Members in the same family have similar chemical properties because they all
2 points
Have the same atomic radius
Have the same # of protons
Have the same # of valence electrons
Have the same # of core electrons
The number of electrons in the outermost shell of the Sodium (Na) atom is (aka valence electrons) (Hint: check the “A” group # on your Periodic Table)
2 points
6
2
1
4

Answer: Ultraviolet rays are the wave which has high enough energy to cause damage to skin and sometimes cancer.

Explanation:

Ultraviolet rays also known as UV rays have a range of wavelength from 400 nm to 10 nm.

As energy is inversely proportional to wavelength. Hence, shorter is the wavelength of a UV-ray higher will be its energy.

Also, UV rays have high enough energy due to which they are able to penetrate through the living cells causing damage to the skin. If a person remains under UV rays for a longer period of time then it can cause sunburn and could also cause skin cancer.

Thus, we can conclude that ultraviolet rays are the wave which has high enough energy to cause damage to skin and sometimes cancer.

Noble gases have completely filled electronic configuration. Therefore, noble gases or group 18 elements are inert in nature.

Noble gases are 18th group elements in periodic table. They are all having complete filled electronic configuration. The group members are helium, neon, argon, krypton, xenon and radon.

All these elements are existing in gaseous state and they are unreactive. Atoms become reactive when they have extra electrons or are deficient of electrons. Thus to achieve octet, they bond with other atoms.

In the case of noble gases, the valence shell is already achieved octet and no need of lose or gain of electrons. Thus, they are generally inert.

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Carbon dioxide and particulates are emitted by volcanoes. Particulates form stratospheric aerosols that reflect sunlight The impact of atmospheric carbon dioxide and stratospheric aerosols can be briefly described below.

Carbon dioxide (CO₂): Carbon dioxide is a greenhouse gas that contributes to the greenhouse effect and global warming. It is released into the atmosphere through various human activities, such as the burning of fossil fuels and deforestation. The increasing concentration of CO₂ in the atmosphere is a significant driver of climate change.

Stratospheric aerosols: Stratospheric aerosols, formed by the release of particulates from volcanic eruptions or human activities, can have a cooling effect on the Earth's climate. These aerosols reflect sunlight back into space, reducing the amount of solar radiation that reaches the Earth's surface. As a result, they can temporarily offset some of the warming caused by greenhouse gases like CO2.

It's important to note that while stratospheric aerosols can have a cooling effect, they are relatively short-lived in the atmosphere compared to CO₂. Carbon dioxide, on the other hand, has a long residence time and accumulates over time, leading to long-term warming.

Therefore, the overall impact of increasing atmospheric CO₂ concentrations outweighs the cooling effect of stratospheric aerosols.

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Answer:

This is called negative adsorption. Hence if the concentration of the adsorbate is less on the surface of the adsorbent than in the bulk, it is known as negative adsorption.

Explanation:

Hope this helps

The substance that donates a proton is acid. Substance that accepts a proton is a base. The substance after its proton has been donated is the conjugate Base. The substance, after it accepted a proton, is conjugate acid.

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Answer:

homozygous dominant

Explanation:

AA or BB would be another example of this. Having two of either capital or lowercase letters makes it homozygous. It is dominate because their is only one type of letter; In this case it is a capital letter.

Answer:

Homozygous

According to Mendelian inheritance, every trait (characteristic) of organsim is governed by pair of genes (that exist in two different forms, recessive and dominant allele).

Dominant allele (expressed in capital letter) masks the expression of recessive allele that is expressed in small letter.

There are two possible genotypes for dominant trait, such as 'tall pea plant' can be expressed by TT (homozygous dominant, since both alleles are same) and Tt (heterozygous dominant, since both are different alleles).

Thus, TT depicts homozygous dominant genotype.

(Hope this helps) Sky

Answer:

Its B all the others arent true and also dont make any sense

Explanation:

Sodium has a lower ionization energy than magnesium describes why sodium reacts vigorously than magnesium chloride.

