Mike has some candies. he gave some to his friend. then, his mom gave him twice as much as he had in the beginning. how much did he have in the beginning if he has a total of 60 candies now?

Hey There!

Answer

You're Answer Is B Why?

Because The Expression I Hope This Helps You On your'e Quiz :) Have A Nice day/night/evening/afternoon/ :)

Sue Smith can calculate confidence limits for sampling error by using a confidence interval. a confidence interval is a range of values that is likely to contain the true population parameter.

The confidence interval is calculated from the sample data and the confidence level. The confidence level is the probability that the true population parameter is within the confidence interval.

For example, if Sue Smith wants to calculate a 95% confidence interval for the mean age of homemakers in the midwestern United States,

she would need to collect a sample of homemakers and calculate the sample mean. She would then use the sample mean and the confidence level to calculate the confidence interval.

The confidence interval would be a range of values that is likely to contain the true mean age of homemakers in the midwestern United States. For example, the confidence interval might be 35 to 45 years old.

This means that there is a 95% probability that the true mean age of homemakers in the midwestern United States is between 35 and 45 years old.

Sue Smith can use the confidence interval to calculate the sampling error. The sampling error is the difference between the sample mean and the true population mean.

The sampling error can be calculated by subtracting the sample mean from the confidence interval. For example, if the confidence interval is 35 to 45 years old and the sample mean is 40 years old, the sampling error is 5 years.

The sampling error is important because it tells Sue Smith how accurate her estimate of the true population mean is. The smaller the sampling error, the more accurate the estimate.

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Answer:

\(\dfrac{2x-1}{(x+1)(x-1)^2} \equiv -\dfrac{3}{4(x+1)}+\dfrac{3}{4(x-1)}+\dfrac{1}{2(x-1)^2}\\\\\)

Step-by-step explanation:

When writing an algebraic fraction as an identity, if its denominator has repeated linear factors, the power of the repeated factor indicates how many times that factor should appear in the partial fractions.  A factor that is squared in the original denominator will appear in the denominator of two partial fractions - once squared and once without the square.

Write out the fraction as an identity:

\(\begin{aligned}\dfrac{2x-1}{(x+1)(x-1)^2} & \equiv \dfrac{A}{(x+1)}+\dfrac{B}{(x-1)}+\dfrac{C}{(x-1)^2}\\\\\implies \dfrac{2x-1}{(x+1)(x-1)^2} & \equiv \dfrac{A(x-1)^2}{(x+1)(x-1)^2}+\dfrac{B(x+1)(x-1)}{(x+1)(x-1)^2}+\dfrac{C(x+1)}{(x+1)(x-1)^2}\\\\\implies 2x-1 & \equiv A(x-1)^2+B(x+1)(x-1)+C(x+1)\end{aligned}\)

Calculate the values of A and C using substitution:

\(\begin{aligned}\textsf{when }x=1 \implies 1 & =A(0)+B(0)+C(2)\implies C=\dfrac{1}{2}\\\\\textsf{when }x=-1 \implies -3& =A(4)+B(0)+C(0)\implies A=-\dfrac{3}{4}\\\\\implies 2x-1 & =-\dfrac{3}{4}(x-1)^2+B(x+1)(x-1)+\dfrac{1}{2}(x+1)\\\\2x-1 & =-\dfrac{3}{4}(x^2-2x+1)+B(x^2-1)+\dfrac{1}{2}(x+1)\\\\2x-1& = \left(B-\dfrac{3}{4}\right)x^2+2x-\left(B+\dfrac{1}{4}\right)\end{aligned}\)

Compare constants to find B:

\(\begin{aligned}\implies -1 & = -\left(B+\dfrac{1}{4}\right)\\\\\implies B & = \dfrac{3}{4}\end{aligned}\)

Replace the found values of A, B and C in the original identity:

\(\implies \dfrac{2x-1}{(x+1)(x-1)^2} \equiv -\dfrac{3}{4(x+1)}+\dfrac{3}{4(x-1)}+\dfrac{1}{2(x-1)^2}\\\\\)

I think its like if you got 80% on a quiz and 20% on the exam then your grade would be 60% which is usually a F

The surface area of the pencil is 835π sq. mm. (option a).

Let's start with the cylinder. The formula to find the surface area of a cylinder is 2πr² + 2πrh, where r is the radius of the circular base, h is the height, and π is pi, which is approximately 3.14. We are given that the diameter of the cylindrical base of the pencil is 10 mm, which means that the radius is 5 mm. We are also given that the height of the cylinder is 70 mm. Plugging these values into the formula, we get:

Surface area of cylinder = 2π(5)² + 2π(5)(70)

= 2π(25) + 2π(350)

= 50π + 700π

= 750π sq. mm.

We can use the Pythagorean theorem, which is a² + b² = c², where a and b are the legs of the triangle and c is the hypotenuse, to solve for the slant height. We have:

(5)² + (12)² = c²

25 + 144 = c²

169 = c²

c = √169

c = 13

Therefore, the slant height of the cone is 13 mm. Now, we can use the formula to find the surface area of the cone:

Surface area of cone = π(5)² + π(5)(13)

= 25π + 65π

= 90π sq. mm.

Finally, we can add the surface area of the cylinder and the cone together to find the total surface area of the pencil:

Total surface area = Surface area of cylinder + Surface area of cone

= 750π + 90π

= 840π sq. mm.

Therefore, the correct answer is option a) 835π sq. mm.

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Complete Question:

A pencil consists of a cone stacked on top of a cylinder. The diameter of the cylindrical base of the pencil is 10 mm and the height of the cylinder is 70 mm, while the height of the cone is 12 mm. Calculate the surface area of the pencil. Leave your answer in terms of π.

a) 835π sq. mm.

b) 790π sq. mm.

c) 785π sq. mm.

d) 1820π sq. mm.

Answer:

\(2.28*10^7\)

Step-by-step explanation:

\((2.4*10^3)(9.5*10^3)=(2.4*9.5)(10^3*10^3)=22.8*10^6=2.28*10^7\)

Answer:

228,000

Step-by-step explanation:

(2.4x10^3) x (9.5x10^3)

(2.4x100) x (9.5x100)

240x950

228,000

Answer:

This is what I got

Step-by-step explanation:

To solve the problem we must know about the formula of the length of the Arc.

\(\rm{ Length\ of\ Arc = \dfrac{2\pi r \theta}{360^o}\)

The angle made by the arc in the center is 2.7 radians.

Given to us

Let the angle be θ.

Substituting the values in the formula of Length of Arc,

\(\rm{ Length\ of\ Arc = \dfrac{2\pi r \theta}{360^o}\\\\ \)

\(8\ in. = \dfrac{2\pi \times 3 \times \theta}{360^o}\)

\(\theta = \dfrac{360^o\times 8\ in.}{2\pi \times 3 }\\\\ \theta = 152.788^o \approx 152.79^o\)

\(\theta = 152.79^o\\\\ \)

   \(=\dfrac{\theta \times \pi}{180^o}\)

   \(\rm{=2.6666667 \approx 2.7\ radians\)

Hence, the angle made by the arc in the center is 2.7 radians.

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Answer:

9 is the largest number of baskets they can make and still have enough muffins.

Step-by-step explanation:

If they want to use all three types of muffins for the basket, they’d have to find the GCF (greatest common factor) of 30, 54, and 27, which is 9. They’d still have a lot left over... but if they want to put all three types of muffins then they can only make 9 full baskets.

Hope this helped :)

Answer:

first question: 24/40

second question: 36/5

Answer:

3. 24/5
4. 36/5

Step-by-step explanation:

For number 3, we can find the answer by multiplying 3/5 by 8, because the rabbits ate 3/5 of the celery in each garden. That's 3/5 eight times.

3/5 · 8/1 = 24/5

For number 4, we apply the rules of multiplication and solve A whole number can turn into a fraction by adding one as the denominator. Next, simply multiply the numerators by the denominators.

