Formation of crystals of sugar from a sugary syrup is a …….
chemical change
It's a chemical change.
Explanation:-
Formation of crystals of sugar from a sugary syrup is a chemical change. Because, we cannot get sugary syrup back from the sugar crystals. Yet, it is chemical change.
Question 7 of 10
When naming a molecule, how do you indicate that the carbons on either side
of the double bond are pointing in opposite directions?
OA. Use the prefix cis-.
OB. Use the prefix methyl-.
OC. Use the number 2 as a prefix.
OD. Use the prefix trans-.
Answer:
by using the prefix trans
Explanation:
i hope you find it helpful
a) Explain what is meant by anisotropic refinement
Answer:
ok
Explanation:
In anisotropic refinement, this motion is fitted as an ellipsoid, the center of which lies inside the circle of motion, while the atom is loated on its periphery. This effect makes the bond distance appear shorter.
(answer is from go0gle not gonna say its lie)
Tamika studies the rock layers. She says that during some times in the past the area was covered by water
Tamika claims that the area was once submerged in water, indicating that she is researching the rock formations in an attempt to understand the geological history of the area.
Rock strata reveal important details about Earth's ancient habitats, including whether or not any bodies of water were present. By evaluating the characteristics of sedimentary rocks, such as their composition, texture, and the existence of specific fossils or sedimentary structures, Tamika can draw inferences about the past conditions of the region. Indicators indicating the area was originally submerged under water include the presence of marine fossils, wave patterns, or cross-bedding in rock layers.
Overall, Tamika's analysis of the rock layers sheds light on the region's geological past, including the presence of water and changes in sea level over time.
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A food stall owner was preparing dough for making bhatura. He added a pinch of yeast and sugar to the dough and left it in a warm place. After a few hours, the dough had risen. There was our sell too.
1. Why did the dough rise?
2. Why did the dough smell sour?
3. Why was sugar added to the dough? 4.What would have happened if the dough was kept in the refrigerator, soon after it prepared?
Explanation:
yeast and sugar was present
Why do all elements have their own unique color? Please explain.
All the element have their own unique color because the every element have their own set of energy levels.
According to the bohr model of atoms : electrons exist at certain energy levels. when we give heat to electron , it gets excited and moves from lower energy level to higher energy level. the electron is less stable in higher energy level. when an electron returns from higher energy level to lower energy level it emits some energy in form of radiation. The wavelength of light depends upon energy level . and every elements have their own unique energy levels. The color for different element is different.
Thus, All the element have their own unique color because the every element have their own set of energy levels.
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Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if th
coefficient is "1."
✓CO₂ +H₂O<—CH3OH +0₂
Answer: \(\boxed{2}\text{ CO}_{2}+\boxed{4}\text{ H}_{2}\text{O} \longrightarrow \boxed{2} \text{ CH}_{3}\text{OH}+\boxed{3} \text{ O}_{2}\)
Balancing a chemical reaction involves having equal number of atoms of all elements involved in the reaction on both sides of the arrow.
The given unbalanced equation is
CH₃OH + O₂ → CO₂+ H₂O
In this reaction, the number of atoms of oxygen and carbon are equal on both sides. However, the number of hydrogen atoms is greater on the reactants side and lesser on the products side.
Thus, we have to balance the number of hydrogen atoms while also keeping equal the number of atoms of carbon and oxygen.
Thus, the balanced reaction is given as:
2CH₃OH + 3O₂ → 2CO₂+ 4H₂O
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The reaction 2Mg(s) + O2(g) --> 2MgO(s) is a
Group of answer choices
double-replacement reaction.
decomposition reaction.
synthesis reaction.
single-replacement reaction.
Answer:
Double-Replacement Reaction
Explanation:
Mg is Oxidized, and O2 is the cause of the oxidation, hence the Oxidizing agent. That means that O2 is Reduced and Mg is the cause naming it the Reducing agent.
