Melissa buys 212 pounds of salmon and 114 pounds of swordfish. She pays a total of $31.25, and the swordfish costs $0.20 per pound less than the salmon. What would be the combined cost of 1 pound of salmon and 1 pound of swordfish? A. $15.60 B. $15.80 C. $16.60 D. $16.80

Answer:

A lot

Step-by-step explanation:

The width of the rectangle is 9 meter.

Now, According to the question:

The perimeter of a rectangle is defined as the sum of all the sides of a rectangle. For any polygon, the perimeter formulas are the total distance around its sides. In case of a rectangle, the opposite sides of a rectangle are equal and so, the perimeter will be twice the width of the rectangle plus twice the length of the rectangle and it is denoted by the alphabet “p”.

Now, Solving the problem:

Perimeter of rectangle is 50 meter sq.

Length of the rectangle(L) is 16 meter.

We have to find the width (W) of the rectangle.

We know that,

Perimeter of rectangle is = 2 (L + W)

50 = 2(16 + W)

50 = 32 + 2W

2W = 50 - 32

2W = 18

W = 18/2

W = 9

Hence, The width of the rectangle is 9 meter.

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Find the derivate of the expression using the general procedure to find the derivative of a polynomial function. To do it, multiply the term times the exponent of the variable and raise the variable to the original exponent minus 1:

Now that we have the expression for the derivative of the function, evaluate it at the value of x that is in the question statement, which is 1:

The derivative of the function is -2 at x=1.

Answer:

y = 3/2x + 5

Step-by-step explanation:

y = Rise/Run + y intercept

Answer:

how am i supposed to know this

Step-by-step explanation:

loser

Answer:

I have no idea tbh I need help with this too

Step-by-step explanation:

PLEASE HELP!!!!!!!!!!!!!!!

The cross product assuming that u×v=⟨7,6,0⟩.(u−7v)×(u+7v) is                ⟨-49, -7u_2 + 6u_3, -7u_3 + 6u_2⟩.

The cross product of two vectors using the distributive property:

(u - 7v) × (u + 7v) = u × u + u × 7v - 7v × u - 7v × 7v

Also, cross product is anti-commutative. Specifically, the cross product of v × w is equal to the negative of the cross product of w × v. So, we can simplify the expression as follows:

(u - 7v) × (u + 7v) = u × 7v - 7v × u - 7(u × 7v)

Now, using u × v = ⟨7, 6, 0⟩ to evaluate the cross products:

u × 7v = 7(u × v) = 7⟨7, 6, 0⟩ = ⟨49, 42, 0⟩

7v × u = -u × 7v = -⟨7, 6, 0⟩ = ⟨-7, -6, 0⟩

Substituting these values into the expression:

(u - 7v) × (u + 7v) = ⟨0, 7u_2 - 6u_3, 7u_3 - 6u_2⟩ - 7⟨7, 6, 0⟩ - 7⟨-7, -6, 0⟩

= ⟨0, 7u_2 - 6u_3, 7u_3 - 6u_2⟩ - ⟨49, 42, 0⟩ + ⟨49, 42, 0⟩

= ⟨-49, -7u_2 + 6u_3, -7u_3 + 6u_2⟩

Therefore, (u - 7v) × (u + 7v) = ⟨-49, -7u_2 + 6u_3, -7u_3 + 6u_2⟩.

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Answer:

El que pesa distinto es aquel que causa un desnivel en la balanza.

Step-by-step explanation:

Sabemos que una balanza tiene dos lados en los cuales podemos poner peso, si la balanza está equilibrada, ambos lados están a la misma altura, de lo contrario, habrá un desnivel entre ambos lados.

Puesto que solo podemos emplear la balanza 3 veces, debemos crear tres grupos de cuatro personas, que dentro de cada una cada mitad, conformada por dos personas, es colocada en un lado de la balanza. Si la balanza está equilibrada, entonces todo ese grupo está integrado por personas del mismo peso, pero si esta desequilibrada, una persona de alguno de los dos subgrupos.

En ese caso, se procede a sacar a dos personas, una por cada lado de la balanza, si el desbalance desaparece, entonces alguna de las dos personas que salió tiene un peso distinto, pero si el desbalance persiste, entonces es causante del desbalance se encuentra en aún en la balanza.

En conclusión, el que pesa distinto es aquel que causa un desnivel en la balanza.

Answer:1 and 6

Step-by-step explanation:1 x 6 = 6

1 + (6) = 7

Are you asking because you are trying to figure out how to factor the following quadratic equation?

x2 + 7x + 6 = 0

If so, the solution to factor the quadratic equation above is:

(X + 1 ) (X + 6)

To summarize, since 1 and 6 multiply to 6 and add up 7, you know that the following is true:

x2 + 7x + 6 = (X + 1 ) (X + 6)

Answer:

A= 61

B=119

Step by step:

a; interior angle

180-(27+92)

=180(119)

=61

b; exterior angle

180-61

=119

Answer: 61 and 119

Step-by-step explanation:

Answer:

10 1/2 pounds are needed.

Step-by-step explanation:

7 x 1.5 = 10.5

If the cube with 2.00 m wide and 2.00 m long and 2.00 m high has a weight of 900.00 n, then the cube exerts a pressure of 225 N/m².

To calculate the pressure exerted by the cube, follow these steps:

Step 1: To calculate the pressure exerted by the cube,  you need to consider its weight and the area over which it is exerting the force. The cube has a weight of 900 N and dimensions of 2.00 m x 2.00 m x 2.00 m.

Step 2: To find the pressure, we will use the formula:

Pressure (P) = Force (F) / Area (A)

Step 3: In this case, the force is the weight of the cube (900 N), and the area is the base of the cube (2.00 m x 2.00 m).

A = 2.00 m * 2.00 m = 4.00 m²

Step 4: Now, you can calculate the pressure:

P = 900 N / 4.00 m² = 225 N/m²

So, the cube exerts a pressure of 225 N/m².

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Answer:

reflection

transition left / right are the location of the vertex

The rate of change of the area is -80.5 \(inches^{2}\)/sec.

Given:

A right triangle has legs of 21 inches and 28 inches whose sides are changing.The short leg is decreasing by 2 in/sec and the long leg is shrinking at 5 in/sec.

Let's set the two legs as a and b, so the lengths are:

a = 21 - 2t

b = 28 - 5t

The area is:

area a = ab /2

= (21 - 2t) (28 - 5t)/2

= (588 - 105t - 56t + 10\(t^{2}\)/2

a = 5\(t^{2}\) - 161t/2 - 299

The rate of change of the area is:

da/dt = d(5\(t^{2}\) - 161t/2 - 299)/dt

da/dt = 10t -161/2

And at t=0,

= 10(0) - 161/2

= - 80.5

so the  rate of change of the area is -80.5 \(inches^{2}\)/sec.

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Answer:

x = 4

Step-by-step explanation:

30x = 29x + 4

subtract 29x from both sides

x = 4

The correct answer to the given question is "True."

Cross-sectional design involves the systematic collection of responses to a consumer survey instrument from one or more samples of respondents at one point in time. The main purpose of the cross-sectional design is to gather information about a population at a specific time or period. Cross-sectional research is frequently used in psychology, epidemiology, marketing research, and other fields. The word "systematic" is used in the question, which implies a methodical or orderly procedure. Cross-sectional design gathers information through a systematic and organized method. Therefore, it is true that cross-sectional design involves the systematic collection of responses to a consumer survey instrument from one or more samples of respondents at one point in time.

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Answer:

area of sector=84°/360°×π×45²=1485cm²

The area of the sector to 3 significant figure is 1480cm²

The formula for calculating the area of a sector is expressed as

A= r²β/2

where;

r is the radius. = 45cm

β is the central angle =84 degrees

Substitute

A = (45)²(84π)/360
A = 1483.65cm²

Hence the area of the sector to 3 significant figure is 1480cm²

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Answer:

Dogodgo

Step-by-step explanation:

Answer:

Step-by-step explanation:

=_=

Answer:

x = 135 degrees

y = 45 degrees

Step-by-step explanation:

angle F = 90 = E  degrees

triangle EBF is isosceles so the angles at the base would be 180-90 = 90/2

which would equal 45.

Hence, y would equal 45.

45 + x = 180 (supplementary)

x = 135

Step-by-step explanation:

the correct answer is option a 6a-7

Answer:I don’t Knowt Try To Answer it yourself

Step-by-step explanation:

The time taken by both to mow the lawn is 36 minutes.

This is a question of time and work.

It is given that:-

Time taken by boy to mow the loan = 90 minutes.

Time taken by girl to mow the loan = 60 minutes.

We have to find the time taken by both of them together to mow the lawn.

LCM(60,90) = 180

Let the total work to be done to mow the lawn be 180 units.

Hence,

Efficiency of boy = 180/90 = 2 units

Efficiency of girl = 180/60 = 3 units

Total efficiency = 2 + 3 = 5 units.

Hence, time taken by both of them to mow the lawn = 180/5 = 36 minutes.

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The speed of the water drop when it strikes the hood is approximately 14.0 m/s downward, and the speed of the car at that moment is approximately 29.3 m/s to the east.

The drop appears to have a velocity of approximately 29.3 m/s to the west and 14.0 m/s downward with respect to the passenger in the car.

The drop appears to have an acceleration of approximately 3 m/s² to the west and 9.8 m/s² downward with respect to the passenger in the car.

(To determine the speed of the water drop and the speed of the car when the drop strikes the hood,

use the kinematic equations of motion.

First, we can find the time it takes for the drop to fall 10m using the kinematic equation:

distance h = 10m,

\(h = 1/2 at^2\)

where

h is the vertical distance,

a is the acceleration due to gravity (9.8m/s²), and t is the time.

Substituting the values, we have;

\(10 = 1/2 (9.8) t^2 \\

t^2 = 20/9.8 \\

t ≈ 1.43 seconds\)

Next, find the final velocity of the drop using the kinematic equation:

\(v = vo + at\)

where v is the final velocity,

vo is the initial velocity (which is 0m/s for the drop),

a is the acceleration due to gravity, and

t is the time we just calculated.

Substituting the values, we have

v = 0 + (9.8)(1.43)

v ≈ 14.0 m/s downward

Finally, find the speed of the car when the drop strikes the hood using the kinematic equation:

\(v = vo + at\)

v = 25 + (3)(1.43)

v ≈ 29.3 m/s to the east

Therefore, the speed of the water drop when it strikes the hood is approximately 14.0 m/s downward, and the speed of the car at that moment is approximately 29.3 m/s to the east.

To determine the velocity and acceleration

The velocity of the water drop with respect to the passenger in the car is simply the vector difference between the velocity of the water drop and the velocity of the car:

v_drop,p = v_drop - v_car

where v_drop is the velocity of the water drop (14.0 m/s downward) and

v_car is the velocity of the car (29.3 m/s to the east).

Substituting the values, we get:

v_drop,p = (0, -14.0, 0) - (29.3, 0, 0)

v_drop,p = (-29.3, -14.0, 0) m/s

Thus, the drop appears to have a velocity of approximately 29.3 m/s to the west and 14.0 m/s downward with respect to the passenger in the car.

The acceleration of the water drop with respect to the passenger in the car is simply the vector difference between the acceleration of the water drop and the acceleration of the car:

a_drop,p = a_drop - a_car

where a_drop is the acceleration due to gravity (9.8 m/s² downward) and

a_car is the acceleration of the car (3 m/s² to the east).

Substituting the values, we have,

a_drop,p = (0, -9.8, 0) - (3, 0, 0)

a_drop,p = (-3, -9.8, 0) m/s²

Therefore, the drop appears to have an acceleration of approximately 3 m/s² to the west and 9.8 m/s² downward with respect to the passenger in the car.

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Answer:

6 hope this was fast

Answer:

6

Step-by-step explanation:

\(\frac{3}{4}\) x 8 =

\(\frac{3}{4}\) × \(\frac{8}{1}\) = \(\frac{24}{4}\)

\(\frac{24}{4}\) = 6

the volume of the region contained in the cylinder x² + y² = 9, bounded above by the plane z = x and below by the xy-plane is 0.

Given: The cylinder is x² + y² = 9, bounded above by the plane z = x and below by the xy-planeWe know that, the cylinder is x² + y² = 9Which is (x/a)² + (y/b)² = 1Where a = 3 and b = 3The plane is z = xThe region is bounded below by the xy-plane Thus, the volume of the region can be found by integrating z = x with limits of x² + y² ≤ 9.So, V = ∭ dx dy dz where the limits are given by the cylinder and the plane.V = ∫∫∫ (x) dV ... (1)Now, converting the integral into cylindrical coordinates we have,∫∫∫ (x) dV = ∫θ = 0 to 2π ∫r = 0 to 3 ∫z = 0 to r cos θ (r cos θ) rdzdrdθ ... (2)x = r cos θ, y = r sin θ, and z = z.We know that the limits of x² + y² ≤ 9 in cylindrical coordinates are 0 ≤ θ ≤ 2π, 0 ≤ r ≤ 3, 0 ≤ z ≤ r cos θ.Using (2) in (1), we haveV = ∫θ = 0 to 2π ∫r = 0 to 3 ∫z = 0 to r cos θ (r cos θ) rdzdrdθ= ∫θ = 0 to 2π ∫r = 0 to 3 [r² cos θ / 2] dr dθ= ∫θ = 0 to 2π [ 9 cos θ / 2 ] dθ= 9 [ sin θ ]θ = 0 to 2π= 0Thus, the volume of the region contained in the cylinder x² + y² = 9, bounded above by the plane z = x and below by the xy-plane is 0.

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The landscape architect should use a length of approximately 80 ft and a width of approximately 50 ft to minimize the cost, resulting in a minimum cost of approximately $9000.

Let the length of the rectangular region be L and the width be W. The total cost, C, is given by C = 3(20L) + 25W, where the first term represents the cost of shrubs along three sides and the second term represents the cost of fencing along the fourth side.

The area constraint is LW = 4000. We can solve this equation for L: L = 4000/W.

Substituting this into the cost equation, we get C = 3(20(4000/W)) + 25W.

To find the dimensions that minimize cost, we differentiate C with respect to W, set the derivative equal to zero, and solve for W. Differentiating and solving yields W ≈ 49.9796 ft.

Substituting this value back into the area constraint, we find L ≈ 80.008 ft.

Thus, the dimensions that minimize cost are approximately L = 80 ft and W = 50 ft.

Substituting these values into the cost equation, we find the minimum cost to be C ≈ $9000.

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