Therefore, sodium is more reactive than magnesium chloride because of lower ionization energy.

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we can use the ideal gas law, which relates the pressure (P), volume (V), temperature (T), and number of moles (n) of a gas. There are 2.32 moles of gas in the sample.

How to calculate no. of moles in the given sample?

To find the number of moles of gas in the sample, we can use the ideal gas law, which relates the pressure (P), volume (V), temperature (T), and number of moles (n) of a gas:

PV = nRT

where R is the gas constant. We can rearrange this equation to solve for n:

n = PV/RT

where P is the pressure in atmospheres, V is the volume in liters, T is the temperature in Kelvin, and R is the gas constant (0.08206 L atm/(mol K)).

First, we need to convert the temperature from Celsius to Kelvin by adding 273.15:

T = 133 C + 273.15 = 406.15 K

Then, we can plug in the given values:

n = (6.9 atm)(25.1 L)/(0.08206 L atm/(mol K))(406.15 K)

n = 2.32 moles

Therefore, there are 2.32 moles of gas in the sample.

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answer below

Explanation:

Warm fronts often bring stormy weather as the warm air mass at the surface rises above the cool air mass, making clouds and storms. warm fronts move more slowly than cold fronts because it is more difficult for the warm air to push the cold, dense air across the Earth's surface.

hope this helps! have a great day!

Answer:

the terminator because i did this test

It is very dangerous to hear anything loud or cause any impact or shock while working with nitroglycerin because it can cause an explosion. Therefore, you cannot hear a dump truck driving through a nitroglycerin plant due to the danger it poses to the employees and the facility.

Nitroglycerin is an explosive material that is highly sensitive to impact, heat, or friction. It is also a primary explosive, which means that it can detonate by itself without any external stimulus. This property makes nitroglycerin one of the most dangerous substances on the planet. As a result, it is always stored in a safe location and transported with the utmost care and security to prevent accidental explosions.

When working with nitroglycerin, it is essential to follow strict safety protocols and procedures to ensure the safety of the employees and the facility. Any loud noise or impact can cause a shock wave that can trigger an explosion. Therefore, it is vital to maintain a quiet environment to avoid any unnecessary risks or accidents.

You cannot hear a dump truck driving through a nitroglycerin plant because it is incredibly dangerous to do so. The vibration and noise generated by the truck can cause a shock wave that can trigger an explosion. Therefore, the facility's employees must maintain a quiet environment and avoid any loud noises or vibrations that can cause an accident or explosion.

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(i) The initial-boundary value problem for the given scenarios are as follows:

a) Scenario a:

PDE: ∂u/∂t = k * ∂²u/∂x²

Initial condition: u(x, 0) = 100 (boiling water temperature)

Boundary conditions: u(0, t) = 10, u(L, t) = 10 (constant temperature at the ends)

b) Scenario b:

PDE: ∂u/∂t = k * ∂²u/∂x²

Initial condition: u(x, 0) = 100 (boiling water temperature)

Boundary conditions: u(0, t) = 0 (temperature at x=0), ∂u/∂x(L, t) = 0 (thermal insulation at x=L)

(iii) The solution for the temperature distribution as time approaches infinity can be found by solving the appropriate steady state equation.

(i) The initial-boundary value problem formulation states the partial differential equation (PDE) governing the temperature distribution in the aluminum bar, along with the initial condition and boundary conditions.

In scenario (a), both ends of the bar are immersed in a medium with a constant temperature of 10 degrees Celsius, while in scenario (b), the end at x=0 is immersed in a medium with temperature 0 degrees Celsius and the end at x=L is insulated.

(ii) As time approaches infinity, the temperature distribution in the bar tends to reach a steady state.

In scenario (a), the temperature throughout the bar will eventually approach a constant value of 10 degrees Celsius, since both ends are immersed in a medium with that temperature.

