-matrices- Use determinants to find the equation of the line passing through (12,4) and (4,19).

Step-by-step explanation:

3x squared -9 = 12

3x squared = 12 + 9

3x squared = 21

am i doing the wrong maths?

is it find what 3x squared is or....

The values of x and y are given as follows:

The geometric mean theorem states that the length of the altitude drawn from the right angle of a triangle to its hypotenuse is equal to the geometric mean of the lengths of the segments formed on the hypotenuse.

The bases for this problem are given as follows:

2 and x.

The altitude is given as follows:

6.

Hence the length x is given as follows:

2x = 6²

2x = 36

x = 18.

Applying the Pythagorean Theorem, the length y is given as follows:

y² = 18² + 6²

y² = 360

\(y = \sqrt{36 \times 10}\)

\(y = 6\sqrt{10}\)

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Answer:

4 yards per sheet and 8 sheets = 32 yards

Step-by-step explanation:

Answer:

8x4=32

So you get 32 yards for 8 sheets (or 96 feet)

The set of numbers that have 11 as a common factor is {154, 231}.

The number that divides two or more numbers is called a common factor.

Given are the pair of numbers as -

{154, 231}

{143, 221}

{33, 39}

{77, 91}

The pair of numbers with the common factor 11 is {154, 231}.

Therefore, the set of numbers that have 11 as a common factor is {154, 231}.

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Answer:

Step-by-step explanation:

it think it 23 becasue u add

1 divide it by 2

Answer:

Missing Angle = 26⁰ ( corresponding angles )

The difference between the selling price and the cost price is the profit he earned.

Profit = Selling Price - Cost Price

Profit = $216 - $180

Profit = $36

To find the percentage profit, we need to calculate what proportion of the cost price the profit represents, and express that as a percentage :

Percentage Profit = (Profit : Cost Price) * 100%

Percentage Profit = ($36 : $180) * 100%

Percentage Profit = 0.2 * 100%

Percentage Profit = 20%

Therefore, his percentage profit is 20%.

Check the picture below.

The sum of the first 97 terms of the arithmetic progression is 153761.

What is arithmetic progression?

Arithmetic progression (AP) is a sequence of numbers in which each term is obtained by adding a constant value (known as the common difference) to the previous term. In other words, an arithmetic progression is a sequence of numbers where each term is a fixed distance apart.

To find the sum of the first 97 terms of an arithmetic progression with the nth term given as 2 + n/3, we use the formula:

S_n = n/2 [2a + (n-1)d]

We first find the first term, a, by substituting n = 1 into the nth term equation to get a = 7/3. Then, we find the common difference, d, by subtracting the (n-1)th term from the nth term, which gives us d = n/3.

Substituting these values into the S_n formula, we get:

S_97 = 97/2 [2(7/3) + (97-1)(97/3)]

Simplifying this expression, we get:

S_97 = 47(14 + 96 × 97/3)

S_97 = 47(3263)

S_97 = 153761

Therefore, the sum of the first 97 terms of the arithmetic progression is 153761.

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when running a line, in a right-triangle, from the 90° angle perpendicular to its opposite side, we will end up with three similar triangles, one Small, one Medium and a containing Large one.  Check the picture below.

\(\cfrac{a}{18}=\cfrac{32}{a}\implies a^2=(32)(18)\implies a=\sqrt{(32)(18)}\implies a=24 \\\\[-0.35em] ~\dotfill\\\\ \cfrac{b}{50}=\cfrac{32}{b}\implies b^2=(32)(50)\implies b=\sqrt{(32)(50)}\implies b=40\)

Answer:

A'={5,0}

B'={2,0}

C'={2,4}

Step-by-step explanation:

The coordinates of the object triangle are;

A = {-3,0}

B= {0,4}

C={0,0}

The reflection is on line x=1

See attached graph with the image for the coordinates of the triangle after reflection

A'={5,0}

B'={2,0}

C'={2,4}

The solution to the system of linear equations is where they intersect which is at (- 0.5, 1.5).

