per cubic foot. This value is used to determine the weight of water based on its volume.
The weight density of a substance is a measure of how much weight it has per unit volume. In the case of water, its weight density is 62.4 pounds per cubic foot. This means that for every cubic foot of water, it will weigh 62.4 pounds.
Weight density is an important concept in various fields, such as engineering, construction, and fluid mechanics. It allows us to calculate the weight of water in different scenarios. For example, if we have a tank with a known volume of water, we can use the weight density to determine the total weight of the water in the tank. Similarly, if we know the weight of water in a container, we can calculate its volume by dividing the weight by the weight density.
Understanding the weight density of water is crucial for various practical applications. It helps in designing structures that involve water, such as dams, reservoirs, and pipes, as it provides insights into the forces exerted by the water. Additionally, it is also relevant in fields like hydrology and environmental science, where accurate measurements of water weight are necessary for calculations and analysis.
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How does kinetic energy play a role in phase change?
Answers
During phase shift, the substance's molecules' average kinetic energy remains constant.
How does kinetic energy affect phase change?Simply put, molecules move more quickly as kinetic energy rises. Nevertheless, molecules change phases when potential energy rises. The molecule changes phases as a result of an increase in potential energy.
In a phase change, matter moves from one state to another either by gaining energy through heat and entering a more energetic state, or by losing energy through heat and entering a state with lower energy.
The energy supplied during phase change is only used to separate the molecules; none of it is used to boost the kinetic energy of the molecules. Therefore, since the molecules' kinetic energy is constant, its temperature won't increase.
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(ii) Let R be a rotation and S be a reflection of the euclidean plane E. Give a precise deion of RS, relating it to the classification of isometries of E². Be careful of special cases.
Answers
RS is a composition of rotation and reflection in the Euclidean plane E². The precise description of RS depends on the specific properties of the rotation R and reflection S.
In general, if R and S have the same axis or line of symmetry, the composition RS results in a translation. If R and S have intersecting lines of symmetry, RS yields a glide reflection. If R and S have perpendicular lines of symmetry, RS produces a rotation.
It is important to consider special cases, such as parallel lines of symmetry, coinciding axes, or perpendicular lines of reflection, as they may lead to different outcomes. The classification of isometries in E² involves understanding how rotations and reflections combine to create different transformations in the plane.
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A long cylinder having a diameter of 2 cm is maintained at 600 °C and has an emissivity of 0.4. Surrounding the cylinder is another long, thin-walled concentric cylinder having a diameter of 6 cm and an emissivity of 0.2 on both the inside and outside surfaces. The assembly is located in a large room having a temperature of 27 °C. Calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length. Also calculate the temperature of the 6-cm- diameter cylinder
Answers
The net radiant energy lost by the 2-cm-diameter cylinder per meter of length is X Joules. The temperature of the 6-cm-diameter cylinder is Y °C.
To calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length, we need to consider the Stefan-Boltzmann law and the emissivities of both cylinders. The formula for net radiant heat transfer is given:
Q_net = ε1 * σ * A1 * (T1^4 - T2^4)
Where:
- Q_net is the net radiant energy lost per meter of length.
- ε1 is the emissivity of the 2-cm-diameter cylinder.
- σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/(m^2·K^4)).
- A1 is the surface area of the 2-cm-diameter cylinder.
- T1 is the temperature of the 2-cm-diameter cylinder.
- T2 is the temperature of the surroundings (27 °C).
To calculate the temperature of the 6-cm-diameter cylinder, we can use the formula for the net radiant energy exchanged between the two cylinders:
Q_net = ε1 * σ * A1 * (T1^4 - T2^4) = ε2 * σ * A2 * (T2^4 - T3^4)
Where:
- ε2 is the emissivity of the 6-cm-diameter cylinder.
- A2 is the surface area of the 6-cm-diameter cylinder.
- T3 is the temperature of the 6-cm-diameter cylinder.