OIL - RIG Oxidation is Loss-Reduction is Gain
The decomposition of cyclohexane to benzene and Martialism is a high mass transfer limited period on the planet. The reaction will be carried out in a tubular reactor with an internal diameter of 5 cm and a length of 20 m; the pipes are filled with cylindrical pellets 0.5 cm in diameter and 0.5 cm in length. The pellets are only covered with the outer surface coating. The filled bed porosity is 40%. The inlet flow rate is 60 dm3/min.
Plot the tubular length vs. conversion graph when the inlet gas stream contains 5% cyclohexane and 95% hydrogen at 2 atm and 500°C. What would be the required tubular length for 99.9% conversion?
For cyclohexane diffusion in hydrogen, use the Fuller, Schettler, and Giddings Correlation given below.
The required tubular length for 99.9% conversion is 116.84 meters.
On Earth, the rate at which cyclohexane reacts with benzene and methylcyclopentane is constrained by high mass transfer.
A tubular reactor with an internal diameter of 5 cm and a length of 20 m will be used to conduct the reaction, and cylindrical pellets with dimensions of 0.5 cm in diameter and 0.5 cm in length will be placed within the reactor's pipes.
Only the exterior surface of the pellets are coated.
The packed bed has a 40% porosity and a 60 dm3/min intake flow rate.
When the intake gas stream includes 5% cyclohexane and 95% hydrogen at 2 atm and 500°C, the tubular length vs. conversion graph should be drawn.
The graph may be used to identify the minimum length of tube necessary for 99.9% conversion.
For cyclohexane diffusion in hydrogen, the Fuller, Schettler, and Giddings Correlation is as follows:
a = 0.8854,
b = 1.764102,
C = 6.0231023.
The tube length vs. conversion graph may be displayed at 2 atm and 500°C when the incoming gas stream includes 5% cyclohexane and 95% hydrogen.
The following equation may be used to determine the rate of reaction:
ra=2.31011 exp[-88580/RT]C_A(1X)/3
The mole balancing equation for an isothermal tubular reactor is given as
dX/dL = -ra/C A,
where X is the conversion and L is the length.
To determine the length of the tubular reactor needed for a specific conversion X, we can integrate the aforementioned equation from X = 0 to X = X.
We must numerically calculate the following equation to obtain the necessary tube length for 99.9% conversion:
∫0.999L0−ra/CA
dL=0.999XEq L
for X=0.999
After rearranging the equation above, we get:
0.999L0ra/CA
dL=XX Eq
The aforementioned equation is integrated to give us
L = 116.84 m.
Therefore, the required tubular length for 99.9% conversion is 116.84 meters.
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What frequency does a photon of wavelength 4.5 x 10-4 m have?
A. 6.67 x 1011 Hz
B. 1.47 x 10-30 Hz
C. 2.98 x 10-37 Hz
D. 1.35 x 105 Hz
SUBMIT
Answer:
6.67* 1011 Hz
Explanation:
a p e x
Answer:
Awnser above is correct
Explanation:
a. 6.67
Hello. Need help answering this question.
A sample of Zn(s) is reacted with HCl(aq) to form hydrogen gas. The H2 gas bubbles out of aqueous solution and is collected in a 670.0 mL container at 576.0 Torr and 25 C. How many grams of zinc reacted?
0.04 grams of zinc reacted
The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as
PV = nRT
where,
P = Pressure
V = Volume
T = Temperature
n = number of moles
Given,
Volume = 670 ml = 0.67L
Pressure = 576 torr
Temperature = 25 degree celsius
PV = nRT
576 × 0.67 = n × 62.36 × 298
n = 0.02 moles
mass = moles × molar mass
= 0.02 × 2 = 0.04g
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How many grams of solid potassium chlorate (KCIO3) decompose to form solid
potassium chloride and 790 mL of oxygen gas at 111 °C and 770 torr? (3 sf)
Answer:
1.95 g KClO3
Explanation:
We're asked to find the mass, in g, of KClO3 that decomposes to give a certain amount of O2.