Graphical solutions of a system of equations are a way of finding the intersection points of all the equations given.

A system with two or more than two equations has a solution only when they have a common intersection point.

From the graph of two lines in the coordinate system, every square box has a side length of 1 unit.

Now, The solution of the system is the point at which these two lines intersect.

By, Observing the graph we conclude that at (- 0.5, 1.5) they intersect and it is the solution of these two linear equations.

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All the table show the linear relationship, but none of the table show the proportional relationship.

A proportional relationship is a relationship between two expressions and where changes in one expression means some constant change in the other expression as well. Generally, it is represented as x/y = k, where x and y are two expressions and k is constant.

Given:

A). x → y

0 → 3

3 → 6

6 → 9

To show the linear relationship:

We have to find the constant first difference.

That means,

6-3 = 3

And 9 - 6 = 3

The values of this table show the linear relationship.

To show the proportional relationship:

Let x/y = k (k is constant)

We have to find the k:

0/3 = 0,

3/6 = 1/2,

6/9 = 2/3.

The values of this table do not show the proportional relationship.

B). x → y

0 → 4

2 → 6

4 → 8

To show the linear relationship:

We have to find the constant first difference.

That means,

6-4 = 2

And 8 - 6 = 2

The values of this table show the linear relationship.

To show the proportional relationship:

Let x/y = k (k is constant)

We have to find the k:

0/4 = 4,

2/6 = 1/3,

4/8 = 1/2.

The values of this table do not show the proportional relationship.

C). x → y

0 → 0

6 → 3

12 → 6

To show the linear relationship:

We have to find the constant first difference.

That means,

3-0 = 3

And 6 - 3 = 3

The values of this table show the linear relationship.

To show the proportional relationship:

Let x/y = k (k is constant)

We have to find the k:

0/0 = undefined,

6/3 = 2,

12/6 = 2.

The values of this table do not show the proportional relationship.

D). x → y

0 → 3

5 → 5

10 → 7

To show the linear relationship:

We have to find the constant first difference.

That means,

5 - 3 = 2

And 7 - 5= 2

The values of this table show the linear relationship.

To show the proportional relationship:

Let x/y = k (k is constant)

We have to find the k:

0/3 = 0,

5/5 = 1,

10/7 = 10/7.

The values of this table do not show the proportional relationship.

Therefore, none of the table show the proportional relationship.

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Hey there!

n * 25 = 5 * 60

25n = 5 * 60

25n = 300

DIVIDE 25 to BOTH SIDES

25n/25 = 300/25

CANCEL out: 25/25 because it gives you 1

KEEP: 300/25 because it helps solve for the n-value

NEW EQUATION: n = 300/25

SIMPLIFY IT!

n = 12

Therefore, your answer is: n = 12

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

The rate (in km/h) at which the distance from the plane to the radar station is increasing a minute later is 0 km/h (rounded to the nearest whole number).

To solve this problem, we can use the concepts of trigonometry and related rates.

Let's denote the distance from the plane to the radar station as D(t), where t represents time. We want to find the rate at which D is changing with respect to time (dD/dt) one minute later.

Given:

The plane is flying with a constant speed of 360 km/h.

The plane passes over the radar station at an altitude of 1 km.

The plane is climbing at an angle of 30°.

We can visualize the situation as a right triangle, with the ground radar station at one vertex, the plane at another vertex, and the distance between them (D) as the hypotenuse. The altitude of the plane forms a vertical side, and the horizontal distance between the plane and the radar station forms the other side.

We can use the trigonometric relationship of sine to relate the altitude, angle, and hypotenuse:

sin(30°) = 1/D.

To find dD/dt, we can differentiate both sides of this equation with respect to time:

cos(30°) * d(30°)/dt = -1/D^2 * dD/dt.

Since the plane is flying with a constant speed, the rate of change of the angle (d(30°)/dt) is zero. Thus, the equation simplifies to:

cos(30°) * 0 = -1/D^2 * dD/dt.

