Matthew records the temperature outside for one day. From 10:00 a.m. to 12:00 p.m., the
temperature rises 4°C. From 12:00 p.m. to 2:00 p.m., it rises another 3°C. From 2:00 p.m. to 4:00
p.m., it drops 2°C. Which of the following predictions about how the temperature will change
between 4:00 p.m. and 6:00 pm. is most reasonable?
The temperature will rise 3°C.
The temperature will drop 14°C.
o the temperature will stay the same
The temperature will drop 4°C.

Answer:

A. its reactivity

Explanation:

It's reactivity because copper was exposed to air and if it is reactivity it must be exposed to air

Answer:

A.  reactivity

Explanation:

Answer:

its 210

Explanation:

Just add all atomic mass used in the formula together: 2*(14+16*3)+88= 2*62+88=124+88=210

Hope this was helpful

The relative formula mass of strontium nitrate Sr(NO₃)₂ is 210

The relative atomic masses of N, O and Sr are 14,16 and 88 respectively.

In calculating the relative atomic mass of an element with isotopes, the relative mass and proportion of each is taken into account. Adding the atomic masses together gives the relative formula mass of a compound

So, relative atomic mass of Sr(NO₃)₂ is calculated as

88+ 2(14+16×3) = 210

The atomic mass constant (symbol: mu) is defined as being 1/12 th of the mass of a carbon-12 atom. Since both quantities in the ratio are masses, the resulting value is dimensionless; hence the value is said to be relative atomic mass.

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Answer: C) gradually increases

Explanation:

Across a period (horizontal row) in the periodic table, the number of protons and electrons in an atom increases while the shielding effect remains constant. As a result, the positively charged nucleus exerts a stronger pull on the negatively charged electrons in the electron cloud, causing the atomic radius to decrease. This trend is known as the "electron shielding effect."

Therefore, the increased pull of an atom's nucleus on the electron cloud gradually increases across a period.

Answer:

\({ \rm{5CaC _{2}O _{4(aq)}+ 2KMnO _{4(aq)} + 8H _{2} SO _{4(aq)} → 5CaSO _{4(s)}+ 2Mn SO _{4(aq)}+ K _{2} SO _{4(s)} + 10CO _{2(g)} + 8H _{2} O _{l} }}\)

Explanation:

This is a redox reaction formed by combining two half equations.

Check the image above, sorry if my handwriting is poor :(

Answer:

After the Peloponnesian War, a period of political and economic unrest ensued in the Greek city-states as disagreements about the post-war settlement divided the cities. The war itself had caused considerable damage to infrastructure and disrupted trade networks, which had a further destabilizing effect on the region. The post-war chaos did eventually lead to the rise of Macedonian power in the fourth century BCE, however, resulting in the unification of the Greek city-states under the rule of Phillip II of Macedon.

Option 1 is correct compound. 2-bromopentanal and pentanal do not have alpha-hydrogens and therefore cannot undergo aldol addition reaction in aqueous sodium hydroxide.

Out of the given options, only 2-methyl pentanal and 3-chloropentanal can undergo aldol addition reaction in the presence of aqueous sodium hydroxide. This is because both of these compounds have alpha-hydrogens (hydrogens attached to the carbon adjacent to the carbonyl group), which are necessary for the aldol reaction to occur.

Aldol condensations play an important role in the creation of organic compounds because they provide a dependable way to create carbon-carbon bonds. For instance, the Robinson annulation reaction sequence results in aldol condensation, and the Wieland-Miescher ketone product is an essential component in a variety of chemical synthesis processes.

In the aldol reaction between 2-bromopentanal pentanal  and a 2-methyl pentanal, the mechanism for the aldol addition product and the aldol condensation product is described .