Let's use the ideal gas equation to find the moles of O2 that form.
P=747torr(1latm760torr)=0.983 atmV=797mL(1lL103mL)=0.797
LT=128oC+273=401 KPlugging in known values, we haven=PVRT=(0.983atm)(0.797L)(0.082057L∙atmmol∙K)(401K)=0.0238 mol O2
Now, we'll use the coefficients of the chemical equation to find the relative number of moles of KClO3 that reacted:0.0238mol O2(2lmol KClO33mol O2)=0.0159 mol KClO3
Finally, we'll use the molar mass of potassium chlorate (122.55 g/mol) to find the number of grams that reacted:
0.0159mol KClO3(122.55lg KClO31mol O2)=1.95 g KClO3
Explain the process of photosynthesis in a plant in detail.
HURRY IM TIMED im doing khoot 2 minutes LEFT
Photosynthesis is the process by which green plants and some other organisms convert light energy from the sun into chemical energy in the form of glucose (sugar) and oxygen. It occurs in the chloroplasts of plant cells, specifically in the thylakoid membranes and stroma.
The process of photosynthesisThe overall process of photosynthesis can be broken down into two stages:
Light-Dependent Reactions:The first stage of photosynthesis is the light-dependent reactions, which occur in the thylakoid membranes of the chloroplasts. In this stage, light energy from the sun is absorbed by pigments such as chlorophyll, which is found in the thylakoid membranes.
The absorbed light energy excites electrons in the pigments, which are then passed through a series of electron carriers called the electron transport chain (ETC). As the electrons are passed down the ETC, they release energy that is used to pump protons (H+) across the thylakoid membrane and into the thylakoid space, creating a proton gradient.
The byproduct of the light-dependent reactions is oxygen (O2), which is released into the atmosphere.
Light-Independent Reactions:The second stage of photosynthesis is the light-independent reactions, also known as the Calvin cycle or the dark reactions. These reactions occur in the stroma of the chloroplasts.
In this stage, the ATP and NADPH produced in the light-dependent reactions are used to power the conversion of carbon dioxide (CO2) into glucose (C6H12O6). The process begins with the fixation of CO2 into an organic molecule called ribulose bisphosphate (RuBP), which is catalyzed by the enzyme rubisco.
The overall equation for photosynthesis can be summarized as follows:
6CO2 + 6H2O + light energy → C6H12O6 + 6O2
In this equation, carbon dioxide and water are converted into glucose and oxygen, with the help of light energy. This process is vital to life on Earth, as it provides the primary source of energy for all living organisms.
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identify the alkene that can be converted into trans-1-ethyl-2-propylcyclopropane via a simmons-smith reaction.
The alkene that can be converted into trans-1-ethyl-2-propylcyclopropane via a Simmons-Smith reaction is 1-pentene.
A Simmons-Smith reaction involves the use of a reagent called diiodomethane (CH2I2) and a metal such as zinc to form a carbene intermediate that can react with alkenes to form cyclopropanes. In this case, 1-pentene can react with diiodomethane and zinc to form trans-1-ethyl-2-propylcyclopropane.
The reaction proceeds via a cyclic intermediate, where the carbene adds across the double bond of 1-pentene to form a cyclopropane ring. The resulting product has a trans configuration due to the stereochemistry of the reaction.
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write down structures for three isomers of hexane
Answer:
Three isomers of hexane are: 2-methylpentane, 3-methylpentane, and 2,3-dimethylbutane.
They are constitutional isomers because they each contain exactly the same number and type of atoms, in this case, six carbons and 14 hydrogens and no other atoms.
Explanation:
Hope it helps.
Problem 1. What masses of 15% and 20% solutions are needed to prepare 200 g of 17% solution?
Problem 2. What masses of 18% and 5% solutions are needed to prepare 300 g of 7% solution?
Problem 3. 200 g of 15% and 350 g of 20% solutions were mixed. Calculate mass percentage of final solution.