We can substitute the known values:

cos(30°) = √3/2,

D = 1 km.

Therefore, we have:

√3/2 * 0 = -1/(1^2) * dD/dt.

Simplifying further:

0 = -1 * dD/dt.

This implies that the rate at which the distance from the plane to the radar station is changing is zero. In other words, the distance remains constant.

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Given statement solution:- g(x) = \(4(1/4 x^2 + 3/4 x + 9) - 3\)

g(x) = \(x^2 + 3x + 33\) , the Transforming Parabolas correct answer is k = 1/2.

Let's start with the general form of the transformation g(x) = f(kx). To find the value of k, we can use the information given about the graphs of f(x) and g(x).

First, we know that the vertex of the graph of f(x) is at (-3, -3) and that the parabola opens up. This means that the equation of f(x) can be written in the form f(x) = \(a(x + 3)^2\) - 3 for some value of a.

Next, we know that the vertex of the graph of g(x) is at (-1, -3) and that the parabola opens up. Using the transformation equation, we can write g(x) = \(f(kx) = a(kx + 3)^2 - 3.\)

To find the value of k, we need to determine the scaling factor that relates the x-coordinates of the vertex of f(x) to the vertex of g(x). Since the x-coordinate of the vertex of g(x) is 2 units to the right of the vertex of f(x), we have k = 1/2.

Substituting k = 1/2 into the equation for g(x), we get:

g(x) = \(f(kx) = a(1/2 x + 3)^2 - 3\)

Simplifying this equation, we get:

g(x) = \(a(1/4 x^2 + 3x + 9) - 3\)

g(x) = \(1/4 a x^2 + 3/4 a x + 3a + (-3)\)

Comparing this equation to the general form of a parabola, y = \(ax^2 + bx\)+ c, we can see that the coefficient of \(x^2\)  is 1/4a, which means that a = 4. Therefore, we have:

g(x) = \(4(1/4 x^2 + 3/4 x + 9) - 3\)

g(x) = \(x^2 + 3x + 33\)

So the Transforming Parabolas correct answer is k = 1/2.

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Answer:

Step-by-step explanation:

Year 1: $850 * 0.91 = $773.50

Year 2: $773.50 * 0.91 = $704.69

Year 3: $704.69 * 0.91 = $641.95

...

Year 34: (continue the pattern)

We can continue this calculation for each year, but to save time, we can use an exponential decay formula:

Remaining Amount = Initial Amount * (1 - rate)^years

Substituting the values:

Remaining Amount = $850 * (1 - 0.09)^34

Calculating this expression:

Remaining Amount ≈ $850 * (0.91)^34 ≈ $255.88

After 34 years, approximately $255.88 will be left with Sally.

y-intercept = (0, 3)

The y-intercept of a linear function is the value of y when x equals to zero. That is, the point where the line crosses the y-axis

By carefully observing the table shown, the value of y at x = 0 is 3.

Therefore, the y-intercept of the linear function represented by the table is (0, 3)

Step-by-step explanation:

40 :100        yellow to purple,  divide both sides by 20

2:5

Answer:

the ratio of yellow to purple is 40:100 that is 2:5 in the simplest form.

Step-by-step explanation:

Hope it helps.

The mistake that Katie made in the stem and leaf diagram, was that she D. Missed a length.

Looking at the stem and leaf diagram, we see that there are 14 leaves. This means that there are 14 lengths of caterpillars. However, there are 15 lengths shown on the table.

This means that there is a length missing that Katie failed to account for. Upon close inspection of the stem and leaf plot, we find that the missing length is a second value of 70 because there are two lengths that are 70 but this is shown only once on the stem and leaf plot.

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The two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let \($&\overline{A B} \cong \overline{D E} \\\) and \($&\overline{A C} \cong \overline{D F}\)

Angle between \($\overline{A B}$\) and \($\overline{A C}$\) exists \($\angle A$\).

Angle between \($\overline{D E}$\) and \($\overline{D F}$\) exists \($\angle D$\).

