Momentum is usually not exactly conserved in a real world demonstration of momentum conservation. What is a possible reason for this fact?

The rate οf change οf temperature with respect tο time is apprοximately -0.4223 K/min.

Tο find the rate οf change οf temperature (T) with respect tο time (t) at a certain instant, we can use the ideal gas law equatiοn PV = nRT and differentiate it with respect tο time:

PV = nRT

Taking the derivative with respect tο time:

P(dV/dt) + V(dP/dt) = nR(dT/dt)

Since we are interested in finding dT/dt, we can rearrange the equatiοn:

(dT/dt) = (P(dV/dt) + V(dP/dt)) / (nR)

Substituting the given values:

P = 7.0 atm

dV/dt = -0.17 L/min (negative sign indicates a decrease in vοlume)

dP/dt = 0.11 atm/min

n = 10 mοl

R = 0.0621 L·atm/(mοl·K)

(dT/dt) = (7.0 atm * (-0.17 L/min) + 12 L * 0.11 atm/min) / (10 mοl * 0.0621 L·atm/(mοl·K))

Calculating the rate οf change οf temperature:

(dT/dt) ≈ -0.4223 K/min

Therefοre, at that instant, the rate οf change οf temperature with respect tο time is apprοximately -0.4223 K/min.

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The Frequency of the resultant pendulum will also be 2 Hz as f does not depend on mass.

The Oscillation frequency of a pendulum depends on 3 things

1. Lenght of string (L).

2. Gravitational pull which is constant for a  planet for earth it 9.8 m/s2.

3. Pie (π)  (Which is again Constant 3.14....)

And this case both the things, length, and g(Gravitational pull) are constant so the frequency will also be the same.

As T = 2π√(L/g) ........ T (Time)

And Frequency  = 1/T so it only required the length of string on which the mass is suspended so it will be constant as the length is taken as same as before.

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The correct answer is A: Bulb 4 is much dimmer and is only barely lit (or not lit at all).

When the switch is open, the circuit containing lightbulbs 1, 2, and 3 is a series circuit, while lightbulb 4 is not part of the circuit due to the open switch. Therefore, the potential difference across bulbs 1, 2, and 3 will be equal, and there will be no potential difference across bulb 4. The correct ranking is: AV1 = AV2 = AV3 > AV4, which corresponds to option B.  After the switch has been closed for a long time, the capacitor C will be fully charged and will act as an open circuit, causing no current to flow through bulb 4. As a result, bulb 4 will not be lit at all.

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The period of the wave is 1.25 seconds.

The period of a wave is the time it takes for one complete cycle to occur. It is the reciprocal of the frequency, meaning that the period (T) is equal to 1 divided by the frequency (f).

Given that the frequency is 0.8 Hz, we can calculate the period as follows:

T = 1 / f

T = 1 / 0.8 Hz

T = 1.25 seconds

Therefore, the period of the wave is 1.25 seconds.

The question is '' What is the period of a wave if the frequency is 0.8 Hz''.

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Six examples in which Physics has been used in daily life include:

Physics plays a major role in transportation, from the design of cars and airplanes to the operation of trains and buses. Physics is also used in communications, from the design of telephone networks to the operation of the internet.

Physics is used to generate energy from various sources, such as fossil fuels, nuclear power, hydroelectric power, and wind power. Physics is used in medical imaging, such as X-rays, CT scans, and MRI.

Physics plays a major role in construction, from the design of buildings and bridges to the materials used in construction.  Physics is also used in entertainment, from the design of amusement park rides to the operation of video games.

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Answer:

What is the frequency of ocean waves that have a speed of 18 m/s and wavelength of 50 m/s?

0.36hz

The frequency of the wave is 0.36 Hz.

Frequency of a wave is defined as the number of oscillations completed by the wave in one second.

Here,

Speed of the wave, v = 18 m/s

Wavelength of the wave, λ = 50 m

We know that, the equation for the speed of a wave is given as,

v = fλ

where f is the frequency of the wave.

Therefore, frequency,

f = v/λ

f = 18/50

f = 0.36 Hz

Hence,

The frequency of the wave is 0.36 Hz.

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Answer:

Explanation:

Given:

R = 18 Ohm

U = 9.0 V

__________

I - ?

Ohm's law:

I = U / R

I = 9.0 / 18 = 0.5 A

The value of log3⁹ is approximately 4.2939. A mathematical function that represents the exponent to which a specified base must be raised to obtain a given number is known as logarithm. We can also say that it is the inverse operation of exponentiation and the logarithm of a number x to a specified base b is denoted as log b(x).

The value of log3⁹ can be found by using the properties of logarithms. Specifically, we'll use the power rule which states that log(a^b) = b * log(a).

The logarithm function can be defined using different bases, but the most

In this case, a = 3 and b = 9, so the expression becomes:

log(3⁹) = 9 * log(3)

The value of log(3) is approximately 0.4771, so the value of log(3⁹) is:

9 * 0.4771 ≈ 4.2939

Therefore, the value of log3⁹ is approximately 4.2939.

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Answer:

In Step 3, he should have multiplied 6.25 J per m2/s2 by 2 instead of dividing it by 2.

Explanation:

D. In Step 3, he should have multiplied 6.25 J per m2/s2 by 2 instead of dividing it by 2.

The energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

According to the question,

The object posses an kinetic energy,

Given Mass of an object = 400 J

Energy moving at a velocity= 8 m/s.

\(E_k =\frac{1}{2} mv^2\\\\=400J = \frac{1}{2} *m(8)^2\\\\\\=\frac{400J}{64m^2/s^2} = \frac{1}{2}*m\\ \\ =6.25 *2 = m\\\\=12.25 kg\)

Hence,

In the step 3 ,he should have multiplied 6.25 J per m²/s² by 2 instead of dividing it by 2.

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Sputnik 1, the first man-made satellite, was released by the Eastern Bloc on October 4, 1957, as part of the Sputnik project, with Sergei Korolev serving as the program's primary designer.

There are a large number of satellite in use. They serve several functions, including the Satellite Navigation System, amateur radio, television transmission, and weather prediction. In order to conduct studies and acquire data, they also employ telescopes to gaze outwards at the solar system.

Natural and artificial satellite are two distinct categories. The Earth and the Moon are two examples of organic satellites. The Moon orbits the earth while the Earth revolves around the Sun.

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The maximum allowable current through the three resistors is approximately 2.47 Amperes.

To determine the maximum allowable current through each resistor, we can use the formula:

I = sqrt(P / R)

where I is the current, P is the power, and R is the resistance.

Given:

r1 = 5 ohms

r2 = 3 ohms

r3 = 6 ohms

p(1n) = 20 watts

p(2n) = 27 watts

p(3n) = 24 watts

For resistor 1 (r1):

I1 = sqrt(p(1n) / r1) = sqrt(20 / 5) = sqrt(4) = 2 Amperes

For resistor 2 (r2):

I2 = sqrt(p(2n) / r2) = sqrt(27 / 3) = sqrt(9) = 3 Amperes

For resistor 3 (r3):

I3 = sqrt(p(3n) / r3) = sqrt(24 / 6) = sqrt(4) = 2 Amperes

Therefore, the maximum allowable current through each resistor is 2 Amperes for r1 and r3, and 3 Amperes for r2.

The maximum allowable current through the resistors is 2 Amperes for r1 and r3, and 3 Amperes for r2 based on the given power and resistance values. It is important to ensure that the actual current through the resistors does not exceed these values to prevent damage to the resistors or the circuit.

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Answer:

B

Explanation:

the lines WILL meet at a point after crossing focal point

Answer:

its d

Explanation:

i searched it up

Using the left hand rule, if current points up and the field is toward you,  the  motion points up.

The left hand rule states that if the thumb, the fore finger and the middle finger are held mutually perpendicular to each other, the thumb points in the direction motion, the middle finger points in the direction of current while the fore finger points in the direction of the magnetic field.

Thus using the left hand rule, if current points up and the field is toward you,  the  motion points up.

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The magnetic field around a current-carrying wire is directly proportional to the current and inversely proportional to the distance from the wire.

The magnetic field strength generated by a current-carrying wire follows the right-hand rule. As the current increases, the magnetic field strength also increases. This relationship is described by Ampere's law.

Additionally, the magnetic field strength decreases as the distance from the wire increases, following an inverse square law. This means that doubling the current will double the magnetic field strength, while doubling the distance from the wire will reduce the field strength to one-fourth of its original value. Therefore, the magnetic field around a current-carrying wire is directly proportional to the current and inversely proportional to the distance from the wire.

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Explanation:

Because they evolved rapidly, and moulted like other arthropods,trilobites serve as excellent index fossils, enabling geologists to date the age of the rock in which they are found

Answer:

11.09 m/s

Explanation:

Given that an object is thrown vertically up and attains an upward velocity of 9.6 m/s when it reaches one fourth of its maximum height above its launch point.

The parameters given are:

Initial velocity U = ?

Final velocity V = 9.6 m/s

Acceleration due to gravity g = 9.8m/s^2

Let first assume that the object is thrown from rest with the velocity U, at maximum height V = 0

Using third equation of motion

V^2 = U^2 - 2gH

0 = U^2 - 2 × 9.8H

U^2 = 19.6H ........ (1)

Using the formula again for one fourth of its maximum height

9.6^2 = U^2 - 2 × 9.8 × H/4

92.16 = U^2 - 19.6/4H

92.16 = U^2 - 4.9H

U^2 = 92.16 + 4.9H ...... (2)

Substitute U^2 in equation (1) into equation (2)

19.6H = 92.16 + 4.9H

Collect the like terms

19.6H - 4.9H = 92.16

14.7H = 92.16

H = 92.16/14.7

H = 6.269

Substitute H into equation 2

U^2 = 92.16 + 4.9( 6.269)

U^2 = 92.16 + 30.72

U^2 = 122.88

U = 11.09 m/s

Therefore, the initial velocity of the object is 11.09 m/s

If the ball isn't travelling as swiftly as the force is pushing itself to keep it moving (in a circular motion), it will fall because gravity and tension pull downward at the top of the swing.

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Answer:

25-0×7×7=25 i think that is it

Answer:

8 g/cm³

Explanation:

density=mass/volume

volume=2*2*2=8 cm³

mass=64 g

density=64/8=8 g/cm³

The density of a 2 cm x 2 cm x 2 cm cube with a mass of 64 g is equal to 8 g/cm³.

Density can be defined as the material mass per unit of volume. The symbol commonly used to represent density ρ and the letter 'D' can also be used.

The mathematical equation of the density can be represented as written below:

Density = Mass /Volume

or,   ρ = m/V

The density of a material varies with pressure and temperature. There is a small variation for solids and liquids of any material but much larger for gases. Increasing the pressure of material decreases the volume and thus increases its density.

Given the volume of the cube =  2 cm x 2 cm x 2 cm

V = 8 cm³

The mass of the cube, m = 64 g

The density of the cube can be calculated from the above-mentioned formula:

Density = Mass of cube/volume

D = 64/8

D = 8 g/cm³

Therefore, the density of the cube is 8 g/cm³.

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Answer:

Recycled answer from jaskhanna07343

Explanation:

Water does not wet waxed surfaces because the cohesive forces within the drops are stronger than the adhesive forces between the drops and the wax. Water wets glass and spreads out on it because the adhesive forces between the liquid and the glass are stronger than the cohesive forces within the water

a) If S is a subspace of vector space V, then the span of S, (S), is equal to S itself.

To show that if S⊆V, then (S) = S, we need to prove two inclusions:(i) (S) ⊆ S:
By definition, (S) is the smallest subspace of V that contains S. Since S⊆(S), it follows that every element in S is also in (S). Therefore, S is a subset of (S).(ii) S ⊆ (S):
Let's consider S as a subspace of V. Since S is already a subspace, it satisfies all the properties of a vector space, including closure under scalar multiplication and addition. Therefore, S is a subset of itself.
Combining both inclusions, we conclude that (S) = S.

b)The span of the union of subspaces W₁ and W₂, (W₁ ∪ W₂), is equal to the sum of W₁ and W₂, denoted by W₁ + W₂.

To show that (W₁ ∪ W₂) = W₁ + W₂, we need to prove two inclusions:
(i) (W₁ ∪ W₂) ⊆ W₁ + W₂:
Let's take an element x from (W₁ ∪ W₂). This means that x is an element of either W₁ or W₂ (or both). If x∈W₁, then x is in the subspace W₁, and therefore, it is also in the sum W₁ + W₂. Similarly, if x∈W₂, then x is in the subspace W₂, and hence it is also in the sum W₁ + W₂. Therefore, any element x from (W₁ ∪ W₂) is also in W₁ + W₂, which implies (W₁ ∪ W₂) ⊆ W₁ + W₂.
(ii) W₁ + W₂ ⊆ (W₁ ∪ W₂):
Let's take an element y from W₁ + W₂. By definition, this means that y can be expressed as the sum of an element in W₁ and an element in W₂. Therefore, y is either an element of W₁ or an element of W₂ (or both), and hence y is in the union (W₁ ∪ W₂). Therefore, any element y from W₁ + W₂ is also in (W₁ ∪ W₂), which implies W₁ + W₂ ⊆ (W₁ ∪ W₂).Combining both inclusions, we conclude that (W₁ ∪ W₂) = W₁ + W₂.

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Although diagnosed with autism and hardly able to speak coherently, 18-year-old Andrew can produce intricate and detailed drawings of scenes he has viewed only once. Andrew illustrates a condition known as savant syndrome.

Savant syndrome is a rare condition in which individuals with developmental or intellectual disabilities display extraordinary abilities in specific areas, such as music, art, math, or memory. In the context of physics, savant syndrome may manifest as an exceptional talent for solving complex equations or understanding abstract concepts that would typically be difficult for someone with their level of cognitive ability.

It is not entirely clear how savant syndrome develops or why some individuals possess these exceptional abilities. Some researchers suggest that the condition may be related to the way in which the brain processes information, while others believe it may be due to a combination of genetic and environmental factors. Regardless of its underlying causes, savant syndrome remains an intriguing area of study for researchers seeking to better understand the potential of the human brain.

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The 3 Ways to cooping with work related stress is to adopt healthy habits, seek social support, and engage in activities that promote relaxation.

The following are three ways to cope with work-related stress:

Exercise- Exercise is a simple yet effective way to reduce stress. When you exercise, your body releases endorphins that are natural mood boosters. Exercise helps to reduce the level of cortisol, which is a stress hormone. The best exercises to do when stressed include yoga, aerobics, walking, jogging, cycling, or dancing.

Engage in relaxation activities-  Engaging in relaxation activities such as meditation, deep breathing, or progressive muscle relaxation helps to relax your mind and body. Deep breathing helps to reduce muscle tension, lower blood pressure and reduce the level of cortisol in the body. Progressive muscle relaxation involves tensing and relaxing muscle groups in the body, one at a time. This technique helps to reduce muscle tension and improve relaxation.

Social support- Social support from family, friends, or colleagues can be a great way to cope with work-related stress. Talking to someone about your problems can help you to gain a different perspective on your situation and feel less isolated. Talking to a colleague can also help to create a supportive work environment. It is essential to identify a trusted confidant who can listen and provide support when you are feeling overwhelmed.

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We have that the  speed of a body covering a distance of 320 km in 4h is mathematically given as

V=22.22m/s is

From the question we are told

calculate the speed of a body covering a distance of 320 km in 4h

Generally the equation for the  Speed  is mathematically given as

\(V=\frac{distance }{time}\\\\Therefore\\\\V=\frac{320*1000}{4*60*60}\\\\\)

V=22.22m/s

Hence

The  speed of a body covering a distance of 320 km in 4h is

V=22.22m/s

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As the mass moves back towards its equilibrium point, its speed is zero.

The motion of the mass attached to the spring can be described using the equation of motion:

\(m(d^2x/dt^2) = -kx\)

where x is the displacement of the mass from its equilibrium position, t is time, m is the mass of the object, and k is the spring constant.

We can solve this differential equation to obtain the displacement x as a function of time:

x(t) = A cos(wt) + B sin(wt)

where A and B are constants that depend on the initial conditions of the system, and w is the angular frequency of the oscillation:

w = sqrt(k/m)

To find the speed of the mass when it returns to the equilibrium position, we need to find the velocity v at that point. The velocity is the derivative of the displacement with respect to time:

v(t) = -Aw sin(wt) + Bw cos(wt)

At the equilibrium position, the displacement x is zero, so we have:

x(0) = A = d

v(0) = Bw = 0

Therefore, the displacement of the mass from its equilibrium position is:

x(t) = d cos(wt)

And the velocity of the mass at the equilibrium position is:

v(0) = -dw sin(0) + 0 = 0

v = 0.

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Answer:

true

Explanation:

based on a scientist's research it is proven true because they travel the exosphere and they give information to the weather people and is used for the latest technology. :>