MATH 2 HELP PLEASE !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

-9?

Step-by-step explanation:

The correlation coefficient that indicates the strongest relationship between two variables is a. -1.0.

The correlation coefficient is a numerical measure that quantifies the relationship between two variables. It ranges from -1 to +1, where -1 indicates a perfect negative correlation, +1 indicates a perfect positive correlation, and 0 indicates no correlation.

In this case, a correlation coefficient of -1.0 represents a perfect negative correlation, meaning that the two variables have a strong, linear relationship where as one variable increases, the other decreases in a perfectly predictable manner. This indicates a very strong and consistent inverse relationship between the variables.

In comparison, a correlation coefficient of 0.80 indicates a strong positive correlation, but it is not as strong as a perfect negative correlation of -1.0. A correlation coefficient of 0.1 suggests a weak positive correlation, while a correlation coefficient of -0.45 indicates a moderate negative correlation.

Therefore, out of the given options, the correlation coefficient of -1.0 represents the strongest relationship between two variables.

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The person who memorized 42,195 digits of pi on February 18, 1995 was Hiroyuki Goto. Hiroyuki Goto was from Japan.

Pi is a mathematical constant that is represented by the Greek letter π. Pi is defined as the ratio of the circumference of a circle to its diameter. This means that for any circle, the circumference (the distance around the edge) divided by the diameter (the distance across the center) will always be the same number, which is approximately equal to 3.14159. This number is often rounded to 3.14, which is why Pi Day is celebrated on March 14th (3/14).

Hiroyuki Goto is a Japanese engineer and computer scientist who has held the world record for memorizing the most digits of pi.

On February 18, 1995, he recited 42,195 digits of pi from memory. This record-breaking feat took him over 9 hours to complete. Goto was born on March 28, 1959, in Japan. He is also known for his work on algorithms and computer security.

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The depth of the water in the cone-shaped tank is increasing at a rate of approximately 1.385 meters per second.

To determine the rate at which the depth of the water is changing, we can use related rates. Let's denote the depth of the water as h(t), where t represents time. We are given that dh/dt (the rate of change of h with respect to time) is 12 m/sec, and we want to find dh/dt when h = 18 meters.

To solve this problem, we can use the volume formula for a cone, which is V = (1/3)πr^2h, where r is the base radius and h is the depth of the water. We can differentiate this equation with respect to time t, keeping in mind that r is a constant (since the base radius does not change).

By differentiating the volume formula with respect to t, we get dV/dt = (1/3)πr^2(dh/dt). Now we can substitute the given values: dV/dt = 12 m/sec, r = 26 meters, and h = 18 meters.

Solving for dh/dt, we have (1/3)π(26^2) (dh/dt) = 12 m/sec. Rearranging this equation and solving for dh/dt, we find that dh/dt is approximately 1.385 meters per second. Therefore, the depth of the water in the tank is increasing at a rate of about 1.385 meters per second.

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The indicated side of the triangle is 17√2 unit.

In a right-angled triangle, the square of the hypotenuse side is equal to the sum of the squares of the other two sides, according to Pythagoras's Theorem.

Given:

The triangle is a right-angled triangle.

The length of the perpendicular = 17 unit.

Two angles of the triangle are 45° and 45°.

That means, base = 17 unit.

And the triangle is an isosceles triangle.

By the Pythagoras' theorem,

a = √(289 + 289)

a = √578

a = 17√2 unit.

Therefore, the value of a is 17√2 unit.

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The interest rate is approximately 0.0403, or 4.03% (rounded to two decimal places).

To calculate the interest rate on the investment, we can use the formula for compound interest: A = P * (1 + r)^n

Where:

A is the future value of the investment ($1,680)

P is the initial principal ($1,500)

r is the interest rate

n is the number of compounding periods (3 years)

Rearranging the formula, we can solve for r:

r = (A/P)^(1/n) - 1

Plugging in the values:

r = (1680/1500)^(1/3) - 1

= 1.12^(1/3) - 1

≈ 0.0403

The interest rate is approximately 0.0403, or 4.03% (rounded to two decimal places).

Therefore, the correct answer is:

C) 4.0 percent

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The trigonometric relations from the triangles are

a) tan A = 5/12

b) sin C = 3/5

c) cos X = 3/5

d) sin Z = 4/5

e) tan Z = 4/3

f) tan X = 12/5

What are trigonometric relations?

Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles

The six trigonometric functions are sin , cos , tan , cosec , sec and cot

Let the angle be θ , such that

sin θ = opposite / hypotenuse

cos θ = adjacent / hypotenuse

tan θ = opposite / adjacent

tan θ = sin θ / cos θ

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

Given data ,

a)

The triangle is ΔABC

tan A = opposite side / adjacent side

Substituting the values in the equation , we get

tan A = 10/24

tan A = 5/12

b)

The triangle is ΔABC

sin C = opposite side / hypotenuse

Substituting the values in the equation , we get

sin C = 24/40

sin C = 3/5

c)

The triangle is ΔXYZ

cos X = adjacent side / hypotenuse

Substituting the values in the equation , we get

cos X =21/35

cos X = 3/5

d)

The triangle is ΔXYZ

sin Z = opposite side / hypotenuse

Substituting the values in the equation , we get

sin Z = 32/40

sin Z = 4/5

e)

The triangle is ΔXYZ

tan Z = opposite side / adjacent side

Substituting the values in the equation , we get

tan Z = 28/21

tan Z = 4/3

f)

The triangle is ΔXYZ

tan X = opposite side / adjacent side

Substituting the values in the equation , we get

tan X = 12/5

Hence , the trigonometric relations are solved from the triangles

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Solutions cannot be more concentrated than a solution that has a %T of 10%

Solutions cannot be less concentrated than a solution that has a %T of 90%.

Beer's Law:

Beer's law (sometimes called Beer-Lambert's law) states that absorption is proportional to the path length b through the sample and the concentration c of the absorbing substance: The constant of proportionality is sometimes designated by the symbol a, which makes Beer's law literal.

The linearity of the law is limited by chemical and instrumental factors. The reasons for the nonlinearity are: Absorbance deviation at high concentrations (>0.01 M) due to electrostatic interactions between adjacent molecules.

Limitation of Beer's Law:

The linearity of the law is limited by chemical and instrumental factors.

Causes of non-linearity include:

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Fisher's Exact Test is used when there are two independent samples of categorical data, and it is a valuable tool for analyzing small sample sizes where other tests may not be appropriate.

Fisher's Exact Test is used when there are two independent samples of categorical data. This test is specifically designed to determine if there is a significant association between two categorical variables in a 2x2 contingency table.

It is commonly used when the sample size is small, which can cause issues with other statistical tests such as the chi-square test.

The two independent samples refer to two different groups or populations that are being compared. For example, we might be interested in comparing the success rates of a new drug treatment versus a placebo in a clinical trial, where success and failure are the two categories being considered.

Fisher's Exact Test calculates the probability of observing the data given the null hypothesis of no association between the variables. It does this by considering all possible arrangements of the data that have the same marginal totals. If the calculated probability is very small (typically less than 0.05), we reject the null hypothesis and conclude that there is a significant association between the variables.

In summary, Fisher's Exact Test is used when there are two independent samples of categorical data, and it is a valuable tool for analyzing small sample sizes where other tests may not be appropriate.

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Answer:

-61

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Define

x + y

x = 13

y = -74

Step 2: Evaluate

The parametric equations for the circle (x−4)^2 (y−1)^2=4 are x=4+2cos(t) and y=1+2sin(t), where t is the parameter.

Assuming the circle is traced clockwise as the parameter increases, if x=9+2cos(t), then t=arccos((x-9)/2). Substituting this into the equation for y gives y=1+2sin(arccos((x-9)/2)). Simplifying this expression gives y=1+2sqrt(1-(x-9)^2/16), which is the equation of the circle traced clockwise. The word count for this answer is 98 words.
Hi! The given circle equation is (x-4)^2 + (y-1)^2 = 4. To convert this into parametric equations, we'll use the parameter t. Since the circle is traced clockwise as the parameter increases, we'll use negative sine and cosine functions. The parametric equations for the given circle are:
x = 4 + 2cos(-t) = 4 - 2cos(t),
y = 1 + 2sin(-t) = 1 - 2sin(t).
Now, if x = 9 + 2cos(t), equate this with the parametric equation for x:
9 + 2cos(t) = 4 - 2cos(t).
Solving this equation will help determine the relationship between the given x-value and the parameter t.

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Answer:

8n+7

Step-by-step explanation:

Answer:

$10.80

Step-by-step explanation:

You should Divide 3 / 5 and get 0.6. 0.6 is the price of only 1 ticket. So you can do 18 x 0.6 and get 10.80.

Answer

Step-by-step explanation: i believe its 35

The sum of the numerator and denominator of the decimal is found as 111.

As for the given question;

The decimal number is given as;

0.12 bar

Decimal to fraction conversion

100(0.12 bar) = 12(0.12 bar)

99.(0.12bar) = 100(0.12bar) - (0.12 bar)

99.(0.12bar) = 12 × 0.12bar - 0.12bar

99.(0.12bar) = 12

0.12 bar = 12/99 (lowest fraction)

Thus, in the result the numerator is found as 12 and the denominator is found as 99.

