Match these questions with the right letter answer choice
1. Large loops of gases
2. Occurs when the layer of our atmosphere are energized
3. An electrically charged mixture of electrons and protons
4. Sunspot regions suddenly connect releasing large amounts of heat and energy
5. When the solar wind affects Earth's upper atmosphere
A. Magnetic Storms
B. Prominence
C. Auroras
D. Solar Flare
E. Solar Wind

Answer:

12.34 amu

Explanation:

Let the 1st isotope be A

Let the 2nd isotope be B

Let the 3rd isotope be C

From the question given above, the following data were obtained:

1st Isotope (A):

Mass of A = 12.32 amu

Abundance (A%) = 19.5%

2nd isotope (B):

Mass of B = 13.08 amu

Abundance (B%) = 26.23%

3rd isotope (C):

Mass of C = 11.99 amu

Abundance (C%) = 54.27%

Atomic mass of X =?

The atomic mass of the element X can be obtained as follow:

Atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]

= [(12.32 × 19.5)/100] + [(13.08 × 26.23)/100] + [(11.99 × 54.27)/100]

= 2.402 + 3.431 + 6.507

= 12.34 amu

Thus, the atomic mass of the element X is 12.34 amu

Answer:

Step-by-step explanation: We are asked to find the distance covered by a man in 15 minutes at a speed of 16 km/hr. 15 minutes = 15/60 hour. Therefore, the person can run 4 km in 15 minutes.

Explanation:

Container 2 is a closed system because the mass did not change even

though the volume changed.

A closed system is the type of system which prohibits the transfer of

matter in and out the system.

In a closed system , the mass of the matter present is always the same

regardless of the changes which occurred which is why option D is the

most appropriate option.

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Solubility product of CaBz in terms of a, b and c is Ksp = [Ca2+][Bz–]2=ac2. The solubility product can be accurately calculated only when the solution is saturated.

a) Calculation of Solubility product of CaBz

Calculation of the solubility product of CaBz involves the use of initial and final concentrations. The dissolution of CaBz will result in the formation of Ca2+ and Bz–.Therefore, the expression for the solubility product of CaBz is given as Ksp = [Ca2+][Bz–]2=ac2

b) Significance of saturation

The solubility of a substance is determined by the tendency of the solute to dissolve in the solvent. However, the solubility limit may vary with temperature, pressure, and solvent properties. Saturated solutions contain the maximum amount of solute that can dissolve in a particular solvent. Therefore, in the lab experiment, the CaBz solution is saturated to ensure that the maximum amount of the substance is dissolved in the solvent. By saturating the solution, we ensure that the experimental values are close to the expected values. In addition, the solubility product can be calculated accurately only when the solution is saturated.



Solubility product of CaBz in terms of a, b and c is Ksp = [Ca2+][Bz–]2=ac2. The solubility product can be accurately calculated only when the solution is saturated.

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Many scientists are dependent on the government for funding for many reasons. One of the main reasons is that research is often too expensive to carry out without the help of the government. Option b)

The government plays a major role in scientific research, especially in areas of national interest. Government research funding plays an important role in promoting scientific inquiry and advancing knowledge of the natural world. The government is in charge of allocating research funds to public and private organizations. For scientists who want to carry out their research, it can be challenging to find funding from other sources, such as private companies.

As a result, the majority of researchers rely on government grants to finance their work. This dependence on government funding has advantages and disadvantages . One of the advantages is that it ensures that scientific research is carried out in areas that are of national interest. By prioritizing funding for specific areas, the government can direct research toward those issues that are considered important to the country. Another advantage is that it can lead to more innovation. Government grants often provide funding for research that might not be carried out otherwise, such as new technologies or techniques. This can result in breakthroughs that lead to new products, services, or ideas.However, there are also some disadvantages to being dependent on government funding. One of the main drawbacks is that it can lead to a lack of independence. Researchers who rely on government grants may feel obligated to focus on areas that the government deems important, rather than pursuing their own interests or those that are considered unconventional. Another disadvantage is that government funding can be unpredictable. Grants are usually awarded for a limited period of time and may be subject to budget cuts or changes in priorities. As a result, scientists may have to constantly seek new sources of funding or may be forced to abandon their research projects. Hence option b) is correct.

