Therefore, the amplitude is: amplitude = 21 cm. So, the correct answer is d. 21cm.
A periodic variable's amplitude measures the change it undergoes throughout a single period. When measured against a standard value, a non-periodic signal's amplitude is its magnitude. There are several definitions of amplitude, all of which depend on how much the extreme values of the variable deviate from one another.
The amplitude of a spring-mass system is half the distance between the equilibrium position (the rest position of the mass) and the highest point of the oscillation (the crest).
Since the length from the lowest point to the highest point of the oscillation is given as 42 cm, the total displacement of the oscillation is 2 times the amplitude.
Therefore, the amplitude is:
amplitude = 42 cm / 2 = 21 cm
So, the correct answer is d. 21cm.
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what is the maximum height reached by the ball? 400 correct: your answer is correct. ft what is the velocity of the ball when it is 384 ft above the ground on its way up? (consider up to be the positive direction.) 32 correct: your answer is correct. ft/s what is the velocity of the ball when it is 384 ft above the ground on its way down? (no response) ft/s when will the ball hit the ground? t
The primary indicator of an object's position and speed is its velocity.It is the distance that an object travels in one unit of time.The displacement of the item in one unit of time is the definition of velocity.
what is the maximum height reached by the ball?Smax = 400 feet.
c) v = 32 ft/s
c) v = - 32 ft/s
(a)
The following is the function provided for ball height:
s = 160 t - 16 t²
Therefore, we must take the derivative with respect to t and make it equal to zero in order to get the time to reach maximum height (in-flexion point):
So, 160 - 32 t = 0, 32 t = 160 t, and 160/32 t = 5 sec.
As a result, the maximum distance is covered every 5 seconds.
Smax = (160)(5) - (16)(5)²
Smax = 800 - 400
Smax=400 feet
b)First, we determine the speed at which the ball travels 384 feet.
384 = 160 t - 16 t
16 t² - 160 t + 384 = 0
Quadratic Equation Solving:
Either:
t = 6 sec
or t = 4 seconds
Since it takes 5 seconds to reach the highest point,
t then equals 5 seconds.
t then equals 4 seconds.
Now, by taking a derivative of ods with respect to t at 4 sec, we can find velocity:
v = 160 - 32 t
v = 160 - (32)(4)
v = 32 ft/s
c,Because t = 6 s > 5 s
The second number of t = 6 sec must represent the point in the ball's downward motion when it is 384 feet above the earth.
So, at that moment, velocity will be:
v = 160 - (32)(6)
v = -32 ft/s
downward motion is a bad sign.
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A tow truck is pulling 25,000 kg van with a tow hook that meets the van at an angle of 30° with the ground. How much force must the tow trucl use to pull the van with an initial acceleration of 3m/s2...!?
Answer:
86605.08 N
Explanation:
The equation to calculate the force is:
Force = mass * acceleration
The force and the acceleration does not have the same direction in this case, so we need to decompose the force into its horizontal component, which is the force that will generate the horizontal acceleration:
Force_x = Force * cos(30)
Then, we have that:
Force_x = mass * acceleration
Force * cos(30) = 25000 * 3
Force * 0.866 = 75000
Force = 75000 / 0.866 = 86605.08 N
Suppose that the system were placed in an elevator that accelerates downward at 2 m/s2. What would the scale read?.
The reading on the scale when the system is placed on elevator accelerating downward is 7.8m (N).
The given parameter
downward acceleration, a = 2 m/s²The reading on the scale is determined by applying Newton's second law of motion;
R = mg - ma
R = m(g - a)
R = m(9.8 - 2)
R = 7.8 m. (N)
where;
m is the mass of the systemThus, the reading on the scale when the system is placed on elevator accelerating downward is 7.8m (N).
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The onset of anorexia typically occurs in:
a. childhood
b. adolescence
c. early adulthood
d. middle adulthood
Anorexia usually appears during option b, adolescence.
Anorexia is an eating disorder that is the trait of chronic dietary restrictions which result into extremely ow body weight and a very distorted body image.
