meter = the basic measure of length in the metric system
milli- = prefix meaning one-thousandth (.001)
percieve = to be aware though the senses
standard unit = reference point from which all other measurements are made
metric system = a decimal system of weights and measures
Physical Science Essential Question: How can the scientific process be used to help us investigate and understand natural phenomena? Elaborate: Challenge students to pretend they are on the scientific journey to develop a vaccine to stop the zombie apocalypse and they need to design an experiment as a result of working in a laboratory. Ask the students to write 2-3 paragraphs describing what they would test and why might this be important in science and the real world. They might need to include the following terms: Experimental design
Test variable
•Outcome
•Control variable
•Hypothesis
•Testable
•Graphs and charts
Answer:
It C 100% bc i alrweady learn this
A 1300 kg sports car can accelerate from 0 to 27 m/s in 5.2 seconds. How much power from the engine is directly going into accelerating the car? Group of answer choices 474,000 W 3375 W 35,100 W 91,100 W
The power expended is calculated as 91,100 W.
What is the power?We know that the acceleration can be obtained by the use of the equation;
v = u + at
v = final velocity
u = initial velocity
t = time
a = acceleration
a= v - u/t
a = 27 - 0/ 5.2 = 5.2 m/s^2
Thus;
v^2 = u^2 + 2as
but u= 0 m/s
v^2 = 2as
s = v^2/2a
s = (27)^2/2 * 5.2
s = 70 m
Now;
Work done = 1300 kg * 5.2 m/s^2 * 70 m = 473200 J
Power = 473200 J/5.2 seconds
Power = 91,100 W
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How can you determine the velocity of a runner from a position time graph?
Answer:
below
Explanation:
The slope of the position-time graph is the velocity at any point in time
This Constitutional right forbids Congress from sending a person to prison__
Explain what this Constitutional right is:___
The formation and operation of prisons, as well as inmates' rights, are governed by federal and state regulations. Although prisoners may not have full constitutional rights, the Eighth Amendment's restriction on cruel and unusual punishment protects them.
An object dropped from rest, what will its velocity be after 30 s?
An object dropped from rest, its velocity be 294 m/s in downward direction after 30 s .
Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them.
initial velocity = u = 0
time = t = 30sec
g = acceleration due to gravity = 9.8 \(m/s^{2}\)
using equation of kinematics
v = u - g*t
v = 0 - 9.8 * 30
v = - 294 m/s
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A hot reservoir at 50oC is connected to a cold reservoir at -60oC by a cylindrical, thermal conductor. The thermal conductor has a constant radius of 5 cm, but is made up of two different metals. The first portion of the conductor, made of aluminum, is 8 cm long and has a thermal conductivity of 205 W/mK and is in contact with the hot reservoir. The second portion of the conductor, made of brass, is 10 cm long and has a thermal conductivity of 109 W/mK, and is in contact with the cold reservoir. (a) What is the temperature at the junction between the aluminum and brass
In order to calculate the temperature at the junction between the aluminum and brass in the given problem, we will use the concept of Thermal Conduction. Thus, for steady-state conduction, the rate of heat conduction between two ends of the conductor is the same as the temperature difference between them.
The rate of heat flow is given by;Q = kA (T1 - T2) / LwhereQ = rate of heat flowk = thermal conductivityA = cross-sectional areaT1 - T2 = temperature differenceL = length of the conductorIn the given problem;Q = kA (T1 - T2) / LFor the first portion of the conductor made of aluminum;Q1 = k1A1 (T1 - T) / L1.
Where Q1 is the heat flow rate through the aluminum, k1 is the thermal conductivity of aluminum, A1 is the cross-sectional area of aluminum, T1 is the temperature of the hot reservoir, T is the unknown temperature of the junction, and L1 is the length of aluminum.
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A sound wave, with an intensity of 50 w/cm2, strikes a boundary and is totally reflected. What is the intensity reflection coefficient (irc)?
The intensity reflection coefficient (irc) is 1.
What is the intensity reflection coefficient (irc)?The ratio of the intensity of the reflected wave to the incident (transmitted) wave is known as the intensity reflection coefficient.
Intensity of incident (transmitted) sound wave = 50 W/cm².
As it is totally reflected, intensity of the reflected sound wave = 50 W/cm².
Hence, intensity reflection coefficient =
intensity of the reflected sound wave ÷ Intensity of incident sound wave
= 50 W/cm² / 50 W/cm².
= 1.
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What is the mass of an object that accelerates at 5 m/s2 when pushed with 100 N?