Therefore, \($\triangle A B C \cong \triangle D E F$\) by SAS, if \($\angle A \cong \angle D$$\).

Given:

\($&\overline{A B} \cong \overline{D E} \\\) and

\($&\overline{A C} \cong \overline{D F}\)

According to the SAS congruence property, two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let \($&\overline{A B} \cong \overline{D E} \\\) and \($&\overline{A C} \cong \overline{D F}\)

Angle between \($\overline{A B}$\) and \($\overline{A C}$\) exists \($\angle A$\).

Angle between \($\overline{D E}$\) and \($\overline{D F}$\) exists \($\angle D$\).

Therefore, \($\triangle A B C \cong \triangle D E F$\) by SAS, if \($\angle A \cong \angle D$$\).

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If the value of b is 8. Then the value of the expression (9 - b) will be 1.

Making anything easier to accomplish or comprehend, as well as making it less difficult, is the definition of simplification.

The expression is given below.

⇒ 9 - b

If the value of b is 8. Then the value of the expression will be

⇒ 9 - b

⇒ 9 - 8

⇒ 1

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Answer: 10.5

Step-by-step explanation:

The median is the middle number in a data set, so in this set 5,6,10,11,12,16

the mean of 10 and 11 would be the median.

Answer:

100k each without tax + interest

Step-by-step explanation:

1. Revised Net Operating Income = $66,760

2. Revised Net Operating Income  =$64,640

3. Revised Net Operating Income  =$52,

1. If the sales volume increases by 40 units:

So, New Sales = 8,700 units + 40 units = 8,740 units

and, New Contribution Margin =

= $14.00 x 8,740 units

= 122, 360

New Fixed Expenses remain the same at $55,600

Then, Revised Net Operating Income

= New Contribution Margin - New Fixed Expenses

= 122360 - 55600

= 66,760.

2. If the sales volume decreases by 40 units:

New Sales = 8,700 units - 40 units = 8,660 units

New Contribution Margin

= 14 x 8660

= 121,240

New Fixed Expenses remain the same at $55,600

Then, Revised Net Operating Income

= New Contribution Margin - New Fixed Expenses

= 65,640

3. If the sales volume is 7,700 units:

New Sales = 7,700 units

New Contribution Margin

= 14 x 7700

= 107,800

New Fixed Expenses remain the same at $55,600

Then, Revised Net Operating Income

= New Contribution Margin - New Fixed Expenses

= 52, 200

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Answer:

Since you have no denominater so domain

\(( - \infty \infty )\)

and Range [

\( - \infty \infty \)

Answer:

f(x) = x³ - 4x + 6

f'(x) = 3x² - 4

a) f'(2) = 3(2²) - 4 = 12 - 4 = 8

6 = 8(2) + b

6 = 16 + b

b = -10

y = 8x - 10

b) 3x² - 4 = 0

3x² = 4, so x = ±2/√3 = ±(2/3)√3

= ±1.1547

f(-(2/3)√3) = 9.0792

f((2/3)√3) = 2.9208

c) 3x² - 4 = 8

3x² = 12

x² = 4, so x = ±2

f(-2) = (-2)³ - 4(-2) + 6 = -8 + 8 + 6 = 6

6 = -2(8) + b

6 = -16 + b

b = 22

y = 8x + 22

f(2) = 6

y = 8x - 10

The equation perpendicular to the tangent is y = -1/8x + 25/4

-The smallest slope on the curve is 2.92

The curve has the smallest slope at the point (1.15, 2.92)

The equations at tangent points are y = 8x + 16 and  y = 8x - 16

From the question, we have the following parameters that can be used in our computation:

y = x³ - 4x + 6

Differentiate

So, we have

f'(x) = 3x² - 4

The point is (2, 6)

So, we have

f'(2) = 3(2)² - 4

f'(2) = 8

The slope of the perpendicular line is

Slope = -1/8

So, we have

y = -1/8(x - 2) + 6

y = -1/8x + 25/4

We have

f'(x) = 3x² - 4

Set to 0

3x² - 4 = 0

Solve for x

x = √[4/3]

x = 1.15

So, we have

Smallest slope = (√[4/3])³ - 4(√[4/3]) + 6

Smallest slope = 2.92

So, the smallest slope is 2.92 at (1.15, 2.92)