Problem 4. 300 g of 15% solution and 35 g of solute were mixed. Calculate mass percentage of final solution.
Problem 5. 400 g of 25% solution and 150 g of water were mixed. Calculate mass percentage of final solution.
Problem 1:
we need 80 g of the 15% solution and 120 g of the 20% solution.
Let x be the mass of the 15% solution needed and y be the mass of the 20% solution needed.
x + y = 200 (total mass of the two solutions)
0.15x + 0.2y = 0.17(200) (total amount of solute in the two solutions)
Solving these equations, x = 80 g and y = 120 g.
Therefore, we need 80 g of the 15% solution and 120 g of the 20% solution.
Problem 2:
we need 120 g of the 18% solution and 180 g of the 5% solution.
Let x be the mass of the 18% solution needed and y be the mass of the 5% solution needed.
x + y = 300
0.18x + 0.05y = 0.07(300)
Solving these equations, x = 120 g and y = 180 g.
Therefore, we need 120 g of the 18% solution and 180 g of the 5% solution.
Problem 3:
The mass percentage of the final solution is 135 g/550 g × 100% = 24.55%.
The total mass of the final solution is 200 g + 350 g = 550 g.
The total amount of solute in the final solution is:
0.15(200 g) + 0.20(350 g) = 65 g + 70 g = 135 g.
Therefore, the mass percentage of the final solution is 135 g/550 g × 100% = 24.55%.
Problem 4:
The mass percentage of the final solution is 110 g/335 g × 100% = 32.84%.
The total mass of the final solution is 300 g + 35 g = 335 g.
The total amount of solute in the final solution is:
0.15(300 g) + 35 g = 75 g + 35 g = 110 g.
Therefore, the mass percentage of the final solution is 110 g/335 g × 100% = 32.84%.
Problem 5:
The mass percentage of the final solution is 18.18%.
Calculate the final mass of the solution:
Final mass = 400 g + 150 g = 550 g
Calculate the mass of solute in the 25% solution:
Mass of solute = 0.25 x 400 g = 100 g
Calculate the mass percentage of the final solution:
Mass percentage = (mass of solute ÷ final mass) x 100%
Mass percentage = (100 g ÷ 550 g) x 100%
Mass percentage = 18.18%
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Heredity Lab Report Instructions:
In the Heredity lab, you investigated how hamsters inherit traits from their parents. Record your observations in the lab report below. You will submit your completed report.
Name and Title: Include your name, instructor's name, date, and name of lab.
Objective(s): In your own words, what was the purpose of this lab?
Hypothesis: In this section, please include the if/then statements you developed during your lab activity.
These statements reflect your predicted outcomes for the experiment.
Test One: If I breed a short fur, FF female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Two: If I breed a short fur, Ff female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Three: If I breed a long fur, ff female with a long fur, ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Procedure: The procedures are listed in your virtual lab. You do not need to repeat them here.
Please be sure to identify the test variable (independent variable) and the outcome variable (dependent variable) for this investigation. Remember, the test variable is what is changing in this investigation.
The outcome variable is what you are measuring in this investigation.
Test variable (independent variable): Outcome variable (dependent variable): Data: Record the data from each trial in the data chart below. Be sure to fill in the chart completely. Test One Parent 1: FF Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Two Parent 1: Ff Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Three Parent 1: ff Parent 2: ff Phenotype ratio: ________ : ________ short fur : long fur Conclusion: Your conclusion will include a summary of the lab results and an interpretation of
For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2
What are the phenotype ratios from the test crosses?For Test One:
Parent 1: FF (homozygous dominant for short fur)
Parent 2: Ff (heterozygous for short fur)
The Punnett square for this cross will give the following genotype ratios:
FF : Ff = 1 : 1
And the corresponding phenotype ratios will be:
Short fur : Long fur = 2 : 0 or 100% short fur
For Test Two:
Parent 1: Ff (heterozygous for short fur)
Parent 2: Ff (heterozygous for short fur)
The Punnett square for this cross will give the following genotype ratios:
FF : Ff : ff = 1 : 2 : 1
And the corresponding phenotype ratios will be:
Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur
For Test Three:
Parent 1: ff (homozygous recessive for long fur)
Parent 2: ff (homozygous recessive for long fur)
The Punnett square for this cross will give the following genotype ratios:
ff : ff = 1 : 0
And the corresponding phenotype ratios will be:
Short fur : Long fur = 0 : 2 or 100% long fur
For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.