Answer:
the answer is 20g
Explanation:
Data:
acceleration:5m/s2
force:100N
mass:?
solution:
force: mass*acceleration
mass: force divided by acceleration
mass:100/5
mass:20g
or another way of solving it is
force: mass*acceleration
100:mass*5
100/5 : mass
20g:mass
12. a) What is the gravitational attraction of the sun
on the earth? (b) of the earth on the sun?
Answer:
About 3.54x1022 N.
Explanation: The gravitational force between the Sun and the Earth is about 3.54x1022 N. This force keeps the Earth orbiting around the Sun. The gravitational force from the other planets does slightly affect the Earth's orbit, but the gravitational pull from the other planets and the Moon is still very small. Sorry if I get this wrong. I am in 5th grade! ♥
State Schrodinger equation.
Hi!Schrodinger equation is written as HΨ = EΨ, where h is said to be a Hamiltonian operator.
Ben worked 3 hours at x dollars per hour. Julie worked 7 hours and earned twice as much as Ben per hour. Phil worked 12 hours and earned 5 dollars an hour less than Julie. Choose the expression that is correctly simplified and best represents their total wages.
29x – 5
29x – 60
22x – 5
41x – 60
Answer:
D) 41x - 60
Explanation:
You need to find the total wages of each person and add them together.
- Ben worked 3 hours at x dollars per hour so his total is: 3x
- Julie worked 7 hours but got 2x per hour so her total is: 7(2x) = 14x.
- Phil worked 12 hours and earned 2x-5 per hour. The 2x is how much Julie earned and Phil gets 5 dollars less than that, his total is: 12(2x - 5) = 24x - 60.
Now we add them all together: 3x + 14x + 24x - 60 = 41x - 60
the coefficient of performance of a residential heat pump is 1.6. calculate the heating effect in kj/s this heat pump will produce when it consumes 2 kw of electrical power.
The heating effect in with the residential heat pump will be 3.2 KJ/s
Heat pump - mechanical device which convert heat from low temperature to high temperature reservoir with the use of external work.
Heating effect - it is the change of electrical energy which passes through the conductor into heat energy.
The rate of heat produced. \(Q_{H}\) is calculated by
The coefficient of residential heat pump = 1.6
The consume of electric power = 2kw
The rate of heat produced.( \(Q_{H}\)) =
The coefficient of performance × consume of electric power
\(Q_{H}\) = 1.6 × 2
= 3.2 KJ/s
The heating effect in with the residential heat pump will be 3.2 KJ/s
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When the mass of a simple pendulum is tripled, the time required for one complete vibration is:.
The time required for one complete vibration of a simple pendulum is affected by various factors, including the length of the pendulum and the gravitational acceleration. However, the mass of the pendulum does not affect the time required for one complete vibration. Therefore, if the mass of a simple pendulum is tripled, the time required for one complete vibration remains the same. This is because the period of a pendulum depends solely on the length of the pendulum and the gravitational acceleration, as derived from the formula T = 2π√(l/g), where T is the period, l is the length of the pendulum, and g is the gravitational acceleration. Therefore, increasing the mass of the pendulum does not affect its period.
Hi! When the mass of a simple pendulum is tripled, the time required for one complete vibration remains the same. The time period of a simple pendulum is given by the formula T = 2π√(L/g), where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity. As you can see, the mass of the pendulum does not appear in this formula, so changing the mass does not affect the time required for one complete vibration.
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Two cars approach each other. How does the
speed of one car relative to the other com-
pare with speed of each car relative to the ground
ground?
Answer:
The car's fast. The ground isn't moving.
Hope this helped! :D
Can someone help me
Answer:
C?
Explanation:
Show that on a hypothetical planet having half the diameter of the Earth but twice its density, the acceleration of free fall is the same as on Earth.
Answer:
Steps include:
Find the ratio between the mass of this hypothetical planet and the mass of planet earth.Calculate the ratio between the acceleration of free fall (gravitational field strength) near the surface of that hypothetical planet and near the surface of the earth.Assumption: both planet earth and this hypothetical planet are spheres of uniform density.
Explanation:
Mass of that hypothetical planetLet \(M_0\), \(r_0\), and \(\rho_0\) denote the mass, radius, and density of planet earth.
The radius and density of this hypothetical planet would be \((1/2)\, r_0\) and \(2\, \rho_0\), respectively.
The volume of a sphere is \(\displaystyle V = \frac{4}{3}\, \pi\, r^3\).