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Explanation:

this is a very easy question, you just need to know the formula of density, the mass and volume.

you're given the mass of the iron which is 28.5g and when it is submerged into a cylinder containing 45.50 ml, it rises to 49.10 ml. the volume of water displaced gives you the volume of the iron. thus,

V² - V¹ = 49.10 ml - 45.50 ml

V of iron = 3.6 ml

now that you know both the mass and volume, you can work out the question.

density (ρ) = mass / volume

ρ = m/v

ρ = 28.5 g / 3.6 ml

ρ = 7.916666...

ρ = 7.92 g/ml (3 sf)

hope this helps you!

- s.

At chemical equilibrium, the equilibrium constant of a chemical reaction is the value of its reaction quotient, a state proceeds by a dynamic chemical system after enough time has passed at which its composition has no quantifiable tendency towards further change.

To calculate the equilibrium constant (Kp) at \(3278^{0} C\), we can use the following equation:

\(Kp=(Pco)^{2} * PH^{2} /Pch^{2}oh\)

where P represents the partial pressure of each gas in the reaction. We can convert the concentrations given in the problem to partial pressures using the ideal gas law:

\(P = nRT/V\)

where n is the number of moles of gas, R is the gas constant, T is the temperature in Kelvin, and V is the volume. At equilibrium, the number of moles of each gas will be constant, so we can use the given concentrations to calculate the number of moles and then use the ideal gas law to find the partial pressures.
\([ch_{3} oh]=0.15M\)\(
\([co]=0.24M\)

\([h_{2} ]=1.1M\)

The molar mass of each gas is:

\(Mch_{3} oh=32.04g/mol\)
\(Mco=28.01g/mol\)
\(Mh_{2} =2.02g/mol\)

We can calculate the number of moles of each gas using the given concentrations and the volume of the system:

\(nch_{3} oh=0.15mol/L*1L=0.15mol\)

\(nco=0.24mol/L*1L=0.24mol\)
\(nh_{2} =1.1mol/L*1L=1.1mol\)

Using the ideal gas law, we can convert the number of moles to partial pressures:

\(Pch_{3} oh=nch_{3} oh*R*T/V=0.15mol*0.08206L atm/mol K*3551K/1L=4.73atm\)

\(Pco=nco*R*T/V=0.24mol*0.08206L atm/mol K*3551K/1L=7057atm\)
\(PH_{2} =nh_{2} *R*T/V=1.1 mol*0.08206Latm/molK*3551K/1L=34.98atm\)

Now we can plug these values into the equation for Kp:
\(kp=(Pco)^{2} *PH_{2} /Pch_{3} oh\)
\(p=(7.57atm)^{2} *2*34.98atm/4.73atm\)
kp=4.95*\(10^{4}\)

Therefore, the equilibrium constant (Kp) at \(3278^{0} C\) for the reaction \(ch_{3} oh_{1}  g_{2} mco_{1} g_{21} 2h_{2} 1g_{2}\) is \(4.95*10^{4}\).

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The H₂SO₄ (sulfuric acid) and HSO₄⁻ (hydrogen sulfate or bisulfate ion) are considered a conjugate acid-base pair. The correct answer is yes.

H₂SO₄ (sulfuric acid) and  HSO₄⁻ (hydrogen sulfate or bisulfate ion) form a conjugate acid-base pair. In the context of the Bronsted-Lowry theory, an acid donates a proton (H+), while a base accepts a proton. When H2SO4 donates a proton, it becomes  HSO₄⁻.

Conversely, when  HSO₄⁻ accepts a proton, it reforms H₂SO₄. They are interconnected through the transfer of a proton, thus qualifying as a conjugate acid-base pair. This relationship allows for the reversible conversion between the two species through proton transfer reactions. Therefore, yes, H₂SO₄ and HSO₄⁻ are considered a conjugate acid-base pair.

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2 covalent bonds

2 pairs or 4 electrons

The ionic equation for dissolution and the solubility product (ksp) expression for each of the following slightly soluble ionic compounds.