Add = 12 + 99

Add = 111

Thus, the sum of the numerator and denominator of the decimal is found as 111.

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\(\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}\)

Total cards = 52

Total diamond cards = 13

So, probability of getting a card of diamond,

P(diamond) = 13/52 = 1/4

Now,

Total cards with number seven = 4

So, probability of getting a seven,

P(seven) = 4/52 = 1/13

Answer:

209,32°F should be the right answer

Answer:

b = -.0018a + 214

Step-by-step explanation:

b = -.0018a + 214

b = -.0018(2600) + 214

b = -4.68 + 214

b = 209.32

In the triangle DEF, the angle  F has the largest measure.

This law is represented by the equation: C²=A²+B²-2ABcos θ, where: A,B and C are the sides of a triangle and θ = angle.

For solving this question, you should apply the Law of Cosines, where:

DF=6, DE=11 and EF=7.

7²=6²+11²-2*6*11*cos D

49=36+121-132*cos D

132*cos D=157-49

132*cos D=108

cos D= 108/132=9/11

arc cos (9/11)=35.1°

Then, D=35.1°

11²=6²+7² -2*6*7*cos (F)

121=36+49-84*cos (F)

84 * cos (F)=-121+85

84* cos (F)=-36

cos (F)= -36/84=-3/7

arccos (-3/7)=115.4°

Then, F=115.4°

Like the sum of the internal angles of a triangle is 180°. You can find the angle E:

D+F+E=180°

35.1+115.4+E=180

150.5+E=180

E=180-150.5=29.5°

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The variance of the sample mean x = 7 is 18(option c).

Given table:

X          7  5  11   1   11

(x₁ - x)² 0  4  16 36 16​

n = number of observations = 5

Variance σ² = 1/n-1 Σ\(\ \ n} \atop {i=1} \right.\) (\(X_{1}\) - X)²

= 1/5-1 (0 +4 + 16 + 36 + 16)

= 1/4(72)

= 18

Therefore variance σ² = 18

Hence the variance of the sample mean x = 7 is 18.

so option c is correct.

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​

Answer:

because a=b and c=d so bisect

I can't see pictures, so I'll do my best.

y= always stays the same.

To find the slope, or x, you have to start at the y-intercept, and find the number of units up, then right.

For example, y=4/3+6

4/3 is the slope because it goes up 4 units and right 3 units from the y-intercept.

6 is the y-intercept, which is the y-coordinate. It can also be graphed as (0,6).

---

hope it helps

Answer:

x = -1

y = -1

Step-by-step explanation:

This is a system of equations- the set up of the problem lends well to using the elimination method. There are always many ways of solving a system of equations, both in methods and different strategies within each method. The problem isn't necessarily complete but I can assume you're being asked to solve for x and y values.

divide the first equation by -2. this means we can use elimination to cancel out the y value, and is also our simplest option (rather than multiplying the second equation by -2.

-2x + 20y = -18 --> x - 10y = 9

x - 10y = 9

8x + 10y = -18

Using the elimination method to essentially add the parts of the equations together, this comes out to 9x = -9 , meaning x = -1 .

We can then return to our original equations, and substitute -1 for x (either equation will work, but the second one is simpler and therefore the better option).

8 (-1) +10y = -18

-8 + 10y = -18

10y = -10

y = -1

CHECKING

Substitute both x and y values back into the original equations to check them. the sides should be equal if our values are correct.

-2 (-1) + 20 (-1) = -18

Our first equation works: 2 - 20 = -18

8 (-1) + 10 (-1) = -18

The second equation works as well: -8-10= -18

The unit tangent vector is \(\(T(t) = \left(\frac{2}{\sqrt{13}}, \frac{-3\sin(t)}{\sqrt{13}}, \frac{3\cos(t)}{\sqrt{13}}\right)\)\), and the unit normal vector is\(\(N(t) = \left(0, -\frac{\cos(t)}{\sqrt{13}}, -\frac{\sin(t)}{\sqrt{13}}\right)\).\)

To find the unit tangent vector\(\(T(t)\)\) and unit normal vector \(\(N(t)\)\)for the given vector function \(\(r(t) = 2t, 3\cos(t), 3\sin(t)\)\), we can follow these steps:

Step 1: Compute the first derivative of \(r(t)\) with respect to \(t\) to obtain the velocity vector:

\(\(v(t) = r'(t) = 2, -3\sin(t), 3\cos(t)\).\)

Step 2: Calculate the magnitude of the velocity vector:

\(\(|v(t)| = \sqrt{(2)^2 + (-3\sin(t))^2 + (3\cos(t))^2} = \sqrt{4 + 9\sin^2(t) + 9\cos^2(t)} = \sqrt{13}\).\)

