The volume of the rain barrel is approximately 10,256.58 cubic inches.
To get the volume of the rain barrel, which is shaped like a right circular cylinder, you need to use the formula for the volume of a cylinder: V = πr²h. Here, V represents the volume, r is the radius, and h is the height of the cylinder.
The given diameter of the rain barrel is 22 inches. To find the radius (r), you need to divide the diameter by 2:
r = 22 / 2 = 11 inches.
The height (h) of the rain barrel is given as 27 inches.
Now, you can plug these values into the formula and use 3.14 for pi (π):
V = πr²h
V = 3.14 * (11²) * 27
V = 3.14 * (121) * 27
V = 3.14 * 3267
V ≈ 10,256.58 cubic inches
So, the volume of the rain barrel is approximately 10,256.58 cubic inches.
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The figure below is an isosceles trapezoid. Solve for x.
Note: the figure may not be drawn to scale.
Answer:
x = 3
Step-by-step explanation:
The diagonals of an isosceles trapezoid are congruent , then
4x - 1 + 4 = 2x + x + 6 , that is
4x + 3 = 3x + 6 ( subtract 3x from both sides )
x + 3 = 6 ( subtract 3 from both sides )
x = 3
please help me !!!!!
Answer:
Cheer up...٩(●˙—˙●)۶٩(●˙—˙●)۶٩(●˙—˙●)۶
Step-by-step explanation:
Hahahah
Answer:
:
To find the new function all you have to do is apply the operation in the order that is specified. In this case, subtract the two functions:
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Answer link
value of x 60+(x+20+3x=180
Answer:
60+(x+20+3x)=180
60+(4x+20)=180
4x=180-20-60
4x=180-80
4x=100
x=100/4
x=25
How do I covert yard into feet with fractions?
Answer: x/3
Step-by-step explanation:
Say "x" is the number of yards you are given.
remember that one yard = 3 feet.
in order to convert x amount of yards into feet, you must divide x by three.
giving you= x/3
define a fruitful function to calculate the area of a triangle. the formula is:area of triangle = base * height /2
A function to define the area of the triangle is A(b,h) = (1/2)*b*h
A function is a process or a relation that associates each element 'a' of a non-empty set A , at least to a single element 'b' of another non-empty set B. A relation f from a set A (the domain of the function) to another set B (the co-domain of the function) is called a function in math. f = {(a,b)| for all a ∈ A, b ∈ B}.
1) A relation is said to be a function if every element of set A has one and only one image in set B.
2) A function is a relation from a non-empty set B such that the domain of a function is A and no two distinct ordered pairs in f have the same first element.
A function from A → B and (a,b) ∈ f, then f(a) = b, where 'b' is the image of 'a' under 'f' and 'a' is the preimage of 'b' under 'f'.
If there exists a function f: A → B, the set A is called the domain of the function f, and the set B is called its co-domain.
Let us assume that the base of the triangle is b and the height of the triangle is h.
So, a function to define the area of the triangle is
A(b,h) = (1/2)*b*h
This function is a function in two variables.
Thus, a function to define the area of the triangle is A(b,h) = (1/2)*b*h
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The
square below is the image of a square that was dilated by a scale factor of 1. Find
the area of the preimage, the original square, before its dilation. Figures are not
necessarily drawn to scale.
11
Answer:
I'm not really sure what you're asking because there's no image.
Step-by-step explanation:
please try to reword it and maybe show a picture .
solve the equation 4x^3 + 32x^2 + 42x - 16 = 0, given that one root is equal to the sum of the other two roots
The solutions to the equation are x = -1, x = -8, and x = 1/2.
How to calculate the valueThe equation 4x³ + 32x² + 42x - 16 = 0 can be divided throuh by 2 as follows:
2x³ + 16x² + 21x - 8 = 0
We can test each of these possible roots by substituting them into the equation and seeing if we get 0. When we substitute -1, we get 0, so -1 is a root of the equation. We can then factor out (x + 1) from the equation to get:
(x + 1)(2x² + 15x - 8) = 0
We can then factor the quadratic 2x² + 15x - 8 by grouping to get:
(x + 8)(2x - 1) = 0
This gives us two more roots, x = -8 and x = 1/2.
Therefore, the solutions to the equation are x = -1, x = -8, and x = 1/2.
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On a coordinate plane, a point is 7 units up on the y-axis. Which of the statements are true? On a coordinate plane, a point is 7 units up on the y-axis.