(a) For PbCl2:
Dissolution: PbCl2 (s) → Pb²⁺ (aq) + 2Cl⁻ (aq)
Ionic equation: PbCl2 (s) ⇌ Pb²⁺ (aq) + 2Cl⁻ (aq)
Solubility product (Ksp) expression: Ksp = [Pb²⁺][Cl⁻]²

(b) For Ag2S:
Dissolution: Ag2S (s) → 2Ag⁺ (aq) + S²⁻ (aq)
Ionic equation: Ag2S (s) ⇌ 2Ag⁺ (aq) + S²⁻ (aq)
Solubility product (Ksp) expression: Ksp = [Ag⁺]²[S²⁻]

(c) For Sr3(PO4)2:
Dissolution: Sr3(PO4)2 (s) → 3Sr²⁺ (aq) + 2PO₄³⁻ (aq)
Ionic equation: Sr3(PO4)2 (s) ⇌ 3Sr²⁺ (aq) + 2PO₄³⁻ (aq)
Solubility product (Ksp) expression: Ksp = [Sr²⁺]³[PO₄³⁻]²

(d) For SrSO4:
Dissolution: SrSO4 (s) → Sr²⁺ (aq) + SO₄²⁻ (aq)
Ionic equation: SrSO4 (s) ⇌ Sr²⁺ (aq) + SO₄²⁻ (aq)
Solubility product (Ksp) expression: Ksp = [Sr²⁺][SO₄²⁻]

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The location of a planet within the solar system influences its orbital characteristics, motion, and temperature, shaping its unique environmental conditions and behaviors.

Shape of orbit: The location of a planet determines the shape of its orbit around the Sun. Planets closer to the Sun, such as Mercury and Venus, have elliptical orbits with smaller eccentricities.

In contrast, planets farther from the Sun, like Mars and Jupiter, have more circular orbits. The shape of the orbit influences the planet's distance from the Sun at different points during its revolution, impacting factors such as temperature and intensity of sunlight.

Motion: The location of a planet affects its motion within the solar system. Planets closer to the Sun have higher orbital speeds, as they experience stronger gravitational forces.

They complete their orbits more quickly compared to planets farther away. Additionally, the location within the solar system determines the direction of a planet's motion—whether it orbits in the same direction as the Sun's rotation (prograde motion) or in the opposite direction (retrograde motion).

Temperature: The location of a planet in the solar system plays a significant role in determining its temperature. Proximity to the Sun affects the amount of solar radiation received by a planet.

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{9.47 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 15.730897...\)

We have the final answer as

Hope this helps you

Answer:

15.7 moles of Ar

Explanation:

Given data:

Number of atoms = 9.47 ×10²⁴ atoms

Number of moles of Ar = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

9.47 ×10²⁴ atoms × 1 mole / 6.022 × 10²³ atoms

1.57×10¹ mol

15.7 mol

The equilibrium constant of the second reaction is 0.155.

The equilibrium constant is a numerical value that shows the extent to which reactants are converted into products at a given temperature.

Now, we have the reaction; 3Z + Q ⇄ 2 X  and  4 X ⇄ 6 Z + 2 Q.

In the first reaction;

K =[ X]^2/[Z]^3 Q

In the second reaction;

[Z]^6 [Q]^2/[X]^4

Let [ X]^2 = A

[Z]^3 Q = B

Then the second reaction can be;

K = (B)^2/(A)^2 = (B/A)^2

The equilibrium constant of the second reaction therefore is; (1/2.54)^2

K = 0.155

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In terms of the energy change in the reaction, the negative value indicates that the reaction is exothermic as the reaction releases 1560.74 kJ of energy for every mole of C2H6 that reacts with 7/2 moles of O2.

The model of chemical energy changes is given below:

Balanced chemical equation:

C2H6 + 7/2 O2 → 2CO2 + 3H2O

Now, to calculate the energy change in the reaction, we will use a table of enthalpy values. The enthalpy change for each of the reactants and products is given in the table below:

Reactants:

C2H6: -84.68 kJ/mol

O2: 0 kJ/mol

Products:

CO2: -393.51 kJ/mol

H2O: -285.83 kJ/mol

The energy change in the reaction can be calculated using the formula:

ΔH = ∑(products) - ∑(reactants)

ΔH = [2(-393.51 kJ/mol) + 3(-285.83 kJ/mol)] - [-84.68 kJ/mol + 7/2(0 kJ/mol)]

ΔH = -1560.74 kJ/mol

Therefore, the energy change in the reaction is -1560.74 kJ/mol.