As per the studies say, 12-18 years is the age when we observe anorexia in kids. Individuals go through a variety of physical, emotional, and social changes during this time, which might lead to the development of the condition.
Also, during the adolescence, pressures like maintaining a particular type of standard can also increase anorexia. As a result, early detection and treatment are critical for preventing the disorder's progression and improving results.
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The maximum speed of a child on a swing is 6 m/s. What is the
maximum height of the child on the swing relative to her lowest
height on the swing?
The maximum height of the child on the swing relative to her lowest height is determined by the conservation of mechanical energy, where the maximum height can be calculated using the maximum speed. Hence, the maximum height of the child on the swing relative to her lowest height is approximately 1.84 meters.
When a child is on a swing, the total mechanical energy is conserved, assuming negligible air resistance. The mechanical energy is the sum of the kinetic energy (KE) and the potential energy (PE). At the highest point of the swing, the kinetic energy is zero, as the child comes to a momentary stop before changing direction. At the lowest point of the swing, the potential energy is zero, as it is fully converted into kinetic energy.
Since the maximum speed is given as 6 m/s, this represents the maximum kinetic energy of the child on the swing. At the highest point, all the kinetic energy is converted into potential energy. Therefore, the maximum height can be calculated using the conservation of energy equation:
KE_max = PE_max
1/2 mv^2 = mgh_max
Simplifying the equation, we can solve for h_max:
h_max = (v^2) / (2g)
Substituting the given values, where v = 6 m/s and g is the acceleration due to gravity (approximately 9.8 m/s^2), we can calculate the maximum height:
h_max = (6^2) / (2 * 9.8) ≈ 1.84 meters
Therefore, the maximum height of the child on the swing relative to her lowest height is approximately 1.84 meters.
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One forecasting model was used to forecast demand for a product. The forecasts and the demand are shown in the table below. B Actual Forecast 11 40 41 35 38 3 38 35 33 30 IX Calculate Moan Absolute Deviation (MAD) and Mean Squared Error (MSE). Show all details and use 1 decimal in your answer For the toolbar, press ALT+F10 (PC) or ALT+FN-F10 (Mac). BI V S Paragraph Arial 14px V QUESTION 1 The department manager is using a combination of methods to forecast sales of tonsters at a local department store. The demanders shown in the be Week Actu Demand 11 24 bo 2 bas x III A Using trend projection, calculate foresting values for week and week & Show details of your answer For the toolbar, pro ALT.F10 PC) O ALT.FN.F10 Mac BIS Paragraph Arial 14 Focus Chile we state
The estimated demand for Week 4 is 36.3
MAD(Mean Absolute Deviation) is used to calculate the average difference between forecast values and actual values. It calculates the deviation by taking the absolute value of the difference between actual and forecasted demand. The formula to calculate Mean Absolute Deviation is:
MAD= Sum of| Actual demand - Forecast demand | / number of periods
In the given table, the Actual demand is shown as B and the forecast demand is shown as F.
B Actual Forecast 11 40 41 35 38 3 38 35 33 30
Calculation of MAD:
Actual (B) Forecast (F) |B-F|11 40 29.041 35 5.043 38 0.053 3 35.054 38 3.055 35 0.056 33 3.057 30 3.058 0.0 30.0Total 103.0
The number of periods is 9 as shown in the table.
MAD= 103/9MAD= 11.44
Mean Squared Error (MSE) measures the average squared difference between the actual and forecasted values. The formula for MSE is:
MSE= Sum of (Actual demand - Forecast demand)^2 / number of periods.
Calculation of MSE:
Actual (B) Forecast (F) (B-F)^2 11 40 841 35 25 625 38 0 0 3 35 484 38 0 0 35 33 4 30 0 900Total 2854
The number of periods is 9 as shown in the table.
MSE= 2854/9MSE= 317.1
Therefore, the calculated MAD is 11.44 and MSE is 317.1.
Trend Projection formula is given by:
Y = a + bx
where Y is the estimated demand for a particular period.
a is the Y-intercept
b is the slope of the regression line x is the period number
In the given table, the Week number is shown as X and the Actual demand is shown as Y.