Which of the statements are true? Select all that apply.
The point is located at (7, 0).
The point is located at (0, 7).
The point is on the y-axis.
The point is on the x-axis.
The point is at the origin.
Answer:
The second one
The third one
Step-by-step explanation:
Answer:
the point is located at 7,0. the point is on the y-axis.
Step-by-step explanation:
Draw a line parallel to the line x=5 that intersects the x-axis at (1,0). What is the equation of this line?
So, on solving the provided question, we cans ay that new slope interest equation is y = 3x +c
what is slope intercept?In mathematics, the intersection point is the place on the y-axis where the slope of the line crosses. a place where the y-axis crosses on a line or curve. Y = mx+c, where m stands for the slope and c for the y-intercept, is used as the equation for the straight line to show this. The slope (m) of the line and its y-intercept (b) are emphasised in the equation's intercept form. When an equation has the intercept form (y=mx+b), the slope is m and the y-intercept is b. Some equations can also be rewritten such that they seem to be slope intercepts. If y=x is rewritten as y=1x+0, for instance, the slope and y-intercept are both changed to 1.
given, x = 5, that is lope
coordinates = (1,0)
new slope interest equation is
y = 3x +c
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The correct question is -
Draw a line parallel to the line x=5 that intersects the x-axis at (1,0). What is the equation of this line?
Is y=9-4x linear or nonlinear
Answer:
Linear
Step-by-step explanation:
The degree of the equation is 1.
what operation should be used to solve
the equation 153 = g + 45? solve the equation
THERE ARE NO PICTURES PLZ HELP
Answer:
g=108
Step-by-step explanation:
153 = g + 45
g+45=153
1g+45-45=153-45
1g=108
1g÷1=108÷1
g=108
What is the slope of a line parallel to the graph of 3x−5y=18 ?
Answer:
The slope of the parallel line is 3.
Step-by-step explanation:
A line that is parallel to a refernce line will have the same slope. The refernce line is 3x-y=18. Rewrite it in slope-intercept form [y=mx+b] so that we can find the slope, m.
3x-y=18
-y= - 3x + 18
y = 3x - 18
The slope, m, is 3
A line parallel to this line will also have a slope of 3.
y = 3x+b
Choose any b, and the line will be parallel. I chose 5 for the attached graph. y = 3x+5
2.2 units to the right of 0 horizontal number line
Answer:
2.2
Step-by-step explanation:
2.2 units to the right of zero indicates that the integer is positive on a horizontal number line.
0 + 2.2 = 2.2
A. 11 B. 17 C. 23 D. 29
Answer:
Is it C?
Step-by-step explanation
y = x + 2
5x - 4y = -3
plz show your work
Answer:
(5, 7) or x = 5 and y = 7
Step-by-step explanation:
Since we are given y, we can use the substitution method and substitute x+2 into y since they are equal. With this, you would have 5x - 4(x+2) = -3. You can distribute the -4 into x and 2 to get 5x - 4x - 8 = -3.
We can simplify 5x-4x to get x and get x - 8 = -3. Afterwards we can add 8 to both sides to get x = 5. We can now replug x into the first equation to get y = 5 + 2. Simplified, y = 7.
So the answer would be (5, 7) or x = 5 and y = 7.
Brainliest would be appreciated!
a proof involving triangle ABC is shown below what title best describes the proof
Given data:
The given figure of the triangle.
In the triangle ACD and triangle BCD.
\(\begin{gathered} AC\cong BC(\text{given)} \\ \angle1\cong\angle2 \\ CD\cong CD(Common) \\ \Delta ACD\cong\Delta\text{BCD(side angle side SAS)} \\ \angle A\cong\angle B(CPCT) \end{gathered}\)Thus, option (B) is correct.
