Moving a charge from point A, where the potential is 506.59 V, to point B, where the potential is 170.81 V, takes 0.62 milliJ of work. What is the value of the charge, in micro-Coulombs?

Answers

Answer 1

For this problem, we will need to work backwards

w = Uf - Ui

U = Vq

.62 x 10^ -3 = 506.59q - 170.81q

q = .62 x 10^ -3/(506.59-170.81) = 1.846 x 10 ^-6 = -1.846 microCoulombs


Related Questions

Which statement about electric charges is correct? (1 point)

*two objects with negative charges will attract each other
*an object with a negative charge and an object with a positive charge will attract each other
*an object with a positive charge and an object with a negative charge will repel each other
*two objects with positive charges will attract each other

Answers

Answer:The correct statement about electric charges is:

"An object with a negative charge and an object with a positive charge will attract each other."

Explanation:

*an object with a negative charge and an object with a positive charge will attract each other" this statement is true.

What is charge ?

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C.

Hence option B is correct.

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Hendry throws an object vertically upwards at a velocity of 26,5 m⋅s-1 from the
edge of a cliff of height 120m. After some time, the projectile lands on the
ground below the cliff After 1 second, Cathy fires a second object upwards FROM THE
GROUND BELOW with a velocity of 45 m⋅s-1. Calculate the time and
distance will the two objects meet.

Answers

Hendry and Cathy will each throw an object, and the time and location at which they will collide can be determined using the laws of motion. Hendry's item had an initial velocity of 26.5 m/s, whereas Cathy's object had an initial velocity of 45 m/s. Hendry's object's equation of motion is given by: s = u*t + 0.5*a*t*2, where s is the displacement, u*t* is the starting velocity, t* is the time, and a*t* is the acceleration brought on by gravity.

The acceleration caused by gravity is negative since the item is being flung upward. The item that Cathy threw has the following equation of motion: s = u * t - 0.5 * a * t2.where s is the distance travelled, u is the starting speed, t is the passage of time, and an is the acceleration brought on by gravity. The acceleration caused by gravity is negative since the item is being flung upward.

These equations allow us to determine the location and timing of the two items' collision. By figuring out the two equations for t, one may determine the moment when the objects will collide. By changing the value of t in either equation, one may determine the distance at which the objects will collide. Therefore, using the equations of motion, it is possible to determine the moment and distance at which the two objects will collide.

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It takes 225 kJ of work to accelerate a car from 20.1 m/s to 28.1 m/s. What is the car's mass?

Answers

Answer:

THE REMAINIG WILL BE 75

Explanation:

HOPE IT HELPS YOU

what observavtion can you make that allows you to determine the magnitudes of the forces on the upper book

Answers

The best, most helpful observation you can make is to LOOK steadily and squarely at the PICTURE of the stack.

For some nefarious reason, you decided to prevent us from doing that.

The higher density a material the:

Faster the speed of light

Slower the speed of light

Speed of light stays the same

Speed of light cannot be determined

Answers

The higher density a material the: Slower the speed of light. Option C. slower the speed of light.

A material is considered high density material when it is endowed with more entity, or stuff gathered into a given space.

What is the relationship between a high density material and the speed of light?

Higher-density materials is known to often have excess refractive indices. The greater the refractive index, the slower light travels through such material. In the same vain, lower-density materials normally have lesser refractive indices. Consequently, the lesser the refractive index, the faster light travels through the material.

Therefore, the correct answer is as given above.

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If the average hang time of a professional football kick is 4.4s, then determine the average maximum height.

Answers

The average highest height of a professional football kick is 189.728 m if the hang time is 4.4 seconds on average.

What is meant by hang time?

A person or an object's total duration in the air after leaving the ground is known as their "hang time." From the time anything leaves the ground until it returns, it is measured.

We know,

y= gt²

Here,

y = Average maximum height

g = acceleration due to gravity

t = Average hang time

Given,

Average hang time (t) = 4.4s

Acceleration due to gravity (g) = 9.8 m/s² (assuming)

Inserting these values in the given equation,

y = gt²

  = 9.8×4.4×4.4

  = 189.728 m.

