Marvin is moving furniture in his house , including the 52.8 kg dresser. he is applying a force of 90 N to the left to overcome 24 N of friction to accelerate the dresser.
1. What is the horizontal acceleration of the dresser?(value only, round to two decimal places, no units, or direction. example: 97.50)
Answers
Answer: 3.81 m/s^2.
Explanation: use the equation for acceleration, which is a = (F - f)/m. In this case, we are given the force applied by Marvin (F), the force of friction (f), and the mass of the dresser (m). Plugging in the given values, we get a = (90 N - 24 N)/(52.8 kg) = 3.81 m/s^2.
Related Questions
The first step to merging is entering the ramp and _____.
A. honking to indicate your location
B. matching your speed
C. signaling your intent
D. telling your passengers where you're going
Answers
Answer:
B. matching your speed
Explanation:
To merge safely, you must identify a gap in traffic and match your speed to the speed of the gap. Before you make your move to fill the gap, you should signal your intent.*
_____
* At least one resource says "The first step ... is to make sure you're traveling at the same speed ..." Then it goes on to say "Use your indicator. Do it early ...." The accompanying animation shows blinkers being activated on the ramp before the merge lane is entered. Apparently, "the first step" is not necessarily the first thing you do.
Answer:
It's C "signaling your intent"
Explanation:
The key thing to look at is they are asking the rest of the first step and that;s C
the fastest tennis service by a man is 246,2 km.hr-1 by Andy Roddick of the United States of America during a match in London in 2004. Calculate the ball's momentum if it has a mass of 58 g?
Answers
Answer:
Approximately \(3.967\; {\rm kg\cdot m\cdot s^{-1}}\).
Explanation:
Convert velocity to the standard units (meters per second):
\(\begin{aligned}v &= 246.2 \; {\rm km \cdot h^{-1}} \\ &= 246.2 \; {\rm km \cdot h^{-1}}\times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &\approx 68.389\; {\rm m\cdot s^{-1}}\end{aligned}\).
Convert mass to standard units (kilograms):
\(\begin{aligned} m &= 58\; {\rm g} \\ &= 58\; {\rm g} \times\frac{1\; {\rm kg}}{1000\; {\rm g}}\\ &= 0.058\; {\rm kg}\end{aligned}\).
When an object of mass \(m\) travels at a velocity of \(v\), momentum of that object would be \(p = m\, v\). In standard units, the momentum of this tennis ball would be:
\(\begin{aligned}p &= m\, v \\ &\approx (0.058\; {\rm kg})\, (68.389\; {\rm m\cdot s^{-1}}) \\ &\approx 3.967\; {\rm kg \cdot m\cdot s^{-1}}\end{aligned}\).
When carbon bonds with oxygen,
what
gas is formed?
When carbon bonds with oxygen, what gas is formed?
Answers
Answer:
Carbon dioxide
Explination:
I remember it from biology.
I hope this helps ^-^
In a chemical reaction, carbon combines with oxygen to form carbon dioxide gas.
What is a chemical reaction?A chemical reaction can be defined as a process that causes the chemical transformation of one chemical substance to another. The chemical reactions accompany chemical changes that involve the rearrangement of electrons in the forming and breaking of bonds between atoms, with no change to the nuclei.
The substances which are primarily involved in a reaction are known as reactants or reagents. Chemical reactions are commonly characterized by a chemical change, and yield products, which exhibit properties different from the reactants.
Chemical reactions take place at a characteristic rate of reaction at a given temperature, pressure, and chemical concentration. The rates increase with the increasing temperature of the reaction when more thermal energy is available to achieve the activation energy for breaking bonds between atoms.
The combustion reaction takes place when carbon combines with oxygen to produce carbon dioxide gas.
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Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
Answers
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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Consider the following water circuit: water is continually pumped to high pressure by a pump, and then funnelled into a pipe that has lower pressure at its far end (else the water would not flow through the pipe) and back to the pump. Two such circuits are identical, except for one difference: the pipes in one circuit have a larger diameter than the pipes in the other circuit. Through which circuit is the flow of water greater
Answers
Answer:
The circuit with the larger diameter pipes will have higher water flow.
Explanation:
The flow rate can be calculated with this formula, \(Q = v.A\) , where \(v\) is the velocity of the water flow and \(A\) is the cross-sectional area of the pipe. Considering the two circuits are identical except only for the diameter of the pipes, the flow of water will be greater through the circuit with the larger diameter pipes. It will be proportional with respect to the square of the pipe's diameter.
I hope this answer helps.
An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike
Answers
The airplane will strike the ground at a horizontal distance of 490 meters.
To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.
The horizontal distance traveled by an object can be calculated using the formula:
Distance = Speed × Time
In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.
Distance = 100 m/s × t
Now, to find the value of time, we can rearrange the equation as follows:
t = Distance / Speed
t = 490 m / 100 m/s
t = 4.9 seconds
Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.
Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:
Distance = Speed × Time
Distance = 100 m/s × 4.9 s
Distance = 490 meters
It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.
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Which of the following is a disadvantage of hybridization? 1.offspring are genetic copies of the parent 2.offspring are stronger and larger than the parents 3.offspring have a combination of traits from both parents 4.offspring often have health problems and are sterile
Answers
Answer:
Explanation:
4 is right
5. A hammer is dropped from the top of atower that is 400 m high. If we neglect airresistance so that the only force on thehammer is gravity, with what velocity doesthe hammer strike the ground?
Answers
We wil have the following:
First, we will determine the travel time:
\(400m=(0m)+(0m/s)t+\frac{1}{2}(9.8m/s^2)t^2\Rightarrow t^2=\frac{2(400m)}{(9.8m/s^2)}\)\(\Rightarrow t^2=\frac{4000}{49}s^2\Rightarrow t=\frac{20\sqrt[]{10}}{7}s\)\(\Rightarrow t\approx9.0s\)Now, we find the velocity after that time:
\(v=(0m/s)+(9.8m/s^2)(20\sqrt[]{10}/7s)\Rightarrow v=28\sqrt[]{10}m/s\)\(\Rightarrow v\approx88.5m/s\)So, it will have approximately 88.5 m/s.
A net force F acts on a mass m and produces an acceleration a. What acceleration results if a net force 4F acts on a mass 6m?
Answers
Answer: The acceleration results if a net force of 4F acts on a mass of 6m is 2/3a.
Explanation:
Force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is:
F= mass( kg) × acceleration( m/ s²)
Acceleration is defined as the rate at which the velocity of an object changes. From the formula of force given above it can be determined by making it the subject of formula. Therefore acceleration= Force/ mass.
From the question,
Force= 4F
Mass= 6m
Therefore acceleration= F/m
= 4/6
Acceleration= 2/3a
The required magnitude of acceleration when force is 4F and mass is 6m is 2/3a.
Given data:
The magnitude of net force is, 4F.
The value of mass is, 6m.
Apply the Newton's second law which says that force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is
F = ma
a = F/m ..........................................(1)
here, a is the acceleration.
Solving as when the force becomes 4F and mass becomes 6m.
\((4F) = (6m) \times a'\\\\a '= \dfrac{4F}{6m}\\\\a '= \dfrac{2}{3}a\)
Thus, the required magnitude of acceleration when force is 4F and mass is 6m is 2/3a.
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i give good amount of points
Answers
(a) The acceleration of the object when it travels 5 m is 2 m/s².
(b) The time taken for the object to travel the first 12 m is 3.46 seconds.
(c) The work done in displacing the object 12 m is 48 J.
(d) The speed of the object at a displacement of 12 m is 6.92 m/s.
(e) The speed of the object at a displacement of 12 m is zero.
What is the acceleration of the object?
The acceleration of the object is calculated as follows;
a = F / m
when the object travels 5 m, the force = 4 N
a = 4 N / 2 kg
a = 2 m/s²
The time taken for the object to travel the first 12 m is calculated as follows;
t = √ (2s / a )
where;
s is the distancet = √ (2 x 12 / 2 )
t = 3.46 seconds
The work done in displacing the object 12 m is calculated as follows;
W = Fd
W = 4 N x 12 m
W = 48 J
The speed of the object at a displacement of 12 m is calculated as;
v = at
v = 2 m/s² x 3.46 s
v = 6.92 m/s
At a displacement of 20 m, the acceleration of the object is zero, hence the velocity is zero.
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Electromagnetic waves from the sun carry what to the earth
Answers
Answer:
Solar radiation
Explanation:
Visible light, ultraviolet light, infrared, radio waves, X-rays, and gamma rays.
==> Energy
==> Radio noise, heat, visible light, ultraviolet radiation, X-rays, gamma rays
==> They carry all these kinds of energy wherever they go. Not only to the Earth.
Someone help me please
Answers
Answer:
A
Explanation:
u = 180
v = 0
t = 20
a = 180 /20
9
since they deceleration question itself no need toshow - sign so
A
Calculate the kinetic energy of a 790-kg roller coaster traveling at a velocity of 20.7 m/s.
Answers
Answer:
The answer is 169253.55 joules
Answer:
\(\displaystyle KE = 169254 \ J\)
General Formulas and Concepts:
Energy
Kinetic Energy Formula: \(\displaystyle KE = \frac{1}{2}mv^2\)
KE is kinetic energy (in J)m is mass (in kg)v is velocity (in m/s)Explanation:
Step 1: Define
[Given] m = 790 kg
[Given] v = 20.7 m/s
Step 2: Solve
Substitute in variables [Kinetic Energy Formula]: \(\displaystyle KE = \frac{1}{2}(790 \ kg)(20.7 \ m/s)^2\)[KE] Evaluate exponents: \(\displaystyle KE = \frac{1}{2}(790 \ kg)(428.49 \ m^2/s^2)\)[KE] Multiply: \(\displaystyle KE = (395 \ kg)(428.49 \ m^2/s^2)\)[KE] Multiply: \(\displaystyle KE = 169254 \ J\)A small heat engine has an energy input of 1,176 joules, and does 201 joules of work. What is the efficiency of the engine? (round your answer to the nearest whole number percent, but leave off the % symbol)
so, if you calculate it is 13.3%, enter your number as 13.
Answers
The efficiency of the engine is 17%.
Given the following data:
Energy input = 1,176 JoulesEnergy output = 201 JoulesTo find the efficiency of the engine:
Mathematically, the efficiency of an engine is calculated by using the formula:
\(Efficiency = \frac{E_O}{E_I}\) × \(100\)
Where:
Eo is the energy output.Ei is the energy input.Substituting the given parameters into the formula, we have;
\(Efficiency = \frac{201}{1176}\) × \(100\)
\(Efficiency = 0.171\) × \(100\)
Efficiency = 17%
Therefore, the efficiency of the engine is 17%.
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A Ping-Pong ball is shot into a circular tube that is lying flat (horizontal) on a table-top.
Figure attached.
When the Ping-Pong ball exits the tube, which path will it follow in the figure?
d
a
c
b
e
Answers
Answer:
e
Explanation:
An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
Answers
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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what are two ways to advance basketball down the Court
Answers
having a plan and listening to your coach
When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?
Answers
The skater's final angular velocity is approximately 9.86 rad/s.
The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Initially, the skater has an angular momentum of:
L_initial = I_initial * ω_initial
Substituting the given values:
L_initial = 2.12 kg m² * 3.25 rad/s
The skater's final angular momentum remains the same, as angular momentum is conserved:
L_final = L_initial
The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:
L_final = I_final * ω_final
0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s
Solving for ω_final:
ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²
Hence, the skater's final angular velocity is approximately 9.86 rad/s.
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What is the physiological response of the body when exercise is stopped instantaneously?
Blood flow rapidly decreases and blood pools in your feet
Blood flow rapidly decreases and lung capacity increases
Blood flow rapidly increases and heart rate decreases
Blood flow rapidly increases and blood pools in your hands
Answers
Answer:
Blood flow rapidly decreases and blood pools in your feet
Explanation:
Because I did the test and if u don't want to except my answer then ***** but if u do and get it right mark it the best. OK?
Answer:
The answer is A blood flows rapidly decreases blood pools in your feet
Explanation:
I hope the helps i just did the quiz/test and got it correct
Which element is usually listed first in the formula of a binary
molecular compound
a the element with the smallest atomic radius
b the element with the lowest electronegativity
C the element with the smallest atomic mass
d the element that is first in alphabetical order help!
Answers
Answer: the element with the lowest electronegativity
Explanation:
A 2.93 kg particle has a velocity of (2.98 i hat - 3.98 j) m/s.
Required:
a. Find its x and y components of momentum.
b. Find the magnitude and direction of its momentum.
Answers
Answer:
a) The x and y components of the momentum are \(8.731\,\frac{kg\cdot m}{s}\) and \(-11.661\,\frac{kg\cdot m}{s}\), respectively.
b) The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.
Explanation:
a) The vectorial equation of momentum is represented by the following expression:
\(\vec p = m\cdot \vec v\) (1)
Where:
\(\vec p\) - Vector momentum, measured in kilogram-meters per second.
\(m\) - Mass of the particle, measured in kilograms.
\(\vec v\) - Vector velocity, measured in meters per second.
If we know that \(m = 2.93\,kg\) and \(\vec v = 2.98\,\hat{i}-3.98\,\hat{j}\,\,\,\left[\frac{m}{s} \right]\), then the momentum is:
\(\vec p = (2.93)\cdot (2.98\,\hat{i}-3.98\,\hat{j})\,\,\,\left[\frac{kg\cdot m}{s} \right]\)
\(\vec p = 8.731\,\hat{i}-11.661\,\hat{j}\,\,\,\left[\frac{kg\cdot m}{s} \right]\)
The x and y components of the momentum are \(8.731\,\frac{kg\cdot m}{s}\) and \(-11.661\,\frac{kg\cdot m}{s}\), respectively.
b) The magnitude and direction of momentum are represented by the following expressions:
\(\|\vec p \| = \sqrt{p_{x}^{2}+p_{y}^{2}}\) (2)
\(\theta = \tan^{-1}\left(\frac{p_{y}}{p_{x}} \right)\) (3)
Where:
\(\|\vec p\|\) - Magnitude of momentum, measured in kilogram-meters per second.
\(\theta\) - Direction of momentum, measured in sexagesimal degrees.
If we know that \(p_{x} = 8.731\,\frac{kg\cdot m}{s}\) and \(p_{y} = -11.661\,\frac{kg\cdot m}{s}\), then the magnitude and direction of momentum are, respectively:
\(\|\vec p\| = \sqrt{\left(8.731\,\frac{kg\cdot m}{s} \right)^{2}+\left(-11.661\,\frac{kg\cdot m}{s} \right)^{2}}\)
\(\|\vec p\| \approx 14.567\,\frac{kg\cdot m}{s}\)
\(\theta =\tan^{-1}\left(\frac{-11.661\,\frac{kg\cdot m}{s} }{8.731\,\frac{kg\cdot m}{s} } \right)\)
\(\theta \approx 306.823^{\circ}\)
The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.
How long would it take you to walk 3,962 km from New York to Los
Angeles?
Answers
Answer:
913 hours ur welcome :)
2. A girl and her bicycle have a total mass of 40 kg. At the top of the hill her speed is 5.0 m/s.
The hill is 10 m high and 100 m long.
If the magnitude of the force of friction as she rides down the hill is 20 N, what is her speed
at the bottom of the hill? (Take g=9.8 m/s?)
(a) 5.0 m/s
(b) 10 m/s
(c) 11 m/s
(d) 18 m/s
(e) She stops before she reaches the bottom.
Answers
Answer:
Explanation:
1. First draw a free body diagram of the scenerio (a block sliding down a a slant surface).
2. Then we analyze the forces and write equations that satisfy Fnet = ma. This will give us the acceleration as the block slides down the surface.
3. Last, we can use the kinematic equation (vf^2 = vi^2 + 2as) and to solve the final speed of the block.
A calorimeter contains a mass m1 = 250g of water. The initial temperature of the system
(calorimeter+water) is T1 = 18 ° C. A mass m2 = 300 g of water is added at the temperature
T2= 80 ° C.
1. What would be the thermal equilibrium temperature Te of the system if the heat capacity of
the calorimeter and its accessories was negligible?
2. in fact a temperature of thermal equilibrium Te = 50 ° C is measured. Determine the heat
capacity C of the calorimeter and its accessories.
Data: Specific heat of liquid water cw = 4185 J.kg-1
.K-1
; Density of water: ρ = 1000 kg.m-3.
Answers
Answer:
To find the thermal equilibrium temperature Te of the system, we can use the principle of conservation of energy, which states that the heat lost by the hot water (m2) is equal to the heat gained by the cold water (m1) and the calorimeter. Mathematically,
m2 * cw * (T2 - Te) = (m1 + m2) * cw * (Te - T1)
where cw is the specific heat of liquid water.
Simplifying and solving for Te, we get:
Te = (m2 * T2 + m1 * T1) / (m1 + m2) = (0.3 kg * 80 °C + 0.25 kg * 18 °C) / (0.3 kg + 0.25 kg) ≈ 51.5 °C
Therefore, the thermal equilibrium temperature Te of the system would be approximately 51.5 °C if the heat capacity of the calorimeter and its accessories was negligible.
If the measured thermal equilibrium temperature is Te = 50 °C, we can use the same principle of conservation of energy to find the heat capacity C of the calorimeter and its accessories. Mathematically,
(m1 + m2) * cw * (Te - T1) = C * (Te - T1)
Simplifying and solving for C, we get:
C = (m1 + m2) * cw / (Te - T1) = (0.25 kg + 0.3 kg) * 4185 J/kg.K / (50 °C - 18 °C) ≈ 3195 J/K
Therefore, the heat capacity C of the calorimeter and its accessories would be approximately 3195 J/K.
Scientist start by asking a question about something what is the initial explanation to that question called
Answers
A hypothesis. It is the first step to the scientific method.
If the current in each wire is the same, which wire produces the strongest magnetic field?
-a wire that is 1 mm thick and not coiled
-a wire that is 2 mm thick and not coiled
-a 1-mm-thick coiled wire with ten loops
-a 2-mm-thick coiled wire with two loops
Answers
Answer:
C
Explanation:
I did this before
Answer:
it is c
Explanation:
cuz i know
Explain why sugar was used in this experiment. How does the experiment relate to a baker adding yeast to bread to make it rise?
Answers
Answer:
Yeast can use oxygen to release the energy from sugar (like you can) in the process called "respiration". ... So, the more sugar there is, the more active the yeast will be and the faster its growth (up to a certain point - even yeast cannot grow in very strong sugar - such as honey).
A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
Answers
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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what determines the size of a launch window? answer specifically and detail.
Answers
Explanation:
The size of a launch window is determined by a variety of factors, including the position of the launch site, the desired orbit, the position of the destination, and the characteristics of the spacecraft being launched.
One of the most important factors is the position of the launch site relative to the desired orbit. The launch site must be positioned in such a way that the rocket can achieve the required velocity and trajectory to reach the desired orbit. The angle and speed at which the rocket is launched are also crucial, as they affect the amount of fuel required and the trajectory of the rocket.
The position of the destination is another factor that affects the size of the launch window. For example, if the spacecraft is bound for a planet that is moving in its orbit, the launch window must be adjusted to account for the changing position of the planet.
In addition, the characteristics of the spacecraft being launched, such as its size, weight, and propulsion system, can also affect the size of the launch window. A larger spacecraft may require more fuel and a longer burn time, which may limit the available launch window.
Overall, the size of a launch window is determined by a complex set of factors, including the position of the launch site, the desired orbit, the position of the destination, and the characteristics of the spacecraft being launched. Launch planners use sophisticated computer models and simulations to calculate the optimal launch window based on these factors.
1. Would a cart that has four solid disks for wheels have a final speed that is greater than, less than, or equal to the final speed of a single disc that has the same mass as the cart and
wheels? Explain.
2. Suppose a cart with four wheels and a disk whose mass is equal to the total mass of the cart roll down the ramp. Which, if either, has more gravitational potential energy at the top?
3. Which of those objects has more kinetic energy at the bottom? Why?
4. Imagine the disk just spinning in place instead of rolling, would it have kinetic energy? Why?
5. Why does the cart have more speed at the bottom even though it doesn't have more kinetic energy than the disk?
Answers
The final speed would be equal because they don't depend on the mass or the radius.
What variables affect kinetic and potential energy, respectively?The mass, gravitational pull, and height above the earth all affect how much potential energy an item has. This energy is transformed into kinetic or indeed the change in momentum, when you fall the thing. An object's mass and speed affect its kinetic energy.
What three variables determine kinetic energy?The quantity of work performed on an object as well as its velocity following an inertia moment caused by external forces are two aspects that affect the overall kinetic energy about an object. The most crucial variables that affect kinetic energy are the motion calculated in terms of the object's mass and velocity.
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