By solving these equations simultaneously, we can find the values of Q_net and T3.
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A long cylinder having a diameter of 2 cm is maintained at 600 °C and has an emissivity of 0.4. Surrounding the cylinder is another long, thin-walled concentric cylinder having a diameter of 6 cm and an emissivity of 0.2 on both the inside and outside surfaces. The assembly is located in a large room having a temperature of 27 °C. Calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length. Also, calculate the temperature of the 6-cm-diameter cylinder
Which of the following statement/s is/are true? Check all that apply. Jupiter's Great Red Spot is in the southern hemisphere of the planet The fastest wind speed recorded in our solar system is on the dwarf planet Pluto Neptune's Great dark spot is in the northern hemisphere of the planet Water geyser is located on the South Pole of Saturn's Moon Enceladus The Hexagon hurricane is on the North Pole of the planet Uranus
Answers
The true statements are:Jupiter's Great Red Spot is in the southern hemisphere.The fastest wind speed recorded in our solar system is on Neptune.
Among the given statements, only two are true. Jupiter's Great Red Spot, a massive storm, is indeed located in the southern hemisphere of the planet. The Great Red Spot is a prominent feature on Jupiter, visible as a giant swirling storm system. On the other hand, the fastest wind speed recorded in our solar system, reaching speeds of up to 2,100 kilometers per hour (1,300 miles per hour), is found on Neptune.
The strong winds on Neptune contribute to its dynamic atmosphere and the formation of features like the Great Dark Spot. The remaining statements about Pluto, Saturn's moon Enceladus, and Uranus are not true according to our current understanding.
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Regarding Newton's 3rd Law, do we always see an equal effect on each object? Aka, are both objects always affected the same? Why so?
Answers
Answer:
not always ot depends mostly on the mass of each object and how the collode
PLEASE HELP!!!!!
The time needed for a water wave to change from the equilibrium level to the crest is 0.5731 s.
1. What is the period of the wave? Answer in units of s.
2. What is the frequency of the wave? Answer in units of Hz.
Answers
The time taken to reach one crest is 0.5731 s. Then the time period of the wave is 1.146 s. The frequency is the inverse of the period that is 0.87 Hz.
What is period of wave ?The time period of a wave is the time required to complete one wave cycle. For a transverse wave the period of the wave is the time required to reach from one crest to the next crest of the wave.
Given that, time to reach one crest = 0.5731 s.
then the time for to the next crest from the equilibrium position is :
T = 0.5731 s× 2 = 1.146 s.
Frequency of a wave is the number of wave cycles per second. It is the inverse of time period of the wave.
Hence, frequency = 1/T
ν = 1/ 1.146 s = 0.87 Hz.
Therefore, the period of the wave is 1.14 s and frequency is 0.87 Hz.
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A 25.0 kg door is 0.925 m wide. A customer
pushes it perpendicular to its face with a 19.2
N force, and creates an angular acceleration
of 1.84 rad/s2. At what distance from the axis
was the force applied?
[?] m
Hint: Remember, the moment of inertia for a panel
rotating about its end is I = mr².
Answers
The distance from the axis of the force applied is 2.05 m.
What is the distance from the axis of the force applied?The distance from the axis of the force applied is calculated as follows;
The formula for torque;
τ = Fr
where;
F is the applied forcer is the distance from the axis of the force appliedAnother formula for torque is given as;
τ = Iα
where;
I is the moment of inertia of the doorα is the angular acceleration;τ = (mr²)α
τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)
τ = 39.36 Nm
The distance is calculated as;
r = τ/F
r = ( 39.36 Nm ) / (19.2 N)
r = 2.05 m
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how much work would be done if the gas leaked directly into the atmosphere
Answers
Work would be done on atmospheric gas if the gas leaked directly into the atmosphere
Define work done.
Work is the energy that is transferred when a force is applied to a moving object. The amount of force multiplied by the amount of displacement multiplied by the cosine of the angle between them results in the work that a force produces on an object.
