Na+1 and S-2 what ionic formula is this​

The distinctive bluish-green color of the flame is brought about by copper.

Flame test: What is it?

Using each element's distinct flame emission spectrum (which may be impacted by the presence of chloride ion), a flame test is an analytical method used in chemistry to detect the presence of specific elements, primarily metal ions. The general color of flames is also influenced by temperature and oxygen availability. A sample of the element or compound needs to be heated up by a non-luminous flame in order to perform the test. The resulting flame's color must then be scrutinized.

Atoms from the sample are heated during evaporation for the experiment, and this heat causes the atoms to emit light.

Prior to the solid particles that have been finely divided

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The equilibrium constant (Keq) is given for the reversible reactions. The concentration of hydrogen iodide will be 1.58 M.

The equilibrium constant (Keq) is the proportion of the ratios of the concentration of the products to the reactants.

The balanced chemical reaction is shown as:

2HI  ⇔ H₂ + I₂

The equilibrium expression for the reaction can be given as:

Keq = [H₂] [I₂] / [HI]²

Given,

Equilibrium constant = 1.6 × 10⁻⁴

Concentration of dihydrogen = 2  × 10⁻³ M

Concentration of iodine = 2 × 10⁻³ M

The concentration of hydrogen iodide is calculated as:

1.6 × 10⁻⁴ = [ 2  × 10⁻³ M][2  × 10⁻³ M] ÷ [HI]²

[HI]² = 4  × 10⁻⁶ ÷ 1.6 × 10⁻⁴

= 2.5 M

[HI] = 1.58 M

Therefore, 1.58 M is the concentration of hydrogen iodide.

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The half life of the dubnium-261, given that 55 g of it has decayed to 1.72 g after 135 seconds is 27 seconds

To obtain the half life of the dubnium-261, we must first determine the number of half lives that has elapsed. This can be obtained as follow:

2ⁿ = N₀ / N

2ⁿ = 55 / 1.72

2ⁿ = 32

2ⁿ = 2⁵

n = 5

Now, we shall obtain the half-life of the dubnium-261. Details below:

n = t / t½

5 = 135 / t½

Cross multiply

5 × t½ = 135

Divide both sides by 5

t½ = 135 / 5

t½ = 27 secods

Thus, we can conclude that the half-life of the dubnium-261 is 27 seconds

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The original substance has undergone a transformation into a new substance with different properties, indicating a change in the chemical composition of the material.

An example of a change in substance is the process of combustion. When a substance, such as wood, is burned, it undergoes a chemical reaction with oxygen in the air, which produces a new substance: carbon dioxide gas, water vapor, and ash. This change in the chemical composition of the wood means that it has transformed into a completely new substance with different physical and chemical properties.

Another example is the process of electrolysis, where an electric current is passed through a solution containing ions. This can cause a chemical reaction to occur, resulting in the breakdown of the original substance into its component parts or the formation of a new substance.

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Answer:

The one inside with "+"--- Protons

The grey ones inside--neutrons

The ones on the electron orbits---electron

Everything is called an atom

Explanation:

Answer:

Explanation:

A Basketball Weigh in Grams? A 29.5 inch (75 cm) basketball typically weighs about 624 grams (g). A 28.5 inch (72.4 cm) basketball weighs about 567 grams (g).

Answer:

Object C

Explanation:

The object experiencing the greatest gravitational force is C.

This choice is made based on the newton's law of universal gravitation.

It states that "every particle attracts every other particle with a force that is directly proportional to their mass and inversely proportional to the square of the distance between them".

  From the law, we understand that the higher the mass, the higher the force of gravitation.

 The force is inversely proportional to the distance between the two bodies, so, the larger the distance the lesser the force.

From the given choices, mass 5kg of two bodies and distance 1m will yield the greatest gravitational force.

The pair of objects at 1 m distance and 5 kg mass have been experiencing the greater gravitational force. Thus, option C is correct.

Gravitational force has been the force acting on the body with the influence of gravity.

