Michelle and Justin are carrying out an investigation into the reactivity of different metals with dilute acids. They place a small piece of each metal into a test tube of acid and observe the reaction.
1) How can they tell reaction has taken place?
2) How can you tell which metal is more active?​

The resistance and the effort force are used to calculate the mechanical advantage. Arranging the threads of the screw closer together will increase the mechanical advantage. Thus, option C is correct.

Mechanical advantage is the ratio of the output force to the input force. It allows easier task performance by obeying the conservation of mass.

The closer threads of the screws make the distance covered to be more, and the force applied will be multiplied which will be a mechanical advantage over threads placed far apart.

Therefore, option C. threads located closer have more mechanical advantages.

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The temperature outside red rubber dodge ball filled with compressed air is -21.86⁰C.

The new temperature of the compressed air is determined from Charles's law as shown below;

V1/T1 = V2/T2

T2 = (T1V2)/V1

where;

T1 = 20 + 273 = 293K

T2 = (293 x 3)/3.5

T2 = 251.14K = -21.86⁰C

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Answer:

calcium chloride because that is the answer

The structure of B is pentan-2-one (C5H10O).

The reaction of propanal (C3H6O) with ethylmagnesium bromide (C2H5MgBr) in anhydrous ether results in the addition of the ethyl group from the Grignard reagent to the carbonyl carbon of propanal, forming a tertiary alcohol with the molecular formula C5H12O.

Treatment of the resulting product with aqueous chromic acid (H2CrO4) leads to oxidation of the alcohol group to a carbonyl group, forming a ketone with the molecular formula C5H10O. The ketone formed is pentan-2-one, which has the structural formula CH3CH2CH2COCH3.

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A pressure saucepan, also known as a pressure cooker, reduces cooking time by increasing atmospheric pressure inside the cooking vessel. This is achieved by sealing the pot tightly and trapping steam generated from boiling liquids and food. The increased pressure raises the boiling point of water, allowing food to cook at higher temperatures than normal. Options 1 and 3 are correct.

Option 1: Increasing atmospheric pressure is correct because the sealed pressure cooker traps steam, which increases the pressure inside the pot. The increased pressure raises the boiling point of water, resulting in faster cooking times.

Option 2: Decreasing atmospheric pressure is incorrect because pressure cookers work by increasing pressure, not decreasing it.

Option 3: Increasing vapor pressure is correct because as the pressure inside the pressure cooker increases, the vapor pressure of water also increases. This higher vapor pressure enables the food to cook more rapidly.

Option 4: Decreasing vapor pressure is incorrect because the pressure cooker actually increases the vapor pressure by raising the overall pressure inside the pot.

Option 5: Ionizing the added salt is unrelated to the operation of a pressure cooker and does not contribute to the reduction in cooking time.

Hence, a pressure saucepan reduces cooking time by increasing the atmospheric pressure and vapor pressure inside the pot.

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Answer:

d

Explanation:

.25 meters per second

25/100

.25

100/100

1

The order of increasing rate of effusion is: C₂H₆ < PH₃ < HCl < Ar.

The rate of effusion for a gas depends on its molar mass and the temperature. According to Graham's law of effusion, the rate of effusion is inversely proportional to the square root of the molar mass. Therefore, gases with lower molar masses will effuse faster than those with higher molar masses at the same temperature.

To arrange the gases in order of increasing rate of effusion, we need to compare their molar masses:

Ar (argon): Molar mass = 39.95 g/mol

HCl (hydrogen chloride): Molar mass = 36.46 g/mol

PH₃ (phosphine): Molar mass = 33.99 g/mol

C₂H₆ (ethane): Molar mass = 30.07 g/mol

Now, we can compare the molar masses and determine the order of increasing rate of effusion:

C₂H₆ (ethane): It has the lowest molar mass among the given gases, so it will have the highest rate of effusion.

PH₃ (phosphine): It has a higher molar mass than ethane but lower than hydrogen chloride and argon. Therefore, it will have a higher rate of effusion compared to hydrogen chloride and argon but lower than ethane.

HCl (hydrogen chloride): It has a higher molar mass than both ethane and phosphine. Hence, it will have a lower rate of effusion than ethane and phosphine.

Ar (argon): It has the highest molar mass among the given gases, so it will have the lowest rate of effusion.

Therefore, the order of increasing rate of effusion is:

C₂H₆ < PH₃ < HCl < Ar

In summary, ethane (C₂H₆) will have the highest rate of effusion, followed by phosphine (PH₃), hydrogen chloride (HCl), and finally, argon (Ar), which will have the lowest rate of effusion.

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Answer:

Explanation:

Since the volume of the gas does not change, we can use the Gay-Lussac's law (also known as Pressure-Temperature law), which states that the pressure of an ideal gas is directly proportional to its absolute temperature when the volume is kept constant. Mathematically, this can be expressed as:

P1/T1 = P2/T2

where P1 and T1 are the initial pressure and temperature, respectively, and P2 and T2 are the final pressure and temperature, respectively.