Here, we set f'(x) to 8

3x² - 4 = 8

Solve for x

x = ±2

Calculate y at x = ±2

y = (-2)³ - 4(-2) + 6 = 6: (-2, 0)

y = (2)³ - 4(2) + 6 = 6: (2, 0)

The equations at these points are

y = 8x + 16

y = 8x - 16

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The solution is, radius: 23 inches.

Arc length formula is used to calculate the measure of the distance along the curved line making up the arc (a segment of a circle). In simple words, the distance that runs through the curved line of the circle making up the arc is known as the arc length.

here, we have,

Formula: ∅r = arc length

Here the ∅ is 2 rads and arc length is 46 inches.

using the formula:

2*r = 46

r = 23 inches

The solution is, radius: 23 inches.

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Answer:

(c)1/6

(d)5/12

Step-by-step explanation:

When two fair six-sided dice are rolled once

(a)The pair (x,y) denotes a single outcome of the experiment where x is the outcome of the first die and y is the outcome of the second die.

For example, (2,1) means the first die shows a 2 while the second die shows an outcome of 1.

(b)Sample Space

The sample space of all possible outcome is:

\((1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5,6)\\(6, 1), (6, 2), (6, 3), (6, 4), (6,5), (6,6)\)

Total Number of Outcomes =36

(c)The probability for the first die to be two

The outcomes where the fist die is 2 are:

\((2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)\)

Therefore:

The probability for the first die is two

\(=\dfrac{6}{36}\\\\=\dfrac{1}{6}\)

(d)The probability that the value rolled on die 1 minus the value rolled on die 2 is positive

These are the outcomes of the pair (x,y) where x>y.

They are:

\((2, 1)\\(3, 1), (3, 2)\\(4, 1), (4, 2), (4, 3)\\(5, 1), (5, 2), (5, 3), (5, 4)\\(6, 1), (6, 2), (6, 3), (6, 4), (6,5)\)

\(P(x-y>0)=\dfrac{15}{36}\\\\=\dfrac{5}{12}\)

We want to see for which one of the given functions, the inverse derivate evaluated in x = 20 is equal to 1/5.

The correct option is B:  f(x) = x^3 + 5x + 20

What is inverse derivative?

The inverse function rule in calculus is a formula that converts the derivative of the inverse of a bijective and differentiable function, f, into the derivative of f.

Remember that two functions f(x) and g(x) are inverses if:

f( g(x)) = g( f(x))) = x

And for the inverse derivate of a function, we have the rule:

\(\frac{d}{dx}[f^{-1} (f(x))]=\frac{1}{{f^'}(x)}\)

So first we need to find for what value of x each function is equal to 20, and then we need to see if the derivate of the function evaluated in that same value of x is equal to 5.

For example, for the first option we have:

A: f(x) = x + 5

We find the x-value such that the function is equal to 20.

f(15) = 15 + 5 = 20

We derivate the function.

f'(x) = 1

We evaluate the function in the x-value we got above.

f'(15) = 1

This is not the correct option, as this is not 5.

Now we need to do that for all the given options.

The only correct option will be the second one:

B: f(x) = x^3 + 5x + 20

First we find the x-value such that this is equal to 20

f(0) = 0^3 + 5*0 + 20 = 20

Then the x-value is x = 0.

Now we find the derivate of f(x).

f'(x) = 3*x^2 + 5

Now we evaluate that in the x-value we got before:

f'(0) = 3*0^2 + 5 = 5

As wanted, this is equal to 5.

Then we have:

\(\frac{d}{dx}[f^{-1} (f(0))]=\frac{1}{{f^'}(0)}\)

\(\frac{d}{dx} [f^{-1} (20)]=\frac{1}{5}\)

As wanted.

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