Step 3: Compute the unit tangent vector \(T(t)\) by dividing the velocity vector by its magnitude:

\(\(T(t) = \frac{v(t)}{|v(t)|} = \left(\frac{2}{\sqrt{13}}, \frac{-3\sin(t)}{\sqrt{13}}, \frac{3\cos(t)}{\sqrt{13}}\right)\).\)

Step 4: Calculate the derivative of the unit tangent vector with respect to \(\(t\)\) to obtain the curvature vector:

\(\(T'(t) = \left(0, -\frac{3\cos(t)}{\sqrt{13}}, -\frac{3\sin(t)}{\sqrt{13}}\right)\).\)

Step 5: Compute the magnitude of the curvature vector:

\(\(|T'(t)| = \sqrt{\left(-\frac{3\cos(t)}{\sqrt{13}}\right)^2 + \left(-\frac{3\sin(t)}{\sqrt{13}}\right)^2} = \frac{3}{\sqrt{13}}\).\)

Step 6: Calculate the unit normal vector \(N(t)\) by dividing the curvature vector by its magnitude:

\(\(N(t) = \frac{T'(t)}{|T'(t)|} = \left(0, -\frac{\cos(t)}{\sqrt{13}}, -\frac{\sin(t)}{\sqrt{13}}\right)\).\)

Therefore, the unit tangent vector is \(\(T(t) = \left(\frac{2}{\sqrt{13}}, \frac{-3\sin(t)}{\sqrt{13}}, \frac{3\cos(t)}{\sqrt{13}}\right)\),\) and the unit normal vector is \(\(N(t) = \left(0, -\frac{\cos(t)}{\sqrt{13}}, -\frac{\sin(t)}{\sqrt{13}}\right)\).\)

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Answer:

Value = 5 + 2n, where in is the sequence number, starting with n = 0.

Step-by-step explanation:

The sequence is predicted by adding 2 for each step.  The formula for the number at point n is given by 5+2n, starting with n = 0:

n  Value

0      5

1       7

2      9

3     11

4     13

5     15

6     17

7     19

8    21

9    23

10   25

Object B will be at a distance of 180 m from the bottom of the well when object A hits the bottom.

The formula for distance covered by a freely falling object is given by :

\(\[s = \frac{1}{2}gt^2\]\)

Where s is the distance covered, g is the acceleration due to gravity and t is time of fall.

So, the distance covered by object A when it hits the bottom of the well can be calculated as:

s = (1/2)gt²

= (1/2)×10×1²

= 5m

Now, let us calculate the time it takes for object B to hit the bottom of the well.

Since both objects are dropped from the same location, the initial velocity of both will be zero.

The time taken for object B to hit the bottom can be calculated as follows:

180 = (1/2)×10×t²

⇒ t = 6 seconds

Now, we can use the same formula as before to calculate the distance covered by object B by the time object A hits the bottom:

s = (1/2)gt²

= (1/2)×10×6²

= 180 m

Therefore, object B will be at a distance of 180 m from the bottom of the well when object A hits the bottom.

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Step-by-step explanation:

The area of the given triangle shape is 7.5 cm^2.

We are given that;

Base=5

Height=3

Now,

A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse. The angle of a right angle is always 90 degrees.

The area of the triangle = 1/2 x b x h

Substituting the values

=1/2 * 3 * 5

=15/2

=7.5

Therefore, by the area answer will be 7.5 cm^2.

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The probability of exactly 3 of the containers being defective is given as 0.1468

We have to set p as the  probability of container being non- defective

We have p as the  probability of container being defective 50 - 10 = 40

p = 40/50

= 0.8

q = 10/50

= 0.2

P(3) = 8c3 * 0.2² * 0.8⁵

= 0.1468

Hence the probability that the container has exactly 3 defective containers is 0.1468

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Answer:

C

Step-by-step explanation:

Hopefully

C

I did it on edge hopefully this helps you and don't think i copied the other person

The volume of a sphere with a radius of 7 cm (or diameter of 12 cm) is 904.32 cubic centimeters.

To find the volume of a sphere with a radius of 7 cm, we can use the formula:

V = (4/3) * π * r^3

where V represents the volume and r represents the radius. However, you mentioned that the diameter of the sphere is 12 cm, so we need to adjust the radius accordingly.

The diameter of a sphere is twice the radius, so the radius of this sphere is 12 cm / 2 = 6 cm. Now we can calculate the volume using the formula:

V = (4/3) * π * (6 cm)^3

V = (4/3) * 3.14 * (6 cm)^3

V = (4/3) * 3.14 * 216 cm^3

V = 904.32 cm^3

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