12/1 · 3/5 = 36/5

hope this helps!

Answer:

A

Step-by-step explanation:

Simplfy each

A.0.2

B.0.75

C.0.4

D.4.44444444

A is the closest to 0

Answer:

-32c + 36

Step-by-step explanation:

10-6(-8c+9)

4(-8c+9)

4 × -8c = -32c

4 × 9 = 36

-32c + 36

There are two ways, factoring or using the quadratic formula.

To factor, split the linear coefficient into m+n as follows:

m + n = -54 ; mn = (9)(-19) = -171

We can see that m = 3, n = -57.

9x2 – 54x – 19 = 0

9x2 + 3x - 57x - 19 = 0

3x(3x + 1) - 19(3x + 1) = 0

(3x - 19)(3x + 1) = 0

x = 19/3 or x = -1/3.

Or if you want to use the quadratic formula, x = [-b±√(b2 - 4ac)]/(2a), then:

x = [54 ± √((-54)2 - 4(9)(-19))]/[2(9)]

= [54 ± √(2916 + 684)]/18

= (54 ± √3600)/18

= (54 ± 60)/18

=  (9 ± 10)/3

= 19/3 or -1/3

\(x = 6 \frac{1}{3} \)

Step-by-step explanation:

the easy ways,you just use the calculator for solve your problem,hehe

Answer:

264 inches

Step-by-step explanation:

Let's start with the top cube.

We can figure out the volume by multiplying the length, width, and height. So for this problem, it will be 4x5x6. 4x5 is obviously 20, and 6x20 is 120. So the top cube is 120 in.

The bottom cube has the dimensions 4x6x6. I know 6x6 is 36. So 36x4 is 144.

So 120+144=264

Let me know if you have any questions!

when two ads two the result will be 4 like this

2+2=4

The type of Balance Sheet Report showing information for today and a year ago is typically a C. Comparison.

A comparison balance sheet report compares the financial position of a company at two different points in time.

In this case, the current day and a year ago.

It presents the assets, liabilities, and equity of the company side by side, allowing for a comparison and analysis of the changes.

That have occurred over the specified period.

The other options mentioned are,

Balance Sheet A,

This is not a recognized classification for balance sheet reports.

Summary,

A summary balance sheet report provides a condensed overview of the financial position.

Usually presenting summarized categories of assets, liabilities, and equity.

It may not include specific details or comparisons with previous periods.

Detailed,

A detailed balance sheet report provides a comprehensive breakdown of all individual accounts.

Assets, liabilities, and equity, offering a more granular view of the financial position.

It may not necessarily include a comparison with a previous period.

Therefore, in the context of comparing the financial position for today and a year ago, the most suitable type of balance sheet report would be a C. Comparison.

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The given statement "The diagonal of a parallelogram does not create alternate interior angles" is false because alternate interior angles are formed when two parallel lines are intersected by a transversal, and they are located on opposite sides of the transversal and between the two parallel lines.

In a parallelogram, the opposite angles are congruent, meaning they have equal measures. When a diagonal is drawn in a parallelogram, it creates two pairs of congruent opposite angles, but these angles are not considered alternate interior angles.

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The number of bicycles they need to sell to make equal money is 5. The amount they would make is $500.

In contrast to variable costs, which change depending on the volume of production or sales, fixed costs are expenses that remain constant. Rent, insurance, and salary are examples of fixed costs that are constant regardless of the volume of output or sales. Materials, labour, and shipping expenses are examples of variable costs that change according to the volume of output or sales.

Let us suppose the number of bicycle sold = x.

Then the equation for Jimmy is:

$250 + 50x

The equation for Tom is:

$400 + 20x

To make the same amount we equate the two equations as follows:

250 + 50x = 400 + 20x

30x = 150

x = 5

Substituting the value of x in equation 1 we have:

J = 250 + 50(5)

J = 250 + 250

J = 500

Hence, the number of bicycles they need to sell to make equal money is 5. The amount they would make is $500.

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Answer:

(x+a)(x+b)= x²+(a+b)x+ab

This is an identity of mathematics! not an equation.

Answer:

x²+(a+b)x+ab

Step-by-step explanation:

(x+a) (x+b) = (x)²+(a+b)x+(a)(b) = x²+(a+b)x+ab

Answer:

angle PSQ=25°

Step-by-step explanation:

angle RQS=angle PSQ.......... alternate angle

so angle PSQ=25°

Answer:

25 degrees

Step-by-step explanation:

If it is a parallelogram, then the sides PS and QR will be parallel, then ∠PSQ and ∠RQS are alternate interior angles, and hence they will be congruent. That is, ∠PSQ ≅ ∠RQS = 25°.

But this is not the confirmation that this would be parallelogram as it could be trapezoid. The given condition is must but not sufficient to prove it.

Hope this helps. Do mark me as BRAINLY. thanks

A significance level of 0.10, we have enough evidence to conclude that the new copy machines have a significantly faster mean repair time compared to the older model.

To test if the new copy machines are faster to repair, we can set up the following null and alternative hypotheses:

Null Hypothesis (H₀): The mean repair time for the new copy machines is the same as the mean repair time for the older model.

Alternative Hypothesis (H₁): The mean repair time for the new copy machines is less than the mean repair time for the older model.

Let's perform a one-sample t-test to test these hypotheses. The test statistic is calculated as:

t = (sample mean - population mean) / (sample standard deviation / √(sample size))

Given:

Population mean (μ) = 93 minutes

Sample mean (\(\bar x\)) = 86.8 minutes

Sample standard deviation (s) = 14.6 minutes

Sample size (n) = 18

Significance level (α) = 0.10

Calculating the test statistic:

t = (86.8 - 93) / (14.6 / sqrt(18))

t = -6.2 / (14.6 / 4.24264)

t ≈ -2.677

The degrees of freedom for this test is n - 1 = 18 - 1 = 17.

Now, we need to determine the critical value for the t-distribution with 17 degrees of freedom and a one-tailed test at a significance level of 0.10. Consulting a t-table or using statistical software, the critical value is approximately -1.333.

Since the test statistic (t = -2.677) is less than the critical value (-1.333), we reject the null hypothesis.

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Answer:

What's the exercise

Step-by-step explanation:

You didn't post anything please re-submit so I can help you

The expressions √1.5 and √1.9 are radical expressions

The true inequality about √1.5 and √1.9 is √1.5 < √1.9

The numbers are given as:

√1.5 and √1.9

Evaluate both root expressions

√1.5 = 1.22

√1.9 = 1.38

By comparison, we have:

1.22 <1.38

Rewrite as:

√1.5 < √1.9

Hence, the true inequality about √1.5 and √1.9 is √1.5 < √1.9

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The given statement "context switching is required by all preemptive algorithms " is False.

Context switching is not required by all preemptive algorithms. Preemptive algorithms allow the operating system to interrupt the currently executing process and switch to another process.

Context switching involves saving the state of the currently running process and restoring the state of the next process to be executed. While context switching is a common mechanism in preemptive scheduling algorithms, there are non-preemptive algorithms that do not require context switching as they allow processes to run until they voluntarily release the CPU.

So, the statement that context switching is required by all preemptive algorithms is false.

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Answer:

whats the question

Step-by-step explanation:

Answer:

y = x + 5

Step-by-step explanation:

x - y = - 5

-y = -x - 5

-(-y = - x - 5)

y = x + 5

We can conclude that there are no nontrivial clean pulsations for the given left-mounted beam with a simple support on the right.

To find the equation of clean pulsations for a left-mounted beam with a simple support on the right, we can use the differential equation that describes the deflection of the beam. Assuming the beam is subject to a distributed load and has certain boundary conditions, the equation governing the deflection can be written as:

d^2y/dx^2 + (chx)^2 * y = 0

Where:

y(x) is the deflection of the beam at position x,

d^2y/dx^2 is the second derivative of y with respect to x,

ch(x) is the hyperbolic cosine function.