To create a model of the energy change in the reaction, we can use an energy level diagram. In this diagram, the energy of the reactants is shown on the left, the energy of the products is shown on the right, and the activation energy is shown as a barrier between them.

The energy level diagram for this reaction is shown below:

Reactants (C2H6 + 7/2 O2)

                |

                |

       Activation energy

                |

                |

Products (2CO2 + 3H2O)

As shown in the diagram, the reactants have a higher energy level than the products, and the activation energy is required to get the reaction started.

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Answer:

Chlorine hope i helped.

Explanation:

Answer:

bbbbnnnnnnnnnnnnnnn

Explanation:

Then 2520 ounces of solution z contains ounces of a is 876 ounces.

given that ;

x contains a and b in the ratio = 2:3

y contains a and b in the ratio = 1:2

z contains the a and b in the ratio 3:11, that, means in 14 parts of solution.

therefore, 2520 ounces solution of z,

x = ( 2520 × 3 ) / 14 = 540

y =  ( 2520 × 11 ) / 14 = 1980

x = 540 (2/5) = 216

y = 1980 / 3 = 660

thus, One ounce of solution x contains only ingredients a and b in a ratio of 2:3. One ounce of solution y contains only ingredients a and b in a ratio of 1:2. If solution z is created by mixing solutions x and y in a ratio of 3:11, then 2520 the ounces of solution of z = 876

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Since ethanol has a more symmetrical structure than methanol and iso-propanol, it would be expected to have a lower heat of vaporization than the other two molecules.

At one of the temperatures used in the Clausius Clapeyron plot, the calculation of the heat of vaporization is as follows:

At 80°C (352 K), the heat of vaporization of ethanol is 41.9 kJ/mole.

The normal boiling point of ethanol is 78.3°C (351.45 K), which is higher than methanol (64.7°C, 337.85 K) but lower than iso-propanol (82.5°C, 355.65 K). This can be attributed to the fact that the molecules of ethanol have a more symmetrical structure than methanol and iso-propanol, which makes them more stable and thus easier to vaporize. This is because the forces of attraction between the molecules of ethanol are weaker than those between the molecules of methanol and iso-propanol, making it easier for ethanol molecules to escape from the liquid

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A. the expansion occurs isothermally and reversibly -27.9 J/K mol, the expansion occurs isothermally against a constant external pressure of 1.00 atm. -27.9 J/K mol and the expansion occurs adiabatically and reversibly 37.1 ln(T f/300) J/K mol.

Pressure is the force applied perpendicular to the surface of an object per unit area. It is typically measured in units of Pascals (Pa) or pounds per square inch (psi). Pressure is an important concept in many fields such as physics, engineering, and fluid mechanics.

a. ds = R ln(P f/P i) = R ln (1/5) = -27.9 J/K mol

ds surr = 0 J/K mol

ds univ = -27.9 J/K mol

b. ds = R ln(P f/P i) = R ln(1/5) = -27.9 J/K mol

ds surr = 0 J/K mol

ds univ = -27.9 J/K mol

c. ds = cp ln(T f/Ti ) = 37.1 ln(T f/300) J/K mol

ds surr = 0 J/K mol

ds univ = 37.1 ln(T f/300) J/K mol

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The modify in include up to entropy (ΔS_univ) is the aggregate of the entropy changes of the system and the environment, so ΔS_un

a. Isothermal and reversible advancement:

In an isothermal handle, the temperature remains relentless. Since CO2 carries on in a culminated world, we are ready to utilize the ideal gas law: PV = nRT, where P is the weight, V is the volume, n is the number of moles, R is the ideal gas steady, and T is the temperature.

In this case, the beginning conditions are P1 = 5.00 atm, V1 (beginning volume) darkens, n = 1.00 mole, and T = 300 K. The extreme conditions are P2 = 1.00 atm and V2 (final volume) is cloud.

Since the strategy is reversible, the alter in entropy (ΔS) is given by ΔS = nR ln(V2/V1). Utilizing the ideal gas law, we are going forward with it as ΔS = nR ln(P1/P2).

Utilizing the values, we have ΔS = (1.00 mole) * (8.314 J K^(-1) mol^(-1)) * ln(5.00 atm/1.00 atm) = 9.21 J K^(-1).