Week number Actual Demand 11 24 22 29
Using trend projection for Week 3, we can calculate the demand as follows:
Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*22 - 1*24)/(2*3 - 1*1) = 20/5 = 4
Intercept (a) = Σy/n - b(Σx/n) =(24+22)/2 - 4(2/2) = 23Y = a + bx = 23 + 4(3) = 35
Therefore, the estimated demand for Week 3 is 35.
Using trend projection for Week 4, we can calculate the demand as follows:
Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*29 - 1*24)/(2*5 - 1*1) = 34/9 = 3.78
Intercept (a) = Σy/n - b(Σx/n) =(24+22+29)/3 - 3.78(2.0) = 21.5Y = a + bx = 21.5 + 3.78(4) = 36.3
Therefore, the estimated demand for Week 4 is 36.3.
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How much gravitational force attracts a ball weighing 300 kilograms ?
Given that,
Mass of a ball = 300 kg
To find,
The gravitational force acting on the ball.
Solution,
The force acting on the ball is force of gravity. It is equal to the weight of the ball.
W = mg
Substitute the value of m and g in the above formula
W = 300 kg × 10 m/s²
= 3000 N
Therefore, the ball attracts with a force of 3000 N.
part b what is the direction of this potential difference? that is, does the potential increase or decrease along the direction of the current?
To maintain the original flux, induced current is in the direction of original current. Hence, potential difference will increase in the direction of current.
Does potential decrease or increase in the direction of current?In the direction of the electric field, electric potential decreases because electric potential is the work done against the direction of electric field.
The direction of an electric current is the direction in which a positive charge would move and electric current flows from higher to lower electric potential.
If a charge is moving in the direction that it would normally move, then its electric potential energy is decreasing. If a charge is moved in a direction opposite to that it would normally move, then its electric potential energy is increasing.
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what is the value of acceleration due to gravity at the pole, equator and the centre of the earth
Answer:
In combination, the equatorial bulge and the effects of the surface centrifugal force due to rotation mean that sea-level gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles, so an object will weigh approximately 0.5% more at the poles than at the Equator.
Astronomers were at first surprised to find complicated molecules in the interstellar medium. They thought ultra-violet light from stars would break apart such molecules. What protects the molecules we observe from being broken apart
Answer:
The dust present in the clouds.
Explanation:
The complicated composition molecules that can be found in space are generally associated with clouds of dust. The significant amount of dust in these clouds provides protection not only for these molecules, but for any body that makes up or is associated with dust clouds.
It is exactly this dust that protects the molecules against the action of ultraviolet rays.
if two vehicles are identical, except for one weighing twice as much as the other vehicle, and they roll down a hill, which car reaches the bottom first?
The heavier car descends first because its rotational inertia (wheels) account for a greater proportion of its mass.
Will a car with double the mass accelerate more quickly or slower?The roller coaster car's mass is unrelated to speed, so doubling the mass would have no impact on the speed of the vehicle. The car with twice the mass will therefore travel at the same speed from top to bottom.
What decides if one car in a collision with another has greater momentum than the other?The momentum of an object in motion is calculated by dividing its mass by its speed. An item has a lot of momentum if its mass or speed is greater than 1. A fast-moving car has more momentum than a slow-moving one because they have the same mass.
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how far do you have to descend in air to experience the same increase in pressure as descending 10ft deep in water?
We have to descend 33 feet in air to experience the same increase in pressure.
The pressure exerted by water on a unit surface area is known as hydrostatic pressure. The pressure varies with the depth of water. For every 33 feet of depth which is equal to 10 meters, the hydrostatic pressure increases by 1 atmosphere (atm).
There are many animals that live in the greater hydrostatic pressure such as - whales they can withstand thousands atmosphere of pressure. Going deeper into the water ca cause some problems such as blocking of ear drums, squeezing of lungs, feeling a heavy load on chest and etc.
The divers face these consequences while they go deep into the ocean. The pressure increases and they feel their ear getting blocked.
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average velocity of 6 km/h. How many kilometers can she walk in three hours?
