Multiple Choice
Which of the following statements explain how
this experiment relates to the cycling of
matter?
Elodea uses water and carbon dioxide to
produce glucose and oxygen. The snail
uses glucose and oxygen and produces
water and carbon dioxide.
Elodea uses light, oxygen and water to
produce glucose. The snail eats the
elodea and releases carbon dioxide as a
waste product
The snail performs photosynthesis which
C releases carbon dioxide into the
atmosphere.
Nitrogen-fixing bacteria remove ammonia
D from the testube and increases dissolved
oxygen.

0.0205 moles of water were lost if the amount of water lost was 0.369 grams. The given answer is in three significant figures with including zero before the decimal.

To find the number of moles of water lost, we need to know the molar mass of water (H2O).

Molar mass is the sum of the atomic masses of all the atoms present in a molecule.

Since the molecule of water contains two atoms of hydrogen and one atom of oxygen, the molar mass of water is given by the sum of the atomic masses of two hydrogen atoms and one oxygen atom, which is: 2(1.008 g/mol) + 1(15.999 g/mol) = 18.015 g/mol

Therefore, one mole of water has a mass of 18.015 g.

The number of moles of water lost can be calculated using the following formula: Number of moles = Mass of substance / Molar mass of substance

Substituting the given values, we get: Number of moles = 0.369 g / 18.015 g/mol = 0.0205 mol

Thus, 0.0205 moles of water were lost if the amount of water lost was 0.369 grams.

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The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

Explanation:

C. A proton and an electron

When the moving car brakes to the stop the kinetic energy of car will be converted to the heat energy.

The mechanical brake will be applies to the friction force and it convert the kinetic energy of the car into the thermal energy that which then dissipates on atmosphere. The process of the braking will follow the principle of the conservation of the energy.

The conservation of the energy is the principle, that is expressed in its the most general form, and it is the first law of the thermodynamics. The first law of thermodynamics explains that "the energy of the universe remains the same."

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This question is incomplete, the complete question is :

A car in motion has kinetic energy. A moving car is suddenly stopped. Why does the car stop? Where did the energy go?

Answer:

unbalanced force

Explanation:

pls mark me brainliest

Answer:

B. balanced forces

Explanation:

the motion of an object will not change if the forces pushing or pulling the object are balanced

From the solution that we have in the question;

The equilibrium constant, denoted as K, is a value that quantitatively represents the ratio of the concentrations of products to reactants at equilibrium in a chemical reaction.

It is a fundamental concept in chemical equilibrium.

The value of the equilibrium constant provides valuable information about the position of equilibrium and the relative concentrations of species involved in a chemical reaction.

Kc = [X] [Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\)

\(0.25(0.5 - x) = (0.1 + x)^2\)

\(0.125 - 0.25x =0.01 + 0.2x + x^2\\ x^2 + 0.45x - 0.115 = 0\)

x = 0.18 M

The equilibrium amount of X and Y=  0.28 M and the equilibrium concentration of XY = 0.32 M

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Based on the answer to the question that we have;

The ratio of the product to reactant concentrations in a chemical reaction at equilibrium is represented quantitatively by the equilibrium constant, abbreviated as K.

It is a cornerstone of the theory of chemical equilibrium.

A chemical reaction's equilibrium position and the relative concentrations of the species involved can both be learned from the equilibrium constant's value.

Kc = [X][Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\\0.25(0.5 - x) = (0.1 +x)^2\\0.125 - 0.25x = 0.01 +0.2x +x^2\\= 0.18 M\)

The equilibrium concentration of;

XY =0.5 - 0.18

=0.32 M

Then the equilibrium amount of

X and Y is

0.1 + 0.18= 0.28 M.

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Answer:

29 L.

Explanation:

Hello!

In this case, considering that we are performing a conversion by which the time should be cancelled out to obtain liters, we first need to convert the seconds on bottom to hours and then the volume on top to liters, just a shown down below:

\(2.0\frac{mL}{s} *\frac{1L}{1000mL} *\frac{3600s}{1hr}*4.0hr\\\\=28.8L\)

Which turns out 29 L with 2 significant figures.

Best regards!

Answer:

Two molecules of hydrogen combine with two molecules of oxygen to form hydrogen peroxide. Hence, its chemical formula is H2O2. It is the simplest peroxide (since it is a compound with an oxygen-oxygen single bond). Hydrogen peroxide has basic uses as an oxidizer, bleaching agent and antiseptic

Answer:

To solve this problem, we can use the definition of percent concentration by mass:

percent concentration = (mass of solute ÷ mass of solution) x 100%

We know that the percent concentration of NaCl in the solution is 15% by mass, and we have a 500 gram sample of the solution. Let's assume that the mass of NaCl in the sample is x grams.