Hence, the average maximum height of the football is 189.728 m.

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What is the hardest stage of BME​

Answers

Answer:

Neural Engineering and Tissue Engineering

Explanation:

• BME is Biomedical Engineering. It has various topics such as Anantomy, Physiology, Neural Engineering and Tissue engineering, Medical mechanisation and others.

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How do tsunamis cause flooding? Please answer in 4-5 sentences.
PLEASE HELP! GIVING BRAINLIEST!

Answers

Answer:  YES

Explanation: The main difference between flood and tsunami  is that the flood is overflow of water that submerges land and tsunami is a series of water waves caused by the displacement by large volume of a volume of water

Answer:

WEEEEEEEEEEEEEEEEEEEEEEEEE

Explanation:

A bunny hopping along the road can travel at an average of 0.6 m/s. Calculate far the bunny can travel in 11 seconds.

Answers

Answer:

6.6 m

Explanation:

.6 m/s   *  11 s  = 6.6 m    ( see how the 's' cancels out and you are left with 'm'  as the answer ?)

Two girls are estimating each other's power. One runs up some step
ng each other's power. One runs up some steps, and the other times her. Here are their
results:
height of one step = 20 cm
number of steps = 36
mass of runner = 45 kg
time taken = 4.2 s
a .Calculate the runner's weight. (Acceleration due to gravity g=10m
b .Calculate the increase in the girl's gravitational potential energy as she runs up the steps.
c. Calculate her power. Give your answer in kilowatts (kW).​

Answers

Answer:

A. 450 N

B. 3240 J

C. 0.77 KW

Explanation:

From the question given above, the following data were obtained:

Height of one step = 20 cm

Number of steps = 36

Mass of runner = 45 kg

Time taken = 4.2 s

Next, we shall convert 20 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

20 cm = 20 cm × 1 m /100 cm

20 cm = 0.2 m

Next, we shall determine the total height. This can be obtained as follow:

Height of one step = 0.2 m

Number of steps = 36

Total height =?

Total height = 36 × 0.2

Total height = 7.2 m

A. Determination of the runner's weight.

Mass of runner (m) = 45 kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

W = m × g

W = 45 × 10

W = 450 N

B. Determination of the increase in the potential energy.

At the ground level, the potential energy (PE₁) is 0 J.

Next, we shall determine the potential energy at 7.2 m. This can be obtained as follow:

Mass of runner (m) = 45 kg

Acceleration due to gravity (g) = 10 m/s²

Total height (h) = 7.2 m

Potential energy at height 7.2 m (PE₂) = ?

PE₂ = mgh

PE₂ = 45 × 10 × 7.2

PE₂ = 3240 J

Final, we shall determine the increase in potential energy. This can be obtained as follow:

Potential energy at ground (PE₁) = 0 J

Potential energy at height 7.2 m (PE₂) = 3240 J

Increase in potential energy =?

Increase in potential energy = PE₂ – PE₁

Increase in potential energy = 3240 – 0

Increase in potential energy = 3240 J

C. Determination of the power.

Energy (E) = 3240 J

Time (t) = 4.2 s

Power (P) =?

P = E/t

P = 3240 / 4.2

P = 771.43 W

Finally, we shall convert 771.43 W to kilowatt (KW). This can be obtained as follow:

1000 W = 1 KW

Therefore,

771.43 W = 771.43 W × 1 KW / 1000 W

771.43 W = 0.77 KW

Therefore, her power is 0.77 KW

3/4+ (10 * 7/3- 4) * (-11) -2

Answers

Answer:

-210.25

Explanation:

you should start at the braces, and start with multipe the numbers and then have the answer

Sequence of operations:

1.Brackets

2.braces

3.multiply

4. plus

5.negetive

3/4+ (10 * 7/3- 4) * (-11) -2

Methane and oxygen combine in a synthesis reaction. true or false

Answers

Answer:

True.