Therefore:
The volume of planet earth would be \(\displaystyle V_0 = \frac{4}{3}\, \pi\, {r_0}^{3}\).The volume of this hypothetical planet would be: \(\displaystyle V = \frac{4}{3}\, \pi\, \left(\frac{r_0}{2}\right)^3 = \frac{1}{6}\, \pi\, {r_0}^3\).The mass of an object is the product of its volume and density. Hence, the mass of the earth could also be represented as:
\(\displaystyle M_0 = \rho_0\, V_0 = \frac{4}{3}\, \pi\, {r_0}^{3}\, \rho_0\).
In comparison, the mass of this hypothetical planet would be:
\(\begin{aligned}M &= \rho\, V\\ &= (2\, \rho_0) \cdot \left(\frac{1}{6}\, \pi\, {r_0}^3\right) \\ &= \frac{1}{3}\, \pi\, {r_0}^{3}\, \rho_0 \end{aligned}\).
Compare these two expressions. Notice that \(\displaystyle M = \frac{1}{4}\, M_0\). In other words, the mass of the hypothetical planet is one-fourth the mass of planet earth.
Gravitational field strength near the surface of that hypothetical planetThe acceleration of free fall near the surface of a planet is equal to the gravitational field strength at that very position.
Consider a sphere of uniform density. Let the mass and radius of that sphere be \(M\) and \(r\), respectively. Let \(G\) denote the constant of universal gravitation. Right next to the surface of that sphere, the strength of the gravitational field of that sphere would be:
\(\displaystyle g = \frac{G \cdot M}{r^2}\).
(That's the same as if all the mass of that sphere were concentrated at a point at the center of that sphere.)
Assume that both planet earth and this hypothetical planet are spheres of uniform density.
Using this equation, the gravitational field strength near the surface the earth would be:
\(\displaystyle g_0 &= \frac{G \cdot M_0}{{r_0}^2}\).
.
On the other hand, the gravitational field strength near the surface of that hypothetical planet would be:
\(\begin{aligned}g &= \frac{G \cdot (M_0/4)}{{(r_0/2)}^2} = \frac{G \cdot M_0}{{r_0}^2}\end{aligned}\).
Notice that these two expressions are equal. Therefore, the gravitational field strength (and hence the acceleration of free fall) would be the same near the surface of the earth and near the surface of that hypothetical planet.
As a side note, both \(g\) and \(g_0\) could be expressed in terms of \(\rho_0\) and \(r_0\) alongside the constants \(\pi\) and \(G\):
\(\begin{aligned}g &= \frac{G \cdot M}{r^2}\\ &= \frac{G \cdot (1/3)\, \pi\, {r_0}^3 \, \rho_0}{(r_0/2)^2} = \frac{4}{3}\,\pi\, G\, r_0\, \rho_0\end{aligned}\).
\(\begin{aligned}g_0 &= \frac{G \cdot M_0}{{r_0}^2}\\ &= \frac{G \cdot (4/3)\, \pi\, {r_0}^3 \, \rho_0}{{r_0}^2} = \frac{4}{3}\,\pi\, G\, r_0\, \rho_0\end{aligned}\).
What is angle of incidence?
The angle of incidence is a measure of how much a light or sound wave deviates from a straight line when it hits a surface. It is the angle between the incoming wave and the surface normal, which is a line perpendicular to the surface.
In physics, the angle of incidence is an important concept in optics and acoustics. For example, in optics, the angle of incidence is used to determine the angle of reflection and refraction when light hits a surface. A larger angle of incidence will result in a larger angle of reflection or refraction.
In addition, the angle of incidence also affects how much of the incoming wave is absorbed or transmitted by the surface. When the angle of incidence is very small, most of the wave is transmitted and only a small portion is absorbed. But as the angle of incidence increases, more of the wave is absorbed and less is transmitted. This is why the angle of incidence is often used to calculate how much of a light or sound wave is absorbed or transmitted by a surface.
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draw the following vector quantity Using the coordinate system.
a. 190 newton east
b. 120km/hr, 250 north of east
c. 60 meters southwest
The given vectors quantities can be described by their properties of both
magnitude and direction.
a. The drawing of the vector extending from point (0, 0) to (190, 0) on the coordinate plane is attached.b. The velocity vector extending from (0, 0) to (108.76, 50.714) on the coordinate plane is attached.c. The displacement vector extending from (0, 0) to (30·√2, 30·√2) is attached.Reasons:
a. The magnitude of the vector = 190 N
The direction in which the vector acts = East
Therefore, in vector form, we have;
\(\vec{F}\) = 190 × cos(0)·i + 190 × sin(0)·j = 190·i
The vector can be represented by an horizontal line, 190 units long
Coordinate points on the vector = (0, 0) and (190, 0)
The drawing of the vector with the above points using MS Excel is attached.