Using the percent concentration formula, we can write:

15% = (x ÷ 500) x 100%

Simplifying this equation, we get:

x = (15 ÷ 100) x 500 = 75 grams

Therefore, there are 75 grams of NaCl in a 500 gram sample of the solution.

The correct answer is c. 75 grams.

When waves travel from one medium to another, they interact. When waves hit a new medium, they may bend or spread out instead of bouncing back like an echo. These three interactions of waves with matter are known as reflection, refraction, and diffraction.

Interactions include reflection, refraction, and diffraction. An example of wave reflection is an echo. Refraction occurs when waves bend at an angle as they enter a new medium. When waves spread out as they travel through an opening in an obstacle, this is referred to as diffraction.

When two or more waves collide, they interact with one another. Wave interference is the interaction of waves with other waves. When two waves traveling in opposite directions collide, wave interference occurs.

Thus, the interactions of waves with matter are known as reflection, refraction, and diffraction.

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The complete form of the table is:

1. For pH = 3.78:

[H₂O¹⁺] can be calculated using the formula [H₂O¹⁺] = 10^(-pH).

[H₂O¹⁺] = 10^(-3.78) = 1.58 x 10⁻⁴ M.

To find pOH, use the equation pOH = 14 - pH.

pOH = 14 - 3.78 = 10.22.

Since the concentration of [OH¹⁻] can be obtained by using the relation [OH¹⁻] = 10^(-pOH).

[OH¹⁻] = 10^(-10.22) = 6.31 x 10⁻¹¹ M.

Based on the pH value, this solution is acidic.

2. For [H₂O¹⁺] = 3.89 x 10⁻⁴ M:

Given the concentration of [H₂O¹⁺],  calculate the pH.

pH can be determined using the equation pH = -log[H₂O¹⁺].

pH = -log(3.89 x 10⁻⁴) ≈ 11.22.

The pOH can be calculated using the equation pOH = 14 - pH.

pOH = 14 - 11.22 ≈ 2.78.

Since the concentration of [OH¹⁻] is related to pOH as [OH¹⁻] = 10^(-pOH).

[OH¹⁻] = 10^(-2.78) ≈ 2.03 x 10⁻¹¹ M.

Based on the pH value, this solution is basic.

3. For pOH = 5.19:

To calculate the concentration of [OH¹⁻], use the relation [OH¹⁻] = 10^(-pOH).

[OH¹⁻] = 10^(-5.19) ≈ 6.05 x 10⁻⁶ M.

To find the pH, we can use the equation pH = 14 - pOH.

pH = 14 - 5.19 ≈ 8.81.

Since the pH is greater than 7, this solution is basic.

4. For [OH¹⁻] = 4.88 x 10⁻¹⁰ M:

Given the concentration of [OH¹⁻], calculate the pOH.

pOH = -log[OH¹⁻].

pOH = -log(4.88 x 10⁻¹⁰) ≈ 9.31.

To find the pH, use the equation pH = 14 - pOH.

pH = 14 - 9.31 ≈ 4.69.

Since the pH is less than 7, this solution is acidic.

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Answer:

i have been doing research and i think its the style. if not its the pollen tube.

Explanation:

Hope i helped!

Answer:

stigma

Explanation:

Answer:

From fastest to slowest its: (4)A to B, (1)E to F, (3)C to D, (2)D to E

Explanation:

The steeper the line is the faster she went. D to E she didn't make any progress because the line is straight. Sry I'm terrible at explaining things.

Answer:

4

Explanation:

From the options provided the result of the error is ( A ) ; The buffer will have a lower capacity because of the smaller number of moles of  HF and F⁻ available to react if an acid or base is added.

Considering the acid ionization equilibrium for the weak acid HF.

A buffer solution is a solution that its PH value remains unchanged when a small amount of acid or base to added to the solution, therefore when the moles of acid or base present in the buffer solution is high enough the buffer solution will have a high buffer capacity. from the mistake of the student the number of moles present is lesser which means that the buffer solution will have a lower capacity

Hence the buffer will have a lower capacity because of the smaller number of moles of HF and F⁻ available to react is an acid or base is added.

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The molecular formula for the compound in the task given above is 2,2,3-trimethylbutane.

The correct answer choice is option b.

The molecular formula of a compound is the name of the compound derived from its structural formula. From the task given above, the parent chain is butane. There are three different substituents groups; 2 different methyl group on carbon 2 and another methyl substituent at carbon 3.

The image to further illustrate the solution to the above problem is attached.

That being said, organic compounds are those compounds which contains carbon and hydrogen.

In conclusion, from the detailed explanation above, it can be deduced that the name of the compound above is 2,2,3-trimethylbutane

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The decomposition of aspirin (acetylsalicylic acid,\(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)).