To solve this differential equation, we can assume a solution in the form of y(x) = A * cosh(kx) + B * sinh(kx), where A and B are constants, and k is a constant to be determined.

Substituting this assumed solution into the differential equation, we get:

k^2 * (A * cosh(kx) + B * sinh(kx)) + (chx)^2 * (A * cosh(kx) + B * sinh(kx)) = 0

Simplifying the equation and applying the given identity (chx)^2 - (shx)^2 = 1, we have:

(A + A * chx^2) * cosh(kx) + (B + B * chx^2) * sinh(kx) = 0

For this equation to hold for all values of x, the coefficients of cosh(kx) and sinh(kx) must be zero. Therefore, we get the following equations:

A + A * chx^2 = 0

B + B * chx^2 = 0

Simplifying these equations, we have:

A * (1 + chx^2) = 0

B * (1 + chx^2) = 0

Since we are looking for nontrivial solutions (A and B not equal to zero), the expressions in parentheses must be zero:

1 + chx^2 = 0

Using the identity (sinx)^2 + (cosx)^2 = 1, we can rewrite this equation as:

1 + (1 - (sinx)^2) = 0

Simplifying further, we get:

2 - (sinx)^2 = 0

Solving for (sinx)^2, we find:

(sin x)^2 = 2

Since the square of the sine function cannot be negative, there are no real solutions to this equation. Therefore, we can conclude that there are no nontrivial clean pulsations for the given left-mounted beam with a simple support on the right.

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(a) Use six rectangles to find estimates of each type for the area under the given graph of f from \(x = 0 to x = 36\):In the following, there are 6 rectangles under the curve f. For each of the three cases, we'll calculate the area under f using the indicated sampling points and divide it by 6.

The left endpoints are the sample points for the first instance. We get:

\($$\begin\)\(L_6 = \frac{12}{6} \cdot 9 + \frac{4}{6} \cdot 6 + \frac{6}{6} \cdot 3 + \frac{6}{6} \cdot 3 + \frac{8}{6} \cdot 6 + \frac{10}{6} \cdot 6 = \frac{324}{6} = 54\)\(\\&\)\(R_6 = \frac{8}{6} \cdot 9 + \frac{10}{6} \cdot 6 + \frac{6}{6} \cdot 3 + \frac{6}{6} \cdot 3 + \frac{4}{6} \cdot 6 + \frac{2}{6} \cdot 6 = \frac{204}{6} = 34\)\(\\&\)\(M_6 = \frac{4}{6} \cdot f(3) + \frac{6}{6} \cdot f(6) + \frac{6}{6} \cdot f(9) + \frac{8}{6} \cdot f(12) + \frac{10}{6} \cdot f(15) + \frac{12}{6} \cdot f(18) = \frac{297}{6} = 49.5\end{aligned}$$\)

Therefore,

\($$L_6 = 54, R_6 = 34, M_6 = 49.5.$$(b)\)

overestimate M6 gives the best estimate.

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"If one were testing whether a particular sample was drawn from a population with a particular mean and the standard deviation of the entire population was known, one would use the Z-test to statistically answer the question". Option A is correct.

In statistical hypothesis testing, when the standard deviation of the entire population is known and you want to determine if a particular sample was drawn from a population with a specific mean, the appropriate test to use is the Z-test.

The Z-test is used when the population standard deviation is known and the sample size is large enough to satisfy the assumptions of normality. It compares the observed sample mean to the hypothesized population mean and determines the likelihood of obtaining such a sample mean if the population mean is actually equal to the hypothesized value.

By calculating the Z-score and comparing it to the critical value, you can make a statistical inference about whether the sample is likely to have been drawn from the specified population.

Option A holds true.

The complete question:

If one were testing whether a particular sample was drawn from a population with a particular mean and the standard deviation of the entire population was known, one would use the ______test to statistically answer the question.

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