b. Magnitude of the velocity vector = 120 km/hr. 25° North of east
Solution;
The vector form of the velocity is; \(\vec{v}\) = 120 × cos(25)·i + 120×sin(25)·j, which gives;
\(\vec{v}\) = 120 × cos(25)·i + 120×sin(25)·j ≈ 108.76·i + 50.714·j
\(\vec{v}\) ≈ 108.76·i + 50.714·j
Therefore, points that define the vector are; (0, 0) and (108.76, 50.714)
The drawing of the vector is attached
c. The magnitude of the vector = 60 m
The direction of the vector is southwest = West 45° south
The vector form of the displacement is \(\vec{d}\) = 60 × cos(45°)·i + 60 × sin(45°)·j
Which gives;
\(\vec{d}\) = 30·√2·i + 30·√2·j
Points on the vector are therefore; (0, 0), and (30·√2, 30·√2)
The drawing of the vector is attached
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i) The energy stored in wound watch spring is
a) K.E
b) P.E
c) Heat Energy
d) Chemical Energy
Answer:
Springs when non compressed has potential energy.
One Newton is equivalent to
A. 1 kg/s2
B. 1 kg*m/s
C. 1 kg*m/s2
D. 1 kg/s
Answer:
B
Explanation:
On October 17, 2006, the population of the United States reached 300. Million. If all of those people jumped up in the air simultaneously, pushing Earth with an average force of 800. N each for a time of 0.10 s, what would happen to the 5.98 1024 kg Earth? Show a calculation that justifies your answer.
Answer:
Generally it shows that the Earth will attain a velocity of
\(v= 4.0133*10^-15 m/s\)
Explanation:
From the question we are told that
Total Number N=300
Force=800
Time=0.10s
Weight of Earth \(W=5.98*10^24kg\)
Generally the equation for Impulse is Force *Time
\(Impulse =Force *Time\)
And
\(Force *Time=Change\ in\ momentum\)
Therefore
\(300*10^6*800*0.1 = 5.98*10^24*v\)
\(v= \frac{300*10^6*800*0.1}{5.98*10^2^4}\)
\(v= \frac{2.4*10^1^0}{5.98*10^2^4}\)
\(v= 4.01*10^-15 m/s\)
Generally it shows that the Earth will attain a velocity of
\(v= 4.0133*10^-15 m/s\)
(hrwc11p41) a man stands on a platform that is rotating (without friction) with an angular speed of 2.0 rev/s; his arms are outreached and he holds a weight in each hand. the rotational inertia of the system of man, weights, and platform about the central axis is 7.00 kg m2. if by moving the weights the man decreases the rotational inertia of the system to 4.06 kg m2, what is the resulting angular speed of the platform?(rad/s)
The resulting angular speed of the platform is 3.04 rad/s, which is higher than the initial speed of 2.0 rev/s.
This increase in angular speed can be explained by the conservation of angular momentum, which states that the total angular momentum of an isolated system remains constant unless acted upon by external torques.
In this case, the man decreases the system's rotational inertia by moving the weights closer to his body, which decreases the moment of inertia and increases the angular velocity to conserve angular momentum.
This can be expressed mathematically as I1ω1 = I2ω2, where I1 and ω1 are the initial rotational inertia and angular velocity, respectively, and I2 and ω2 are the final rotational inertia and angular velocity, respectively. Solving for ω2 gives the resulting angular velocity of 3.04 rad/s.
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PLEASE DO ASAP WILL GIVE BRAINLIEST!!!
An initially neutral and non-polarized conducting rod is moving to the right at a constant speed v through a large region that has a uniform magnetic field, as shown above. Which of the following statements correctly describes the motion of the particles within the rod and the resulting charge separation in the rod caused by this motion?
(A) Positively charged particles within the rod moved downward, causing the bottom of the rod to have a positive charge and the top to have a negative charge.
(B) Negatively charged particles moved upward, causing the bottom of the rod to have a positive charge and the top to have a negative charge.
(C) Positively charged particles moved upward, causing the top of the rod to have a positive charge and the bottom of the rod to have a negative charge.
(D) Negatively charged particles moved downward, causing the top of the rod to have a positive charge and the bottom of the rod to have a negative charge.
Answer:
C
Explanation:
(C) Positively charged particles moved upward, causing the top of the rod to have a positive charge and the bottom of the rod to have a negative charge.