The decomposition of aspirin (acetylsalicylic acid, \(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)). To determine the moles of each product formed, we need to consider the balanced chemical equation for the reaction:

\(C_{9} H_{8} O_{4} = > C_{7} H_{6}O_{3} +CH_{3} COOH\)

From the equation, we can see that for every 1 mole of aspirin, 1 mole of salicylic acid and 1 mole of acetic acid are produced.

Therefore, the moles of salicylic acid and acetic acid formed will be equal to the number of moles of aspirin that decomposes. If we know the amount of aspirin in moles, we can directly calculate the moles of each product based on stoichiometry.

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Answer:

4.69 x 10²⁴ molecules CH₄

Explanation:

To find the amount of molecules, you need to (1) convert grams to moles (via molar mass) and then (2) convert moles to molecules (via Avogadro's Number). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (125 g).

Molar Mass (CH₄): 16.05 g/mol

Avogadro's Number:

6.022 x 10²³ molecules = 1 mole

125 g CH₄         1 mole            6.022 x 10²³ molecules
----------------  x  ---------------  x  -------------------------------------  =  
                          16.05 g                       1 mole

=  4.69 x 10²⁴ molecules CH₄

Based on their bond and polarity H20 has a higher boiling point than H2S because oxygen has a higher electronegativity than sulfur.

The main atoms in H20 and H2S are oxygen and sulfur. In H20, oxygen and sulfur can create more intermolecular H-bonds than sulfur because oxygen has a higher electronegative which means a tendency to gain electrons.

According to van der Waals attraction, the boiling point is higher when there are more hydrogen bonds. The Partial charges are attracted to one another and the hydrogen in one water molecule is attracted to the oxygen in another molecule.

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Explanation:

Well,

Light travels approximately 1 foot per nanosecond or 186 miles per millisecond or 300,000 kilometers per second.

Hope this helps!

Answer:

2.48 × 10⁴ mol

Explanation:

Step 1: Write the balanced equation

2 CrO₄²⁻ + 3 SO₂ + 4 H⁺ ⇒ Cr₂(SO₄)₃ + 2 H₂O

Step 2: Calculate the reacting moles of CrO₄²⁻

3.00 × 10⁸ L of 5.50 × 10⁻² mM CrO₄²⁻ react. The reacting moles are:

3.00 × 10⁸ L × 5.50 × 10⁻² × 10⁻³ mol/L = 1.65 × 10⁴ mol

Step 3: Calculate the reacting moles of SO₂

The molar ratio of CrO₄²⁻ to SO₂ is 2:3. The reacting moles of SO₂ are 3/2 × 1.65 × 10⁴ mol = 2.48 × 10⁴ mol.

1584 Kg of SO2 is required to treat 3.00 x 10^8 L of 5.50 x 10^-2 mM Cr(VI).

The equation of the reaction is;

2CrO4^2-(aq) + 3SO2(g) + 4H^+(aq) -------> Cr2(SO4)3(s) + 2H2O(l)

Number of moles of Cr(VI) = concentration × volume

concentration =  5.50 x 10^-2 mM or 5.5 x 10^-5 M

volume =  3.00 x 10^8 L

Number of moles of Cr(VI) = 5.5 x 10^-5 M × 3.00 x 10^8 L

= 1.65 x 10^4 moles

From the reaction equation;

2 moles of Cr(VI) reacts with 3 moles of SO2

1.65 x 10^4 moles reacts with  1.65 x 10^4 moles ×  3 moles/2 moles

= 24750 moles

Mass of SO2 = 24750 moles × 64 g/mol

Mass of SO2 = 1584 Kg of SO2

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Answer:

(1). CH3-CH=N-CH2-CH2-CH3.

(2). CH3-CH2-CH =N-CH2-CH3.

(3). CH3-CH2-CH2-CH=N-CH3.

(3). CH3-CH2-CH2-CH2-CH=N.

Explanation:

This is a spectroscopy question. Spectroscopy is an important part of chemistry which is used in the identification of chemical compounds.

So, without mincing words let's dive straight into the solution to the question.

Starting from values of IR given, the absorption at 1620-1680 cm^-1 shows the presence of C = N.

From the question, it is given that there is no signal showing on the spectrum at 3010 - 3090 cm^-1. The absorption at 3010 - 3090 cm^-1 shows the presence of N - H. But, it is not show on the spectrum. Hence, there is no N - H in the compound. That's, there are no Hydrogen atoms attached to Nitrogen atom.

We are given that the mass spectrum of compound A shows the molecular ion at m/z 85, therefore the molar mass of the compound is 85.

Also, from the question the elements present are carbon, Hydrogen and Nitrogen. Therefore, the compound is likely to be C5H11N.

The likely compounds are given below;

(1). CH3-CH=N-CH2-CH2-CH3.

(2). CH3-CH2-CH =N-CH2-CH3.

(3). CH3-CH2-CH2-CH=N-CH3.

(3). CH3-CH2-CH2-CH2-CH=N.

The outer core is about 1,400 miles thick, and it's made mostly of a combination (called an alloy) of iron and nickel, along with small amounts of other dense elements like gold, platinum, and uranium. These metals can, of course, be found on the surface of Earth in solid form.

Answer:

Ni(NO3)2 is the limiting reactant.

Explanation:

- First, we balance the equation...

Ni(NO3)2 + 2 KOH --->  2 KNO3 + Ni(OH)2

- Second, we find the moles of each substance...

65g Ni(NO3)2 / 182.703g Ni(NO3)2 = 0.356 mol Ni(NO3)2

58g KOH / 56.1056g KOH = 1.034 mol KOH

- Third, to make the molar ratio equal to each other for comparison, we either multiply KOH by 1/2 or multiply Ni(NO3)2 by 2 to compare the number of moles; because the Ni(NO3)2 to KOH molar ratio is 1 to 2. Note that the multiplication of moles is only for comparison. We do not use these multiplied values. We use the values from step 2...

0.356 mol Ni(NO3)2 * 2 = 0.712 mol Ni(NO3)2

0.712 mol Ni(NO3)2 < 1.034 mol KOH ... Ni(NO3)2 is the limiting reactant.

1)The new volume at a pressure of 1 atm is 0.25 L.

2)The new temperature of the container at a volume of 2 L is approximately 398°C.

3)The new pressure at 2.5 L is approximately 4.8 atm.

4)The new volume at a temperature of 60°C is approximately 55.8

1)To solve these gas law problems, we can use the ideal gas law equation, which states:

PV = nRT,

where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature in Kelvin.

Balloon volume at a pressure of 0.5 atm:\(V_1\) = 0.5 L, \(P_1\)= 0.5 atm.

New volume at a pressure of 1 atm:\(P_2\) = 1 atm.

We can use the relationship\(P_1V_1 = P_2V_2\) to find the new volume (\(V_2\)).

(0.5 atm)(0.5 L) = (1 atm)(\(V_2\))

\(V_2\) = 0.25 L.

Therefore, the new volume at a pressure of 1 atm is 0.25 L.

2)Container volume: \(V_1\) = 2 L, \(T_1\)= 125°C.

New temperature at the same volume: \(V_2\) = 2 L.

We can use the relationship\(V_1\)/\(T_1\) = \(V_2\)/\(T_2\) to find the new temperature (\(T_2\)).

(2 L)/(125 + 273) K = (2 L)/(\(T_2\) + 273) K

Solving for\(T_2\), we get \(T_2\) ≈ 398°C.

Therefore, the new temperature of the container at a volume of 2 L is approximately 398°C.

3)Initial volume: \(V_1\)= 4.0 L, \(P_1\) = 3.0 atm.

Final volume: \(V_2\) = 2.5 L.

Since the temperature (T) is constant, we can use the relationship \(P_1\)\(V_1\) = \(P_2V_2\) to find the new pressure (\(P_2\)).

(3.0 atm)(4.0 L) = (\(P_2\))(2.5 L)

\(P_2\) ≈ 4.8 atm.

Therefore, the new pressure at 2.5 L is approximately 4.8 atm.

4)Initial volume: \(V_1\)= 50 mL, \(T_1\) = 25°C.

New temperature: \(T_2\) = 60°C.

We need to convert the temperatures to Kelvin.

\(T_1\)= 25 + 273 = 298 K, \(T_2\) = 60 + 273 = 333 K.

We can use the relationship \(V_1/T_1 = V_2/T_2\) to find the new volume (\(V_2\)).

(50 mL)/(298 K) = (\(V_2\))/(333 K)

\(V_2\) ≈ 55.8 mL.

Therefore, the new volume at a temperature of 60°C is approximately 55.8

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Answer:

18.1 g

Explanation:

Step 1: Write the balanced equation

CaO + 3 C ⇒ CaC₂ + CO

Step 2: Calculate the moles corresponding to 10.2 g of C

The molar mass of C is 12.01 g/mol.

10.2 g × 1 mol/12.01 g = 0.849 mol

Step 3: Calculate the moles of CaC₂ produced from 0.849 moles of C

The molar ratio of C to CaC₂ is 3:1. The moles of CaC₂ produced are 1/3 × 0.849 mol = 0.283 mol

Step 4: Calculate the mass corresponding to 0.283 moles of CaC₂

The molar mass of CaC₂ is 64.10 g/mol.

0.283 mol × 64.10 g/mol = 18.1 g

Answer:

B.

Explanation:

Weather changes daily and varies in different areas around the world