An experiment to compare k=4 factor levels has n = 12. n2 = 8. n3 = 13,114 = 11. X1. = 16.09. X2 = 21.55, X3. = 16.72. X4 = 17.57, and SST = 485.53 Please find SSTI Question 13 10 out of 10 points An experiment to compare k=4 factor levels has n = 12. n2 = 8. n3 = 13, 14 = 11. X1. = 16.09. X3. = 21.55. X3 = 16.72 X = 17.57. and SST = 485.53 Please find SSE
The SSE value is 222.19. The formula to calculate the sum of squares error (SSE) is SSE = SST – SSTI where SSTI represents the sum of squares treatment. Here, k = 4, and the degrees of freedom for treatment (dfI) can be calculated using the formula,
dfI = k – 1 Therefore, dfI = 4 – 1
dfI = 3 .Now, the sum of squares treatment (SSTI) can be calculated as SSTI = Σn(X – X¯)2 / dfI
where X¯ represents the grand mean
X¯ = (n1X1 + n2X2 + n3X3 + n4X4) / n where n = n1 + n2 + n3 + n4 = 12
Solving for X¯, we get
X¯ = (12*16.09 + 8*21.55 + 13*16.72 + 11*17.57) / 12X¯ = 17.1888
Therefore, SSTI = (12*(16.09 – 17.1888)2 + 8*(21.55 – 17.1888)2 + 13*(16.72 – 17.1888)2 + 11*(17.57 – 17.1888)2) / 3SSTI = 263.34
Now, substituting the given values in the formula,
SSE = SST – SSTISSE = 485.53 – 263.34SSE = 222.19
Therefore, the SSE value is 222.19.
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1. Suppose X~N(30, 144). That is, X has a normal distribution with ?=30 and ?2=144.
1a. Find a transformation of X that will give it a mean of zero and a variance of one (ie., standardize X).
1b. Find the probability that 18
1c. Supposing Y=10+5X, find the mean of Y.
1d. Find the variance of Y.
X has a normal distribution, X that will give it a mean of zero and a variance , then the mean of Y = E(10+5X) = 1020
The variance is a measure of variability. It is calculated by taking the average of squared deviations from the mean. Variance tells you the degree of spread in your data set. The more spread the data, the larger the variance is in relation to the mean.
Given that,
E(x) = 30
Var(x) = 144
E(y) = ?
Var(y) = 144
Then,
E(10+5X)
To do this, we make use of the following equation
E(ax + by) = a E(x) + b E(y)
E(10+5X) = 10 E(x) + 5 E(y)
E(10+5X) = 10*30 + 5*144
E(10+5X) = 300 + 720
E(10+5X) = 1020
Therefore,
X has a normal distribution, X that will give it a mean of zero and a variance , then the mean of Y = E(10+5X) = 1020
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If the product of two numbers is equal to zero then at least one of the numbers must be zero
1.True
2.False
Answer:
True
Step-by-step explanation:
Answer:
True, because if we multiply any number with zero the product will still be zero.
one fourth of 120 is equal to 10% of what number
Answer:
3
Step-by-step explanation:
vanessa tried to prove that \triangle klm\cong \triangle mnk△klm≅△mnktriangle, k, l, m, \cong, triangle, m, n, k. statement reason 1 \overline{kl}\cong\overline{mn} kl ≅ mn start overline, k, l, end overline, \cong, start overline, m, n, end overline given 2 \overline{lm}\cong\overline{nk} lm ≅ nk start overline, l, m, end overline, \cong, start overline, n, k, end overline given 3 \triangle klm\cong \triangle mnk△klm≅△mnktriangle, k, l, m, \cong, triangle, m, n, k side-side-side congruence what is the first error vanessa made in her proof? choose 1 answer: choose 1 answer:
What is the first error Vanessa made in her proof: B. Vanessa only established some of the necessary conditions for a congruence criterion.
What are the properties of similar triangles?In Mathematics and Geometry, two triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.
Additionally, the lengths of three (3) pairs of corresponding sides or corresponding side lengths are proportional to the lengths of corresponding altitudes when two (2) triangles are similar.
Based on the reflexive property of equality, we can logically deduce the following congruent and similar triangles:
KM ≅ KM
ΔKLM ≅ ΔMNK (SSS similarity theorem).
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
A lawnmower blade has a diameter of 36 inches and spins at a rate of 60 revolutions per minute. What is the linear velocity, in inches per minute, at the end of the blade?.
You can use the circumference of the circle that the blade makes to calculate the linear velocity at the end of the blade.
The linear velocity at the end of the blade is 13571.7 inches per minute
How to find the linear velocity of the lawnmower blade?You can think of it as if some circle is being drawn by the end of the blade and then that circle is like wheel of a bicycle and its travelling on road. Each rotation will make it cover distance equal to its circumference. Since there are 60 revolutions of the blade in each minute, thus, 60 rounds of that wheel.
The total distance in 1 minute = 60 times circumference of the circle made by the end of the blade of the lawnmower.
Since the blade is 36 inches long, it can be taken as radius of that circle.
