n earthquake-produced surface wave can be approximated by a sinusoidal transverse wave. assuming a frequency of 0.60 hz (typical of earthquakes, which actually include a mixture of frequencies), what amplitude is needed so that objects begin to leave contact with the ground? [hint: set the acceleration a > g.

Method of section is a significant method of determining forces in members of a structure.

The basic concept of the method of section is to find out the forces acting on the sections by separating them from the rest of the structure.

In this problem, the moment at point b has to be determined using the method of section.

The given weight of the beam is

w = 40.3 lb/ft.

Let's draw the free-body diagram for the given beam:

Free-Body Diagram:

As we can see from the above diagram, the section has been drawn which passes through point b.

We have to determine the moment at point b using this section.

Now, we will write the equation for the moment of the section passing through point b as:

- 12(6) - 4(8) - (20)(12) - (32)(20) - (40.3)(12/2) = 0Mb = 1126.05 lb-ft

the moment at point b is 1126.05 lb-ft.

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Answer:

Explanation:

from t = .3 to t = .33 , velocity appears to be uniform .

uniform velocity = .22 m /s

displacement will be area of the v-t graph which is a rectangle .

= .22 x ( .33 - .3 )

= .22 x .03

= 66 x 10⁻⁴ m

= 6.6 mm .

Answer:

Intensity

Explanation:

Intensity is how hard you exercise. Time refers to the time of day you exercise and how long each session lasts.

Hope this helps you!

Answer: Intensity

Explanation: Intensity is how hard your exercise. We might categorize this as low, moderate, or high intensity.

When the amplitude varies, it means twice as much.

Simple harmonic motion, such the swinging of a pendulum or the weight of a weight on a spring, produces a sinusoidal relationship between position and time. Sound and water waves, for example, can be visualized as sinusoids.

Given:

if the string is given four times as much power.

According to the power that a sinusoidal wave on a stretched string transmits,

P =\(\frac{1}{2}\) μω^A^2v

Where  μ=mass per unit length, w= angular speed, A= amplitude, v= wave speed, P= power delivered.

P ∝\(A^{2}\)

Here, the only terms we need are power and amplitude.

A =K\(\sqrt{P}\)

Where K is constant

Here, "power become quadruple" refers to four,

A = \(\sqrt{4P}\)

A =2 \(\sqrt{P}\)

Therefore, an increase in amplitude by a factor of two is equivalent to a twofold increase.

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The pendulum should be made approximately 8.7 cm longer in order to increase its period by 0.29 s.

The period of a simple pendulum is given by the formula T=2π√(l/g), where T is the period, l is the length of the pendulum, and g is the acceleration due to gravity. In this case, the original period of the pendulum is given as 1.13 s.

To find out how much longer the pendulum should be made, we can use the following equation:
(T + 0.29) = 2π√((l+x)/g), where x is the additional length that the pendulum needs to be made longer by.

Substituting the given values, we get:
(1.13 + 0.29) = 2π√((l+x)/9.81)

Simplifying the equation, we get:
1.42 = √(l+x)

Squaring both sides, we get:
2 = l/g + x/g

Therefore, x/g = 2 - l/g.

Substituting the values of l and g, we get:
x/9.81 = 2 - (1.13/2π)^2

Solving for x, we get:
x = 0.087 m or 8.7 cm (approx.)

Hence, the pendulum should be made approximately 8.7 cm longer in order to increase its period by 0.29 s.