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The complete question is

select the compound(s) can undergo an aldol addition reaction in the presence of aqueous sodium hydroxide? options: 1. ,2-bromopentanal pentanal option 2.  2-methyl pentanal option 3. 3-chloropentanal

10 moles of an ideal gas are compressed isothermally and reversibly from a pressure of 1 atm to 10 atm at 300 K. a. 11.3 kJ work is done on the gas. b. There is no heat evolved in this process, the temperature remains constant. c. There is no change in the internal energy of the gas.

a. The expression for work done on the gas is

W = nRTln(Vf/Vi).

Here, n = 10 moles, R = 8.31 J/mol K, T = 300 K, P1 = 1 atm, P2 = 10 atm.

The volume of the gas

V = nRT/P.W

= nRT ln(Vf/Vi)

= 10 × 8.31 × 300 × ln(1/10)

= 10 × 8.31 × 300 × (-2.303)≈ 11.3 kJ

b. Since the process is isothermal, the temperature remains constant at 300 K. Hence,

Q = W = - 11.3 kJ (as the work is done on the gas)

c. As the process is reversible, it follows the first law of thermodynamics which is ΔU = Q + W.

So,

ΔU = Q + W= - 11.3 kJ + 11.3 kJ= 0 kJ.

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I believe the ans is (2) pH = 7.

Explanation:

At the equivalence point, the salt of strong acid and strong base is completely hydrolyzed which gives a neutral solution with pH 7 as H+ ion concentration is equal to OH- ion concentration.

KBr has a Van't Hoff factor of 1.63.

The formula for freezing point reduction brought on by a solute is as follows:

ΔT = Kf×m×i

Where T is the shift in freezing point, Kf is the solvent X's freezing point depression constant, m is the solution's molality (mol/kg), and I is the Van't Hoff factor

Molar masses of 177g of alanine (89.09g/mol) are:

1mol / 89.09g times 177g equals 1.99 moles. In 0.800kg:

1.9 mol/0.8 kilo = 2.49 m

In the freezing point depression formula, replace:

5.9°C = Kf×2.49m×1

The Van't Hoff factor for alinine is 1.

The solvent's Kf is as follows:

2.37 °C/m

The 177.0g of KBr solution has the following molality (molar mass: 119g/mol):

1mol/119g times 177.0g gives 1.487 moles/0.800kg and 1.859m respectively.

The freezing point depression equation is as follows:

7.2°C = 2.37°C/m×1.859m×i

1.63 = I

The complete question is:

When 177. g of alanine (C3H7NO2) are dissolved in 800.0 g of a certain mystery liquid X, the freezing point of the solution is 5.9 °C lower than the freezing point of pure X. On the other hand, when 177.0 g of potassium bromide are dissolved in Van't Hoff factor the same mass of X, the freezing point of the solution is 7.2 °C lower than the freezing point of pure X. Calculate the van't Hoff factor for potassium bromide in X. Be sure your answer has a unit symbol, if necessary, and is rounded to the correct number of significant digits.

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Answer:

C. The balloon with CH4 has the same moles of gas molecules as the balloon with H2

Explanation:

Based on combined gas law, gases under the same pressure, temperature and volume have the same number of moles. With this information we can say the rigth statement is:

Buffer ability of an acidic buffer is most while the attention of salt and acid are equal. Once the buffering ability is passed the price of pH alternate speedy jumps.

This takes place due to the fact the conjugate acid or base has been depleted through neutralization. This precept means that a bigger quantity of conjugate acid or base could have a extra buffering ability. Maximum buffer ability method that the answer resists adjustments in pH the maximum at this pH. A buffer has the best resistance to pH alternate while the pH = pKa.

This graph suggests the buffering place that is at its most withinside the region in which pH = pKa.

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Yes, hexane and diethyl ether, a solvent pair, will definitely function as a team during crystallization.

This is due to the fact that crystal formation requires a miscible solvent pair. Normally, two solvents—one in which the compound is soluble and one in which it is not—are required for crystallization. Additionally, these two solvents ought to mix easily.

Hexane and diethyl ether, the given solvent pair, are miscible with one another. Therefore, we can crystallize using the solvent pair mentioned above.