Since the expansion is isothermal, there's no temperature differentiate between the system and the environment, so ΔS_surr = 0.

The modify in add up to entropy (ΔS_univ) is the complete of the entropy changes of the system and the environment, so ΔS_univ = ΔS + ΔS_surr = 9.21 J K^(-1).

b. Isothermal improvement against a unfaltering exterior weight:

In this case, the exterior weight is reliable and rise to to the extreme weight (1.00 atm). The strategy is still isothermal, so the temperature remains reliable.

Utilizing the same condition as in parcel a, we have ΔS = nR ln(P1/P2). Ceasing inside the values, we get ΔS = (1.00 mole) * (8.314 J K^(-1) mol^(-1)) * ln(5.00 atm/1.00 atm) = 9.21 J K^(-1).

Since the expansion is against a steady exterior weight, the environment do work on the system, and the surroundings' entropy modify (ΔS_surr) is given by ΔS_surr = -w_surr/T, where w_surr is the work done by the environment. In this case, since the strategy is isothermal, the work done is w_surr = -PΔV = -PΔnRT.

Change in enthropy (ΔS) = -(1.00 atm) multiplied by (1.00 mole) multiplied by (8.314 J K^(-1) mol^(-1)) multiplied by ln(5.00 atm/1.00 atm) / 300 K = -0.0308 J K^(-1).

The change in entropy (ΔS_univ) = 9.18 J K^(-1).

c. Adiabatic and reversible expansion:

In an adiabatic handle, there's no warm exchange between the system and the environment, so ΔS = 0.

The change in entropy of the environment (ΔS_surr) in addition since no warm is traded.

The modify in include up to entropy (ΔS_univ) is the aggregate of the entropy changes of the system and the environment, so ΔS_un

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There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, the given statement is Slightly true.

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound.  Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.

The formula of an ionic compound starts with a metal and that of a molecular compound starts with a nonmetal. The statement is Slightly true.

Therefore, the given statement is Slightly true.

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Answer:

Ka = 9.2x10⁻⁷

Explanation:

The equilibrium of carbonic acid in water is:

H₂CO₃ ⇄ HCO₃⁻ + H⁺

Where Ka is defined as:

Ka = [HCO₃⁻] [H⁺] / [H₂CO₃]

The equilibrium concentration of the species is:

[H₂CO₃] = 1.9x10⁻² - X

[HCO₃⁻] = X

[H⁺] = X

As pH is -log[H⁺]

3.88 = -log[H⁺]

1.318x10⁻⁴ = [H⁺] = X

Replacing:

[H₂CO₃] = 1.9x10⁻² - 1.318x10⁻⁴ = 1.8868x10⁻²

[HCO₃⁻] = 1.318x10⁻⁴

[H⁺] = 1.318x10⁻⁴

Replacing in ka equation:

Ka = [1.318x10⁻⁴] [1.318x10⁻⁴] / [1.8868x10⁻²]

Answer: 9.2 x 10^-7

Explanation:

The Kelvin temperature at which the vapor pressure will be 6.50 times higher than it was at 289 K is approximately 322 K.

The Clausius-Clapeyron equation relates the vapor pressure of a substance to its enthalpy of vaporization and the temperature. It can be expressed as:

ln(P2/P1) = (ΔHvap/R) x (1/T1 - 1/T2)

where P1 and P2 are the vapor pressures at temperatures T1 and T2, respectively, ΔHvap is the enthalpy of vaporization, R is the gas constant, and ln denotes the natural logarithm.

We can use this equation to solve the problem. Let P1 be the initial vapor pressure at T1 = 289 K, and let P2 be the vapor pressure we want to find at T2. We are given that P2 is 6.50 times higher than P1, so we can write:

P2/P1 = 6.50

Taking the natural logarithm of both sides gives:

ln(P2/P1) = ln(6.50)

Next, we substitute the given values into the Clausius-Clapeyron equation and solve for T2:

ln(6.50) = (ΔHvap/R) x (1/289 K - 1/T2)

ΔHvap for the substance is given as 48.85 kJ/mol, and R is the gas constant, which is 8.314 J/mol·K. Therefore, we have:

ln(6.50) = (48.85 kJ/mol / 8.314 J/mol·K) x (1/289 K - 1/T2)