Answer:
18 km
Explanation:
. Una varilla de cobre de coeficiente de dilatación 1,4*10-5 °C -1 , tiene una longitud de 1.20 metros a una temperatura ambiente de 18 ˚C . ¿Cuál sera su longitud 100 ˚C
Answer:
La longitud de la varilla de cobre es de 1.201 metros a una temperatura de 100 °C.
Explanation:
Asumiendo que la varilla de cobre experimenta deformaciones muy pequeñas y que las deformaciones no longitudinales son despreciables con respecto a las deformaciones longitudinales, la deformación longitudinal de la varilla se estima mediante la siguiente fórmula:
\(l_{f} = l_{o}\cdot [1+\alpha \cdot (T_{f}-T_{o})]\) (1)
Donde:
\(l_{o}\) - Longitud inicial de la varilla, en metros.
\(\alpha\) - Coeficiente de dilatación, en \(^{\circ}C^{-1}\).
\(T_{o}\) - Temperatura inicial de la varilla, en grados Celsius.
\(T_{f}\) - Temperatura final de la varilla, en grados Celsius.
Si sabemos que \(l_{o} = 1.20\,m\), \(\alpha = 1.4\times 10^{-5}\,^{\circ}C^{-1}\), \(T_{o} = 18\,^{\circ}C\) y \(T_{f} = 100\,^{\circ}C\), entonces la longitud final de la varilla es:
\(l_{f} = (1.20\,m)\cdot \left[1 + \left(1.4\times 10^{-5}\,^{\circ}C^{-1}\right)\cdot (100\,^{\circ}C-18\,^{\circ}C)\right]\)
\(l_{f} = 1.201\,m\)
La longitud de la varilla de cobre es de 1.201 metros a una temperatura de 100 °C.
Select an item that is common in our society that you believe is elastic and, using two determinants of elasticity (pages 133-134), briefly explain why you believe this product is elastic.
Select an item that is common in our society that you believe is inelastic and, using two determinants of elasticity (pages 133-134), briefly explain why you believe this product is inelastic. Expectations are a minimum of one paragraph (4 to 5 sentences) for each question in the initial post.
There are no immediate substitutes for gasoline as public transportation is often limited and walking, biking, or taking a cab is not always feasible. Therefore, people may continue to purchase gasoline despite an increase in price.
One item that is common in our society that I believe is elastic is fast food. Elasticity is the degree to which changes in price affect demand for a good or service.
Fast food is elastic because it has many substitutes such as restaurants, home-cooked meals, and even other fast-food chains. Fast food is also highly responsive to price changes, which means that a small change in price can cause a large change in demand.
For example, a $1 price increase for a burger meal at a fast-food chain might cause many people to switch to a competitor with a cheaper price. Thus, fast food is an elastic product in our society.One item that is common in our society that I believe is inelastic is gasoline.
Gasoline is an inelastic product because it has few substitutes and people need it for transportation. If the price of gasoline increases, people may continue to purchase it even if it means spending more money because there are few alternative options.
Additionally, there are no immediate substitutes for gasoline as public transportation is often limited and walking, biking, or taking a cab is not always feasible.
Therefore, people may continue to purchase gasoline despite an increase in price.
For example, if the price of gasoline increases by $1, a consumer will still purchase gasoline because they require it to get to work or school. Thus, gasoline is an inelastic product in our society.
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One item in our society that I believe is elastic is the price of gasoline because of various alternatives to gasoline and the proportion of income spent. An item in our society that I believe is inelastic is medical treatment because of the necessity of medical treatment and lack of substitutes.
Firstly, the availability of substitutes contributes to the elasticity of gasoline. In our society, there are various alternatives to gasoline, such as electric vehicles or public transportation. When the price of gasoline increases, consumers have the option to switch to these substitutes, reducing their demand for gasoline. Conversely, when the price of gasoline decreases, consumers may choose to drive more or purchase larger vehicles, increasing their demand for gasoline. This flexibility in consumer choices demonstrates the elasticity of gasoline.