Substituting the given values in the above equation, we get:

P2 = (P1/T1) × T2

   = (100 kPa/273 K) × 350 K

   = 128.83 kPa (approx.)

Therefore, the final pressure of the flask is approximately 128.83 kPa.

The final temperature of copper will be approximately 28.92°C.

To find the final temperature of copper, we can use the equation:

q = m × C × ΔT

Where:

q = heat absorbed or released

m = mass of the sample

C = specific heat capacity of the substance

ΔT = change in temperature

First, let's calculate the heat absorbed by the copper using the given information:

q = 4.50 kJ = 4.50 × 10^3 J (converting kilojoules to joules)

m = 0.560 mol × molar mass of copper (Cu) = 0.560 mol × 63.55 g/mol = 35.648 g (converting moles to grams)

C = 0.385 J/g·K

Now we can rearrange the equation to solve for ΔT:

ΔT = q / (m × C)

ΔT = (4.50 × 10^3 J) / (35.648 g × 0.385 J/g·K)

ΔT ≈ 3.92 K

Finally, we can calculate the final temperature by adding the change in temperature to the initial temperature:

Final temperature = 25.0°C + 3.92 K

Final temperature ≈ 28.92°C

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Answer: The water will taste sour.

Explanation:

Answer: D. The water will taste sour (Edmentum)

Explanation:

High-quality scientific research is characterized by several key criteria. Three examples of such criteria include: rigorous experimental design and methodology, reliable data analysis and interpretation, and clear and transparent reporting of results.

These criteria ensure that research is conducted in a systematic and reliable manner, leading to trustworthy and valid findings.

Rigorous Experimental Design and Methodology: High-quality scientific research requires a well-designed experimental approach. This involves careful planning, proper control groups, randomization, and replication. A rigorous methodology ensures that experiments are conducted under controlled conditions, minimizing bias and confounding variables, and allowing for accurate and reliable data collection.

Reliable Data Analysis and Interpretation: After data collection, high-quality research involves thorough and appropriate analysis of the data. This includes using appropriate statistical methods to evaluate the significance of the results and drawing valid conclusions. Proper data analysis helps researchers identify patterns, trends, and relationships, supporting or refuting their hypotheses in an objective and reliable manner.

Clear and Transparent Reporting of Results: High-quality research demands transparent reporting of the methods, procedures, and findings. This includes providing detailed descriptions of the experimental setup, data collection processes, and statistical analyses used. Clear reporting allows other researchers to replicate the study and verify its results. Additionally, complete reporting ensures that readers can understand the research methodology and draw their own conclusions based on the evidence presented.

By adhering to these criteria, high-quality scientific research maintains integrity, credibility, and reproducibility. It fosters trust among the scientific community and facilitates the advancement of knowledge by building upon reliable foundations.

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Answer: Yellow

Explanation:

See attached table.

Answer:

Plants : Cactus, tumbleweed

Animals : camel, fennec fox

Answer:

Desert plant - Cactus & Tumbleweed

Desert animal - Camel & Scorpion

the change in Gibbs energy is 5.2 J/mol, and the reaction is non-spontaneous under these conditions.

To calculate the change in Gibbs energy, we can use the equation:

ΔG = ΔH - TΔS

ΔH - change in enthalpy,

ΔS - change in entropy,

T - temperature in Kelvin.

at 188 K, ΔH = 2380 J/mol and ΔS = 12.6 J/mol K

ΔG = (2380 J/mol) - (188 K)(12.6 J/mol K)

ΔG = 2380 J/mol - 2374.8 J/mol

ΔG = 5.2 J/mol

The positive value of ΔG indicates that the reactants are more stable than the products and that energy must be added to the system to drive the reaction forward.

Therefore, the change in Gibbs energy is 5.2 J/mol, and the reaction is non-spontaneous under these conditions.

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Answer:

matter is substance that has mass.

Answer: Mass and Volume?

Explanation:

The lower reactivity of 2,2-dimethyl-1-bromopropane in the Sn2 reaction compared to bromoethane can be attributed to steric hindrance. The two methyl groups on the carbon adjacent to the bromine in 2,2-dimethyl-1-bromopropane create a bulky structure that hinders the approach of the nucleophile during the Sn2 reaction.

This hindrance slows down the reaction and makes it less favorable compared to bromoethane, which has a simpler structure with no such hindrance.

Therefore, even though both are primary alkyl halides, the presence of the bulky methyl groups makes the Sn2 reaction of 2,2-dimethyl-1-bromopropane significantly lower than bromoethane.
The Sn2 reaction of 2,2-dimethyl-1-bromopropane is significantly lower than bromoethane because of the steric hindrance in the former compound.

Both are primary alkyl halides, but 2,2-dimethyl-1-bromopropane has two methyl groups attached to the carbon bearing the bromine atom, making it more sterically hindered. This steric hindrance reduces the accessibility of the nucleophile to the reaction site, resulting in a lower Sn2 reaction rate compared to bromoethane, which has a less hindered structure.

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Nitrogen gas has a pressure of 706 kPa in a 2 L flask and a pressure of 177 kPa when a 6 L flask is added, both at 28 °C.

