2.45
add the 2 numbers and divide by 2
. What is the product of (2x -1) and (3x + 4)?
Answer:
Step-by-step explanation:
(2x-1)*(3x+4) = \(2x*3x + 2x(4)+(-1)*(3x)+(-1)(4)\)=6\(x^{2}\)\(+8x-3x-4\)=\(6x^{2} +5x-4\)
What is the x-intercept of the line graphed on the grid? 0)
A) 2
B) 4
C)- 2
D) -4
Answer:
-2
Step-by-step explanation:
It intersects with x-axis at -2 which is the x-intercept of the line.
Answer:
-2
Step-by-step explanation:
The x intercept is where the line crosses the x axis.
The line crosses where x = -2
elect all equations that represent the number of subscribers, , in terms of months since the beginning of the year (when she had 150 subscribers).
Using the income statement below, calculate the following profitability ratios for Western Bookkeeping and Tax Service. Assume that stockholder's equity equals $441,600 and total assets equal $640,000.
Profit margin ratio
Return on equity ratio
Asset turnover ratio
Write the profit margin and return on equity ratios as a percent, rounded to the nearest percent. Write the asset turnover ratio as a decimal, rounded to two decimal places.
The computation of the profitability ratios for Western Bookkeeping and Tax Service is as follows:
Profit margin ratio = 8%Return on equity ratio = 8%Asset turnover ratio = 0.75.What are profitability ratios?Profitability ratios are the financial ratios that evaluate an entity's ability to convert its earnings (revenue) into profit versus different criteria.
Some of the common profitability ratios include:
Gross Profit MarginOperating Income RatioNet Income RatioReturn on Investment (ROI)Return on EquityReturn on Total AssetsAsset turnover RatioEarnings per share.Stockholders' equity = $442,600
Total assets = $640,000
Net sales = $480,000
Net income = $36,000
Profit margin ratio = Net income/Net Sales x 100
= $36,000/$480,000 x 100
= 7.5%
= 8%
Return on equity ratio = Net income/Shareholders' Equity x 100
= $36,000/$442,600 x 100
= 8.13%
= 8%
Asset turnover ratio = Net Sales/Total Assets
= $480,000/$640,000
= 0.75
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Solve this its not 48
\(\begin{cases} 3x+5y=50\\ x+5y=31\\[-0.5em] \hrulefill\\ x+5y=31\\ x = 31-5y \end{cases}\qquad \implies \stackrel{\textit{substituting in the 1st equation}}{3(31-5y)+5y=50} \\\\\\ 93-15y+5y=50\implies 93-10y=50\implies -10y=-43 \\\\\\ y=\cfrac{-43}{10}\implies \boxed{y=\cfrac{43}{10}} \\\\[-0.35em] ~\dotfill\\\\ x = 31-5y\implies x = 31-5\left( \frac{43}{10} \right)\implies x = 31-\cfrac{43}{2}\implies \boxed{x = \cfrac{19}{2}}\)
\(\stackrel{~\hfill \textit{\large total for 7x + 5y}}{7\left( \cfrac{19}{2} \right)+5\left( \cfrac{43}{10} \right)\implies \cfrac{133}{2}+\cfrac{43}{2}\implies \cfrac{133+43}{2}\implies \cfrac{176}{2}\implies 88}\)
Let the following grouped frequency dsitribution represent the markof 230 students out of 70.
CL 0-9 10-19 20-29 30-39 40-49 50-59 60-69 Total
freq. 4 16 f3 f4 f5 6 4 230
Based on the above grouped frequency distribution, answer the following question by showing all neccessary steps.
a. Determine the missing frequencies if median and mode are 33.5 and 34.0 respectively
16 & 81 are the missing frequencies if median and mode are 33.5 and 34.0 respectively.
To determine the missing frequencies, we need to use the information given about the median and mode.
First, let's find the position of the median in the cumulative frequency distribution. The total number of students is given as 230, so the median position will be (230 + 1) / 2 = 115.5. This means that the median falls within the 115th and 116th position in the ordered data.
Next, we need to determine the class interval that contains the median. Looking at the cumulative frequency distribution, we can see that the cumulative frequency just before the median position (115) is 34. This means that the median falls within the 30-39 class interval.
To find the missing frequency (f4) for the 30-39 class interval, we subtract the cumulative frequency of the previous class from the median position:
f4 = 115 - 34 = 81
So, the missing frequency for the 30-39 class interval is 81.