Simplifying the right-hand side, we get:

ln(6.50) = (5.878 mol/K) x (T2 - 289 K)

Dividing both sides by 5.878 mol/K, we obtain:

(T2 - 289 K) = ln(6.50) / 5.878 mol/K

Solving for T2, we get:

T2 = (ln(6.50) / 5.878 mol/K) + 289 K

Plugging in the values, we get:

T2 = (1.871 / 5.878) + 289 K

T2 = 322 K (rounded to three significant figures)

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Answer:

Explanation:

This is because,

Chlorine atoms (Cl2) displaces with Bromine atoms (Br) in Sodium bromide (2NaBr) solution to give a result as, Sodium Chloride (2NaCl) and left out atom Bromine (Br)

Answer:

0.3549

Explanation:

the percentage yield is the percentage of the product formed based on the theoretical yield.in this question the percentage yield and theoretical yield have been given all that's left is the actual yield.so you use the formula

percentage yield=theoretical yield/actual yield×100

83.4=0.296/ay×100

83.4ay/83.4=100×0.296/83.4

ay=0.3549

I hope this helps

Answer:

D: Na

Explanation:

Hope this helps!

Have a nice day!!

:D

The calcium ion has 18 protons, 20 neutrons, and 20 electrons.
The relationship between the components a and b is Inverse proportion.


The calcium ion (Ca2+) has a 2+ charge, indicating that it has lost 2 electrons from its neutral state. To determine the number of protons, neutrons, and electrons in the calcium ion, we need to consider its atomic number and mass.

The atomic number of calcium is 20, which indicates that it has 20 protons. Since the calcium ion has a 2+ charge, it means it has lost 2 electrons. Therefore, the number of electrons in the calcium ion is 20 - 2 = 18.

The mass number of calcium is 40 amu, which represents the total number of protons and neutrons. Since the calcium ion has 20 protons, the number of neutrons can be calculated as 40 - 20 = 20.

So, the correct option is: d. 18 protons, 20 neutrons, and 20 electrons

In the expression a∼1/b, the relationship between the components a and b is an inverse proportion. This means that as the value of a increases, the value of b decreases, and vice versa. The symbol ∼ represents the proportional relationship between a and 1/b, indicating that they are inversely related. Therefore, the correct answer is: Inverse proportion

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Answer:

N/A

Explanation:

Is this a true or false answer or.....?

The concentration of a solution is the amount of solute dissolved in the solvent. In order to calculate the concentration of the sodium acetate solution in table 1 (question 2 above). Answer: The concentration of the sodium acetate solution in table 1 is 0.120 M.

We need to use the formula of Molarity, which is: `Molarity = moles of solute / liters of solution where moles of solute are the number of moles of the solute present in the solution. Here, we have been given the mass of sodium acetate and we need to find the number of moles of the solute present in the solution. We can use the molar mass of the solute for this. The molar mass of sodium acetate is 82.03 g/mol. Hence, number of moles of NaCH3COO present = mass of solute / molar mass of solute= 2.35 g / 82.03 g/mol= 0.0286 mol.

Now, let's calculate the volume of solution. We have been given the mass of the solution which is 249.8 g. We know that density = mass/volume of solution. Hence, volume of solution = mass of solution / density of solution = 249.8 g / 1.05 g/cm³= 237.5 mL= 0.2375 L. Therefore, the concentration of the sodium acetate solution is given by; Molarity = number of moles / liters of solution Molarity = 0.0286 mol / 0.2375 L= 0.120 M

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The pH of a solution made by dissolving 13.7 g of HCl in 643 ml of water is 2.23.

The pH of a solution made by dissolving 13.7 g of hydrochloric acid (HCl) in 643 ml of water can be calculated using the following steps:

1. Calculate the molarity of the solution. This is done by dividing the amount of HCl (13.7 g) by the molar mass of HCl (36.46 g/mol), which gives us 0.376 mol of HCl. Then, divide this number by the volume of the solution (643 ml), which gives us a molarity of 0.00587 mol/L.

2. Calculate the pH of the solution. This is done by using the expression pH = -log[H+], where [H+] is the concentration of hydrogen ions in the solution. Taking the negative logarithm of 0.00587 mol/L gives us a pH of 2.23.

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