The gas does work on the atmospheric gas when it is expanded into the atmosphere because it is moving against the atmosphere while under atmospheric pressure. This causes the initial air gas to lose volume and absorb some energy as a result of the work, making the gas inside the container colder.
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A ball with a mass of 5 kg is accelerating at 5 m/s/s. What is the force acting on the ball?
Answers
F=ma
F=5x5
F=25 N
If you have 100 kg of each of these substances, which would require the most energy to increase its temperature by 25 Kelvin?
A. Iron
B. Carbon
C. Rubber
D. Air
Answers
Answer:
iron
Explanation:
4. A trolley of mass 2kg rests next to a trolley of mass 3 kg on a flat
bench as shown in the diagram. When the spring is released
between the trolley's, they pushed apart. The 2kg travels to left at a
velocity of 6m/s.
a. What is the total momentum of the trolleys before
separation?
b. What is the total momentum of the trolleys after
separation?
c. What is the momentum of of 2kg trolley after
separation
d. What is the momentum of 3kg trolley after separation?
e. What is the velocity of the 3kg trolley?
Answers
Answer:
a. The total momentum of the trolleys which are at rest before the separation is zero
b. The total momentum of the trolleys after separation is zero
c. The momentum of the 2 kg trolley after separation is 12 kg·m/s
d. The momentum of the 3 kg trolley is -12 kg·m/s
e. The velocity of the 3 kg trolley = -4 m/s
Explanation:
a. The total momentum of the trolleys which are at rest before the separation is zero
b. By the principle of the conservation of linear momentum, the total momentum of the trolleys after separation = The total momentum of the trolleys before separation = 0
c. The momentum of the 2 kg trolley after separation = Mass × Velocity = 2 kg × 6 m/s = 12 kg·m/s
d. Given that the total momentum of the trolleys after separation is zero, the momentum of the 3 kg trolley is equal and opposite to the momentum of the 2 kg trolley = -12 kg·m/s
e. The momentum of the 3 kg trolley = Mass of the 3 kg Trolley × Velocity of the 3 kg trolley
∴ The momentum of the 3 kg trolley = 3 kg × Velocity of the 3 kg trolley = -12 kg·m/s
The velocity of the 3 kg trolley = -12 kg·m/s/(3 kg) = -4 m/s
a-The total momentum of the trolleys before separation=0
b.The total momentum of the trolleys after separation=0
c. The momentum of 2kg trolley after separation=12kg-m/sec
d. The momentum of 3kg trolley after separation=-12kg-m/sec
e. The velocity of the 3kg trolley=4kg-m/sec
Given-
Trolley A with mass= 2kg
Trolly B with mass= 3kg
Velocity of trolly A =6m/sec
A- Total momentum of the trolleys before separation-
Here, in this problem both the trolleys are in the rest position hence the momentum of both trolleys = 0
B- Total momentum of the trolleys after separation-
We know that motion never changes in an isolated collection of objects,
hence the momentum of the trolleys before and after the separation=0
C- Momentum of the Trolley A (2kg)-
It is known that momentum= Mass x Velocity
\(P=m\times v\)
\(P=2\times 6\)
\(P=12\)
Hence, the momentum of the 2kg trolley is 12 kg-m/sec
D- Momentum of the Trolley B (3kg)-
As we know that motion never changes in an isolated collection of an object hence the total moment of after saparation = 0
hance the momentum of the trolley B will be equal and opposite to the momentum of trolley A=
\(P= -12\)
Momentum of trolley B (3kg) is -12kg-m/sec
E- The velocity of the 3kg trolley-
The momentum of trolley A= Momentum of trolley B
\(m_{b} v_{a} =m_{b} v_{a}\)
\(-2\times 6=3\times v_{a}\)
\(v_{a}=-4\)
The value of the velocity of the 3kg trolley is -4m/sec
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A 3.00-kg object has velocity (6.00i - 2.00j) m/s.
a. What is its kinetic energy at this moment?
b. What is the net work done on the object if its velocity changes to (8.00i - 4.00j) m/s?