The circumference is thus calculated as \(2 \times \pi \times 36 = 226.19 \: \rm inches\)
Thus, linear velocity = 226.19 times 60 inches per minute = 13571.7 inches per minute
Thus,
The linear velocity at the end of the blade is 13571.7 inches per minute
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Answer:
i think its D or 4,320pi
Step-by-step explanation:
just divided the previous persons answer by pi and its d on edge 2022.
on monday, cody bought 41 4141 cherries. on tuesday, cody ate 19 1919 cherries. now, she wants to divide the remaining cherries into bags of 4 44 cherries each. estimate how many bags of 4 44 cherries cody can make.
we're estimating, we can round down to the nearest whole number to get an answer of 50. This means Cody can make approximately 50 bags of 4 44 cherries with the cherries she has left.
To estimate the number of bags of 4 44 cherries that Cody can make, we first need to calculate how many cherries she has left after eating 19 1919 cherries on Tuesday.
The number of cherries left will be:
41 4141 - 19 1919 = 22 2222 cherries.
Now, to estimate the number of bags of 4 44 cherries Cody can make, we divide the remaining cherries by 4 44 cherries per bag:
22 2222 ÷ 4 44 ≈ 50.225
Since we're estimating, we can round down to the nearest whole number to get an answer of 50. This means Cody can make approximately 50 bags of 4 44 cherries with the cherries she has left.
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find area of figuresend pic
The total area will be the area of the semi circle, plus the area of the rectangle, so:
Area of the semicircle:
\(\begin{gathered} A_c=\frac{\pi(r^2)}{2} \\ A_c=\frac{\pi(56.25)}{2} \\ A_c=\frac{225}{8}\pi \end{gathered}\)The area of the rectangle is:
\(\begin{gathered} Ar=w\cdot l \\ Ar=7\cdot15=105 \end{gathered}\)The total area is:
\(T_A=Ac+Ar=193.4\)Section 2 - Determining Validity of Propositional Arguments ( 50 points) For the following arguments, (a) provide the argument in propositional form. Be sure to indicate which letters represent which propositions. (b) Provide a truth table for the argument: (c) State whether the argument is valid or invalid. 1. If X is an even number, then X is divisible by 2. But X is not divisible by 2 . Thus, X is not an even number. 2. Eddie can vote if and only if he is registered. But Eddie is not registered. Therefore, Eddie cannot vote.
Argument 1:
(a) The argument in propositional form can be expressed as:
P → Q
¬Q
Therefore, ¬P.
(b) In this case, we can observe that in all rows where P → Q is true (rows 1, 3, and 4), the conclusion ¬P is also true.
(c) The argument is valid.
Argument 2:
(a) The argument can be expressed as:
P ↔ Q
¬Q
Therefore, ¬P.
(b) In this case, we can observe that in all rows where P ↔ Q is true (rows 1 and 4), the conclusion ¬P is also true.
(c) The argument is valid.
Argument 1:
(a) Argument in propositional form:
Let P represent "X is an even number."
Let Q represent "X is divisible by 2."
The argument can be expressed as:
P → Q
¬Q
Therefore, ¬P.
(b) Truth table for the argument:
P Q P → Q ¬Q Conclusion: ¬P
True True True False False
True False False True False
False True True False True
False False True True True
(c) The argument is valid.
To determine the validity of the argument, we look for rows in the truth table where all the premises are true and the conclusion is also true. If the conclusion holds true in all cases where the premises are true, then the argument is valid.
In this case, we can observe that in all rows where P → Q is true (rows 1, 3, and 4), the conclusion ¬P is also true. Therefore, the argument is valid.
Argument 2:
(a) Argument in propositional form:
Let P represent "Eddie can vote."
Let Q represent "Eddie is registered."
The argument can be expressed as:
P ↔ Q
¬Q
Therefore, ¬P.
(b) Truth table for the argument:
P Q P ↔ Q ¬Q Conclusion: ¬P
True True True False False
True False False True False
False True False False True
False False True True True
(c) The argument is valid.
To determine the validity of the argument, we look for rows in the truth table where all the premises are true and the conclusion is also true. If the conclusion holds true in all cases where the premises are true, then the argument is valid.
In this case, we can observe that in all rows where P ↔ Q is true (rows 1 and 4), the conclusion ¬P is also true. Therefore, the argument is valid.
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Write the ratio in simplest form.
28 elementary schools to 10 middle schools.