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To increase the period by 0.29 s, the pendulum should be made approximately 0.0941 m (or 9.41 cm) longer. To answer your question, we need to use the formula for the period of a simple pendulum: T = 2π√(L/g). where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

Given that the pendulum's period is 1.13 s, we can solve for its current length as follows: 1.13 s = 2π√(L/g),Squaring both sides, we get: 1.28 s^2 = 4π^2(L/g),Solving for L, we get: L = (g/4π^2) * 1.28 s^2
Now we can find the new length of the pendulum that would increase its period by 0.29 s. Let's call this new length L'.
The new period would be: T' = T + 0.29 s = 1.13 s + 0.29 s = 1.42 s,L' = (g/4π^2) * 2.01 s^2.Finally, to find how much longer the pendulum should be made, we can subtract L from L': L' - L = (g/4π^2) * 0.73 s^2

Since we don't know the value of g, we can't calculate this difference exactly. However, we can use the approximate value of g = 9.81 m/s^2 to estimate the answer. Plugging in this value, we get: L' - L ≈ 0.295 m
Therefore, the pendulum should be made approximately 0.295 m longer to increase its period by 0.29 s.

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Answer:

W

Explanation:

its the longest period of time

For A racing car travels on a circular track with a radius of 250 m:

(a) Angular speed (ω) is 0.18 rad/s.

(b) Magnitude of acceleration is  8.1 m/s².

To solve this problem, we can use the following formulas:

(a) Angular speed (ω) is defined as the ratio of the linear speed (v) to the radius (r) of the circular path. Mathematically, it can be expressed as ω = v / r.

(b) The magnitude of acceleration (a) can be determined using the formula a = v² / r.

Now, let's calculate the values:

(a) Angular speed (ω) = v / r

                                    = 45.0 m/s / 250 m

                                    = 0.18 rad/s.

(b) Magnitude of acceleration (a) = v² / r

                                                       = (45.0 m/s)² / 250 m

                                                       = 8.1 m/s².

Since the car is moving in a circular path, the direction of its acceleration is always directed towards the center of the circle. Therefore, the direction of its acceleration is radial inward or centripetal.

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Answer:

When the sun shines onto a solar panel, energy from the sunlight is absorbed by the PV cells in the panel. This energy creates electrical charges that move in response to an internal electrical field in the cell, causing electricity to flow.

Answer: 0,96 m

Explanation: speed in concrete is 4300 m/s

According to wave equation speed v = lambda × frequency

Lambda = speed /frequency

If the amount demand of a product changes more than proportionally as its price rises or falls, then it is said to be elastic.

The more replacements there are for an item, more elastic the good is, according to definition of an elastic good, which is where change in price results in a large movement in demand. Price elasticity of demand is determined by dividing percentage change in quantity required by the percentage change in price.

Products like cars, appliances, and luxury items that are rarely purchased are examples of elastic commodities. In the event that the cost of these products is momentarily high, consumers may decide to put off buying.

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velocity and wavelength are likely to change in the process

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The destructive interference formula for diffraction grating problems is \(d sin \theta = (n+\frac{1}{2})\lambda\).

Destructive interference happens when the maxima of two waves are 180° out of phase a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.

The formula for brighter patches resulting from constructive interference and darker patches resulting from destructive interference in a diffraction grating is:

\(\rm d sin \theta = n \lambda\)

The grating spacing is denoted by d, the angle of light is denoted by a the fringe order is denoted by n, and the wavelength is denoted by \(\rm \lambda\).

The destructive interference formula is now based on the fact that destructive interference occurs between the fringes.

Hence the destructive interference formula for diffraction grating problems is \(d sin \theta = (n+\frac{1}{2})\lambda\).

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Answer:

A. dsin  =

Explanation:

Answer:

The SI base units are the standard units of measurement defined by the International System of Units (SI) for the seven base quantities of what is now known as the International System of Quantities: they are notably a basic set from which all other SI units can be derived.

Explanation:

The difference in point of view that occurs when the lens (or other device) through which the eye views a scene is separate from the lens that exposes the film is called the parallax effect.

Parallax effect is an interactive technique used by web developers to create a visually engaging experience for users. It works by having the background move at a slower speed than the foreground when the user scrolls down the page. This creates an illusion of depth, as if the user is looking into the scene from different angles. The effect is especially popular for creating immersive experiences such as 3D games, virtual tours, and interactive storytelling. Parallax effect can be used to bring websites to life, offering users an engaging and dynamic experience. It is also a great tool for storytelling, helping to convey emotion and create a unique visual experience.