Next, let's determine the mode. The mode is the class interval with the highest frequency. From the given distribution, we can see that the highest frequency is for the 20-29 class interval. However, the mode is given as 34.0, which does not fall within the 20-29 class interval.
To determine the missing frequency (f3) for the 20-29 class interval, we need to distribute the difference in frequencies between the 20-29 and 30-39 class intervals proportionally based on the mode. The difference in frequencies is 81 - 16 = 65.
We can set up the following proportion:
(34 - 20) / (29 - 20) = f3 / (30 - 20)
Simplifying the proportion:
14 / 9 = f3 / 10
Cross-multiplying:
9f3 = 140
Solving for f3:
f3 = 140 / 9 ≈ 15.6
Since frequencies should be whole numbers, we round f3 to the nearest whole number, which is 16.
Therefore, the missing frequencies are:
f3 = 16
f4 = 81
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Help with the following equation 8x²-6x-5=x
Answer:
\(8 {x}^{2} - 6x - 5 = x\)
\(8 {x}^{2} - 7x - 5 = 0\)
x = (7 + √((-7)^2 - 4(8)(-5)))/(2×8)
= (7 + √(49 + 160))/16
= (7 + √209)/16
= -.4661, 1.3411 (to 4 decimal places)
How do I find the mean of a given set of numbers?
Answer:
Add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.
Step-by-step explanation:
:D
Given the points P (3, 5) and Q (-5, 7) on the cartesian plane such that R (x, y) is
the midpoint of PQ, find the equation of the line that passes through R and
perpendicular
to PQ.
Answer:
-22=22
Step-by-step explanation:
3,5-5,7=
-22/22
The equation of the line passing through R and PQ is 4(y - 6) = -x - 1/2.
To find the equation of the line passing through the midpoint R and the points P and Q, we first need to find the coordinates of the midpoint R. The midpoint coordinates can be found by taking the average of the x-coordinates and the average of the y-coordinates of P and Q.
The x-coordinate of the midpoint R is (3 + (-5)) / 2 = -1/2.
The y-coordinate of the midpoint R is (5 + 7) / 2 = 6.
So, the coordinates of the midpoint R are (-1/2, 6).
Next, we can use the two-point form of the equation of a line, which states that the equation of the line passing through points (x₁, y₁) and (x₂, y₂) is given by:
(y - y₁) = (y₂ - y₁) / (x₂ - x₁) \(\times\) (x - x₁)
Substituting the coordinates of R (-1/2, 6) and P (3, 5) into the equation, we have:
(y - 6) = (7 - 5) / (-5 - 3) \(\times\)(x - (-1/2))
Simplifying the equation:
(y - 6) = (2 / -8) \(\times\)(x + 1/2)
(y - 6) = -1/4 \(\times\)(x + 1/2)
4(y - 6) = -x - 1/2
Therefore, the equation of the line passing through R and PQ is 4(y - 6) = -x - 1/2.
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Suppose that following is known about the currency "Ruthenian peso." At the current exchange rate, 45 Ruthenian pesos is equal to 37 dollars. Calculate how many Ruthenian pesos I can get for 25 dollars.
Answer: 30.41 pesos
Step-by-step explanation:
$37 = 45 Ruthenian pesos
.: $1 ≅ 1.2161 Ruthenian pesos
Using cross multiplication:
.: $25 ≅ 30.4054 Ruthenian pesos
I'd round the answer to two decimal places, so you can get about 30.41 Ruthenian pesos for 25 US dollars :)
Please helpppppppppp
Answer:
77 cubed in.
Step-by-step explanation:
I think it is 77 cubed inches because the formula is V-bh
What is the probability that either event will occur?
A
30
8
B
7
P(A or B) = P(A) + P(B)
P(A or B) = [?]
Enter as a decimal rounded to the nearest hundredth.
The probability that either event will occur is 0.33
What is the probability that either event will occur?From the question, we have the following parameters that can be used in our computation:
Event A = 8Event B = 7Other Events = 30Using the above as a guide, we have the following:
Total = A + B + C
So, we have
Total = 8 + 7 + 30
Evaluate
Total = 45
So, we have
P(A) = 8/45
P(B) = 7/45
For either events, we have
P(A or B) = 8/45 + 7/45
P(A or B) = 15/45
Evaluate
P(A or B) = 0.33
Hence, the probability that either event will occur is 0.33
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Suppose a bond with no expiration date has a face value of $10,000 and annually pays a fixed amount of interest of $700.
a. In the table provided below, calculate and enter either the interest rate that the bond would yield to a bond buyer at each of the bond prices listed below or the bond price at each of the interest yields shown.