Explanation:

A synthesis reaction is a type of chemical reaction in which two or more substances combine to form a new compound. Methane (CH4) and oxygen (O2) can combine in a synthesis reaction to form carbon dioxide (CO2) and water (H2O). This reaction is exothermic and is the basis of combustion reactions.

The balanced equation for this reaction is:

CH4 + 2O2 -> CO2 + 2H2O

In this reaction, one methane molecule and two oxygen molecules combine to form one carbon dioxide molecule and two water molecules.

It's worth mentioning that methane is considered a greenhouse gas, and the combustion of methane releases carbon dioxide and water vapor into the air, which contribute to global warming and climate change.

The answer is true you can even look up on the web… I will also give you a site where you can learn more…

I need help with this question

I need help with this question

Answers

Explanation:

a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed

A boy starts at rest and slides down a frictionless slide as in the figure below. The bottom of the track is a height h above the ground. The boy then leaves the track horizontally, striking the ground a distance d as shown. Using energy methods, determine the initial height H of the boy in terms of h and d.

Answers

The initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track: H = h + d.

To determine the initial height H of the boy in terms of h and d, we can use the principle of conservation of energy. The total mechanical energy of the system remains constant throughout the motion.

At the top of the slide, the boy has gravitational potential energy given by mgh, where m is the mass of the boy, g is the acceleration due to gravity, and h is the height of the slide above the ground.

As the boy slides down the slide, there is no friction or other dissipative forces, so there is no change in mechanical energy. At the bottom of the track, the gravitational potential energy is converted entirely into kinetic energy.

Therefore, we can equate the initial potential energy to the final kinetic energy:

mgh = 1/2 m\(v^{2}\),

where v is the horizontal velocity of the boy when he leaves the track.

Since the boy leaves the track horizontally, the vertical component of his velocity is zero. Therefore, we can use the relationship between horizontal distance d and horizontal velocity v:

d = vt.

Solving these equations, we can express the initial height H in terms of h and d:

H = h + d.

So the initial height H of the boy can be determined by adding the height of the slide h and the horizontal distance d the boy travels after leaving the track.G

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Find the size of the image formed in the situation shown in figure.
A) 0.5 cm
B) 0.6 cm
C) 1.2 cm
D) 1 cm

Answers

Given

distance of the object  u = -40 cm.

radius of curvature of the refracting surface  R = -20 cm.

The height of the object  h = 1 cm.

To Find

The size of the image

Solution

We will now write the following data using the sign convention:

The object's distance is u = -40 cm.

The refracting surface has a radius of curvature of R = -20 cm.

The object's height is h = 1 cm.

We know that the lens maker formula is: n2vn1u=n2n1R.

v denotes the image formation distance.

The refractive index of the second medium is n2=1.33, and the refractive index of the first medium is n1=1.

In the preceding equation, we will now substitute the known values.

1.33v−1−40cm=1.33−1−20cmv=32.05cm

We know that the magnification ratio can be expressed as vu=Hh.

H denotes the height of the created image.

We'll now swap the given and obtained values.

32.05cm divide by 40cm=H divide by 1cm

H=0.6cm

As a result, the best choice is (B).

Further information: The rules of reflection apply to reflection from a concave mirror. The normal to the point of incidence is drawn along the radius of the mirror, that is, by connecting the point of incidence to the centre of curvature.

The development of an image in a concave mirror is mostly determined by the distance between the object and the mirror. The concave mirror produces both real and virtual images.  A virtual and magnified picture is generated when the object is placed very close to the mirror.

The complete question is -

Find the size of the image formed in the situation shown in figure.

photo

A) 0.5 cm

B) 0.6 cm

C) 1.2 cm

D) 1 cm

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Find the size of the image formed in the situation shown in figure.A) 0.5 cmB) 0.6 cmC) 1.2 cmD) 1 cm

If a person is putting in 500 J of work in a 25 second period, how much power are they producing?​

Answers

P= work/time. the work here is 500J and the time is 25s. simply plug in the given info into the equation. 500J/25s. remember that the unit of power is watts. your answer is 20 watts. hope this helps !