When a neutral and non-polarized conducting rod moves through a magnetic field, it will experience a force known as the Lorentz force. This force acts on the moving charges within the rod, and causes them to move perpendicular to both the direction of motion and the magnetic field. In this case, since the rod is moving to the right, and the magnetic field is pointing into the screen, the Lorentz force will act upward on the positively charged particles within the rod. This motion will cause a separation of charges in the rod, with the top having a positive charge and the bottom having a negative charge.
A book weighing 10 kg is preparing to fall off the desk from a 1 meter height. The book's
gravitational potential energy is 980 Joules.
O True
O False
Answer:
False
Explanation:
gravitational potential energy = mgh
10*10*1 = 100 joules
If a net force acts on an object, the object may change speed, change direction or do neither.
True
False
Answer:
False
Explanation:
A net force on an object causes acceleration or a change in direction....not 'neither'
It is false that if a net force acts on an object, the object may change speed, change direction or do neither. Details about motion can be found below.
What is Newton's law of motion?Newton's first law of motion also called law of inertia states that an object will remain at rest until it is acted upon by an external force.
This law suggests that an object will change direction or speed when acted upon by a net force.
Therefore, it is false that if a net force acts on an object, the object may change speed, change direction or do neither.
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Please help!! Energy work!
need help asap, thank you !
In the absence of air resistance, a projectile launched at an angle of 33 above the horizontal will have the same range as a projectile launched at which of the following angles? O 38 O 57⁰ 0:45. 07
A projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰. The correct option is (B) 57⁰.
In the absence of air resistance, a projectile launched at an angle of 33 above the horizontal will have the same range as a projectile launched at an angle of 57⁰.
The range of a projectile can be determined by using the range formula.
R = ((v^2 * sin(2θ))/g) Where
R is the range of the projectile,
v is the velocity of the projectile,
θ is the angle at which the projectile is launched, and
g is the acceleration due to gravity.
In the absence of air resistance,
the horizontal component of velocity of a projectile remains constant throughout the flight.
So, the range of a projectile depends only on its initial velocity and the angle at which it is launched.
If a projectile is launched at an angle θ,
the time of flight of the projectile can be calculated by using the following formula:
T = (2v * sin(θ))/g
The maximum height reached by the projectile is given by the formula:
H = (v^2 * sin^2(θ))/2gIf a projectile is launched at an angle θ, then the range of the projectile will be the same as the range of the projectile launched at an angle of (90 - θ).
So, if a projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰.
Therefore, the correct option is (B) 57⁰.
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Would you want to minimize or maximize the heat transfer to and from the handrails? Explain your reasoning.
Answer:
minimize some of the steel and the handrails would be a lot more safer for the children
Explanation:
I would like to minimize the heat transfer from the handrails because when it is decrease, the friction will increase.
What is Heat transfer?
Any or all of a number of events, referred to as processes, known as heat transfer, are capable of moving energy + entropy from one place to another. Typically, convection, nonlinear thermal, etc. conduction are used to describe specific methods. It involves the slow, energy- and entropy-transfer-involved process of conduction between adjacent molecules.
A hot fluid, such as air, must move during convective; this process is typically quite quick.
Radiation is indeed the term for the electromagnetic radiation that is used to describe how energy is transferred from its emission at a heated surface to its absorption on that other surface without a medium.
The reason behind minimizing the heat transfer from the handrails is because when the heat transfer is decreased, the friction in the rails will increase, and it will be easy to hold them for support.
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20 POINTS!!! The photograph shows a the result of waves made by an earthquake.
What was transported to this location by the earthquake waves?
A. Gravity
O B. Energy
C. Rock
D. Matter
Answer:
It's B = Energy ....
i hope its right
An electron (charge -e) is at rest in a region of electric potential that varies as a function of position. When released it will move A. into a region of lower potential B. into a region of higher potential c. along an equipotential line D. in the direction of the electric field E. in the direction perpendicular to the electric field F. not at all
An electron (charge -e) is at rest in a region of electric potential that varies as a function of position. When released it will move A. into a region of lower potential.
Since the electric potential varies as a function of position, there will be regions of higher and lower potential energy. The electron will move from a region of higher potential energy to a region of lower potential energy. Therefore, the electron will move into a region of lower potential The direction of the electric field is perpendicular to the equipotential lines. Therefore, the electron will move in the direction of the electric field if the equipotential lines are not parallel to the electric field.
If the equipotential lines are parallel to the electric field, the electron will move perpendicular to the electric field. In summary, the electron will move into a region of lower potential while following the direction of the electric field or moving perpendicular to it depending on the orientation of the equipotential lines. So therefore the correct answer is An electron (charge -e) is at rest in a region of electric potential that varies as a function of position. When released it will move A. into a region of lower potential.
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