Answer:
Step-by-step explanation:
9300
1. Lindsey is designing a stained glass window using parallelograms. She draws a model before starting her work. In her model, BCGF and CDHG are parallelograms and BC ≅CD. Find all the segments that are congruent to KG
A. KD, CJ
B. KD
C. KD, CJ, JF, KH, JG
D. KD, CJ, JF
2. Determine whether the statement is always, sometimes, or never true. Explain your reasoning.
In parallelogram MNPQ, the diagonals MP and NQ meet at R with MP=2RP
A. Always. Diagonals of a parallelogram bisect each other.
B. Sometimes. MR¯¯¯¯¯¯¯¯¯ and RP¯¯¯¯¯¯¯¯ may or may not be congruent.
C. Never. The relationship between MP and RP should be MP=3RP.
D. Never. Diagonals of a parallelogram do not bisect each other.
Answer:
D: KD, CJ, JF
Step-by-step explanation:
I just took the quick check and it was right.
82°
118°
95°
X°
Image not to scale
Calculate the missing angle x.
Answer:
x = 65
Step-by-step explanation:
the sum of the interior angles of a quadrilateral = 360°
sum the angles and equate to 360
x + 95 + 118 + 82 = 360
x + 295 = 360 ( subtract 295 from both sides )
x = 65
plssssssssssssssssssssssssssss
Answer: \(49\pi\)
Step-by-step explanation:
\(A=\pi r^{2}\)
if diameter is 14, the radius is 7
\(A=\pi 7^{2} \\A=49\pi\)
A runner can run 2 miles in 10 minutes. At this rate how many miles can he run in 40 minutes
Answer:
8 miles
Step-by-step explanation:
At a rate of 2 miles in 10 minutes, in 40 minutes he can run 8 miles.
2 / 10 == x / 40
x == (40 * 2) / 10
x == 8
Cheers.
Answer:
Step-by-step explanation:
8
help me plz branniest to whoever right
in an equilateral triangle the first side is x+1, second side is 2x+4, the third side is 3x+y, find the value of x and y
The value of x is -3 and y is 7 for equilateral triangle having x+1, 2x+4 and 3x+y sides.
We can use the fact that an equilateral triangle has equal lengths on each of its three sides to determine the values of x and y.
Given:
First side=x+y
second side= 2x+4
third side=3x+y
An equilateral triangle has three equal sides, hence the following equations can be constructed:
x + 1 = 2x + 4
2x + 4 = 3x + y
Let's tackle each of these equations separately:
x + 1 = 2x + 4
We will subtract x from both sides and subtract 4 from both sides in order to solve this equation:
x + 1 - x = 2x + 4 - x
1 = x + 4
By taking 4 away from both sides, we arrive at:
1 - 4 = x + 4 - 4 , -3 = x
Therefore, x has been determined to be -3.
Now, substitute the value of x in the second equation:
2x + 4 = 3x + y
2(-3) + 4 = 3(-3) + y
-6 + 4 = -9 + y
-2 = -9 + y
y = -2 + 9
y = 7
So, we determined that y has a value of 7.
As a result, the values of x and y are, respectively, x=-3 and y=7
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Answer:
Step-by-step explanation:
In an equilateral triangle all sides are equal.
So each of these sides (and their equations are equal to each other.)
To find x - set the first two (as they only involve x) equal to each other and solve.
x + 1 = 2x + 4
x -x + 1 = 2x - x + 4
1 = x + 4
1- 4 = x + 4 - 4
-3 = x
Then substitute -3 for x in the last equation to find y, also setting it equal to one of the other equations.
3(x) + y = x + 1
3(-3) + y = -3 + 1
-9 + y = -2
-9 + 9 + y = -2 + 9
y = 7
so x = -3 and y equal 7
Solve for k. K(K + 8) = 0 Write your answers as integers or as proper or improper fractions in simplest form. k = 1 or k = submit
Answer:
k= -8
Step-by-step explanation:
Solve the equation below for x.
cx-4=7
A. x=c/3
B. x=3/c
C. x=11/c
D. x=c/11
Answer:
x = 11/c
Step-by-step explanation:
Solve for x:
c x - 4 = 7
Hint: | Isolate terms with x to the left-hand side.
Add 4 to both sides:
c x = 11
Hint: | Solve for x.