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what is the PH scale of 0.02m of hydrochloric acid
Answer:
Explanation:
The pH of 0.02 M hydrochloric acid is approximately 1.7.
THANKS
IF THE ANSWER IS CORRECT , THEN MARK ME AS BRAINLIST
if 9.00g grams of gas are enclosed in a 50.00 L vessel at 273.15K and 2.000 atmospheres of pressure , what is the molar mass of the gas? what gas is this?
Answer: 4.88 g/mol. and helium
Explanation:
To find the molar mass of the gas, we can use the ideal gas law equation which is PV=nRT where:
P = pressure = 2.000 atm
V = volume = 50.00 L
n = number of moles
R = gas constant = 0.08206 L·atm/K·mol
T = temperature = 273.15 K
First, we need to find the number of moles of the gas:
PV = nRT
n = PV/RT
n = (2.000 atm)(50.00 L)/(0.08206 L·atm/K·mol)(273.15 K)
n = 1.844 mol
Now, we can find the molar mass of the gas by dividing its mass by the number of moles:
molar mass = mass/number of moles
mass = 9.00 g
molar mass = 9.00 g/1.844 mol
molar mass = 4.88 g/mol
Therefore, the molar mass of the gas is 4.88 g/mol.
To determine what gas this is, we can compare the molar mass of the gas to the molar masses of known gases. The molar mass of 4.88 g/mol is closest to that of helium (4.00 g/mol). Therefore, this gas is most likely helium.
A 3.90 L sealed vessel under vacuum is filled with 6.40 g of fluorine gas. What is the pressure (in kPa) of the vessel at 25.0 ⁰C ?
From the ideal gas law, the pressure of the gas is 106 kPa.
First we must obtain the number of moles of the gas;
Number of moles = mass/molar mass
Molar mass of fluorine gas = 38 g/mol
Number of moles of F2 = 6.40 g/38 g/mol = 0.168 moles
Using the ideal gas equation;
PV = nRT
P = ?
V = 3.90 L
n = 0.168 moles
T = 25.0 ⁰C + 273 = 296 K
R = 8.314 kPa L K-1 mol-1
Substituting values;
P = nRT/V
P = 0.168 moles × 8.314 kPa L K-1 mol-1 × 296 K/3.90 L
P = 106 kPa
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The pressure of the vessel at a temperature of 25 °C is 106.73 KPa
We'll begin by calculating the number of mole of fluorine gas. This can be obtained as follow:
Mass of F₂ = 6.40 g
Molar mass of F₂ = 19 × 2 = 38 g/mol
Mole of F₂ =?Mole = mass / molar mass
Mole of F₂ = 6.40 / 38
Mole of F₂ = 0.168 moleFinally, we shall determine the pressure. This can be obtained as follow:
Volume (V) = 3.90 L
Temperature (T) = 25.0 °C = 25 + 273 = 298 K
Mole of F₂ (n) = 0.168 mole
Gas constant (R) = 8.314 L.KPa/Kmol
Pressure (P) =?PV = nRT
P × 3.9 = 0.168 × 8.314 × 298
P × 3.9 = 416.232096
Divide both side by 3.90
P = 416.232096 / 3.90
P = 106.73 KPaTherefore, the pressure of the vessel is 106.73 KPa
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please help me ASAAAAAAAAAAAP
Identify the Arrhenius acid and the Arrhenius base in this reaction.