Secondly, the proportion of income spent on the product also influences the elasticity of gasoline. For many individuals, the cost of gasoline represents a significant portion of their overall budget. When the price of gasoline rises, consumers may have to make adjustments to their spending habits or seek alternative means of transportation to cope with the higher expenses. Conversely, when the price of gasoline decreases, consumers may have more disposable income to spend on other goods and services. This sensitivity to price changes further supports the elasticity of gasoline.
On the other hand, an item in our society that I believe is inelastic is medical treatment. Two determinants of elasticity that contribute to this belief are the necessity of the product and the lack of substitutes.
Firstly, the necessity of medical treatment makes it an inelastic product. When individuals require medical treatment, they often have no choice but to seek the necessary healthcare services regardless of the price. This is especially true for life-saving procedures or medications. The demand for medical treatment is driven by the urgency and importance of preserving one's health, which leads to a less responsive consumer behavior to price changes.
Secondly, the lack of substitutes also contributes to the inelasticity of medical treatment. In many cases, there are limited alternatives or substitutes available for specific medical treatments. For example, if a person requires a specific surgery or medication to treat a condition, they cannot easily switch to a different treatment option to lower their expenses. The lack of viable substitutes reduces consumer choice and makes the demand for medical treatment less responsive to changes in price.
In summary, the price of gasoline is elastic due to the availability of substitutes and the proportion of income spent on the product. On the other hand, medical treatment is inelastic due to its necessity and the lack of substitutes. These determinants of elasticity highlight the different levels of responsiveness to price changes in these two common items in our society.
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Describe how magma changes form through the rock cycle to become magma again eventually.
The process by which magma changes form through the rock cycle to become magma again eventually is described in the following steps:
magma is formed from the melting of rocksmagma solidifies to form igneous rocks.igneous rocks undergo weathering forming sedimentthe sediment is compacted to form sedimentary rocksthe sedimentary rocks become metamorphic rocksthe metamorphic rocks melt to form magmaWhat is the rock cycle?The rock cycle refers to the process by which the three main types of rocks—igneous, metamorphic, and sedimentary—are formed and decomposed according to various applications of heat and pressure over time.
For instance, when heat and pressure are applied to sedimentary rock shale, slate is formed.
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After measurements or observations are made in a scientific investigation, it is most appropriate to
A.
formulate a hypothesis.
B.
draw a conclusion.
C.
organize the data in a chart or table.
D.
propose a new scientific question.
Answer:
The real answer is C : organize the data in a chart or a table.
Can anyone please help
a) The motion of the object between 15 s to 30 s is increasing velocity, to a constant velocity and finally a decreasing velocity.
(b) The average velocity of the object between 0 and 15 seconds is 0.167 m/s.
(c) The position of the object at 5.0 seconds is 0.5 m.
(d) Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.
What is the motion of the object?(a) The motion of the object between 15 s to 30 s can be described as increasing velocity, to a constant velocity and finally a decreasing velocity.
(b) The average velocity of the object between 0 and 15 seconds is calculated as;
average velocity = total displacement / total time
average velocity = (2.5 m - 0 m ) / ( 15 s - 0 s ) = 0.167 m/s
(c) The position of the object at 5.0 seconds is calculated as follows;
at 5.0 seconds, the position of the object is traced from the graph as 0.5 m.
(d) The motion of the object between 30 and 40 seconds is calculated as;
velocity = ( 0 m - 4 m ) / ( 40 s - 30 s ) = - 0.4 m/s
Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.
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A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2. What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2 . What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
–1.6 × 103 N
–1.63 × 103 N
–2.4 × 103 N
–5.27 × 104 N
The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N
How do I determine the gravitational force?The gravitaional force between two objects can be obtained by using the following formula:
F = GM₁M₂ / r²
Where
F is the gravitaional force G is the gravitational constant M₁ and M₂ are the masses of the objects r is the distance apartThe following data were obtained from he question:
Mass of satellite (M₁) = 5400 = 5.4×10³ KgHeight (h) = 30000 km = 30000 × 1000 = 30000000 mMass of Earth (M₂) = 6.0×10²⁴ KgRadius of Earth (R) = 6400 km = 6400 × 1000 = 6400000 mDistance apart (r) = R + h = 6400000 + 30000000 = 36400000 mGravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²Gravitational force (F) =?The gravitaional force can be obtained as shown below:
F = GM₁M₂ / r²
F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²
F = 1.63×10³ N
Thus, the gravitational force is 1.63×10³ N
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can you draw an equipotential surface through a position where the electric field vanishes? select the correct answer and explanation.