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point. What is the heat of fusion of the substance?

Answers

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point ,  the heat of fusion of the substance is 548 joules .

What is heat of fusion ?

Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.

Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams  of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.

q = m×∆Hf

q: Total change in heat energy (in Joules)

∆Hf: Heat of fusion of substance (in Joules per gram)

m: Mass of substance (in grams)

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Assume the three blocks

(m1 = 1.0 kg,


m2 = 2.0 kg,

and

m3 = 3.5 kg)

portrayed in the figure below move on a frictionless surface and a force

F = 46 N

acts as shown on the 3.5 kg block.
find acceleration, tension of the cord between the 3.5 and 1 block, and the force excreted on the 2 block from the 1 block.

Answers

The  acceleration, tension of the cord between the 3.5 and 1 block, and the force excreted on the 2 block from the 1 block is 12.6 N.

How to find the acceleration?

To solve this problem, we need to apply Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

We can start by finding the acceleration of the system. Since the surface is frictionless, there are no horizontal forces acting on the blocks except for the tension in the string. Thus, we can write:

F - T = (m1 + m2 + m3) * a

where F is the force acting on the 3.5 kg block, T is the tension in the string between the 3.5 kg and 1 kg blocks, and a is the acceleration of the system. Substituting the values given in the problem, we get:

46 N - T = (1 kg + 2 kg + 3.5 kg) * a

46 N - T = 6.5 kg * a

Next, we need to find the tension in the string between the 3.5 kg and 1 kg blocks. This tension is the same throughout the string, so we can use the same equation we used to find the acceleration:

T - m1 * g = m1 * a

where g is the acceleration due to gravity (9.8 m/s^2). Substituting the values given in the problem, we get:

T - 1 kg * 9.8 m/s^2 = 1 kg * a

T = 1 kg * (a + 9.8 m/s^2)

Now, we can substitute this expression for T into the first equation we derived to get:

46 N - 1 kg * (a + 9.8 m/s^2) = 6.5 kg * a

Simplifying and solving for a, we get:

a = 2.84 m/s^2

Now that we know the acceleration of the system, we can find the force exerted by the 1 kg block on the 2 kg block. Since there are no horizontal forces acting on the 2 kg block, this force is equal in magnitude and opposite in direction to the force exerted by the 2 kg block on the 1 kg block. Thus, we can write:

F1-2 = -m2 * a

where F1-2 is the force exerted by the 1 kg block on the 2 kg block. Substituting the values given in the problem, we get:

F1-2 = -2 kg * 2.84 m/s^2

F1-2 = -5.68 N

Therefore, the force exerted by the 1 kg block on the 2 kg block is 5.68 N, directed to the left.

Finally, we can use the equation we derived earlier for the tension in the string to find the tension between the 3.5 kg and 1 kg blocks. Substituting the value we found for a, we get:

T = 1 kg * (2.84 m/s^2 + 9.8 m/s^2)

T = 12.6 N

Therefore, the tension in the string between the 3.5 kg and 1 kg blocks is 12.6 N.

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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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You have a piece of cork with a volume of 2 cm3 and a density of 210 kg/m3. You hold it under water and release it.
a. What is the mass of the piece of cork? (1 point)



b. What is the buoyant force on the cork after you release it? (1 point)



c. What is the net force on the cork after you release it? (1 point)





d. What is the acceleration of the cork after you release it? (1 point)

Answers

Answer:

a.   m = 4.2•10⁻⁴ kg

b.   B = 0.01962 N

c.   ∑F = 0.0155 N (upward)

d.   a = 6.51•10⁻⁶ m/s² (upward)

Explanation: I'm unsure if you have the correct values, but either way, the steps are below:

a. Mass:

Volume • Density = Mass

(2 cm³)(210 kg/m³)(10⁻⁶ m³/cm³)= 0.00042 kg or 4.2•10⁻⁴ kg

b. Buoyant Force:

Fluid Density • Displaced Volume • Gravity = Buoyant Force

**The Fluid is water, so the fluid density = 1 g/cm³, and the displaced volume is the same as the volume of the cork.**

ρ • V • g = B

[(1 g/cm³)(10⁻³ kg/g)](2 cm³)(9.81 m/s²) =

(10⁻³)(2)(9.81) = 0.01962 N

c. Net Force:

∑F: B - W = ma

mass • gravity = W

(4.2•10⁻⁴ kg)(9.81 m/s²) = 0.0041202 N

(0.01962) - (0.0041202) = 0.0154998 N

d. Acceleration:

F = ma

F/m = a

(0.0155•10⁻² kg•m/s²)/(4.2•10⁻⁴ kg) = 0.000006509916 m/s²

                                                      or 6.51•10⁻⁶ m/s²

––––––––––––––––––––––––––––––––––––––

The reason the values are so small is because N = kg•m/s², so all mass units need to stay in kg, even though it would be simpler to have them in grams.

A laser positioned on a ship is used to communicate with a small two man research submarine resting on the bottom of a lake. The laser is positioned 12 m above the surface of the water, and it strikes the water 20 m from the side of the ship. The water is 76 m deep and has an index of refraction of 1.33. How far is the submarine from the side of the ship

Answers

Answer:

84.1 m

Explanation:

Given :

The distance from the ship to submarine :

20 + y

Using Pythagoras :

Tan θ = opposite / Adjacent

Tan θ = 20 / 12

12 tan θ = 20

θ = tan^-1(20/12)

20

θ = 59.036°

The angle phi;

n1sinθ1 = n2sin θ

Sin 59.036 = 1.33 * sin phi

Sin phi = sinsin(59.04) ÷1.33

0.8574907 = 1.33 * sin phi

Sin phi = 0.8574907 / 1.33

Sin phi = 0.6447298

phi = sin(0.6447298

Phi = 40.15°

From Pythagoras :

y = 76tan40.15°

y = 76 * 0.8435707

y = 64.11

20 + y

20 + 64.11 = 84.11

A laser positioned on a ship is used to communicate with a small two man research submarine resting on

Which object would have more momentum?

A 2 kg ball rolling at 4 m/s

A 5 kg ball rolling at 2 m/s

(Hint: Use momentum = mass * velocity)

a
Not enough information to determine which ball has more momentum.
b
They have the same momentum.
c
The 2 kg ball will have more momentum.
d
The 5 kg ball will have more momentum.

Answers

Answer:

b is the ans......

Explanation:

"b" (and any subsequent words) was ignored because we limit queries to 32 words.

Calculate the wavelength (in m) of a 589 Hz sound in air at room temperature and pressure where the velocity of sound is 344 m/s.

Answers

Answer:

just use the formula λ = v/f

Explanation:

v = velocity

f = frequency

If My mom is 40 and my goldfish died what is my favorite color ?

Answers

Answer:

square

Explanation:

+=-=

Answer:

SɴOWʙʟØWɘR

Explanation:

1)Answer the following question in sort
a)Define pressure ?
b)What is the value of standard atmospheric pressure?
c)Mention any one application of liquid pressure in our daily life?
d)Mention in the name of the instruments used to measure the pressure of compressed air?
e)Which instrument is used to measure atmospheric pressure ?
f)What is the unit of compressed air?
g)Define standard atmospheric pressure?
h)Which property of liquid is applicable in water supply system in cities?
i)Which property of liquid supports to use in it in hydraulic machine?

2)Answer the following questions in detail a)Define atmospheric pressure? Prove the presence of atmospheric pressure with the help of an activity?
b)Derive that P=dgh?
c)Describe the structure and working method of mercury barometer briefly?
d)Enlist any three points to show the importance of atmospheric pressure?
e)Enlist any four application of liquid pressure?f)Mention any three events occurred in our daily life which are directly related with pressure?​

Answers

1)a) Pressure is the force exerted per unit area, measured in units such as pascals (Pa) or pounds per square inch (psi).

b) The value of standard atmospheric pressure is approximately 101.3 kilopascals (kPa) or 1 atmosphere (atm).

c) One application of liquid pressure in our daily life is in hydraulic systems, like car brakes, where liquid pressure is used to transmit force and amplify it.

d) The instruments used to measure the pressure of compressed air include pressure gauges or manometers.

e) An instrument called a barometer is used to measure atmospheric pressure.

f) The unit of compressed air is typically measured in pounds per square inch (psi) or pascals (Pa).

g) Standard atmospheric pressure is the pressure exerted by the Earth's atmosphere at sea level. It is approximately equal to 1 atm or 101.3 kPa.

h) The property of liquid that is applicable in water supply systems in cities is its ability to flow and exert pressure, allowing water to be distributed through pipes and reach different levels in buildings.

i) The property of liquid that supports its use in hydraulic machines is its incompressibility, allowing it to transmit force and energy effectively.

2) a)Atmospheric pressure is the force exerted by the weight of the Earth's atmosphere on a surface.

b) The equation P = dgh. This equation can be derived by considering the weight of the fluid column and the force it exerts on a unit area at the base.

c) A mercury barometer consists of a glass tube filled with mercury, inverted into a dish of mercury. The mercury in the tube adjusts its height based on the atmospheric pressure.

d) The importance of atmospheric pressure can be seen in its role in weather patterns, maintaining the balance of gases in the atmosphere, and facilitating breathing for humans and animals.

e) Applications of liquid pressure include hydraulic systems in machinery, such as lifts and cranes, hydraulic brakes in vehicles, and water towers for maintaining water pressure in buildings.

f) Events in daily life directly related to pressure include inflating a balloon, using a bicycle pump to inflate tires, and squeezing toothpaste out of a tube.

1)a) Pressure is defined as the force per unit area. Its unit in the S.I system is newtons per square meter (N/m²) or Pascal (Pa).

b) The value of standard atmospheric pressure at sea level is 101.3 kPa (kilopascals) or 1 atm (atmosphere). c) Liquid pressure has numerous applications in our daily life, but one of the most common ones is the hydraulic braking system used in cars.

d) An instrument used to measure the pressure of compressed air is called a pressure gauge. e) An instrument used to measure atmospheric pressure is called a barometer.

f) The unit of compressed air is generally psi (pounds per square inch).

g) Standard atmospheric pressure is the pressure exerted by the atmosphere at sea level and is equal to 101.3 kPa or 1 atm.

h) The property of liquids that is applicable in water supply systems in cities is their incompressibility. i) The property of liquids that supports their use in hydraulic machines is their incompressibility.

2)a) Atmospheric pressure is defined as the force per unit area exerted by the weight of the atmosphere on the surface. It is proven with the help of the following activity: Take a glass full of water and place a cardboard over it. Hold the cardboard tight and invert the glass. The water will not spill out of the glass, which is because the atmospheric pressure is greater on the cardboard than the pressure inside the glass.

b) The pressure exerted by a fluid can be derived using P = dgh, where P is the pressure, d is the density, g is the acceleration due to gravity, and h is the height of the fluid column.

c) A mercury barometer is made up of a glass tube that is closed at one end and filled with mercury. The tube is inverted and placed in a container of mercury. The pressure of the atmosphere on the open surface of the container forces the mercury in the tube to rise to a height that is proportional to the atmospheric pressure.

d) The importance of atmospheric pressure can be explained by the following points: it enables breathing, regulates the weather, and causes the ocean tides.

e) Some applications of liquid pressure include hydraulic brakes in cars, hydraulic lifts, and hydraulic jacks.

f) Some events that are directly related to pressure include gas escaping from a pressurized container, balloons being inflated, and soda cans being opened.

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blank refers to the method of spreading fertilizer evenly over the entire field by hand it is done at the blank stage

Answers

Answer:

Broadcasting is the method, not sure about the stage it is done in

Explanation:

Answer:

Broadcasting is the first (blank) second (blank) is Cultivation.

Explanation:

I took the test & got this answer correct.