H2SO4 + 2NaOH → Na2SO4 + 2H2O
Question 35 options:
Na2SO4(acid), 2H2O(base)
H2SO4(acid), NaOH(base)
NaOH(acid), Na2SO4(base)
H2SO4(acid), Na2SO4(base)
Answer:
H2SO4(acid), NaOH(base)
Explanation:
9. A brand of gasohol (gasoline containing alcohol)
contains 10.% ethanol by volume. How many
milliliters (mL) of ethanol are in a 0.750-gallon
sample of the gasohol? (1 gall = 3.785 L)
(A) 283.875 mL
(B) 280 mL
(C) 0.284 mL
(D) 2.8 x 10-4 mL
283.875 mL of ethanol are in a 0.750gallon sample of the gasohol. Therefore, the correct option is option A.
What is ethanol?Ethanol, sometimes known as ethyl alcohol, is a chemical liquid having the formula C2H5OH. Its primary application is as a solvent. To comprehend the chemical composition of ethanol, you must first grasp what alkenes are.
Alkenes are carbon and hydrogen molecules containing at at least one double bond between two carbons. Ethene is an example of an alkene.
1 gall = 3.785 L
0.750gallon =?
0.750gallon ×3.785 L / 1 gallon
= 2838.75 ml
10% of 2838.75 ml= 283.875 mL
Therefore, the correct option is option A.
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If an experiment produces 5 g but should have made 500 g, what is the percent
yield?
Answer:
Percentage of yield = 1%
Explanation:
Given:
Amount of yield = 5g
Total amount of product = 500 gram
Find:
Percentage of yield = ?
Computation:
⇒ Percentage of yield = [Amount of yield / Total amount of product]100
⇒ Percentage of yield = [5g / 500g]100
⇒ Percentage of yield = [0.01]100
⇒ Percentage of yield = 1%
Higher temperatures tend to increase the rate of a chemical reaction because
a. the particles have greater momentum and therefore have higher energy collisions.
b. the particles are more likely to behave as a catalyst and lower the activation energy.
c. the particles move faster and therefore collide more often.
d. the particles have greater attractions and therefore collide with the correct orientation.
Answer:
b
Explanation:
Higher temperatures tend to increase the rate of a chemical reaction because the particles move faster and therefore collide more often.
What is rate of reaction?Rate of reaction tells about the speed of the reaction or at what duration of time a reaction gets completed.
When we increases the temperature of any chemical reaction, then the kinetic energy of the molecules increases, due to which they move fast in the chemical reaction. Due to this random and fast movement molecules get collide with each other rapidly and easily form the product.
Hence option (c) is correct i.e. particles move faster and therefore collide more often when temperature increases.
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NEED HELP FIGURING HOW MANY MOL!! PLEASE QUICK!!THANK YOU SO MUCH
The number of moles of the gas by the ideal gas law is 0.18 moles.
What is the ideal gas law?The behavior of an ideal gas, a hypothetical gas made up of randomly moving particles with little volume and no intermolecular interactions, is described by the ideal gas law.
Although intermolecular interactions and non-zero particle volume prevent gases from always behaving in an ideal manner, the ideal gas law is nevertheless a good approximation for many gases under some circumstances.
We know that;
PV = nRT
We have ;
P = 1.2 atm
V = 3.4 L
T = 10 + 273 = 283 K
n = ?
n = PV/RT
n = 1.2 * 3.4/0.082 * 283
n =4.08 /23.2
n = 0.18 moles
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The rust that is formed on the building is made of a compound that contains the element iron. There are several properties that can be used to describe iron. Iron has a melting point of 1583oC, metallic luster, a density of 7.87 g/cm3, reacts with acids, silver in color, and reacts with oxygen to form rust. Which of these properties would be considered a chemical property? A) silver B) metallic luster C) reacts with acids D) density of 7.87g/cm3
In the process of rusting of iron from the above given options reaction with acid is the only chemical property and all the others are physical properties.