What is crystallization?

Crystallization is the process of increasing the concentration of a solution to a supersaturated state in order to form solid particles in a homogeneous phase. Crystallization is the process by which crystals are formed from either melted material or a solution.

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Answer:

I will say D. Sulfuric Acid

Explanation:

An acid turns blue litmus paper red and a base turns red litmus paper blue.

Brainliest please! I am so close to getting my next rating! I would really appreciate it, and it would make my day! Thank you so much, and have a wonderful rest of your day!

Answer:

Explanation:

all bases

Answer:

In cold water, the food coloring diffuses (spreads out) through the water slowly. The hot water causes the food coloring to diffuse faster.

Explanation:

Explanation:

First, we need to know that Calcium oxide is:

CaO.

Molar mass of it is:

Ca = 40 g/mol

O = 16 g/mol

CaO = 56 g/mol

To discover the number in moles of 5.45 g of CaO we just need to use the following formula:

n = m/MM

m = 5.45

MM = 56 g/mol

n = 5.45/56

n = 0.09732 moles

Answer:

0.09732 moles

Answer:

Decane doesn't have any free electrons because all the electrons of carbon is used for bonding.

Answer:like my photo bc i like it

Explanation:

omg i look .........................................  

The density of CO2 gas at STP conditions is 1.8926 g/L if 2.50 g of CO2 occupies 5.60 L at 789 torr. This calculation was done using the ideal gas law and the formula ρ = m / V.

Given conditions:

Mass (m) = 2.50 g

Volume (V) = 5.60 L

Pressure (P) = 789 torr

Standard Temperature and Pressure (STP) conditions:

Temperature (T) = 273.15 K (0°C)

Pressure (P) = 1 atm (760 torr)

Molar mass of CO2 = 44.01 g/mol

Using the ideal gas law (PV = nRT), we can calculate the number of moles of CO2:

n = m / MM

n = 2.50 g / 44.01 g/mol

n = 0.0568 mol

Using the ideal gas law again, we can calculate the volume at STP:

V = nRT / P

V = (0.0568 mol x 0.08206 L atm / mol K x 273.15 K) / (1 atm)

V = 1.3219 L

Now, we can find the density of CO2 at STP:

ρ = m / V

ρ = 2.50 g / 1.3219 L

ρ = 1.8926 g/L

Therefore, the density of CO2 gas at STP conditions is 1.8926 g/L if 2.50 g of CO2 occupies 5.60 L at 789 torr. This calculation was done using the ideal gas law and the formula ρ = m / V.

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As the volume of  the sound is seen to increase, the sound that we hear is louder as the amplitude of the sound increases.

Sound is a kind of wave that moves through a medium. We know that sound has to move via several compressions and rare factions. This implies that sound is as well propagated through air. The movement of the sound waves through air is because the air is set into vibration by the sound. Thus, the air is very imprtant in the movement of the sound waves.

With this much said, we can see that if there is more air, there would more molecules that can be set into vibration and the sound wave would tend to increase and that is the deal that we are trying to communicate here.

Thus, the amplitude of air increases as the volume of  the sound gets higher and the sound that we hear is much louder.

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Answer:

yes

Explanation:

the element is in group 2

The sequence represents the portion of the protein molecule coded for by the mRNA sequence is Leucine-lysine-cysteines phenylalanine. The correct option is c.

The order of amino acids in a protein from the N-terminus (methionine) to the C-terminus is specified by mRNA codons, which are read from 5' to 3'. 5'-AUGAUCUCGUAA-5' is the mRNA sequence.

The mRNA interacts with a specialized complex known as a ribosome, which "reads" the mRNA nucleotide sequence. A codon is a three-nucleotide sequence that normally codes for one amino acid.

Therefore, the correct option is c, Leucine-lysine-cysteines phenylalanine.