According to the Newton's law of the gravitational force, the force has been directly proportional to the mass of the object and has been inversely proportional to the square root of the distance between the object.

In the given set of objects, the objects with least distance and greater mass have been experiencing the higher gravitational force.

Thus, objects at 1 m distance and 5 kg mass have been experiencing the greater gravitational force. Thus, option C is correct.

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Answer:

Bacteria or mold grows in the can giving of the gasses and producing byproducts that may be harmful or dangerous to ingest (eat).

Explanation:

Answer:

Explanation:

Safety: The rate of energy release determines how quickly and explosively the energy is released. In the case of the stick of dynamite, the rapid and instantaneous release of energy can cause a violent explosion. On the other hand, the controlled release of energy from gasoline allows for safer and more manageable energy output, reducing the risk of accidents and minimizing potential harm.

Efficiency: The rate at which energy is output affects the efficiency of a system. In many practical applications, such as engines or power generation, it is desirable to convert energy into useful work as efficiently as possible. Controlling the rate of energy release allows for a more efficient conversion of energy, minimizing waste and maximizing the desired output.

Control and Functionality: Different systems require energy to be released at specific rates to perform their intended functions. For example, in an internal combustion engine, the controlled and timed release of energy from fuel allows for the synchronized movement of engine components, resulting in the desired mechanical work. Controlling the rate of energy output ensures that a system operates effectively and performs its intended function.

Environmental Impact: The rate at which energy is output can also impact the environment. In processes that release energy too rapidly or uncontrollably, such as certain combustion reactions or explosions, there can be significant environmental consequences, including air pollution, damage to ecosystems, and the release of harmful byproducts. Controlling the rate of energy release allows for better management and mitigation of these environmental impacts.

Overall, the rate at which energy is output from a system is crucial for safety, efficiency, control, functionality, and environmental considerations. By regulating and optimizing the rate of energy release, we can ensure that energy is utilized effectively and responsibly in various applications.

Similar, much older remnants of flooded forests have been discovered in Cascadia by earth scientists. On the coasts of British Columbia, Washington, Oregon, and northern California, they were found near bays and river mouths. Researchers discovered additional proof of powerful earthquakes in the same regions.

In 1997, scientists used dendrochronology — a method of dating trees by comparing ring patterns to samples of known age — on the ghost forest trees.1997 by scientists.

Because of the thinned coast, tides were able to drown coastal forests. Today's ghostly tree trunks serve as physical evidence of the devastating earthquakes. In Cascadia, similar, much older remnants of inundated forests have been discovered by earth scientists.

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The total energy released per gram of methane in the experiment is 119941.33 J/g

Change in temperature (ΔT) = T₂ – T₁

Change in temperature (ΔT) = 68 – 25

Change in temperature (ΔT) = 43 °C

The absorbed by the water can be obtained as illustrated below:

Q = MCΔT

Q = 500 × 4.184 × 43

Q = 89956 J

Heat absorbed by water = 30% of heat released by methane

89956 = 30% × heat released by methane

89956 = 0.3 × heat released by methane

Divide both sides by 0.3

Heat released by methane = 89956 / 0.3

Heat released by methane = 299853.33 J

Q = m × ΔH

Divide both sides by m

ΔH = Q / m

ΔH = 299853.33 / 2.5

ΔH =119941.33 J/g

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Answer:

As electrons move from higher-energy to lower-energy levels, energy in the atom is released in the form of photons.

I) A photon was released.

Explanation:

Answer: A)

Explanation:

Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Answer:

A third type of circuit involves the dual use of series and parallel connections in a circuit; such circuits are referred to as compound circuits or combination

Explanation:

The formula of the salt is R-X + NaOH → R-ONa + H₂O; the alkyl halide layer switches from the top layer to the bottom layer due to its lower density than water; and the by-products formed are an ether and an alkene.

1. The reaction mixture is cooled to cause the salts to precipitate. The formula of the salts is dependent on the reactants used in the reaction. In this case, the reaction of an alkyl halide with an aqueous solution of sodium hydroxide gives the sodium salt of the alkyl halide plus water. The chemical formula of this salt is R-X + NaOH → R-ONa + H2O.

2. When the reaction mixture is cooled, the alkyl halide layer switches from the top layer to the bottom layer because the alkyl halide is less dense than water. This causes the alkyl halide to sink to the bottom of the mixture, forming a separate layer from the aqueous layer above.

3. An ether and an alkene are formed as by-products in this reaction. The ether is formed from the dehydration of the alkyl alcohol, which is formed when the alkyl halide reacts with the sodium hydroxide.

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Complete Question:

1. What are the formulas of the salts that precipitates when the reaction mixture is cooled?

2. Why does the alkyl halide layer switch from the top layer to the bottom layer at the point where water is used to extract the organic layer?

3. An ether and an alkene are formed as by-products in the reaction. Draw the structures of these by-products and give mechanisms for their formation.

Answer:

Eclipse: 3. To vanish

Corona: 2. During a solar eclipse, the moon covers the sun, a small ring of fire is visible around the edge

Umbra: 4. The inner, darkest, cone-shaped shadow is

Penumbra: 1. The outer, larger, lighter shadow

Answer:

I found 3. 2. 4. and 1.

Explanation:

I got my answer from this website https://eclipse.aas.org/eclipse-america/eclipse-glossary

Answer:  343 Celsius

Explanation:

Gay lussac law

T2=T1V2/V1  Temp must be in Kelvin

T2= 308.15 X 9.00 / 4.50 =616.30 K - 273.15 to get back in celsius

=343.15 C

The question is incomplete, the complete question is;

A 8.00 L tank at 2.64 °C is filled with 9.82 g of chlorine pentafluoride gas and 10.1 g of dinitrogen difluoride gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank. Be sure your answers have the correct number of significant digits.

Answer:

See explanation for details

Explanation:

Number of moles of N2F2 = mass/ molar mass

Molar mass of N2F2 = 66 g/mol

Number of moles = 10.1 g/66 = 0.15 moles

Number of moles of ClF5 = 9.82 g/130 g/mol= 0.08 moles

Molar mass of ClF5= 130g/mol

Total number of moles = 0.15 moles + 0.08 moles = 0.23 moles

Given that;

T= 2.64 °C + 273 = 275.64 K

n= 0.23 moles

R= 0.082 Latmmol-1K-1

V= 8.00 L

P= ??

From;

PV =nRT

P= nRT/V

P= 0.23 ×0.082 × 275.64/8.00

P= 0.65 atm

Mole fraction of N2F2= 0.15/0.23 = 0.65

Partial pressure = mole fraction × total pressure = 0.65 × 0.65 = 0.42 atm

Mole fraction of ClF5 = 0.08/0.23 = 0.35

Partial pressure of ClF5 = mole fraction × total pressure = 0.35 × 0.65 = 0.22 atm

Consider the following mechanism.

The overall balanced chemical equation : 2O₃  ---->   3O₂

The intermediates within the mechanism : O

The order with respect to each reactant :  2

The rate law for the overall reaction : R = k[O₃]²/[O]

The equations are :

O₃  ---->   O₂  +  O   fast

O₃  +   O  --->  2O₃   slow

a) The overall reaction is given as :

2O₃  ---->   3O₂

b) The intermediates within the mechanism is O.

c)  The order with respect to each reactant is 2

d) slow step rate : k[O][O₃]

at equilibrium, kc = [O][O₂] / [O₃]

The rate law = R = k[O₃]²/[O]

Thus, Consider the following mechanism.

The overall balanced chemical equation : 2O₃  ---->   3O₂

The intermediates within the mechanism : O

The order with respect to each reactant :  2

The rate law expression for the reaction : R = k[O₃]²/[O]

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we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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A type of fossil fuel,known as Tar stands.

A fossil fuel is a hydrocarbon-containing material formed naturally in to  the Earth's crust from to the  remains of dead plants and animals and birds that is the  extracted and burned as thr  a fuel. The main fossil  fuels are mainly coal, oil, and natural gas.

Tar sands are a combination of clay, sand, water and bitumen, which is a heavy hydrocarbon. Like the  kerogen in oil shale, tar sands' bitumen can be upgraded to synthetic crude oil.

So answer is tar sands.

These include tar sands – deposits of moist sand and it is  clay with 1-2 percent  bitumen (thick and heavy are  petroleum rich in the  carbon and poor in the  hydrogen). These are the  removed by strip mining in the  (see section below on coal)

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Time increases as the volume of hydrochloric acid remains the same. This is because the concentration of hydrochloric acid would remain constant, affecting the reaction rate. Option B

Based on factors that affect the rates of chemical reactions, the expected trend in the table can be analyzed.

In this experiment, calcium carbonate reacts with hydrochloric acid to produce carbon dioxide gas. The reaction rate is influenced by factors such as concentration, surface area, temperature, and presence of a catalyst. Let's examine the options provided:

A. Time increases as the volume of hydrochloric acid decreases:

This option suggests that as the volume of hydrochloric acid decreases, the time taken for carbon dioxide to form increases. However, in general, a decrease in the volume of hydrochloric acid would result in an increase in its concentration.

B. Time increases as the volume of hydrochloric acid remains the same:

If the volume of hydrochloric acid remains the same, it means the concentration of hydrochloric acid is constant. In this case, the reaction rate is not expected to change significantly, and the time taken for carbon dioxide to form should remain relatively constant. Therefore, this option is plausible.

C. Time decreases as the mass of calcium carbonate decreases:

If the mass of calcium carbonate decreases, the surface area of the reactant particles decreases. A smaller surface area would result in less contact between reactant particles, leading to a slower reaction rate. Thus, the time taken for carbon dioxide to form would be expected to increase, making this option unlikely.

D. Time decreases as the mass of calcium carbonate remains the same:

If the mass of calcium carbonate remains the same, the surface area of the reactant particles also remains the same. Therefore, the reaction rate should remain relatively constant, and the time taken for carbon dioxide to form would not show a significant change. Thus, this option is also plausible.

Option B is correct.

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Answer:

Drawing conclusions

Explanation:

6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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This describes a fission chain reaction:

Initially, the reaction starts with the fission of an atom with an unstable nucleus. In fission, neutrons are produced, and they travel through the surrounding medium. Eventually, they meet other atoms and they are captured by their nuclei: the nuclei become unstable and they undergo fission as well.

The order will be: answer

1) One atom undergoes fission.

2) A number of neutrons are produced.

3) Each neutron finds another atom.

4) A number of atoms undergo fission.

Jared marks the center of the kite-shaped area with a stake and measures 50 ft from the center in one direction, placing another stake. He then extends the rope from the center to the second stake, folds it in half, connects the ends, and drives a stake where they meet. Finally, he completes the kite shape by extending the remaining portion of the rope from the second stake back to the center stake.

To use all of the 100 ft rope to complete the kite shape for the food vendor area, Jared can follow the steps outlined below:

Jared starts by driving a stake into the ground to mark the center of the kite-shaped area.

Using the rope, Jared measures a distance of 50 ft from the center stake in one direction and places a stake there.

Next, Jared extends the rope from the center stake to the newly placed stake, forming one side of the kite.

To create the other side of the kite, Jared folds the rope in half, bringing the end that is still connected to the center stake to meet the newly placed stake.

Jared drives another stake at the point where the two halves of the rope meet, securing the second side of the kite.

Finally, Jared extends the remaining portion of the rope from the second stake back to the center stake, completing the kite shape.

Jared marks the center of the kite-shaped area with a stake and measures 50 ft from the center in one direction, placing another stake. He then extends the rope from the center to the second stake, folds it in half, connects the ends, and drives a stake where they meet. Finally, he completes the kite shape by extending the remaining portion of the rope from the second stake back to the center stake.

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