No. Calculating the potential is difficult if the electric field disappears. Drawing an equipotential surface in this situation is therefore impossible.
What is the position where the electric field vanishes?Any sort of charge causes an electric field to be associated to a location in space. The strength and direction of the electric field are expressed by the value of E, also referred to as the electric field strength, electric field intensity, or simply the electric field.
The field lines never cross each other. The surface of the charge is parallel to the field lines. The number of field lines and the charge's magnitude are inversely correlated.
Fields at the centre will be equal and opposite because they will have the same charges at the opposite two corners. The centre will have a zero net field.
Therefore, A positive point charge is pointed straight away by the electric field, and a negative point charge is pointed directly in.
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Which of the following are examples of etiquette? Check all of the boxes that apply.
prioritizing tasks
writing a note about a patient’s medical condition
following an employer’s dress code
following a company’s policy of addressing patients by their last names
Answer:
C& D
Explanation:
ON EDG2020
Answer: Its C and D
Explanation:
edge
The signal g(t) = 8 cos(400πt) cos(200, 000πt) + 18 cos(200, 000nt) is applied at the input of an ideal bandpass filter with unit gain and a bandwidth of 200 Hz centered at 100, 200 Hz. Sketch the amplitude spectrum of the signal at the output of the filter.
An ideal bandpass filter with unit gain and a bandwidth of 200 Hz is applied to the input signal g(t) = 8 cos(400πt) cos(200,000πt) + 18 cos(200,000nt). The center frequency of the filter is 100,200 Hz. We can sketch the amplitude spectrum of the signal at the output of the filter using the following steps:
Step 1: Determine the Fourier transform of the input signal g(t)The Fourier transform of g(t) is given by: G(ω) = π[δ(ω + 2π × 200,000) + δ(ω - 2π × 200,000)] + π/2[δ(ω + 2π × 200) + δ(ω - 2π × 200)]
Step 2: Determine the transfer function of the bandpass filter
The transfer function of the ideal bandpass filter with unit gain and a bandwidth of 200 Hz centered at 100,200 Hz is given by: H(ω) = {1 for |ω - 2π × 100,200| < π × 100, and 0 otherwise}
Step 3: Multiply the Fourier transform of the input signal by the transfer function of the filter
The output of the filter is given by:
Y(ω) = G(ω)H(ω)The product of the Fourier transform of the input signal and the transfer function of the filter is shown in the figure below.
The given signal is a combination of two cosines, where the first cosine has a frequency of 400π radians/second and the second cosine has a frequency of 200,000π radians/second.
The output of the filter is a bandpass signal with a center frequency of 100,200 Hz and a bandwidth of 200 Hz. The amplitude spectrum of the output signal is zero outside the bandpass region and is equal to the product of the amplitude spectrum of the input signal and the frequency response of the filter within the passband region.
The amplitude spectrum of the output signal is shown in the figure below:
Therefore, the amplitude spectrum of the signal at the output of the filter is a bandpass signal with a center frequency of 100,200 Hz and a bandwidth of 200 Hz. The amplitude of the signal within the passband region is given by the product of the amplitude of the input signal and the frequency response of the filter within the passband region.
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The rarest type of stars are A. stars that are about 1 solar mass. B. stars that are more than 50 solar masses. C. stars that are about 10 solar masses. D. stars that are about 0.5 solar mass.
The rarest type of stars is those that are more than 50 solar masses.
How are stars categorized?
Stars are categorized on the basis of mass, spectral behavior, and temperature.