In scenario (b), the temperature at x=0 will approach 0 degrees Celsius, while the temperature at x=L will remain constant due to thermal insulation.

(iii) To find the solution as time approaches infinity, we need to solve the appropriate steady state equation.

In scenario (a), the steady state equation is ∂²u/∂x² = 0, which implies that the temperature gradient is zero throughout the bar, resulting in a constant temperature of 10 degrees Celsius.

In scenario (b), the steady state equation is ∂²u/∂x² = 0 with the boundary condition u(0) = 0, which implies a linear temperature distribution from 0 degrees Celsius at x=0 to a constant temperature at x=L due to insulation.

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Answer:

yy

Explanation:

The final volume of the hydrogen gas is approximately 0.22 L. The correct response is 0.22 L. We use the ideal gas law.

We can use the ideal gas law to solve this problem:

PV = nRT

where P is the pressure of the gas, V is its volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas.

Assuming that the number of moles of hydrogen gas and the temperature remain constant, we can write:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume of the hydrogen gas, and P2 and V2 are the final pressure and volume of the gas. Rearranging, we get:

V2 = (P1/P2) * V1

Substituting the given values, we get:

V2 = (150 kPa/2 atm) * 3.0 L = 0.22 L

Therefore, the final volume of the hydrogen gas is approximately 0.22 L. The correct response is 0.22 L.

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Answer: 10

A cup of coffee has a hydroxide ion concentration of 1. 0 × 10−10 m. The pH of this coffee will be 10

pH = - log [H+]

    = - log [1. 0 × ]

    = - log 1 - ( -10 log 10 )

    = 0 + 10  = 10

The pH of this coffee will be 10

Explanation:

Answer:

The five conditions of chemical change: color change, formation of a precipitate, formation of a gas, odor change, temperature change

Hope that helps

The number of particles of water that exist in a closed test tube after the water vaporizes and turns into a gas will be the same as the number of particles before the phase change.

This is because during the phase change, the molecules of water simply change their state from liquid to gas.the phase change from liquid to gas does not involve any change in the number of molecules, only a change in the physical state of the molecules.  The molecules do not disappear or gain additional molecules from outside the test tube. As such, the number of particles of water in the test tube after the phase change is the same as before the phase change.

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Answer:

C! Hope this helps !:)

Explanation:

Answer:

Arrows pointing from the sun to the juice pop

Explanation: Trust I got it right

2H₂ + O₂ ⇒ 2H₂O

Conservation of mass states that

In a closed system, the masses before and after the reaction are the same

So it can be concluded

So let's see which of the several options , which one has the same number of atoms on both sides of the equation

2H₂ + O₂ ⇒ 2H₂O

H ⇒ left 4, right 4

O ⇒ left 2, right 2

so the equation is in balance and represents the Law of Conservation of

Mass

1. 12 L = 12 dm³

2. 3.18 g

Given

1. Reaction

K₂CO₃+2HNO₃⇒ 2KNO₃+H₂O+CO₂

69 g K₂CO₃

2. 0.03 mol/L Na₂CO₃

Required

1. volume of CO₂

2. mass Na₂CO₃

Solution

1. mol K₂CO₃(MW=138 g/mol) :

= 69 : 138

= 0.5

mol ratio of K₂CO₃ : CO₂ = 1 : 1, so mol CO₂ = 0.5

Assume at RTP(25 C, 1 atm) 1 mol gas = 24 L, so volume CO₂ :

= 0.5 x 24 L

= 12 L

2. M Na₂CO₃ = 0.03 M

Volume = 1 L

mol Na₂CO₃ :

= M x V

= 0.03 x 1

= 0.03 moles

Mass Na₂CO₃(MW=106 g/mol) :

= mol x MW

= 0.03 x 106

= 3.18 g

Answer:

welcome to 2021 dude

its been a long time since i answered this but here is my new account

Explanation: