Megan exercises every morning for 40 minutes. She does a combination of step aerobics, which burns about 11 calories/min and stretching which burns about 4 calories/min. Her goal is to burn 335 calories during her routine. How long should she participate in each activity in order to burn 335 calories?

Answer:

after 60 seconds = 1 minute ,they will together for the first time.

Step-by-step explanation:

Three bells toll at an interval of 4,5 and 6 second.

They will ring together at the time which will be the multiple of all the three time interval (i.e 4,5,6)

4 = 2*2

5= 5*1

6 = 2*3

LCM  of these three number will be multiple of highest power of each prime number

highest power of 2 in the above problem 2^2

3 = 3

5 = 5

Thus, LCM 2^2 * 3*5 = 60

Thus, after 60 seconds they will together for the first time.

Then they will toll together after each interval of 60 seconds together.

An appropriate measure for ∠CDE would be

∠CDE = ∠ADE - ∠ADC

we have the following angles as parallel BC¯, DE¯, and FG¯ also  CD¯, EF¯, and GH¯.

The angles that we have to check in order to measure would be

∠ABC, ∠AEG, ∠ADC, ∠AHG, ∠ADE, ∠AFE, ∠AHG.

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The measure of angle a is 15 degrees and this can be determined by using the properties of the isosceles triangle.

In geometry, interior angles are formed in two ways. One is inside a polygon, and the other is when parallel lines cut by a transversal. Angles are categorized into different types based on their measurements.

Given:

The following steps can be used in order to determine the measure of angle a:

Step 1 - According to the given data, it can be concluded that triangle PQR and triangle PSR are isosceles triangles.

Step 2 - Apply the sum of interior angle property on triangle PQR.

\(\angle\text{Q}+\angle\text{P}+\angle\text{R}=180\)

\(\angle\text{Q}+2\angle\text{R}=180\)

\(2\angle\text{R}=180-60\)

\(\angle\text{R}=60^\circ\)

Step 3 - Now, apply the sum of interior angle property on triangle PSR.

\(\angle\text{P}+\angle\text{S}+\angle\text{R}=180\)

\(\angle\text{S}+2\angle\text{R}=180\)

\(2\angle\text{R}=180-90\)

\(\angle\text{R}=45^\circ\)

Step 4 - Now, the measure of angle a is calculated as:

\(\angle\text{a}=60-45\)

\(\angle\text{a}=15\)

The measure of angle a is 15 degrees.

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Answer: 135 degrees

Step-by-step explanation:

Answer:

135

Step-by-step explanation:

sum of triangle angles = 180

then JLK =. 180 -(70+65) = 180 - 135 = 45

then JLK = 45

since JLM = 180

then KLM = 180 - 45 = 135

The gravitational potential energy of the vacationers will decrease as they approach the end of the pier.

As the vacationers approach the end of the pier, their gravitational potential energy will decrease.

Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. It depends on the height of the object and the acceleration due to gravity.

In this scenario, as the vacationers walk out on the horizontal pier, their height above the ground remains constant. Since the height does not change, the gravitational potential energy also remains constant.

However, as they approach the end of the pier, their distance from the center of the Earth decreases. As a result, the gravitational potential energy decreases because it is directly proportional to the distance from the center of the Earth.

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The data includes independent random samples from two regions, with mound-shaped and symmetric chemical distributions. To find a 90% confidence interval, find the sample means, standard deviations, and sample sizes. The lower limit of confidence interval is -269.31, while the upper limit is 303.31.

The given data are the content loaded Independent random samples from two regions. Let be the population mean for the first region, and be the population mean for the second region, where X1, and X2 are two independent samples of sizes n1 and n2, respectively.Assume the population distributions of the chemical are mound-shaped and symmetric for these two regions.

The formulas for the 90% confidence interval for the difference between two means are as follows: Lower limit of confidence interval = (X1 - X2) - t(α/2,ν) × SED

Upper limit of confidence interval = (X1 - X2) + t(α/2,ν) × SED

Where, SED = \(√(s1^2/n1 + s2^2/n2)α\)

= 1 - confidence level (As the confidence level is 90%, α = 0.10)t(α/2,ν) is the t-critical value based on the degrees of freedom ν = (n1 + n2 - 2).

To find a 90% confidence interval for the difference between two population means: We need to first find the sample means, sample standard deviations, and sample sizes.

n1 = 12, X1 = 696.33, and s1 = 329.71n2 = 16, X2 = 660.31, and s2 = 179.20ν

= (n1 + n2 - 2)

= (12 + 16 - 2)

= 26α/2

= 0.10/2

= 0.05t(0.05, 26)

= 1.706SED

= \(√(s1^2/n1 + s2^2/n2)\)

= \(√(329.71^2/12 + 179.20^2/16)\)

= 120.93

Lower limit of confidence interval = (X1 - X2) - t(α/2,ν) × SED

= (696.33 - 660.31) - 1.706 × 120.93

= -269.31

Upper limit of confidence interval = (X1 - X2) + t(α/2,ν) × SED

= (696.33 - 660.31) + 1.706 × 120.93

= 303.31

Hence, a 90% confidence interval for the difference between two population means is [-269.31, 303.31].Therefore, the answer is: a 90% confidence interval for the difference between two population means is [-269.31, 303.31].

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Answer:

the correct one is c

Step-by-step explanation:

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To determine the marginal and conditional probability distributions across states, we examine the given joint probability distribution. Let's denote the endowment in period t as yt and in period t+1 as yt+1.

(a) The marginal probability distribution of yt represents the probabilities of different endowment values in period t. From the joint probability distribution, we can see that:

\(Pr(yt=L) = Pr(yt+1=L, yt=L) + Pr(yt+1=L, yt=H) = 0.2 + 0.1 = 0.3Pr(yt=H) = Pr(yt+1=H, yt=L) + Pr(yt+1=H, yt=H) = 0.1 + 0.5 = 0.6\)

The conditional probability distribution represents the probabilities of different endowment values in period t+1 given the endowment value in period t. From the joint probability distribution, we have:

Pr(yt+1=L | yt=L) = 0.2/0.3 ≈ 0.667

Pr(yt+1=H | yt=L) = 0.1/0.3 ≈ 0.333

Pr(yt+1=L | yt=H) = 0.1/0.6 ≈ 0.167

Pr(yt+1=H | yt=H) = 0.5/0.6 ≈ 0.833

(b) The price of a one-period bond represents the expected present value of receiving one unit of the endowment in the next period, given the current state. In period one, the price of a one-period bond for each possible state is given by:

\(Price(y1=L) = Pr(y2=L | y1=L) * 1 + Pr(y2=H | y1=L) * 1 = 0.667 + 0.333 = 1Price(y1=H) = Pr(y2=L | y1=H) * 1 + Pr(y2=H | y1=H) * 1 = 0.167 + 0.833 = 1\)

(c) The price of a ten-period bond represents the expected present value of receiving ten units of the endowment in the next ten periods, given the current state. In period one, the price of a ten-period bond for each possible state is given by:

\(Price(y1=L) = Pr(y2=L | y1=L) * 1 + Pr(y2=H | y1=L) * 2 + ... + Pr(y11=L | y1=L) * 10 = 0.667 + 0.667 + ... + 0.667 = 6.67Price(y1=H) = Pr(y2=L | y1=H) * 1 + Pr(y2=H | y1=H) * 2 + ... + Pr(y11=L | y1=H) * 10 = 0.167 + 0.167 + ... + 0.167 = 1.67\)

(d) The unconditional mean price for the one-year bond is the average of the prices for each possible state in period one:

Unconditional mean price for one-year bond =

(Price(y1=L) + Price(y1=H)) / 2 = (1 + 1) / 2 = 1 The unconditional mean price for the ten-year bond is the average of the prices for each possible state in period one:

Unconditional mean price for ten-year bond = (Price(y1=L) + Price(y1=H)) / 2 = (6.67 +

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Using greater than sign or number line, we can show the numbers from greatest to least as 35/4 > √72 > 25/3 > 8.4

To arrange numbers from greatest to least, you would first find the largest number and place it at the beginning of the list. Then, you would compare the remaining numbers and place the next largest number after the first. You would continue this process until all of the numbers are arranged in order from largest to smallest.

In this problem, we can arrange the number from greatest to least and assigning the greater than sign to show the decrease in number. We dan also use the concept of number line to show how the numbers are placed.

From the data given,

35/4 > √72 > 25/3 > 8.4

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Answer:

She rode 1/10 of an hour more on Saturday

Step-by-step explanation:

Take the time she rode on Sunday and subtract that from Saturday

7/10 - 3/5

Get a common denominator

7/10 - 3/5*2/2

7/10 - 6/10

1/10

She rode 1/10 of an hour more on Saturday

The value of p is 80

p= kq²/√r

p= 60, q= 6, r= 81

60= k(6)²/√81

60= 36k/9

cross multiply

36k= 60×9

36k= 540

k= 540/36

k= 15

The value of p can be calculated as follows

p= kq²/√r

p= 15(8)²/√144

p= 15(64)/12

p= 960/12

p= 80

Hence the value of p is 80

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Answer:

p=2/3

Step-by-step explanation:

The value of p in the linear equation in one variable p - 3 1/6 = -2 1/2 is 2/3 or p = 2/3.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

The equation is:

p - 3 1/6 = -2 1/2

To solve the above linear equation in one variable first convert mixed fraction to fraction:

p - 19/6 = -5/2

p = -5/2 + 19/6

Take LCM of 2 and 6

p = (-15 + 19)/6

p = (4)/6

p = 2/3

Thus, the value of p in the linear equation in one variable p - 3 1/6 = -2 1/2 is 2/3 or p = 2/3.

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In 100 million years, the seafloor spreading zone will create 10 million square kilometers of new surface area.


The seafloor spreading zone creates 1 centimeter of new crust over its entire 1000 kilometers length every year. To calculate the surface area created, we need to multiply the length of the zone by the amount of new crust created each year.

First, we convert the length from kilometers to centimeters: 1000 kilometers = 100,000,000 centimeters.
Then, we multiply the length by the amount of new crust created each year: 100,000,000 cm * 1 cm = 100,000,000 square centimeters.

Finally, we convert square centimeters to square kilometers: 100,000,000 cm^2 = 10,000 km^2. Therefore, in 100 million years, the seafloor spreading zone will create 10,000 square kilometers of new surface area.

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Remove the brackets.

Take the like terms closer.

Now do the addition and subtraction

Let us split the middle term

Now take x as common from the first two terms and -1 from the next two terms.

Answer:

(x - 1)(7x + 12)

Hope you could understand.

If you have any query, feel free to ask.

Solve (6x² + 5x - 3) + (x² - 9)

(x-1) (7x+12)

please look at the attached picture :)

The set of all objects of interest is called population.

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Answer:

Step-by-step explanation:

1.5

Answer:

A=πr2=π·32≈28.27433ft²

Step-by-step explanation:

The probability of obtaining a sum of 18 when rolling four dice and taking the sum of the three highest values can be calculated by determining the number of favorable outcomes and dividing it by the total number of possible outcomes.

When rolling four dice, each die can have six possible outcomes, ranging from 1 to 6. To find the probability of obtaining a sum of 18, we need to determine the number of favorable outcomes. In this case, we are interested in the three highest values summing up to 18.

To calculate this, we can use combinations. The three highest values that can result in a sum of 18 are 6, 6, and 6. We can choose these three values from the four dice in only one way. The remaining die can have any value from 1 to 6, giving us six possible outcomes.

Therefore, the number of favorable outcomes is 1, and the total number of possible outcomes is 6^4 (since each die has six possible outcomes and we are rolling four dice). Dividing the number of favorable outcomes by the total number of possible outcomes gives us the probability: 1/(6^4) ≈ 0.00077, or approximately 0.077%. Thus, the probability of obtaining a sum of 18 when rolling four dice and taking the sum of the three highest values is very low.

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Answer:

\(\displaystyle 1\frac{2}{5}=\frac{7}{5}\)

Step-by-step explanation:

\(\displaystyle a\frac{b}{c}=\frac{ac+b}{c}\\\\1\frac{2}{5}=\frac{(1)(5)+2}{5}=\frac{5+2}{5}=\frac{7}{5}\)

We can conclude that there are no nontrivial clean pulsations for the given left-mounted beam with a simple support on the right.

To find the equation of clean pulsations for a left-mounted beam with a simple support on the right, we can use the differential equation that describes the deflection of the beam. Assuming the beam is subject to a distributed load and has certain boundary conditions, the equation governing the deflection can be written as:

d^2y/dx^2 + (chx)^2 * y = 0

Where:

y(x) is the deflection of the beam at position x,

d^2y/dx^2 is the second derivative of y with respect to x,

ch(x) is the hyperbolic cosine function.

To solve this differential equation, we can assume a solution in the form of y(x) = A * cosh(kx) + B * sinh(kx), where A and B are constants, and k is a constant to be determined.

Substituting this assumed solution into the differential equation, we get:

k^2 * (A * cosh(kx) + B * sinh(kx)) + (chx)^2 * (A * cosh(kx) + B * sinh(kx)) = 0

Simplifying the equation and applying the given identity (chx)^2 - (shx)^2 = 1, we have:

(A + A * chx^2) * cosh(kx) + (B + B * chx^2) * sinh(kx) = 0

For this equation to hold for all values of x, the coefficients of cosh(kx) and sinh(kx) must be zero. Therefore, we get the following equations:

A + A * chx^2 = 0

B + B * chx^2 = 0

Simplifying these equations, we have:

A * (1 + chx^2) = 0

B * (1 + chx^2) = 0

Since we are looking for nontrivial solutions (A and B not equal to zero), the expressions in parentheses must be zero:

1 + chx^2 = 0

Using the identity (sinx)^2 + (cosx)^2 = 1, we can rewrite this equation as:

1 + (1 - (sinx)^2) = 0

Simplifying further, we get:

2 - (sinx)^2 = 0

Solving for (sinx)^2, we find:

(sin x)^2 = 2

Since the square of the sine function cannot be negative, there are no real solutions to this equation. Therefore, we can conclude that there are no nontrivial clean pulsations for the given left-mounted beam with a simple support on the right.

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Finding the union of the sets A and C is the first step in solving P(A U C). Since set C only contains the number 6, the union of A and C has the elements 1, 2, 3, 4, and 6. A U C thus equals 1, 2, 3, 4, and 6.

The power set of A U C, which comprises all conceivable subsets of 1, 2, 3, 4, and 6, must then be located. If all conceivable subsets are listed, the power set of A U C, designated as P(A U C), will be discovered.

P(A U C) = { {}, {1}, {2}, {3}, {4}, {6}, {1,2}, {1,3}, {1,4}, {1,6}, {2,3}, {2,4}, {2,6}, {3,4}, {3,6}, {4,6}, {1,2,3}, {1,2,4}, {1,2,6}, {1,3,4}, {1,3,6}, {1,4,6}, {2,3,4}, {2,3,6}, {2,4,6}, {3,4,6}, {1,2,3,4}, {1,2,3,6}, {1,2,4,6}, {1,3,4,6}, {2,3,4,6}, {1,2,3,4,6}}.

There are 31 subsets in the power set P(A U C) that result from the union of sets A and C.

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Answer:

Step-by-step explanation:

x(x-4)= x^2-4x

x^2-4x(x-1)

x^3-5x^2+4x

\(f(x) = \frac{1}{9}x + 2 \\ \)

\(y = \frac{1}{9}x + 2 \\ \)

Subtract the sides of the equation minus 2

\(y - 2 = \frac{1}{9}x \\ \)

Multiply the sides of the equation by 9

\(9(y - 2) = x\)

\(9y - 18 = x\)

So ;

\( {f}^{ - 1}(x) = 9x - 18 \)

_________________________________

And we're done.

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Answer:

click the turn in button

theres a button you can click to turn in

The distance of the swing of a pendulum decreases by a constant amount each swing. To find the distance of the swing at the tenth swing, you can use the formula:

distance at nth swing = distance at first swing * (1 - decay factor)^(n-1)

Where decay factor is the fractional decrease in distance per swing. In this case, the decay factor is (80 - 76) / 80 = 0.05. Plugging this into the formula above, we get:

distance at 10th swing = 80 * (1 - 0.05)^9 = 53.78 cm

So the distance of the swing at the tenth swing is approximately 53.78 cm.

Answer:

its 50

Step-by-step explanation:

Answer:

-2.76115787098

Step-by-step explanation:

First you do 35/92 which is 0.3804347826

Then you subtract it from pi which has a value of 3.14159265359.

Then you subtract the former from the latter to give the answer.

Answer: -2.7611

Step-by-step explanation:

Solve for J by simplifying both sides of the equation, then isolate the variable.

35/92 - π = J

J = 35/92 - π

= -2.7611