Answer:
1 : 7
Step-by-step explanation:
Green : Brown
3 : 21
1 : 7
Question 3 Let X1, X2,..., Xn be independent random variables, each having a uniform distri- bution over (0,1). Let M = maximum (X₁, X₂,..., Xn). Show that the distribution function of M, FM(-), is given by FM(x)=x, 0≤x≤1 What is the probability density function of M?
The distribution function of M, FM(-), is given by FM(x) = x, 0 ≤ x ≤ 1.
The probability density function of M is\(fM(x) = n * x^(^n^-^1^)\), 0 ≤ x ≤ 1.
In order to understand the distribution function of M, we need to consider the probability that M is less than or equal to a given value x. Since each Xi is uniformly distributed over (0,1), the probability that Xi is less than or equal to x is x.
For M to be less than or equal to x, all of the random variables Xi must be less than or equal to x. Since these variables are independent, their joint probability is the product of their individual probabilities. Therefore, the probability that M is less than or equal to x can be expressed as the product of n x's: P(M ≤ x) = x * x * ... * x = \(x^n\).
The distribution function FM(x) is defined as the probability that M is less than or equal to x. Therefore, FM(x) = P(M ≤ x) = \(x^n\).
To find the probability density function (PDF) of M, we differentiate the distribution function FM(x) with respect to x. Taking the derivative of \(x^n\)with respect to x gives us \(n * x^(^n^-^1^)\). Since the range of M is (0,1), the PDF is defined only within this range.
The distribution function of M is FM(x) = x, 0 ≤ x ≤ 1, and the probability density function of M is \(fM(x) = n * x^(^n^-^1^)\), 0 ≤ x ≤ 1.
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Jake spent d dollars to go on vacation. He bought a plane ticket for $250 and stayed in a hotel for 5 nights. If the cost of the hotel room was the same each night, what expression can be used to find how much Jake paid each night for the hotel?
The expression can be used Jake paid each night for the hotel is:
x = d/5 - $50
Now, According to the question:
An expression in math is a sentence with a minimum of two numbers or variables and at least one math operation. This math operation can be addition, subtraction, multiplication, or division.
The given data is:
He bought a plane ticket for $250 and stayed in a hotel for 5 nights.
The price d is equal to $250 + 5 prices of staying in a hotel for a night.
If we let "x" be the price per night then we can get the following:
The expression will be:
d = $250 + 5x
5x = d - $250
\(x = \frac{d - 250}{5}\)
x = d/5 - $50
Hence, The expression can be used Jake paid each night for the hotel is:
x = d/5 - $50.
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Solve.
5x - 10 s 20
O (2]
O (2.2)
O (2, 6]
(6)
Answer:
(6)
Step-by-step explanation:
5×=20+10=
5×=30=
×=6
NEED DONE BY 8 PLEASE HELP
If X is a normal random variable with parameters mu=10 and sigma2=36, compute P(X>5); P(416).
In order to compute the probabilities P(X > 5) and P(X < 16) for a normal random variable X with mean (mu) of 10 and variance (sigma squared) of 36, we can use the properties of the normal distribution.
In the first case, we need to calculate the probability of X being greater than 5. This can be done by standardizing the variable X using the z-score formula: z = (X - mu) / sigma. Plugging in the given values, we get z = (5 - 10) / 6 = -5/6 = -0.8333. By looking up the corresponding value in the standard normal distribution table, we find that the area to the left of z = -0.8333 is approximately 0.2033. Since we are interested in the probability of X being greater than 5, we subtract this value from 1: P(X > 5) ≈ 1 - 0.2033 = 0.7967.
In the second case, we want to calculate the probability of X being less than 16. Using the same approach, we standardize the variable X: z = (16 - 10) / 6 = 1. By referencing the standard normal distribution table, we find that the area to the left of z = 1 is approximately 0.8413. Therefore, P(X < 16) ≈ 0.8413.
To summarize, the probability that X is greater than 5 is approximately 0.7967, while the probability that X is less than 16 is approximately 0.8413.
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Suppose that Sam has vNM utility function u, which is known at two points: u(100) = 1 and u(200) = 2. When facing a lottery L1 = ( £100, w.p. 0.6 £200, w.p. 0.4 , Sam tells the max amount he is willing to pay for this lottery is £120. (a) What is Sam’s expected utility for the lottery L2 = ( £100, w.p. 0.6 £120, w.p. 0.4 ? [15 marks] (b) What is Sam’s risk preferences? [15 marks]
(a) Expected utility is calculated as the weighted average of the utilities of all possible outcomes.
According to the problem, Sam's utility function is u(100) = 1 and u(200) = 2.
The lottery L1 = ( £100, w.p. 0.6; £200, w.p. 0.4 ) has two outcomes with the probabilities of 0.6 and 0.4.
Therefore, the expected utility of the lottery L1 is:
Expected utility of L1 = 0.6 × u(100) + 0.4 × u(200)= 0.6 × 1 + 0.4 × 2= 1.4
Since Sam is willing to pay at most £120 for the lottery L1, this indicates that the expected utility of L1 is worth £120 to Sam. Thus:1.4 = u(£120)
Since we know u(100) = 1 and u(200) = 2, we can linearly interpolate to find u(£120):
u(£120) = u(100) + [(120 - 100)/(200 - 100)] × (u(200) - u(100))= 1 + [(120 - 100)/(200 - 100)] × (2 - 1)= 1.3
Therefore, the expected utility of the lottery L2 = ( £100, w.p. 0.6; £120, w.p. 0.4 ) is:
Expected utility of L2 = 0.6 × u(100) + 0.4 × u(£120)= 0.6 × 1 + 0.4 × 1.3= 0.78
So, Sam's expected utility for the lottery L2 is 0.78
.(b) The risk preferences of Sam can be determined by comparing the utility of the lottery L1 and the sure outcome that gives the same expected value as the lottery L1.
The expected value of the lottery L1 is:Expected value of L1 = 0.6 × £100 + 0.4 × £200= £140
Therefore, Sam needs to be indifferent between the lottery L1 and the sure outcome of receiving £140. Since the expected utility of L1 is 1.4, Sam's utility for receiving £140 must also be 1.4.
This can be represented as:u(£140) = 1.4From part (a), we know that u(£120) = 1.3.
Therefore, the difference between the two utility values is:u(£140) - u(£120) = 1.4 - 1.3= 0.1
The difference in utility is positive but not enough to reflect risk-loving behavior. Therefore, Sam is risk-averse.
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Given the function h(x) = x2 – 7x + 6, determine the average rate of change of
the function over the interval 3 x < 7.
Step-by-step explanation:
the average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.
so,
(h(7) - (h(3)) / (7 - 3)
h(7) = 7² - 7×7 + 6 = 49 - 49 + 6 = 6
h(3) = 3² - 7×3 + 6 = 9 - 21 + 6 = -6
7 - 3 = 4
(6 - -6)/4 = 12/4 = 3
the average change rate in that interval is 3 (or fully 3/1).
Algebra 2 honors, practice homework Really need help with, struggling on !!
SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
The details of the solution are as follows:
a) Equation:
\(f(x)=(3.25)^x\)b) Value of b ( base ): 3. 25
c) Growth or decay: Growth
d) y-intercept: ( 1, 0)
e) Key point : ( 1, 3. 25)
f) Horizontal Asymptote:
\(\text{y = 0}\)g) Domain:
\(\begin{gathered} x\in\text{ R} \\ \text{where R = set of real numbers} \end{gathered}\)h) Range:
\(y>0\)
an analysis of variance comparing three treatment conditions produces dfwithin = 21. if the samples are all the same size, how many individuals are in each sample?a. 7b. 7c. It's impossible for tge sample to be the same of 21d. 8
The ANOVA produced 21 degrees of freedom within three treatment conditions with equal sample sizes. Therefore, each sample contains 8 individuals. So, the correct answer is D).
The formula for calculating degrees of freedom within a one-way ANOVA is
dfwithin = (N - k)
where N is the total number of observations (across all groups) and k is the number of groups being compared.
In this case, we know that dfwithin = 21, and since there are three treatment conditions being compared, k = 3
So, we can rearrange the formula to solve for N:
N = dfwithin + k
N = 21 + 3
N = 24
Since we are told that the sample sizes are all the same, we can divide the total number of observations by the number of groups to get the size of each sample
n = N/k
n = 24/3
n = 8
Therefore, there are 8 individuals in each sample. The answer is (d) 8.
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pls pls pls help me Find x.
Answer:
29 degrees
Step-by-step explanation:
The arc intercepted by inscribed angle x = 360 -180 -122 = 58 degrees
inscribed angles intercept twice as many degrees of arc
x = 58/2 = 29 degrees
Which point represents the unit rate?
Answer:
A
Step-by-step explanation:
FOLLOW DIRECTIONS IN THE PICTURE AND ANSWER PLEASE! WILL MARK BRAINLIEST!!
#5: This is a function. It passes the vertical line test.
#6: This is not a function. It does not pass the vertical line test. For example, x=0 has six y-values paired with that one x-value. A function that does not make.
#7: This passes the vertical line test.
1. Convert the parametric equations below to the form y=f(x) by eliminating the parameter. x=e −2t ,y=6e^4t,0≤t≤ In 4
To eliminate the parameter and express the parametric equations in the form y = f(x), we need to solve for t in terms of x and substitute it into the equation for y.
From the given parametric equations, we have:
x = e^(-2t) ---- (1)
y = 6e^(4t) ---- (2)
To eliminate t, we can take the natural logarithm (ln) of equation (1):
ln(x) = ln(e^(-2t))
ln(x) = -2t
t = -ln(x)/2
Now we can substitute this value of t into equation (2):
y = 6e^(4(-ln(x)/2))
y = 6e^(-2ln(x))
y = 6(x^(-2))
Therefore, the parametric equations x = e^(-2t) and y = 6e^(4t) can be expressed in the form y = f(x) as y = 6(x^(-2)).
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what is the radius of a right circular cylinder with a volume of 12 in3 if it has a minimum surface area?
The value of radius of a right circular cylinder is 1,248 in for which the minimum surface area is obtained.
Define right circular cylinder?A cylinder with two circular bases and a line connecting their centers that is perpendicular to both bases.Volume of the right circular cylinder be;
v(c) = 12 in³ = π*r²*h
In which, h is the height of the cylinder,
Then , h = 12 / π*r²
Surface area of a right circular cylinder is:
S = area of base and top + lateral area
S(A) = 2*π*r² + 2*π*r*h ....eq 1
Put value of 'h' in equation (1)
S(r) = 2*π*r² + 2*π*r* ( 12 / π*r²)
S(r) = 2*π*r² + 24 /r
Differentiate both sides,
S´(r) = 4*π*r - 24 /r²
Put , S´(r) = 0 to get the critical points.
4*π*r - 24 /r² = 0
π*r - 6/r² = 0
π*r³ - 6 = 0
r³ = 1,91
r = 1,248 in
Check for the minimum surface area for r = 1,248 in.
Find the second derivative,
S´´(r) = 4*π + 48/r³
S´´(r) will always be positive.
Thus, the minimum surface area S is for r = 1,248 in.
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Bearing a to b is 280 what is bearing b to A
Answer:
please see photo attached for detailed analysis.
help all questions are in the picture
Answer:
5. 2=1+1
6. 0= -3*0
7.2=3*0+2
find x=, if x-5=10 HURRY!!!!
please help I will give you any award
Answer:
218.57
Step-by-step explanation:
Since it is an isoceles triangle, the sides are 32, 32, and 14.
Using Heron's Formula, which is Area = sqrt(s(s-a)(s-b)(s-c)) when s = a+b+c/2, we can calculate the area.
(A+B+C)/2 = (32+32+14)/2=39.
A = sqrt(39(39-32)(39-32)(39-14) = sqrt(39(7)(7)(25)) =sqrt(47775)= 218.57.
Hope this helps have a great day :)
Check the picture below.
so let's find the height "h" of the triangle with base of 14.
\(\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{32}\\ a=\stackrel{adjacent}{7}\\ o=\stackrel{opposite}{h} \end{cases} \\\\\\ h=\sqrt{ 32^2 - 7^2}\implies h=\sqrt{ 1024 - 49 } \implies h=\sqrt{ 975 }\implies h=5\sqrt{39} \\\\[-0.35em] ~\dotfill\)
\(\stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(\underset{b}{14})(\underset{h}{5\sqrt{39}})}\implies 35\sqrt{39} ~~ \approx ~~ \text{\LARGE 218.57}\)
In ΔKLM, k = 8. 1 inches, l = 6. 6 inches and ∠M=127°. Find the area of ΔKLM, to the nearest 10th of a square inch
The area of triangle ΔKLM is approximately 22.7 square inches.
To calculate the area of triangle ΔKLM, we can use the formula for the area of a triangle: A = (1/2) * base * height.
Given that the length of KL (the base) is 8.1 inches and LM (the height) is 6.6 inches, we can substitute these values into the formula:
A = (1/2) * 8.1 inches * 6.6 inches
A = 0.5 * 8.1 inches * 6.6 inches
A = 26.73 square inches
Since we need to round the answer to the nearest 10th of a square inch, the area of triangle ΔKLM is approximately 26.7 square inches.
The area of triangle ΔKLM is approximately 22.7 square inches.
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£500 is invested for 2 years at 3% simple interest per year.
Work out the total interest.
The total interest of the investment is £30.
How to determine total interest of the investmentFrom the question statement,, we have
Principal, P = 500
Time, t = 2 years
Rate, r = 3%
The formula for simple interest is:
I = Prt
where I is the interest, P is the principal (the amount of money invested), r is the interest rate (as a decimal), and t is the time in years.
In this case, P = £500, r = 0.03 (since the interest rate is 3%), and t = 2 years.
Plugging in these values, we get:
I = £500 x 0.03 x 2
Evaluate
I = £30
Therefore, the total interest earned after 2 years is £30.
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Which of the following algebraic represents shows a dilation that is an enlargement ?
The algebraic representation that shows a dilation that is an enlargement is (5/2 x,5/2 y). (Option D)
A dilation is a type of transformation that changes the size of the shape or object. It refers to a process of changing an object’s size by decreasing or increasing its dimensions by a scaling factor. A dilation produces an image that has the same shape as the original image but is a different size.
A dilation that results in a larger image is called an enlargement while a dilation that generates a smaller image is called a reduction. A dilation is described using the scale factor and the center of the dilation (which is a fixed point in the plane).
For a scale factor > 1, the image is an enlargement; for a scale factor < 1 and > 0, the image is a reduction; and for a scale factor = 1, the figure and the image are congruent. Hence, for a point (x,y), algebraic representation that shows a dilation that is an enlargement is (5/2 x,5/2 y) as the scale factor is greater than 1. For the remaining options, the scale factor is between 0 and 1, hence they are reduction.
Note: The question is incomplete. The complete question probably is: Which of the following algebraic representation shows a dilation that is an enlargement? A) (1/3 x,1/3 y) B) (0.1x, 0.1y) C) (5/6 x,5/6 y) D) (5/2 x,5/2 y)
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What is the midpoint of the segment shown below? For geometry worksheet!
Answer:
D
Step-by-step explanation:
The y-coordinate will be the average of 5 and -2 which is 3/2. This eliminates options A and B. C doesn't make sense because the x-coordinate (which is -7) of the midpoint can't be larger or smaller than the x-coordinates of the endpoints, so that means that the answer is D.
On 1 October 2015 Karen purchased freehold land and buildings for £480,000, of which the land element was £80,000. The buildings had a useful life of 25 years at the date of purchase. The residual value was nil.
On 1 October 2020 the land and buildings were revalued to £500,000, of which the land element was £100,000. There was no change in the useful life of the property.
According to IAS 16 Property, Plant and Equipment, what should be the depreciation charge for the year ended 30 September 2021 and the balance on the revaluation surplus as at that date?
A Depreciation charge £16,000; revaluation surplus £100,000
B Depreciation charge £20,000; revaluation surplus £100,000
C Depreciation charge £25,000; revaluation surplus £116,000
D Depreciation charge £20,000; revaluation surplus £116,000
Accoding to the calculations , the correct answer is:
A) Depreciation charge 16,000; revaluation surplus £20,000
According to IAS 16 Property, Plant and Equipment, the depreciation charge for an asset should be based on its carrying amount, useful life, and residual value.
In this case, the buildings were purchased for £400,000 (£480,000 - £80,000) and had a useful life of 25 years. Since there is no residual value, the depreciable amount is equal to the initial cost of the buildings (£400,000).
To calculate the annual depreciation charge, we divide the depreciable amount by the useful life:
£400,000 / 25 = £16,000
Therefore, the depreciation charge for the year ended 30 September 2021 is £16,000.
Now, let's calculate the balance on the revaluation surplus as at that date.
The revaluation surplus is the difference between the fair value of the property and its carrying amount. On 1 October 2020, the property was revalued to £500,000, and the carrying amount was £480,000 (£400,000 for buildings + £80,000 for land).
Revaluation surplus = Fair value - Carrying amount
Revaluation surplus = £500,000 - £480,000
Revaluation surplus = £20,000
Therefore, the balance on the revaluation surplus as at 30 September 2021 is £20,000.
Based on the calculations above, the correct answer is:
A) Depreciation charge £16,000; revaluation surplus £20,000
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in a certain company 120 of the employees are men. what is the total number of employees if 5 out of every 8 employees are men?
Answer:
There are 192 employees in the company.
Step-by-step explanation:
Let x be the total number of employees
Use ratio and proportion
\(\frac{120}{x} =\frac{5}{8} \\5x = 120(8)\\5x = 960\\\frac{5x}{5} = \frac{960}{5} \\x = 192\)
x = 192
The local theater sells tickets to its plays at a rate of $38 each. Patrons who attend multiple shows are encouraged to
buy an annual membership for $80. Members are able to buy tickets at a discounted rate of $20 each. Roger expects
to attend 6 shows this year. Grace expects to attend 4 shows. Who would benefit from buying a membership this
year?
O neither Grace nor Roger
only Grace
O only Roger
O both Grace and Roger
Answer: C
Step-by-step explanation:
The local weather sells the tickets the play rate of $38 and patrons attend multiple shows to encourage the buyers giving them a discount of 20$ each. The rogers has to attend the shows same year.
Without Membership: 38*6 = 228 having the membership: 80 + 20*6 = 200. For grace the total Cost/Revenue for Grace: Without the membership: 38*4 = 152. Buying with the Membership: 80 + 20*4 = 160Hence the option B is correct.
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factorise completely 15a^3 - 5ab
pwease help me
4x + 2(2x - 3) = 8(x - 1)
Answer:
No solution
Step-by-step explanation:
4x + 2(2x - 3) = 8(x - 1)
4x + 4x - 6 = 8x - 8
8x - 6 = 8x - 8
0 = -2
There is no value of x makes the equation true.
Given the parent functions f(x) = 5x - 1 and g(x) = 3^x-
9, what is g(x) - f(x)?
Answer:
g(x) - f(x) = 3^x - 9 - (5x - 1) = 3^x -5x - 8
n a survey of randomly selected people, the ratio of people who prefer oatmeal to those who prefer eggs is 3 to 5. if 21 people said they prefer oatmeal, how many said they prefer eggs?
The number of people who prefer eggs is 35.
In mathematics, a ratio is a comparison of two or more numbers that indicates their sizes in relation to each other. A ratio compares two quantities by division, with the dividend or number being divided termed the antecedent and the divisor or number that is dividing termed the consequent. A ratio might be formatted as a Part to Part or Part to Whole comparison. A Part to Part comparison looks at two individual quantities within a ratio of greater than two numbers, such as the number of dogs to the number of cats in a poll of pet type in an animal clinic. A Part to Whole comparison measures the number of one quantity against the total, such as the number of dogs to the total number of pets in the clinic.
Let the number of people who prefer eggs be x.
21 people said they prefer oatmeal.
The ratio of people who prefer oatmeal to those who prefer eggs is 3 to 5.
∴ \(\frac{21}{x} = \frac{3}{5} \\x = \frac{21*5}{3}\\ x = \frac{105}{3} \\x = 35\)
Thus, the number of people who prefer eggs is 35.
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a circular cake is split into four quarters. if the diameter of the cake is 25 cm, how long is the perimeter of each piece?
Answer:
(6.25\(\pi\) + 25)cm is the exact answer
44.625 cm is an approximation
Step-by-step explanation:
c = circumference (perimeter)
d = diameter
C = \(\frac{\pi d}{4}\)
C = \(\frac{25\pi }{4}\) = 6.25\(\pi\) This is the exact answer
That would be the curved part of the pi. Then we need to add the 2 sides which would be \(\frac{25}{2}\) + \(\frac{25}{2}\) = \(\frac{50}{2}\) = 25 The sides are the length of the radius which is half of the diameter.
(6.25\(\pi\) + 25)cm is the exact answer
If we use 3.14 for \(\pi\) The approximate answer would be:
6.25(3.14) + 25
19.625 + 25
44.625 cm is an approximation