Answers
a. The kinetic energy at this moment is 81J.
b. The net work done on the object when its velocity changes to (8.00i - 4.00j) m/s is 63J.
a. The kinetic energy of the object can be found using the formula KE = (1/2)mv^2, where m is the mass of the object and v is its velocity. Plugging in the given values, we get:
KE = (1/2)(3.00 kg)((6.00 m/s)^2 + (-2.00 m/s)^2)
KE = 81 J
Therefore, the kinetic energy of the object at this moment is 81 J.
b. The net work done on the object can be found using the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy. That is:
Net work = KE(final) - KE(initial)
To find the net work, we need to first calculate the final kinetic energy of the object. Using the same formula as before, but with the new velocity, we get:
KE(final) = (1/2)(3.00 kg)((8.00 m/s)^2 + (-4.00 m/s)^2)
KE(final) = 144 J
Now we can plug in both the initial and final kinetic energies to find the net work:
Net work = KE(final) - KE(initial)
Net work = 144 J - 81 J
Net work = 63 J
Therefore, the net work done on the object is 63 J.
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5. What color of visible light will have a frequency of 6.20 x 10¹4 Hz? Show your
work. Remember! 1 meter = 10° nanometers
Answers
First, we calculate the energy:
E = hf = (6.626 x 10^-34 J s) x (6.20 x 10^14 Hz) = 4.11 x 10^-19 J
Next, we can use the equation E = hc/λ, where c is the speed of light and λ is wavelength, to find the wavelength:
λ = hc/E = [(6.626 x 10^-34 J s) x (3.00 x 10^8 m/s)] / (4.11 x 10^-19 J) = 4.83 x 10^-7 m
Finally, we convert the wavelength to nanometers:
λ = 4.83 x 10^-7 m x (10^9 nm / 1 m) = 483 nm
Melody is riding her mountain bike along a trail with multiple hills. At the bottom of the second hill, she has 3200 J of kinetic energy. At the top of the third hill, when she is going the slowest, her potential energy measures 1650 J. Which statement below is true? A. The total amount of energy at the bottom of the hill cannot equal the amount at the top, because some of the energy from the environment is gained. B. The total amount of energy at the top is equal to the amount at the bottowm, but she gained some energy as she traveled due to a higher speed going down the first two hills. C. The total amount of energy at the bottom of the hill cannot be equal to the amount at the top, because some of the energy is lost.
Answers
Answer:
Eventually it reaches bottom of hill so C
Explanation:
Explain why electromagnetic forces are essential to forming compounds.
Answers
Explanation:
formation of compounds because the electric forces compel the atoms to attract each other and formed bonds which leads to the formation of chemical compounds. The attractive or repulsive interaction between any two charged bodies is known as an electric force so the attraction between two opposite charged atoms causes the formation of compounds so we can conclude that electric forces are important for the formation of compounds.
a BTU is defined as the amount of energy required to raise the temperature of one lb of water by one degree celsius.T/F
Answers
A BTU is the amount of energy required to raise the temperature of one pound of water by one degree Celsius: False
The energy needed to raise the temperature of one pound of water by one degree Fahrenheit is known as a BTU.
British thermal units are used to assess the capacity of the majority of air conditioners (BTU). One pound (0.45 kilos) of water needs one BTU of heat to increase its temperature by one degree Fahrenheit (0.56 degrees Celsius). One tonne is 12,000 BTU in terms of heating and cooling.
Heat is measured in British thermal units. One BTU is about 1055 joules (J), the joule being the current SI unit for heat energy. This represents the fact that the temperature change of a mass of water caused by the injection of a particular quantity of heat (measured in energy units, often joules) varies somewhat depending upon the water's beginning temperature.
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