Nitrogen gas at 28 °C and 706 kPa (P₁) occupies a 2 L flask (V₁). When a valve is opened, the gas can also occupy a 6 L flask. The total volume occupied by the gas (V₂) will be:

\(V_2 = 2 L + 6 L = 8 L\)

Assuming constant temperature and ideal behavior, we can calculate the final pressure (P₂) of the gas using Boyle's law.

\(P_1 \times V_1 = P_2 \times V_2\\\\P_2 = \frac{P_1 \times V_1 }{V_2} = \frac{706 kPa \times 2L }{8L} = 177kPa\)

Nitrogen gas has a pressure of 706 kPa in a 2 L flask and a pressure of 177 kPa when a 6 L flask is added, both at 28 °C.

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Answer:

Heat transfer in the atmosphere from the equatorial regions to higher latitudes occurs through the process of Convection

Explanation:

The equatorial regions of the earth's surface receive the most heat from the sun than any other region of the earth. This is because the are most directly in line with the direct heat from the sun.

Due to this heat from the sun, atmospheric air around the equatorial regions are hot and less dense than air in regions of higher latitudes, and thus, rises above the equator. The rising air at the equator is replaced by colder and denser air from higher latitudes north and south of the equator. As the rising air of the equatorial regions are being replaced by colder and denser air from higher latitudes, the hot and humid air moves away from the equator, toward regions of higher latitude, north and south thereby setting up a convection current of heat flow.

Answer:

Repetition

Explanation:

In the world of science, experiments are regularly conducted to test out hypotheses. These experiments are however, not conducted by scientist once to derive a result. They are rather conducted multiple times (repeated) to ascertain the accuracy i.e not as a result of random occurrence. The experiments that undergo multiple trials are said to undergo REPETITION.

This is the case of the scientist in this question, who is conducting an experiment to test what temperature causes the fastest growth rate in sunflower plants. He conducted the experiment multiple times, making it an example of REPETITION.

N.B: Replication is when the experiment is re-conducted by another scientist to see if same result is derived.

Answer:

Question does not show the problem in its entirety

Explanation:

The ion that has 26 protons, 28 neutrons, and 24 electrons is Iron (Fe) (option c).

An element can be determined by the number of protons in the nucleus of its atom. The number of protons present in an atom is referred to as the atomic number of the element.

This means that the number of protons in an atom is unique to a specific element.

Iron (Fe) has 26 protons in the nucleus of its atom.

Therefore, an ion with 26 protons is an ion of the element iron (Fe).

Magnesium (Mg) has 12 protons, Chromium (Cr) has 24 protons, Xenon (Xe) has 54 protons and Nickel (Ni) has 28 protons.

Thus, an ion which has 26 protons, 28 neutrons, and 24 electrons  is Fe (option c)

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Answer:

ice land should be it

Explanation:

Answer:

Iceland is the answer.

Explanation:

Determine how many mL of solution A (acetic acid-indicator solution) must be added to solution B (sodium acetate-indicator solution) to obtain a buffer solution that is equimolar in acetate and acetic acid. Solution A: 10.0 mL 3.0e-4M bromescol green

hoped I helped

Answer:

keep your skin moisturized

Explanation:

but if your crowd produces excessive lubricate, it can cause blemishes. However, skilled is a bright side -- lubricate keeps skin smooth and wet, making it less inclined wrinkle

15. To counter the effects of gravity and allow the universe to remain static.

16. The Steady State Theory.

17. Edwin Hubble.

18. No, the galaxies expand away from each other at different rates depending on their distances.

15. Einstein created the cosmological constant in an effort to counteract the forces of gravity, preventing the cosmos from growing or contracting but keeping it static at the same size.

16. The Steady State Theory, which was put forth in the 1920s, claimed that the world is motionless and limitless, and that new stuff is constantly being produced as the universe expands.

17. American astronomer Edwin Hubble observed that galaxies were moving apart from one another, and that the farther they were from one another, the quicker they were travelling, which led him to conclude that the universe was expanding in 1929.

18. Depending on how far apart they are from one another, galaxies separate from one another at varying rates. The greater the distance between any two galaxies

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Re-crystallization is carried out to purify solid compounds by dissolving and re-crystallizing them to remove impurities and obtain a higher-purity product.

Re-crystallization is a typical method in chemistry for removing impurities from solid substances. A solid substance is dissolved in a solvent at high temperatures, and then the solution is gradually cooled to allow the substance to re-crystallize. A higher quality product is produced as a result of this procedure, which frequently results in the exclusion of contaminants that were present in the original solid from the new crystals.

The removal of impurities from organic compounds, which frequently have a broad range of boiling points and can be challenging to purify using conventional techniques, is made possible via re-crystallization.

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Edible mushrooms: Consuming edible mushrooms is safe and provides health advantages like fiber, vitamins, and minerals.

Non-Edible mushrooms: Mushrooms that cannot be eaten could be harmful or have unappealing flavors and textures that could be harmful if consumed.