Divide both sides by c:
Answer: x = 11/c
raito 6 servings per platter
Answer: 6:1
Step-by-step explanation:
help fast plz I need it
Answer:
<JLK
Step-by-step explanation:
Angle ADB and CD are straight lines. angle ADC = 5 x angle CDB Work out the size of angle ADC.
Answer:
Step-by-step explanation:
Your class is taking a trip to the public library. You can travel in cars and large vans. A car holds 5 people and a large van holds 12 people.
Identify what x and y represent.
The unknown parameters x and y represent number of car needed for the trip to the public library and number of large van needed for the trip to the public library respectively.
Simultaneous equationSimultaneous equation is a type of equation which helps to solve for two unknown values simultaneously.
Number of people the car holds = 5Number of people the large van holds = 121The unknown values of x and y represent:
x = number of car needed for the trip to the public libraryy = number of large van needed for the trip to the public libraryIn conclusion, x and y are variables used to represent number of cars and number of large vans needed for the trip respectively.
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Jane Peterson has taken Amtrak to travel from New York to Washington, DC, on six occasions, of which three times the train was late. Therefore, Jane tells her friends that the probability that this train will arrive on time is 0.50. Would you label this probability as empirical or classical? Why would this probability not be accurate?
Answer:
a) This probability as empirical Probability.
b) This probability is not accurate because this experiment must be repeated a large number of times for empirical probabilities should be accurate.
Step-by-step explanation:
On 6 occasions, of which three times the train was late. that means 3 times the train is on time.
Empirical probability = Number of outcomes satisfying event / No.of trails
= 3/6 = 0.5.
a) This probability as empirical Probability.
b) This probability is not accurate because this experiment should be repeated a large number of times for empirical probabilities should be accurate.
Find the sum of the first 8 terms of the fallowing sequence?
3,15,75,375 …
Answer:
\( \frac{3( {5}^{8} - 1) }{5 - 1} = 292968\)
Quadrilateral ABCD is a square and the length of BD¯¯¯¯¯ is 10 cm.
What is the length of AE¯¯¯¯¯ ?
Enter your answer in the box.
the length of AE¯¯¯¯¯ =
cm
The length of AE¯¯¯¯¯ is 5√2 cm.
Since quadrilateral ABCD is a square, all four sides are congruent. Let's denote the length of one side as s. Therefore, the length of BD¯¯¯¯¯ is equal to s.
Given that the length of BD¯¯¯¯¯ is 10 cm, we can conclude that s = 10 cm.
Now, we need to find the length of AE¯¯¯¯¯. Looking at the square, AE¯¯¯¯¯ is the diagonal connecting opposite corners.
In a square, the diagonal divides the square into two congruent right triangles. We can use the Pythagorean theorem to find the length of the diagonal.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
In this case, the diagonal (the hypotenuse) is the same as the side length, s.
Applying the Pythagorean theorem:
s^2 = AE¯¯¯¯¯^2 + AE¯¯¯¯¯^2
10^2 = AE¯¯¯¯¯^2 + AE¯¯¯¯¯^2
100 = 2 * AE¯¯¯¯¯^2
AE¯¯¯¯¯^2 = 50
Taking the square root of both sides:
AE¯¯¯¯¯ = √50
Simplifying the square root:
AE¯¯¯¯¯ = √(25 * 2) = 5√2 cm
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Consider a sample with a mean of 60 and a standard deviation of 5. Use Chebyshev's theorem to determine the percentage of the data within each of the following ranges (to the nearest whole number).
a. 50 to 70, at least %
b. 35 to 85, at least %
c. 51 to 69, at least %
d. 47 to 73, at least %
e. 43 to 77, at least %
Answer:
a)75%
b)96%
c)69.4%
d)85.2%
e)91.3%
Step by step explanation:
Given:
Mean=60
Standard deviation= 5
We were told to use chebyshev's theorem.to determine the percentage of the above given data within each of the following ranges
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION.
Pls fast I need help plsssss
Answer:
ok so u know that all triangles in the inside are equal to 180
Step-by-step explanation:
1. 180-162= 18 angle a is 18, now to solve for b 180-122-18=40, angle b is 40
2.180-171=9 angle a is 9, now to solve for b 180-128-9=43, angle b is 43
3.180-35-22=132 angle c is 132, now to solve for angle d 180-22=158, angle d is 158
4. 180-20-29=131 angle c is 131, now to solve for angle d 180-20=160, angle d is 160