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The question is incomplete. Your most probably complete question is given below:

threonine-lysine-leucine-serine

arginine lysine leucine cystiene

Leucine-lysine-cysteines phenylalanine

Cisteine phenylalanine glutamic acid serine.

Answer:

thermal shock

Explanation:

the temperatures inside the glass jar should have continued to increase over time. Internal stresses due to uneven heating. This is also known as “thermal shock”.

In general, the thicker the glass, the more prone it will be to breaking due to the immediate differences in temperature across the thickness of glass.

Borosilicate glass is more tolerant of this, as it has a higher elasticity than standard silicon glass.

You may also note that laboratory test tubes and flasks are made with thinner walls, and of borosilicate glass, when designated for heating.

Answer:

B. to counteract the sourness of the acids

Explanation:

Edge:) Good luck!

Answer:

B. to counteract the sourness of the acids

Explanation:

B. to counteract the sourness of the acids

Hydrogen bonds exist in the water molecule below.

Only molecules in which hydrogen is covalently bound to either fluorine, oxygen, or nitrogen experience hydrogen bonding. These three elements are sufficiently electronegative that they remove the majority of the electron density from the hydrogen atom's covalent link, leaving the latter atom with an extremely low electron density.

A hydrogen atom that is connected to an electronegative atom moves toward another electronegative atom nearby to form hydrogen bonds, which are potent intermolecular forces. The hydrogen-bond strength will rise as the hydrogen bond acceptor's electronegativity increases.

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Answer: Why exacly am i a rat

Explanation:

,....

but thanks

Answer:

what!!!??????

An electron with a negative energy is attached to the nucleus by the attraction between its opposing charges. The closer it is to the nucleus, the more closely connected it is. The farther an electron is from the nucleus, the greater its energy. The correct option is B.

The electron's energy grows as it goes away from the nucleus and gets less and less negative. When the electron is not subject to the nucleus's attracting Coulomb attraction, it has zero potential energy and only kinetic energy, which is always positive. The electron has greater energy the further it travels.

On the other hand, the nucleus's weak forces of attraction hold electrons that are moving away from it.

Thus the correct option is B.

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The reaction equations for acetic acid-acetate buffer reacting with an acid and a base are as follows:
Reaction with Acid:
\(CH_{3} COOH\) + HX → \(CH_{3} COOH\)  + \(X^{-}\)  + \(H^{+}\)
Reaction with Base:
\(CH_{3} COOH\)  + YOH → \(CH_{3}COO ^{-}\) + \(Y^{+}\) + \(H_{2}O\)

To explain how an acetic acid-acetate buffer reacts with an acid and a base, we can write the following reaction equations:

1. Reaction of the buffer with an acid:
Buffer: \(CH_{3} COOH\) (acetic acid) /  \(CH_{3}COO ^{-}\)  (acetate ion)
Acid: HX (general acid)

Reaction equation:
\(CH_{3}COO ^{-}\)  + HX → \(CH_{3} COOH\) +  \(X^{-}\)

In this reaction, the acetate ion (CH3COO-) reacts with the added acid (HX) to form acetic acid (CH3COOH) and the corresponding anion of the added acid ( \(X^{-}\)). This helps neutralize the added acid.

2. Reaction of the buffer with a base:
Buffer: \(CH_{3} COOH\) (acetic acid) /  \(CH_{3}COO ^{-}\)  (acetate ion)
Base: YOH (general base)

Reaction equation:
\(CH_{3} COOH\)+ YOH →  \(CH_{3}COO ^{-}\)  + \(H_{2}O\) + \(Y^{+}\)

In this reaction, acetic acid (\(CH_{3} COOH\)) reacts with the added base (YOH) to form acetate ion ( \(CH_{3}COO ^{-}\) ), water (\(H_{2}O\)), and the corresponding cation of the added base (\(Y^{+}\) ). This helps neutralize the added base.

In both cases, the acetic acid-acetate buffer is able to maintain the pH of the solution by reacting with added acids or bases.

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