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Answer:

Friction

Explanation:

friction is the force that tries to slow things down when two things are rubbed together.

Answer:

That is friction don't know

Explanation:

how I know that

Answer:

hi your question is incomplete below is the missing part of your question

Question : How does the direction and magnitude of Fe compare to Fg

answer : Not enough information is given

Explanation:

From the above information given in the question the direction and magnitude of FE cannot be compared to Fg and this is simply because the mass of the particle that  force is been exerted on is not given therefore we cannot ascertain the magnitude of the gravitational force. Therefore we can conclude that not enough information is given

Answer:

Explanation:

Its surface is rocky, with canyons, volcanoes, dry lake beds and craters all over it. Red dust covers most of its surface. Mars has clouds and wind just like Earth

Answer:

The new kinetic energy is 9 times of the initial kinetic energy.

Explanation:

The kinetic energy of an object is given by the formula as follows :

\(E=\dfrac{1}{2}mv^2\)

Where

m is mass and v is speed of the body

If the speed of the body is tripled. Let v' is the new speed, v' = 3v. The new kinetic energy is E' and it is given by :

\(E'=\dfrac{1}{2}mv'^2\\\\\text{Put v' = 3v}\\\\E'=\dfrac{1}{2}m\times (3v)^2\\\\=\dfrac{1}{2}m\times 9v^2\\\\=9\times (\dfrac{1}{2}mv^2)\\\\E'=9\times E\)

Hence, the new kinetic energy is 9 times of the initial kinetic energy.

Answer:A 2.2kg block of ice slides across a rough floor. Its initial velocity is 2.5m/s and its final velocity is 0.50m/s. How much of the ice block melted as a result of the work done by friction? (Latent Heat of water is 3.3*10^5J/kg)

Explanation:

The heat produced by friction between a skate and the ice during movement over the surface melts the topmost layer of ice. However, even when you are still, ice is still slick. When you remain still on ice, there is no friction to produce heat, but the ice is still slippery.

Although friction does generate heat, the amount of heat it produces is insufficient to melt ice that is at a very low temperature. But even at low temperatures, ice still creates a slick liquid layer. The formation of a slippery coating even when the item is totally still cannot be explained by frictional heating.

Therefore, A rough floor is traversed by a 2.2 kg lump of ice. It moves at a final speed of 0.50 m/s after starting out at 2.5 m/s. What portion of the ice block melted as a result of the friction's work? (Water has a latent heat of 3.3×105 J/kg.)

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Answer:

u go to vanguard? in 6th grade

Answer:

is it correct ? sorry of it is incorrec

The persοn is mοving at a speed οf 55 miles per hοur in the Sοuth directiοn when the persοn is 50 miles West and 70 miles Sοuth οf the car, and the distance between them is increasing at a rate οf 55 miles per hοur.

Tο determine the speed at which the persοn is mοving, we can use the cοncept οf relative velοcity.

Let's cοnsider the hοrizοntal and vertical cοmpοnents separately:

Hοrizοntal Cοmpοnent:

The persοn is walking due East, which is perpendicular tο the Nοrth directiοn οf the car. Therefοre, the hοrizοntal cοmpοnent οf the persοn's velοcity dοes nοt affect the speed at which the persοn is mοving away frοm the car.

Vertical Cοmpοnent:

The persοn is 70 miles Sοuth οf the car, and the distance between them is increasing at a rate οf 55 miles per hοur. This indicates that the persοn's vertical pοsitiοn is changing with time. Since the persοn is mοving in the Sοuth directiοn and the distance is increasing, the persοn's speed can be determined by the rate οf change οf the vertical distance.

Given that the distance is increasing at a rate οf 55 miles per hοur, the persοn's speed in the Sοuth directiοn is 55 miles per hοur.

Therefοre, the persοn is mοving at a speed οf 55 miles per hοur in the Sοuth directiοn when the persοn is 50 miles West and 70 miles Sοuth οf the car, and the distance between them is increasing at a rate οf 55 miles per hοur.

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Answer:

B

Explanation:

because it would change the direction and speed

The answer is 6624000J.

Given mass = 0.046 kg

speed= 0.75 c=2.099\(\times\)\(10^8\)m/s

we know that K.E=\(\frac{1}{2} \times m\times v^2\)

KE=\(\frac{1}{2} \times0.046\times2.88\times10^8\)

KE=6624000J

What is kinetic energy?

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Answer: happy Ramadan

Explanation: thanks

Answer:

Explanation:

Im not sure if this is right but multiply the 7 by 1.2 and you shoulf robaaly get the answer

Like I said Im not sure so....

Two conducting cylindrical wires are made out of the same material. Wire X has twice the length and twice the diameter of wire Y. The ratio of their resistances Rx/Ry is 1/2.

The resistance of a cylindrical wire depends on its length and cross-sectional area, and is given by the formula: R = (ρL) / A, where ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area. Since both wires are made of the same material, they have the same resistivity ρ.

Wire X has twice the length and twice the diameter of wire Y. The length of wire Y is L and its cross-sectional area is A. Therefore, the length of wire X is 2L and its cross-sectional area is 4A (since the diameter is doubled, the area is quadrupled).
Using the formula for resistance, the ratio of the resistances of the two wires is:

Rx/Ry = [(ρ x 2L) / (4A)] / [(ρ x L) / A] = 1/2

Therefore, the answer is A) 1/2.

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Answer:

0.119 s is the correct answer to this question.

Explanation:

As mentioned in the question

U=3.89\ m/s

a=-1.44\ m/s^2

S=4.8\ m

Consider the final speed of the softball covering the distance of 4.8m is v

Now using the equation

\(v^2=U^2+2aS\)

Putting the value of U, A, S in the previous equation we get

\(V^2=3.89^2-2\times 1.44\times 4.8\\V=3.7\ m/s\\\)

Now again using the equation

v=U+at

where U=intial velocity, t= time

Substituting the value of v, U, a

\(3.7=3.89-1.44\times t\\t=0.119\ s\\\)

Hence the slide time is 0.119 s

Given data: Capacitance, C = 7.50 nF, Charged voltage, V = 12.0 VPeriod of oscillation, T = 5.00 ms.Let's solve the given problem:

A) The inductance of the coil, L. We know that the period of the circuit is: T = 2π √LCWhere, L = (T/2π)^2/C Substitute the given values:L = (5.00 x 10^-3 s/ 2π)^2 / (7.50 x 10^-9 F)L = 6.81 mH

B) Maximum charge on the capacitor. Using the formula, Q = CV, Substitute the given values, the maximum amount on the capacitor, Q = (7.50 x 10^-9 F) x (12.0 V)Q = 9.00 x 10^-8 C

C) Total energy of the circuitThe total energy of the circuit is the sum of points stored in the capacitor and inductor. The formula for calculating the energy stored in a capacitor and an inductor is given by: Energy stored in a capacitor, EC = 1/2 x C x V^2Energy stored in an inductor, EL = 1/2 x L x I^2The total energy of the circuit, ET = EC + EL = 1/2 x C x V^2 + 1/2 x L x I^2Substitute the given values in the above formula to get the total energy, ET = (1/2) x (7.50 x 10^-9 F) x (12.0 V)^2 + (1/2) x (6.81 x 10^-3 H) x (0.737 A)^2ET = 6.23 x 10^-5 J

D) Maximum current in the circuit. The maximum current in the course can be calculated by the formula, I = V/√(L/C). Substitute the given values, I = 12.0 V/√(6.81 x 10^-3 H / 7.50 x 10^-9 F)I = 0.737 A

Thus, (a) the Inductance of the coil is 6.81 mH(b) the Maximum charge on the capacitor is 9.00 x 10^-8 C(c) the Total energy of the circuit is 6.23 x 10^-5 J(d) the Maximum current in the course is 0.737 A.

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