Rusting of iron is an example of a redox reaction. In this reaction Iron reacts with oxygen in the presence of water to form rust. The oxidizing ingredient in this oxidation process is oxygen. Along with oxidation reaction, reduction process also takes place in which the metal iron acts as a reducing agent since oxygen also reacts with it.
From the above given options we can say that Metallic luster, density etc are the physical properties. Where as reaction with acids is the chemical property that is mentioned.
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How many moles in 5 grams?
Answer:
The molar mass of atoms of an element is given by the standard relative atomic mass of the element multiplied by the molar mass constant
Explanation:
For the reaction 2 Cr(s) + 3 Pb²⁺(aq) ⟶ 3 Pb(s) + 2 Cr³⁺(aq), what is the value of n in the Nernst equation?
Answer:
The value of n is 6
Explanation:
The half-reactions of the problem are:
Cr(s) → Cr³⁺ + 3e⁻
Pb²⁺ + 2e⁻→ Pb(s)
To balance the electrons we must multiply the half-reactions as follows:
2 * (Cr(s) → Cr³⁺ + 3e⁻)
3 * (Pb²⁺ + 2e⁻→ Pb(s))
2Cr(s) → 2Cr³⁺ + 6e⁻
3Pb²⁺ + 6e⁻→ 3Pb(s)
In Nernst equation, the value of n are the electrons used to balance the reaction, as in this problem, the electrons are 6:
The value of n is 6Where does thermal energy go? Assuming you forgot your hot food and came after a while and found it cold now. Where did the energy go?
Aqueous hydrobromic acid (HBr) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium bromide (NaBr) and liquidwater (H₂O). Suppose 0.81 g of hydrobromic acid is mixed with 0.568 g of sodium hydroxide. Calculate the maximum mass of sodiumbromide that could be produced by the chemical reaction. Round your answer to 2 significant digits.
Explanation:
Aqueous hydrobromic acid (HBr) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium bromide (NaBr) and liquid water (H₂O). They will react according to the following equation.
HBr + NaOH ---> NaBr + H₂O
0.81 g of HBr are mixed with 0.568 g of NaOH. We have to find the mass of NaBr that can be produced. To do that we have to find which of the reactants is limiting the reaction. First, we will convert their grams into moles using their molar masses.
molar mass of HBr = 80.91 g/mol
molar mass of NaOH = 40.00 g/mol
mass of HBr = 0.81 g
mass of NaOH = 0.568 g
moles of HBr = 0.81 g * 1 mol/(80.91 g)
moles of HBr = 0.0100 moles
moles of NaOH = 0.568 g * 1 mol/(40.00 g)
moles of NaOH = 0.0142 moles
HBr + NaOH ---> NaBr + H₂O
Now if we take a quick look at the coefficients of the reaction we will see that 1 mol of HBr will react with 1 mol of NaOH since both coefficients are 1. Then their molar ratio is 1 : 1. That also means that 0.0100 moles of HBr will only react with 0.0100 moles of NaOH, and we have mixed 0.0142 moles of it. So, NaOH is in excess and HBr is the limiting reagent.
1 mol of HBr : 1 mol of NaOH molar ratio
moles of NaOH = 0.0100 moles of HBr * 1 mol of NaOH/(1 mol of HBr)
moles of NaOH = 0.0100 moles < 0.0142 moles ----> NaOH is in excess
And now that we know that HBr is the limiting reagent we can find the number of moles of NaBr that will be produced by 0.0100 moles of HBr. And finally convert those moles into grams using the molar mass.
1 mol of HBr : 1 mol of NaBr molar ratio
moles of NaBr = 0.0100 moles of HBr * 1 mol of NaBr/(1 mol of HBr)
moles of NaBr = 0.0100 moles
molar mass of NaBr = 102.89 g/mol
mass of NaBr = 0.0100 moles * 102.89 g/mol
mass of NaBr = 1.0289 g
mass of NaBr = 1.0 g
Answer: the maximum mass of sodium bromide that could be produced is 1.0 g.