Which law of thermodynamics does each of the following scenarios violate (if any)?
A machine that can turn 1000J of heat directly into 1000J of electricity
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed

Answers

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

(ASAP) would it be 125 m/s2 to calculate for her speeding up?

(ASAP) would it be 125 m/s2 to calculate for her speeding up?

Answers

Answer:

\(0\:\mathrm{ m/s^2}\)

Explanation:

Recall the formula for acceleration:

\(\displaystyle\\a=\frac{v_f-v_i}{\Delta t}\), where \(v_f\) is final velocity, \(v_i\) is initial velocity, and \(\Delta t\) is elapsed time (change in velocity over this amount of time).

Let's look at our time vs velocity graph. At t=0 seconds, V=25 m/s. So her initial velocity is 25 m/s.

We want to find the acceleration during the first 5 seconds of motion. Well, looking at our graph, at t=5 seconds, isn't our velocity still 25 m/s? Therefore, final velocity is 25 m/s (for this period of 5 seconds).

We are only looking from t=0 seconds to t=5 seconds which is a total period of 5 seconds. Therefore, elapsed time is 5 seconds.

Substituting values in our formula, we have:

\(\displaystyle a=\frac{25-25}{5}=\frac{0}{5}=\boxed{0\:\mathrm{m/s^2}}\)

Alternative:

Without even worrying about plugging in numbers, let's think about what acceleration actually is! Acceleration is the change in velocity over a certain period of time. If we are not changing our velocity at all, we aren't accelerating! In the graph, we can see that we have a straight line from t=0 seconds to t=5 seconds, the interval we are worried about. This indicates that our velocity is staying the same! At t=0 seconds, we have a velocity of 25 m/s and that velocity stays the same until t=5 seconds. Even though we are moving, we haven't changed velocity, which means our average acceleration is zero!

A Student 330 m 990m from another tall flip between the the Student stands Sound Interval beteeen cliff is cliff from of 1 st and 630 tall Hip which speed of 330 if the 330 m/s 2nd eh what is echo?​

Answers

The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

For the simple harmonic oscillation where k = 19.6
N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v =
(0.808 m/s) sin 8.08t, determine (a) the total energy, (b)
the kinetic and potential energies as a function of time,
(c) the velocity when the mass is 0.050 m from
equilibrium, (d) the kinetic and potential energies at
half amplitude (x = A/2).

Answers

a. Total energy is 0.098 J

b. Potential and Kinetic Energies is 0.032 sin^2(8.08t) J

c. Velocity at x is -0.808 sin(8.08t) m/s

d. Potential and Kinetic Energies at x is 0.016 sin^2(8.08t) J

Step by step explanation

We can use the following formulas for the energy, velocity, and potential and kinetic energies of a simple harmonic oscillator:

Total Energy: E = 1/2 k A^2Velocity: v = -ωA sin(ωt)Potential Energy: U = 1/2 k x^2Kinetic Energy: K = 1/2 m v^2

where ω = √(k/m) is the angular frequency.

Given that k = 19.6 N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v = (0.808 m/s) sin 8.08t, we can find the values of E, U, and K as follows:

(a) Total Energy:

E = 1/2 k A^2 = 1/2 * 19.6 * 0.1^2 = 0.098 J

(b) Potential and Kinetic Energies:

U = 1/2 k x^2 = 1/2 * 19.6 * (-0.1 cos(8.08t))^2 = 0.098 cos^2(8.08t) J

K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.032 sin^2(8.08t) J

(c) Velocity at x = 0.050 m:

When x = 0.050 m, cos(8.08t) = -0.5, so we have:

v = -ωA sin(ωt) = -ω(0.1) sin(8.08t) = -0.808 sin(8.08t) m/s

(d) Potential and Kinetic Energies at x = A/2:

When x = A/2 = 0.050 m, cos(8.08t) = -0.5, so we have:

U = 1/2 k x^2 = 1/2 * 19.6 * (0.050)^2 = 0.0245 J

K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.016 sin^2(8.08t) J

Note that the sum of potential and kinetic energies at any point in time is equal to the total energy, which is constant.

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