There are 7 spectral types of stars:
O-type (Blue) stars have more than 50 times the solar mass of the sun and are the rarest main sequence stars present in the universe. Their abundance is merely 0.000001% of known stars.Thus, the rarest type of stars are the O-type stars that have more than 50 times the solar mass of the sun.
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What is produced by AC and DC generators?
A. mechanical energy
B. chemical energy
C. electrical energy
Answer:
I'm positive the Answer to this would be C :)
Which part of the following graph shows the object going at the fastest speed?
Distance
5
4-
in km
2-
1-
A А
0
6 5 10 15 20 25 30 35 40 45
Time in minutes
O Ato B
B to C
C to D
A to B and C to D are going equal speeds
Answer:
more point plzzzzz... eeeeeeeee
A to B in the graph shows the object going at the fastest speed.
In a distance-time graph, the gradient of the line is equal to the speed of the object. The greater the gradient (and the steeper the line) the faster the object is moving.
What is speed ?"The rate of change of position of an object in any direction. Speed is measured as the ratio of distance to the time in which the distance was covered. Speed is a scalar quantity as it has only direction and no magnitude."
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A force of 0.8n stretches an elastic spring by 2cm. find the elastic constant of the spring
The elastic constant of the spring can be calculated by dividing the force applied to the spring by the displacement it undergoes. In this case, a force of 0.8 N stretches the spring by 2 cm.
The elastic constant, also known as the spring constant or stiffness, represents the measure of the stiffness of a spring. It relates the force applied to the spring to the displacement it undergoes. The formula for calculating the elastic constant is:
Elastic constant (k) = Force (F) / Displacement (x)
In this case, the force applied to the spring is 0.8 N, and the displacement is 2 cm (which is equivalent to 0.02 m). Substituting these values into the formula, we can calculate the elastic constant:
k = 0.8 N / 0.02 m
= 40 N/m
Therefore, the elastic constant of the spring is 40 N/m. This means that for every meter the spring is stretched or compressed, it exerts a force of 40 N. The elastic constant provides a measure of the spring's resistance to deformation and is a fundamental parameter in studying the behavior of springs and elastic materials.
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A __________ is an abnormal crackling, rattling, or bubbling sound heard on auscultation of the chest.
A __rales ________ is an abnormal crackling, rattling, or bubbling sound heard on auscultation of the chest.
What are rales ?
Rales are an abnormal sound heard accompanying the normal respiratory sounds on auscultation of the chest
Rales heard over the lung bases are a sign of of heart failure that is of at least moderate severity. With acute pulmonary edema, rales are frequently accompanied by wheezing and expectoration of frothy, blood-tinged sputum.
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describe the set of all b for which axequalsb does have a solution.
The set of all possible values for vector b, denoted as \(\(\mathbb{R}^m\)\), for which the equation Ax = b has a solution depends on the properties of the matrix A. Specifically, the equation has a solution if and only if b belongs to the column space of A.
Let's consider a system of linear equations represented by the matrix equation Ax = b, where A is an \(\(m \times n\)\) matrix, x is an \(\(n \times 1\)\) column vector, and b is an \(\(m \times 1\)\) column vector. The equation Ax = b can be interpreted as a linear combination of the columns of A, where the coefficients are given by the entries of x.
The equation Ax = b has a solution if and only if b can be expressed as a linear combination of the columns of A. In other words, b must belong to the column space of A. The column space of A is the set of all possible linear combinations of the columns of A. Geometrically, it represents the subspace spanned by the columns of A.
If b does not belong to the column space of A, then there is no solution to the equation Ax = b. This occurs when b lies outside the subspace spanned by the columns of A. On the other hand, if b does belong to the column space of A, then there exists at least one solution to the equation Ax = b. This occurs when b lies within the subspace spanned by the columns of A.
Therefore, the set of all possible values for vector b, denoted as \(\(\mathbb{R}^m\)\), for which the equation Ax = b has a solution is the column space of A.
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Areas that reflect light well are called
Answer:
specular reflection
Explanation:
Explain using Newton's Third Law of Motion, how starting blocks have helped lower times in track events.