Answer:14/5
Step-by-step explanation:28/10
Divide through by 2
min
x1+2x2
s.t. X1 + X2 ≤ 4
x1 - X2≥ 5
X1, X2 ≥ 0
For the LP problem above, which of the following statement is true?
A• The LP has a unique optimal solution.
B• The LP has multiple optimal solutions.
C• The LP has no feasible solution.
D• The LP is unbounded.
The correct option is B• "The LP has multiple optimal solutions". Because feasible region, intersects with the objective function in multiple points.
The given linear programming (LP) problem consists of two constraints and two decision variables, x1 and x2. The objective function to be minimized is x1 + 2x2.
To determine the nature of the LP problem, we need to analyze its feasible region and objective function.
The first constraint, x1 + x2 ≤ 4, defines a region in the xy-plane that lies below the line x1 + x2 = 4. The second constraint, x1 - x2 ≥ 5, defines a region that lies to the right of the line x1 - x2 = 5. The feasible region is the intersection of these two regions.
By analyzing the feasible region, we can determine the potential optimal solutions. Since the feasible region is a bounded region, there are finite points within it. The objective function, x1 + 2x2, represents a straight line in the xy-plane with a positive slope. As long as this line intersects the feasible region, there will be multiple points of intersection, each representing a potential optimal solution.
Therefore, the LP problem has multiple optimal solutions because there are multiple points of intersection between the objective function and the feasible region.
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How do you prove f is one to one?
To prove that f is one-to-one function, it must be proven that f(x1)=f(x2) and x1=x2.
What is a one to one function?
The mapping of two sets is essentially what a one to one function refers to. When every element in a function's range and domain match exactly one another, the function is said to be one-to-one.
The one-to-one function, also known as an injective function, is one of the many different types of functions.
A function that transfers different components of its domain to different elements of its codomain is known as a one-to-one function.
For example, a function f:A→B is said to be one-to-one if -
f(x1)=f(x2)⇒x1=x2
for all elements x1,x2∈A.
To prove f:A→B is one-to-one -
Consider the fact that f(x1)=f(x2).
Then it must be true that x1=x2.
Therefore, it is now understood that f is one-to-one by definition if f(x1)=f(x2) and x1=x2.
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108° 4x+8° O alternate interior corresponding vertical linear pair same-side Interior alternate exterior degrees
Alternate Interior angles
x = 25
Explanations:By careful observation of the diagram, we would see that both angles are at the opposite sides of the transversal. At the same time, they are at the interior of the two parallel lines.
This means that <108 and <4x + 8 are alternate interior angles.
Since the two lines intersecting the transversal are parallel, the alternate interior angles are equal
That is,
4x + 8 = 108
4x = 108 - 8
4x = 100
x = 100/4
x = 25
Assistance woukd be much apreaciated, match determine the single unit (ex; find out if t=4), then find the equation used to solve it.
Step-by-step explanation:
1.
use equation 1
vf = vi + a×t = 5.2 + 2.3×7 = 21.3 m/s
deltax (displacement) not needed
vi = 5.2 m/s
vf = 21.3 m/s
a = 2.3 m/s²
t = 7 s
2.
use equation 4.
vf² = vi² + 2×a×deltax
47² = vi² + 2×4.7×150
2209 = vi² + 1410
vi² = 799
vi = 28.26658805... m/s
deltax = 150 m
vi = 28.26658805... m/s
vf = 47 m/s
a = 4.7 m/s²
t not needed
3.
use equation 2.
deltax = (vf + vi)×t/2
228 = (3.15 + 3.15)×t/2
456 = 6.3×t
t = 456/6.3 = 72.38095238... s
deltax = 228 m
vf = 3.15 m/s
vi = 3.15 m/s
a not needed
t = 72.38095238... s
4.
use equation 5.
deltax = vf×t - 1/2 × a×t²
897 = 0×15.5 - 1/2 × a×15.5² = -1/2 ×a×240.25 = a×-120.125
a = 897/-120.125 = -7.467221644... m/s²
deltax = 897 m
vi not needed
vf = 0 m/s
a = -7.467221644... m/s²
t = 15.5 s
Gazelle vs. Lion.
use equation 2.
deltax = (vf + vi)×t/2
deltax = (18.4 + 0)×3.09/2 = 18.4×3.09/2 =
= 9.2×3.09 = 28.428 m
deltax = 28.428 m
vi = 0 m/s
vf = 18.4 m/s
a not needed
t = 3.09 s